Search Results

Search found 6679 results on 268 pages for 'echo'.

Page 28/268 | < Previous Page | 24 25 26 27 28 29 30 31 32 33 34 35  | Next Page >

  • What’s wrong with this code

    - by Arlen Beiler
    I get this error for the code below, what does it mean? [Fri Apr 23 10:57:42 2010] [error] [client 10.0.0.1] PHP Fatal error: Cannot re-assign $this in C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\abp\fol\test.php on line 27, referer: http://abp.bhc.com/fol/ <?php $voiceboxes = array( '141133' => array( 'title' => 'Title', '1' => array( 'Title' => 'Title2', 'Link' => 'http://...', ), '12' => array( 'Title' => 'Title3', 'Link' => 'http://...', ) ), '1070453' => array( 'title' => 'Title4', '1' => array( 'Title' => 'Title5', 'Link' => 'http://...', ) ) ); $last = 0; //$this = 0; echo "<ol>\n"; foreach ($voiceboxes as $key => $value) { $last = 0; $this = null; //Error is thrown here, Line 27 //$voiceboxes[$key]['title'] echo "<ol>\n"; foreach ($value as $key2 => $value2) { if ($key2 == 'title') { echo "<li>$value2</li>\n"; } else { $this = (int) $key2; if ($this == $last + 1) { echo '<li>'; } else { '<li value="' . $key2 . '">';} $last = $key2; echo $voiceboxes[$key][$key2]['Title'] . "<br/>" . $voiceboxes[$key][$key2]['Link'] . '</li>' . "\n"; } } echo "</ol>\n"; }

    Read the article

  • jQuery ajax link, returned data includes a from that wont submit

    - by calumogg
    Hi everyone, I have a problem with the returned data from a ajax request. Basically when I click on a link it runs a ajax request to load some html into a div, that part is working fine the problem comes when the data has been loaded. Part of the html loaded is a form, this form works fine if I load the page directly but when it is loaded through ajax into the div it wont submit but the rest of the links in the html work fine. Here is the code that requests the remote html data: // Ajax to load image editing page $('a.editpicture').click(function(e) { e.preventDefault(); var picture = $(this).attr("id") $.ajax({ url: 'http://localhost/digital-xposure/index.php/members/viewpicture/' + picture, success: function(data) { $('#update-picture').html(data); } }); }); This is the form it loads: <form method="post" id="updatepicture" name="updatepicture" action="http://localhost/digital-xposure/index.php/members/editpicture"/> <p>Title<input type="text" name="title" id="title" style="input" value="<?php echo $title; ?>"></P> <p>Album<?php echo $albums;?></p> <p>Description<textarea name="description" id="description" cols="50" rows="5"><?php echo $description; ?></textarea></P> <input type="hidden" name="filename" id="filename" value="<?php echo $filename; ?>" /> <input type="button" name="update-submit" id="update-submit" value="Update details" class="button"> Or <input type="button" onClick="location.href='<?php echo base_url(); ?>index.php/members/deletepicture/<?php echo $filename; ?>'" value="Delete picture" class="button"> </form> Any ideas why the form wont submit after being loaded into the div? Any help is greatly appreciated, thanks. Calum

    Read the article

  • How to include multiple tables programmaticaly into a Sweave document using R

    - by PaulHurleyuk
    Hello, I want to have a sweave document that will include a variable number of tables in. I thought the example below would work, but it doesn't. I want to loop over the list foo and print each element as it's own table. % \documentclass[a4paper]{article} \usepackage[OT1]{fontenc} \usepackage{longtable} \usepackage{geometry} \usepackage{Sweave} \geometry{left=1.25in, right=1.25in, top=1in, bottom=1in} \listfiles \begin{document} <<label=start, echo=FALSE, include=FALSE>>= startt<-proc.time()[3] library(RODBC) library(psych) library(xtable) library(plyr) library(ggplot2) options(width=80) #Produce some example data, here I'm creating some dummy dataframes and putting them in a list foo<-list() foo[[1]]<-data.frame(GRP=c(rep("AA",10), rep("Aa",10), rep("aa",10)), X1=rnorm(30), X2=rnorm(30,5,2)) foo[[2]]<-data.frame(GRP=c(rep("BB",10), rep("bB",10), rep("BB",10)), X1=rnorm(30), X2=rnorm(30,5,2)) foo[[3]]<-data.frame(GRP=c(rep("CC",12), rep("cc",18)), X1=rnorm(30), X2=rnorm(30,5,2)) foo[[4]]<-data.frame(GRP=c(rep("DD",10), rep("Dd",10), rep("dd",10)), X1=rnorm(30), X2=rnorm(30,5,2)) @ \title{Docuemnt to test putting a variable number of tables into a sweave Document} \author{"Paul Hurley"} \maketitle \section{Text} This document was created on \today, with \Sexpr{print(version$version.string)} running on a \Sexpr{print(version$platform)} platform. It took approx \input{time} sec to process. <<label=test, echo=FALSE, results=tex>>= cat("Foo") @ that was a test, so is this <<label=table1test, echo=FALSE, results=tex>>= print(xtable(foo[[1]])) @ \newpage \subsection{Tables} <<label=Tables, echo=FALSE, results=tex>>= for(i in seq(foo)){ cat("\n") cat(paste("Table_",i,sep="")) cat("\n") print(xtable(foo[[i]])) cat("\n") } #cat("<<label=endofTables>>= ") @ <<label=bye, include=FALSE, echo=FALSE>>= endt<-proc.time()[3] elapsedtime<-as.numeric(endt-startt) @ <<label=elapsed, include=FALSE, echo=FALSE>>= fileConn<-file("time.tex", "wt") writeLines(as.character(elapsedtime), fileConn) close(fileConn) @ \end{document} Here, the table1test chunk works as expected, and produced a table based on the dataframe in foo[[1]], however the loop only produces Table(underscore)1.... Any ideas what I'm doing wrong ?

    Read the article

  • Unable to set variables in bash script in Mac OSX

    - by cohortq
    Hello! I am attempting to automate moving files from a folder to a new folder automatically every night using a bash script run from applescript on a schedule. I am attempting to write a bash script on Mac OSX, and it keeps failing. In short this is what I have (all my ECHOs are for error checking): !/bin/bash folder = "ABC" useracct = 'test' day = date "+%d" month = date "+%B" year = date "+%Y" folderToBeMoved = "/users/$useracct/Documents/Archive/Primetime.eyetv" newfoldername = "/Volumes/Media/Network/$folder/$month$day$year" ECHO "Network is $network" $network ECHO "day is $day" ECHO "Month is $month" ECHO "YEAR is $year" ECHO "source is $folderToBeMoved" ECHO "dest is $newfoldername" mkdir $newfoldername cp -R $folderToBeMoved $newfoldername if [-f $newfoldername/Primetime.eyetv]; then rm $folderToBeMoved; fi Now my first problem is that I cannot set variables at all. Even literal ones where I just make it equal some literal. All my echos come out blank. I cannot grab the day, month, or year either,it comes out blank as well. I get an error saying that -f is not found. I get an error saying there is an unexpected end of file. I made the file and did a chmod u+x scriptname.sh I'm not sure why nothing is working at all. I am very new to this bash script on OSX, and only have experience with windows vbscript. Any help would be great, thanks!

    Read the article

  • How to generate Thumbnails with phpThumb and save it into a file?

    - by CuSS
    Hi all, i wan't to know how to generate thumbnails with phpThumb Class, with an array with file paths already. And then Save the result of each image on other path but with the same name. Thank you all ;) EDIT: I have my code something like this: echo "A iniciar gerador de miniaturas para a área de cliente: \n"; include $wincli['files']['phpThumbClass']; $files = file_list($wincli['dirs']['logos']); $phpThumb = new phpThumb(); foreach( $files as $file ) { echo " # A converter o ficheiro '".basename($file)."' : "; if(is_file($file)){ $phpThumb->setSourceFilename($file); $phpThumb->setParameter('w', 880); $phpThumb->setParameter('h', 241); $phpThumb->setParameter('q', 90); $phpThumb->setParameter('zc', 1); $outputFilename = $wincli['dirs']['logosthumbs'].$file; if($phpThumb->GenerateThumbnail()){ if($phpThumb->RenderToFile($outputFilename)){ echo "OK \n"; }else{ echo "Falhou (Ao guardar no ficheiro)\n"; } }else{ echo "Falhou (Ao gerar miniatura)\n"; } }else{ echo "Falhou (Ficheiro inexistente)\n"; } }

    Read the article

  • php ftp upload problem

    - by Autobyte
    Hi I am trying to write a small php function that will upload files to an FTP server and I keep getting the same error but I cannot find any fix by googling the problem, I am hoping you guys can help me here... The error I get is: Warning: ftp_put() [function.ftp-put]: Unable to build data connection: No route to host in . The file was created at the FTP server but it is zero bytes. Here is the code: <?php $file = "test.dat"; $ftp_server="ftp.server.com"; $ftp_user = "myname"; $ftp_pass = "mypass"; $destination_file = "test.dat"; $cid=ftp_connect($ftp_server); if(!$cid) { exit("Could not connect to server: $ftp_server\n"); } $login_result = ftp_login($cid, $ftp_user, $ftp_pass); if (!$login_result) { echo "FTP connection has failed!"; echo "Attempted to connect to $ftp_server for user $ftp_user"; exit; } else { echo "Connected to $ftp_server, for user $ftp_user"; } $upload = ftp_put($cid, $destination_file, $file, FTP_BINARY); if (!$upload) { echo "Failed upload for $source_file to $ftp_server as $destination_file<br>"; echo "FTP upload has failed!"; } else { echo "Uploaded $source_file to $ftp_server as $destination_file"; } ftp_close($cid); ?>

    Read the article

  • The Select query I am using is not working.. Can Somebody Guide me to the Correct way?

    - by Parth
    I am using the Select query as SELECT id, ordering FROM `jos_menu` WHERE ordering='".$rec['ordering'] -'1' ."' AND parent = '0' Here I need all the records whose ordering is less than 1 of the selected record's order($rec['ordering'] = getting from other select query ) when I am trying to echo the query I am not getting complete statement but getting only this -1' AND parent = '0' here is the whole snippet $where = ' WHERE (id = ' . implode( ' OR id = ', $cid ) . ')';//Pranav Dave Coded echo $selquery = "SELECT id, ordering FROM `jos_menu`".$where; //Pranav Dave Coded $db->setQuery( $selquery );//Pranav Dave Coded $record = $db->loadAssocList(); //Pranav Dave Coded if ($model->orderItem($id, -1)) { echo "<pre>"; print_r($model); /*exit;*/ //echo $updorderup = mysql_escape_string($model->_db->_sql);//Pranav Dave Coded foreach($record as $rec)//Pranav Dave Coded { echo $aboverow = "SELECT id, ordering FROM `jos_menu` WHERE ordering='".$rec['ordering'] -'1' ."' AND parent = '0'"; $db->setQuery( $aboverow ); $above = $db->loadAssoc(); echo "<pre>"; print_r($above); }//end of foreach }//end of if Please suggest me where I am getting wrong.....

    Read the article

  • Bash and regex problem : check for tokens entered into a Coke vending machine

    - by Michael Mao
    Hi all: Here is a "challenge question" I've got from Linux system programming lecture. Any of the following strings will give you a Coke if you kick: L = { aaaa, aab, aba, baa, bb, aaaa"a", aaaa"b", aab"a", … ab"b"a, ba"b"a, ab"bbbbbb"a, ... } The letters shown in wrapped double quotes indicate coins that would have fallen through (but those strings are still part of the language in this example). Exercise (a bit hard) show this is the language of a regular expression And this is what I've got so far : #!/usr/bin/bash echo "A bottle of Coke costs you 40 cents" echo -e "Please enter tokens (a = 10 cents, b = 20 cents) in a sequence like 'abba' :\c" read tokens #if [ $tokens = aaaa ]||[ $tokens = aab ]||[ $tokens = bb ] #then # echo "Good! now a coke is yours!" #else echo "Thanks for your money, byebye!" if [[ $token =~ 'aaaa|aab|bb' ]] then echo "Good! now a coke is yours!" else echo "Thanks for your money, byebye!" fi Sadly it doesn't work... always outputs "Thanks for your money, byebye!" I believe something is wrong with syntax... We didn't provided with any good reference book and the only instruction from the professor was to consult "anything you find useful online" and "research the problem yourself" :( I know how could I do it in any programming language such as Java, but get it done with bash script + regex seems not "a bit hard" but in fact "too hard" for anyone with little knowledge on something advanced as "lookahead"(is this the terminology ?) I don't know if there is a way to express the following concept in the language of regex: Valid entry would consist of exactly one of the three components : aaaa, aab and bb, regardless of order, followed by an arbitrary sequence of a or b's So this is what is should be like : (a{4}Ua{2}bUb{2})(aUb)* where the content in first braces is order irrelevant. Thanks a lot in advance for any hints and/or tips :)

    Read the article

  • Modify shell script to monitor/ping multiple ip addresses

    - by Alex
    Alright so I need to constantly monitor multiple routers and computers, to make sure they remain online. I have found a great script here that will notify me via growl(so i can get instant notifications on my phone) if a single ip cannot be pinged. I have been attempting to modify the script to ping multiple addresses, with little luck. I'm having trouble trying to figure out how to ping a down server while the script keeps watching the online servers. any help would be greatly appreciated. I haven't done much shell scripting so this is quite new to me. Thanks #!/bin/sh #Growl my Router alive! #2010 by zionthelion73 [at] gmail . com #use it for free #redistribute or modify but keep these comments #not for commercial purposes iconpath="/path/to/router/icon/file/internet.png" # path must be absolute or in "./path" form but relative to growlnotify position # document icon is used, not document content # Put the IP address of your router here localip=192.168.1.1 clear echo 'Router avaiability notification with Growl' #variable avaiable=false com="################" #comment prefix for logging porpouse while true; do if $avaiable then echo "$com 1) $localip avaiable $com" echo "1" while ping -c 1 -t 2 $localip do sleep 5 done growlnotify -s -I $iconpath -m "$localip is offline" avaiable=false else echo "$com 2) $localip not avaiable $com" #try to ping the router untill it come back and notify it while !(ping -c 1 -t 2 $localip) do echo "$com trying.... $com" sleep 5 done echo "$com found $localip $com" growlnotify -s -I $iconpath -m "$localip is online" avaiable=true fi sleep 5 done

    Read the article

  • Dropdown in PHP

    - by VP
    Hi, I am using PHP 5.2 on SUN OS server. Having problems with the following piece of code that for a drop down: echo '<form action="" method="get">'; echo '<p>Information:<br />'; echo '<select name="acctno" style="width: 100px;">'; foreach ($this->account_names as $acctno => $acctname) { echo '<option value="'.$acctno.'">'.$acctname.'</option>'; } echo '</select> <input type="submit" value="view" />'; echo '</form>'; Worked perfectly fine on Firefox and Chrome; however there is a problem with Internet Explorer. In IE the dropdown width is limited to the size i.e 100px. So only the first 15-16 characters of the account name are displayed all the time. However in chrome or firefox, even if only 15-16 characters are displayed initially, when the drop down arrow is clicked upon, it show the entire name (however long it may be). This does not happen with IE. So if the account name is, lets say, "1223456789abcdefghijkl" then: For IE: shows only "123456789" all the time Ffor chrome or firefox: shows "123456789" and when it is dropped down it show the full name as "123456789abcdefghijkl". Any help here would be much appreciated. Thanks, VP

    Read the article

  • How can I add my desired links to be read using PHP Universal FeedParser

    - by lightingwrist
    Hello, I have been trying to use the PHP Universal FeedParser to read RSS feeds and display the output on my site. Problem is I am VERY green with this and although it seems very simple. the only link that is working is the link provided in the sample. When I try to add another address with the xml or rss.php extensions, I keep getting errors,the page is loading blank,or the designated area for the feeds is blank. In addition to this, how can I add multiple links to feeds in a syntactically correct manor and how can I limit the amount of feeds? Thank you Here it is: <?php require_once($_SERVER['DOCUMENT_ROOT'] . '/includes/system/FeedParser.php'); $Parser = new FeedParser(); $Parser->parse("http://www.sitepoint.com/rss.php"); $channels = $Parser->getChannels(); $items = $Parser->getItems(); ?> and then: <div id="rss_feeder"> <h1 id="title"><a href="<?php echo $channels['LINK']; ?>"><?php echo $channels['TITLE']; ?></a></h1> <p id="description"><?php echo $channels['DESCRIPTION']; ?> </p> <?php foreach($items as $item): ?> <a class="feed-title" href="<?php echo $item['LINK']; ?>"><?php echo $item['TITLE']; ?></a> <p class="feed-description"><?php echo $item['DESCRIPTION']; ?></p> <?php endforeach;?> </div>

    Read the article

  • [ZF & jQuery] How can I access an URL using AJAX, receive no response, but just manipulate HTML?

    - by rasouza
    I don't know if it's better used with AJAX (tell me, otherwise) but here is my problem: Assuming i'm using Zend Framework, I have a table with several registries from a database with a delete button on each row. That's like this [...] <tbody> <?php foreach ($row as $reg) { ?> <tr <?php if ($reg['value'] < 0) { echo "class='error'"; } ?>> <td><?php echo $reg['creditor'] ?></td> <td><?php echo $reg['debtor'] ?></td> <td><?php echo $reg['reason'] ?></td> <td>R$ <?php echo number_format(abs($reg['value']), 2, ',', ' ')?></td> <td><a href="#" id="<?php echo $reg['id']; ?>" class="delete"><img src="http://192.168.0.102/libraries/css/blueprint/plugins/buttons/icons/cross.png" alt=""/></a></td> </tr> <?php } ?> </tbody> [...] I would like to .fadeOut() and delete (through the link history/delete/id/ROW_ID ) a table row when clicked in the respective delete button. My deleteAction() has no render. It really shouldn't have one, it just deletes a row in the database. Still, how can I make it happen? I tried: // TR Fading when deleted $('.delete') .click(function() { $.ajax({ type: 'GET', url: 'history/delete/id/'+$(this).attr('id'), success: function() { $(this).parent().parent().fadeOut(); } }); return false; }); without success

    Read the article

  • foreach() error handling - how do make it do nothing?

    - by Jared
    Hey all, This should be very basic, but I am a little stumped! Here is my array: $menu = array( 'Home', 'Stuff'=>array( 'Losta Stuff', 'Less Stuff', 'Ur moms stuff', 'FAQ' ), 'Public Works' ); Here is my logic: echo "<ol>\n"; foreach( (array)$menu as $header ) { echo ' <li><b>'.$header."</b><br />\n"; echo ' <ol>'; foreach( (array)$header as $headers ) { echo ' <li>'.$headers.".</li>\n"; } echo ' </ol>'; } echo "</ol>\n"; As you can see, Home and Public Works don't have data in the them, so I get a Warning: Invalid argument supplied for foreach() in test.php on line ## If I add (array) to $header like this: foreach( (array)$header as $headers ), It no longer gives me the error, but it just displays the $header as the $headers (i.e. Home - Home, Instead of Home - nothing). Basically, if the data is empty, I want it to do nothing!

    Read the article

  • use php to parse json data posted from another php file

    - by akshay.is.gr8
    my web hosting has blocked the outward traffic so i am using a free web hosting to read data and post it to my server but the problem is that my php file receives data in the $_REQUEST variable but is not able to parse it. post.php function postCon($pCon){ //echo $pCon; $ch = curl_init('http://localhost/rss/recv.php'); curl_setopt ($ch, CURLOPT_POST, 1); curl_setopt ($ch, CURLOPT_POSTFIELDS, "data=$pCon"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $d=curl_exec ($ch); echo $d."<br />"; curl_close ($ch); } recv.php <?php if(!json_decode($_REQUEST['data'])) echo "json error"; echo "<pre>"; print_r($data); echo "</pre>"; ?> every time it gives json error. but echo $_REQUEST['data'] gives the correct json data. plz help.

    Read the article

  • upload picture to and send path to database

    - by opa.mido
    I am trying to upload picture and link it to my database and I used the codes below : Upload2.php <?php // Check if a file has been uploaded if(isset($_FILES['uploaded_file'])) { // Make sure the file was sent without errors if($_FILES['uploaded_file']['error'] == 0) { // Connect to the database $dbLink = new mysqli('localhost', 'root', '1234', 'fyp'); if(mysqli_connect_errno()) { die("MySQL connection failed: ". mysqli_connect_error()); } // Gather all required data $name = $dbLink->real_escape_string($_FILES['uploaded_file']['name']); $mime = $dbLink->real_escape_string($_FILES['uploaded_file']['type']); $data = $dbLink->real_escape_string(file_get_contents($_FILES ['uploaded_file']['tmp_name'])); $size = intval($_FILES['uploaded_file']['size']); // Create the SQL query $query = " INSERT INTO `pic` ( `Name`, `size`, `data`, `created` ) VALUES ( '{$name}', '{$mime}', {$size}, '{$data}', NOW() )"; // Execute the query $result = $dbLink->query($query); // Check if it was successfull if($result) { echo 'Success! Your file was successfully added!'; } else { echo 'Error! Failed to insert the file' . "<pre>{$dbLink->error}</pre>"; } } else { echo 'An error accured while the file was being uploaded. ' . 'Error code: '. intval($_FILES['uploaded_file']['error']); } // Close the mysql connection $dbLink->close(); } else { echo 'Error! A file was not sent!'; } // Echo a link back to the main page echo '<p>Click <a href="index.html">here</a> to go back</p>'; ?> I reached the last stage and its give error a file was not sent I don't know where I have missed. thank you

    Read the article

  • Magento Replacing super attributes table with dropdown

    - by thrice801
    Hi, I am trying to replace my magento super attributes table with a drop down menu in place of it, Ive got the menu created but I am struggling to get it to actually use the data from the select dropdown. On submit it calls up function productAddToCartForm, which I feel like if I could modify, I could figure it out. But I have no idea where that function is. My php code looks like the following. <?php if (count($_associatedProducts)): ?> <select name="selectedSku"> <?php foreach ($_associatedProducts as $_item): ?> <?php $prodname = $this->htmlEscape($_item->getName()); $prodprice = $this->htmlEscape($_item->getPrice()); $prodcolor = $_item->getFullColor(); $prodsize = $_item->getTopSize(); $prodcombined = $prodname; $prodcombined .= " / "; $prodcombined .= $prodprice; echo "<option "; echo "value ='"; echo $_item->getId(); echo "'>"; echo $prodcombined; echo "</option>"; ?> <?php endforeach; ?> </select> Any help would be much appreciated. Thanks!

    Read the article

  • facebook open graph meta property og:type of 'website'. The property 'object-name' requires an object of og:type 'object-name'

    - by chinmayahd
    in cake php 1.3 in view ctp i have follow code: $url = 'http://example.com/exmp/explus/books/view/'.$book['Book']['id']; echo $this->Html->meta(array('property' => 'fb:app_id', 'content' => '*******'),'',array('inline'=>false)); echo $this->Html->meta(array('property' => 'og:type', 'content' => 'book'),'',array('inline'=>false)); echo $this->Html->meta(array('property' => 'og:url', 'content' => $url ),'',array('inline'=>false)); echo $this->Html->meta(array('property' => 'og:title', 'content' => $book['Book']['title']),'',array('inline'=>false)); echo $this->Html->meta(array('property' => 'og:description', 'content' => $book['Book']['title']),'',array('inline'=>false)); $imgurl = '../image/'.$book['Book']['id']; echo $this->Html->meta(array('property' => 'og:image', 'content' => $imgurl ),'',array('inline'=>false)); ?> and it gives the following error when i am posting it' { "error": { "message": "(#3502) Object at URL http://example.com/exmp/explus/books/view/234' has og:type of 'website'. The property 'book' requires an object of og:type 'book'. ", "type": "OAuthException", "code": 3502 } } is any one know how to solve it?

    Read the article

  • PHP Facebook Cronjob with offline access

    - by Mohamed Salem
    1:the code to greet the user, ask for his permission and store his session data so that we can use a cronjob with his session data afterwards. <?php $db_server = "localhost"; $db_username = "username"; $db_password = "password"; $db_name = "databasename"; #go to line 85, the script actually starts there mysql_connect($db_server,$db_username,$db_password); mysql_select_db($db_name); #you have to create a database to store session values. #if you do not know what columns there should be look at line 76 to see column names. #make them all varchars # Now lets load the FB GRAPH API require './facebook.php'; // Create our Application instance. global $facebook; $facebook = new Facebook(array( 'appId' => '121036530138', 'secret' => '9bbec378147064', 'cookie' => false,)); # Lets set up the permissions we need and set the login url in case we need it. $par['req_perms'] = "friends_about_me,friends_education_history,friends_likes, friends_interests,friends_location,friends_religion_politics, friends_work_history,publish_stream,friends_activities, friends_events, friends_hometown,friends_location ,user_interests,user_likes,user_events, user_about_me,user_status,user_work_history,read_requests, read_stream,offline_access,user_religion_politics,email,user_groups"; $loginUrl = $facebook->getLoginUrl($par); function save_session($session){ global $facebook; # OK lets go to the database and see if we have a session stored $sid=mysql_query("Select access_token from facebook_user WHERE uid =".$session['uid']); $session_id=mysql_fetch_row($sid); if (is_array($session_id)) { # We have a stored session, but is it valid? echo " We have a session, but is it valid?"; try { $attachment = array('access_token' => $session_id[0]); $ret_code=$facebook->api('/me', 'GET', $attachment); } catch (Exception $e) { # We don't have a good session so echo " our old session is not valid, let's delete saved invalid session data "; $res = mysql_query("delete from facebook_user WHERE uid =".$session['uid']); #save new good session #to see what is our session data: print_r($session); if (is_array($session)) { $sql="insert into facebook_user (session_key,uid,expires,secret,access_token,sig) VALUES ('".$session['session_key']."','".$session['uid']."','". $session['expires']."','". $session['secret'] ."','" . $session['access_token']."','". $session['sig']."');"; $res = mysql_query($sql); return $session['access_token']; } # this should never ever happen echo " Something is terribly wrong: Our old session was bad, and now we cannot get the new session"; return; } echo " Our old stored session is valid "; return $session_id[0]; } else { echo " no stored session, this means the user never subscribed to our application before. "; # let's store the session $session = $facebook->getSession(); if (is_array($session)) { # Yes we have a session! so lets store it! $sql="insert into facebook_user (session_key,uid,expires,secret,access_token,sig) VALUES ('".$session['session_key']."','".$session['uid']."','". $session['expires']."','". $session['secret'] ."','". $session['access_token']."','". $session['sig']."');"; $res = mysql_query($sql); return $session['access_token']; } } } #this is the first meaningful line of this script. $session = $facebook->getSession(); # Is the user already subscribed to our application? if ( is_null($session) ) { # no he is not #send him to permissions page header( "Location: $loginUrl" ); } else { #yes, he is already subscribed, or subscribed just now #in case he just subscribed now, save his session information $access_token=save_session($session); echo " everything is ok"; # write your code here to do something afterwards } ?> error Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/content/28/9687528/html/ss/src/indexx.php:1) in /home/content/28/9687528/html/ss/src/facebook.php on line 49 Fatal error: Call to undefined method Facebook::getSession() in /home/content/28/9687528/html/ss/src/indexx.php on line 86 2:A cronjob template that reads the stored session of a user from database, uses his session data to work on his behalf, like reading status posts or publishing posts etc. <?php $db_server = "localhost"; $db_username = "username"; $db_password = "pass"; $db_name = "database"; # Lets connect to the Database and set up the table $link = mysql_connect($db_server,$db_username,$db_password); mysql_select_db($db_name); # Now lets load the FB GRAPH API require './facebook.php'; // Create our Application instance. global $facebook; $facebook = new Facebook(array( 'appId' => 'appid', 'secret' => 'secret', 'cookie' => false, )); function get_check_session($uidCheck){ global $facebook; # This function basically checks for a stored session and if we have one it returns it # OK lets go to the database and see if we have a session stored $sid=mysql_query("Select access_token from facebook_user WHERE uid =".$uidCheck); $session_id=mysql_fetch_row($sid); if (is_array($session_id)) { # We have a session # but, is it valid? try { $attachment = array('access_token' => $session_id[0],); $ret_code=$facebook->api('/me', 'GET', $attachment); } catch (Exception $e) { # We don't have a good session so echo " User ".$uidCheck." removed the application, or there is some other access problem. "; # let's delete stored data $res = mysql_query("delete from facebook_user where WHERE uid =".$uidCheck); return; } return $session_id[0]; } else { # "no stored session"; echo " error:newsFeedcrontab.php No stored sessions. This should not have happened "; } } # get all users that have given us offline access $users = getUsers(); foreach($users as $user){ # now for each user, check if they are still subscribed to our application echo " Checking user".$user; $access_token=get_check_session($user); # If we've not got an access_token we actually need to login. # but in the crontab, we just log the error, there is no way we can find the user to give us permission here. if ( is_null($access_token) ) { echo " error: newsFeedcrontab.php There is no access token for the user ".$user." "; } else { #we are going to read the newsfeed of user. There are user's friends' posts in this newsfeed try{ $attachment = array('access_token' => $access_token); $result=$facebook->api('/me/home', 'GET', $attachment); }catch(Exception $e){ echo " error: newsfeedcrontab.php, cannot get feed of ".$user.$e; } #do something with the result here #but what does the result look like? #go to http://developers.facebook.com/docs/reference/api/user/ and click on the "home" link under connections #we can also read the home of user. Home is the wall of the user who has given us offline access. try{ $attachment = array('access_token' => $access_token); $result=$facebook->api('/me/feed', 'GET', $attachment); }catch(Exception $e){ echo " error: newsfeedcrontab.php, cannot get wall of ".$user.$e; } #do something with the result here # #but what does the result look like? #go to http://developers.facebook.com/docs/reference/api/user/ and click on the "feed" link under connections } } function getUsers(){ $sql = "SELECT distinct(uid) from facebook_user Where 1"; $result = mysql_query($sql); while($row = mysql_fetch_array($result)){ $rows [] = $row['uid']; } print_r($rows); return $rows; } mysql_close($link); ?> error Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/content/28/9687528/html/ss/src/cron.php:1) in /home/content/28/9687528/html/ss/src/facebook.php on line 49 Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/content/28/9687528/html/ss/src/cron.php on line 110 Warning: Invalid argument supplied for foreach() in /home/content/28/9687528/html/ss/src/cron.php on line 64

    Read the article

  • What is the space character for the browser?

    - by Hiro Protagonist
    echo "\n\s\s\s\s\s\s" . "<div id='data-load' data-load='" . $load . "'></div>"; \n works for adding a return in...I tried \s logically for space but this does not work. Keep mind, I don't want this rendered in the browser view...but in the source view ( when you click view-source )...I'm trying to put my html in to a readable form. echo "&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp\n" . "<div id='data-path' data-path='" . $path . "'></div>"; This does not work either. I am composing HTML from PHP... echo " \n" . "<div id='data-load' data-load='" . $load . "'></div>"; This does not work either. Actual Code: public static function setUniversals() { $shared_object = new Shared(); if ( $shared_object->getLoadOn() == 1 ) { $load = 'server'; } else { $load = 'client'; } if( getcwd() === '/home/foo/public_html/develop' ) { $path = 'development'; } else { $path = 'production'; } $shared_object = new Shared(); echo "\n"; echo "\n " . "<div id='data-path' data-path='" . $path . "'></div>"; echo "\n " . "<div id='data-load' data-load='" . $load . "'></div>"; }

    Read the article

  • Parsing the Youtube API with DOM

    - by Kirk
    I'm using the Youtube API and I can retrieve the date information without a problem, but don't know how to retrieve the description information. My Code: <?php $v = "dQw4w9WgXcQ"; $url = "http://gdata.youtube.com/feeds/api/videos/". $v; $doc = new DOMDocument; $doc->load($url); $pub = $doc->getElementsByTagName("published")->item(0)->nodeValue; $desc = $doc->getElementsByTagName("media:description")->item(0)->nodeValue; echo "<b>Video Uploaded:</b> "; echo date( "F jS, Y", strtotime( $pub ) ); echo '<br>'; if (isset ($desc)) { echo "<b>Description:</b> "; echo $desc; echo '<br>'; } ?> Here's a link to the feed: http://gdata.youtube.com/feeds/api/videos/dQw4w9WgXcQ?prettyprint=true And the excerpt of code I don't know how to retrieve data from: <media:group> <media:description type='plain'>Music video by Rick Astley performing Never Gonna Give You Up. (C) 1987 PWL</media:description> </media:group> Thanks in advance.

    Read the article

  • How can I change a form's input value with javascript

    - by Biroka
    How can I change a form's input value with javascript depending on witch combobox item is selected. I have a form with some imported values, and there is a field of witch imported value can be changed via a combobox. In my case: print("<input type='hidden' name='issue_array[{$issue["nr"]}][\"supplier\"]' value='{$issue["supplier"]}' />"); I have a combobox, that if I change it's value, should change the value of the input above. This is what I tried: print("<select name='supplier_combo' onchange='setSupplierInputValue(this.value, ${issue['nr']})'>"); and the script: echo "\r\n" . '<SCRIPT TYPE="text/javascript">' . "\r\n"; echo 'function setSupplierInputValue(value, issue_nr)' . "\r\n"; echo '{' . "\r\n"; echo ' issue_array[issue_nr]["supplier"] = value;'; echo '}' . "\r\n"; echo '</SCRIPT>'. "\r\n"; But it doesn't work, please help.

    Read the article

  • Folder permission and submit button

    - by bob
    I want to create a simple installation script. Below are simple code. <ul> <?php function check_perms($path,$perm) { clearstatcache(); $configmod = substr(sprintf('%o', fileperms($path)), -4); $css = (($configmod != $perm) ? " class='error r2'" : " class='none'"); echo "<li".$css.">\n"; echo '<span style="float:left; padding-right:20px;">'.$path.'</span>'; echo '<span style="float:right; width:100px; text-align:right;"> <strong>'.$perm.'</strong></span>'; echo '<span style="float:right; padding-right:100px;"><strong>'.$configmod.'</strong></span>'; echo '<div class="clear"></div>'; echo "</li>"; } check_perms("config.php","0777"); check_perms("themes","0777"); check_perms("themes/images","0777"); check_perms("useruploads","0777"); ?> </ul> How to make if all file and folder is valid permission to 777 will appear Submit button. <input type='submit' name='submit' value='Submit' /> If there still have incorrect permission do not show the Submit button Let me know.

    Read the article

  • PHP date returning wrong time

    - by gargantaun
    The following script is returning the wrong time after I call date_default_timezone_set("UTC") <?PHP $timestamp = time(); echo "<p>Timestamp: $timestamp</p>"; // This returns the correct time echo "<p>". date("Y-m-d H:i:s", $timestamp) ."</p>"; echo "<p>Now I call 'date_default_timezone_set(\"UTC\")' and echo out the same timestamp.</p>"; echo "Set timezone = " . date_default_timezone_set("UTC"); // This returns a time 5 hours in the past echo "<p>". date("Y-m-d H:i:s", $timestamp) ."</p>"; ?> The timezone on the server is BST. So what should happen is that the second call to 'date' should return a time 1 hour behind the first call. It's actually returning a time 5 hours behind the first one. I should note that the server was originally set up with the EDT timezone (UTC -4). That was changed to BST (UTC +1) and the server was restarted. I can't figure out if this is a PHP problem or a problem with the server.

    Read the article

  • Why doesn't this PHP execute?

    - by cam
    I copied the code from this site exactly: http://davidwalsh.name/web-service-php-mysql-xml-json as follows, /* require the user as the parameter */ if(isset($_GET['user']) && intval($_GET['user'])) { /* soak in the passed variable or set our own */ $number_of_posts = isset($_GET['num']) ? intval($_GET['num']) : 10; //10 is the default $format = strtolower($_GET['format']) == 'json' ? 'json' : 'xml'; //xml is the default $user_id = intval($_GET['user']); //no default /* connect to the db */ $link = mysql_connect('localhost','username','password') or die('Cannot connect to the DB'); mysql_select_db('db_name',$link) or die('Cannot select the DB'); /* grab the posts from the db */ $query = "SELECT post_title, guid FROM wp_posts WHERE post_author = $user_id AND post_status = 'publish' ORDER BY ID DESC LIMIT $number_of_posts"; $result = mysql_query($query,$link) or die('Errant query: '.$query); /* create one master array of the records */ $posts = array(); if(mysql_num_rows($result)) { while($post = mysql_fetch_assoc($result)) { $posts[] = array('post'=>$post); } } /* output in necessary format */ if($format == 'json') { header('Content-type: application/json'); echo json_encode(array('posts'=>$posts)); } else { header('Content-type: text/xml'); echo '<posts>'; foreach($posts as $index => $post) { if(is_array($post)) { foreach($post as $key => $value) { echo '<',$key,'>'; if(is_array($value)) { foreach($value as $tag => $val) { echo '<',$tag,'>',htmlentities($val),'</',$tag,'>'; } } echo '</',$key,'>'; } } } echo '</posts>'; } /* disconnect from the db */ @mysql_close($link); } And the php doesn't execute, it just displays as plain text. What's the dealio? The host supports PHP, I use it to run a Wordpress blog and other things.

    Read the article

  • confirm alert not working ....

    - by user318068
    I want the work of the Control Panel in my site for members ... I designed the page is displayed all the registered members on my site And i but it checkbox front each member name ,becuase it allowed to select multiple name then click delete button The following code works but now i want confirm alert before delete code working even , if clicked on ok the deletion is working , and if clicked on cancel the is not working .. how i can work it ?? while($row = mysql_fetch_array($sql1)) { ?> <tr> <td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<?php echo $row['MemberID']; ?>"></td> <td bgcolor="#FFFFFF"><?php echo $row['MemberName']; ; ?></td></tr> <?php } ?> <tr> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="delete" onclick="javascript:return confirm('are you sure to delete this record???? ')"/></td> </tr> <?php $delete = $_REQUEST['delete']; $checkbox = $_REQUEST['checkbox']; $count = count($_REQUEST['checkbox']); // Check if delete button active, start this if($delete){ echo "<script language=\"Javascript\">\n"; for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $sql = "Delete FROM members where MemberID ='$del_id'"; $sq2 = "Delete FROM joinroom where MemberID ='$del_id'"; $result1 = mysql_query($sql); $result2 = mysql_query($sq2); echo "else {\n"; echo "alert ('Nothing deleted');\n }"; echo "</script>"; } } Thanks a lot.........

    Read the article

< Previous Page | 24 25 26 27 28 29 30 31 32 33 34 35  | Next Page >