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  • PHP alternating colors

    - by Jordan Pagaduan
    $dbc = mysql_connect('localhost','root','') or die (mysql_error()); mysql_select_db('payroll') or die (mysql_error()); $sql = "SELECT * FROM employee ORDER BY employee_id DESC"; $result = mysql_query($sql); while($row = mysql_fetch_array($result)) { echo " <tr> <td style=\"padding-left: 20px; border-bottom: 1px solid #999; border-right: 1px solid #999;\">".$row['first_name']." ".$row['last_name']."</td> <td style=\"text-align: center; border-bottom: 1px solid #999; border-right: 1px solid #999; padding-top: 2px ; padding-bottom: 3px ;\"><input type=\"button\" name=\"edit\" value=\"Edit\" class=\"selbtn\">&nbsp;<input type=\"button\" name=\"delete\" value=\"Delete\" class=\"selbtn\"></td> </tr> "; } I wanted to add an alternating color in the loop. what code should I add?

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  • How to add text to email sent from a php contact form

    - by JustStatic
    Hi all this is the PHP im using: <?php $name = $_POST['name']; $email = $_POST['email']; $phone = $_POST['phone']; $message = $_POST['message']; $formcontent=" From: $name \n Phone: $phone \n Message: $message"; $recipient = "[email protected]"; $subject = "Contact Form"; $mailheader = "From: $email \r\n"; mail($recipient, $subject, $formcontent, $mailheader) or die("Error!"); echo "Thank You!" . " -" . "<a href='contact.html' style='text-decoration:none; color:#ff0099;'> Return Home</a>"; ?> Its working perfectly fine but i would like there to be some text sent with this email that says "This is from your website" or something similar to tell the recipient that it isnt spam (my client isn't tech friendly and sees everything plain text as spam). I'm very new to PHP with nearly 0 knowledge and have no idea how to add something like that. I did have a go at making a new variable with the string inside and then include that in the: mail($recipient, $subject, $formcontent, $mailheader) or die("Error!"); line but with no success. Thanks for taking the time any help would be welcome.

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  • Mysql query problem

    - by Sergio
    I have a problem with (for me to complicated) MySql query. Okay, here is what I need to do: First I need to check messages that some specific user received $mid=$_SESSION['user']; $stat1=mysql_query("SELECT id, fromid, toid, subject FROM messages WHERE toid = '".$mid."' AND subject != 'not readed' GROUP BY fromid ") or die(mysql_error()); while ($h = mysql_fetch_array($stat1)) { $whosend=$h['fromid']; Second thing that I need to do is check the status of the users (deleted or not) who sent the messages ("fromid") to my specific user ("toid"). This I must do from another table: $stat2=mysql_query("SELECT id, status FROM members WHERE id='".$whosend."' AND status ='1'")or die(mysql_error()); while ($s = mysql_fetch_array($stat)) { Then my problems begin to show up. How can I get the number of the users who sent messages to my specific user with status =1? Not the number of the messages but the total number of the users who sent them. Is there any easier way to do this query? I tried with join tables like $stat=mysql_query("SELECT memebers.id, memebers.status, messages.toid, messages.fromid,messages.subject,messages.id FROM members, messages WHERE messages.toid='".$mid."' AND members.status ='7' .... But even in this query I need to have id's of the user who sent messages before this query so there will be another query before this join tables.

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  • Help with my PHP template class

    - by blerh
    I want to separate the output of HTML from my program code in my projects, so I wrote a very simple database class. <?php class Template { private $template; function load($filePath) { if(!$this->template = file_get_contents($filePath)) $this->error('Error: Failed to open <strong>' . $filePath . '</strong>'); } function replace($var, $content) { $this->template = str_replace("{$var}", $content, $this->template); } function display() { echo $this->template; } function error($errorMessage) { die('die() by template class: <strong>' . $errorMessage . '</strong>'); } } ?> The thing I need help with is the display() method. Say for example I use this code: $tplObj = new Template(); $tplObj->load('index.php'); $tplObj->replace('{TITLE}', 'Homepage'); $tplObj->display(); And the index.php file is this: <html> <head> <title>{TITLE}</title> </head> <body> <h1>{TITLE}</h1> <?php if($something) { echo '$something is true'; } else { echo '$something is false'; } ?> </body> </html> I'm just wondering if the PHP code in there would be run? Or would it just be sent to the browser as plaintext? I was using eval() in my template class but I hate that function :P Thanks.

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  • mEncrypt/Decrypt binary mp3 with mcrypt, missing mimetype

    - by Jeremy Dicaire
    I have a script that read a mp3 file and encrypt it, I want to be able to decrypt this file and convert it to base64 so it can play in html5. Key 1 will be stored on the page and static, key2 will be unique for each file, for testing I used: $key1 = md5(time()); $key2 = md5($key1.time()); Here is my encode php code : //Get file content $file = file_get_contents('test.mp3'); //Encrypt file $Encrypt = mcrypt_encrypt(MCRYPT_RIJNDAEL_256, $key1, $file, MCRYPT_MODE_CBC, $key2); $Encrypt = trim(base64_encode($Encrypt)); //Create new file $fileE = "test.mp3e"; $fileE = fopen($file64, 'w') or die("can't open file"); //Put crypted content fwrite($fileE, $Encrypt); //Close file fclose($fileE); Here is the code that doesnt work (decoded file is same size, but no mimetype): //Get file content $fileE = file_get_contents('test.mp3e'); //Decode $fileDecoded = base64_decode($fileE); //Decrypt file $Decrypt = mcrypt_decrypt(MCRYPT_RIJNDAEL_256, $key1, $fileDecoded, MCRYPT_MODE_CBC, $key2); $Decrypt = trim($Decrypt); //Create new file $file = "test.mp3"; $file = fopen($file, 'w') or die("can't open file"); //Put crypted content fwrite($file, $Decrypt); //Close file fclose($file);

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  • GET and XMLHttpRequest

    - by Neethusha
    i have an XMLHttpRequest.The request passes a parameter to my php server code in /var/www. But i cannot seem to be able to extract the parameter back at the server side. below i have pasted both the codes: javascript: function getUsers(u) { alert(u);//here u is 'http://start.ubuntu.com/9.10' xmlhttp=new XMLHttpRequest(); var url="http://localhost/servercode.php"+"?q="+u; xmlhttp.onreadystatechange= useHttpResponse; xmlhttp.open("GET",url,true); xmlhttp.send(null); } function useHttpResponse() { if (xmlhttp.readyState==4 ) { var response = eval('('+xmlhttp.responseText+')'); for(i=0;i<response.Users.length;i++) alert(response.Users[i].UserId); } } servercode.php: <?php $q=$_GET["q"]; //$q="http://start.ubuntu.com/9.10"; $con=mysql_connect("localhost","root","blaze"); if(!$con) {die('could not connect to database'.mysql.error()); } mysql_select_db("BLAZE",$con) or die("No such Db"); $result=mysql_query("SELECT * FROM USERURL WHERE URL='$q'"); if($result == null) echo 'nobody online'; else { header('Content-type: text/html'); echo "{\"Users\":["; while($row=mysql_fetch_array($result)) { echo '{"UserId":"'.$row[UsrID].'"},'; } echo "]}"; } mysql_close($con); ?> this is not giving the required result...although the commented statement , where the variable is assigned explicitly the value of the argument works...it alerts me the required output...but somehow the GET method's parameter is not reaching my php or thats how i think it is....pls help....

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  • Show last 4 table entries mysql php

    - by user272899
    I have a movie database Kind of like a blog and I want to display the last 4 created entries. I have a column in my table for timestamp called 'dateadded'. Using this code how would I only display the 4 most recent entries to table <?php //connect to database mysql_connect($mysql_hostname,$mysql_user,$mysql_password); @mysql_select_db($mysql_database) or die("<b>Unable to connect to specified database</b>"); //query databae $query = "SELECT * FROM movielist"; $result=mysql_query($query) or die('Error, insert query failed'); $row=0; $numrows=mysql_num_rows($result); while($row<$numrows) { $id=mysql_result($result,$row,"id"); $imgurl=mysql_result($result,$row,"imgurl"); $imdburl=mysql_result($result,$row,"imdburl"); ?> <div class="moviebox rounded"><a href="http://<?php echo $domain; ?>/viewmovie?movieid=<?php echo $id; ?>" rel="facebox"> <img src="<?php echo $imgurl; ?>" /> <form method="get" action=""> <input type="text" name="link" class="link" style="display:none" value="http://us.imdb.com/Title?<?php echo $imdburl; ?>"/> </form> </a></div> <?php $row++; } ?>

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  • Integrating legacy Ajax script in CakePHP

    - by octavian
    Hi, I have a legacy script that I would like to integrate in a cakephp app. The script makes use of $_POST and such and since I'm quite a noob I would need some help for the integration. Here is how the script looks like: THE JAVASCRIPT: prototype.js builder.js (these two are from the prototype fw) lib.js (makes a ajax requests to remote.php) THE PHP remote.php (contains FastJSON class and $_POST vars) if ($_POST['cmd'] == 'SAVETEAM' && $_POST['info']) { $INFO = json_decode(str_replace('\"', '"', $_POST['info'])); $nr = 1; $SORT = array($INFO->GK, $INFO->DEF, $INFO->MID, $INFO->FOR, $INFO->RZ); foreach ($SORT as $STD) foreach ($STD as $v) mysql_query("UPDATE players_teams SET fieldposition = ".$nr++." WHERE player_id = {$v->player_id} AND team_id = {$v->team_id}") or die(mysql_error()); // CAPTAION mysql_query("UPDATE `teams` SET captain = '{$_POST['captain']}' WHERE `user_id` = {$_POST['userid']}") or die(mysql_error()); } transfers.php (containts the form that uses the javascript and link to the JS) I have really no idea how to structure the files and calls in cakephp. Currently I have "Undefined index: cmd [APP/vendors/remote.php, line 230]" errors since I use $_POST['cmd'] (I placed remote.php in Vendors and included it, the JS was just included old fashion way, as a link and appears in the source code). How can I make this work? I'm sorry but I'm not familiar with AJAX and Cake... If you want a full look at the code, here it is: http://octavian.be/thecode.zip Thank you for reading and helping me out.

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  • Trouble making login page?

    - by Ken
    Okay, so I want to make a simple login page. I've created a register page successfully, but i can't get the login thing down. login.php: <?php session_start(); include("mainmenu.php"); $usrname = mysql_real_escape_string($_POST['usrname']); $password = md5($_POST['password']); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } mysql_select_db("users", $con) or die(mysql_error()); $login = "SELECT * FROM `users` WHERE (usrname = '$usrname' AND password = '$password')"; $result = mysql_query($login); if(mysql_num_rows($result) == 1 { $_SESSION = true; header('Location: indexlogin.php'); } else { echo = "Wrong username or password." ; } ?> indexlogin.php just echoes "Login successful." What am I doing wrong? Oh, and just FYI- my database is "users" and my table is "data".

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  • How to troubleshoot memcache set method always fail issue?

    - by Morgan Cheng
    I have XAMPP 1.7.3 installed on Windows 7. The PHP version is 5.3.1. I have successfully installed memcache for win32 from http://www.splinedancer.com/memcached-win32. I got PHP extension php_memcache.dll from http://downloads.php.net/pierre. Restarting apache and checking phpinfo() shows memcache is OK. When I test it with below PHP page. It always fail in set method. <?php $memcache = new Memcache; $memcache->connect('127.0.0.1', 11211) or die ("Could not connect"); $version = $memcache->getVersion(); echo "Server's version: ".$version." \n"; $tmp_object = new stdClass; $tmp_object->str_attr = 'test'; $tmp_object->int_attr = 123; $memcache->set('key', $tmp_object, false, 10) or die ("Failed to save data at the server"); echo "Store data in the cache (data will expire in 10 seconds)\n"; $get_result = $memcache->get('key'); echo "Data from the cache: \n" ?> The set method always return false so it constantly output Server's version: Failed to save data at the server I'm stuck. I don't know which way to trouble shoot this issue. Anybody has any idea about possible direction? Thanks.

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  • exec() in BeanShell macro causes jEdit to hang when it returns non-zero exit code

    - by rossmeissl
    I have a jEdit BeanShell macro that runs my Markdown files through Maruku when I save them: if (buffer.getMode().toString().equals("markdown")) { cmd = "C:\\Ruby\\bin\\maruku.bat -o " + buffer.getDirectory() + buffer.getName().replaceAll("markdown$", "html") + " " + buffer.getPath(); exec(cmd); } This works great when the Markdown file is valid. But if I've made a mistake, jEdit just waits around forever for the exec() call to "succeed," which it never will. When this happens, I have to kill jEdit's javaw.exe process and run Maruku manually from the command line to discover the error, e.g.: E:\bp\plan\supply_chain>maruku business_plan.markdown ___________________________________________________________________________ | Maruku tells you: +--------------------------------------------------------------------------- | Could not find ref_id = "17" for md_link(["17"],"17") | Available refs are [] +--------------------------------------------------------------------------- !C:/Ruby/lib/ruby/gems/1.8/gems/maruku-0.6.0/lib/maruku/errors_management.rb:49:in `maruku_error' !C:/Ruby/lib/ruby/gems/1.8/gems/maruku-0.6.0/lib/maruku/output/to_html.rb:716:in `to_html_link' !C:/Ruby/lib/ruby/gems/1.8/gems/maruku-0.6.0/lib/maruku/output/to_html.rb:970:in `send' !C:/Ruby/lib/ruby/gems/1.8/gems/maruku-0.6.0/lib/maruku/output/to_html.rb:970:in `array_to_html' !C:/Ruby/lib/ruby/gems/1.8/gems/maruku-0.6.0/lib/maruku/output/to_html.rb:961:in `each' \___________________________________________________________________________ Not creating a link for ref_id = "17". Then I restart jEdit, fix the error, and re-save the file, at which point the macro succeeds. How can I make my macro more resilient to either die helpfully (display Maruku's error output) or, at the very least, die silently so I don't have to kill jEdit?

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  • What do I have to change in my PHP/CURL code to retrieve data from a https:// URL?

    - by Edward Tanguay
    I have a PHP file using CURL that accepts a Google Doc URL as a parameter, then returns the plain text of the Google Doc. It worked well until recently when apparently a redirect was added so that the http:// address redirects to the equivalent https:// address, as in this example: http://docs.google.com/View?id=dc7gj86r_20dn2csqg3 So I changed my code to access the https:// address, but it just returns blank. What do I have to change my CURL code so that I can get the HTML text from the https:// address? $url = filter_input(INPUT_GET, 'url',FILTER_SANITIZE_STRING); $validUrlPrefixes[] = "https://docs.google.com"; if(beginsWithOneOfThese($url, $validUrlPrefixes)) { $user_agent = 'Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 (.NET CLR 3.5.30729)'; $ch = curl_init(); curl_setopt($ch, CURLOPT_COOKIEJAR, "/tmp/cookie"); curl_setopt($ch, CURLOPT_COOKIEFILE, "/tmp/cookie"); curl_setopt($ch, CURLOPT_URL, $url ); curl_setopt($ch, CURLOPT_FAILONERROR, 1); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 0); curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); curl_setopt($ch, CURLOPT_TIMEOUT, 15); curl_setopt($ch, CURLOPT_USERAGENT, $user_agent); curl_setopt($ch, CURLOPT_VERBOSE, 0); $rawData = curl_exec($ch); $rawData = cleanText($rawData); if(beginsWith($url, "https://docs.google.com")) { echo qstr::convertGoogleDocContentToText($rawData); die; } echo $rawData; die;

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  • How to get MySQL database to appear on index.php

    - by Teddy Truong
    Hi, I have a submission form on my website (index.php) and I have the data(user submissions) being stored into a MySQL database. Right now, I have the user submitting a post and then the page directs them to an update.php which shows what they inputed. However, I want all of the data in the database in MySQL to be shown on the index.php. It's a lot like a comment system. User submits a post... and sees their post above the other submitted posts all on the same page. I think I'm missing AJAX... ? Here is the code for index.php <div align="center"> <p>&nbsp;</p> <h2 align="center" class="Title"><em><strong>REDACTED</strong></em></h2> <form id="form1" name="form1" method="post" action="update.php"> <hr /> <label><br /> <form action="update.php" method="post"> REDACTED: <input type="text" name="text" /> <input type="submit" /> </form> </label> </form> </div> On update.php I have this: ?php $text = $_POST['text']; $myString = "REDACTED"; mysql_connect ("db----.net", "-----3", "------------") or die ('Error: ' . mysql_error()); mysql_select_db ("-----------"); $query="INSERT INTO TextArea (ID, text) VALUES ('NULL', '".$text."')"; mysql_query($query) or die ('Error updating database'); echo " $myString "," $text "; ?> Thanks a lot!

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  • Double Slash at end of URL when going to HTTPS?

    - by J M 4
    My site currently uses http and https sections based on the data being collected on the site (form data uses https). On my index page, I have the PHP code at the top: <?php session_start(); ob_start(); if( $_SERVER['SERVER_PORT'] == 443) { header('Location:http://'.$_SERVER['HTTP_HOST'].dirname($_SERVER['PHP_SELF'])); die(); } ?> However, the page will not load and I get a 404 error. Similarly, when i visit the sections with https security using the head code: <?php session_start(); ob_start(); if( $_SERVER['SERVER_PORT'] == 80) { header('Location:https://'.$_SERVER['HTTP_HOST'].dirname($_SERVER['PHP_SELF']).'/'.basename($_SERVER['PHP_SELF'])); die(); } ?> The site does not respond AND for some reason creates a double slash when switching from http to https. Example: http://www.abc.com/, then clicking button which should route to enroll.php shows http://www.abc.com//enroll.php why the need for the double slash and can anybody help with the 404 errors?

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  • UTF-8 MySQL and Charset, pls help me understand this once and for all!

    - by FFish
    Can someone explain me when I set everything to UTF-8 I keep getting those damn ??? MySQL Server version: 5.1.44 MySQL charset: UTF-8 Unicode (utf8) I create a new database name: utf8test collation: utf8_general_ci MySQL connection collation: utf8_general_ci My SQL looks like this: SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO"; CREATE TABLE IF NOT EXISTS `test_table` ( `test_id` int(11) NOT NULL, `test_text` text NOT NULL, PRIMARY KEY (`test_id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; INSERT INTO `test_table` (`test_id`, `test_text`) VALUES (1, 'hééélo'), (2, 'wööörld'); My PHP / HTML: <?php $db_conn = mysql_connect("localhost", "root", "") or die("Can't connect to db"); mysql_select_db("utf8test", $db_conn) or die("Can't select db"); // $result = mysql_query("set names 'utf8'"); // this works... why?? $query = "SELECT * FROM test_table"; $result = mysql_query($query); $output = ""; while($row = mysql_fetch_assoc($result)) { $output .= "id: " . $row['test_id'] . " - text: " . $row['test_text'] . "<br />"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html lang="it" xmlns="http://www.w3.org/1999/xhtml" xml:lang="it"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>UTF-8 test</title> </head> <body> <?php echo $output; ?> </body> </html>

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  • AJAX Post Not Sending Data?

    - by Jascha
    I can't for the life of me figure out why this is happening. This is kind of a repost, so forgive me, but I have new data. I am running a javascript log out function called logOut() that has make a jQuery ajax call to a php script... function logOut(){ var data = new Object; data.log_out = true; $.ajax({ type: 'POST', url: 'http://www.mydomain.com/functions.php', data: data, success: function() { alert('done'); } }); } the php function it calls is here: if(isset($_POST['log_out'])){ $query = "INSERT INTO `token_manager` (`ip_address`) VALUES('logOutSuccess')"; $connection->runQuery($query); // <-- my own database class... // omitted code that clears session etc... die(); } Now, 18 hours out of the day this works, but for some reason, every once in a while, the POST data will not trigger my query. (this will last about an hour or so). I figured out the post data is not being set by adding this at the end of my script... $query = "INSERT INTO `token_manager` (`ip_address`) VALUES('POST FAIL')"; $connection->runQuery($query); So, now I know for certain my log out function is being skipped because in my database is the following data: if it were NOT being skipped, my data would show up like this: I know it is being skipped for two reasons, one the die() at the end of my first function, and two, if it were a success a "logOutSuccess" would be registered in the table. Any thoughts? One friend says it's a janky hosting company (hostgator.com). I personally like them because they are cheap and I'm a fan of cpanel. But, if that's the case??? Thanks in advance. -J

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  • pagination and url encoding help

    - by Sufyan
    <?php $name=$_POST['name']; ?> <form method="POST" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input type="text" name="name"> <input type="submit" value="GO" name="submit"> </form> <?php include ('db.php'); if(isset($_POST['submit'])) { mysql_query ("INSERT INTO example (name) VALUES('$name')") or die(mysql_error()); } if (!isset($_GET['startrow']) or !is_numeric($_GET['startrow'])) { $startrow = 0; } else { $startrow = (int)$_GET['startrow']; } $query = "SELECT * FROM example ORDER BY id DESC LIMIT $startrow, 20"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ echo "<li>"; echo $row['name'] ." "." <a href= 'like.php?quote=" . urlencode( $row['name'] ) . "'>Click Here</a>"; echo "</li>"; } echo '<a href="'.$_SERVER['PHP_SELF'].'?startrow='.($startrow+10).'">Next</a>'; ?> I want to make my page links hidden , how can i make then hidden so that a user cant edit it. 2nd question, currently i am showing total 10 records on each page and then a next page button , but the next button is keep showing even when there is no more records...! how to remove a next page button when records ended. ?? line number 28 is the link to pages which can be easyily editable by any user, i wnat to make them secure (using ID) and line 35 is n'next' page link , this link should not be appear when number of records ended

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  • How do you convert a parent-child (adjacency) table to a nested set using PHP and MySQL?

    - by mrbinky3000
    I've spent the last few hours trying to find the solution to this question online. I've found plenty of examples on how to convert from nested set to adjacency... but few that go the other way around. The examples I have found either don't work or use MySQL procedures. Unfortunately, I can't use procedures for this project. I need a pure PHP solution. I have a table that uses the adjacency model below: id parent_id category 1 0 ROOT_NODE 2 1 Books 3 1 CD's 4 1 Magazines 5 2 Books/Hardcover 6 2 Books/Large Format 7 4 Magazines/Vintage And I would like to convert it to a Nested Set table below: id left right category 1 1 14 Root Node 2 2 7 Books 3 3 4 Books/Hardcover 4 5 6 Books/Large Format 5 8 9 CD's 6 10 13 Magazines 7 11 12 Magazines/Vintage Here is an image of what I need: I have a function, based on the pseudo code from this forum post (http://www.sitepoint.com/forums/showthread.php?t=320444) but it doesn't work. I get multiple rows that have the same value for left. This should not happen. <?php /** -- -- Table structure for table `adjacent_table` -- CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'ROOT'), (2, 1, 'Books'), (3, 1, 'CD''s'), (4, 1, 'Magazines'), (5, 2, 'Hard Cover'), (6, 2, 'Large Format'), (7, 4, 'Vintage'); -- -- Table structure for table `nested_table` -- CREATE TABLE IF NOT EXISTS `nested_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `lft` int(11) DEFAULT NULL, `rgt` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; */ mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); adjacent_to_nested(0); /** * adjacent_to_nested * * Reads a "adjacent model" table and converts it to a "Nested Set" table. * @param integer $i_id Should be the id of the "root node" in the adjacent table; * @param integer $i_left Should only be used on recursive calls. Holds the current value for lft */ function adjacent_to_nested($i_id, $i_left = 0) { // the right value of this node is the left value + 1 $i_right = $i_left + 1; // get all children of this node $a_children = get_source_children($i_id); foreach ($a_children as $a) { // recursive execution of this function for each child of this node // $i_right is the current right value, which is incremented by the // import_from_dc_link_category method $i_right = adjacent_to_nested($a['id'], $i_right); // insert stuff into the our new "Nested Sets" table $s_query = " INSERT INTO `nested_table` (`id`, `lft`, `rgt`, `category`) VALUES( NULL, '".$i_left."', '".$i_right."', '".mysql_real_escape_string($a['category'])."' ) "; if (!mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } echo "<p>$s_query</p>\n"; // get the newly created row id $i_new_nested_id = mysql_insert_id(); } return $i_right + 1; } /** * get_source_children * * Examines the "adjacent" table and finds all the immediate children of a node * @param integer $i_id The unique id for a node in the adjacent_table table * @return array Returns an array of results or an empty array if no results. */ function get_source_children($i_id) { $a_return = array(); $s_query = "SELECT * FROM `adjacent_table` WHERE `father_id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } if (mysql_num_rows($i_result) > 0) { while($a = mysql_fetch_assoc($i_result)) { $a_return[] = $a; } } return $a_return; } ?> This is the output of the above script. INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '5', 'Hard Cover' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '7', 'Large Format' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '8', 'Books' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '10', 'CD\'s' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '10', '13', 'Vintage' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '14', 'Magazines' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '0', '15', 'ROOT' ) As you can see, there are multiple rows sharing the lft value of "1" same goes for "2" In a nested-set, the values for left and right must be unique. Here is an example of how to manually number the left and right ID's in a nested set: UPDATE - PROBLEM SOLVED First off, I had mistakenly believed that the source table (the one in adjacent-lists format) needed to be altered to include a source node. This is not the case. Secondly, I found a cached page on BING (of all places) with a class that does the trick. I've altered it for PHP5 and converted the original author's mysql related bits to basic PHP. He was using some DB class. You can convert them to your own database abstraction class later if you want. Obviously, if your "source table" has other columns that you want to move to the nested set table, you will have to adjust the write method in the class below. Hopefully this will save someone else from the same problems in the future. <?php /** -- -- Table structure for table `adjacent_table` -- DROP TABLE IF EXISTS `adjacent_table`; CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'Books'), (2, 0, 'CD''s'), (3, 0, 'Magazines'), (4, 1, 'Hard Cover'), (5, 1, 'Large Format'), (6, 3, 'Vintage'); -- -- Table structure for table `nested_table` -- DROP TABLE IF EXISTS `nested_table`; CREATE TABLE IF NOT EXISTS `nested_table` ( `lft` int(11) NOT NULL DEFAULT '0', `rgt` int(11) DEFAULT NULL, `id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`lft`), UNIQUE KEY `id` (`id`), UNIQUE KEY `rgt` (`rgt`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; */ /** * @class tree_transformer * @author Paul Houle, Matthew Toledo * @created 2008-11-04 * @url http://gen5.info/q/2008/11/04/nested-sets-php-verb-objects-and-noun-objects/ */ class tree_transformer { private $i_count; private $a_link; public function __construct($a_link) { if(!is_array($a_link)) throw new Exception("First parameter should be an array. Instead, it was type '".gettype($a_link)."'"); $this->i_count = 1; $this->a_link= $a_link; } public function traverse($i_id) { $i_lft = $this->i_count; $this->i_count++; $a_kid = $this->get_children($i_id); if ($a_kid) { foreach($a_kid as $a_child) { $this->traverse($a_child); } } $i_rgt=$this->i_count; $this->i_count++; $this->write($i_lft,$i_rgt,$i_id); } private function get_children($i_id) { return $this->a_link[$i_id]; } private function write($i_lft,$i_rgt,$i_id) { // fetch the source column $s_query = "SELECT * FROM `adjacent_table` WHERE `id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } $a_source = array(); if (mysql_num_rows($i_result)) { $a_source = mysql_fetch_assoc($i_result); } // root node? label it unless already labeled in source table if (1 == $i_lft && empty($a_source['category'])) { $a_source['category'] = 'ROOT'; } // insert into the new nested tree table // use mysql_real_escape_string because one value "CD's" has a single ' $s_query = " INSERT INTO `nested_table` (`id`,`lft`,`rgt`,`category`) VALUES ( '".$i_id."', '".$i_lft."', '".$i_rgt."', '".mysql_real_escape_string($a_source['category'])."' ) "; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } else { // success: provide feedback echo "<p>$s_query</p>\n"; } } } mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); // build a complete copy of the adjacency table in ram $s_query = "SELECT `id`,`father_id` FROM `adjacent_table`"; $i_result = mysql_query($s_query); $a_rows = array(); while ($a_rows[] = mysql_fetch_assoc($i_result)); $a_link = array(); foreach($a_rows as $a_row) { $i_father_id = $a_row['father_id']; $i_child_id = $a_row['id']; if (!array_key_exists($i_father_id,$a_link)) { $a_link[$i_father_id]=array(); } $a_link[$i_father_id][]=$i_child_id; } $o_tree_transformer = new tree_transformer($a_link); $o_tree_transformer->traverse(0); ?>

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  • Account activation PHP

    - by Wayne
    I created this account registration activation script of my own, I have checked it over again and again to find errors, I don't see a particular error... The domain would be like this: http://domain.com/include/register.php?key=true&p=AfRWDCOWF0BO6KSb6UmNMf7d333gaBOB Which comes from an email, when a user clicks it, they get redirected to this script: if($_GET['key'] == true) { $key = $_GET['p']; $sql = "SELECT * FROM users WHERE user_key = '" . $key . "'"; $result = mysql_query($sql) or die(mysql_error()); if(mysql_affected_rows($result) > 0) { $sql = "UPDATE users SET user_key = '', user_active = '1' WHERE user_key = '" . $key . "'"; $result = mysql_query(sql) or die(mysql_error()); if($result) { $_SESSION['PROCESS'] = $lang['Account_activated']; header("Location: ../index.php"); } else { $_SESSION['ERROR'] = $lang['Key_error']; header("Location: ../index.php"); } } else { $_SESSION['ERROR'] = $lang['Invalid_key']; header("Location: ../index.php"); } } It doesn't even work at all, I looked in the database with the user with that key, it matches but it keeps coming up as an error which is extremely annoying me. The database is right, the table and column is right, nothing wrong with the database, it's the script that isn't working. Help me out, guys. Thanks :)

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  • POSTmethod and PHP- login verification

    - by Neethusha
    I wrote a code for login verification..I got output with GET. But i need output with POST since it is more secure.pls let me know if there is any error in my code. javascript code: var xml; function verifyusernamepasswd(pass) { //pass is password that will be passed as parameter xml=new XMLHttpRequest(); var url="http://localhost/loginvalidate.php"; var para="q="+username+"&p="+pass;//username is global xml.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xml.setRequestHeader("Content-length", para.length); xml.setRequestHeader("Connection", "close"); xml.open("POST",url,true); xml.onreadystatechange=statechanged1; xml.send(para); } function statechanged1() { if(xml.readyState==4) alert(xml.responseText); } php code: <?php $username=$_POST["q"]; $password=$_POST["p"]; $con=mysql_connect("localhost","root","blaze"); if(!$con) { die('Could not connect: '.mysql.error()); } mysql_select_db("BLAZE",$con) or die("No such Db"); $result=mysql_query("SELECT Passwword FROM USERTABLE WHERE Userhandle='$username'"); if($result==null) echo "false"; else if($result!=null) { $row=mysql_fetch_array($result); if((strcmp($row['Passwword'],$password)==0)) echo "true"; else echo "false"; } ?> the verification does not return anything, cos my alert is not displayed at all...pls tell me whats wrong....

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  • OUTPUT DID NOT REDIRECT TO THE INTENDED FILE OPENED FOR..

    - by rockyurock
    HELLO ALL, I USED THE BELOW CODE FOR CAPTURING THE OUTPUT (BELOW IN lines) IN A FILE "my_output.txt" BUT FAILED TO CAPTURE. **************output*************** inside value loop ------------------------------------------------------------ Server listening on UDP port 5001 Receiving 1470 byte datagrams UDP buffer size: 108 KByte (default) ------------------------------------------------------------ [ 3] local 192.168.16.2 port 5001 connected with 192.168.16.1 port 3189 [ ID] Interval Transfer Bandwidth Jitter Lost/Total Datagrams [ 3] 0.0- 5.0 sec 2.14 MBytes 3.61 Mbits/sec 0.369 ms 0/ 1528 (0%) inside value loop3 clue1 clue2 inside value loop4 one iperf completed *************************************** however when i enabled the local *STDOUT; in below code then i could see the above output on command prompt display (ofcourse server is sending some data). could anybody suggest me how can i capture the o/p in a file intended? below is the code i am using .. my $file = 'my_output.txt'; use Win32::Process; print"inside value loop\n"; # redirect stdout to a file #local *STDOUT; open STDOUT, '>', $file or die "can't redirect STDOUT to <$file> $!"; Win32::Process::Create(my $ProcessObj, "D:\\IOT_AUTOMATION_UTILITY\\_SATURDAY_09-04-10\\adb_cmd.bat", "adb shell /data/app/iperf -u -s -p 5001", 0, NORMAL_PRIORITY_CLASS, ".") || die ErrorReport(); #$alarm_time = $IPERF_RUN_TIME+10; #20sec #$ProcessObj->Wait(40); #print"inside value loop2\n"; #sleep $alarm_time; sleep 40; $ProcessObj->Kill(0); sub ErrorReport{ print Win32::FormatMessage( Win32::GetLastError() ); } /rocky

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  • PHP: Join two separate mysql queries into the same json data object

    - by Dan
    I'm trying to mesh the below mysql query results into a single json object, but not quite sure how to do it properly. //return data $sql_result = mysql_query($sql,$connection) or die ("Fail."); $arr = array(); while($obj = mysql_fetch_object($sql_result)) { $arr[] = $obj; } echo json_encode($arr); //return json //plus the selected options $sql_result2 = mysql_query($sql2,$connection) or die ("Fail."); $arr2 = array(); while($obj2 = mysql_fetch_object($sql_result2)) { $arr2[] = $obj2; } echo json_encode($arr2); //return json Here's the current result: [{"po_number":"test","start_date":"1261116000","end_date":"1262239200","description":"test","taa_required":"0","account_overdue":"1","jobs_id":null,"job_number":null,"companies_id":"4","companies_name":"Primacore Inc."}][{"types_id":"37"},{"types_id":"4"}] Notice how the last section [{"types_id":"37"},{"types_id":"4"}] is placed into a separate chunk under root. I'm wanting it to be nested inside the first branch under a name like, "types". I think my question has more to do with Php array manipulation, but I'm not the best with that. Thank you for any guidance.

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  • JVM GC demote object to eden space?

    - by Kevin
    I'm guessing this isn't possible...but here goes. My understanding is that eden space is cheaper to collect than old gen space, especially when you start getting into very large heaps. Large heaps tend to come up with long running applications (server apps) and server apps a lot of the time want to use some kind of caches. Caches with some kind of eviction (LRU) tend to defeat some assumptions that GC makes (temporary objects die quickly). So cache evictions end up filling up old gen faster than you'd like and you end up with a more costly old gen collection. Now, it seems like this sort of thing could be avoided if java provided a way to mark a reference as about to die (delete keyword)? The difference between this and c++ is that the use is optional. And calling delete does not actually delete the object, but rather is a hint to the GC that it should demote the object back to Eden space (where it will be more easily collected). I'm guessing this feature doesn't exist, but, why not (is there a reason it's a bad idea)?

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  • regular expression code

    - by Gaia Andreoletti
    Deal all, I need to find match between two tab delimited files files like this: File 1: ID1 1 65383896 65383896 G C PCNXL3 ID1 2 56788990 55678900 T A ACT1 ID1 1 56788990 55678900 T A PRO55 File 2 ID2 34 65383896 65383896 G C MET5 ID2 2 56788990 55678900 T A ACT1 ID2 2 56788990 55678900 T A HLA what I would like to do is to retrive the matching line between the two file. What I would like to match is everyting after the gene ID So far I have written this code but unfortunately perl keeps giving me the error: use of "Use of uninitialized value in pattern match (m//)" Could you please help me figure out where i am doing it wrong? Thank you in advance! use strict; open (INA, $ARGV[0]) || die "cannot to open gene file"; open (INB, $ARGV[1]) || die "cannot to open coding_annotated.var files"; my @sample1 = <INA>; my @sample2 = <INB>; foreach my $line (@sample1) { my @tab = split (/\t/, $line); my $chr = $tab[1]; my $start = $tab[2]; my $end = $tab[3]; my $ref = $tab[4]; my $alt = $tab[5]; my $name = $tab[6]; foreach my $item (@sample2){ my @fields = split (/\t/,$item); if ($fields[1]=~ m/$chr(.*)/ && $fields[2]=~ m/$start(.*)/ && $fields[4]=~ m/$ref(.*)/ && $fields[5]=~ m/$alt(.*)/&& $fields[6]=~ m/$name(.*)/){ print $line,"\n",$item; } } }

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  • PHP: MySQL query duplicating update for no reason

    - by ThinkingInBits
    The code below is first the client code, then the class file. For some reason the 'deductTokens()' method is calling twice, thus charging an account double. I've been programming all night, so I may just need a second pair of eyes: if ($action == 'place_order') { if ($_REQUEST['unlimited'] == 200) { $license = 'extended'; } else { $license = 'standard'; } if ($photograph->isValidPhotographSize($photograph_id, $_REQUEST['size_radio'])) { $token_cost = $photograph->getTokenCost($_REQUEST['size_radio'], $_REQUEST['unlimited']); $order = new ImageOrder($_SESSION['user']['id'], $_REQUEST['size_radio'], $license, $token_cost); $order->saveOrder(); $order->deductTokens(); header('location: account.php'); } else { die("Please go back and select a valid photograph size"); } } ######CLASS CODE####### <?php include_once('database_classes.php'); class Order { protected $account_id; protected $cost; protected $license; public function __construct($account_id, $license, $cost) { $this->account_id = $account_id; $this->cost = $cost; $this->license = $license; } } class ImageOrder extends Order { protected $size; public function __construct($account_id, $size, $license, $cost) { $this->size = $size; parent::__construct($account_id, $license, $cost); } public function saveOrder() { //$db = Connect::connect(); //$account_id = $db->real_escape_string($this->account_id); //$size = $db->real_escape_string($this->size); //$license = $db->real_escape_string($this->license); //$cost = $db->real_escape_string($this->cost); } public function deductTokens() { $db = Connect::connect(); $account_id = $db->real_escape_string($this->account_id); $cost = $db->real_escape_string($this->cost); $query = "UPDATE accounts set tokens=tokens-$cost WHERE id=$account_id"; $result = $db->query($query); } } ?> When I die("$query"); directly after the query, it's printing the proper statement, and when I run that query within MySQL it works perfectly.

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