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  • How do I delete the next line in vim?

    - by Jason Baker
    In emacs, whenever I want to delete a few lines of text, I just use C-k until all the text is gone. However, in vim it seems a bit more complex. I know I can do d$ to delete until the end of the line and dd to delete the entire line I'm on, but how do I delete all of the next line?

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  • How to configure bugzilla to not advance to next bug when updating?

    - by WilliamKF
    By default, when you apply changes to a Bugzilla entry, the web interface advances to the next bug in your list. I would like to disable this feature since it is almost never what I desire, planning to make further updates later. Further, I often update the wrong bug subsequently due to its changing the current bug without my noticing. How do I configure Bugzilla to not advance like this?

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  • Jquery / PHP - pre-loading next page before navigating to it.

    - by Tim
    Hey all Using jQuery, is there a way to prevent going to the next page until the animation has finished AND the next page has completely loaded (including images)? The code below works but it is a bit clunky. You can see what I am trying to achieve here: http://bit.ly/aOeYgE The first three or so pages work. But when you click to go to the homepage a few times (after it's cached) you will see that it jumps, and the animation isn't very smooth. As you can see with the code below, the height is immediately set to 0, then when the page has loaded the height is set to 500px. When users navigate to a new page, the height should go back to 0, the next page content should load, and then upon loading the new window, the first bit of code will run again to set the width back to 500px. $(".content-center").css({"height": "0px"}); $(window).load(function() { if($('.content-center').is(':not(:animated)')) { $('.content-center').animate({height: "500px"}, 450); } }); $("a").click(function(event){ $(".content-center").animate({height: "0px"}, 500); if($('.content-center').is(':not(:animated)')) { navigate($(this).attr('href')); event.preventDefault(); } }); If anyone has any suggestions or alternative ideas to this code then it would be hugely appreciated. Many thanks Tim

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  • How to force div to appear below not next to another?

    - by Vafello
    I would like to place my div below the list, but actually it is placed next to the list.The list is generated dynamically, so it doesn't have a fixed hight. I would like to have the map div on the right, and on the left (next to the map) the list placed on top and the second div below the list. #map { float:left; width:700px; height:500px; } #list { float:left; width:200px; background:#eee; list-style:none; padding:0; } #similar { float:left; width:200px; background:#000; } <div id="map"></div> <ul id="list"></ul> <div id ="similar"> this text should be below, not next to ul. </div> Any ideas?

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  • this is my first time asking here, I wanted to create a linked list while sorting it thanks

    - by user2738718
    package practise; public class Node { // node contains data and next public int data; public Node next; //constructor public Node (int data, Node next){ this.data = data; this.next = next; } //list insert method public void insert(Node list, int s){ //case 1 if only one element in the list if(list.next == null && list.data > s) { Node T = new Node(s,list); } else if(list.next == null && list.data < s) { Node T = new Node(s,null); list.next = T; } //case 2 if more than 1 element in the list // 3 elements present I set prev to null and curr to list then performed while loop if(list.next.next != null) { Node curr = list; Node prev = null; while(curr != null) { prev = curr; curr = curr.next; if(curr.data > s && prev.data < s){ Node T = new Node(s,curr); prev.next = T; } } // case 3 at the end checks for the data if(prev.data < s){ Node T = new Node(s,null); prev.next = T; } } } } // this is a hw problem, i created the insert method so i can check and place it in the correct order so my list is sorted This is how far I got, please correct me if I am wrong, I keep inserting node in the main method, Node root = new Node(); and root.insert() to add.

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  • Attempt to use a while loop for the 'next' arg of a for loop generates #arg error

    - by JerryK
    Am attempting to teach myself to program using Tcl. The task i've set myself to motivate my learning of Tcl is to solve the 8 queens problem. My approach to creating a program is to successively 'prototype' a solution. I have asked an earlier question related to the correctly laying out the nested for loops and received a helpful answer. To my dismay I find that the next development of my code creates the same interpreter error : "wrong # args" I have been careful to have an open brace at the end of the line preceding the while loop command. I've also tried to put the arguments of the whileloop in braces. This generates a different error. I have sincerely tried to understand the Tcl syntax man page - not too successfully - suggested by the answerer of my earlier question. Here is the code set allowd 1 set notallowd 0 for {set r1p 1} {$r1p <= 8} {incr r1p } { puts "1st row q placed at $r1p" ;# re-initialize r2 'free for q placemnt' array after every change of r1 q pos: for {set i 1 } {$i <= 8} {incr i} { set r2($i) $allowd } for { set r2($r1p) $notallowd ; set r2([expr $r1p-1]) $notallowd ; set r2([expr $r1p+1]) $notallowd ; set r2p 1} {$r2p <= 8} { ;# 'next' arg of r2 forloop will be a whileloop : while r2($r2p)== $notallowd incr r2p } { puts "2nd row q placed at $r2p" ;# end of 'commnd' arg of r2 forloop } } Where am I going wrong? EDIT : to provide clear reply @slebetman As stated in my text, I did brace the arguments of the whileloop (indeed that was how i first wrote the code) below is exactly the layout of the r2 forloop tried: for { set r2($r1p) $notallowd ; set r2([expr $r1p-1]) $notallowd ; set r2([expr $r1p+1]) $notallowd ; set r2p 1} {$r2p <= 8} { ;# 'next' arg of r2 forloop will be a whileloop : while { r2($r2p)== $notallowd } { incr r2p } } { puts "2nd row q placed at $r2p" ;# end of 'commnd' arg of r2 forloop } but this generates the fatal interpreter error : "unknown math function 'r2' while compiling while { r2($r2p .... "

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  • linked list sort function only loops once

    - by Tristan Pearce
    i have a singly linked list that i am trying to sort from least to greatest by price. here is what i have so far struct part { char* name; float price; int quantity; struct part *next; }; typedef struct part partType; partType *sort_price(partType **item) { partType *temp1 = *item; partType *temp2 = (*item)->next; if ( *item == NULL || (*item)->next == NULL ) return *item; else { while ( temp2 != NULL && temp2->next != NULL ){ if (temp2->price > temp2->next->price){ temp1->next = temp2->next; temp2->next = temp2->next->next; temp1->next->next = temp2; } temp1 = temp2; temp2 = temp2->next; } } return *item; } the list is already populated but when i call the sort function it only swaps the first two nodes that satisfy the condition in the if statement. I dont understand why it doesnt do the check again after the two temp pointers are incremented.

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  • How to install Oracle Weblogic Server using OS-specific Package installer?(Linux/Solaris)

    - by PratikS -- Oracle
    Note: OS-specific Package installer As the name suggests the installer is platform specific. It is meant for installation with a 32bit JVM only. Both SUN and JROCKIT 32 bit JDKs come bundled with "OS-specific Package installer", so no need to install the JDK in advance. There are three different ways of installing Oracle Weblogic Server: Graphical mode Console mode Silent mode For Linux/Solaris: Steps to install OS-specific Package .bin installer(for Linux/Solaris) are almost same as windows except for the way we launch the installation.Installer: wls_<version>_<linux/solaris>32.bin (E.g. wls1036_linux32.bin/wls1036_solaris32.bin) 1) Graphical mode: Log in to the target UNIX system. Go to the directory that contains the installation program.(Make sure GUI is enabled or else it will default to console mode) Launch the installation by entering the following commands: [weblogic@pratik ~]$ pwd/home/oracle[weblogic@pratik ~]$ cd WLSInstallers/[weblogic@pratik WLSInstallers]$ ls -ltrtotal 851512-rw-rw-r-- 1 oracle oracle 871091023 Dec 22  2011 wls1036_linux32.bin[weblogic@pratik WLSInstallers]$ chmod a+x wls1036_linux32.bin[weblogic@pratik WLSInstallers]$ ls -ltrtotal 851512-rwxrwxr-x 1 oracle oracle 871091023 Dec 22  2011 wls1036_linux32.bin[weblogic@pratik WLSInstallers]$ ./wls1036_linux32.bin As soon as you run ./wls1036_linux32.bin with GUI enabled you would see the following screen: Rest of the screens and steps are similar to that of Graphical mode installation on windows, refer: How to install Oracle Weblogic Server using OS-specific Package installer?(Windows) 2) Console mode: Log in to the target UNIX system. Go to the directory that contains the installation program. Launch the installation by entering the following commands: [weblogic@pratik ~]$ pwd/home/oracle[weblogic@pratik ~]$ cd WLSInstallers/[weblogic@pratik WLSInstallers]$ ls -ltrtotal 851512-rw-rw-r-- 1 weblogic weblogic 871091023 Dec 22  2011 wls1036_linux32.bin[weblogic@pratik WLSInstallers]$ chmod a+x wls1036_linux32.bin[weblogic@pratik WLSInstallers]$ ls -ltrtotal 851512-rwxrwxr-x 1 weblogic weblogic 871091023 Dec 22  2011 wls1036_linux32.bin [weblogic@pratik WLSInstallers]$ ./wls1036_linux32.bin -mode=consoleExtracting 0%....................................................................................................100%<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Welcome:--------This installer will guide you through the installation of WebLogic 10.3.6.0.Type "Next" or enter to proceed to the next prompt.  If you want to change data entered previously, type "Previous".  You may quit the installer at any time by typing "Exit".Enter [Exit][Next]> Next<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Choose Middleware Home Directory:--------------------------------- ->1|* Create a new Middleware Home   2|/home/oracle/wls_12cEnter index number to select OR [Exit][Previous][Next]> Next<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Choose Middleware Home Directory:---------------------------------    "Middleware Home" = [Enter new value or use default"/home/oracle/Oracle/Middleware"]Enter new Middleware Home OR [Exit][Previous][Next]> /home/oracle/WLS1036<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Choose Middleware Home Directory:---------------------------------    "Middleware Home" = [/home/oracle/WLS1036]Use above value or select another option:    1 - Enter new Middleware Home    2 - Change to default [/home/oracle/Oracle/Middleware]Enter option number to select OR [Exit][Previous][Next]> Next<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Register for Security Updates:------------------------------Provide your email address for security updates and  to initiate configuration manager.   1|Email:[]   2|Support Password:[]   3|Receive Security Update:[Yes]Enter index number to select OR [Exit][Previous][Next]> 3<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Register for Security Updates:------------------------------Provide your email address for security updates and  to initiate configuration manager.    "Receive Security Update:" = [Enter new value or use default "Yes"]Enter [Yes][No]? No<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Register for Security Updates:------------------------------Provide your email address for security updates and  to initiate configuration manager.    "Receive Security Update:" = [Enter new value or use default "Yes"]    ** Do you wish to bypass initiation of the configuration manager and    **  remain uninformed of critical security issues in your configuration?Enter [Yes][No]? Yes<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Register for Security Updates:------------------------------Provide your email address for security updates and  to initiate configuration manager.   1|Email:[]   2|Support Password:[]   3|Receive Security Update:[No]Enter index number to select OR [Exit][Previous][Next]>Next<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Register for Security Updates:------------------------------Provide your email address for security updates and  to initiate configuration manager.   1|Email:[]   2|Support Password:[]   3|Receive Security Update:[No]Enter index number to select OR [Exit][Previous][Next]> Next<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Choose Install Type:--------------------Select the type of installation you wish to perform. ->1|Typical    |  Install the following product(s) and component(s):    | - WebLogic Server    | - Oracle Coherence   2|Custom    |  Choose software products and components to install and perform optional    |configuration.Enter index number to select OR [Exit][Previous][Next]> Next<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Choose Product Installation Directories:----------------------------------------Middleware Home Directory: [/home/oracle/WLS1036]Product Installation Directories:   1|WebLogic Server: [/home/oracle/WLS1036/wlserver_10.3]   2|Oracle Coherence: [/home/oracle/WLS1036/coherence_3.7]Enter index number to select OR [Exit][Previous][Next]> Next<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->The following Products and JDKs will be installed:--------------------------------------------------    WebLogic Platform 10.3.6.0    |_____WebLogic Server    |    |_____Core Application Server    |    |_____Administration Console    |    |_____Configuration Wizard and Upgrade Framework    |    |_____Web 2.0 HTTP Pub-Sub Server    |    |_____WebLogic SCA    |    |_____WebLogic JDBC Drivers    |    |_____Third Party JDBC Drivers    |    |_____WebLogic Server Clients    |    |_____WebLogic Web Server Plugins    |    |_____UDDI and Xquery Support    |    |_____Evaluation Database    |_____Oracle Coherence    |    |_____Coherence Product Files    |_____JDKs         |_____SUN SDK 1.6.0_29         |_____Oracle JRockit 1.6.0_29 SDK    *Estimated size of installation: 1,276.0 MBEnter [Exit][Previous][Next]> Next<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Installing files..0%          25%          50%          75%          100%[------------|------------|------------|------------][***************************************************]<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Installing JDK....0%          25%          50%          75%          100%[------------|------------|------------|------------][***************************************************]Performing String Substitutions...<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Configuring OCM...0%          25%          50%          75%          100%[------------|------------|------------|------------][***************************************************]Creating Domains...<-------------------- Oracle Installer - WebLogic 10.3.6.0 ------------------->Installation CompleteCongratulations! Installation is complete.Press [Enter] to continue or type [Exit]> [weblogic@pratik ~]$ Note: All the inputs are in Bold 3) Silent mode:              1) Log in to the target Unix system.             2) Create a silent.xml file that defines the configuration settings normally entered by a user during an interactive installation process, such as graphical-mode or console-mode installation. <?xml version="1.0" encoding="UTF-8"?><bea-installer>     <input-fields>        <data-value name="BEAHOME" value="/home/oracle/WLS1036" />        <data-value name="WLS_INSTALL_DIR" value="/home/oracle/WLS1036/wlserver_10.3" />        <data-value name="COMPONENT_PATHS" value="WebLogic Server|Oracle Coherence" />    </input-fields></bea-installer> <!-- Note: This sample silent.xml file is used to install all the components of WebLogic Server and Oracle Coherence. All the values in Bold are the variables. -->               3) Place the silent.xml file in the same directory as where the WebLogic Server Package installer is located.              4) Go to the directory that contains the installation program.              5) Start the installer as follows: [weblogic@pratik WLSInstallers]$ chmod a+x wls1036_linux32.bin[weblogic@pratik WLSInstallers]$ ls -ltrtotal 851516-rwxrwxr-x 1 weblogic weblogic 871091023 Dec 22  2011 wls1036_linux32.bin-rw-rw-r-- 1 weblogic weblogic       331 Jul  5 03:48 silent.xml[weblogic@pratik WLSInstallers]$ cat silent.xml<?xml version="1.0" encoding="UTF-8"?><bea-installer>        <input-fields>                <data-value name="BEAHOME" value="/home/oracle/WLS1036" />                <data-value name="WLS_INSTALL_DIR" value="/home/oracle/WLS1036/wlserver_10.3" />                <data-value name="COMPONENT_PATHS" value="WebLogic Server|Oracle Coherence" />        </input-fields></bea-installer>[weblogic@pratik WLSInstallers]$ ./wls1036_linux32.bin -mode=silenlent.xml -log=/home/oracle/WLSInstallers/install.logExtracting 0%....................................................................................................100%[weblogic@pratik WLSInstallers]$ -log=/home/oracle/WLSInstallers/install.log creates a installation log(install.log) under "/home/oracle/WLSInstallers/", when installation completes you will see the following printed in the log file: 2012-07-05 03:59:36,788 INFO  [WizardController] com.bea.plateng.wizard.silent.tasks.LogTask - The installation was successfull! For other configurable values in silent.xml refer: Values for the Sample silent.xml File for WebLogic Server Important links to Refer: Running the Installation Program in Graphical Mode Running the Installation Program in Console Mode Running the Installation Program in Silent Mode

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  • How is the "change password at next logon" requirement supposed to work with RDP using Network Level Authentication?

    - by NReilingh
    We have a Windows server (2008 R2) with the "Remote Desktop Services" feature installed and no Active Directory domain. Remote desktop is set up to "Allow connections only from computers running Remote Desktop with Network Level Authentication (more secure)". This means that before the remote screen is displayed, the connection is authenticated in a "Windows Security: Enter your credentials" window. The only two role services installed on this server is the RD Session Host and Licensing. When the "User must change password at next logon" checkbox is selected in the properties for a local user on this server, the following displays on a client computer after attempting to connect using the credentials that were last valid: On some other servers using RDP for admin access (but without the Remote Desktop Services role installed), the behavior is different -- the session begins and the user is given a change password prompt on the remote screen. What do I need to do to replicate this behavior on the Remote Desktop Services server?

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  • bash starts replacing the characters on the current line insead of moving over to the next line

    - by Lazer
    I use bash shell $ bash --version GNU bash, version 3.2.25(1)-release (x86_64-redhat-linux-gnu) Copyright (C) 2005 Free Software Foundation, Inc. $ Sometimes, when typing a command on the prompt that is pretty lengthy and does not fit in the current line, instead of displaying the extra characters on the next line, bash starts again on the current line.. replacing the characters that were there and making a mess. what should happen : |---------------------------------------------| | $ my big long command takes a lot of argumen| | s and does not fit in a single line | | | |---------------------------------------------| what happens instead : |---------------------------------------------| | s and does not fit in a single linef argumen| | | | | |---------------------------------------------| The issue is intemittent If I resize my shell window to really small width, normal behaviour is restored Does anyone have any idea what is happening here? $ echo $TERM xterm $ echo $PS1 \[\e[30m\][\t]\[\e[0m\]\[\e]0;\w\a\]\[\e[30m\][\W]$ $

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  • Why does some of the songs in my iTunes library stop prematurely and go to the next song?

    - by joshhunt
    For the couple of weeks a whole bunch of the songs from my iTunes library stop early and skip to the next song (just as if it was at the end of the song). Although the point where it skips varies for each song (for one song it is 2:32, another is 2:46), it will always skip at the same point for each song. A while back I ran BPMer and, although it crashed half way through, it did not appear to corrupt my music the way it is now. A few days ago I backed up my iTunes library and reformatted my hard drive (for a completely unrelated issue) and reinstalled OS X from scratch. The problem was happening before and after the reinstall. This problem also persists when the music is synced across to my iPod touch running 3.0. Listening to the same troublesome songs in my iPod causes them to end prematurely. However, I can listen to the whole song using Quicklook, so the problem must be with my iTunes library or something.

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  • postfix, webmin installed. whats next?

    - by Johnny Craig
    Im trying to get imap running and dont know the problem. i a developer, not a network guy.( our network guy left) we had postfix installed already for outgoing mail on 8 domains. we only had incoming on 1 domain. but that mail server is located on a different ip. now we want incoming on another domain, but we dont want it on another ip, we want it on the same ip as the website itself. I installed dovecot today because my hosting company said i needed it. it seems to run fine. do i need dovecot AND postfix? or are they the same thing? dovecot does not show up anywhere in webmin what i cant seem to figure out how to do is add a user email so i can try to telnet in on port 143. i think i have evrything installed, just need the next step.... sorry for the newb question

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  • How do I change until the next underscore in VIm?

    - by Nathan Long
    If I have this text in vim, and my cursor is at the first character: www.foo.com I know that I can do: cw to change up to the first period, because a word (lowercase w) ends at any punctuation OR white space cW to change the whole address, because a Word (uppercase w) ends only at whitespace Now, what if I have this: stupid_method_name and want to change it to this? awesome_method_name Both cw and cW change the whole thing, but I just want to change the fragment before the underscore. My fallback technique is c/_, meaning 'change until you hit the next underscore in a search,' but for me, that also causes all underscores to be highlighted as search terms, which is slightly annoying. Is there a specifier like w or W that doesn't include underscores?

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  • Will I have internet connection issues next day, if I unplug router at night?

    - by headskracher77
    I did this regularly a few years ago and used to feel like I was 'being punished' by the Interent svc provider for disabling access to my computer, because trying to re-connect the next day became a constant pain. I have the same linksys router, a comcast modem, and hi-speed broadband through their LAN. Question: who or what is at fault for lousy internet connections, slow connections, or no connections: (everybody's tech dept. blames everybody else) The router? 10 year olds, maybe obsolete? The modem? came with the service plan - can connect three devices on a sharedconnection. The ISP: I read they not only even control and completely regulate bandwidth usage, but they also ration it!! (true?) So can I safely 'pull the plug' each night for security or not? thnx

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  • After binding Mac to AD, first login successfully creates mobile account and logs in, after that next login locks AD account

    - by user132844
    Mac os x 10.7 and 10.8 AD Server 2008 R2 Binding using AD Plugin or dsconfigad -add mydomain -username myuser -ou "OU=Computers,OU=Sites,OU=Mysite,DC=mycompany,DC=com" Works fine. First login happens fine. Creates mobile account, no issues noticed. After I logout, the next login attempt fails, and after only shaking one time, their AD account is locked out. opendirectory.log makes a vague mention of account being expired but honestly I don't see much in the logs that pops out as useful. Any help?

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  • Excel Macro To Lookup a User Entered String, and return data from the field next to it

    - by CJG
    On worksheet A, a user is prompted to enter a product number, such as BCI610. On worksheet B somewhere, that value exists. I want excel to lookup/find that value, and then return the data in the cell that is right next to it one column to the right, by copying that data, and pasting it somewhere in worksheet A. If I enter BCI610, it should return the value M332651, because that is the number in the cell immediately to the right of BCI610. I tried VLookup and HLookup, but to no avail... Any suggestions?

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  • Testing a Non-blocking Queue

    - by jsw
    I've ported the non-blocking queue psuedocode here to C#. The code below is meant as a near verbatim copy of the paper. What approach would you take to test the implementation? Note: I'm running in VS2010 so I don't have CHESS support yet. using System.Threading; #pragma warning disable 0420 namespace ConcurrentCollections { class QueueNodePointer<T> { internal QueueNode<T> ptr; internal QueueNodePointer() : this(null) { } internal QueueNodePointer(QueueNode<T> ptr) { this.ptr = ptr; } } class QueueNode<T> { internal T value; internal QueueNodePointer<T> next; internal QueueNode() : this(default(T)) { } internal QueueNode(T value) { this.value = value; this.next = new QueueNodePointer<T>(); } } public class ConcurrentQueue<T> { private volatile int count = 0; private QueueNodePointer<T> qhead = new QueueNodePointer<T>(); private QueueNodePointer<T> qtail = new QueueNodePointer<T>(); public ConcurrentQueue() { var node = new QueueNode<T>(); node.next.ptr = null; this.qhead.ptr = this.qtail.ptr = node; } public int Count { get { return this.count; } } public void Enqueue(T value) { var node = new QueueNode<T>(value); node.next.ptr = null; QueueNodePointer<T> tail; QueueNodePointer<T> next; while (true) { tail = this.qtail; next = tail.ptr.next; if (tail == this.qtail) { if (next.ptr == null) { var newtail = new QueueNodePointer<T>(node); if (Interlocked.CompareExchange(ref tail.ptr.next, newtail, next) == next) { Interlocked.Increment(ref this.count); break; } else { Interlocked.CompareExchange(ref this.qtail, new QueueNodePointer<T>(next.ptr), tail); } } } } Interlocked.CompareExchange(ref this.qtail, new QueueNodePointer<T>(node), tail); } public T Dequeue() { T value; while (true) { var head = this.qhead; var tail = this.qtail; var next = head.ptr.next; if (head == this.qhead) { if (head.ptr == tail.ptr) { if (next.ptr == null) { return default(T); } Interlocked.CompareExchange(ref this.qtail, new QueueNodePointer<T>(next.ptr), tail); } else { value = next.ptr.value; var newhead = new QueueNodePointer<T>(next.ptr); if (Interlocked.CompareExchange(ref this.qhead, newhead, head) == head) { Interlocked.Decrement(ref this.count); break; } } } } return value; } } } #pragma warning restore 0420

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  • printing reverse in singly link list using pointers

    - by theoneabhinav
    i have been trying this code. i think the logic is ok but the program terminates abruptly when the display_rev function is called here is code of display_rev void display_rev(emp_node *head) { emp_node *p=head, *q; while(p->next != NULL) p=p->next; while(p!=head || p==head){ q=head; display_rec(p); while(q->next != p) q=q->next; p=q; } } here is my whole code #include<stdio.h> #include<stdlib.h> #include<ctype.h> #include<string.h> //Declarations=============================================================== typedef struct //employee record { int emp_id; char name[150]; char mob_no[11]; float salary; int proj[5]; struct emp_node *next; } emp_node; emp_node* add_rec(emp_node*); emp_node* create_db(emp_node*); emp_node* search_db(emp_node*, int); emp_node* delete_rec(emp_node*, int); void read_name(emp_node*); void read_mob(emp_node*); void display_db(emp_node*); void display_rec(emp_node*); void display_rev(emp_node*); void modify_rec(emp_node*); void swtch(emp_node*); //=========================================================================== int main() { char ans; emp_node *head = NULL; head = create_db(head); display_db(head); do { swtch(head); printf("\n\n\tDo you want to continue (y/n) : "); getchar(); scanf("%c", &ans); } while (ans == 'y' || ans == 'Y'); return 0; } //Definitions================================================================ emp_node* create_db(emp_node *head) //database creation { int i = 1, no; emp_node *p; printf("Enter number of employees:"); scanf("%d", &no); printf("\n\n"); head = (emp_node *) malloc(sizeof(emp_node)); head = add_rec(head); head->next = NULL; p = head; while (i < no) { p->next = (emp_node *) malloc(sizeof(emp_node)); p = p->next; p = add_rec(p); p->next = NULL; i++; } return head; } emp_node* add_rec(emp_node *p) //new record { int j; printf("\n\tEmployee ID : "); scanf("%d", &(p->emp_id)); printf("\n\tFirst Name:"); read_name(p); printf("\n\tMobile No.:"); read_mob(p); printf("\n\tSalary :"); scanf("%f", &(p->salary)); printf( "\n\tEnter \"1\" for the projects employee is working on, otherwise enter \"0\": \n"); for (j = 0; j < 5; j++) { printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); while (p->proj[j] != 1 && p->proj[j] != 0) { printf("\n\nInvalid entry!! Please re-enter."); printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); } } printf("\n\n\n"); return p; } void read_name(emp_node *p) //validation for name { int j, len; scanf("%s", p->name); len = strlen(p->name); for (j = 0; j < len; j++) { if (!isalpha(p->name[j])) { printf( "\n\n\tInvalid name!!Can contain only characters. Please Re-enter.\n"); printf("\n\tName : "); read_name(p); } } } void read_mob(emp_node *p) //validation for mobile no. { int j; scanf("%s", p->mob_no); while (strlen(p->mob_no) != 10) { printf("\n\nInvalid Mobile No!!Please Re-enter"); printf("\n\n\tMobile No.:"); read_mob(p); } for (j = 0; j < 10; j++) { if (!(48 <= p->mob_no[j] && p->mob_no[j] <= 57)) { printf( "\n\nInvalid Mobile No!!Can contain only digits. Please Re-enter."); printf("\n\n\tMobile No.:"); read_mob(p); } } } void display_db(emp_node *head) //displaying whole database { emp_node *p; p = head; printf("\n\n\t\t****** EMPLOYEE DATABASE ******\n"); printf( "\n=============================================================================="); printf("\n Id.\t Name\t\t Mobile No\t Salary\t Projects\n"); while (p != NULL) { display_rec(p); p = p->next; printf("\n\n\n"); } printf( "\n=============================================================================="); } void swtch(emp_node *head) //function for menu and switch case { int cho, x; emp_node *p; printf("\n\n\t\t****** MENU ******"); printf( "\n\n\t1. insert Record\n\t2. Search Record\n\t3. Modify Record\n\t4. Delete Record\n\t5. Display Reverse\n\t6. Exit"); printf("\n\tWhich operation do you want to perform? "); scanf("%d", &cho); switch (cho) { case 1: p=head; while(p->next != NULL) p=p->next; p->next = (emp_node *) malloc(sizeof(emp_node)); p=p->next; p = add_rec(p); p->next = NULL; display_db(head); break; case 2: printf("\n\n\tEnter employee ID whose record is to be Searched :"); scanf("%d", &x); p = search_db(head, x); if (p == NULL) printf("\n\nRecord not found."); else display_rec(p); break; case 3: printf("\n\n\tEnter employee ID whose record is to be modified :"); scanf("%d", &x); p = search_db(head, x); if (p == NULL) printf("\n\nRecord not found."); else modify_rec(p); display_db(head); break; case 4: printf("\n\n\tEnter employee ID whose record is to be deleted :"); scanf("%d", &x); head = delete_rec(head, x); display_db(head); break; case 5: display_rev(head); case 6: exit(0); default: printf("Invalid Choice!! Please try again."); } } emp_node* search_db(emp_node *head, int id) //search database { emp_node *p = head; while (p != NULL) { if (p->emp_id == id) return p; p = p->next; } return NULL; } void display_rec(emp_node *p) //display a single record { int j; printf("\n %d", p->emp_id); printf("\t %10s", p->name); printf("\t %10s", p->mob_no); printf("\t %05.2f", p->salary); printf("\t "); for (j = 0; j < 5; j++) { if (p->proj[j] == 1) printf(" %d,", j + 1); } } void modify_rec(emp_node *p) //modifying a record { int j, cho; char ch1, edt; do { printf( "\n\t1. Name\n\t2. Email Address\n\t3. Mobile No.\n\t4. Salary\n\t5. Date of birth\n\t6. Projects\n"); printf("Enter your choice : "); scanf("%d", &cho); switch (cho) { case 1: printf("\n\tPrevious name:%s", p->name); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New Name:"); read_name(p); } break; case 2: printf("\n\tPrevious Mobile No. : %s", p->mob_no); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New Mobile No. :"); read_mob(p); } break; case 3: printf("\n\tPrevious salary is : %f", p->salary); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New salary:"); scanf("%f", &(p->salary)); } break; case 4: printf("the employee is currently working on project no. "); for (j = 0; j < 5; j++) { if (p->proj[j] == 1) printf(" %d,", j + 1); } printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf( "\n\tEnter \"1\" for the projects employee is working on : \n"); for (j = 0; j < 5; j++) { printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); while (p->proj[j] != 1) { printf("\n\nInvalid entry!! Please re-enter."); printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); } } } break; default: printf("\n\nInvalid Choice!! Please Try again."); } printf("\n\nDo you want to edit any other fields ?(y/n)"); getchar(); scanf("%c", &edt); } while (edt == 'y' || edt == 'Y'); } emp_node* delete_rec(emp_node *head, int id) //physical deletion of record { emp_node *p = head, *q; if (head->emp_id == id) { head = head->next; free(p); return head; } else { q = p->next; while (q->emp_id != id) { p = p->next; q = q->next; } if (q->next == NULL) p->next = NULL; else p->next = q->next; free(q); return head; } } void display_rev(emp_node *head) { emp_node *p=head, *q; while(p->next != NULL) p=p->next; while(p!=head || p==head){ q=head; display_rec(p); while(q->next != p) q=q->next; p=q; } }

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  • What's next for all of these Microsoft "overlapping" and "enhanced" products ?

    - by indyvoyage
    Recently I attended a road show, organised by MS Gold Partner company in the UK. The products discussed were: SharePoint server (2010 and 2007), Exchange server, Office Communication Server 2007, Exchange hosted services Office Live meeting, Office Communicator, System Center Configuration Manager and Operation Manager, VMware, Windows 7 etc. As Microsoft claims the enhancement in the each product against higher version, I felt that clients are not much interested in all these details. For example Office Communicator, surely they have improved a lot the product and first site all said 'WOW' great product, but nobody wish to pay money for all these extra features. Some argued, they are bogged down by all these increased number of menus. They don't need soft call feature included with mobile call. It apply for all other products as well such as MS office (next what 2 ribbons ?), windows OS and many more. Indeed there must be good features in all these products, but is it worth to spend money and time to update the older system ? Also sometimes these feature will decrease the productivity instead increase it. *So do you think what ever enhancement MS is doing in the products is only for selling purpose, not a real use ?? and I think also keep the developer busy learning the new tools and features. * I am sure some some people here will argue that some people need this sort of features. But I am not talking about NASA or MI5 guys. I am talking of usual businesses and joe public. Any ideas welcome.

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  • How to find the next generated value for a auto-increment column?

    - by Tim Büthe
    I face some trouble with IBM DB2's auto-increment columns. At first, all my columns were defined as GENERATED ALWAYS, but since I had trouble with this when using the "db2 import ..." command, I changed them to GENERATED BY DEFAULT. This is necessary, sinceI need the IDs to be consistent, because other tables reference them. So using "db2 import ... modified by identityignore ..." isn't an option. When I now import data, the IDs are inserted correctly, but everytime I do this, I have to remember to set a new start for the auto-increment column by getting the highest Id+1 and alter the column like this: SELECT MAX(mycolumn)+ 1 FROM mytable; ALTER TABLE mytable ALTER COLUMN mycolumn RESTART WITH <above_result>; If I forget this, an Insert-Statement will fail with an duplicate PK error, since the auto-increment column is the primary key. So my question is: Is there a way to find the next value for an auto-increment column, so I could write Statements that would check, if this value is less then the SELECT MAX and needs to be set? Or: Isn't this whole thing as complicated as it seems to me? Could I somehow import data, preserving the IDs and have the auto-increment column still working as expected?

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  • Can sendmail be configured to discard routed email that has been rejected by the next hop?

    - by Guy Bolton King
    Background: We have a handful of hosts (running sendmail) acting as the MXs for a few domains each. Each domain is handled via the sendmail/cf /etc/mail/virtusertable, with a set of known recipients and a catch-all reject rule. Mail to postmaster on each host is aliased to root, and root is aliased to root+<host>@ourdomain.com. The MX for ourdomain.com is Google Apps, and [email protected] is a simple group that forwards to the admins. Google Apps will reject some emails at the SMTP stage, usually because of illegal attachments (instead of accepting them and filing them as spam). Problem: Given a particular spam email sent to a domain in a virtusertable entry: If the recipient address rejects the mail, then sendmail will try and send a DSN to the sender. If that sender also rejects the mail (because it's a falsified sender, and the MX for the sender rejects the mail as spam), then sendmail sends a DSN to the postmaster. The routing detailed above takes place, and...Google Apps rejects the mail as well. sendmail now gives up with a "savemail panic", and leaves the mail in the queue forever. Our mail queue fills up with garbage Is there any way I can get sendmail to discard messages that have been rejected by the next virtusertable hop (i.e. after step 1 in the Problem description)? Or does anyone have any other solutions to this?

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  • htaccess hacked - i've deleted code and file - what next?

    - by user1762595
    My website was hacked recently. I think i've found the code that was added to the htaccess file, deleted it and then added script to prevent the htaccess file being accessed again. I've also deleted the php file that the hacked code refers to (common.php). What do i need to do next? I'm not a programmer or website developer but i really wanted to see if i could fix the problem myself as i've spent quite a few hours trying and don't give up easily. Here is the hacked code that i deleted; <IfModule mod_rewrite.c> RewriteEngine On RewriteCond %{HTTP_USER_AGENT} (google|yahoo) [OR] RewriteCond %{HTTP_REFERER} (google|yahoo) RewriteCond %{REQUEST_URI} /$ [OR] RewriteCond %{REQUEST_FILENAME} (shtml|html|htm|php|xml|phtml|asp|aspx)$ [NC] RewriteCond %{REQUEST_FILENAME} !common.php RewriteCond /home/httpd/vhosts/bluestardive.com/httpdocs/common.php -f RewriteRule ^.*$ /common.php [L] </IfModule> this code has to stay in the htaccess file as it redirects my url to seo friendly ones or the website errors, but has this code been hacked as well? # Apache search queries statistic module RewriteEngine On AddHandler php5-fastcgi .php .php5 # <contrexx> # <core_modules__alias> RewriteRule ^about-us$ /index.php?page=883 [L,NC] RewriteRule ^ausfluge-und-aktivitaten$ /index.php?page=800 [L,NC] RewriteRule ^bluestardive-news$ /index.php?page=919 [L,NC] RewriteRule ^bookings$ /index.php?page=911 [L,NC] RewriteRule ^diveresort$ /index.php?page=879 [L,NC] RewriteRule ^diving$ /index.php?page=880 [L,NC] RewriteRule ^excursions-and-activities$ /index.php?page=881 [L,NC] RewriteRule ^galerie$ /index.php?section=gallery [L,NC] RewriteRule ^oceannight$ http://www.bluestardive.com/index.php?page=906 [L,NC] RewriteRule ^philosophy$ /index.php?page=846 [L,NC] RewriteRule ^reservation$ /index.php?page=917 [L,NC] RewriteRule ^reservierung$ /index.php?page=918 [L,NC] RewriteRule ^resort$ /index.php?page=798 [L,NC] # </core_modules__alias> # </contrexx> many thanks for any help Claire

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  • How do I find the unix timestamp for the start of the next day in php?

    - by zeckdude
    I have a unix timestamp for the current time. I want to get the unix timestamp for the start of the next day. $current_timestamp = time(); $allowable_start_date = strtotime('+1 day', $current_timestamp); As I am doing it now, I am simply adding 1 whole entire day to the unix timestamp, when instead I would like to figure out how many seconds are left in this current day, and only add that many seconds in order to get the unix timestamp for the very first minute of the next day. What is the best way to go about this?

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  • How can I skip the current item and the next in a Python loop?

    - by uberjumper
    This might be a really dumb question, however I've looked around online, etc. And have not seen a solid answer. Is there a simple way to do something like this? lines = open('something.txt', 'r').readlines() for line in lines: if line == '!': # force iteration forward twice line.next().next() <etc> It's easy to do in C++; just increment the iterator an extra time. Is there an easy way to do that in Python? I would just like to point, out the main purpose of this question is not about "reading files and such" and skipping things. I was more looking for C++ iterator style iteration. Also the new title is kinda dumb, and i dont really think it reflects the nature of my question.

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