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  • How can I force a tree itemrenderer to redraw during a drag and drop operation?

    - by swidnikk
    I have a tree control with a custom item renderer. The item renderer has different states that should be set while an item is being dragged over the item renderer. I understand from reading this post http://forums.adobe.com/message/2091088 that the 'right way' to do this is to override the 'getCurrentState' method and append some text. I do that. Now in my tree control I handle the drag over event and get a reference to the itemrenderer that is being dragged over and I set the boolean 'dragOver' property to true. Now I just need to force my itemRenderer to redraw. I can't figure that out. A workaround, is to just set the currentState of the itemRenderer. My question then, how can I force my itemRenderer to refresh? (and I've tried calling validateNow, invalideDisplayList/Properties/Size, to no avail) <?xml version="1.0" encoding="utf-8"?> <s:MXTreeItemRenderer xmlns:fx="http://ns.adobe.com/mxml/2009" xmlns:s="library://ns.adobe.com/flex/spark" xmlns:mx="library://ns.adobe.com/flex/mx"> <fx:Script> <![CDATA[ import mx.events.DragEvent; import mx.events.FlexEvent; import spark.layouts.supportClasses.DropLocation; public var dragOver:Boolean = false; override protected function getCurrentRendererState():String { var skinState:String = super.getCurrentRendererState(); if( dragOver ) skinState += "AndDragOver"; trace('getCurrentRendererState', skinState); return skinState; } ]]> </fx:Script> <s:states> <s:State name="normal" /> <s:State name="hovered" /> <s:State name="selected" /> <s:State name="normalAndDragOver" stateGroups="dragOverGroup" /> <s:State name="hoveredAndDragOver" stateGroups="dragOverGroup" /> <s:State name="selectedAndDragOver" stateGroups="dragOverGroup" /> </s:states> ...

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  • How to modify preorder tree traversal algorithm to handle nodes with multiple parents?

    - by poldo
    I've been searching for a while now and can't seem to find an alternative solution. I need the tree traversal algorithm in such a way that a node can have more than 1 parent, if it's possible (found a great article here: Storing Hierarchical Data in a Database). Are there any algorithms so that, starting from a root node, we can determine the sequence and dependencies of nodes (currently reading topological sorting)?

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  • merge sort recursion tree height

    - by Tony
    Hello! I am learning about recursion tree's and trying to figure out how the height of the tree is log b of n where n = 2 and one has 10 elements as input size. I am working with Merge sort. The number of times the split is done is the height of the tree as far as I understood, and the number of levels in the tree is height + 1. But if you take (for merge sort) log2 of 10 you get 1, where if you draw the tree you get at least 2 times that the recursion occurs. Where have I gone wrong? (I hope I am making sense here) NOTE: I am doing a self study, this is not homework!

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  • Tree item edit event listener in flex

    - by Biroka
    I want to catch itemEditEnd in a tree control, but i'm having a little trouble. I call the item editing a bit different: <mx:Tree id="tree" width="100%" height="100%" itemDoubleClick="treeProjects_itemDoubleClickHandler(event)" doubleClickEnabled="true" editable="true" itemEditBeginning="treeProjects_itemEditBeginingHandler(event)" itemEditEnd="treeProjects_itemEditEndHandler(event)" > but: protected function treeProjects_itemEditBeginingHandler(event:ListEvent):void { event.preventDefault(); } i do this, because I want to edit the field just when clicking rename in the context menu. And when I click rename in the context menu, this is what i'm doing (contextParentItem is the event catched on itemRollOver in the tree) : Tree( contextParentItem.target ).editedItemPosition = { columnIndex: 0, rowIndex: contextParentItem.rowIndex }; Thisway I can't catch the itemEditEnd event, but I want to handle some stuff, like: if the new entered value is an empty string, then I don't want to accept the new value if I hit ESC then, the old value should remain.

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  • Help on understanding multiple columns on an index?

    - by Xaisoft
    Assume I have a table called "table" and I have 3 columns, a, b, and c. What does it mean to have a non-clustered index on columns a,b? Is a nonclustered index on columns a,b the same as a nonclustered index on columns b,a? (Note the order). Also, Is a nonclustered index on column a the same as a nonclustered index on a,c? I was looking at the website sqlserver performance and they had these dmv scripts where it would tell you if you had overlapping indexes and I believe it was saying that having an index on a is the same as a,b, so it is redundant. Is this true about indexes? One last question is why is the clustered index put on the primary key. Most of the time the primary key is not queried against, so shouldn't the clustered index be on the most queried column. I am probably missing something here like having it on the primary key speeds up joins? Great explanations. Should I turn this into a wiki and change the title index explanation?

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  • dojo 1.4: difference in tree html rendering

    - by Fell
    Hi, I have written an application using dojo 1.3 in which i have used the dijit tree. I am loading the tree with json data specified in the store which is in turn used by the tree model. In the 1.3 version the tree elements pick up the id directly from the json data.However in 1.4 the tree elements have their own id which is something like dijit__treenode_4. The id's that I have specified in json are unique and im not able to understand why these are not being used anymore. Please help me understand how this functionality has changed and how I can override the automatic id generation.. Thanks in advance, Fell

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  • Very long tree control inside a <frame>

    - by ryancerium
    I have an tree control inside of a frame. It's quite tall, around 2000 pixels. Right now, we use the frame's scroll bars, which is mostly good. Unfortunately, when you select an item near the bottom of the list, the page reloads and the view goes back to the top of the list. I tried calling the tree control's ScrollNodeIntoView() function, but since we're not using the tree's scroll bars, it just thinks that it's displaying the full 2000 pixels and the control doesn't have its own scroll bar. I'm not much of an HTML guru, so I have two ideas, neither of which I know how to do. 1) Tell the frame to not to let the tree render all 2000 pixels and instead stay inside the viewable area. 2) Tell the tree to not render all 2000 pixels and instead stay within the viewable area. Setting the CSS height property on the within the frame doesn't do anything. Thanks.

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  • Behavior of Struts2 and convention-plugin when there is Index(extends ActionSupport)

    - by hanishi
    We have an Action class named 'Index' immediately under com.example.common.action and is annotated @ParentPackage('default') which is declared in package directive in struts.xml and has "/" for its namespace and extends "struts-default". It also declares @Result so that it responses with jsp files corresponding the string values returned by its execute() method. In our struts.xml, the following struts setting is configured along with other necessary configurations that are needed for convention-plugin. <constant name="struts.action.extension" value=","/> When accessing /my_context/none_existing_path, the request apparently hits this Index class and the contents of the jsp declared in the Index's @Result section gets returned. However, if we provide /my_context/, we receive the following error: HTTP Status 404-There is no Action mapped for namespace[/] and action name [] associated with context path [/my_context]. We want to know the reason why accessing /my_context/none_existing_path, where none_existing_path has no matching action, can fallback to Index class, but error is returned when when the URL requested is just /my_context/. Currently, our convention-plugin settings are declared as follows: <constant name="struts.convention.package.locators.basePackage" value="com.example"/> <constant name="struts.convention.package.locators" value="action"/> Strangely, if we changed the value of the struts.convention.package.locators.basePackage to om.example.common, in which the aforementioned Index file can be immediately found by narrowing the search scope, requesting /my_context/ displays the content of the jsps declared in @Result section of the Index class. However, as our action classes are distributed throughout the com.example.[a-z].action packages, where [a-z] represents the large volume of directories we have in our package structure, we cannot use this trick as a workaround. We have also tried placing index.jsp at the top level of the class path, and have the index.jsp redirect to /my_context/index, which worked but not what we want. Could this be a bug? We appreciate your responses. Thank you in advance. EDIT: JIRA registered, problem solved (from Struts 2.3.12 up)

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  • Virtual String Tree - Display subnode when parent node is hidden

    - by daemon_x
    Is there a way to show subnode if the parent node is hidden in the Virtual String Tree ? I have some tasks in the tree structure and I wish to display only tasks which belongs to the current user as the list, but from all levels. What I've done is the function to display a list, which hides tree buttons, tree lines, sets the fixed indent and enable toShowHiddenNodes option. Then in this function I iterate through the whole tree (all levels) and hide nodes which doesn't belong to the current user IsVisible[Node] := False and show those which belongs him IsVisible[Node] := True, but the subnodes which should be displayed are invisible when their parent is hidden. VT.TreeOptions.PaintOptions - toShowButtons - toShowTreeLines + toFixedIndent + toShowHiddenNodes

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  • Last element not getting insert in Tree

    - by rdk1992
    So I was asked to make a Binary Tree in Haskell taking as input a list of Integers. Below is my code. My problem is that the last element of the list is not getting inserted in the Tree. For example [1,2,3,4] it only inserts to the tree until "3" and 4 is not inserted in the Tree. data ArbolBinario a = Node a (ArbolBinario a) (ArbolBinario a) | EmptyNode deriving(Show) insert(x) EmptyNode= insert(tail x) (Node (head x) EmptyNode EmptyNode) insert(x) (Node e izq der) |x == [] = EmptyNode --I added this line to fix the Prelude.Head Empty List error, after I added this line the last element started to be ignored and not inserted in the tree |head x == e = (Node e izq der) |head x < e = (Node e (insert x izq) der) |head x > e = (Node e izq (insert x der)) Any ideas on whats going on here? Help is much appreciated

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  • Efficiently get the size of a parameter pack up to a certain index

    - by NmdMystery
    I want to be able to determine the number of bytes that are in a subset of a parameter pack from 0 to a given index. Right now I'm using a non-constexpr way of doing this. Below is my code: template <size_t index, typename... args> struct pack_size_index; template <size_t index, typename type_t, typename... args> struct pack_size_index <index, type_t, args...> { static const size_t index_v = index; static const size_t value(void) { if (index_v > 0) { return sizeof(type_t) + pack_size_index<index - 1, args...>::value(); } return 0; } }; template <size_t index> struct pack_size_index <index> { static const size_t index_v = index; static const size_t value(void) { return 0; } }; Usage: //output: 5 (equal to 1 + 4) std::cout << pack_size_index<2, bool, float, int, double>::value() << std::endl; //output: 20 (equal to 8 + 8 + 4) std::cout << pack_size_index<3, double, double, float, int>::value() << std::endl; This gets the job done, but this uses runtime comparison and the resulting executable increases in size rapidly whenever this is used. What's a less expensive way of doing this?

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  • SQL SERVER – Four Posts on Removing the Bookmark Lookup – Key Lookup

    - by pinaldave
    In recent times I have observed that not many people have proper understanding of what is bookmark lookup or key lookup. Increasing numbers of the questions tells me that this is something developers are encountering every single day but have no idea how to deal with it. I have previously written three articles on this subject. I want to point all of you looking for further information on the same post. SQL SERVER – Query Optimization – Remove Bookmark Lookup – Remove RID Lookup – Remove Key Lookup SQL SERVER – Query Optimization – Remove Bookmark Lookup – Remove RID Lookup – Remove Key Lookup – Part 2 SQL SERVER – Query Optimization – Remove Bookmark Lookup – Remove RID Lookup – Remove Key Lookup – Part 3 SQL SERVER – Interesting Observation – Execution Plan and Results of Aggregate Concatenation Queries In one of my recent class we had in depth conversation about what are the alternative of creating covering indexes to remove the bookmark lookup. I really want to this question open to all of you and see what community thinks about the same. Is there any other way then creating covering index or included index to remove his expensive keylookup? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Backup and Restore, SQL Index, SQL Optimization, SQL Performance, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, SQLAuthority News, SQLServer, T SQL, Technology

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  • Retrieving only the first record or record at a certain index in LINQ

    - by vik20000in
    While working with data it’s not always required that we fetch all the records. Many a times we only need to fetch the first record, or some records in some index, in the record set. With LINQ we can get the desired record very easily with the help of the provided element operators. Simple get the first record. If you want only the first record in record set we can use the first method [Note that this can also be done easily done with the help of the take method by providing the value as one].     List<Product> products = GetProductList();      Product product12 = (         from prod in products         where prod.ProductID == 12         select prod)         .First();   We can also very easily put some condition on which first record to be fetched.     string[] strings = { "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine" };     string startsWithO = strings.First(s => s[0] == 'o');  In the above example the result would be “one” because that is the first record starting with “o”.  Also the fact that there will be chances that there are no value returned in the result set. When we know such possibilities we can use the FirstorDefault() method to return the first record or incase there are no records get the default value.        int[] numbers = {};     int firstNumOrDefault = numbers.FirstOrDefault();  In case we do not want the first record but the second or the third or any other later record then we can use the ElementAt() method. In the ElementAt() method we need to pass the index number for which we want the record and we will receive the result for that element.      int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };      int fourthLowNum = (         from num in numbers         where num > 5         select num )         .ElementAt(1); Vikram

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  • Virtual Brown Bag Recap: FancyHands, CanCan, 1KB XMas Tree, YouTube Yuks

    - by Brian Schroer
    At this week's Virtual Brown Bag meeting: Claudio has some one-month Evernote premium accounts to give away Claudio & George talked about FancyHands, the 4-hour work week, and paying people to do the stuff you don't want to JB shared more Ruby gems: cancan and open and talked about insert and other Ruby Enumerable functions We looked at the winner of the 1KB JavaScript Christmas contest and some fun YouTube videos For detailed notes, links, and the video recording, go to the VBB wiki page: https://sites.google.com/site/vbbwiki/main_page/2010-12-23

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  • index.html in subdirectory will not open

    - by Dušan
    I want to have a website structure like this example.com/ - homepage example.com/solutions/ - this will be the solution parent page example.com/solutions/solution-one - child solution page example.com/solutions/solution-two- child solution page i have setup the example.com/solutions/index.html file so it can be opened as a parent page, but is shows me an error You don't have permission to access /solutions/.html on this server. What is the problem to this, how can i open parent, directory page? I na just using regular html pages, no cms or anything...

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  • Most efficient way to rebuild a tree structure from data

    - by Ahsan
    Have a question on recursively populating JsTree using the .NET wrapper available via NuGet. Any help would be greatly appreciated. the .NET class JsTree3Node has a property named Children which holds a list of JsTree3Nodes, and the pre-existing table which contains the node structure looks like this NodeId ParentNodeId Data AbsolutePath 1 NULL News /News 2 1 Financial /News/Financial 3 2 StockMarket /News/Financial/StockMarket I have a EF data context from the the database, so my code currently looks like this. var parentNode = new JsTree3Node(Guid.NewGuid().ToString()); foreach(var nodeItem in context.Nodes) { parentNode.Children.Add(nodeItem.Data); // What is the most efficient logic to do this recursively? } as the inline comment says in the above code, what would be the most efficient way to load the JStree data on to the parentNode object. I can change the existing node table to suite the logic so feel free to suggest any changes to improve performance.

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  • You don't have permission to access /index.php on this server

    - by Tran Dinh Thoai
    I made a 'login with OpenID' page and I had a error when OpenID provider return to my page: You don't have permission to access /index.php on this server. Additionally, a 404 Not Found error was encountered while trying to use an ErrorDocument to handle the request. If I remove parameters which are returned by OpenID provider, the page run well. How can I fix this problem? The login page that cause error is: http://bryox.com/login

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