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  • A Short Guide To Html Form Builder

    HTML form builder is used for additional security and to increase interaction with visitors. There are several benefits of form builder and it is the perfect way to unleash the potential. Form builde... [Author: Caimile Essien - Web Design and Development - April 21, 2010]

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  • Symfony2: validate an object that is not an entity

    - by Marronsuisse
    I am using CraueFormFlowBundle to have a multiple page form, and am trying to do some validation on some of the fields but can't figure out how to do this. The object that needs to be validated isn't an Entity, which is causing me trouble. I tried adding a collectionConstraint in the getDefaultOption function of my form type class, but this doesn't work as I get the "Expected argument of type array or Traversable and ArrayAccess" error. I tried with annotations in my object class, but they don't seem to be taken into account. Are annotations taken into account if the class isn't an entity? (i set enable_annotations to true) Anyway, what is the proper way to do this? Basically, I just want to validate that "age" is an integer... class PoemDataCollectorFormType extends AbstractType { public function buildForm(FormBuilder $builder, array $options) { switch ($options['flowStep']) { case 6: $builder->add('msgCategory', 'hidden', array( )); $builder->add('msgFIB','text', array( 'required' => false, )); $builder->add('age', 'integer', array( 'required' => false, )); break; } } public function getDefaultOptions(array $options) { $options = parent::getDefaultOptions($options); $options['flowStep'] = 1; $options['data_class'] = 'YOP\YourOwnPoetBundle\PoemBuilder\PoemDataCollector'; $options['intention'] = 'my_secret_key'; return $options; } } EDIT: add code, handle validation with annotations As Cyprian, I was pretty sure that using annotations should work, however it doesn't... Here is how I try: In my Controller: public function collectPoemDataAction() { $collector = $this->get('yop.poem.datacollector'); $flow = $this->get('yop.form.flow.poemDataCollector'); $flow->bind($collector); $form = $flow->createForm($collector); if ($flow->isValid($form)) { .... } } In my PoemDataCollector class, which is my data class (service yop.poem.datacollector): class PoemDataCollector { /** * @Assert\Type(type="integer", message="Age should be a number") */ private $age; } EDIT2: Here is the services implementation: The data class (PoemDataCollector) seems to be linked to the flow class and not to the form.. Is that why there is no validation? <service id="yop.poem.datacollector" class="YOP\YourOwnPoetBundle\PoemBuilder\PoemDataCollector"> </service> <service id="yop.form.poemDataCollector" class="YOP\YourOwnPoetBundle\Form\Type\PoemDataCollectorFormType"> <tag name="form.type" alias="poemDataCollector" /> </service> <service id="yop.form.flow.poemDataCollector" class="YOP\YourOwnPoetBundle\Form\PoemDataCollectorFlow" parent="craue.form.flow" scope="request"> <call method="setFormType"> <argument type="service" id="yop.form.poemDataCollector" /> </call> </service> How can I do the validation while respecting the craueFormFlowBundle guidelines? The guidelines state: Validation groups To validate the form data class a step-based validation group is passed to the form type. By default, if getName() of the form type returns registerUser, such a group is named flow_registerUser_step1 for the first step. Where should I state my constraint to use those validation groups..? I tried: YOP\YourOwnPoetBundle\PoemBuilder\Form\Type\PoemDataCollectorFormType: properties: name: - MinLength: { limit: 5, message: "Your name must have at least {{ limit }} characters.", groups: [flow_poemDataCollector_step1] } sex: - Type: type: integer message: Please input a number groups: [flow_poemDataCollector_step6] But it is not taken into acount.

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  • How do you do HTML form testing without real user input simulation ?

    - by justjoe
    this question is like this one, except it's for PHP testing via browser. It's about testing your form input. Right now, i have a form on a single page. It has 12 input boxes. Every time i test the form, i have write those 12 input boxes in my browser. i know it's not a specific coding question. This question is more about how to do direct testing on your form So, how to do recursive testing without consuming too much of your time ?

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  • Convert an HTML form field to a JSON object with inner objects.

    - by Tawani
    Given the following HTML form: <form id="myform"> Company: <input type="text" name="Company" value="ACME, INC."/> First Name: <input type="text" name="Contact.FirstName" value="Daffy"/> Last Name: <input type="text" name="Contact.LastName" value="Duck"/> </form> What is the best way serialize this form in javascript to a JSON object in the format: { Company:"ACME, INC.", Contact:{FirstName:"Daffy", LastName:"Duck"} } Also note that there might be more than 1 "." sign in the field name.

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  • scripting a google docs form submission

    - by justSteve
    I'm trying to create a bookmarklet that parses a page and sends the results to a googledocs spreadsheet via a form that I've defined. The relevent bit of the script is: var form = document.createElement("form"); form.action = "http://spreadsheets.google.com/formResponse?formkey=Fd0SHgwQ3YwSFd5UHZpM1QxMlNOdlE6MA&ifq"; form.method = "POST"; form.id="ss-form"; form.innerHTML = ["<input id='entry_0' name = 'entry.0.single' value = '" + orderDate + "'/>", "<input name = 'entry.2.single' value = '" + email + "'/>", "<input name = 'entry.3.single' value = '" + customerID + "'/>", ].join(""); form.submit(); alert(form.innerHTML); // returns: Nothing is being saved to the form via the bookmarklet - any way to capture google's response in my bookmarklet's code? (fwiw, i've injected jQuery via jQueryify) EDIT: Firebug's Net panel isn't hearing any of the activity triggered by the bookmarklet - How about i approach this from goolgle's viewform method instead of formresponse. The form i'm trying to submit is located at: http://spreadsheets.google.com/viewform?hl=en&formkey=dFd0SHgwQ3YwSFd5UHZpM1QxMlNOdlE6MA How can I go about injecting the script values into that form and then submitting that - again...via script within the bookmarklet that would have been triggered while on the page being parsed?

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  • How to return id of a submitted form using Prototype?

    - by pstinnett
    I have a page that has several ajax submission forms. Each form has a dynamic id assigned to it when it's written to the page. Does anyone know if there is an easy way to return the id of the form that is being submitted? I'm basically looking to click "submit" and alert the id of the submitted form. From there I can use it in the ajax onSuccess function.

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  • JQuery Validation Plugin: Prevent validation issue on nested form

    - by Majid
    I have a form on which I use validation. This form has a section for photo upload. Initially this section contains six elements with the following code: <img class="photo_upload" src="image/app/photo_upload.jpg"> I have bound a function to the click event for the class of photo_upload. This function replaces the image with a minimal form with this code: Copy code <form onsubmit="startUploadImage();" target="control_target" enctype="multipart/form-data" method="post" action="index.php"> <input type="hidden" value="add_image" name="service"> <input type="hidden" value="1000000" name="MAX_FILE_SIZE"> <input type="file" size="10" name="photo" id="photo_file_upload"><br> <button onclick="javascript:cancel_photo_upload();return false;">Cancel</button> </form> So, essentially, after the image is clicked, I'd have a new form nested in my original, validated form. Now, when I use this new form and upload an image, I receive an error (repeated three times) saying: validator is undefined http://host.com/path/index.php Line 286 What is going on here? My guess is this Submit event bubbles up to the outer form As we have validation on that form, validation is triggered, Validation tries to find the form triggering it, Since we have not bound validation to the inner form it returns 'undefined' Now, is my assessment correct? Whether it is or not, how can I solve this issue?

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  • Disappearing IE6 elements.

    - by Stefan Kendall
    I don't know what could be causing this issue, but for some reason, elements on my page (list navigation items, specifically), are disappearing in IE6. That is, from IE developer toolbar, I can see that the elements are there, and the DOM/css is correct, but the elements just aren't visible. The odd thing is that if you set or toggle ANY css element on the list items with the IE6 toolbar, the elements appear. I also have a hover() jQuery action set on the list navigation items, and the event fires as if the elements were visible and working correctly. What could possibly be going wrong here? I initially thought z-index could be an issue, but changing ANY attribute or css value (not necessarily z-index), causes the element to render. I should note, however, that doing this programmatically does not cause the elements to display properly, even if triggered seconds after the page load.

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  • Retrieving models from form with ModelMultipleChoiceField

    - by colinjameswebb
    I am having difficulties with forms, specifically ModelMultipleChoiceField. I've pieced together this code from various examples, but it sadly doesn't work. I would like to be able to: Search for some Works on work_search.html Display the results of the search, with checkboxes next to each result Select the Works I want, via the checkboxes After pressing Add, display which works were selected. I believe everything is okay except the last part. The page simply displays "works" :( Here is the code - sorry about the length. Models.py class Work(models.Model): title = models.CharField(max_length=200) artist = models.CharField(max_length=200) writers = models.CharField(max_length=200) def __unicode__(self): return self.title + ' - ' + self.artist forms.py class WorkSelectForm(forms.Form): def __init__(self, queryset, *args, **kwargs): super(WorkSelectForm, self).__init__(*args, **kwargs) self.fields['works'] = forms.ModelMultipleChoiceField(queryset=queryset, widget=forms.CheckboxSelectMultiple()) views.py def work_search(request): query = request.GET.get('q', '') if query: qset = ( Q(title__icontains=query) | Q(artist__icontains=query) | Q(writers__icontains=query) ) results = Work.objects.filter(qset).distinct() form = WorkSelectForm(results) return render_to_response("work_search.html", {"form": form, "query": query }) else: results = [] return render_to_response("work_search.html", {"query": query }) def add_works(request): #if request.method == POST: form = WorkSelectForm(request.POST) #if form.isvalid(): items = form.fields['works'].queryset return render_to_response("add_works.html", {"items":items}) work_search.html {% extends "base.html" %} {% block content %} <h1>Search</h1> <form action="." method="GET"> <label for="q">Search: </label> <input type="text" name="q" value="{{ query|escape }}"> <input type="submit" value="Search"> </form> {% if query %} <h2>Results for "{{ query|escape }}":</h2> <form action="add_works" method="post"> <ul> {% if form %} {{ form.as_ul }} {% endif %} </ul> <input type="submit" value="Add"> </form> {% endif %} {% endblock %} add_works.html {% extends "base.html" %} {% block content %} {% if items %} {% for item in items %} {{ item }} {% endfor %} {% else %} <p>Nothing selected</p> {% endif %} {% endblock %}

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  • How to redirect to the current page with form in php?

    - by garcon1986
    Hello, I tried to redirect to the current page with form in my php application. Now i have met a problem. <form name="myform" action="?page=matching" method="GET"> <input id="match_button" type="submit" name="button" value="button" onClick="func_load3()" /> </form> action="?page=matching" means the current page, because i use the single entry in my php application. With the code upon, When i click the button, it redirects to the homepage. And I tried to use: <form name="myform" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="GET"> but it still doesn't work. So i have to ask for help from you. Do you have any ideas about that? How to fix it? Thanks in advance.

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  • How do I add descriptive text to form link .gif ?

    - by erynion
    I want to make the descriptive text around a form link also open the form. I want to make it so you can click on "Some Text Here" (below) and open the form on somesomite.com just as if you clicked on the image below this text (somebut.gif, below) <DIV style="position: absolute; top:10px; right:10px; width:70px; height:25px"> <font color="white"><b>Some Text Here<b></font> </div> <DIV style="position: absolute; top:50px; right:10px; width:70px; height:25px"> <form action="https://www.somesite.com/cgi-bin/something" method="post"> <input type="hidden" name="cmd" value="_s-xclick"> <input type="image" src="https://www.somesite.com/somebut.gif" border="0" name="submit"> <input type="hidden" name="encrypted" value="-----BEGIN PKCS7-----LONG_KEY...> </form> </div> Thanks

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  • Serializing form data with field names that have dots in them.

    - by Dave
    Does the serialize function in jQuery replace dots ('.') with underscores? For example, I have a form field such as: <input id="Project.name" name="Project.name" type="text"> When the form is POSTed, I'm serializing the form data and sending it to another PHP file to save. The dots seem to be converted to underscores. Is this normal behavior?

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  • How can I retrieve the values of controls in the form that posted?

    - by Mike at KBS
    I know this has got to be the simplest-sounding question ever asked about ASP.Net but I'm baffled. I have a form wherein my visitor will enter name, address, etc. Then I am POSTing that form via the PostBackUrl property of my Submit button to another page, where the fields are supposed to be all re-formed into new hidden fields, then POSTed again to Paypal. My problem is I cannot get at the values entered by the visitor in the original page. Any time I put in "runat='server'", ASP.Net completely changes the ID of the control, making it impossible to figure out how to access. In the POSTed form I tried Request.Form["_txtFirstName"] and that turned up null. Then I tried ((TextBox)PreviousPage.FindControl("_txtFirstName")).Text and that was null, too. I've tried variations on those. I cannot figure out how I'm supposed to get at these controls. Why does this stuff need to be so difficult?

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  • Why is my form triggering the wrong controller action?

    - by COCoach
    This form has multiple submit buttons, when clicked, it calls a simple JavaScript function to change the value of a hidden input (function is called "setHidden". This worked before, after some other not relevant code, it has ceased working. Essentially, the action it is supposed to call is never called, instead it seems to default back to a previous URL. The Form: <form action="/League/RemoveOwner" method="post"> <input type="hidden" value="1007" name="lid"/> <input type="hidden" value="0" id="index" name="index"/> <input type="image" src="../../Resources/Images/Delete.png" height="12" alt="Remove Owner" title="Remove Owner" onclick="setHidden('index', '1031')"/></a> coach<br /> </form> The Controller: [HttpPost] public ActionResult RemoveOwner(int id, string index) { //yada return PartialView(); } When clicking the image, it should call the remove owner controller, instead it calls the "View" controller: public ActionResult View(int id) { //yada return View(); }

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  • How to send data after form has been validated using jQuery?

    - by Keith Donegan
    I have a simple email address sign up form as follows: <form action="" id="newsletterform" method="get"> <input type="text" name="email" class="required email" id="textnewsletter" /> <input type="submit" id="signup" /> </form> Here's what I want to be able to do: Validate the form to look for an empty string or a incorrectly filled out email address one the user clicks submit or hits enter. If one of the above happens (empty string etc), I would like to generate an error to let the user know. Then once the user fills out a correctly formed email address and hits submit (or enter) I want the form to send the email address to wherever I specify in the jQuery code and then generate a little "Thank you for signing up notice", all without reloading the browser. I have looked at too many tutorials and my eyes are pretty much aching at this stage, so please don't point me to any urls (I most likely have been there). If someone could provide a barebone outline of what to do It would be so much appreciated.

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  • Stable separation for two classes of elements in an array

    - by AndreyT
    Consider the following problem. We are given an array of elements belonging to one two classes: either red or blue. We have to rearrange the elements of the array so that all blue elements come first (and all red elements follow). The rearrangement must be done is stable fashion, meaning that the relative order of blue elements must be preserved (same for red ones). Is there a clever algorithm that would perform the above rearrangement in-place? A non-in place solution is, of course, straightforward. An obvious in-place solution would be to apply any stable sorting algorithm to the array. However, using a full-fledged sorting algorithm on an array intuitively feels like an overkill, especially taking into account the fact that we are only dealing with two classes of elements. Any ideas greatly appreciated.

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  • Can you set a form field value with PHP?

    - by dcp3450
    I use the $_GET function to pull a value with php from the url (http:..../index.html?variable=value), basic stuff. However, I need to use that value in my form. Typically, I would set <?php echo 'value="'.$variable.'"' ; ?> or something to that effect. However, I can't use php inside my form using the editor I'm working with. Can I set a value in the form without using PHP in my form? If so, how?

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  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    I have a form with multiple fields in it along with a image input field, just below the form i have a list to be displayed on every submit of this form... this has to be done without the use of DB.. I think this can be achieved by using session but its not working with me, as evrytime page gets refreshed and session gets recreated/reset.. Please help me in resolving this issue

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  • how many dojo fliteringselect can I have on a form?

    - by Grant Collins
    I have a quick question How many dojo filteringselects can I have on a form? I have a form with 2 filteringselects on it, both getting data from different json datastores to populate the values. However only the first filteringselect is being populated, the other grabs no data. I am using Zend Framework and Zend_Dojo_Form to create the form elements for this. Many thanks. Ok looks like my code is broken somewhere then. The element that is failing in my form is: $location = new Zend_Dojo_Form_Element_FilteringSelect('location'); $location->setAutocomplete(true) ->setStoreId('countiesstore') ->setStoreType('dojo.data.ItemFileReadStore') ->setStoreParams(array('url' => $baseUrl.'/dojo/counties')) ->setAttrib('searchAttr', 'title') ->setRequired(true) ->removeDecorator('DtDdWrapper') ->removeDecorator('label') ->removeDecorator('HtmlTag') ->removeDecorator('Error'); When I go to http://localhost/dojo/counties I get the json file to read, but the element isn't populated with any data. Any ideas?

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