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  • Get the last checked checkboxes...

    - by Sara
    Hi everyone, I'm not sure how to accomplish this issue which has been confusing me for a few days. I have a form that updates a user record in MySQL when a checkbox is checked. Now, this is how my form does this: if (isset($_POST['Update'])) { $paymentr = $_POST['paymentr']; //put checkboxes array into variable $paymentr2 = implode(', ', $paymentr); //implode array for mysql $query = "UPDATE transactions SET paymentreceived=NULL"; $result = mysql_query($query); $query = "UPDATE transactions SET paymentdate='0000-00-00'"; $result = mysql_query($query); $query = "UPDATE transactions SET paymentreceived='Yes' WHERE id IN ($paymentr2)"; $result = mysql_query($query); $query = "UPDATE transactions SET paymentdate=NOW() WHERE id IN ($paymentr2)"; $result = mysql_query($query); foreach ($paymentr as $v) { //should collect last updated records and put them into variable for emailing. $query = "SELECT id, refid, affid FROM transactions WHERE id = '$v'"; $result = mysql_query($query) or die("Query Failed: ".mysql_errno()." - ".mysql_error()."<BR>\n$query<BR>\n"); $trans = mysql_fetch_array($result, MYSQL_ASSOC); $transactions .= '<br>User ID:'.$trans['id'].' -- '.$trans['refid'].' -- '.$trans['affid'].'<br>'; } } Unfortunately, it then updates ALL the user records with the latest date which is not what I want it to do. The alternative I thought of was, via Javascript, giving the checkbox a value that would be dynamically updated when the user selected it. Then, only THOSE checkboxes would be put into the array. Is this possible? Is there a better solution? I'm not even sure I could wrap my brain around how to do that WITH Javascript. Does the answer perhaps lie in how my mysql code is written? Thanks - I sincerely appreciate it!!!

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  • Login in via curl then open that page logged in

    - by user207022
    I'm trying the following code to send post data to the login form, then reload that page in the browser as a logged in user. somehow it's not saving the cookie, and reusing it for the header() function, can the same thing as header be done by calling curl again after sending the login details? .. $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); $ch = curl_init(); curl_setopt($ch, CURLOPT_URL,$url); curl_setopt($ch, CURLOPT_FOLLOWLOCATION,true); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_HEADER, true); curl_setopt($ch, CURLOPT_TIMEOUT, 60); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER , false ); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST , false ); curl_setopt($ch, CURLOPT_USERAGENT, $defined_vars['HTTP_USER_AGENT']); //curl_setopt($ch, CURLOPT_COOKIEJAR, $cookie); curl_setopt($ch, CURLOPT_COOKIEFILE, $cookie); curl_setopt($ch, CURLOPT_MAXREDIRS, 1); // Apply the XML to our curl call curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $data); $data = curl_exec($ch); setcookie($cookie); header('location: ' . $url); die();

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  • What are the attributes that are need to Send with this FEDEX shipping script?

    - by Fero
    could any one please tell me what are the attributes that are send with $ship_data ? I am too confused about it. I know that ORIGIN ADDRESS, DESTINATION ADDRESS, NAME etc.. need to be send. But how the data should be aligned. Like name is FIRST, address is SECOND etc... Any help will be useful ** // create new fedex object $fed = new FedExDC('#########','#########'); $ship_data = array( 75= 'LBS', 16= 'Ma' , 13= '44 Main street' , 5= '312 stuart st', 1273= '01', 1274= '01', 18= '6173335555', 15= 'Boston', 23= '1', 9= '02134', 183= '6175556985', 8= 'MA', 117= 'US', 17= '02116', 50= 'US', 4= 'Vermonster LLC', 7= 'Boston', 1369= '1', 12= 'Jay Powers', 1333= '1', 1401= '1.0', 116= 1, 68= 'USD', 1368= 1, 1369= 1, 1370= 5 ); // Ship example $ship_Ret = $fed-ship_express($ship_data); if ($error = $fed-getError()) { echo "ERROR :". $error; } else { // Save the label to disk $fed-label('mylabel.png'); } /* tracking example $track_Ret = $fed-track( array( 29 = 790344664540, )); echo $fed-debug_str. "\n"; echo "Price ".$ship_Ret[1419];*/ echo ""; if ($error = $fed-getError()) { die("ERROR: ". $error); } else { // decode and save label $fed-label('myLabel.png'); echo $fed-debug_str. "\n"; echo "\n\n"; echo "Price $".$ship_Ret[1419]; echo "\n"; echo "Tracking# ".$ship_Ret[29]; } echo ""; ?** Thanks Fero

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  • Server.TransferRequest returns blank page on specific server

    - by jishi
    I'm facing an issue that seems to be related to configuration. I have a webapplication based on MonoRail, where we utilize the routing feature from MonoRail. On the first request after the application has started, the routing isn't initialized. To circumvent this, I have the following code in Application_OnError(): public virtual void Application_OnError() { if ( // identified as routing error ) Server.TransferRequest( Context.Request.RawUrl, false ); return; } Problem beeing that on our development server (which runs server 2008 R2, with IIS 7.5 and .NET 3.5) returns a blank page without headers, but on my workstation (which runs win7, IIS 7.5 and .NET 3.5) it works fine. What could be the cause of this? If the code in Application_OnError() throws an exception, what would be the expected output? I have verified the following: The access-log shows one entry, I'm not sure if a TransferRequest would show up as a second entry when invoked successfully The application actually do some work according to my internal logs, and it doesn't die since a subsequent requests works flawlessly (because routing will be active) Any hints on what to look for would be greatly appreciated!

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  • php curl login not work

    - by Massimo Zampieri
    Hi i have a problem with the curl. I watched an old post Remote Login not Working With Curl, but it not work. I followed baba's advice but the code enter in the if statement. Sorry for my bad english. Can anyone help me? This is the code: $url="http://hipfile.com/"; $urllog="http://hipfile.com/login.html"; $postdata = "login=bnnoor&password=########&op=login"; $ch = curl_init(); curl_setopt ($ch, CURLOPT_URL, $url); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt ($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.6) Gecko/20070725 Firefox/2.0.0.6"); curl_setopt ($ch, CURLOPT_TIMEOUT, 60); curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 1); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_REFERER, $urllog); curl_setopt ($ch, CURLOPT_POSTFIELDS, $postdata); curl_setopt ($ch, CURLOPT_POST, 1); $result = curl_exec ($ch); if (!$result) { $http_code = curl_getinfo($ch, CURLINFO_HTTP_CODE); curl_close($ch); // make sure we closeany current curl sessions die($http_code.' Unable to connect to server. Please come back later.'); } echo $result; curl_close($ch);

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  • How to fetch populated associated models in CakePHP when calling read()

    - by Code Commander
    I have the following Models: class Site extends AppModel { public $name = "Site"; public $useTable = "site"; public $primaryKey = "id"; public $displayField = 'name'; public $hasMany = array('Item' => array('foreignKey' => 'siteId')); public function canView($userId, $isAdmin = false) { if($isAdmin) { return true; } return array_key_exists($this->id, $allowedSites); } } and class Item extends AppModel { public $name = "Item"; public $useTable = "item"; public $primaryKey = "id"; public $displayField = 'name'; public $belongsTo = array('Site' => array('foreignKey' => 'siteId')); public function canView($userId, $isAdmin = false) { // My problem appears to be the next line: return $this->Site->canView($userId, $isAdmin); } } In my controller I am doing something like this: $result = $this->Item->read(null, $this->request->id); // Verify permissions if(!$this->Item->canView($this->Session->read('userId'), $this->Session->read('isAdmin'))) { $this->httpCodes(403); die('Permission denied.'); } I notice that in Item->canView() $this->data['Site'] is populated with the column data from the site table. But it merely an array and not an object. On the other hand $this->Site is a Site object, but it has not been populated with the column data from the site table like $this->data. What is the proper way to have CakePHP get the associated model as the object and containing the data? Or am I going about this all wrong? Thanks!

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  • problem with enable/disable button using javascript

    - by LiveEn
    Im am trying to add a check box that will enable/disable the edit button. Im retrieving a price list and displaying it inside a table. When i add the javascript into the php code it doesn't work. Below is my code <table border="1"> <tr> <td width="100">Fee % </td> <td width="100">Price</td> <td width="100">Total</td> <td width="102">&nbsp;</td> </tr> <tr> <?php $sql1="select * from pricelist"; $result1=mysql_query($sql1) or die(mysql_error()); while ($row=mysql_fetch_array($result1)) { $id=$row['id']; $price=$row['h_price']; $a=0; print "<form id='form1' name='$a+' method='post' action=''>"; print "<td><input name='fees' value ='$fees' type='text' size='4' /></td>"; print "<td><input name='price' value ='$price' type='text' size='15' /></td>"; echo "<td><input type='checkbox' onclick='this.$a+.disabled = !this.checked;'><td>"; print"<td><input type='submit' name='$a+' value='Submit' disabled='disabled' /></td>"; print "</tr>"; print "</form>"; } ?> </table> Can someone please tell me what am i doing wrong? Thanks

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  • Who to select value from DropDown list in PHP???Problem

    - by sandy
    Hello .. I want to know the error in this code The following code retrieves the names of the members of the database query in the dropdownlist But how do I know who you selected.... I want to send messages only to the members that selected form dropdown list <?php include ("connect.php"); $name = $_POST['sector_list']; echo $name ; ?> <form method="POST" action="" > <input type="hidden" name="sector" value="sector_list"> <select name="sector_list" class="inputstandard"> <option size ="40" value="default">send to </option> <?php $result = mysql_query('select * from members ') or die (mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo '<option size ="40" value=" '. $row['MemberID'] . '" name="' . $row['MemberName']. '">' . $row['MemberName']. '</option>'; } ?> </select> </form> I hope somebody can help me

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  • MySQL PHP SELECT throwing up an error?

    - by user1909695
    I am trying to make a comment section on my hand made site, using PHP and MySQL. I have got the comments stored in my database, but when I try to SELECT them my site throws up this error, mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 9 in /home/a9210109/public_html/comments.php on line 16 My code so far is below <?php $comment = $_POST['comment']; $mysql_host = ""; $mysql_database = ""; $mysql_user = ""; $mysql_password = ""; mysql_connect($mysql_host,$mysql_user,$mysql_password); @mysql_select_db($mysql_database) or die( "Unable to select database"); $CreateTable = "CREATE TABLE comments (comment VARCHAR(255), time VARCHAR(255));"; mysql_query($CreateTable); $UseComment = "INSERT INTO comments VALUES ('$comment')"; mysql_query($UseComment); $SelectComments = "SELECT * FROM comments"; $comments = mysql_query($SelectComments); $num=mysql_numrows($comments); $variable=mysql_result($comments,$i,"comment"); mysql_close(); ?> <a href="#" onclick="toggle_visibility('hidden');">Show/Hide Comments</a> <?php $i=0; while ($i < $num) { $comment=mysql_result($comments,$i,"comment"); echo "<div id='hidden' style='display:none'><h3>$comment</h3></div>"; $i++; } ?>

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  • PHP - Select from database the same query

    - by How to PHP
    I created a table that contains the name of the user and his job, and created PHP page that shows me all the users that works doctor, I entered doctor into a variable then I selected from the table where Jobs equal to $doctor, that is great, but I need it to get the same Jobs into a table in the page and the other same jobs into a table in the same page. this is my code that shows only the users works doctor in one table, <html> <h1>Doctors</h1> </html> <?php mysql_connect('localhost','root',''); mysql_select_db('data'); $doctor='doctor'; $query= mysql_query("SELECT * FROM `users` WHERE `job` = '$doctor'")or die(mysql_error()); while ($arr = mysql_fetch_array($query)) $name= $arr['name']; echo $name; } ?> That shows me doctors when I put doctor in a variable I want to show all same Jobs in a table. Is there is a way to do this? Thanks :)

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  • problem with insert into mysql DB using PHP

    - by user504363
    Hi all I have strange problem that I have a PHP page used to insert data into Mysql DB. the problem is that when I execute the code, nothing added to db and no errors is appeared although I set display errors codes error_reporting(E_ALL); ini_set('display_errors', TRUE); ini_set('display_startup_errors', TRUE); any idea about this problem ! here is my used code for inserting function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { if (PHP_VERSION < 6) { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; } $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? doubleval($theValue) : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } include("Connections/mzk_mdc.php"); $ext = 1; $website = "mzk"; $mzk_sql=sprintf("INSERT INTO downloads (image, `by`, `rapid_title`, title, `description`, category, div_id, topic_url, down_times, ext, `website`) VALUES (%s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s)", GetSQLValueString($topic_thumb_image, "text"), GetSQLValueString($topic_by, "text"), GetSQLValueString($topic_des, "text"), GetSQLValueString($topic_title, "text"), GetSQLValueString($forum_content, "text"), GetSQLValueString($topic_category, "text"),GetSQLValueString($topic_div, "text"),GetSQLValueString($forum_link, "text") ,GetSQLValueString($topic_down_times, "int"),GetSQLValueString($ext, "int"), GetSQLValueString($website, "text")); mysql_select_db($database_mdc, $mdc); $mzk_result = mysql_query($mzk_sql, $mdc) or die("can not do more"); mysql_close($mdc);

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  • User input in Perl with IO::Socket

    - by David
    I am trying to make a perl program which allows a user to input the host and the port number of a foreign host to connect to using IO::Socket. It allows me to run the program and input a host and a port but it never connects and says "Could not connect to [host] at c:\users\USER\Documents\code\perl\sql.pl line 18, line 2." What am i doing wrong with this code shown below? And also, how can i have input validation on my host, which can either be a host name or an ip address? Thanks a bunch! Code Below use IO::Socket print "Host to connect to: "; chomp ($host = <STDIN>); print "Port to connect with: "; chomp ($port = <STDIN>); while(($port > 65535) || ($port <= 0)){ print "Port to connect with [Port > 0 < 65535] : "; chomp ($port = <STDIN>); } print "\nConnecting to host $host on port $port\n"; $socket = new IO::Socket::INET ( LocalHost => '$host', LocalPort => '$port', Proto => 'tcp', Listen => 5, Reuse => 1 ); die "Could not connect to $host";

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  • Why am I returning empty records when querying in mysql with php?

    - by Brian Bolton
    I created the following script to query a table and return the first 30 results. The query returns 30 results, but they do not have any text or information. Why would this be? The table stores Vietnamese characters. The database is mysql4. Here's the page: http://saomaidanang.com/recentposts.php Here's the code: <?php header( 'Content-Type: text/html; charset=utf-8' ); //CONNECTION INFO $dbms = 'mysql'; $dbhost = 'xxxxx'; $dbname = 'xxxxxxx'; $dbuser = 'xxxxxxx'; $dbpasswd = 'xxxxxxxxxxxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpasswd ) or die('Error connecting to mysql'); mysql_select_db($dbname , $conn); //QUERY $result = mysql_query("SET NAMES utf8"); $cmd = 'SELECT * FROM `phpbb_posts_text` ORDER BY `phpbb_posts_text`.`post_subject` DESC LIMIT 0, 30 '; $result = mysql_query($cmd); ?> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html dir="ltr"> <head> <title>recent posts</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> </head> <body> <p> <?php //DISPLAY while ($myrow = mysql_fetch_row($result)) { echo 'post subject:'; echo(utf8_encode($myrow ['post_subject'])); echo 'post text:'; echo(utf8_encode($myrow ['post_text'])); } ?> </p> </body>

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  • I need to sort php jquery gallery script alphabetically

    - by David Cahill
    know nothing about php, but I have this script that reads a folder and displays a thumbnail gallery, problem is it dosent display alphabetically. Have searched the net and seen that sort does this but have no idea where to start any help would be much appreciated. heres the script $sitename = $row_wigsites['id']; $directory = 'sites/'.$sitename.'/pans'; $allowed_types=array('jpg','jpeg','gif','png'); $file_parts=array(); $ext=''; $title=''; $i=0; $dir_handle = @opendir($directory) or die("There is an error with your image directory!"); while ($file = readdir($dir_handle)) { if($file=='.' || $file == '..') continue; $file_parts = explode('.',$file); $ext = strtolower(array_pop($file_parts)); $title = implode('.',$file_parts); $title = htmlspecialchars($title); $nomargin=''; if(in_array($ext,$allowed_types)) { if(($i+1)%4==0) $nomargin='nomargin'; echo ' <div class="pic '.$nomargin.'" style="background:url('.$directory.'/'.$file.') no-repeat 50% 50%;"> <a href="'.$directory.'/'.$file.'" title="Panoramic Stills taken at '.$title.'°" rel="pan1" target="_blank">'.$title.'</a> </div>'; $i++; } } closedir($dir_handle);

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  • How can I send multiple images in a server push Perl CGI program?

    - by Jujjuru
    I am a beginner in Perl CGI etc. I was experimenting with server-push concept with a piece of Perl code. It is supposed to send a jpeg image to the client every three seconds. Unfortunately nothing seems to work. Can somebody help identify the problem? Here is the code: use strict; # turn off io buffering $|=1; print "Content-type: multipart/x-mixed-replace;"; print "boundary=magicalboundarystring\n\n"; print "--magicalboundarystring\n"; #list the jpg images my(@file_list) = glob "*.jpg"; my($file) = ""; foreach $file(@file_list ) { open FILE,">", $file or die "Cannot open file $file: $!"; print "Content-type: image/jpeg\n\n"; while ( <FILE> ) { print "$_"; } close FILE; print "\n--magicalboundarystring\n"; sleep 3; next; } EDIT: added turn off i/o buffering, added "use strict" and "@file_list", "$file" are made local

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  • Reading a binary file in perl: Bad File Descriptor

    - by Magicked
    I'm trying to read a binary file 40 bytes at a time, then check to see if all those bytes are 0x00, and if so ignore them. If not, it will write them back out to another file (basically just cutting out large blocks of null bytes). This may not be the most efficient way to do this, but I'm not worried about that. However, right now I'm getting a "Bad File Descriptor" error and I cannot figure out why. my $comp = "\x00" * 40; my $byte_count = 0; my $infile = "/home/magicked/image1"; my $outfile = "/home/magicked/image1_short"; open IN, "<$infile"; open OUT, ">$outfile"; binmode IN; binmode OUT; my ($buf, $data, $n); while (read (IN, $buf, 40)) { ### Problem is here ### $boo = 1; for ($i = 0; $i < 40; $i++) { if ($comp[$i] != $buf[$i]) { $i = 40; print OUT $buf; $byte_count += 40; } } } die "Problems! $!\n" if $!; close OUT; close IN; I marked with a comment where it is breaking. Thanks for any help!

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  • Server Push CGI Perl Problem writing the JPEG image

    - by Jujjuru
    I am a beginner in Perl CGI etc. I was experimenting with server-push concept with a piece of perl code. It is supposed to send a jpeg image to the client every 3 seconds. Unfortunately nothing seems to work. Can somebody help identify the problem? Here is the code.... use strict; # turn off io buffering $|=1; print "Content-type: multipart/x-mixed-replace;"; print "boundary=magicalboundarystring\n\n"; print "--magicalboundarystring\n"; #list the jpg images my(@file_list) = glob "*.jpg"; my($file) = ""; foreach $file(@file_list ) { open FILE,">", $file or die "Cannot open file $file: $!"; print "Content-type: image/jpeg\n\n"; while ( <FILE> ) { print "$_"; } close FILE; print "\n--magicalboundarystring\n"; sleep 3; next; } EDIT: added turn off i/o buffering, added "use strict" and "@file_list", "$file" are made local

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  • PHP post request to retrieve JSON

    - by Brian
    I'm trying to write some simple php code that will make a post request and then retrieve a JSON result from the server. It seemed simple to me, but the below code simply doesn't open a connection. $port = 2057; $path = "/validate/"; $request = "value1=somevalue&value2=somevalue&value3=somevalue"; $http_request = "POST $path HTTP/1.0\r\n"; $http_request .= "Host: $server\r\n"; $http_request .= "Content-Type: application/x-www-form-urlencoded;\r\n"; $http_request .= "Content-Length: " . strlen($request) . "\r\n"; $http_request .= "\r\n"; $http_request .= $request; $response = ''; if( false == ( $fs = @fsockopen($server, $port) ) ) { die ('Could not open socket'); } fwrite($fs, $http_request); while ( !feof($fs) ) { $response .= fgets($fs, 1160); } fclose($fs); In addition I've tried a more simple approach with: $handle = fopen('http://localhost:2057/validate/?'.$request, "r"); or $response = file_get_contents('http://localhost:2057/validate/' . $request); but both of these approaches just time out. I'm trying to connect to a development server I'm running in Visual Studio, so I'm not sure if that has anything to do with the timeout/connection issues. Open to any suggestions here as long as they are built in PHP.

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  • How to count the Chinese word in a file using regex in perl?

    - by Ivan
    I tried following perl code to count the Chinese word of a file, it seems working but not get the right thing. Any help is greatly appreciated. The Error message is Use of uninitialized value $valid in concatenation (.) or string at word_counting.pl line 21, <FILE> line 21. Total things = 125, valid words = which seems to me the problem is the file format. The "total thing" is 125 that is the string number (125 lines). The strangest part is my console displayed all the individual Chinese words correctly without any problem. The utf-8 pragma is installed. #!/usr/bin/perl -w use strict; use utf8; use Encode qw(encode); use Encode::HanExtra; my $input_file = "sample_file.txt"; my ($total, $valid); my %count; open (FILE, "< $input_file") or die "Can't open $input_file: $!"; while (<FILE>) { foreach (split) { #break $_ into words, assign each to $_ in turn $total++; next if /\W|^\d+/; #strange words skip the remainder of the loop $valid++; $count{$_}++; # count each separate word stored in a hash ## next comes here ## } } print "Total things = $total, valid words = $valid\n"; foreach my $word (sort keys %count) { print "$word \t was seen \t $count{$word} \t times.\n"; } ##---Data---- sample_file.txt ??????,???????,????.??????.????:"?????????????,??????,????????.????????,?????????, ???????????.????????,???????????,??????,??????.???:`??,???????????.'?????, ??????????."??????,??????.????.???, ????????????,????,??????,?????????,??????????????. ????????,??????,???????????,????????,????????.????,????,???????, ??????????,??????,????????.??????.

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  • PHP Class Question

    - by Jerry
    Hi all I am trying to build a PHP class to check the username and password in MySql. I am getting "mysql_query(): supplied argument is not a valid MySQL-Link resource in D:\2010Portfolio\football\main.php on line 38" database has errors:" message. When I move my userQuery code out of my Class, it works fine. Only if it is inside my Class. I am not sure if the problem is that I don't build the connection to mysql inside my Class or not. Thanks for any helps!! Here is my code <?php $userName=$_POST['userName']; $userPw=$_POST['password']; class checkUsers { public $userName; public $userPw; function checkUsers($userName='', $userPw=''){ $this->userName=$userName; $this->userPw=$userPw; } function check1(){ if (empty($this->userName) || empty($this->userPw)){ $message="<strong>Please Enter Username and Password</strong>"; }else{ //line 38 is next line $userQuery=mysql_query("SELECT userName, userPw FROM user WHERE userName='$this->userName' and userPw='$this->userPw'", $connection); if (!$userQuery){ die("database has errors: ". mysql_error()); } if(mysql_num_rows($userQuery)==0){ $message="Please enter valid username and password"; } }//end empty check return $message; }//end check1 method }//end Class $checkUser=new checkUsers($userName, $userPw); echo $checkUser->check1(); ?> I appreciate any helps!!!!

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  • csv to hash data structure conversion using perl

    - by Kavya S
    1. Convert a .csv file to perlhash data structure Format of a .csv file: sw,s1,s2,s3,s4 ver,v1,v2,v3,v4 msword,v2,v3,v1,v1 paint,v4,v2,v3,v3 outlook,v1,v1,v3,v2 my perl script: #!/usr/local/bin/perl use strict; use warnings; use Data::Dumper; my %hash; open my $fh, '<', 'some_file.csv' or die "Cannot open: $!"; while (my $line = <$fh>) { $line =~ s/,,/-/; chomp ($line); my @array = split /,/, $line; my $key = shift @array; $hash{$key} = $line; $hash{$key} = \@array; } print Dumper(\%hash); close $fh; perl hash i.e output should look like: $sw_ver_db = { s1 => { msword => {ver => v2}, paint => {ver => v4}, outlook => {ver => v1}, }, s2 => { msword => {ver => v3}, paint => {ver => v2}, outlook => {ver => v1}, }, s3 => { msword => {ver =>v1}, paint => {ver =>v3}, outlook => {ver =>v3}, }, s4 => { msword => {ver =>v1}, paint => {ver =>v3}, outlook => {ver =>v2}, }, };

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  • php insert doesnot take place _ URGENT HELP PLEASE

    - by reggie
    my code is as follows <?php include("config.php"); $ip=$_SERVER['REMOTE_ADDR']; if($_POST['id']) { $id=$_POST['id']; $id = mysql_escape_String($id); $ip_sql=mysql_query("select ip_add from Voting_IP where mes_id_fk='$id' and ip_add='$ip'"); $count=mysql_num_rows($ip_sql); if($count==0) { $sql = "update Messages set up=up+1 where mes_id='$id'"; mysql_query($sql); $sql_in = "insert into Voting_IP (mes_id_fk,ip_add) values ('$id','$ip')"; mysql_query($sql_in) or die(mysql_error()); echo "<script>alert('Thanks for the vote');</script>"; } else { echo "<script>alert('You have already voted');</script>"; } $result=mysql_query("select up from Messages where mes_id='$id'"); $row=mysql_fetch_array($result); $up_value=$row['up']; echo "<img src='button.png' width='110' height='90'>"; echo $up_value; } ?> My problem is that the insert process doesnot take place at all. the script tags echos an alert box. even the img tag is echoed to the web page. but the insert process doesnot take place. the config file is fine.. note: this code works on my local machine which has php 5.3 but it doesnot work on the server which has php 5.2.. any advice..???

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  • Why do I get "Bad File Descriptor" when I try to read a file with Perl?

    - by Magicked
    I'm trying to read a binary file 40 bytes at a time, then check to see if all those bytes are 0x00, and if so ignore them. If not, it will write them back out to another file (basically just cutting out large blocks of null bytes). This may not be the most efficient way to do this, but I'm not worried about that. However, right now I'm getting a "Bad File Descriptor" error and I cannot figure out why. my $comp = "\x00" * 40; my $byte_count = 0; my $infile = "/home/magicked/image1"; my $outfile = "/home/magicked/image1_short"; open IN, "<$infile"; open OUT, ">$outfile"; binmode IN; binmode OUT; my ($buf, $data, $n); while (read (IN, $buf, 40)) { ### Problem is here ### $boo = 1; for ($i = 0; $i < 40; $i++) { if ($comp[$i] != $buf[$i]) { $i = 40; print OUT $buf; $byte_count += 40; } } } die "Problems! $!\n" if $!; close OUT; close IN; I marked with a comment where it is breaking. Thanks for any help!

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  • Complex SQL design, help/advice needed

    - by eugeneK
    Hi, i have few questions for SQL gurus in here ... Briefly this is ads management system where user can define campaigns for different countries, categories, languages. I have few questions in mind so help me with what you can. Generally i'm using ASP.NET and i want to cache all result set of certain user once he asks for statistics for the first time, this way i will avoid large round-trips to server. any help is welcomed Click here for diagram with all details you need for my questions 1.Main issue of this application is to show to the user how many clicks/impressions were and how much money he spent on campaign. What is the easiest way to get this information for him? I will also include filtering by date, date ranges and few other params in this statistics table. 2.Other issue is what happens when user will try to edit campaign. Old campaign will die this means if user set 0.01$ as campaignPPU (pay-per-unit) and next day updates it to 0.05$ all will be reset to 0.05$. 3.If you could re-design some parts of table design so it would be more flexible and easier to modify, how would you do it? Thanks... sorry for so large job but it may interest some SQL guys in here

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  • Forcing user to new page in php. (PHP newbie)

    - by JohnC
    Hello I'm a newbie web programmer. My background is writing Windows applications with sql. I'm putting together my 1st data entry screens in Php. I have a search form that links to a form that displays records in a grid. On each row of the grid I have a delete url to allow the user to remove a record. This links to a form delete.php (which calls the sql to remove the record). Ideally I would like to automatically take the user back to the search form rather than forcing the user to click on a link to do so. I have used ob_start with the header to do this elsewhere but cannot get it to work on this page. Is there another way to do it? (Using php 5 as part of LAMP) file delete.php <?php $id = $_GET['recordID']; //ob_start(); require_once('connections/local.php'); mysql_select_db($database_local, $local); mysql_query("DELETE FROM user_access WHERE id = {$id}") or die(mysql_error()); echo("Record ".$id." deleted"); echo("<br>"); //header("location:http://localhost/search7.htm); //ob_flush(); echo("<a href=\"http://localhost/search7.htm\">Search for Members</a>"); ?>

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