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  • Set focus on a component with Apache Wicket?

    - by vagabond
    How do you set focus on a component with Apache Wicket? Searching leads to very little information, mostly on setting the default field. I do not want to set a default field, rather I am looking to set focus when, for example, a specific radio button is selected.

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  • Tweet's xml format

    - by Anand Kulkarni
    I get ' top tweets ' from twitter as an RSS feed in xml format . There is a guid field in that xml format. There is a long 11 digit number at the end of guid field , is it unique for every tweet ?

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  • Adding SPFieldLookup to a list programmatically ?

    - by Mina Samy
    Hi all I added a SPFieldLookup field to a list programmatically. when I checked my list view I found that the lookup field is as if I added it from the user inerface without specifying that it is linked to item. is there a method to force the lookupfield to be linked to item programmatically ? thanks

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  • I need to get form data from multiple forms on one page using $_POST

    - by CDeanMartin
    My project is a menu that displays daily specials at a cafe. The Pointy Haired Boss(PHB) needs to add/remove items from the menu on a daily basis, so I stored all dishes with MySQL, and created a page which will load all menu items as buttons. When clicked, the button will UPDATE the item, turning it on or off. I need form data to detect which button was pressed, so my query knows which $menuItem to UPDATE. That is the purpose of the hidden fields. <html><head></head> <body> <html><head></head> <body> <?php include("getElement.php"); $keys = array_keys($_POST); echo $keys[0]; echo $keys[1]; //if(isset($_POST["menuItem"])){ //toggleItem($_POST["menuItem"]); //echo print_r(array_keys($_POST));} ?> <form name="b" action="scratchpad.php" method="post" > <input type="hidden" name="b" value="Cajun Gumbo"/> <input type="submit" style="color:blue" value="Cajun Gumbo" /> </form> <form name="a" action="scratchpad.php" method="post" > <input type="hidden" name="a" value="Guacomole Burger"/> <input type="submit" style="color:blue" value="Guacomole Burger" /> </form> </body> </html> Can I get $_POST to identify which button was pressed?

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  • How can I alter a temp table?

    - by William
    I need to create a temp table, than add a new int NOT NULL AUTO_INCREMENT field to it so I can use the new field as a row number. Whats wrong with my query? SELECT post, newid FROM ((SELECT post`test_posts`) temp ALTER TABLE temp ADD COLUMN newid int NOT NULL AUTO_INCREMENT)

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  • How can I display multiple django modelformset forms together?

    - by JT
    I have a problem with needing to provide multiple model backed forms on the same page. I understand how to do this with single forms, i.e. just create both the forms call them something different then use the appropriate names in the template. Now how exactly do you expand that solution to work with modelformsets? The wrinkle, of course, is that each 'form' must be rendered together in the appropriate fieldset. For example I want my template to produce something like this: <fieldset> <label for="id_base-0-desc">Home Base Description:</label> <input id="id_base-0-desc" type="text" name="base-0-desc" maxlength="100" /> <label for="id_likes-0-icecream">Want ice cream?</label> <input type="checkbox" name="likes-0-icecream" id="id_likes-0-icecream" /> </fieldset> <fieldset> <label for="id_base-1-desc">Home Base Description:</label> <input id="id_base-1-desc" type="text" name="base-1-desc" maxlength="100" /> <label for="id_likes-1-icecream">Want ice cream?</label> <input type="checkbox" name="likes-1-icecream" id="id_likes-1-icecream" /> </fieldset> I am using a loop like this to process the results for base_form, likes_form in map(None, base_forms, likes_forms): which works as I'd expect (I'm using map because the # of forms can be different). The problem is that I can't figure out a way to do the same thing with the templating engine. The system does work if I layout all the base models together then all the likes models after wards, but it doesn't meet the layout requirements.

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  • Javascript click function not working

    - by Nabe
    I need to null the value in text box on click, currently I have written a code as such <div class="keyword_non"> <h1>Keywords : <a class="someClass question_off" title="Keywords "></a></h1> <h2><input type="text" name="kw1" value="one" /></h2> <h2><input type="text" name="kw2" value="two" /></h2> <h2><input type="text" name="kw3" value="three" /></h2> <h2><input type="text" name="kw4" value="four" /></h2> </div> <script type="text/javascript" src="/functions/javascript/custom/non_profit_edit.js"></script> <script type="text/javascript" src="/functions/javascript/jquery-1.7.1.min.js"></script> <script type="text/javascript" src="/functions/javascript/custom/jquery-ui-1.8.7.custom.min.js"></script> Inside non_profit_edit.js i have written as such $(document).ready(function(){ $(".kw1").click(function() { $(".kw1").val(" "); }); $(".kw2").click(function() { $(".kw2").val(" "); }); $(".kw3").click(function() { $(".kw3").val(" "); }); $(".kw4").click(function() { $(".kw4").val(" "); }); }); But write now its not working properly... Is this any browser issues or error in code..

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  • how to conditional display a control in asp wizard based on the radiobutton click in a particular st

    - by Pramod
    Hi, I've been stuck with this problem where there are 3 steps in an asp wizard control. The first step has a radiobutton (yes and no) and based on the radio button input chosen by the user, i would need to hide or show a label in the second wizardstep. Example: Step 1: Choose 1 among the two options: Yes No (radStep1) Step 2: if the radiobutton option in the previous step was yes.. then display a label(lblStep2) in this step.. Else hide the label. I've been handling this through the jquery as i want the functionality in the aspx page itself... The jquery code goes like this... $("#<%=radStep1.ClientID %> input").click(function() { if($("#<%= radStep1.ClientID %> input").index(this) == 0) { $("#<%=lblStep2.ClientID %>").show(); } else if($("#<%= radStep1.ClientID %> input").index(this) == 1) { $("#<%=lblStep2.ClientID %>").hide(); } However, in both the cases, the label is getting displayed.. Could you please help me out if there is anything that i'm missing? I'm guessing that the label is getting hidden at first and then getting shown again once i click on the next button... Thanks a ton in advance....

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  • Insert statement with where clause.

    - by debraj
    I had a table with unique Date_t1 date type field, but in Table description field is not mentioned as unique, now while inserting new row i need to validate if date exist or not, If already exist i should not allow to make changes on that row, neither a new row needs to be created, Any idea how to resolve this problem in efficient way,

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  • uploading image & getting back from database

    - by Anup Prakash
    Putting a set of code which is pushing image to database and fetching back from database: <!-- <?php error_reporting(0); // Connect to database $errmsg = ""; if (! @mysql_connect("localhost","root","")) { $errmsg = "Cannot connect to database"; } @mysql_select_db("test"); $q = <<<CREATE create table image ( pid int primary key not null auto_increment, title text, imgdata longblob, friend text) CREATE; @mysql_query($q); // Insert any new image into database if (isset($_POST['submit'])) { move_uploaded_file($_FILES['imagefile']['tmp_name'],"latest.img"); $instr = fopen("latest.img","rb"); $image = addslashes(fread($instr,filesize("latest.img"))); if (strlen($instr) < 149000) { $image_query="insert into image (title, imgdata,friend) values (\"". $_REQUEST['title']. "\", \"". $image. "\",'".$_REQUEST['friend']."')"; mysql_query ($image_query) or die("query error"); } else { $errmsg = "Too large!"; } $resultbytes=''; // Find out about latest image $query = "select * from image where pid=1"; $result = @mysql_query("$query"); $resultrow = @mysql_fetch_assoc($result); $gotten = @mysql_query("select * from image order by pid desc limit 1"); if ($row = @mysql_fetch_assoc($gotten)) { $title = htmlspecialchars($row[title]); $bytes = $row[imgdata]; $resultbytes = $row[imgdata]; $friend=$row[friend]; } else { $errmsg = "There is no image in the database yet"; $title = "no database image available"; // Put up a picture of our training centre $instr = fopen("../wellimg/ctco.jpg","rb"); $bytes = fread($instr,filesize("../wellimg/ctco.jpg")); } if ($resultbytes!='') { echo $resultbytes; } } ?> <html> <head> <title>Upload an image to a database</title> </head> <body bgcolor="#FFFF66"> <form enctype="multipart/form-data" name="file_upload" method="post"> <center> <div id="image" align="center"> <h2>Heres the latest picture</h2> <font color=red><?php echo $errmsg; ?></font> <b><?php echo $title ?></center> </div> <hr> <h2>Please upload a new picture and title</h2> <table align="center"> <tr> <td>Select image to upload: </td> <td><input type="file" name="imagefile"></td> </tr> <tr> <td>Enter the title for picture: </td> <td><input type="text" name="title"></td> </tr> <tr> <td>Enter your friend's name:</td> <td><input type="text" name="friend"></td> </tr> <tr> <td><input type="submit" name="submit" value="submit"></td> <td></td> </tr> </table> </form> </body> </html> --> Above set of code has one problem. The problem is whenever i pressing the "submit" button. It is just displaying the image on a page. But it is leaving all the html codes. even any new line message after the // Printing image on browser echo $resultbytes; //************************// So, for this i put this set of code in html tag: This is other sample code: <!-- <?php error_reporting(0); // Connect to database $errmsg = ""; if (! @mysql_connect("localhost","root","")) { $errmsg = "Cannot connect to database"; } @mysql_select_db("test"); $q = <<<CREATE create table image ( pid int primary key not null auto_increment, title text, imgdata longblob, friend text) CREATE; @mysql_query($q); // Insert any new image into database if (isset($_POST['submit'])) { move_uploaded_file($_FILES['imagefile']['tmp_name'],"latest.img"); $instr = fopen("latest.img","rb"); $image = addslashes(fread($instr,filesize("latest.img"))); if (strlen($instr) < 149000) { $image_query="insert into image (title, imgdata,friend) values (\"". $_REQUEST['title']. "\", \"". $image. "\",'".$_REQUEST['friend']."')"; mysql_query ($image_query) or die("query error"); } else { $errmsg = "Too large!"; } $resultbytes=''; // Find out about latest image $query = "select * from image where pid=1"; $result = @mysql_query("$query"); $resultrow = @mysql_fetch_assoc($result); $gotten = @mysql_query("select * from image order by pid desc limit 1"); if ($row = @mysql_fetch_assoc($gotten)) { $title = htmlspecialchars($row[title]); $bytes = $row[imgdata]; $resultbytes = $row[imgdata]; $friend=$row[friend]; } else { $errmsg = "There is no image in the database yet"; $title = "no database image available"; // Put up a picture of our training centre $instr = fopen("../wellimg/ctco.jpg","rb"); $bytes = fread($instr,filesize("../wellimg/ctco.jpg")); } } ?> <html> <head> <title>Upload an image to a database</title> </head> <body bgcolor="#FFFF66"> <form enctype="multipart/form-data" name="file_upload" method="post"> <center> <div id="image" align="center"> <h2>Heres the latest picture</h2> <?php if ($resultbytes!='') { // Printing image on browser echo $resultbytes; } ?> <font color=red><?php echo $errmsg; ?></font> <b><?php echo $title ?></center> </div> <hr> <h2>Please upload a new picture and title</h2> <table align="center"> <tr> <td>Select image to upload: </td> <td><input type="file" name="imagefile"></td> </tr> <tr> <td>Enter the title for picture: </td> <td><input type="text" name="title"></td> </tr> <tr> <td>Enter your friend's name:</td> <td><input type="text" name="friend"></td> </tr> <tr> <td><input type="submit" name="submit" value="submit"></td> <td></td> </tr> </table> </form> </body> </html> --> ** But in this It is showing the image in format of special charaters and digits. 1) So, Please help me to print the image with some HTML code. So that i can print it in my form to display the image. 2) Is there any way to convert the database image into real image, so that i can store it into my hard-disk and call it from tag? Please help me.

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  • problem when cloning jQuery UI datepicker

    - by h3
    I have a div in which there is a datepicker. I use something like this to clone it: mydiv = $('#someDiv'); // works fine so far mydiv.find('input.datefield').datepicker(); // clone without the events and insert newDiv = myDiv.clone(false).insertAfter(myDiv); // datepicker won't re-init if this class is present newDiv.find('.hadDatepicker').removeClass('hadDatepicker'); // reinitialize datepicker newDiv.find('input.datefield').datepicker(); This is a stripped down version of my code. It works and the calendar shows up as expected where it is expected .. but when a date is clicked, the previous datepicker's value gets updated.. (the one from which it was cloned). I've tried to destroy the (inexisting) instance before like this: newDiv.find('input.datefield').datepicker('destroy').datepicker(); No luck .. I've checked how it keeps track of instances and manually cleared the data like this: newDiv.find('input.datefield').data('datepicker', false).datepicker('destroy').datepicker(); Still no luck. What I don't understand is that only the date selection behavior is buggy, everything else works as expected. I really don't know what else to check now ..

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  • PHP error problem.

    - by TaG
    I get the following error on line 8: Undefined index: real_name which is $privacy_policy = mysqli_real_escape_string($mysqli, $_POST['privacy_policy']); I was wondering how can I fix this problem? Here is the PHP. if (isset($_POST['submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id=3"); $privacy_policy = mysqli_real_escape_string($mysqli, $_POST['privacy_policy']); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, privacy_policy) VALUES ('$user_id', '$privacy_policy')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET privacy_policy = '$privacy_policy' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } } Here is the HTML. <form method="post" action="index.php"> <fieldset> <ul> <li><input type="checkbox" name="privacy_policy" id="privacy_policy" value="yes" <?php if (isset($_POST['privacy_policy'])) { echo 'checked="checked"'; } else if($privacy_policy == "yes") { echo 'checked="checked"'; } ?> /></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • Cocoa touch - prepopulate facebook connect publish to feed

    - by teepusink
    Hi, I'm using the iPhone facebook connect package. How do I prepopulate the "publish to feed" example or take out the message field? Something like this one http://www.burnthebox.us/mobile/iPhone/products/disconnect/instructions/images/DisConnect_FB_Publish_Story.png (The default in the example has an input text field) Also what would it take to skin the popup look? Thanks, Tee

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  • Need help in Select query..

    - by Parth
    If I have four rows for a field with different values with other fields similar and then other four rows with same condition, as given below here u can see there different rows for insert with only difference in the "newvalue" and "field" excluding "id" for the table_name=jos_menu, operation=INSERT and live=0 now here what select query should be used to get only single row from the table on every change of table_name...??

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  • LINQ-to-SQL - C# - OnValidate()

    - by Mark Comix
    Hello, I have a system with 3 layers and I am using LINQ-to-SQL to persist. I want to validate if the description field of my object is empty. I am using partial classes and the method OnValidate(). If the field is empty, it throws an exception. Is this correct? What do I do after the exception to not close the form, letting the user continue working? Thank you very much Sorry for my poor english

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  • how to insert a verify code HTML Standard Paypal

    - by user304828
    i have a product , product infor was save in table , and have a field verify_code, i will create a string by md5 and insert to this field, and i want send this verify_code to paypal then i can check response return from paypal if verify_code == response verify_code will do next action how i can do it with html standard paypal?

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  • Hide the built-in Send button in Outlook 2003

    - by Raheem
    I am using ms-outlook 2003, i want to hide the built-in send button and use the custom button to send the mail. As i have worked on C,C++ and on Java, dont know how to work on VB/VBScript/VBA, can any body tell me how to hide this button and also how to send mail from custom button, how to access the fields of mail (ie., the TO field, Subject field, Msg Body, attachment etc).

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  • Same jQuery code returns two different results – Submit Button Text

    - by Lijo
    I have two jQuery codes - http://jsfiddle.net/Lijo/CXGX7/7/ and http://jsfiddle.net/Lijo/CXGX7/8/ . The first code returns undefined whereas the second code returns text of button. QUESTIONS What is the reason for this difference in result? Why is the first code not returning expected text of button? Note: I verified that both are using same version of jQuery (by an alert of jQuery) alert($.fn.jquery); CODE <html xmlns="http://www.w3.org/1999/xhtml"> <head><title> </title> <script type="text/javascript" src="http://ajax.aspnetcdn.com/ajax/jquery/jquery-1.8.1.js"></script> <script type="text/javascript"> alert($('.myButton').attr("value")); </script> </head> <body> <form method="post" action="Test.aspx" id="form1"> <div class="aspNetHidden"> <input type="hidden" name="__VIEWSTATE" id="__VIEWSTATE" value="/wEPDwULLTE0MDM4MzYxMjNkZMycQvsYQ+GPFsQHoQ8j/8vEo2vQbqkhfgPc60kxXaQO" /> </div> <div class="aspNetHidden"> <input type="hidden" name="__EVENTVALIDATION" id="__EVENTVALIDATION" value="/wEWAwKqxqqrCgLi/JazDQKM54rGBqgaroRQTXJkD1LyUlVxAmLRCNfTGVe73swQBMemBtvN" /> </div> <div> <input name="txtEmpName" type="text" id="txtEmpName" /> <input type="submit" name="Button1" value="Submit" id="Button1" class="myButton" /> </div> </form> </body> </html> REFERENCES Retrieve Button value with jQuery How to determine and print jQuery version?

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  • pass data to Html.TextBoxFor with JQuery

    - by ognjenb
    In one of fields like this: <div class="editor-field" > <%= Html.TextBoxFor(model => model.Engineer1Id)%> <%= Html.ValidationMessageFor(model => model.Engineer1Id) %> </div> I try to pass data with JQuery: var Id = $(this).attr("rel"); $("#Engineer1Id").append(Id); Why data doesn't put in specified field

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  • added row to a table with jquery but added rows disappear with browser refresh

    - by user840930
    I added rows to a html table with jquery, but when I refresh the browser, the rows disappear. How can I get the rows to stay? <TABLE id="dataTable" width="100%" align="center"> <TR align="center" border="1"> <TH></TH> <TH>ID </TH> <TH>Name</TH> <TH>Status</TH> </TR> <TR align="center"> <TD><INPUT type="checkbox" name="chk"/></TD> <TD> 1 </TD> <TD> <INPUT type="text" value="Submission 1" /> </TD> <TD>Working version</TD> </TR> </TABLE> <script type="text/javascript"> $(document).ready(function(){ $('#createNew').click(function() { var table = document.getElementById('dataTable'); var rowCount = table.rows.length; $('#dataTable tr:last').after('<TR align="center"><TD><INPUT type="checkbox" name="chk"/></TD><TD>'+ rowCount + '</TD><TD> <INPUT type="text" value="Submission 1" /> </TD><TD>Working version</TD></TR>');

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  • PHP matching a string

    - by John Jones
    Hi, I have an Indian company data set and need to extract the City and Zip from the address field: Address Field Example: Gowripuram West, Sengunthapuram Post, Near L.G.B., Karur, Tamilnadu, Karur - 639 002, India As you can see the City is Karur and the zip is followed after the - (hyphen). I need the PHP code to match [city] - [zip] Not sure how to do this I can find the Zip after the Hypen but not sure how to find the City, please note the City can be 2 words. Cheers for your time./ J

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