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  • How to sort Map in Java

    - by kalpesh
    hi i want to sort map according to its key value plz see code below public static void main(String[] args) { SortedMap map = new TreeMap(); // Add some elements: map.put("2", "Two"); map.put("1", "One"); map.put("5", "Five"); map.put("4", "Four"); map.put("3", "Three"); map.put("10", "Ten"); map.put("12", "Twelve"); map.put("7", "Seven"); map.put("9", "Nine"); Iterator iterator = map.keySet().iterator(); while (iterator.hasNext()) { Object key = iterator.next(); System.out.println("key : " + key + " value :" + map.get(key)); } } Result Should come below key : 1 value :One key : 2 value :Two key : 3 value :Three key : 4 value :Four key : 5 value :Five key : 7 value :Seven key : 9 value :Nine key : 10 value :Ten key : 12 value :Twelve

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  • What's wrong with this JAVA code for android?

    - by Umair Ashraf
    I have written this piece of code to break an image into 9 pieces and it gives me runtime error. There is no error in LogCat and I am stuck. The error comes at line 7 line from bottom (Bitmap.createBitmap(...);). public Bitmap[] getPieces(Bitmap bmp) { Bitmap[] bmps = new Bitmap[9]; int width = bmp.getWidth(); int height = bmp.getHeight(); int rows = 3; int cols = 3; int cellHeight = height / rows; int cellWidth = width / cols; int piece = 0; for (int x = 0; x <= width; x += cellWidth) { for (int y = 0; y <= height; y += cellHeight) { Bitmap b = Bitmap.createBitmap(bmp, x, y, cellWidth, cellHeight, null, false); bmps[piece] = b; piece++; } } return bmps; }

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  • Who is preventing the release of Java 1.7

    - by Shawn
    I recently attended a talk by a Sun engineer Charlie Hunt regarding performance. The talk was interesting enough but one question was regarding release date of 1.7. He said it's delayed as there are parties who are refusing to sign off JSRs they own and thus preventing the 1.7 release. It apparently has something to do with the cost of determining your Sun compliance. I would be interested to know the full story if anyone knows or can point me in the right direction. What triggered my question was the amazing long release notes for 6u18. Thanks

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  • Java HTTP Request Occasionally Hangs

    - by behrk2
    Hello Everyone, For the majority of the time, my HTTP Requests work with no problem. However, occasionally they will hang. The code that I am using is set up so that if the request succeeds (with a response code of 200 or 201), then call screen.requestSucceeded(). If the request fails, then call screen.requestFailed(). When the request hangs, however, it does so before one of the above methods are called. Is there something wrong with my code? Should I be using some sort of best practice to prevent any hanging? The following is my code. I would appreciate any help. Thanks! HttpConnection connection = (HttpConnection) Connector.open(url + connectionParameters); connection.setRequestMethod(method); connection.setRequestProperty("WWW-Authenticate", "OAuth realm=api.netflix.com"); if (method.equals("POST")) { connection.setRequestProperty("Content-type", "application/x-www-form-urlencoded"); } int responseCode = connection.getResponseCode(); System.out.println("RESPONSE CODE: " + responseCode); if (connection instanceof HttpsConnection) { HttpsConnection secureConnection = (HttpsConnection) connection; String issuer = secureConnection.getSecurityInfo() .getServerCertificate().getIssuer(); UiApplication.getUiApplication().invokeLater( new DialogRunner( "Secure Connection! Certificate issued by: " + issuer)); } if (responseCode != 200 && responseCode != 201) { screen.requestFailed("Unexpected response code: " + responseCode); connection.close(); return; } String contentType = connection.getHeaderField("Content-type"); ByteArrayOutputStream baos = new ByteArrayOutputStream(); InputStream responseData = connection.openInputStream(); byte[] buffer = new byte[20000]; int bytesRead = 0; while ((bytesRead = responseData.read(buffer)) > 0) { baos.write(buffer, 0, bytesRead); } baos.close(); connection.close(); screen.requestSucceeded(baos.toByteArray(), contentType); } catch (IOException ex) { screen.requestFailed(ex.toString()); }

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  • How do I detect unicode characters in a Java string to resolve sax parser exception

    - by Madhumita
    Suppose I have a string that contains '¿'. How would I find all those unicode characters? Should I test for their code? How would I do that? I want to detect it to avoid sax parser exception which I am getting it while parsing the xml saved as a clob in oracle 10g database. Exception javax.servlet.ServletException: org.xml.sax.SAXParseException: Invalid byte 1 of 1-byte UTF-8 sequence.

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  • using extends with Java Generics

    - by Sandro
    Lets say that I have the following code: public class Shelter<A extends Animal, B extends Animal> { List<A> topFloor = new Vector<A>(); List<B> bottomFloor = new Vector<B>(); public A getFirstTopFloorAnimal(){return topFloor.firstElement();} public B getFirstBottomFloorAnimal(){return bottomFloor.firstElement();} //This compiles but when I try to use it, it only returns objects public List<Animal> getAnimals() { Vector a = new Vector(topFloor); a.addAll(bottomFloor); return a; } } Now for somereason the following code compiles. But when I try to use getAnimals() I get a of objects instead of Animal. Any ideas why this is? Does this have to do with the List is NOT a List idea in the Generics tutorial? Thank you.

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  • Java: downloading issue using BufferedInputStream, BufferedOutputStream

    - by nkr1pt
    When downloading a rar file from the internet with the code below, the downloaded file is larger than it actually is. Not sure what causes this? bis = new BufferedInputStream(urlConn.getInputStream()); bos = new BufferedOutputStream(new FileOutputStream(outputFile)); eventBus.fireEvent(this, new DownloadStartedEvent(item)); int read; byte[] buffer = new byte[2048]; while ((read = bis.read(buffer)) != -1) { bos.write(buffer); } eventBus.fireEvent(this, new DownloadCompletedEvent(item));

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  • Java - Collections.sort() performance

    - by msr
    Hello, Im using Collections.sort() to sort a LinkedList whose elements implements Comparable interface, so they are sorted in a natural order. In the javadoc documentation its said this method uses mergesort algorithm wich has n*log(n) performance. My question is if there is a more efficient algorithm to sort my LinkedList? The size of that list could be very high and sort will be also very frequent. Thanks!

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  • Java: Implement own message queue (threadsafe)

    - by derMax
    The task is to implement my own messagequeue that is thread safe. My approach: public class MessageQueue { /** * Number of strings (messages) that can be stored in the queue. */ private int capacity; /** * The queue itself, all incoming messages are stored in here. */ private Vector<String> queue = new Vector<String>(capacity); /** * Constructor, initializes the queue. * * @param capacity The number of messages allowed in the queue. */ public MessageQueue(int capacity) { this.capacity = capacity; } /** * Adds a new message to the queue. If the queue is full, it waits until a message is released. * * @param message */ public synchronized void send(String message) { //TODO check } /** * Receives a new message and removes it from the queue. * * @return */ public synchronized String receive() { //TODO check return "0"; } } If the queue is empty and I call remove(), I want to call wait() so that another thread can use the send() method. Respectively, I have to call notifyAll() after every iteration. Question: Is that possible? I mean does it work that when I say wait() in one method of an object, that I can then execute another method of the same object? And another question: Does that seem to be clever?

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  • Control - C exception in Java

    - by Phil
    I need to catch that exception but I can't figure out which one it is. The IDE i'm using right now doesn't allow for a program interrupt that way. I know how to user try/catch, but I don't actually know what I'm trying to catch.. Can anyone help me with this?

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  • java Getting a list of words from a Trie

    - by adam08
    I'm looking to use the following code to not check whether there is a word matching in the Trie but to return a list all words beginning with the prefix inputted by the user. Can someone point me in the right direction? I can't get it working at all..... public boolean search(String s) { Node current = root; System.out.println("\nSearching for string: "+s); while(current != null) { for(int i=0;i<s.length();i++) { if(current.child[(int)(s.charAt(i)-'a')] == null) { System.out.println("Cannot find string: "+s); return false; } else { current = current.child[(int)(s.charAt(i)-'a')]; System.out.println("Found character: "+ current.content); } } // If we are here, the string exists. // But to ensure unwanted substrings are not found: if (current.marker == true) { System.out.println("Found string: "+s); return true; } else { System.out.println("Cannot find string: "+s +"(only present as a substring)"); return false; } } return false; } }

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  • Loading all files in a directory in a Java applet

    - by WarrenB
    How would one go about programatically loading all the resource files in a given directory in a JAR file for an applet? The resources will probably change several times over the lifetime of the program so I don't want to hardcode names in. Normally I would just traverse the directory structure using File.list(), but I get permission issues when trying to do that within an applet. I also looked at using an enumeration with something line ClassLoader.getResources() but it only finds files of the same name within the JAR file. Essentially what I want to do is (something like) this: ClassLoader imagesURL = this.getClass().getClassLoader(); MediaTracker tracker = new MediaTracker(this); Enumeration<URL> images = imagesURL.getResources("resources/images/image*.gif"); while (images.hasMoreElements()){ tracker.add(getImage(images.nextElement(), i); i++; } I know I'm probably missing some obvious function, but I've spent hours searching through tutorials and documentation for a simple way to do this within an unsigned applet.

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  • JTable horizontal scrollbar in Java

    - by Mr CooL
    Is there any way to enable horizontal scrollbar whenever necessary?? The situation was as such: I've a JTable on Netbeans, one of the cells, stored a long length of data. Hence, I need to have horizontal scrollbar. Anyone has idea on this? THanks in advance for any helps..

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  • Java - JPA - @Basic and @Embedded

    - by Yatendra Goel
    I am learning JPA from this tutorial. I have some confusions in understanding the following annotations: @Basic @Embedded Fields of an embeddable type default to persistent, as if annotated with @Embedded. If the fields of embeddable types defualt to persistent, then why would we need @Embedded

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  • special debugging lines (java)

    - by David
    Recently i've found myself writing a lot of methods with what i can only think to call debugging scaffolding. Here's an example: public static void printArray (String[] array, boolean bug) { for (int i = 0; i<array.lenght; i++) { if (bug) System.out.print (i) ; //this line is what i'm calling the debugging scaffolding i guess. System.out.println(array[i]) ; } } in this method if i set bug to true, wherever its being called from maybe by some kind of user imput, then i get the special debugging text to let me know what index the string being printed as at just in case i needed to know for the sake of my debugging (pretend a state of affairs exists where its helpful). All of my questions more or less boil down to the question: is this a good idea? but with a tad bit more objectivity: Is this an effective way to test my methods and debug them? i mean effective in terms of efficiency and not messing up my code. Is it acceptable to leave the if (bug) stuff ; code in place after i've got my method up and working? (if a definition of "acceptability" is needed to make this question objective then use "is not a matter of programing controversy such as ommiting brackets in an if(boolean) with only one line after it, though if you've got something better go ahead and use your definition i won't mind) Is there a more effective way to accomplish the gole of making debugging easier than what i'm doing? Anything you know i mean to ask but that i have forgotten too (as much information as makes sense is appreciated).

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  • Is this a Java DateFormat bug?

    - by anonymous
    The pattern is "dd-MM-yyyy" I think the string "01-01-2010mwwwwwwwwwwwwwww" does not satisfy the pattern, but the following code shows the contrary. Anyone can explain why? public static void main(String[] args) throws Exception { SimpleDateFormat df = new SimpleDateFormat("dd-MM-yyyy"); Date date = df.parse("01-01-2010mwwwwwwwwwwwwwww"); System.out.println(date); } Thanks

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  • Ideal Java library for cleaning html, and escaping malformed fragments

    - by Tyler
    I've got some HTML files that need to be parsed and cleaned, and they occasionally have content with special characters like <, , ", etc. which have not been properly escaped. I have tried running the files through jTidy, but the best I can get it to do is just omit the content it sees as malformed html. Is there a different library that will just escape the malformed fragments instead of omitting them? If not, any recommendations on what library would be easiest to modify? Clarification: Sample input: <p> blah blah <M+1> blah </p> Desired output: <p> blah blah &lt;M+1&gt; blah </p>

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  • TACACS lib for java

    - by guaz
    The only open source TACACS lib I was able to find was Jnetlib http://sourceforge.net/projects/jnetlib But there is not any description about how to use it!! Anyone have used it before?? thanks

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  • goto statements in java

    - by user238284
    I executed the below code in Eclipse, but the GOTO statements in it is not effective. How to use it? case 2: **outsideloops:** System.out.println("Enter the marks (in 100):"); System.out.println("Subject 1:"); float sub1=Float.parseFloat(br.readLine()); **if(sub1<=101) goto outsideloops;** System.out.println("Subject 2:"); float sub2=Float.parseFloat(br.readLine()); System.out.println("Subject 3:"); float sub3=Float.parseFloat(br.readLine()); System.out.println("The Student is "+stu.average(sub1,sub2,sub3)+ "in the examinations"); break;

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  • Java Swing - Problem in disabling JCheckbox

    - by Yatendra Goel
    I am disabling a JCheckbox and then enabling it with the help of setEnabled(...) method. But the problem is if I disable a unselected checkbox, then it becomes selected after I enable it. I want all of them to have the same state after being enabled that they had before being disabled.

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