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  • objective c compare two date strings in NSDate

    - by mac
    Hi I am having two date as string , that is assigned to two labels, one label holds current date string, that is may 29, 2010 similarly the other date will be selected by user in this same format, i need to check the user date is present, past , or future. by comparing with current date string. please provide some sample code. Thanks in advance.

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  • PHP bitwise left shifting 32 spaces problem and bad results with large numbers arithmetic operations

    - by Victor Stanciu
    Hello, I have the following problems: First: I am trying to do a 32-spaces bitwise left shift on a large number, and for some reason the number is always returned as-is. For example: echo(516103988<<32); // echoes 516103988 Because shifting the bits to the left one space is the equivalent of multiplying by 2, i tried multiplying the number by 2^32, and it works, it returns 2216649749795176448. Second: I have to add 9379 to the number from the above point: printf('%0.0f', 2216649749795176448 + 9379); // prints 2216649749795185920 Should print: 2216649749795185827

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  • Calculate year for end date: PostgreSQL

    - by Dave Jarvis
    Background Users can pick dates as shown in the following screen shot: Any starting month/day and ending month/day combinations are valid, such as: Mar 22 to Jun 22 Dec 1 to Feb 28 The second combination is difficult (I call it the "tricky date scenario") because the year for the ending month/day is before the year for the starting month/day. That is to say, for the year 1900 (also shown selected in the screen shot above), the full dates would be: Dec 22, 1900 to Feb 28, 1901 Dec 22, 1901 to Feb 28, 1902 ... Dec 22, 2007 to Feb 28, 2008 Dec 22, 2008 to Feb 28, 2009 Problem Writing a SQL statement that selects values from a table with dates that fall between the start month/day and end month/day, regardless of how the start and end days are selected. In other words, this is a year wrapping problem. Inputs The query receives as parameters: Year1, Year2: The full range of years, independent of month/day combination. Month1, Day1: The starting day within the year to gather data. Month2, Day2: The ending day within the year (or the next year) to gather data. Previous Attempt Consider the following MySQL code (that worked): end_year = start_year + greatest( -1 * sign( datediff( date( concat_ws('-', year, end_month, end_day ) ), date( concat_ws('-', year, start_month, start_day ) ) ) ), 0 ) How it works, with respect to the tricky date scenario: Create two dates in the current year. The first date is Dec 22, 1900 and the second date is Feb 28, 1900. Count the difference, in days, between the two dates. If the result is negative, it means the year for the second date must be incremented by 1. In this case: Add 1 to the current year. Create a new end date: Feb 28, 1901. Check to see if the date range for the data falls between the start and calculated end date. If the result is positive, the dates have been provided in chronological order and nothing special needs to be done. This worked in MySQL because the difference in dates would be positive or negative. In PostgreSQL, the equivalent functionality always returns a positive number, regardless of their relative chronological order. Question How should the following (broken) code be rewritten for PostgreSQL to take into consideration the relative chronological order of the starting and ending month/day pairs (with respect to an annual temporal displacement)? SELECT m.amount FROM measurement m WHERE (extract(MONTH FROM m.taken) >= month1 AND extract(DAY FROM m.taken) >= day1) AND (extract(MONTH FROM m.taken) <= month2 AND extract(DAY FROM m.taken) <= day2) Any thoughts, comments, or questions? (The dates are pre-parsed into MM/DD format in PHP. My preference is for a pure PostgreSQL solution, but I am open to suggestions on what might make the problem simpler using PHP.) Versions PostgreSQL 8.4.4 and PHP 5.2.10

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  • Converting Oracle date arithmetic to work in HSQLDB

    - by JBristow
    I'm trying to spot-test an Oracle backed database with hsqldb and dbunit, but I've run into a snag. The problem is with the following EJB-QL (simplified a bit): SELECT o FROM Offer o WHERE :nowTime BETWEEN o.startDate AND o.startDate + 7 This seems to only work in Oracle's version of SQL. What's the easiest way for me to convert this to work in both hsqldb and oracle? Assume that changing the two between arguments to named parameters is a very difficult refactor, so I'm going to favor answers that provides a more standardized analog to o.startdate + 7 EDIT: After doing some more research, it looks like Oracle converts the above snippet to o.startdate + INTERVAL '7' DAY which is apparently more standard, but doesn't work in HSQLDB.

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  • How do I get date form week, working also with 53-week years? c#

    - by Oskar Kjellin
    Hey, I have made a function to cound the weeks in a year, and that works fine. The problem is that I need a method to get the mondaydate of the week. This is a swedish calendar. The code below works well for years that have 52 weeks, but some years(like 2009) has 53 weeks. Then I got a date from januari as the mondaydate(cant be right). So please help me to get it to work for all years. What I probably could do is check if the year has 53 weeks and then do some checks but I'd like it to go smooth without special checks. Here's what I've come up with: public static DateTime GetDateFromWeek(int year, int week) { //First day of the year DateTime d = new DateTime(year, 1, 1); GregorianCalendar calendar = new GregorianCalendar(GregorianCalendarTypes.MiddleEastFrench); d = calendar.AddWeeks(d, week); d = d.AddDays(1 - (double)d.DayOfWeek); return d; }

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  • Doing 64 bit manipulation using 32 bit data in Fixed point arithmetic using C.

    - by Viks
    Hi, I am stuck with a problem. I am working on a hardware which only does support 32 bit operations. sizeof(int64_t) is 4. Sizeof(int) is 4. and I am porting an application which assumes size of int64_t to be 8 bytes. The problem is it has this macro BIG_MULL(a,b) ( (int64_t)(a) * (int64_t)(b) 23) The result is always a 32 bit integer but since my system doesn't support 64 bit operation, it always return me the LSB of the operation, rounding of all the results making my system crash. Can someone help me out? Regards, Vikas Gupta

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  • Java Date exception handling try catch

    - by user69514
    Is there some sort of exception in Java to catch an invalid Date object? I'm trying to use it in the following method, but I don't know what type of exception to look for. Is it a ParseException. public boolean setDate(Date date) { this.date = date; return true; }

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  • How to break this string and sort on version number

    - by Sean P
    I have an ASP app that has a string array as such (there are much more than this): 7.5.0.17 Date: 05_03_10 7.5.0.18 Date: 05_03_10 7.5.0.19 Date: 05_04_10 7.5.0.2 Date: 02_19_10 7.5.0.20 Date: 05_06_10 7.5.0.3 Date: 02_26_10 7.5.0.4 Date: 03_02_10 7.5.0.5 Date: 03_08_10 7.5.0.6 Date: 03_12_10 7.5.0.7 Date: 03_19_10 7.5.0.8 Date: 03_25_10 7.5.0.9 Date: 03_26_10 7.5.1.0 Date: 05_06_10 How do I go about sorting these string by version descending?

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  • Beginner SQL question: arithmetic with multiple COUNT(*) results

    - by polygenelubricants
    Continuing with the spirit of using the Stack Exchange Data Explorer to learn SQL, (see: Can we become our own “Northwind” for teaching SQL / databases?), I've decided to try to write a query to answer a simple question (on meta): What % of stackoverflow users have over 10,000 rep?. Here's what I've done: Query#1 SELECT COUNT(*) FROM Users WHERE Users.Reputation >= 10000 Result: 556 Query#2 SELECT COUNT(*) FROM USERS Result: 227691 Now, how do I put them together into one query? What is this query idiom called? What do I need to write so I can get, say, a one-row three-column result like this: 556 227691 0,00244190592

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  • C# Expression Tree Simple Arithmetic

    - by Richard Adnams
    Hello, I've been trying to figure out how to achieve some simple maths using the Expression class. What I'm trying to do is this (1 + 10 * 15) When I try to do this via Expression.Add and Expression.Constant but the result I get is this ((1 + 10) * 15) Which is not right as it evaluates the 1 + 10 first instead of 10 * 15. Is there a way to combine Expression.Add/Multiply etc.. without it creating the brackets? I assume there is but I just can't find where or how! The test code I have is this var v1 = Expression.Constant(1, typeof(int)); var v2 = Expression.Constant(10, typeof(int)); var v3 = Expression.Constant(15, typeof(int)); var a1 = Expression.Add(v1, v2); var m2 = Expression.Multiply(a1, v3); Thanks for your time, Richard.

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  • Array pointer arithmetic question

    - by Konrad
    Is there a way to figure out where in an array a pointer is? Lets say we have done this: int nNums[10] = {'11','51','23', ... }; // Some random sequence int* pInt = nNums[4]; // Some index in the sequence. ... pInt++; // Assuming we have lost track of the index by this stage. ... Is there a way to determine what element index in the array pInt is 'pointing' to without walking the array again?

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  • How to sanity check a date in java

    - by Bloodboiler
    I find it curious that the most obvious way to create Date objects in Java has been deprecated and appears to have been "substituted" with not so obvious to use lenient calendar. So... How do you check that a date given as a combination of day, month and year is a valid date? For instance a date 2008-02-31 (as in yyyy-mm-dd) would be invalid date.

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  • Problem with JavaScript arithmetic

    - by Lynn
    I have a form for my customers to add budget projections. A prominent user wants to be able to show dollar values in either dollars, Kila-dollars or Mega-dollars. I'm trying to achieve this with a group of radio buttons that call the following JavaScript function, but am having problems with rounding that make the results look pretty crummy. Any advice would be much appreciated! Lynn function setDollars(new_mode) { var factor; var myfield; var myval; var cur_mode = document.proj_form.cur_dollars.value; if(cur_mode == new_mode) { return; } else if((cur_mode == 'd')&&(new_mode == 'kd')) { factor = "0.001"; } else if((cur_mode == 'd')&&(new_mode == 'md')) { factor = "0.000001"; } else if((cur_mode == 'kd')&&(new_mode == 'd')) { factor = "1000"; } else if((cur_mode == 'kd')&&(new_mode == 'md')) { factor = "0.001"; } else if((cur_mode == 'md')&&(new_mode == 'kd')) { factor = "1000"; } else if((cur_mode == 'md')&&(new_mode == 'd')) { factor = "1000000"; } document.proj_form.cur_dollars.value = new_mode; var cur_idx = document.proj_form.cur_idx.value; var available_slots = 13 - cur_idx; var td_name; var cell; var new_value; //Adjust dollar values for projections for(i=1;i<13;i++) { var myfield = eval('document.proj_form.proj_'+i); if(myfield.value == '') { myfield.value = 0; } var myval = parseFloat(myfield.value) * parseFloat(factor); myfield.value = myval; if(i < cur_idx) { document.getElementById("actual_"+i).innerHTML = myval; } }

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  • How to read date from the form and calculate a timestamp

    - by Vafello
    I would like to calculate a timestamp based on the input date. I would like to calculate it from the user input (something like 12/12/2011) I guess I need a function that changes the format to something readable for php and then calculate timestamp for this date. Maybe I should use strtotime() function? Any ideas will be appreciated. $date = $_POST['date']; <input type="text" name="date" value="">

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  • Floating Point Arithmetic - Modulo Operator on Double Type

    - by CrimsonX
    So I'm trying to figure out why the modulo operator is returning such a large unusual value. If I have the code: double result = 1.0d % 0.1d; it will give a result of 0.09999999999999995. I would expect a value of 0 Note this problem doesn't exist using the dividing operator - double result = 1.0d / 0.1d; will give a result of 10.0, meaning that the remainder should be 0. Let me be clear: I'm not surprised that an error exists, I'm surprised that the error is so darn large compared to the numbers at play. 0.0999 ~= 0.1 and 0.1 is on the same order of magnitude as 0.1d and only one order of magnitude away from 1.0d. Its not like you can compare it to a double.epsilon, or say "its equal if its < 0.00001 difference". I've read up on this topic on StackOverflow, in the following posts one two three, amongst others. Can anyone suggest explain why this error is so large? Any any suggestions to avoid running into the problems in the future (I know I could use decimal instead but I'm concerned about the performance of that).

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  • Generate a list of file names based on month and year arithmetic

    - by MacUsers
    How can I list the numbers 01 to 12 (one for each of the 12 months) in such a way so that the current month always comes last where the oldest one is first. In other words, if the number is grater than the current month, it's from the previous year. e.g. 02 is Feb, 2011 (the current month right now), 03 is March, 2010 and 09 is Sep, 2010 but 01 is Jan, 2011. In this case, I'd like to have [09, 03, 01, 02]. This is what I'm doing to determine the year: for inFile in os.listdir('.'): if inFile.isdigit(): month = months[int(inFile)] if int(inFile) <= int(strftime("%m")): year = strftime("%Y") else: year = int(strftime("%Y"))-1 mnYear = month + ", " + str(year) I don't have a clue what to do next. What should I do here? Update: I think, I better upload the entire script for better understanding. #!/usr/bin/env python import os, sys from time import strftime from calendar import month_abbr vGroup = {} vo = "group_lhcb" SI00_fig = float(2.478) months = tuple(month_abbr) print "\n%-12s\t%10s\t%8s\t%10s" % ('VOs','CPU-time','CPU-time','kSI2K-hrs') print "%-12s\t%10s\t%8s\t%10s" % ('','(in Sec)','(in Hrs)','(*2.478)') print "=" * 58 for inFile in os.listdir('.'): if inFile.isdigit(): readFile = open(inFile, 'r') lines = readFile.readlines() readFile.close() month = months[int(inFile)] if int(inFile) <= int(strftime("%m")): year = strftime("%Y") else: year = int(strftime("%Y"))-1 mnYear = month + ", " + str(year) for line in lines[2:]: if line.find(vo)==0: g, i = line.split() s = vGroup.get(g, 0) vGroup[g] = s + int(i) sumHrs = ((vGroup[g]/60)/60) sumSi2k = sumHrs*SI00_fig print "%-12s\t%10s\t%8s\t%10.2f" % (mnYear,vGroup[g],sumHrs,sumSi2k) del vGroup[g] When I run the script, I get this: [root@serv07 usage]# ./test.py VOs CPU-time CPU-time kSI2K-hrs (in Sec) (in Hrs) (*2.478) ================================================== Jan, 2011 211201372 58667 145376.83 Dec, 2010 5064337 1406 3484.07 Feb, 2011 17506049 4862 12048.04 Sep, 2010 210874275 58576 145151.33 As I said in the original post, I like the result to be in this order instead: Sep, 2010 210874275 58576 145151.33 Dec, 2010 5064337 1406 3484.07 Jan, 2011 211201372 58667 145376.83 Feb, 2011 17506049 4862 12048.04 The files in the source directory reads like this: [root@serv07 usage]# ls -l total 3632 -rw-r--r-- 1 root root 1144972 Feb 9 19:23 01 -rw-r--r-- 1 root root 556630 Feb 13 09:11 02 -rw-r--r-- 1 root root 443782 Feb 11 17:23 02.bak -rw-r--r-- 1 root root 1144556 Feb 14 09:30 09 -rw-r--r-- 1 root root 370822 Feb 9 19:24 12 Did I give a better picture now? Sorry for not being very clear in the first place. Cheers!! Update @Mark Ransom This is the result from Mark's suggestion: [root@serv07 usage]# ./test.py VOs CPU-time CPU-time kSI2K-hrs (in Sec) (in Hrs) (*2.478) ========================================================== Dec, 2010 5064337 1406 3484.07 Sep, 2010 210874275 58576 145151.33 Feb, 2011 17506049 4862 12048.04 Jan, 2011 211201372 58667 145376.83 As I said before, I'm looking for the result to b printed in this order: Sep, 2010 - Dec, 2010 - Jan, 2011 - Feb, 2011 Cheers!!

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  • How to return the date value from DatePickerDialog in Android?

    - by user1855222
    I am new to android . I ve created a Date picker in android using following guide .http://developer.android.com/guide/topics/ui/controls/pickers.html public class DatePickerFragment extends DialogFragment implements DatePickerDialog.OnDateSetListener { StringBuilder sb = new StringBuilder(); public static String date; @Override public Dialog onCreateDialog(Bundle savedInstanceState) { // Use the current date as the default date in the picker final Calendar c = Calendar.getInstance(); int year = c.get(Calendar.YEAR); int month = c.get(Calendar.MONTH); int day = c.get(Calendar.DAY_OF_MONTH); // Create a new instance of DatePickerDialog and return it return new DatePickerDialog(getActivity(), this, year, month, day); } public void onDateSet(DatePicker view, int year, int month, int day) { // Do something with the date chosen by the user sb.append(year); sb.append('-'); sb.append(month+1); sb.append('-'); sb.append(day); date = sb.toString(); System.out.println("The date is "+date); } I need to return this date value (date = sb.toString()) to my MainActivity . Since the onDateSet method is void what should I do ? Additional Information - DatePickerDialog Triggers at the MainActivity class ,But not with single button click . There are several processes happens in side a single button , Date picker will triggers only when certain condition is met . I do not want to display the date value either . Just want it returned for further processing. Appreciate any kind of guidance Changed onDataset method and justshow() public void onDateSet(DatePicker view, int year, int month, int day) { // Do something with the date chosen by the user sb.append(year); sb.append('-'); sb.append(month+1); sb.append('-'); sb.append(day); date = sb.toString(); MainActivity.newdate=sb.toString(); System.out.println("The date is "+MainActivity.newdate); } public void justShow(){ System.out.println("The date is "+MainActivity.newdate); } This is the relevant Part From Main(After making changes suggested in first reply ) DateToken mydate=new DateToken(); String test=dayvals.get(0); DialogFragment df=new DatePickerFragment(); if(test.equalsIgnoreCase("day")){ df.show(getSupportFragmentManager(), "DatePik"); } System.out.println("Date is on Main"+newdate); DatePickerFragment dpf=new DatePickerFragment(); dpf.justShow(); newdate is the static String , but still outputs null. In both MainActivity and justShow methods . But in onDataSet method date outputs correctly

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  • date representation in user interface

    - by Samuel
    Most of the sites capture the date (e.g. birth date) information as either a single entity (i.e via a calendar control) or instead as separate fields (date, month, year). Are there any benefits in showing them as separate fields? Are they represented in the database as DATE data type or as separate fields. I am just trying to understand the pros & cons of representing the date field.

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  • Keeping sync in multiplayer RTS game that uses floating point arithmetic

    - by Calmarius
    I'm writing a 2D space RTS game in C#. Single player works. Now I want to add some multiplayer functionality. I googled for it and it seems there is only one way to have thousands of units continuously moving without a powerful net connection: send only the commands through the network while running the same simulation at every player. And now there is a problem the entire engine uses doubles everywhere. And floating point calculations are depends heavily on compiler optimalizations and cpu architecture so it is very hard to keep things syncronized. And it is not grid based at all, and have a simple phisics engine to move the space-ships (space ships have impulse and angular-momentum...). So recoding the entire stuff to use fixed point would be quite cumbersome (but probably the only solution). So I have 2 options so far: Say bye to the current code and restart from scratch using integers Make the game LAN only where there is enough bandwidth to have 8 players with thousands of units and sending the positions and orientation etc in (almost) every frame... So I looking for better opinions, (or even tips on migrating the code to fixed-point without messing everything up...)

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  • Pointer arithmetic.

    - by Knowing me knowing you
    Having code: int** a = new int*[2]; a[0] = new int(1); a[1] = new int(2); cout << "a[0] " << a[0] << '\n'; cout << "a[1] " << a[1] << '\n'; cout << "a[2] " << a[2] << '\n'; cout << "a[0] + 1 " << a[0] + 1 << '\n';//WHY THIS ISN'T == a[1] ? cout << "*(a + 1): " << *(a + 1) << '\n'; //WHY THIS IS == a[1] ? cout << "a[0] - a[1] " << static_cast<int>(a[0] - a[1])<< '\n';//WHY THIS IS == 16 not 4? cout << sizeof(int**); Questions are included right next to relevant lines in code.

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  • Removing time from date format

    - by Prash.......
    Hi, I am developing an application in that i have used DatePicker to pick the date but it gives me date with time .I have converted that format into string, now i just want date from that. How should i do that.Plz suggest me something. Following is my code Snippet. NSDate *selected =[datePicker date]; NSString *dateString = [NSString stringWithFormat:@"%@", selected]; here date picker is object of UIDatePicker.

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  • Working with a list, performing arithmetic logic in Python

    - by haea ohoh
    Suppose I have made a large list of numbers, and I want to make another one which I will add, pairwise, with the first list. Here's the first list, A: [109, 77, 57, 34, 94, 68, 96, 72, 39, 67, 49, 71, 121, 89, 61, 84, 45, 40, 104, 68, 54, 60, 68, 62, 91, 45, 41, 118, 44, 35, 53, 86, 41, 63, 111, 112, 54, 34, 52, 72, 111, 113, 47, 91, 107, 114, 105, 91, 57, 86, 32, 109, 84, 85, 114, 48, 105, 109, 68, 57, 78, 111, 64, 55, 97, 85, 40, 100, 74, 34, 94, 78, 57, 77, 94, 46, 95, 60, 42, 44, 68, 89, 113, 66, 112, 60, 40, 110, 89, 105, 113, 90, 73, 44, 39, 55, 108, 110, 64, 108] And here's B: [35, 106, 55, 61, 81, 109, 82, 85, 71, 55, 59, 38, 112, 92, 59, 37, 46, 55, 89, 63, 73, 119, 70, 76, 100, 49, 117, 77, 37, 62, 65, 115, 93, 34, 107, 102, 91, 58, 82, 119, 75, 117, 34, 112, 121, 58, 79, 69, 68, 72, 110, 43, 111, 51, 102, 39, 52, 62, 75, 118, 62, 46, 74, 77, 82, 81, 36, 87, 80, 56, 47, 41, 92, 102, 101, 66, 109, 108, 97, 49, 72, 74, 93, 114, 55, 116, 66, 93, 56, 56, 93, 99, 96, 115, 93, 111, 57, 105, 35, 99] How might I generate the arithmatic addition logic, processing each pairwise value one by one (A[0] and B[0], through A[99], B[99]) and producing the list C (A[0] + B[0] through A[99]+ B[99])?

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  • Unexpected variable update when using bash's $(( )) operator for arithmetic

    - by philo
    I'm trying to trim a few lines from a file. I know exactly how many lines to remove (say, 2 from the top), but not how many total lines are in the file. So I tried this straightforward solution: $ wc -l $FILENAME 119559 my_filename.txt $ LINES=$(wc -l $FILENAME | awk '{print $1}') $ tail -n $(($LINES - 2)) $FILENAME > $OUTPUT_FILE The output is fine, but what happened to LINES?? $ wc -l $OUTPUT_FILE 119557 my_output_file.txt $ echo $LINES 107 Hoping someone can help me understand what's going on.

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  • Extend Javascript Date Object

    - by jAndy
    Hi Folks, I'm curious what would be the best practice to extend the Date constructor. The problem I'm facing is, that the Internet Explorer (< 7+8) can't parse a date like new Date('2010-05-11'); I have to admit that this is not a standard method to parse, anyways FireFox and Chrome perform well on that kind of date string. Now I'm wondering, should I just split/parse/rebuild the string before calling new Date() or is there a more elegant solution ?

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