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  • How to determine the radius and center of a circle when only three noncollinear points are known?

    - by Bob
    I'm working on a C# program that deals with Oracle Spatial geometry. When circle data is stored in a geometry field only three non-collinear points are stored to represent the circle. The problem is that I need to use this data on a Google Maps web page and need the center point and radius of the circle (since my circle drawing function uses that information). Can anyone help with the math involved and translating said math to C#? I think this page may hold the answer, but I'm having a hard time following it. There are formulas for radius and center given three points, but then they define the variables as matrices and I get lost at that point. How would I solve that in code?

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  • How to setup Math program

    - by Miles
    I'm needing to write a program (C#) that will allow the user to create generic formulas with variables and numbers. For example: D = A + (A - C / X)(7.8 - 6.6) F = E + (E - C / X)(7.8 - 6.6) FinalResult = (A + D)(0.9) + (E + F)(0.32) + B(0.1) + .023 where all variables would mean for me to go to a database and look something up based on values and return a number in its place. So A would be 2.12 for example (and the same for C and E) Whats the best way to structure this program? How would I make my program read these formulas? I've seen a little bit of the MathML but not sure how to get that started (or an example of it)

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  • game currency convert: math efficient

    - by Comradsky
    For variables:4 text views named diamondText, goldText, silverText, and bronzeText;money variable unsigned int money;and an NSTimer, every .1 sec,runs function: -(void)updateMoney{ money++; bronzeText.text = [NSString stringWithFormat:@"%d",money]; silverText.text = [NSString stringWithFormat:@"%d",money%10]; goldText.text = [NSString stringWithFormat:@"%d",money%100]; diamondText.text= [NSString stringWithFormat:@"%d",money%1000]; } Given that my currency is diamond = 10 gold = 10 silver = 10 bronze = 1; What would be most efficient way to calculate and display the money labels? How would you store this variable, with GameCenter and NSDictionary or GameCenter and something else? More details are below if you don't understand. To clarify: bronze has the last 2 numbers, silver has the next 2 numbers, and so on. I understand I could use 4 ints or an array, but i would rather try to use this method, unless theres a much more efficient way. Example: When money = 1000;bronzeText = nothing, silverText = 10,goldText = nothing, diamondText = nothing; What other ways would you do this that you think would be more efficient? I will be calling a function (void)collisionDetector that detects if my player.frame crosses with a flyingObject.frame, and if that object is a coin it gives an added value to money and then calls (void)updateMoney. Im just using the timer to test this and spawn these flying objects.

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  • Text + randomchar dosn't work [JavaScript]

    - by user558773
    <script> function makeid() { var text = "var text = document.write(lastNumber);"; var possible = "*+-/"; for( var i=0; i < 1; i++ ) document.write(lastNumber + possible.charAt(Math.floor(Math.random() * possible.length)); return text; } document.write(makeid(1))</script> How do i make this to type for ex: 23* 45- 13/ and so on. What is wrong? It just show me 2 numbers and no char after.

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  • Typing math formulas in LaTex and getting them in MathType format?

    - by Tim
    I am asked to type some math formulas that can work in Microsoft Office and MathType equation editor. But I only have access to Ubuntu 12.04 near me, there is LibreOffice available under Ubuntu as well, but I am used to type math formulas in LaTex. So I wonder how to provide math formulas that will work in Microsoft Office and MathType, if I work under Ubuntu, preferably with LaTex but LibreOffice being also acceptable since it is still under Ubuntu? Thanks and regards!

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  • Final Man vs. Machine Round of Jeopardy Unfolds; Watson Dominates

    - by ETC
    The final round of IBM’s Watson against Ken Jenning and Brad Rutter ended last night with Watson coming out in a strong lead against its two human opponents. Read on to catch a video of the match and see just how quick Watson is on the draw. Watson tore through many of the answers, the little probability bar at the bottom of the screen denoting it was often 95%+ confident in its answers. Some of the more interesting stumbles were, like in the last matches, based on nuance. By far the biggest “What?” moment of the night, however, was when it answered the Daily Double question of “The New Yorker’s 1959 review of this said in its brevity and clarity, it is ‘unlike most such manuals, a book as well as a tool’”. Watson, inexplicably, answered “Dorothy Parker”. You can win them all, eh? Check out the video below to see Watson in action on its final day. Latest Features How-To Geek ETC How to Enable User-Specific Wireless Networks in Windows 7 How to Use Google Chrome as Your Default PDF Reader (the Easy Way) How To Remove People and Objects From Photographs In Photoshop Ask How-To Geek: How Can I Monitor My Bandwidth Usage? Internet Explorer 9 RC Now Available: Here’s the Most Interesting New Stuff Here’s a Super Simple Trick to Defeating Fake Anti-Virus Malware The Citroen GT – An Awesome Video Game Car Brought to Life [Video] Final Man vs. Machine Round of Jeopardy Unfolds; Watson Dominates Give Chromium-Based Browser Desktop Notifications a Native System Look in Ubuntu Chrome Time Track Is a Simple Task Time Tracker Google Sky Map Turns Your Android Phone into a Digital Telescope Walking Through a Seaside Village Wallpaper

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  • Faut-il être bon en math pour être un bon développeur ? Quelle place ont les maths dans votre parcou

    Faut-il être bon en math pour être un bon développeur ? Quelle place ont les maths dans votre métier et votre parcours ? Faut-il être bon en math pour être un bon développeur ? La question mérite d'être posée. Certes, l'informatique est à classer, dans le système universitaire, du coté des sciences "dures", par oppositions aux sciences sociales et humaines. L'enseignement des mathématiques et la rigueur qu'elles amènent paraissent donc indispensable. Pourtant, beaucoup, comme Alan Skorkin - qui vient d'aborder ce sujet sur son blog -, reconnaissent qu'ils n'ont jamais vraiment eu besoin des maths dans leur travail. La position de Alan Skorkin est c...

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  • glm matrix conversion for DirectX

    - by niktehpui
    For on of the coursework specification I need to work with DirectX, so I tried to implement a DirectX Renderer in my small cross-platform framework (to have it optionally available for Windows). Since I want to stick to my dependencies I want use glm for vector/matrix/quaternions math. The vectors seem to be fully compatible with DirectX, but the glm::mat4 is not working properly in DirectX Effects Framework. I assumed the reason is that DirectX uses row majors layouts and OpenGL column majors (although if I remember right internally in HLSL DX uses column major as well), so I transposed the matrix, but I still get no proper results compared to using XNA-Math. XNA-Version of the code (works): XMMATRIX world = XMMatrixIdentity(); XMMATRIX view = XMMatrixLookAtLH(XMVectorSet(5.0, 5.0, 5.0, 1.0f), XMVectorZero(), XMVectorSet(0.0f, 1.0f, 0.0f, 0.0f)); XMMATRIX proj = XMMatrixPerspectiveFovLH(0.25f*3.14f, 1.25f, 1.0f, 1000.0f); XMMATRIX worldViewProj = world*view*proj; m_fxWorldViewProj->SetMatrix(reinterpret_cast<float*>(&worldViewProj)); This works flawlessly and displays the expected colored cube. GLM-Version (does not work): glm::mat4 world(1.0f); glm::mat4 view = glm::lookAt(glm::vec3(5.0f, 5.0f, 5.0f), glm::vec3(0.0f, 0.0f, 0.0f), glm::vec3(0.0f, 1.0f, 0.0f)); glm::mat4 proj = glm::perspective(0.25f*3.14f, 1.25f, 1.0f, 1000.0f); glm::mat4 worldViewProj = glm::transpose(world*view*proj); m_fxWorldViewProj->SetMatrix(glm::value_ptr(worldViewProj)); Displays nothing, screen stays black. I really would like to stick to glm on all platforms.

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  • How would you solve this graph theory handshake problem in python?

    - by Zachary Burt
    I graduated college last year with a degree in Psychology, but I also took a lot of math for fun. I recently got the book "Introductory Graph Theory" by Gary Chartrand to brush up on my math and have some fun. Here is an exercise from the book that I'm finding particularly befuddling: Suppose you and your husband attended a party with three other married couples. Several handshakes took place. No one shook hands with himself (or herself) or with his (or her) spouse, and no one shook hands with the same person more than once. After all the handshaking was completed, suppose you asked each person, including your husband, how many hands he or she had shaken. Each person gave a different answer. a) How many hands did you shake? b) How many hands did your husband shake? Now, I've been reasoning about this for a while, and trying to draw sample graphs that could illustrate a solution, but I'm coming up empty-handed. My logic is this: there are 8 different vertices in the graph, and 7 of them have different degrees. The values for the degrees must therefore be 0, 1, 2, 3, 4, 5, 6, and x. The # of degrees for one married couple is (0, 6). Since all graphs have an even number of odd vertices, x must be either 5, 3, or 1. What's your solution to this problem? And, if you could solve it in python, how would you do it? (python is fun.) Cheers.

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  • How would you solve this graph theory handshake problem in python?

    - by Zachary Burt
    I graduated college last year with a degree in Psychology, but I also took a lot of math for fun. I recently got the book "Introductory Graph Theory" by Gary Chartrand to brush up on my math and have some fun. Here is an exercise from the book that I'm finding particularly befuddling: Suppose you and your husband attended a party with three other married couples. Several handshakes took place. No one shook hands with himself (or herself) or with his (or her) spouse, and no one shook hands with the same person more than once. After all the handshaking was completed, suppose you asked each person, including your husband, how many hands he or she had shaken. Each person gave a different answer. a) How many hands did you shake? b) How many hands did your husband shake? Now, I've been reasoning about this for a while, and trying to draw sample graphs that could illustrate a solution, but I'm coming up empty-handed. My logic is this: there are 8 different vertices in the graph, and 7 of them have different degrees. The values for the degrees must therefore be 0, 1, 2, 3, 4, 5, 6, and x. The # of degrees for one married couple is (0, 6). Since all graphs have an even number of odd vertices, x must be either 5, 3, or 1. What's your solution to this problem? And, if you could solve it in python, how would you do it? (python is fun.) Cheers.

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  • Double type returns -1.#IND/NaN error when calculating pi iteratively

    - by Draak
    I am working through a problem for my MCTS certification. The program has to calculate pi until the user presses a key, at which point the thread is aborted, the result returned to the main thread and printed in the console. Simple enough, right? This exercise is really meant to be about threading, but I'm running into another problem. The procedure that calculates pi returns -1.#IND. I've read some of the material on the web about this error, but I'm still not sure how to fix it. When I change double to Decimal type, I unsurprisingly get Overflow Exception very quickly. So, the question is how do I store the numbers correctly? Do I have to create a class to somehow store parts of the number when it gets too big to be contained in a Decimal? Class PiCalculator Dim a As Double = 1 Dim b As Double = 1 / Math.Sqrt(2) Dim t As Double = 1 / 4 Dim p As Double = 1 Dim pi As Double Dim callback As DelegateResult Sub New(ByVal _callback As DelegateResult) callback = _callback End Sub Sub Calculate() Try Do While True Dim a1 = (a + b) / 2 Dim b1 = Math.Sqrt(a * b) Dim t1 = t - p * (a - a1) ^ 2 Dim p1 = 2 * p a = a1 b = b1 t = t1 p = p1 pi = ((a + b) ^ 2) / (4 * t) Loop Catch ex As ThreadAbortException Finally callback(pi) End Try End Sub End Class

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  • Solving Naked Triples in Sudoku

    - by Kave
    Hello, I wished I paid more attention to the math classes back in Uni. :) How do I implement this math formula for naked triples? Naked Triples Take three cells C = {c1, c2, c3} that share a unit U. Take three numbers N = {n1, n2, n3}. If each cell in C has as its candidates ci ? N then we can remove all ni ? N from the other cells in U.** I have a method that takes a Unit (e.g. a Box, a row or a column) as parameter. The unit contains 9 cells, therefore I need to compare all combinations of 3 cells at a time that from the box, perhaps put them into a stack or collection for further calculation. Next step would be taking these 3-cell-combinations one by one and compare their candidates against 3 numbers. Again these 3 numbers can be any possible combination from 1 to 9. Thats all I need. But how would I do that? How many combinations would I get? Do I get 3 x 9 = 27 combinations for cells and then the same for numbers (N)? How would you solve this in classic C# loops? No Lambda expression please I am already confused enough :) Many Thanks for any help,

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  • What function does .NET NPV() use? Doesn't match manual calculations

    - by Matthew PK
    I am using the NPV() function in VB.NET to get NPV for a set of cash flows. However, the result of NPV() is not consistent with my results performing the calculation manually (nor the Investopedia NPV calc... which matches my manual results) My correct manual results and the NPV() results are close, within 5%.. but not the same... Manually, using the NPV formula: NPV = C0 + C1/(1+r)^1 + C2/(1+r)^2 + C3/(1+r)^3 + .... + Cn/(1+r)^n The manual result is stored in RunningTotal With rate r = 0.04 and period n = 10 Here is my relevant code: EDIT: Do I have OBOB somewhere? YearCashOutFlow = CDbl(TxtAnnualCashOut.Text) YearCashInFlow = CDbl(TxtTotalCostSave.Text) YearCount = 1 PAmount = -1 * (CDbl(TxtPartsCost.Text) + CDbl(TxtInstallCost.Text)) RunningTotal = PAmount YearNPValue = PAmount AnnualRateIncrease = CDbl(TxtUtilRateInc.Text) While AnnualRateIncrease > 1 AnnualRateIncrease = AnnualRateIncrease / 100 End While AnnualRateIncrease = 1 + AnnualRateIncrease ' ZERO YEAR ENTRIES ListBoxNPV.Items.Add(Format(PAmount, "currency")) ListBoxCostSave.Items.Add("$0.00") ListBoxIRR.Items.Add("-100") ListBoxNPVCum.Items.Add(Format(PAmount, "currency")) CashFlows(0) = PAmount '''' Do While YearCount <= CInt(TxtLifeOfProject.Text) ReDim Preserve CashFlows(YearCount) CashFlows(YearCount) = Math.Round(YearCashInFlow - YearCashOutFlow, 2) If CashFlows(YearCount) > 0 Then OnePos = True YearNPValue = CashFlows(YearCount) / (1 + DiscountRate) ^ YearCount RunningTotal = RunningTotal + YearNPValue ListBoxNPVCum.Items.Add(Format(Math.Round(RunningTotal, 2), "currency")) ListBoxCostSave.Items.Add(Format(YearCashInFlow, "currency")) If OnePos Then ListBoxIRR.Items.Add((IRR(CashFlows, 0.1)).ToString) ListBoxNPV.Items.Add(Format(NPV(DiscountRate, CashFlows), "currency")) Else ListBoxIRR.Items.Add("-100") ListBoxNPV.Items.Add(Format(RunningTotal, "currency")) End If YearCount = YearCount + 1 YearCashInFlow = AnnualRateIncrease * YearCashInFlow Loop

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  • How to calculate the normal of points on a 3D cubic Bézier curve given normals for its start and end points?

    - by Robert
    I'm trying to render a "3D ribbon" using a single 3D cubic Bézier curve to describe it (the width of the ribbon is some constant). The first and last control points have a normal vector associated with them (which are always perpendicular to the tangents at those points, and describe the surface normal of the ribbon at those points), and I'm trying to smoothly interpolate the normal vector over the course of the curve. For example, given a curve which forms the letter 'C', with the first and last control points both having surface normals pointing upwards, the ribbon should start flat, parallel to the ground, slowly turn, and then end flat again, facing the same way as the first control point. To do this "smoothly", it would have to face outwards half-way through the curve. At the moment (for this case), I've only been able to get all the surfaces facing upwards (and not outwards in the middle), which creates an ugly transition in the middle. It's quite hard to explain, I've attached some images below of this example with what it currently looks like (all surfaces facing upwards, sharp flip in the middle) and what it should look like (smooth transition, surfaces slowly rotate round). Silver faces represent the front, black faces the back. Incorrect, what it currently looks like: Correct, what it should look like: All I really need is to be able to calculate this "hybrid normal vector" for any point on the 3D cubic bézier curve, and I can generate the polygons no problem, but I can't work out how to get them to smoothly rotate round as depicted. Completely stuck as to how to proceed!

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  • Run Javascript on the body of a Gmail message

    - by saturn
    I want to display LaTeX math in the gmail messages that I receive, so that for example $\mathbb P^2$ would show as a nice formula. Now, there are several Javascripts available (for example, this one, or MathJax which would do the job, I just need to call them at the right time to manipulate the gmail message. I know that this is possible to do in "basic HTML" and "print" views. Is it possible to do in the standard Gmail view? I tried to insert a call to the javascript right before the "canvas_frame" iframe, but that did not work. My suspicion is that manipulating a Gmail message by any Javascript would be a major security flaw (think of all the malicious links one could insert) and that Google does everything to prevent this. And so the answer to my question is probably 'no'. Am I right in this? Of course, it would be very easy for Google to implement viewing of LaTeX and MathML math simply by using MathJax on their servers. I made the corresponding Gmail Lab request, but no answer, and no interest from Google apparently. So, again: is this possible to do without Google's cooperation, on the client side?

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  • Plotting a graph with GD

    - by Nayena
    Here it goes. I have been thinking about this for a long time, and havent really been able to put up a proper way to do it yet. I havent implemented anything yet, as im still designing the thing. The idea is that i crawl a website for internal links, i got this settled, its easy, but after the crawling, i end up with an array with lots of links, and how many times those particular link appears on the site that i crawled (and how they're connected). With this huge array, i want to draw a graph somehow. Assuming i can handle the data correctly, the real question here is how i can draw this in a image by the use of the GD library. I figured if theres less than 12 elements, i can align them up on a unit circle spacing them up as a circle and then connecting them accordingly, so anything up to 12 elements shouldn't be a problem, but if theres more than 12, it could be awesome getting them lined up like this Or well, thats just a rough drawing, but i guess its just to prove a point. So i'm here looking for guidance or tips towards getting the math down to getting the stuff lined up in a good way. I have previously made bar-graphs, so i have little experience doing math with GD. If possible, id prefer not using some plotter-library - in the end, it gives me a better understanding on how things are supposed to be.

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  • Optimizing a 3D World Javascript Animation

    - by johnny
    Hi! I've recently come up with the idea to create a tag cloud like animation shaped like the earth. I've extracted the coastline coordinates from ngdc.noaa.gov and wrote a little script that displayed it in my browser. Now as you can imagine, the whole coastline consists of about 48919 points, which my script would individually render (each coordinate being represented by one span). Obviously no browser is capable of rendering this fluently - but it would be nice if I could render as much as let's say 200 spans (twice as much as now) on my old p4 2.8 Ghz (as a representative benchmark). Are there any javascript optimizations I could use in order to speed up the display of those spans? One 'coordinate': <div id="world_pixels"> <span id="wp_0" style="position:fixed; top:0px; left:0px; z-index:1; font-size:20px; cursor:pointer;cursor:hand;" onmouseover="magnify_world_pixel('wp_0');" onmouseout="shrink_world_pixel('wp_0');" onClick="set_askcue_bar('', 'new york')">new york</span> </div> The script: $(document).ready(function(){ world_pixels = $("#world_pixels span"); world_pixels.spin(); setInterval("world_pixels.spin()",1500); }); z = new Array(); $.fn.spin = function () { for(i=0; i<this.length; i++) { /*actual screen coordinates: x/y/z --> left/font-size/top 300/13/0 300/6/300 | / |/ 0/13/300 ----|---- 600/13/300 /| / | 300/20/300 300/13/600 */ /*scale font size*/ var resize_x = 1; /*scale width*/ var resize_y = 2.5; /*scale height*/ var resize_z = 2.5; var from_left = 300; var from_top = 20; /*actual math coordinates: 1 -1 | / |/ 1 ----|---- -1 /| / | 1 -1 */ //var get_element = document.getElementById(); //var font_size = parseInt(this.style.fontSize); var font_size = parseInt($(this[i]).css("font-size")); var left = parseInt($(this[i]).css("left")); if (coast_line_array[i][1]) { } else { var top = parseInt($(this[i]).css("top")); z[i] = from_top + (top - (300 * resize_z)) / (300 * resize_z); //global beacause it's used in other functions later on var top_new = from_top + Math.round(Math.cos(coast_line_array[i][2]/90*Math.PI) * (300 * resize_z) + (300 * resize_z)); $(this[i]).css("top", top_new); coast_line_array[i][3] = 1; } var x = resize_x * (font_size - 13) / 7; var y = from_left + (left- (300 * resize_y)) / (300 * resize_y); if (y >= 0) { this[i].phi = Math.acos(x/(Math.sqrt(x^2 + y^2))); } else { this[i].phi = 2*Math.PI - Math.acos(x/(Math.sqrt(x^2 + y^2))); i } this[i].theta = Math.acos(z[i]/Math.sqrt(x^2 + y^2 + z[i]^2)); var font_size_new = resize_x * Math.round(Math.sin(coast_line_array[i][4]/90*Math.PI) * Math.cos(coast_line_array[i][0]/180*Math.PI) * 7 + 13); var left_new = from_left + Math.round(Math.sin(coast_line_array[i][5]/90*Math.PI) * Math.sin(coast_line_array[i][0]/180*Math.PI) * (300 * resize_y) + (300 * resize_y)); //coast_line_array[i][6] = coast_line_array[i][7]+1; if ((coast_line_array[i][0] + 1) > 180) { coast_line_array[i][0] = -180; } else { coast_line_array[i][0] = coast_line_array[i][0] + 0.25; } $(this[i]).css("font-size", font_size_new); $(this[i]).css("left", left_new); } } resize_x = 1; function magnify_world_pixel(element) { $("#"+element).animate({ fontSize: resize_x*30+"px" }, { duration: 1000 }); } function shrink_world_pixel(element) { $("#"+element).animate({ fontSize: resize_x*6+"px" }, { duration: 1000 }); } I'd appreciate any suggestions to optimize my script, maybe there is even a totally different approach on how to go about this. The whole .js file which stores the array for all the coordinates is available on my page, the file is about 2.9 mb, so you might consider pulling the .zip for local testing: metaroulette.com/files/31218.zip metaroulette.com/files/31218.js P.S. the php I use to create the spans: <?php //$arbitrary_characters = array('a','b','c','ddsfsdfsdf','e','f','g','h','isdfsdffd','j','k','l','mfdgcvbcvbs','n','o','p','q','r','s','t','uasdfsdf','v','w','x','y','z','0','1','2','3','4','5','6','7','8','9',); $arbitrary_characters = array('cat','table','cool','deloitte','askcue','what','more','less','adjective','nice','clinton','mars','jupiter','testversion','beta','hilarious','lolcatz','funny','obama','president','nice','what','misplaced','category','people','religion','global','skyscraper','new york','dubai','helsinki','volcano','iceland','peter','telephone','internet', 'dialer', 'cord', 'movie', 'party', 'chris', 'guitar', 'bentley', 'ford', 'ferrari', 'etc', 'de facto'); for ($i=0; $i<96; $i++) { $arb_digits = rand (0,45); $arbitrary_character = $arbitrary_characters[$arb_digits]; //$arbitrary_character = "."; echo "<span id=\"wp_$i\" style=\"position:fixed; top:0px; left:0px; z-index:1; font-size:20px; cursor:pointer;cursor:hand;\" onmouseover=\"magnify_world_pixel('wp_$i');\" onmouseout=\"shrink_world_pixel('wp_$i');\" onClick=\"set_askcue_bar('', '$arbitrary_character')\">$arbitrary_character</span>\n"; } ?>

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  • seam page parameters not working as expected.

    - by rangalo
    Hi, I am learning seam and following a very famous book Seam In Action by Dan Allen. This is an example from this book. Seam 2.2.0.GA JBoss 5.1.0.GA Here the page parameter roundId is always null even after a round is serialized, it is never passed. Neither to Roud.xhtml nor to RoundEdit.xhtml after clicking save on RoundEdit.xhtml. The entity always stays unmanaged. RoundEdit.page.xml <?xml version="1.0" encoding="UTF-8"?> <page xmlns="http://jboss.com/products/seam/pages" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://jboss.com/products/seam/pages http://jboss.com/products/seam/pages-2.2.xsd" login-required="true"> <begin-conversation join="true" /> <param name="roundId" value="#{roundHome.id}" converterId="javax.faces.Long"/> <param name="teeSetId" value="#{teeSetHome.teeSetId}" /> <param name="roundFrom" /> <action execute="#{roundHome.wire}" /> <navigation from-action="#{roundHome.persist}"> <rule if-outcome="persisted"> <end-conversation/> <redirect view-id="#{null != roundFrom ? roundFrom : '/Round.xhtml'}" /> </rule> </navigation> </page> RoundEdit.xhtml <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE composition PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <ui:composition xmlns="http://www.w3.org/1999/xhtml" xmlns:s="http://jboss.com/products/seam/taglib" xmlns:ui="http://java.sun.com/jsf/facelets" xmlns:f="http://java.sun.com/jsf/core" xmlns:h="http://java.sun.com/jsf/html" xmlns:a="http://richfaces.org/a4j" xmlns:rich="http://richfaces.org/rich" template="layout/template.xhtml"> <ui:define name="body"> <h:form id="roundform"> <rich:panel> <f:facet name="header>"> #{roundHome.managed ? 'Edit' : 'Add' } Round </f:facet> <s:decorate id="dateField" template="layout/edit.xhtml"> <ui:define name="label">Date:</ui:define> <rich:calendar id="date" datePattern="dd/MM/yyyy" value="#{round.date}"/> </s:decorate> <s:decorate id="notesField" template="layout/edit.xhtml"> <ui:define name="label">Notes:</ui:define> <h:inputTextarea id="notes" cols="80" rows="3" value="#{round.notes}" /> </s:decorate> <s:decorate id="totalScoreField" template="layout/edit.xhtml"> <ui:define name="label">Total Score:</ui:define> <h:inputText id="totalScore" value="#{round.totalScore}" /> </s:decorate> <s:decorate id="weatherField" template="layout/edit.xhtml"> <ui:define name="label">Weather:</ui:define> <h:selectOneMenu id="weather" value="#{round.weather}"> <s:selectItems var="_weather" value="#{weatherCategories}" label="#{_weather.label}" noSelectionLabel=" Select " /> <s:convertEnum/> </h:selectOneMenu> </s:decorate> <h:messages/> <div style="clear: both;"> <span class="required">*</span> required fields </div> </rich:panel> <div class="actionButtons"> <h:commandButton id="save" value="Save" action="#{roundHome.persist}" rendered="#{!roundHome.managed}" disabled="#{!roundHome.wired}" /> <h:commandButton id="update" value="Update" action="#{roundHome.update}" rendered="#{roundHome.managed}" /> <h:commandButton id="delete" value="Delete" action="#{roundHome.remove}" rendered="#{roundHome.managed}" /> <s:button id="discard" value="Discard changes" propagation="end" view="/Round.xhtml" rendered="#{roundHome.managed}" /> <s:button id="cancel" value="Cancel" propagation="end" view="/#{empty roundFrom ? 'RoundList' : roundFrom}.xhtml" rendered="#{!roundHome.managed}" /> </div> <rich:tabPanel> <rich:tab label="Tee Set"> <div class="association"> <h:outputText value="Tee set not selected" rendered="#{round.teeSet == null}" /> <rich:dataTable var="_teeSet" value="#{round.teeSet}" rendered="#{round.teeSet != null}"> <h:column> <f:facet name="header">Course</f:facet>#{_teeSet.course.name} </h:column> <h:column> <f:facet name="header">Color</f:facet>#{_teeSet.color} </h:column> <h:column> <f:facet name="header">Position</f:facet>#{_teeSet.pos} </h:column> </rich:dataTable> </div> </rich:tab> </rich:tabPanel> </h:form> </ui:define> </ui:composition> Round.page.xml <?xml version="1.0" encoding="UTF-8"?> <page xmlns="http://jboss.com/products/seam/pages" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://jboss.com/products/seam/pages http://jboss.com/products/seam/pages-2.2.xsd"> <param name="roundId" value="#{roundHome.id}" converterId="javax.faces.Long"/> </page> Round.xhtml <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE composition PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <ui:composition xmlns="http://www.w3.org/1999/xhtml" xmlns:s="http://jboss.com/products/seam/taglib" xmlns:ui="http://java.sun.com/jsf/facelets" xmlns:f="http://java.sun.com/jsf/core" xmlns:h="http://java.sun.com/jsf/html" xmlns:a="http://richfaces.org/a4j" xmlns:rich="http://richfaces.org/rich" template="layout/template.xhtml"> <ui:define name="body"> <h:form id="roundform"> <rich:panel> <f:facet name="header>">Round</f:facet> <s:decorate id="id" template="layout/display.xhtml"> <ui:define name="label">Id:</ui:define> <h:outputText value="#{null == roundHome.id ? 'null' : roundHome.id}"> <s:convertDateTime type="date" /> </h:outputText> </s:decorate> <s:decorate id="date" template="layout/display.xhtml"> <ui:define name="label">Date:</ui:define> <h:outputText value="#{roundHome.instance.date}"> <s:convertDateTime type="date" /> </h:outputText> </s:decorate> <s:decorate id="golfer" template="layout/display.xhtml"> <ui:define name="label">Golfer:</ui:define> #{roundHome.instance.golfer.name} </s:decorate> <s:decorate id="totalScore" template="layout/display.xhtml"> <ui:define name="label">Total Score:</ui:define> #{roundHome.instance.totalScore} </s:decorate> <s:decorate id="weather" template="layout/display.xhtml"> <ui:define name="label">Weather:</ui:define> #{roundHome.instance.weather} </s:decorate> <s:decorate id="notes" template="layout/display.xhtml"> <ui:define name="label">Notes:</ui:define> #{roundHome.instance.notes} </s:decorate> <div style="clear:both"/> </rich:panel> <div class="actionButtons"> <s:button id="edit" view="/RoundEdit.xhtml" value="Edit" /> </div> <rich:tabPanel> <rich:tab label="Tee Set"> <div class="association"> <h:outputText value="Tee set not selected" rendered="#{roundHome.instance.teeSet == null}" /> <rich:dataTable var="_teeSet" value="#{roundHome.instance.teeSet}" rendered="#{roundHome.instance.teeSet != null}"> <h:column> <f:facet name="header">Course</f:facet>#{_teeSet.course.name} </h:column> <h:column> <f:facet name="header">Color</f:facet>#{_teeSet.color} </h:column> <h:column> <f:facet name="header">Position</f:facet>#{_teeSet.pos} </h:column> </rich:dataTable> </div> </rich:tab> </rich:tabPanel> </h:form> </ui:define> </ui:composition> The entityHome RoundHome.java @Name("roundHome") public class RoundHome extends EntityHome<Round>{ @In(required = false) private Golfer currentGolfer; @In(create = true) private TeeSetHome teeSetHome; @Logger private Log logger; public void wire() { logger.info("wire called"); TeeSet teeSet = teeSetHome.getDefinedInstance(); if (null != teeSet) { getInstance().setTeeSet(teeSet); logger.info("Successfully wired the teeSet instance with color: " + teeSet.getColor()); } } public boolean isWired() { logger.info("is wired called"); if(null == getInstance().getTeeSet()) { logger.info("wired teeSet instance is null, the button will be disabled !"); return false; } else { logger.info("wired teeSet instance is NOT null, the button will be enabled !"); logger.info("teeSet color: "+getInstance().getTeeSet().getColor()); return true; } } @RequestParameter public void setRoundId(Long id) { logger.info("in Setter RoundId is: " + id); super.setId(id); } public Long getRoundId() { Long id = (Long) getId(); logger.info("Setting RoundId : " + id); return id; } @Override protected Round createInstance() { Round round = super.createInstance(); round.setGolfer(currentGolfer); round.setDate(new java.sql.Date(System.currentTimeMillis())); logger.info("Created a Round with roundId: " + round.getId()); return round; } @Override protected Round loadInstance() { logger.info("loadInstance for id: " + getId()); return (Round) getEntityManager().createQuery( "select r from Round r " + "join fetch r.golfer g " + "join fetch r.teeSet ts " + "join fetch ts.course c " + "where r.id = :id ") .setParameter("id",getId()) .getSingleResult(); } }

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  • An array with values 4 days apart

    - by Luke
    I have a piece of code that generates soccer/football fixtures. The idea is that for every round of fixtures, the date will be 4 days further than the last round. So round one will be 3rd may, round two will be 7th may, round three 11th may, etc. I am not sure how to do this? The code that currently makes the fixtures are as follows: $totalRounds = $teams - 1; $matchesPerRound = $teams / 2; $rounds = array(); for ($i = 0; $i < $totalRounds; $i++) { $rounds[$i] = array(); } for ($round = 0; $round < $totalRounds; $round++) { for ($match = 0; $match < $matchesPerRound; $match++) { $home = ($round + $match) % ($teams - 1); $away = ($teams - 1 - $match + $round) % ($teams - 1); // Last team stays in the same place while the others // rotate around it. if ($match == 0) { $away = $teams - 1; } $rounds[$round][$match] = "$user[$home]~$team[$home]@$user[$away]~$team[$away]"; } } The teams would be the total users in the league. So if there are 8 teams, there will be 7 rounds. And i will want each round 4 days apart. And that date will be within each fixture within each round. Any further information needed just ask! Thanks, really stuck on this

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  • linear algebra libraries for clusters

    - by Abruzzo Forte e Gentile
    Hi all I need to develop applications doing linear algebra + eigenvalue + linear equation solutions over a cluster of pcs ( I have a lot of machines available ). I discovered Scalapack libraries but they seem to me developed long time ago. Do you know if these are other libs available that I should learn doing math & linear algebra in a cluster? My language is C++ and off course I am newbie to this topic. Kind Regards to everybody AFG

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  • Uses of a C++ Arithmetic Promotion Header

    - by OlduvaiHand
    I've been playing around with a set of templates for determining the correct promotion type given two primitive types in C++. The idea is that if you define a custom numeric template, you could use these to determine the return type of, say, the operator+ function based on the class passed to the templates. For example: // Custom numeric class template <class T> struct Complex { Complex(T real, T imag) : r(real), i(imag) {} T r, i; // Other implementation stuff }; // Generic arithmetic promotion template template <class T, class U> struct ArithmeticPromotion { typedef typename X type; // I realize this is incorrect, but the point is it would // figure out what X would be via trait testing, etc }; // Specialization of arithmetic promotion template template <> class ArithmeticPromotion<long long, unsigned long> { typedef typename unsigned long long type; } // Arithmetic promotion template actually being used template <class T, class U> Complex<typename ArithmeticPromotion<T, U>::type> operator+ (Complex<T>& lhs, Complex<U>& rhs) { return Complex<typename ArithmeticPromotion<T, U>::type>(lhs.r + rhs.r, lhs.i + rhs.i); } If you use these promotion templates, you can more or less treat your user defined types as if they're primitives with the same promotion rules being applied to them. So, I guess the question I have is would this be something that could be useful? And if so, what sorts of common tasks would you want templated out for ease of use? I'm working on the assumption that just having the promotion templates alone would be insufficient for practical adoption. Incidentally, Boost has something similar in its math/tools/promotion header, but it's really more for getting values ready to be passed to the standard C math functions (that expect either 2 ints or 2 doubles) and bypasses all of the integral types. Is something that simple preferable to having complete control over how your objects are being converted? TL;DR: What sorts of helper templates would you expect to find in an arithmetic promotion header beyond the machinery that does the promotion itself?

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  • Operations on Python hashes

    - by cdecker
    I've got a rather strange problem. For a Distributed Hash Table I need to be able to do some simple math operations on MD5 hashes. These include a sum (numeric sum represented by the hash) and a modulo operation. Now I'm wondering what the best way to implement these operations is. I'm using hashlib to calculate the hashes, but since the hashes I get are then string, how do I calculate with them?

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