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  • Android Launcher Shortcuts

    - by Tim
    I have made a simple punch in / punch out time clock application. I want to add the user the option of making a shortcut on the homescreen that will toggle the state of the app(time out / time in) but I don't want this shortcut to open up the app on the screen at all. here is my setupShortcut() private void setupShortcut() { Intent shortcutIntent = new Intent(this, Toggle.class); // shortcutIntent.setClassName(this, Toggle.class.getName()); shortcutIntent.putExtra(EXTRA_KEY, "ToggleShortcut"); shortcutIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP); Intent intent = new Intent(); intent.putExtra(Intent.EXTRA_SHORTCUT_INTENT, shortcutIntent); intent.putExtra(Intent.EXTRA_SHORTCUT_NAME, "ToggleShortcut"); Parcelable iconResource = Intent.ShortcutIconResource.fromContext(this, R.drawable.app_sample_code); intent.putExtra(Intent.EXTRA_SHORTCUT_ICON_RESOURCE, iconResource); setResult(RESULT_OK, intent); } Toggle.class is an activity that toggles the state for me. In the manifest I have these settings on it <activity android:name=".Toggle" android:exported="true" android:theme="@android:style/Theme.Translucent.NoTitleBar"> As it is now I can create a shortcut on the home screen then press it. The first time I press it it starts the Toggle activity and completes it fine, but it also opens up the TimeClock activity on the screen. If I then hit the back button I go back to the home. I can now press this shortcut and it will start the Toggle activity and not change the screen. Before I added: shortcutIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP); It would open up the TimeClock activity every time. Now it is just the first time. But I want it to never show anything on the screen when the Toggle shortcut is pressed. Does anyone have any idea of how to get rid of that?

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  • How to parse the "<media:group>" using feedparser?

    - by Wayle.C
    The rss file is shown as below, i want to get the content in section media:group . I check the document of feedparser, but it seems not mention this. How to do it? Any help is appreciated. XYZ InfoX: Special hello http://www1.XYZInfoX.com/learninghello/home hello en Wed, 17 Mar 2010 08:50:06 GMT 2010-03-17T08:50:06Z en Voice of America http://www1.XYZInfoX.com/learninghello http://media.XYZInfoX.com/designimages/XYZRSSIcon.gif <item> <title>Who Were the Deadliest Gunmen of the Wild West?</title> <link>http://www1.XYZInfoX.com/learninghello/home/Deadliest-Gunmen-of-the-Wild-West-87826807.html</link> <description> The story of two of them: "Killin'" Jim Miller was an outlaw, "Texas" John Slaughter was a lawman | EXPLORATIONS </description> <pubDate>Wed, 17 Mar 2010 00:38:48 GMT</pubDate> <guid isPermaLink="false">87826807</guid> <dc:creator></dc:creator> <dc:date>2010-03-17T00:38:48Z</dc:date> *<media:group> <media:content url="http://media.XYZInfoX.com/images/archives_peace_comm_480_16mar_se.jpg" medium="image" isDefault="true" height="300" width="480" /> <media:content url="http://media.XYZInfoX.com/images/archives_peace_comm_230_16mar_se_edited-1.jpg" medium="image" isDefault="false" height="230" width="230" /> <media:content url="http://media.XYZInfoX.com/images/tex_trans_lawmans_230_16mar10_se.jpg" medium="image" isDefault="false" height="230" width="230" /> <media:content url="http://www.XYZInfoX.com/MediaAssets2/learninghello/dalet/se-exp-outlaws-part2-17mar2010.Mp3" type="audio/mpeg" medium="audio" isDefault="false" /> </media:group>* </item>

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  • Problem with Flash...help

    - by aarontb
    Hey Guys...need help. Working on a project and get this error on the Output Log TypeError: Error #1009: Cannot access a property or method of a null object reference. at FlashSite_fla::MainTimeline/frame16() Here's every frame that is on, begins, or crosses frame 16 Layer Name: Top Menu (4 Button named Home_btn, Works_btn, Tech_btn, Contact_btn) Code attached to frame: stop(); Home_btn.addEventListener(MouseEvent.CLICK, home); function home(event:MouseEvent):void { gotoAndStop(16); } Works_btn.addEventListener(MouseEvent.CLICK, works); function works(event:MouseEvent):void { gotoAndStop(17); } Tech_btn.addEventListener(MouseEvent.CLICK, tech); function tech(event:MouseEvent):void { gotoAndStop(18); } Contacts_btn.addEventListener(MouseEvent.CLICK, contact); function contact(event:MouseEvent):void { gotoAndStop(19); } Layer Name: Investment Opp (button named Invest_btn) Code attached to frame: Invest_btn.addEventListener(MouseEvent.CLICK, invest); function invest(event:MouseEvent):void { var link:URLRequest = new URLRequest('#'); navigateToURL(link); } Layer Name: MfgOpp (Button named Mfg_btn) Code attached to frame: Mfg_btn.addEventListener(MouseEvent.CLICK, mfg); function mfg(event:MouseEvent):void { var link:URLRequest = new URLRequest('#'); navigateToURL(link); } Layer Name: MarketResearch (button name Own_btn) Code attached to frame: Own_btn.addEventListener(MouseEvent.CLICK, own); function own(event:MouseEvent):void { var link:URLRequest = new URLRequest('#'); navigateToURL(link); } Layer Name: ActionScript Code attached to frame: import flash.events.MouseEvent; What am I doing wrong?!?!

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  • popup with dynamic menuitems, each menuitem is another popup

    - by encryptor
    I am building an extension that has a pop up whose elements are constructed by a function call everytime the mouse hovers over the popup option. I am able to achieve this. Now I need to have a popup for each of the menu item (inside the original popup) which is not dynamic though. I have this code, but it does not work: for (var m=0; m < localpubliclist.length; m++) { var newItem = document.createElement("menu"); newItem.setAttribute("label", publicdisplayname[m]); newItem.setAttribute("id", "public" + m); myMenuPopup.appendChild(newItem); var newpopup = document.createElement("menupopup"); newpopup.setAttribute("id","publicpop" + m); newItem.appendChild(newpopup); var new1= document.createElement("menuitem"); new1.setAttribute("label", "Home"); new1.setAttribute("id", "publichome" + m); newpopup.appendChild(new1); } doing this forms the first popup where i can see all my menu with names publicdisplayname[m]. each of these is to be a popup which displays "Home". This does not work. the second popup (popup on publicdisplayname[m]) does not open. i have been stuck on this for quite some time and have tried various things cut it doesnt work. Can we do this at all? can we have double dynamic popups?

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  • ASP.NET MVC 2 router matches correct area route but generates URL to the first registered area inste

    - by Sandor Drieënhuizen
    I'm working on a S#arpArchitecture 1.5 project, which uses ASP.NET MVC 2. I've been trying to get areas to work properly but I ran into a problem: The ASP.NET MVC 2 routing engine matches the correct route to my area but then it generates an URL that belongs to the first registered area instead. Here's my request URL: /Framework/Authentication/LogOn?ReturnUrl=%2fDefault.aspx I'm using the Route Tester from Phil Haack and it shows: Matched Route: Framework/{controller}/{action}/{id} Generated URL: /Data/Authentication/LogOn?ReturnUrl=%2FDefault.aspx using the route "Data/{controller}/{action}/{id}" That's clearly wrong, the URL should point to the Framework area, not the Data area. This is how I register my routes, nothing special there IMO. private static void RegisterRoutes(RouteCollection routes) { routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); AreaRegistration.RegisterAllAreas(); routes.MapRoute( "default", "{controller}/{action}/{id}", new { controller = "Home", action = "Index", id = UrlParameter.Optional }); } The area registration classes all look like this. Again, nothing special. public class FrameworkAreaRegistration : AreaRegistration { public override string AreaName { get { return "Framework"; } } public override void RegisterArea(AreaRegistrationContext context) { context.MapRoute( "Framework_default", "Framework/{controller}/{action}/{id}", new { controller = "Home", action = "Index", id = UrlParameter.Optional }); } }

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  • How to set up RPX widget and facebook app to be able to authenticate with rpx_now?

    - by Andrei
    Using the sample app for rpx_now gem ( http://github.com/grosser/rpx_now_example) on localhost:3000, I have successfully logged in via Google Accounts, myOpenID, Yahoo, but cannot make it via Facebook. In the RPX app/widget settings I have set my facebook-app key and secret. In my facebook app settings, the Connect URL is myappname.rpxnow.com. But when I try to connect, then I don't even see a facebook login page, just a number of redirects and I am back to my localhost with the following exception http://gist.github.com/386520 . Before I was successfully connecting with oauth2 gem, however, without fetching user data - only authentication. That time I set only key/secret and localhost as my Connect URL. Currently, I don't even ask for email etc., but still the same problem. Can it happen because rpx_now cannot get requested user data from facebook? Or it is a problem of facebook key/secret? May be I need to provide more settings of my facebook app? RPXNow::ApiError in UsersController#create Got error: Invalid parameter: token (code: 1), HTTP status: 200 RAILS_ROOT: /home/Andrei/rpx_now_example Application Trace | Framework Trace | Full Trace /usr/lib/ruby/gems/1.8/gems/rpx_now-0.6.20/lib/rpx_now/api.rb:71:in `parse_response' /usr/lib/ruby/gems/1.8/gems/rpx_now-0.6.20/lib/rpx_now/api.rb:21:in `call' /usr/lib/ruby/gems/1.8/gems/rpx_now-0.6.20/lib/rpx_now.rb:23:in `user_data' /home/Andrei/rpx_now_example/app/controllers/users_controller.rb:16:in `create' Request Parameters: None Show session dump Response Headers: {"Content-Type"="", "Cache-Control"="no-cache"}

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  • Can the same ssh key be used to access two different users on the same server?

    - by Nick
    I have an new ubuntu (hardy 8.04) server, it has two users, User1 and User2. User1 is listed in sudoers. I appended my public ssh key to authorized_keys in /home/user1/.ssh/authorized_keys, changed the permissions on user1/.ssh/ to 700 and user1/.ssh/authorized_keys to 600 and both file and folder are owned my User1. Then added I User1 to sshd_config (AllowUsers User1). This works and I can login into User1 debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from 86.141.61.197 I then copied the authorized_keys file to /home/user2/.shh/ and changed the permissions and ownership and added User2 to AllowUsers in sshd_config (AllowUsers User1 User2). Now when I try to login to User2 it will not authenticate the same public key. debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works? Thanks in advance, Nick

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  • Jetty startup delay

    - by Tauren
    I'm trying to figure out what would be causing a 1 minute delay in the startup of Jetty. Is it a configuration problem, my application, or something else? I have Jetty 7 (jetty-7.0.1.v20091125 25 November 2009) installed on a server and I deploy a 45MB ROOT.war file into the webapps directory. This is the only webapp configured in Jetty. I then start Jetty with the command: java -DSTOP.PORT=8079 -DSTOP.KEY=mystopkey -Denv=stage -jar start.jar etc/jetty-logging.xml etc/jetty.xml & I get two lines of output right after doing this: 2010-03-07 14:20:06.642:INFO::Logging to StdErrLog::DEBUG=false via org.eclipse.jetty.util.log.StdErrLog 2010-03-07 14:20:06.710:INFO::Redirecting stderr/stdout to /home/zing/jetty-distribution-7.0.1.v20091125/logs/2010_03_07.stderrout.log When I press the enter key, I get my command prompt back. Looking at the log file (logs/2010_03_07.stderrout.log), I see the following at the beginning: 2010-03-07 14:08:50.396:INFO::jetty-7.0.1.v20091125 2010-03-07 14:08:50.495:INFO::Extract jar:file:/home/zing/jetty-distribution-7.0.1.v20091125/webapps/ROOT.war!/ to /tmp/Jetty_0_0_0_0_8080_ROOT.war___.8te0nm/webapp 2010-03-07 14:08:52.599:INFO::NO JSP Support for , did not find org.apache.jasper.servlet.JspServlet 2010-03-07 14:09:51.379:INFO::Set web app root system property: 'webapp.root' = [/tmp/Jetty_0_0_0_0_8080_ROOT.war___.8te0nm/webapp] 2010-03-07 14:09:51.585:INFO::Initializing Spring root WebApplicationContext INFO - ContextLoader - Root WebApplicationContext: initialization started INFO - XmlWebApplicationContext - Refreshing Root WebApplicationContext: startup date [Sun Mar 07 14:09:51 PST 2010]; root of context hierarchy ... Notice the 1 minute long pause between the 3rd and 4th lines. What is Jetty doing at this point? What other things could be going on? It doesn't even look like it has started my Spring initialization yet. Note that I checked my /tmp directory to see if it was simply the time to unpack my war file, but the file had been completely unpacked even at the start of this 1 minute delay.

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  • jqGrid - edit function never getting called

    - by dcp
    I'm having a problem with JQGrid using ASP.NET MVC. I'm trying to follow this example (after you go to that link, over on the left side of the page please click Live Data Manipulation, then Edit Row), but my edit function is never getting called (i.e. it's never getting into the $("#bedata").click(function(). Does anyone know what could be the problem? <script type="text/javascript"> var lastsel2; jQuery(document).ready(function() { jQuery("#editgrid").jqGrid({ url: '/Home/GetMovieData/', datatype: 'json', mtype: 'GET', colNames: ['id', 'Movie Name', 'Directed By', 'Release Date', 'IMDB Rating', 'Plot', 'ImageURL'], colModel: [ { name: 'id', index: 'Id', width: 55, sortable: false, hidden: true, editable: false, editoptions: { readonly: true, size: 10} }, { name: 'Movie Name', index: 'Name', width: 250, editable: true, editoptions: { size: 10} }, { name: 'Directed By', index: 'Director', width: 250, align: 'right', editable: true, editoptions: { size: 10} }, { name: 'Release Date', index: 'ReleaseDate', width: 100, align: 'right', editable: true, editoptions: { size: 10} }, { name: 'IMDB Rating', index: 'IMDBUserRating', width: 100, align: 'right', editable: true, editoptions: { size: 10} }, { name: 'Plot', index: 'Plot', width: 150, hidden: false, editable: true, editoptions: { size: 30} }, { name: 'ImageURL', index: 'ImageURL', width: 55, hidden: true, editable: false, editoptions: { readonly: true, size: 10} } ], pager: jQuery('#pager'), rowNum: 5, rowList: [5, 10, 20], sortname: 'id', sortorder: "desc", height: '100%', width: '100%', viewrecords: true, imgpath: '/Content/jqGridCss/redmond/images', caption: 'Movies from 2008', editurl: '/Home/EditMovieData/', caption: 'Movie List' }); }); $("#bedata").click(function() { var gr = jQuery("#editgrid").jqGrid('getGridParam', 'selrow'); if (gr != null) jQuery("#editgrid").jqGrid('editGridRow', gr, { height: 280, reloadAfterSubmit: false }); else alert("Hey dork, please select a row"); }); </script> The relevant HTML is here: <table id="editgrid"> </table> <div id="pager" style="text-align: center;"> </div> <input type="button" id="bedata" value="Edit Selected" />

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  • Source Control - XCode - Visual Studio 2005/2008 / 2010

    - by Mick Walker
    My apologies if this has been asked before, I wasnt quite sure if this question should be asked on a programming forum, as it more relates to programming environment than a particular technology, so please accept my (double) appologies if I am posting this in the wrong place, my logic in this case was if it effects the code I write, then this is the place for it. At home, I do a lot of my development on a Mac Pro, I do development for the Mac, iPhone and Windows on this machine (Xcode & Visual Studio - (multiple versions installed in bootcamp, but generally I run it via Parallels)). When visiting a client, I have a similar setup, but on my MacBook Pro. What I want is a source control solution to install on the Mac Pro, that will support both XCode and multiple versions of visual studio, so that when I visit a client, I can simply grab the latest copy from source control via the MacBook Pro. Whilst visiting the client, he / she may suggest changes, and minor ones I would tend to make on site, so I need the ability to merge any modified code back into the trunk of the project / solution when I return home. At the moment, I am using no source control at all, and rely on simply coping folders and overwriting them when I return from a client- thats my 'merge'!!! I was wondering if anyone had any ideas of a source provider I could use, which would support both Windows and Mac development environments, and is cheap (free would be better).

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  • move_uploaded_file() error

    - by James R.
    I have a website on free hosting - 000webhost.com and it allows you to upload images. However, when I try to upload an image, I get these errors: Warning: move_uploaded_file(images/SmallSmileyFace.jpg) [function.move-uploaded-file]: failed to open stream: Permission denied in /home/a6621074/public_html/m/write.php on line 76 Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move '/tmp/phpcmW3mo' to 'images/SmallSmileyFace.jpg' in /home/a6621074/public_html/m/write.php on line 76 This is the code: if (!empty($_FILES['fileImage']['name'])) { // check image type and size if ((($imagetype == 'image/gif') || ($imagetype == 'image/jpeg') || ($imagetype == 'image/pjpeg') || ($imagetype == 'image/png')) && ($imagesize > 0) && ($imagesize <= 32768)) { if ($_FILES['fileImage']['error'] == 0) { //move file $target = 'images/' . $image; if (move_uploaded_file($_FILES['fileImage']['tmp_name'], $target)) { $query = "INSERT INTO reviews (post_date, food_name, location, cafeteria, review, image, rating, user_id) VALUES (NOW(), '$foodname', '$location', '$cafeteria', '$review', '$image', $rate, $id)"; mysqli_query($dbc, $query); //confirm success echo '<p>Thank you for your submission!</p>'; } else { echo '<p class="errmsg">There was a problem uploading your image.</p>'; } } @unlink($_FILES['fileImage']['tmp_name']); } else { echo '<p class="errmsg">The screen shot must be a GIF, JPEG, or PNG image file no greater than 32KB in size.</p>'; } } Any ideas?

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  • Automatically support new changes with Python.

    - by Zachary Brown
    I was working on a program,that I need to support new additions. Hmmm. Let me give you some background on the program. It is an educational software program that has quizzes for the user to take, just to gain odd knowledge. Now, It currently supports 6 subjects, all organized with directores on the HDD ( i.e. the Science directory is called science. ) and the way you launch the subject to see what quizzes you have to take is by pushing a button on the home screen. This sort of thing prevents easy subject additions. I want to be able to add a subject later on without having to recode the home screen and re organize all the buttons. I would use a Listbox and os.listdir(...), but I was kind of wanting something prettier than a Listbox. I am using Tkinter on Windows. The Python version I am using is 2.6 Is there a "fancy" listbox sort of thing that can be styled to work with the background?

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  • Autotools automatic invocation of lcov after 'make check'

    - by disown
    I have successfully set up an autotools project where the tests compiles with instrumentation so I can get a test coverage report. I can get the report by running lcov in the source dir after a successful 'make check'. I now face the problem that I want to automate this step. I would like to add this to 'make check' or to make it a separate goal 'make check-coverage'. Ideally I would like to parse the result and fail if the coverage falls below a certain percentage. Problem is that I cannot figure out how to add a custom target at all. The closest I got was finding this example autotools config, but I can't see where in that project the goal 'make lcov' is added. I can only see some configure flags in m4/auxdevel.m4. Any tips?

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  • MVC Areas - View not found

    - by user314827
    Hi, I have a project that is using MVC areas. The area has the entire project in it while the main "Views/Controllers/Models" folders outside the Areas are empty barring a dispatch controller I have setup that routes default incoming requests to the Home Controller in my area. This controller has one method as follows:- public ActionResult Index(string id) { return RedirectToAction("Index", "Home", new {area = "xyz"}); } I also have a default route setup to use this controller as follows:- routes.MapRoute( "Default", // Default route "{controller}/{action}/{id}", new { controller = "Dispatch", action = "Index", id = UrlParameter.Optional } ); Any default requests to my site are appropriately routed to the relevant area. The Area's "RegisterArea" method has a single route:- context.MapRoute( "xyz_default", "xyz/{controller}/{action}/{id}", new { action = "Index", id = UrlParameter.Optional } My area has multiple controllers with a lot of views. Any call to a specific view in these controller methods like "return View("blah"); renders the correct view. However whenever I try and return a view along with a model object passed in as a parameter I get the following error:- Server Error in '/DeveloperPortal' Application. The view 'blah' or its master was not found. The following locations were searched: ~/Views/Profile/blah.aspx ~/Views/Profile/blah.ascx ~/Views/Shared/blah.aspx ~/Views/Shared/blah.ascx It looks like whenever a model object is passed in as a param. to the "View()" method [e.g. return View("blah",obj) ] it searches for the view in the root of the project instead of in the area specific view folder. What am I missing here ? Thanks in advance.

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  • Core Data iPad/iPhone BLOBS vs File system for 20k PDFs

    - by jamone
    I'm designing an iPad/iPhone app using core data. The main focus of the app is sorting and viewing up to 20,000 PDFs They are ~200KB each. Typically its best to not store BLOBS in a DB, but for desktop systems I've typically seen it said that if the blobs are < 1 MB then its fine to use the DB. Any considerations I should take into count? If I store them in the file system can I store them all in one directory and not have performance issues (I won't need to ever get a directory list since I'd store each's path in the DB)? Should I divide them among a handful of directories? If so is there a good rule on # of files per dir?

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  • PHP Include Windows XP Notepad++ Editor - Nav Include Not Working - Nav Disappears

    - by Lorianna Sprague
    I am creating a website, and have a tabbed horizontal menu. In order to cut back on the number of files I have to edit when I have to make changes to the menu I want to put the navigation in a separate file that I can call using a PHP include statement. When I do this, however, the nav disappears entirely from the page. The rest of the content remains, and there are no error messages. I have been looking for answers for this for weeks, and have tried every version of the PHP include statement that I could find. None of them worked. This was the last attempt. I have the file "nav.php" in a folder named "includes" in a main dir called "testsite" I use Windows XP, use NotePad++ as my text editor, and have been testing in Firefox. I can't find an answer anywhere - any help would be appreciated. Lorianna

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  • ejb lookup failing with NamingException

    - by Drake
    I've added the following in my web.xml: <ejb-ref> <ejb-ref-name>ejb/userManagerBean</ejb-ref-name> <ejb-ref-type>Session</ejb-ref-type> <home>gha.ywk.name.entry.ejb.usermanager.UserManagerHome</home> <remote>what should go here??</remote> </ejb-ref> The following java code is giving me NamingException: public UserManager getUserManager () throws HUDException { String ROLE_JNDI_NAME = "ejb/userManagerBean"; try { Properties props = System.getProperties(); Context ctx = new InitialContext(props); UserManagerHome userHome = (UserManagerHome) ctx.lookup(ROLE_JNDI_NAME); UserManager userManager = userHome.create(); WASSSecurity user = userManager.getUserProfile("user101", null); return userManager; } catch (NamingException e) { log.error("Error Occured while getting EJB UserManager" + e); return null; } catch (RemoteException ex) { log.error("Error Occured while getting EJB UserManager" + ex); return null; } catch (CreateException ex) { log.error("Error Occured while getting EJB UserManager" + ex); return null; } } The code is used inside the container. By that I mean that the .WAR is deployed on the server (Sun Application Server). StackTrace (after jsight's suggestion): >Exception occurred in target VM: com.sun.enterprise.naming.java.javaURLContext.<init>(Ljava/util/Hashtable;Lcom/sun/enterprise/naming/NamingManagerImpl;)V java.lang.NoSuchMethodError: com.sun.enterprise.naming.java.javaURLContext.<init>(Ljava/util/Hashtable;Lcom/sun/enterprise/naming/NamingManagerImpl;)V at com.sun.enterprise.naming.java.javaURLContextFactory.getObjectInstance(javaURLContextFactory.java:32) at javax.naming.spi.NamingManager.getURLObject(NamingManager.java:584) at javax.naming.spi.NamingManager.getURLContext(NamingManager.java:533) at javax.naming.InitialContext.getURLOrDefaultInitCtx(InitialContext.java:279) at javax.naming.InitialContext.lookup(InitialContext.java:351) at gov.hud.pih.eiv.web.EjbClient.EjbClient.getUserManager(EjbClient.java:34)

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  • Incorrect site usage report (Sharepoint)

    - by Jorge E. Barsoba
    Hi... After restarting "Windows Sharepoint Services Timer" service the "Site usage report" shows only one day of activity (matches the day we restarted the service) while every other day has zeros. I took a look in the "\LOGS\" dir and is plenty of logs with the visit's information for the whole year! Why the usage report ignores it? I think maybe the log file of the day showed could have some kind of mark that the other ones doesn't... Thanks, Jorge.

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  • inbound/outbound url routing in asp.net MVC

    - by Stephane
    The routing I need is quite simple, I must be missing something there. As code example I put the simpler situation where I can reproduce my behavior. You have this ActionMethod : public ActionResult Index(string provider) { ViewData["Message"] = provider; return View("Index"); } And you have this route : routes.MapRoute( null, "{controller}/{action}/{provider}", new { controller = "Home", action = "Index", provider = "Default" } ); // Parameter defaults You can call /Home/Index/Custom and provider will take the value "Custom" What Route would I need if I want the url /?provider=Custom to map the provider to the parameter. I thought that would just work, because the default controller and the default action would be used, and the provider from the querystring would be used instead of the default one. but the querystring is just ignored here. That's a problem in my situation as I have a form using HTTP GET method. The form action has to be Html.BeginForm(c=c.Index(null)) which is resolved as / and the value of my form are added in the querystring. (the provider being a dropdown in the form) So the url built by the form is /?abc=value&cde=value...

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  • pycurl installation on Windows

    - by Vijayendra Bapte
    I am not able to install pycurl on Windows on Python2.6. Getting following error: C:\Documents and Settings\vijayendra\Desktop\Downloads\pycurl-7.19.0>python setup.py install --curl-dir="C:\Documents and Settings\vijayendra\Desktop\Downloads\ curl-7.19.5-win32-ssl\curl-7.19.5" Using curl directory: C:\Documents and Settings\vijayendra\Desktop\Downloads\curl-7.19.5-win32-ssl\curl-7.19.5 Traceback (most recent call last): File "setup.py", line 210, in <module> assert os.path.isfile(o), o AssertionError: C:\Documents and Settings\vijayendra\Desktop\Downloads\curl-7.19.5-win32-ssl\curl-7.19.5\lib\libcurl.lib Any idea what is this error about and how to fix this?

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  • add methods in subclasses within the super class constructor

    - by deamon
    I want to add methods (more specifically: method aliases) automatically to Python subclasses. If the subclass defines a method named 'get' I want to add a method alias 'GET' to the dictionary of the subclass. To not repeat myself I'd like to define this modifation routine in the base class. But if I check in the base class init method, there is no such method, since it is defined in the subclass. It will become more clear with some source code: class Base: def __init__(self): if hasattr(self, "get"): setattr(self, "GET", self.get) class Sub(Base): def get(): pass print(dir(Sub)) Output: ['__doc__', '__init__', '__module__', 'get'] It should also contain 'GET'. Is there a way to do it within the base class?

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  • Any tutorial for Python PalmDB library?

    - by roddik
    Hello, I've downloaded the Python PalmDB lib, but can't find any info on how to use it. I've tried reading docstrings and so far I've been able to come up with the following code: from pprint import pprint from PalmDB.PalmDatabase import PalmDatabase pdb = PalmDatabase() with open('testdb.pdb','rb') as data: pdb.fromByteArray(data.read()) pprint(dir(pdb)) pprint(pdb.attributes) print pdb.__doc__ #print pdb.records print pdb.records[10].toXML() which gives me the xml representation of a record (?) with some nasty long payload attribute, which doesn't resemble any kind of human-readable text to me. I just want to read the contents of the pdb file. Is there a guide/tutorial for this library? What would you do to figure out the proper way to make things done in my situation?

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  • SHA function issues

    - by Damian James
    I have this php code from my login.php if (isset($_POST['logIn'])) { $errmsg = ""; $logname = mysqli_real_escape_string($dbc, trim($_POST['usernameIn'])); $logpassword = mysqli_real_escape_string($dbc, trim($_POST['passwordIn'])); $query = "SELECT user_id, username FROM members WHERE username = '$logname' AND password = SHA('$logpassword')"; $data = mysqli_query($dbc, $query); if (mysqli_num_rows($data) == 1) { $row = mysqli_fetch_array($data); setcookie('user_id', $row['user_id'], time() + (60 * 60 * 24 * 30)); //expires after 30 days setcookie('username', $row['username'], time() + (60 * 60 * 24 * 30)); $home = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']) . '/index.php'; header('Location: ' . $home); } else { $errmsg = '<p class="errormsg">Username or password is incorrect.</p>'; } } And for some reason, it always ends up setting $errmsg in the else statement. I am sure that I'm entering information (username,password) that is correct and exists in the database. I insert my values (from a signup script) using this query: $query = "INSERT INTO members (username, password, email) VALUES ('$username', SHA('$password'), '$email')"; Anyone see the problem with this script? Thanks!

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  • issue in property file

    - by devuser
    I want to load the property file when tomcat is starting.so I'm using servletContextListener to do that and i can get values of property file to my web application. But i want to keep the same value after changing the property file once log into web application.But when i change the value of property file and log into system again it change the value to new one.I want to keep the same value that loaded when tomcat was starting.how can i implement this? My coding is as below import javax.servlet.*; import java.io.IOException; import java.util.Properties; import java.util.logging.Level; import java.util.logging.Logger; import java.io.*; import java.util.ResourceBundle; public final class sysProperties implements javax.servlet.ServletContextListener { private static Properties props = new Properties(); private static String file_name = "com/util/contact.properties"; public addSystemProperties() { } public void contextInitialized(ServletContextEvent servletContextEvent) { // Get the context ServletContext servletContext = servletContextEvent.getServletContext(); // Set a context attribute try { // props.load(servletContext.getResourceAsStream(file_name)); props.load(getClass().getClassLoader().getResourceAsStream(file_name)); System.out.println(" Application X is starting"); servletContext.setAttribute("h1",props.getProperty("home.h1")); servletContext.setAttribute("h2",props.getProperty("home.h2")); System.out.println("h1"+servletContext.getAttribute("h1")); System.out.println("h2"+ servletContext.getAttribute("h2")); ; } catch (Exception e) { System.out.println(" Error setting context attribute: " + e.getMessage()); } } public void contextDestroyed(ServletContextEvent servletContextEvent) { // Get the context ServletContext servletContext = servletContextEvent.getServletContext(); // Output the context variable we set earlier System.out.println(" Application X is shutting down"); System.out.println(" Value of h1 is: " + servletContext.getAttribute("h1")); System.out.println(" Value of h2 is: " + servletContext.getAttribute("h2")); // Clean up (not really necessary as the context is being destroyed, but let's be neat) servletContext.removeAttribute(props.getProperty("h1")); servletContext.removeAttribute(props.getProperty("h2")); } }

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  • WebSVN install on IIS 6.0

    - by ClayB
    I am trying to set up WebSVN on a Windows Server 2003 machine and not having any luck. I have done the following: Installed FastCGI Installed PHP 5.3.1.0 to c:\PHP Updated php.ini with the following: cgi.force_redirect = 0 cgi.fix_pathinfo = 1 fastcgi.impersonate = 1 fastcgi.logging = 0 Downloaded and extracted WebSVN 2.3.0 to D:\myWebRoot\websvn Copy distconfig.php to config.php Added the following: $config-setSVNCommandPath('c:\Program Files\Subversion\bin'); $config-setDiffPath('C:\Program Files\FogBugz\accessories'); $config-addRepository('Documents', 'https://myServer/myDir/Docs)', null, 'myDocsUser', 'myDocsPassword'); When I browse to URL myServer//websvn, I get the following error: Error running this command: "c:\Program Files\Subversion\bin\svn" --version --config-dir /tmp Any ideas?

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