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  • Calling a function in a JavaScript file with Selenium IDE

    - by user1059903
    So, I'm running these Selenium IDE tests against a site I'm working on. Everything about the tests themselves is running fine, except I would like to do a bit of clean-up once I'm done. In my MVC3 Razor based site, I have a JavaScript file with a function that gets a JsonResult from a Controller of mine. That Controller handles the database clean-up that Selenium IDE otherwise couldn't handle. However, I'm having a hard time finding any sort of documentation on how to do this. I know I can do JavaScript{ myJavascriptGoesHere } as one of the Values for a line in the test, but I can't seem to find a way to tell it to go find my clean-up function. Is it even possible for Selenium IDE to do this sort of thing? If it comes down to it, I can just make a separate View to handle the clean-up, but I'd really like to avoid that if possible. Thanks!

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  • Best way to support large dropdowns

    - by JustAProgrammer
    Say I have a report that can be restricted by specifying some value in a dropdown. This dropdown list references a table with 30,000 records. I don't think this would be feasible to populate a dropdown with! So, what is the best way to provide the user the ability to select a value given this situation? These values do not really have categories and even if I subdivided (by having some nesting dropdown situation) by the first letter of the value, that may still leave a few thousand entries. What's the best way to deal with this?

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  • How to read modelstate errors when returned by Json?

    - by learning
    How can I display modelstate errors returned by Json ? I want to do somthing like that... if (!ValidateLogOn(Name, currentPassword)) { ModelState.AddModelError("_FORM", "Username or password is incorrect."); //Return a json object to the javascript return Json(new { ModelState }); } What must be my code in the view to read the modelstate errors and display them? My actual code in the view is as follows to read the Json values: function createCategoryComplete(e) { var obj = e.get_object(); alert(obj.Values); }

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  • CakePHP accessing other controllers

    - by James
    CakePHP Newbie :) I am having trouble accessing another controller and passing that data to a view in one of my controllers: In controllers/landings_controller.php: var $uses = 'User'; function home() { $userdata = $this->User->read(); $this->set(compact('userdata')); } In views/landings/home.ctp: <?php echo $this->userdata; ?> When accessing /landings/home I get the following error: Notice (8): Undefined property: View::$userdata [APP/views/landings/home.ctp, line 38] I don't know what I am doing wrong. Any help? Thanks!

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  • setting value to a parameter - always saying that it is null REALLY NEED INPUT

    - by Amina
    So I have this schedule visit page with two groups. Group 1 contains a list of: Cases. Group 2 contains a list of: Parties. each group has a checkboxes next to its item for the user to select. My Issue when i select a case and/or a party and save -- then go to the edit page of the visit i just saved and only my selected case is checked and the party i selected is not checked. After debugging i realized that the partyId is not being saved properly during the create page and thus not showing as selected or saved on the edit page. I really need help on how to properly save the party selected and setting for it a value from the parameter. Here is my code of what i have for saving a case and would like to know how to properly save with party. Controller [HttpPost] [ValidateInput(false)] public ActionResult Create(VisitViewModel viewModel, Guid[] associatedCasesSelected, Guid[] selectedParties) { if (!ModelState.IsValid) { viewModel.Time = _timeEntryHelper.Value; AddLookupsToViewModel(viewModel); return View(viewModel); } var visitEntry = Mapper.Map<VisitViewModel, VisitEntry>(viewModel); ... viewModel.CasePartyIds = selectedParties; try { _visitEntryService.Create(visitEntry, associatedCasesSelected); this.FlashInfo(string.Format(Message.ConfirmationMessageCreate, Resources.Entities.Visit.EntityName)); } catch (RulesException ex) { ex.CopyTo(ModelState); } if (ModelState.IsValid) return RedirectToAction("Edit", "Case", new { caseId = viewModel.CaseId }); AddLookupsToViewModel(viewModel); return View(viewModel); } VisitEntryService public void Create(VisitEntry visitEntry,IList<Guid>caseIds) { EnsureValid(visitEntry); _visitEntryRepository.Save(visitEntry); caseIds = AddCurrentCaseToCases(visitEntry.CaseId, caseIds); foreach (var caseId in caseIds.Distinct()) { var visit = new Visit {CaseId = caseId, VisitEntryId = visitEntry.VisitEntryId}; _visitService.Create(visit); } } AddCurrentCaseToCases private static IList<Guid>AddCurrentCaseToCases(Guid caseId, IEnumerable<Guid>caseIds) { var cases = new List<Guid>(); if (caseIds != null) { cases.AddRange(caseIds); if(!caseIds.Contains(caseId)) cases.Add(caseId); } else cases.Add(caseId); return cases; } VisitService public Visit Get(Guid visitId) { return DataContext.Visits.SingleOrDefault(v => v.VisitId == visitId); } public void Save(Visit visit) { if(visit.VisitId == Guid.Empty) { visit.VisitId = Guid.NewGuid(); DataContext.Visits.InsertOnSubmit(visit); } else { var currentVisit = Get(visit.VisitId); if (currentVisit == null) throw RepositoryExceptionFactory.Create("Visit", "VisitId"); } DataContext.SubmitChanges(); } Any TIPS or IDEAS is greatly appreciated at this time :) The entitiy for the parties will be VisitEntryParty

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  • Use textbox value on submit as a query string variable

    - by Eric
    How would I take a text box value and use it in the query string on submit? I'd like it to start as this, /News?favorites=True and end up something like this after the user enters in a search and clicks search. /News?query=test&favorites=True The controller action looks like this public ActionResult Index(string query,bool favorites) { //search code } This question is something close to what I'd like to do, but I'd like to use the query string and maintain the existing values in the query string. Thanks.

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  • How should nested components interact with model in a GUI application?

    - by fig-gnuton
    Broad design/architecture question. If you have nested components in a GUI, what's the most common way for those components to interact with data? For example, let's say a component receives a click on one of its buttons to save data. Should the save request be delegated up that component's ancestors, with the uppermost ancestor ultimately passing the request to a controller? Or are models/datastores in a GUI application typically singletons, so that a component at any level of a hierarchy can directly get/set data? Or is a controller injected as a dependency down the hierarchy of components, so that any given component is only one intermediary away from the datastore/model?

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  • Display Friendly Date, Numbers

    - by user310657
    I am searching for a custom control for asp.net, which helps display user friendly dates, like instead of article date: (2-april-2010) it displays (2 months old) I am unable to find it on google, please can any one suggest links, custom controls, articles for the same. Thank you.

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  • mvc3 ActionResult does not reload page if is already on it

    - by senzacionale
    public ActionResult DeleteCategory(int id) { CategoryManager manager = new CategoryManager(); manager.DeleteCategory(id); TempData["IsDeleted"] = true; return RedirectToAction("CategoriesList"); } public ActionResult CategoriesList() { List<CategoryModel> model = new CategoryManager().GetAll(); return View(model); } public void DeleteCategory(int categoryId) { using (AsoEntities context = new AsoEntities()) { var categoryToDelete = (from c in context.Categories where c.Id == categoryId select c).SingleOrDefault(); if (categoryToDelete == null) return; context.Categories.DeleteObject(categoryToDelete); context.SaveChanges(); } } when i delete article i go back to CategoriesList but page is not reloaded if i am already on CategoriesList. What to do that page will be reloaded and data will be changed?

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  • Spring Web: Correct way to have a single default ViewResolver

    - by wuntee
    What is the best way to have every request be sent to a single ViewResolver - specifically in this case a JsonView? Was thinking this: <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.json.MappingJacksonJsonView" /> <property name="prefix" value="*" /> </bean> but, is there something better/easier?

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  • error while adding WCF service reference

    - by user1561256
    There was an error downloading . Unable to connect to the remote server No connection could be made because the target machine actively refused it Metadata contains a reference that cannot be resolved.There was no endpoint listening at that could accept the message. This is often caused by an incorrect address or SOAP action. See Inner Exception, if present, for more details. Unable to connect to the remote server No connection could be made because the target machine actively refused it. If the service is defined in the current solution, try building the solution and adding the service reference again. can pls somebody solve this.

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  • Is this a good approach to dealing with tagging?

    - by Mel
    Can this code be optimized or re-factored? Is this an optimal approach to tagging? The following code is a callback in my posts model. It creates a record that associates a tag with a post in a QuestionsTags joiner table. When necessary, if a given tag does not already exist in the tags table, the function creates it, then uses its id to create the new record in the QuestionsTags table. The difficulty with this approach is the QuestionsTags table depends on data in the tags table which may or may not exist. The function assumes the following tables: tags(id, tagName), posts(tags) // Comma delimited list questionsTags(postId, tagId) The idea is to loop over a delimited list of tags submitted with a post and check to see if each tag already exists in the tags table If tag exists: Check to see if there's already a QuestionTag record for this post and this tag in the QuestionTags table. If yes, do nothing (the association already exists) If no, create a new QuestionTag record using the id of the existing tag and the postId If tag does not already exist: Create the new tag in the tags table Use its id to create a new QuestionsTags record Code /** * @hint Sets tags for a given question. **/ private function setTags() { // Loop over the comma and space delmited list of tags for (local.i = 1; local.i LTE ListLen(this.tags, ", "); local.i = (local.i + 1)) { // Check if the tag already exists in the database local.tag = model("tag").findOneByTagName(local.i); // If the tag exists, look for an existing association between the tag and the question in the QuestionTag table if (IsObject(local.tag)) { local.questionTag = model("questionTag").findOneByPostIdAndTagId(values="#this.postId#,#local.tag.id#"); // If no assciatione exists, create a new QuestionTag record using the tagId and the postId if (! IsObject(local.questionTag)) { local.newQuestionTag = model("questionTag").new(postId = this.id, tagId = local.tag.id); // Abort if the saving the new QuestionTag is unsuccesful if (! local.newQuestionTag.save()) { return false; } } } // If the tag does not exist create it else { local.newTag = model("tag").new(tagName = local.i, userId = this.ownerUserId); // Abort if the the new tag is not saved successfully if (! local.newTag.save()) { return false; } // Otherwise create a new association in the QuestionTags table using the id of the newly created tag and the postId local.newQuestionTag = model("questionTag").new(postId = this.id, tagId = local.newTag.id); // Abort if the new QuestionTag does not save correctly if (! local.newQuestionTag.save()) { return false; } } } } FYI: I'm using CFWheels in my application, which explains the ORM functions used.

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  • Add multiple ActionName for button

    - by NewToBirtReporting
    I have one controller on which i have Save button click event. Im using same controller and view for Add and Edit purpose. My code is as per below [HttpPost] [Button(ButtonName = "Save")] [ActionName("Create")] [ValidateAntiForgeryToken(Salt = "PostData")] public ActionResult Save(Ntegra m_Ntegra,FormCollection form) {} As Im Using ActionName("Create") here so button can not work for ActionName("Edit"). can anyone tell me how i can achive my requirnment!! Thanks for help...... :)

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  • Creating non-framework calsses in CakePHP

    - by Affian
    I'm making a tournament manager in CakePHP 1.3 and I have a tournament controller which is fine but I want to implement a interface that can be used to define how a tournament runs. the controller needs to load a concrete class that implements the TournamentStyle interface that defines how the tournament works. At the end of a round the TournamentStyle is used to calculate the scores and winners and generate the next round of matches. That gives me a .php file for the interface and other files for the various styles. My question is: where would I put these files and how would I load them into my tournament controller?

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  • MVC3 Custom view engine

    - by eth0
    I have a custom View Engine that derives from WebFormViewEngine. There's a lot of stuff going on in here, mostly caching. I want to be able to use WebFormViewEngine AND RazorViewEngine at the same time, is this possible? Ideally I'd like to do; ViewEngines.Add(new MyViewEngine<WebFormsViewEngine>()); ViewEngines.Add(new MyViewEngine<RazorViewEngine>()); if a .ascx/.aspx/.master file exists then use WebForms, otherwise use Razor is a .cshtml file exists. EDIT: I should of worded my question better. As my custom view engine derives from WebFormViewEngine it obviously uses WebForms, I can't derive from two classes. I can derive from RazorViewEngine but then I'll loose WebForms. I can duplicate my code entirely, derive from RazorViewEngine and edit the views file extensions, etc. but as I said I've got a lot of custom code in my view engine and would be duplicating hundreds of lines. WebFormViewEngine and RazorViewEngine derive from BuildManagerViewEngine which in turn implements IViewEngine. The problem with that is I have to implement methods CreatePartialView() and CreateView() but how would I know what to return (WebForms/Razor?) using generics?

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  • MVC2 JSON action, if I want to be RESTful should I allow GET, POST, or Both?

    - by Yads
    The project I'm currently working has a whole bunch of JSON actions in order to populate cascading dropdowns via ajax calls. Since they're technically Select queries and we're trying to be RESTful, we've been marking these actions with the HttpGet attributes. However by default, JsonResultdoes not allow to return results via a GET. So we've had to explicitly call Json(data, JsonRequestBehavior.AllowGet). What I'm wondering is, is this bad practice? Should we only be allowing Post requests to our Json actions? If it makes a difference, this is an enterprise application, that requires a log in to a particular environment before it can be accessed.

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  • how do I get the form data in a javascript object so I can send it as the data parameter of an $.aja

    - by user281180
    How to return json after form.submit()? <form id="NotificationForm" action="<%=Url.Action("Edit",new{Action="Edit"}) %>" method="post" enctype="multipart/form-data" onsubmit='getJsonRequestAfterSubmittingForm(this); return false;'> <%Html.RenderPartial("IndexDetails", Model);%> </form> $.ajax({ url: '<%=Url.Action("Edit","Notification") %>', type: "POST", dataType: 'json', data: $("#NotificationForm").submit(), contentType: "application/json; charset=utf-8", success: function(result) { if (result.Result == true) { alert("ghjghsgd"); } }, error: function(request, status, error) { $("#NotSelectedList").html("Error: " & request.responseText); } });

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