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  • Conditionaly strip the last line from a text file

    - by fraXis
    Hello, I posted this yesterday on SO, and I received an answer that works great, but I need to change it around and I don't know how. Here is my original message: I need to strip the last line from a text file. I know how to open and save text files in C#, but how would I strip the last line of the text file? The text file will always be different sizes (some have 80 lines, some have 20). Can someone please show me how to do this? Here is the code that someone gave me to do this (which works fine) //Delete the last line from the file. This line could be 8174, 10000, or anything. This is from SO string tempfile = @"C:\junk_temp.txt"; using (StreamReader reader2 = new StreamReader(newfilename)) { using (StreamWriter writer2 = new StreamWriter(tempfile)) { string line = reader2.ReadLine(); while (!reader2.EndOfStream) { writer2.WriteLine(line); line = reader2.ReadLine(); } // by reading ahead, will not write last line to file } } File.Delete(newfilename); File.Move(tempfile, newfilename); File.Delete(tempfile); How would I change this to only delete the last line of the text file if it is a 4 or 5 digit string (such as 8001 or 99999). If it is anything other than that, such as a %, then I don't want to delete the last line. Can someone please modify the above code to do this for me? Thanks so much.

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  • Most efficient way to write over file after reading

    - by Ryan McClure
    I'm reading in some data from a file, manipulating it, and then overwriting it to the same file. Until now, I've been doing it like so: open (my $inFile, $file) or die "Could not open $file: $!"; $retString .= join ('', <$inFile>); ... close ($inFile); open (my $outFile, $file) or die "Could not open $file: $!"; print $outFile, $retString; close ($inFile); However I realized I can just use the truncate function and open the file for read/write: open (my $inFile, '+<', $file) or die "Could not open $file: $!"; $retString .= join ('', <$inFile>); ... truncate $inFile, 0; print $inFile $retString; close ($inFile); I don't see any examples of this anywhere. It seems to work well, but am I doing it correctly? Is there a better way to do this?

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  • PHP unlink OR rewrite own/current file by itself

    - by Email
    Hi Task: Cut or erase a file after first walk-through. i have an install file called "index.php" which creates another php file. <? /* here some code*/ $fh = fopen($myFile, 'w') or die("can't open file"); $stringData = "<?php \n echo 'hallo, *very very long text*'; \n ?>"; fwrite($fh, $stringData); /*herecut"/ /*here some code */ after the creation of the new file this file is called and i intent to erase the filecreation call since it is very long and only needed on first install. i therefor add to the above code echo 'hallo, *very very long text*'; \n ***$new= file_get_contents('index.php'); \n $findme = 'habanot'; $pos = strpos($new, $findme); if ($pos === false) { $marker='herecut';\n $new=strstr($new,$marker);\n $new='<?php \n /*habanot*/\n'.$new;\n $fh = fopen('index.php', 'w') or die 'cant open file'); $stringData = $new; fwrite($fh, $stringData); fclose($fh);*** ?>"; fwrite($fh, $stringData);]} Isnt there an easier way or a function to modify the current file or even "self destroy" a file after first call? Regards

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  • Unable to write to a text file

    - by chrissygormley
    Hello, I am running some tests and need to write to a file. When I run the test's the open = (file, 'r+') does not write to the file. The test script is below: class GetDetailsIP(TestGet): def runTest(self): self.category = ['PTZ'] try: # This run's and return's a value result = self.client.service.Get(self.category) mylogfile = open("test.txt", "r+") print >>mylogfile, result result = ("".join(mylogfile.readlines()[2])) result = str(result.split(':')[1].lstrip("//").split("/")[0]) mylogfile.close() except suds.WebFault, e: assert False except Exception, e: pass finally: if 'result' in locals(): self.assertEquals(result, self.camera_ip) else: assert False When this test run's, no value has been entered into the text file and a value is returned in the variable result. I havw also tried mylogfile.write(result). If the file does not exist is claim's the file does not exist and doesn't create one. Could this be a permission problem where python is not allowed to create a file? I have made sure that all other read's to this file are closed so I the file should not be locked. Can anyone offer any suggestion why this is happening? Thanks

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  • Write to the second line of a PHP file

    - by Woz
    I have a php file that I want to add an include path to on the second line. I need to open the file and inset a line of code on line 2. I have tried a few techniques none of which are working but I think it has something to do with the text I am trying to write and possibly not escaping character correctly as I am not too familiar with file writing. So here is the file I want to write to: $file = $_SERVER['DOCUMENT_ROOT'].'/'.$domaindir.'/test.php'; Here is the piece of text I want to insert into the file: $dbfile = "include('".$_SERVER['DOCUMENT_ROOT']."/".$domaindir."/web_".$dbname.".inc.php');"; Then what I was doing was a string replace but all it did was bump the "session_start();" bit to a newline! Can anyone point me in the direction of a tutorial that might tell me how to insert this into the second line of my php file or indeed if anyone has any ideas? I can say for sure that the path to the PHP file is fully tested so i know its not that the file is not being open or written to. Any ideas would be much appreciated. Thanks in advance.

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  • Truncating a file while it's being used (Linux)

    - by Hobo
    I have a process that's writing a lot of data to stdout, which I'm redirecting to a log file. I'd like to limit the size of the file by occasionally copying the current file to a new name and truncating it. My usual techniques of truncating a file, like cp /dev/null file don't work, presumably because the process is using it. Is there some way I can truncate the file? Or delete it and somehow associate the process' stdout with a new file? FWIW, it's a third party product that I can't modify to change its logging model. EDIT redirecting over the file seems to have the same issue as the copy above - the file returns to its previous size next time it's written to: ls -l sample.log ; echo > sample.log ; ls -l sample.log ; sleep 10 ; ls -l sample.log -rw-rw-r-- 1 user group 1291999 Jun 11 2009 sample.log -rw-rw-r-- 1 user group 1 Jun 11 2009 sample.log -rw-rw-r-- 1 user group 1292311 Jun 11 2009 sample.log

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  • Making Thunar the default file browser without hiding the desktop icons

    - by Manu
    I really dislike Ubuntu's default file browser, nautilus, and decided to opt for a lighter alternative (Thunar or Xfe). I've used the following script to change the default to Thunar, but now all my icons are gone from the desktop ! The files are still there, in /home/myid/Desktop, but they do not appear. Is there a way to show them, or is this a consequence of removing nautilus as the default file browser ? Can I modify the following script* in order to keep the icons ? *copied from https://help.ubuntu.com/...: ## Originally written by aysiu from the Ubuntu Forums ## This is GPL'ed code ## So improve it and re-release it ## Define portion to make Thunar the default if that appears to be the appropriate action makethunardefault() { ## I went with --no-install-recommends because ## I didn't want to bring in a whole lot of junk, ## and Jaunty installs recommended packages by default. echo -e "\nMaking sure Thunar is installed\n" sudo apt-get update && sudo apt-get install thunar --no-install-recommends ## Does it make sense to change to the directory? ## Or should all the individual commands just reference the full path? echo -e "\nChanging to application launcher directory\n" cd /usr/share/applications echo -e "\nMaking backup directory\n" ## Does it make sense to create an entire backup directory? ## Should each file just be backed up in place? sudo mkdir nonautilusplease echo -e "\nModifying folder handler launcher\n" sudo cp nautilus-folder-handler.desktop nonautilusplease/ ## Here I'm using two separate sed commands ## Is there a way to string them together to have one ## sed command make two replacements in a single file? sudo sed -i -n 's/nautilus --no-desktop/thunar/g' nautilus-folder-handler.desktop sudo sed -i -n 's/TryExec=nautilus/TryExec=thunar/g' nautilus-folder-handler.desktop echo -e "\nModifying browser launcher\n" sudo cp nautilus-browser.desktop nonautilusplease/ sudo sed -i -n 's/nautilus --no-desktop --browser/thunar/g' nautilus-browser.desktop sudo sed -i -n 's/TryExec=nautilus/TryExec=thunar/g' nautilus-browser.desktop echo -e "\nModifying computer icon launcher\n" sudo cp nautilus-computer.desktop nonautilusplease/ sudo sed -i -n 's/nautilus --no-desktop/thunar/g' nautilus-computer.desktop sudo sed -i -n 's/TryExec=nautilus/TryExec=thunar/g' nautilus-computer.desktop echo -e "\nModifying home icon launcher\n" sudo cp nautilus-home.desktop nonautilusplease/ sudo sed -i -n 's/nautilus --no-desktop/thunar/g' nautilus-home.desktop sudo sed -i -n 's/TryExec=nautilus/TryExec=thunar/g' nautilus-home.desktop echo -e "\nModifying general Nautilus launcher\n" sudo cp nautilus.desktop nonautilusplease/ sudo sed -i -n 's/Exec=nautilus/Exec=thunar/g' nautilus.desktop ## This last bit I'm not sure should be included ## See, the only thing that doesn't change to the ## new Thunar default is clicking the files on the desktop, ## because Nautilus is managing the desktop (so technically ## it's not launching a new process when you double-click ## an icon there). ## So this kills the desktop management of icons completely ## Making the desktop pretty useless... would it be better ## to keep Nautilus there instead of nothing? Or go so far ## as to have Xfce manage the desktop in Gnome? echo -e "\nChanging base Nautilus launcher\n" sudo dpkg-divert --divert /usr/bin/nautilus.old --rename /usr/bin/nautilus && sudo ln -s /usr/bin/thunar /usr/bin/nautilus echo -e "\nRemoving Nautilus as desktop manager\n" killall nautilus echo -e "\nThunar is now the default file manager. To return Nautilus to the default, run this script again.\n" } restorenautilusdefault() { echo -e "\nChanging to application launcher directory\n" cd /usr/share/applications echo -e "\nRestoring backup files\n" sudo cp nonautilusplease/nautilus-folder-handler.desktop . sudo cp nonautilusplease/nautilus-browser.desktop . sudo cp nonautilusplease/nautilus-computer.desktop . sudo cp nonautilusplease/nautilus-home.desktop . sudo cp nonautilusplease/nautilus.desktop . echo -e "\nRemoving backup folder\n" sudo rm -r nonautilusplease echo -e "\nRestoring Nautilus launcher\n" sudo rm /usr/bin/nautilus && sudo dpkg-divert --rename --remove /usr/bin/nautilus echo -e "\nMaking Nautilus manage the desktop again\n" nautilus --no-default-window & ## The only change that isn't undone is the installation of Thunar ## Should Thunar be removed? Or just kept in? ## Don't want to load the script with too many questions? } ## Make sure that we exit if any commands do not complete successfully. ## Thanks to nanotube for this little snippet of code from the early ## versions of UbuntuZilla set -o errexit trap 'echo "Previous command did not complete successfully. Exiting."' ERR ## This is the main code ## Is it necessary to put an elseif in here? Or is ## redundant, since the directory pretty much ## either exists or it doesn't? ## Is there a better way to keep track of whether ## the script has been run before? if [[ -e /usr/share/applications/nonautilusplease ]]; then restorenautilusdefault else makethunardefault fi;

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  • Java File URI error ?

    - by Frank
    I need to get a file object online, and I know the file is located at : http://nmjava.com/Dir_App_IDs/Dir_GlassPaneDemo/GlassPaneDemo_2010_04_06_15_00_SNGRGLJAMX If I paste it into my browser's url, I'll be able to download this file, now I'm trying to get it with Java, my code looks like this : String File_Url="http://nmjava.com/Dir_App_IDs/Dir_GlassPaneDemo/GlassPaneDemo_2010_04_06_15_00_SNGRGLJAMX"; Object myObject=Get_Online_File(new URI(File_Url)); Object Get_Online_File(URI File_Uri) throws IOException { return readObject(new ObjectInputStream(new FileInputStream(new File(File_Uri)))); } public static synchronized Object readObject(ObjectInput in) throws IOException { Object o; ...... return o; } But I got the following error message : java.lang.IllegalArgumentException: URI scheme is not "file" at java.io.File.<init>(File.java:366) Why ? How to fix it ? Frank

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  • C# .Net file in use issue

    - by Dan
    I'm having an issue opening files that have recently been closed by the .Net framework. Basically, what happens is the following: -Read in an XML file using DataSet.ReadXml() -Make some changes to the data -Write out the XML file using DataSet.WriteXml() -Copy the XML file to a new location using File.Copy -FTP the file using a custom control This sequence can intermittently fail either after the WriteXML or the File.Copy with a file in use exception. I'm guessing it could be the Windows write cache not flushing right away. Can anyone confirm that this could be causing my issue? Any solutions to suggest? Thanks, Dan

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  • for a single-table inheritance in rails, how do I know the 'type' when creating a record?

    - by Angela
    I have several models which are very similar: Contact_Emails, Contact_Letters, Contact_Calls -- and I think life could be easier making them into a Single Table Inheritance called Contact_Event. However, the way I have it set up now is when something is created for a Contact_Email, I have a dedicated controller that I call and know that I am passing the arguments that are approrpriate. For example, new_contact_email(contact, email). I then have: Emails.find(email.contact_id), etcera, all very specific to that Model. I'm not sure how I extract the class/models to use. For example, I currently have the following because I have separate controllers for each model: def do_event(contact, call_or_email_or_letter) model_name = call_or_email_or_letter.class.name.tableize.singularize link_to( "#{model_name.camelize}", send("new_contact_#{model_name}_path", :contact => contact, :status => 'done', :"#{model_name}" => call_or_email_or_letter ) ) end What I really want is to: link_to("#model_name.camelize}", send("new_contact_event_path(contact,call_or_email_or_letter)"

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  • How to create a new File in Qt

    - by GG
    Hello friends, I am a Qt beginner and just got stuck with the problem. I am looking for a file SomePath/NewDirectoryA/NewFile.kml ( NewFile.kml will be the only file in NewDirectoryA, having this directory just to maintain semantics in the project ). If SomePath/NewDirectoryA/NewFile.kml exists then I will use it in my code and If it doesn't exist then I have to create it. If this File doesn't exist then this directory also doesn't exist in SomePath. So If only I have to create a file I can use QFile and open it in ReadWrite or WriteOnly mode. But the problem is I have to create the file with the directory itself. I tried with QFile with file name SomePath/NewDirectoryA/NewFile.kml but it didn't worked. Please suggest me a way in which I can create a new file( NewFile.kml ) in a new directory( NewDirectorA ) at a given location( SomePath ).

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  • Bash: Check if file was modified since used in script

    - by Thomas Münz
    I need to check in a script if a file was modified since I read it (another application can modify it in between). According to bash manual there is a "-N" test which should report if a file was modified since last read. I tried it in a small script but it seems like it doesn't work. #!/bin/bash file="test.txt" echo "test" > $file cat $file; if [ -N $file ]; then echo "modified since read"; else echo "not modified since read"; fi I also tried an alternative way by touching another file and using if [ "file1" -nt "file2 ]; but this works only on a seconds accuracy which may under rare conditions not be sufficient. Is there any other bash-inbuilt solution for this problem or I do really need to use diff or md5sum?

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  • Perl, deleting an .xml file created and open with IO::File and XML::Writer?

    - by Sho Minamimoto
    So I'm running through a list of things and have code that creates an .xml file with IO::File called $doc, then I make a new writer with XML::Writer(OUTPUT = $doc). More code runs and I build a big xml file with XML::Writer. Then, near the end of the file, I find out if I need this file at all. If I do need it, I just $writer-end(); $doc-close(); but if I don't need it, what should I enter to just delete all data I've stored/saved and move onto the next file? I tried unlink($docpath) (before and after $doc-close()), the file was not deleted.

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  • How do I create the Controller for a Single Table Inheritance in Rails?

    - by Angela
    I am setting up the Single Table Inheritance, using ContactEvent as the Model that ContactEmail, ContactLetter, and ContactCall will all inherit. But I'm stumped on how to create the routing and the controller. For example, let's say I want to create a new ContactEvent with type Email. I would like a way to do the following: new_contact_event_path(contact, email) This would take the instance from Contact model and from Email model. Inside, I would imagine the contact_event_controller would need to know... @contact_event.type = (params[:email]) # get the type based on what was passed in? @contact_event.event_id = (params[:email]) #get the id for the correct class, in this case Email.id Just not sure how this works....

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  • How to concatenate multiple lines of log file into single variable in batch file?

    - by psych
    I have a log file containing a stack trace split over a number of lines. I need to read this file into a batch file and remove all of the lines breaks. As a first step, I tried this: if exist "%log_dir%\Log.log" ( for /F "tokens=*" %%a in ("%log_dir%\Log.log") do @echo %%a ) My expectation was that this would echo out each line of the log file. I was then planning to concatenate these lines together and set that value in a variable. However, this code doesn't do what I would expect. I have tried changing the value of the options for delims and tokens, but the only output I can get is the absolute path to the log file and nothing from the contents of this file. How can I set a variable to be equal to the lines of text in a file with the line breaks removed?

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  • How to know the file type of the file which you are forcing the user to download?

    - by Starx
    I am trying to force the user to download a file. For that my script is: $file = "file\this.zip"; header("Cache-Control: public"); header("Content-Description: File Transfer"); header("Content-Disposition: attachment; filename=$file"); header("Content-Type: application/zip"); //This is what I need header("Content-Transfer-Encoding: binary"); readfile($file); The files I am going to upload my not be .zip all the time so I want to know the content type of the image I am going to receive in $file. How to accomplish this

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  • How can I insert a line at the beginning of a file with Perl's Tie::File?

    - by thebourneid
    I'm trying to insert/add a line 'COMMENT DUMMY' at the beginnig of a file as a first row if /PATTERN/ not found. I know how to do this with OPEN CLOSE function. Probably after reading the file it should look something like this: open F, ">", $fn or die "could not open file: $!"; ; print F "COMMENT DUMMY\n", @array; close F; But I have a need to implement this with the use of the Tie::File function and don't know how. use strict; use warnings; use Tie::File; my $fn = 'test.txt'; tie my @lines, 'Tie::File', $fn or die "could not tie file: $!"; untie @lines;

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  • Create Zip File In Windows and Extract Zip File In Linux

    - by Yan Cheng CHEOK
    I had created a zip file (together with directory) under Windows as follow : package sandbox; import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.util.zip.ZipEntry; import java.util.zip.ZipOutputStream; /** * * @author yan-cheng.cheok */ public class Main { /** * @param args the command line arguments */ public static void main(String[] args) { // These are the files to include in the ZIP file String[] filenames = new String[]{"MyDirectory" + File.separator + "MyFile.txt"}; // Create a buffer for reading the files byte[] buf = new byte[1024]; try { // Create the ZIP file String outFilename = "outfile.zip"; ZipOutputStream out = new ZipOutputStream(new FileOutputStream(outFilename)); // Compress the files for (int i=0; i<filenames.length; i++) { FileInputStream in = new FileInputStream(filenames[i]); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(filenames[i])); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file out.close(); } catch (IOException e) { e.printStackTrace(); } } } The newly created zip file can be extracted without problem under Windows, by using http://www.exampledepot.com/egs/java.util.zip/GetZip.html However, I realize if I extract the newly created zip file under Linux, using http://www.exampledepot.com/egs/java.util.zip/GetZip.html, I will get a file named "MyDirectory\MyFile.txt" instead of MyFile.txt being placed under folder MyDirectory. I try to solve the problem by changing the zip file creation code to String[] filenames = new String[]{"MyDirectory" + "/" + "MyFile.txt"}; But, is this an eligible solution, by hard-coded the seperator? Will it work under Mac OS? (I do not have a Mac to try out)

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  • Automate Windows 7's file sharing and firewall settings

    - by nhinkle
    I am working with my school to customize Windows 7 on some new laptops we are receiving. The laptops come with Windows 7 Professional already installed, and we do not need or want to reimage them. We would however like to customize the installation once it is in place, through a series of scripts. We will also be deploying these scripts to computers which have already been set up. Most of the settings we wish to change can be done easily from the command line or with a registry file. However, there is one thing we keep getting hung up on: networking options. Is there any unattended way to set the Windows 7 networking configuration? We would like to set the following things automatically, which are found under Control Panel > Network and Sharing Center > Advanced sharing settings > Home or Work network: Turn on network discovery Turn on printer and file sharing Turn off public folder sharing Turn on password protected sharing Use user accounts and passwords to connect to other computers We also need to configure the firewall to allow the following exceptions: File and printer sharing Remote assistance Remote desktop Remote scheduled tasks management Remote service management Windows remote management I've looked around, and can't find any way to change these things - I looked into netsh, registry settings, and even used RegMon to watch while I changed the values manually, all to no avail. Google hasn't offered up anything helpful so far. If anyone could provide some insight, I would very much appreciate it. I did find out that much of this is configurable with group policy, but because these computers are in a workgroup, not a domain, I don't know of any way to take advantage of that in an unattended manner.

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  • windows rename command to rename file.a.b to file.b

    - by sakibmoon
    I have a few folders with hundreds of html files. The file name should have been .htm but it is .asp.htm and it does not run. It is plain html file and there is no asp code. So, I tried to rename the files using rename command. I tried like this rename *.asp.htm *.htm But it does not work. After trying a few other combinations I believe rename or ren command can't change the double dot extension. The only change the last extension. So, if I try rename *.asp.htm *.asp.htm I thought nothing would be changed, but, the file name changes from file.asp.htm to file.asp.asp.htm I hope someone would help me with this. Another thing is, can I force apache to run files with .asp.htm extension? Currently it can't run those files. Thanks in advance.

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  • Running Java from a Windows batch file causes the batch file to stop

    - by jjkparker
    When I run Java from a Windows .cmd file (Vista 32-bit here), the Java command causes the batch file to stop executing additional commands. For example, this is a simple test.cmd file: java java This should cause Java to print its help message twice. However when I run it in cmd.exe, I get this: C:\>test C:\>java Usage: java [-options] class [args...] (to execute a class) or java [-options] -jar jarfile [args...] (to execute a jar file) where options include: -client to select the "client" VM -server to select the "server" VM ... C:\> The batch file simply exits when Java exits. What's going on here?

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  • Windows XP SP3 client over NAT to a Windows 2008 R2 SP1 file server disconnection

    - by Patrick Pellegrino
    we just transferred a pilot group from our old(!!) Netware infrastructure to an Microsoft infrastructure. Since then, our users got problems accessing their files. They all experience disconnection from the mapped drives. The file server is access via a WAN connection by a firewall (Sonicwall) between both network and we do NAT. All clients have Windows XP SP3 and the file server is an Windows 2008 R2 SP1. On the file server I got many Event Id 2012. Many post over the Internet suggested a problem between the SMB protocol and NAT. We need a short term fix to continue to transfer users from Netware to Microsoft after what will work to remove the NATing. I found this MS KB http://support.microsoft.com/kb/2444558 that suggested a kind of workaround for Windows 7 clients but I can found anything for Windows XP. Anyone can help me with this ? We don't want to stop the project and do a network job before migrating. Regards. Update: Our few Windows 7 computers doesn't seem to have this issue.

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  • Tip 16 : Open Multiple Documents within Single Application Instance Using C#

    - by StanleyGu
    1.       Using Microsoft Word 2007 as an example, you can open test1.docx and test2.docx at same time. The two documents are opened within single instance of the word application. World application supports command line argument of passing multiple documents. 2.       Again, Using Microsoft Word 2007 as an example, you can open test1.docx first and then test2.docx. The two documents are opened within single instance of the Word application. Word application supports Multiple Document Interface (MDI). 3.       Using Notepad as an example, you receive error message of “The filename, directory name, or volume label syntax is incorrect” if you want to open two documents at the same time. Notepad does not support command line argument of passing multiple documents 4.       Again, using Notepad as an example, you can open test1.txt first and then test2.txt. The two documents are opened to two different instances of Notepad application. Notepad does not support Multiple Document Interface (MDI). 5.       In conclusion, there is nothing you can do trying to rely on System.Diagnostics.Process class to open multiple documents within a single instance of an application because it is controlled by the application itself. The best approach is to read any developer or user guide of the application and make sure: 1. The application supports Multiple Document Interface (MDI) 2. The application provides command line argument of passing multiple documents. Then, you can use Process class and the command line argument syntax to open multiple documents for the application.  

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  • "Windows cannot find" file when opening Excel spreadsheet

    - by DanH
    For all of my Excel spreadsheets when I attempt to open them (by double-clicking in explorer) I get the message "Windows cannot find C:...". The files are there, and are valid zip files as seen by 7-Zip. There are no apparent lock files in the directories. I did just install Norton-360 over the weekend (replacing Kasperski), but the Norton log shows no events related to Excel. However, while installing Norton I did reboot with some Excel files open. Presumably something is hosed in my Excel configuration but I don't know what. Update (Before actually posting) -- I found an article that suggested turning off Advanced Option "Ignore other applications that use DDE", then doing excel.exe /unregister followed by excel.exe /register. I tried this but I suspect that the two Excel calls were ignored (Excel opened, but no obvious change). With that option off the spreadsheets load OK, but not with it on. And, curiously, spreadsheets load OK with the option on or off if I open Excel first and then open the spreadsheet in it. Does anyone have any idea what effect leaving that option off will have? Update 2 -- I tried running the "repair" option. It said it corrected a couple of config things (without saying what they were), but I still get a failure if I double-click an Excel file with the "Ignore other applications..." option checked. Update 3 -- I managed to fix this problem, but failed at the time to come back and say what I did, and now I can't remember for sure. But I think it had something to do with "Options"/"Save" and some of the values there. Something to do with AutoRecover, perhaps. (Possibly there was a file in recovery and I had to specify "Disable AutoRecover for this workbook" to let bring-up get past it. Or perhaps the AutoRecover file location was hosed.) Anyway, if it happens to someone else, and you find the fix, post it below and I'll mark it answered.

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  • Setup.exe called from a batch file crashes with error 0x0000006

    - by Alex
    We're going to be installing some new software on pretty much all of our computers and I'm trying to setup a GPO to do it. We're running a Windows Server 2008 R2 domain controller and all of our machines are Windows 7. The GPO calls the following script which sits on a network share on our file server. The script it self calls an executable that sits on another network share on another server. The executable will imediatelly crash with an error 0x0000006. The event log just says this: Windows cannot access the file for one of the following reasons: there is a problem with the network connection, the disk that the file is stored on, or the storage drivers installed on this computer; or the disk is missing. Windows closed the program Setup.exe because of this error. Here's the script (which is stored on \\WIN2K8R2-F-01\Remote Applications): @ECHO OFF IF DEFINED ProgramFiles(x86) ( ECHO DEBUG: 64-bit platform SET _path="C:\Program Files (x86)\Canam" ) ELSE ( ECHO DEBUG: 32-bit platform SET _path="C:\Program Files\Canam" ) IF NOT EXIST %_path% ( ECHO DEBUG: Folder does not exist PUSHD \\WIN2K8R2-PSA-01\PSA Data\Client START "" "Setup.exe" "/q" POPD ) ELSE ( ECHO DEBUG: Folder exists ) Running the script manually as administrator also results in the same error. Setting up a shortcut with the same target and parameters works perfectly. Manually calling the executable also works. Not sure if it matters, but the installer is based on dotNETInstaller. I don't know what version though. I'd appreciate any suggestions on fixing this. Thanks in advance! UPDATE I highly doubt this matters, but the network share that the script is hosted in is a shared drive, while the network share the script references for the executable is a shared folder. Also, both shares have Domain Computers listed with full access for the sharing and security tabs. And PUSHD works without wrapping the path in quotes.

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