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  • perl dancer: passing database info to template

    - by Bubnoff
    Following Dancer tutorial here: http://search.cpan.org/dist/Dancer/lib/Dancer/Tutorial.pod I'm using my own sqlite3 database with this schema CREATE TABLE if not exists location (location_code TEXT PRIMARY KEY, name TEXT, stations INTEGER); CREATE TABLE if not exists session (id INTEGER PRIMARY KEY, date TEXT, sessions INTEGER, location_code TEXT, FOREIGN KEY(location_code) REFERENCES location(location_code)); My dancer code ( helloWorld.pm ) for the database: package helloWorld; use Dancer; use DBI; use File::Spec; use File::Slurp; use Template; our $VERSION = '0.1'; set 'template' => 'template_toolkit'; set 'logger' => 'console'; my $base_dir = qq(/home/automation/scripts/Area51/perl/dancer); # database crap sub connect_db { my $db = qw(/home/automation/scripts/Area51/perl/dancer/sessions.sqlite); my $dbh = DBI->connect("dbi:SQLite:dbname=$db", "", "", { RaiseError => 1, AutoCommit => 1 }); return $dbh; } sub init_db { my $db = connect_db(); my $file = qq($base_dir/schema.sql); my $schema = read_file($file); $db->do($schema) or die $db->errstr; } get '/' => sub { my $branch_code = qq(BPT); my $dbh = connect_db(); my $sql = q(SELECT * FROM session); my $sth = $dbh->prepare($sql) or die $dbh->errstr; $sth->execute or die $dbh->errstr; my $key_field = q(id); template 'show_entries.tt', { 'branch' => $branch_code, 'data' => $sth->fetchall_hashref($key_field), }; }; init_db(); true; Tried the example template on the site, doesn't work. <% FOREACH id IN data.keys.nsort %> <li>Date is: <% data.$id.sessions %> </li> <% END %> Produces page but with no data. How do I troubleshoot this as no clues come up in the console/cli? Thanks Bubnoff

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  • NHibernate QueryOver Issue

    - by Yoann. B
    Hi, I've a query that works well with the NH 3.0 LINQ Provider but not with the QueryOver API. I got a "could not resolve property : Profile.Customer.CustomerId" Exception var query = Session.QueryOver<Suggest>() .Where(p => p.Profile.Customer.CustomerId == customerId) .And(p => p.Job.Customer.CustomerId != customerId); var total = query.RowCount(); Any help ? Thanks.

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  • Handing over FaceBook SessionKey from iPhone to PHP

    - by Stefan Mayr
    Hi! Users authenticate normally on my iPhone app, and the permission for publish_stream is requested correctly. When the user want to post something on his wall, the text is transmitted to my backend and the backend posts it (with the transmitted session key) to the users facebook wall. The first post is always possible but at the second, the response is: "The user hasn't authorized the application to perform this action" But I was already able to post some seconds ago. What is wrong? Best Steve

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  • need to refresh web page after clicking close on pop-up window

    - by Brad
    I have a pop-up window a user logs into, once they are logged in successful, I have a message that has a link to close the window. But I want it to not only close that pop up window, but I want it to refresh the webpage the pop-up window was clicked on. So the page can refresh to see that there is a valid login session for that user. Is this possible w/ jQuery?

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  • How to programmly download image from website ?

    - by MemoryLeak
    I need to download images from a website, and I have the login name and password, but if i just use URL to download the image, it will throw a exception: there is no value in session. I think I need to login the website before I can programmingly download the image. Do you have any solutions ? Thanks in advance !

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  • Configuring FluentNHibernate to use multiple databases in .net

    - by Miral
    I am using c#.net and we are using nhibernate. It was fine until i was connecting to a single database. Now in the same project i am suppose to use multiple database, how can this be achived. Configuration of the nhibernate is lies in web/app.config file. How to specify multiple connection string over there and how to create multiple session factories.

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  • MySQL best usage in Tomcat?

    - by mabuzer
    Which one is better way of using MySQL in Tomcat : A) assign a DB connection for user as long as it's session is valid. [OR] B) open connection to DB, on every request come to server and when it's done close that. ?

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  • Compare term to current date in HQL (with .Net)

    - by Jan-Frederik Carl
    Hello, I want to compare a column value to the current date, using HQL. I tried IQuery someQuery = session.CreateQuery(String.Format( @"Select s.Id From InventoryProductStateItem s where s.ValidFrom < current_date()")); This throws the exception "Incorrect syntax near keyword current_date()" Can someone help me?

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  • PHP cannot connect to MySQL

    - by yogal
    Hello, I recently installed Apache 2 + PHP 5.3.1 + MySQL 5.1.44 on my Windows 7 64bit machine following this guide: http://sleeplessgeek.blogspot.com/2010/01/setting-up-apache-php-mysql-phpmyadmin.html It all went fine, php is working great (even with XDebug) but I cannot connect to mysql server. A simple script I wrote to test connection (yes, root has no pass): $username = "root"; $password = ""; $database = "test"; $hostname = "localhost"; $conn = mysql_connect($hostname, $username, $password) or die("Unable to connect to MySQL Database!!"); It prints this error after 60sec of timeout: Warning: mysql_connect() [function.mysql-connect]: A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond. I can connect to mysql using cmdmysql -h localhost -u root Services are working properly. There also seems to be a problem with PhpMyAdmin (using 3.2.5). As soon as I type user and pass the page loads and turns blank (content-lenght in headers is 0 but status code is 302 Found). Looks like something wrong with cookies (my auth method). I hope someone has a clue, it has to be something dumb simple I missed. Thanks in advance.

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  • Passing Info From One View to Another

    - by 01010011
    EDIT 1. The results of a query from my database are displayed on my view page. Next to each unique result is a button: // first_view.php <?php echo form_open('controller/method'); ?> <?php foreach($results_found as $item): ?> <p><?php echo $item->name ?></p> <p><?php form_submit('buy','Buy This'); ?></p> When a user clicks on one of these buttons (lets say button 4), I would like to display the user's choice from the array onto another view. I've tried using this: // first_view.php <?php echo $this->session->set_userdata('choice',$item); ?> immediately before // first_view.php <?php echo form_close(); ?> thinking that the user's final choice would be stored there so I can display it on another view like this: // second_controller.php $c = $this->session->userdata('choice'); // second_view.php echo 'Your Choose: '. $c; However, what actually displays is the last result displayed on first_view.php, not what the user choose. My question is, if the user clicked on button 4, how do I get that particular choice displayed onto another view? END OF EDIT1 ORIGINAL QUESTION My view page (CodeIgniter) displays the contents of an array in the form of several links. If a user clicks on a link, I want the user to be taken to another view page (via a controller) that gives more information concerning that particular link (which is stored in that particular position in the array) My question is, how do I access and display the contents of that particular location within the array on the second view file without getting a "Undefined variable error" on the second view? Here is what I am trying to do in code form // my_controller.php $array_name['variable_name']; $this->load->view('first_view.php'); // first_view.php <?php foreach($variable_name as $vn): ?> <?php echo anchor('controller_name' $vn->info ?> // if user clicks on 3rd link <?php endforeach ?> // I want to beable to access // index 2 of the array in the // second view file so I can // display more info // second_view.php <?php $vn[2]->info ?>

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  • Login error in phpMyAdmin, problem setting auth_type in config.inc.php

    - by sergiom
    I'm having a problem accessing phpMyAdmin. A few weeks ago I did succeed configuring it for auth_type = 'cookie', but I still receive an error stating that I should have to set blowfish_secret. That was strange because it was set. So I changed auth_type from cookie to http, but it didn't work. I changed it back to cookie, but it doesn't work anymore. this is the error. phpMyAdmin - Error Cannot start session without errors, please check errors given in your PHP and/or webserver log file and configure your PHP installation properly. this is my C:\wamp\apps\phpmyadmin3.2.0.1\config.inc.php <?php /* Servers configuration */ $i = 0; /* Server: localhost [1] */ $i++; $cfg['Servers'][$i]['verbose'] = 'localhost'; $cfg['Servers'][$i]['host'] = 'localhost'; $cfg['Servers'][$i]['port'] = ''; $cfg['Servers'][$i]['socket'] = ''; $cfg['Servers'][$i]['connect_type'] = 'tcp'; $cfg['Servers'][$i]['extension'] = 'mysqli'; $cfg['Servers'][$i]['auth_type'] = 'cookie'; $cfg['Servers'][$i]['user'] = ''; $cfg['Servers'][$i]['password'] = ''; $cfg['Servers'][$i]['AllowNoPassword'] = false; $cfg['Servers'][$i]['blowfish_secret'] = 'this is my passphrase'; /* End of servers configuration */ $cfg['DefaultLang'] = 'en-utf-8'; $cfg['ServerDefault'] = 1; $cfg['UploadDir'] = ''; $cfg['SaveDir'] = ''; ?> I changed the blowfish_secret, since I don't remember the old one, and I deleted the cookies in my browser and restartd all wamp services and the browser. After I enter username and password in the login page I get the error. I've tried searching into the log files, but I'm a newbie and I'm not sure I've searched the right ones. I'm using Wamp server 2.0 that has Apache Version : 2.2.11 PHP Version : 5.3.0 MySQL Version : 5.1.36 phpmyadmin : 3.2.0.1

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  • Debug HTTPS errors

    - by Murkin
    Hello everyone, When accessing my site, the SSL session is successful while the page loads. A few seconds after the page loaded FireFox shows that SSL is no longer available. I am guessing its some script (all I have is Google Analytics and Facebook). How can I see what caused FireFox (or IE/Chrome) to drop the SSL and why ?

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  • Why AVCaptureSession output a wrong orientation?

    - by Peter
    Hey guys, So, I followed Apple's instructions to capture video session using AVCaptureSession: http://developer.apple.com/iphone/library/qa/qa2010/qa1702.html. One problem I'm facing is that even though the orientation of the camera / iphone device is vertical (and the AVCaptureVideoPreviewLayer shows a vertical camera stream), the output image seems to be in the landscape mode. I checked the width and height of imageBuffer inside imageFromSampleBuffer: of the sample code, and I got 640px and 480px respectively. Does anyone know why this's the case? Thanks!

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  • I cannot access Windows Update at all

    - by Cardinal fang
    I have been unable to access the Windows update site for a couple of weeks now. I just get a message saying "Internet Explorer cannot display the webpage" and saying I have connection problems. Same thing is replicated with any other Microsoft site I try to access. The Automatic Updates also do not work. I can access every other wesbite I've surfed to. I've tried Googling the problem and based on what other site have suggested I have cleared my cache and temp files. I've scanning my hard drive with my antivirus in case I have a virus (nada). I've tried turning off my firewall and anti-virus (I run Zone Alarm). I've downloaded SpyBot and scanned my drive with that in case something was missed by Zone Alarm (again nada). Based on suggestions from the smart cookies on the Bad Science forum, I've used nslookup to check my translation isn't wonky (got all the info they said I should get). I've also tried navigating there directly using the IP address I was given (nope). I normally access the internet through a 3 mobile broadband connection, but have also tried connecting using a mate's wi-fi connection in case it was something on my mobile modem interferring. I run Windows XP SP3 with Internet Explorer 7 and Zone Alarm Internet Security Suite as my anti-virus/ firewall. Any suggestions?

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  • SQLAlchemy unsupported type error - and table design issues?

    - by Az
    Hi there, back again with some more SQLAlchemy shenanigans. Let me step through this. My table is now set up as so: engine = create_engine('sqlite:///:memory:', echo=False) metadata = MetaData() students_table = Table('studs', metadata, Column('sid', Integer, primary_key=True), Column('name', String), Column('preferences', Integer), Column('allocated_rank', Integer), Column('allocated_project', Integer) ) metadata.create_all(engine) mapper(Student, students_table) Fairly simple, and for the most part I've been enjoying the ability to query almost any bit of information I want provided I avoid the error cases below. The class it is mapped from is: class Student(object): def __init__(self, sid, name): self.sid = sid self.name = name self.preferences = collections.defaultdict(set) self.allocated_project = None self.allocated_rank = 0 def __repr__(self): return str(self) def __str__(self): return "%s %s" %(self.sid, self.name) Explanation: preferences is basically a set of all the projects the student would prefer to be assigned. When the allocation algorithm kicks in, a student's allocated_project emerges from this preference set. Now if I try to do this: for student in students.itervalues(): session.add(student) session.commit() It throws two errors, one for the allocated_project column (seen below) and a similar error for the preferences column: sqlalchemy.exc.InterfaceError: (InterfaceError) Error binding parameter 4 - probably unsupported type. u'INSERT INTO studs (sid, name, allocated_rank, allocated_project) VALUES (?, ?, ?, ?, ?, ?, ?)' [1101, 'Muffett,M.', 1, 888 Human-spider relationships (Supervisor id: 123)] If I go back into my code I find that, when I'm copying the preferences from the given text files, it actually refers to the Project class which is mapped to a dictionary, using the unique project id's (pid) as keys. Thus, as I iterate through each student via their rank and to the preferences set, it adds not a project id, but the reference to the project id from the projects dictionary. students[sid].preferences[int(rank)].add(projects[int(pid)]) Now this is very useful to me since I can find out all I want to about a student's preferred projects without having to run another check to pull up information about the project id. The form you see in the error has the object print information passed as: return "%s %s (Supervisor id: %s)" %(self.proj_id, self.proj_name, self.proj_sup) My questions are: I'm trying to store an object in a database field aren't I? Would the correct way then, be copying the project information (project id, name, etc) into its own table, referenced by the unique project id? That way I can just have the project id field for one of the student tables just be an integer id and when I need more information, just join the tables? So and so forth for other tables? If the above makes sense, then how does one maintain the relationship with a column of information in one table which is a key index on another table? Does this boil down into a database design problem? Are there any other elegant ways of accomplishing this? Apologies if this is a very long-winded question. It's rather crucial for me to solve this, so I've tried to explain as much as I can, whilst attempting to show that I'm trying (key word here sadly) to understand what could be going wrong.

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  • Frequent error in Oracle ORA-04068: existing state of packages has been discarded

    - by martilyo
    Hi, We're getting this error once a day on a script that runs every two hours, but at different times of the day. ERROR at line 1: ORA-04068: existing state of packages has been discarded ORA-04061: existing state of package body "PACKAGE.NAME" has been invalidated ORA-06508: PL/SQL: could not find program unit being called: "PACKAGE.NAME" ORA-06512: at line 1 Could someone list what conditions can cause this error so that we could investigate? Thanks. UPDATE: Would executing 'ALTER SESSION CLOSE DATABASE LINK DBLINK' invalidate a state of the package?

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  • C# VSTO Outlook 2007: How to show contact by EntryID

    - by DjCzermino
    How to open Contact using C# VSTO Outlook 2007 addin by EntryID. Now I am foreaching all contacts in Contact Folder: string entryid = ... Outlook.Application outlookApp = new Outlook.Application(); Outlook.MAPIFolder fldContacts = outlookApp.Session.GetDefaultFolder(Outlook.OlDefaultFolders.olFolderContacts) as Outlook.MAPIFolder; foreach (Outlook._ContactItem contact in fldContacts.Items) { if (contact.EntryID==entryid) { contact.Display(false); break; } } but this is not effective code for many contacts in Contact Folder

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  • Rails: Extracting the raw url from the request

    - by pankajbhageria
    I am working with Rails 2.2. The required behaviour is as follows: I have a link(with a ajax link embedded) xyz.com/admin#page1 When I go to the above page, I should be redirected to the login page, if I am not logged in. After I log in, I should be taken back to xyz.com/admin#page1 For this I need to store the url in session when I visit any page. The problem is that when I do request.uri, I get xyz.com/admin But I want to store xyz.com/admin#page1 Regards, Pankaj

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  • jsf: propagate the viewscope to new popup window

    - by rahul_d_m
    in jsf2.0 is it possible to propagate the viewscope to new popup window, so that if new url is opened as model popup it should get the value from same managed bean. i tried by passing parent page's javax.faces.ViewState as url parameter to model popup page but getting viewexpired exception with this. i dont want to use session scope, is there any other solution?

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  • Facebook Connect for iPhone persistant login

    - by Sam
    Hi, I have implemented Facebook Connect in my iPhone project and it is working great. The only problem I have is that every time the user closes the app, the next time they load it they have to re-enter their username and password to login even if the 'keep me logged in' box is checked. My question is is there a way to save the user's session so next time the app is launched they are automatically logged into Facebook Connect without any prompts? Thanks!

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  • C# Select clause returns system exception instead of relevant object

    - by Kashif
    I am trying to use the select clause to pick out an object which matches a specified name field from a database query as follows: objectQuery = from obj in objectList where obj.Equals(objectName) select obj; In the results view of my query, I get: base {System.SystemException} = {"Boolean Equals(System.Object)"} Where I should be expecting something like a Car, Make, or Model Would someone please explain what I am doing wrong here? The method in question can be seen here: // this function searches the database's table for a single object that matches the 'Name' property with 'objectName' public static T Read<T>(string objectName) where T : IEquatable<T> { using (ISession session = NHibernateHelper.OpenSession()) { IQueryable<T> objectList = session.Query<T>(); // pull (query) all the objects from the table in the database int count = objectList.Count(); // return the number of objects in the table // alternative: int count = makeList.Count<T>(); IQueryable<T> objectQuery = null; // create a reference for our queryable list of objects T foundObject = default(T); // create an object reference for our found object if (count > 0) { // give me all objects that have a name that matches 'objectName' and store them in 'objectQuery' objectQuery = from obj in objectList where obj.Equals(objectName) select obj; // make sure that 'objectQuery' has only one object in it try { foundObject = (T)objectQuery.Single(); } catch { return default(T); } // output some information to the console (output screen) Console.WriteLine("Read Make: " + foundObject.ToString()); } // pass the reference of the found object on to whoever asked for it return foundObject; } } Note that I am using the interface "IQuatable<T>" in my method descriptor. An example of the classes I am trying to pull from the database is: public class Make: IEquatable<Make> { public virtual int Id { get; set; } public virtual string Name { get; set; } public virtual IList<Model> Models { get; set; } public Make() { // this public no-argument constructor is required for NHibernate } public Make(string makeName) { this.Name = makeName; } public override string ToString() { return Name; } // Implementation of IEquatable<T> interface public virtual bool Equals(Make make) { if (this.Id == make.Id) { return true; } else { return false; } } // Implementation of IEquatable<T> interface public virtual bool Equals(String name) { if (this.Name.Equals(name)) { return true; } else { return false; } } } And the interface is described simply as: public interface IEquatable<T> { bool Equals(T obj); }

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  • What is the best way to create a wizard for web?

    - by Yan
    I want to create a wizard that includes a few steps, that in the final steps we need to include all the steps and save to the data base. What is the best design to do this ? Is there an implementation for jquery ? Do I need to save the steps in session till the final save ?

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  • xauth, ssh and missing home directory

    - by flolo
    We have several servers, and normaly everything works fine, except now... we get a new aircondition installed. This takes 36 hours and for this time almost all servers got shutdown, only 2 remaining servers run for the most important tasks (i.e. accepting incoming email, delivering some important websites, login-server). Everybody was informed that when they need appropiate data from the homedirs they should fetch it before take down. Long story short: Someone realized that he have run a certain program on one of the servers. No Problem, he can remote login into our login server and run the programm there without home directory (binaries are local and necessary information can be copied to the /tmp). That works like a charm until... ... the user needs to run a GUI programm. I find no easy way to make it running, usually ssh -Y honk@loginserver is enough but now the homedirectory is missing and ssh is not able to copy the cookies into ~/.Xauthority (as the file server with the home directories is down). Paranoid as all systemadmins all X-Server just listen locally not on tcp ports, so no remote X connection possible SSH config is waterproof - i.e. no way to set environment variables. My Problem is, that the generated proxy MIT cookie from ssh get lost as the .Xauthority doesnt exist. If I could retrieve it somehow I could reenter it a .Xauthority in /tmp. The only other option (besides changing the config) which came to my mind is, makeing a tunnel (netcat, or better ssh) from the remote host to the loginserver and copy the cookie manually (not sure if it the tcp-unix domain socket stuff works as expected). Any good suggestions (for the future - now our servers are already up)?

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  • How to get the EJB listening port?

    - by Alotor
    I'm currently developing a library for monitoring calls to several remote services (WebServices, EJBs...). One of the parameters that i would like to register is the port from which a EJB is called (a Stateless Session Bean invoked like a remote object) There is any standarised way of getting the port? Or should I inspect the JNDI tree for this kind of information? I'm using the EJB 2.1 spec, but it's also posible for me to use EJB 3

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  • Hibernate SessionFactory: how to configure JNDI in Tomcat?

    - by EugeneP
    that's how the session factory should be gotten: protected SessionFactory getSessionFactory() { try { return (SessionFactory) new InitialContext() .lookup("SessionFactory"); } catch (Exception e) { } } Please provide a simple solution for Tomcat6 to be able to get SessionFactory thru simple jndi lookup in Java code. What should be written in what file on the side of Tomcat ?

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