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  • JavaScript - string regex backreferences

    - by quano
    You can backreference like this in JavaScript: var str = "123 $test 123"; str = str.replace(/(\$)([a-z]+)/gi, "$2"); This would (quite silly) replace "$test" with "test". But imagine I'd like to pass the resulting string of $2 into a function, which returns another value. I tried doing this, but instead of getting the string "test", I get "$2". Is there a way to achieve this? // Instead of getting "$2" passed into somefunc, I want "test" // (i.e. the result of the regex) str = str.replace(/(\$)([a-z]+)/gi, somefunc("$2"));

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  • Using RegEx to replace invalid characters

    - by yeahumok
    Hello I have a directory with lots of folders, subfolder and all with files in them. The idea of my project is to recurse through the entire directory, gather up all the names of the files and replace invalid characters (invalid for a SharePoint migration). However, i'm completely unfamiliar with Regular Expressions. The characters i need to get rid in filenames are: ~, #, %, &, *, { } , \, /, :, <, ?, -, | and "" I want to replace these characters with a blank space. I was hoping to use a string.replace() method to look through all these file names and do the replacement. So far, the only code i've gotten to is the recursion. I was thinking of the recursion scanning the drive, fetching the names of these files and putting them in a List. Can anybody help me with how to find/replace invalid chars with RegEx with those specific characters?

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  • RegEXP Javascript URL matching

    - by Blondie
    I have this so far: chrome.tabs.getSelected(null, function(tab) { var title = tab.title; var btn = '<a href="' + tab.url + '" onclick="save(\'' + title + '\');"> ' + title + '</a>'; if(RegExp('/http:\/\/www.mydomain.com\/version.php/i') == true) { document.getElementById('link').innerHTML = '<p>' + btn + '</p>'; } }); Basically it should match the domain within this: http://www.mydomain.com/version.php?* Anything that matches that even when it includes something like version.php?ver=1, etc When I used the code above of mine, it doesn't display anything, but when I remove the if statement, it's fine but it shows on other pages which it shouldn't only on the matched URL.

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  • Regex to replace relative link with root relative link

    - by Kendall Hopkins
    I have a string of text that contains html with all different types of links (relative, absolute, root-relative). I need a regex that can be executed by PHP's preg_replace to replace all relative links with root-relative links, without touching any of the other links. I have the root path already. Replaced links: <tag ... href="path/to_file.ext" ... > ---> <tag ... href="/basepath/path/to_file.ext" ... > Untouched links: <tag ... href="/any/path" ... > <tag ... href="protocol://domain.com/any/path" ... >

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  • java.util.regex.Pattern matching the beginning of a String

    - by Pierre
    Hi all, Is it possible to know if a stream/string contains an input that could match a regular expression. For example String input="AA"; Pattern pat=Pattern.compile("AAAAAB"); Matcher matcher=pat.matcher(input); //<-- something here returning true ? or String input="BB"; Pattern pat=Pattern.compile("AAAAAB"); Matcher matcher=pat.matcher(input); //<-- something here returning false ? Thanks

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  • PHP regex to match sentences that contain a year

    - by zen
    I need a regular expression that will extract sentences from text that contain a year in them. Example text: Next, in 1988 the Bradys were back again for a holiday celebration, "A Very Brady Christmas". Susan Olsen (Cindy) would be missing from this reunion, Jennifer Runyon took her place. This was a two hour movie in which the Bradys got together to celebrate Christmas, introducing the world to the spouses and children of the Brady kids. This movie was the highest rated TV-movie of 1988. If the example text was variable $string, I need it to return: $sentenceWithYear[0] = Next, in 1988 the Bradys were back again for a holiday celebration, "A Very Brady Christmas". $sentenceWithYear[1] = This movie was the highest rated TV-movie of 1988. If it's possible to retain the year via regex, I'd use the year within the sentence and eventually insert the sentences into a database like: INSERT INTO table_name (year, sentence) VALUES ('$year', '$sentenceWithYear[x]')

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  • java Regular expression matching html

    - by user121196
    I want to match and capture the enclosing content of the <pre></pre> tag tried the following, not working, what's wrong? String p="<pre>.*</pre>"; Matcher m=Pattern.compile(p,Pattern.MULTILINE|Pattern.CASE_INSENSITIVE).matcher(input); if(m.find()){ String g=m.group(0); System.out.println("g is "+g); }

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  • regex to match trailing whitespace, but not lines which are entirely whitespace (indent placeholders

    - by Tim
    I've been trying to construct a ruby regex which matches trailing spaces - but not indentation placeholders - so I can gsub them out. I had this /\b[\t ]+$/ and it was working a treat until I realised it only works when the line ends are [a-zA-Z]. :-( So I evolved it into this /(?!^[\t ]+)[\t ]+$/ and it seems like it's getting better, but it still doesn't work properly. I've spent hours trying to get this to work to no avail. Please help. Here's some text test so it's easy to throw into Rubular, but the indent lines are getting stripped so it'll need a few spaces and/or tabs. Once lines 3 & 4 have spaces back in, it shouldn't match on lines 3-5, 7, 9. some test test some test test some other test (text) some other test (text) likely here{ dfdf } likely here{ dfdf } and this ; and this ; Alternatively, is there an simpler / more elegant way to do this?

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  • Help with password complexity regex

    - by Alex
    I'm using the following regex to validate password complexity: /^.*(?=.{6,12})(?=.*[0-9]{2})(?=.*[A-Z]{2})(?=.*[a-z]{2}).*$/ In a nutshell: 2 lowercase, 2 uppercase, 2 numbers, min length is 6 and max length is 12. It works perfectly, except for the maximum length, when I'm using a minimum length as well. For example: /^.*(?=.{6,})(?=.*[0-9]{2})(?=.*[A-Z]{2})(?=.*[a-z]{2}).*$/ This correctly requires a minimum length of 6! And this: /^.*(?=.{,12})(?=.*[0-9]{2})(?=.*[A-Z]{2})(?=.*[a-z]{2}).*$/ Correctly requires a maximum length of 12. However, when I pair them together as in the first example, it just doesn't work!! What gives? Thanks!

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  • Problem with Regex in .NET (C#)

    - by Craig Bovis
    I'm trying to write a a regex to validate a string to match the following rules. Must start with a-z (case insensitive) Must only contain a-z A-Z 0-9 . - I've put something together based on my limited knowledge and ran it through an online testing tool for a whole bunch of situations and the results were as I had hoped however when I place the pattern into my .NET code it doesn't match correctly. The pattern I am using is, [a-zA-Z][a-zA-Z0-9.\-]* Is this the correct pattern or am I barking up the wrong tree? Some examples of what I'm expecting. craig.bovis - VALID 24craig - INVALID craig@bovis - INVALID craig24 - VALID -craig24 - INVALID craig24.bovis-test - VALID

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  • help with regex pattern

    - by noname
    i have multiple strings containing a link like: <A HREF="http://www.testings2">testings2</A> <A HREF="http://www.blabla">blabla</A> <A HREF="http://www.gowick">gowick</A> i want to use a regex pattern that gets the uri within the href. i could do like: /".*?"/ but then the "" will come along. is there a way to just get the uri within the HREF="" without using preg_replace function? thanks!

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  • How to make regex variables to capture of routes

    - by Zephiro
    anyone can help me with this problem. example $uri = '/username/carlos'; => $routes[] = '/username/@name'; @name convert in variable $name capturing string "carlos" $routes[] = '/list/edit/@id:[0-9]{3}'; $routes[] = '/username/@name'; $routes[] = '/archive/*'; $routes[] = '/'; $uri = '/username/carlos'; foreach ( $routes as $pattern ) { if ( preg_match( '#^' . preg_replace( '#(?:{{)?@(\w+\b)(?:}})?#i', '(?P<\1>[\w\-\.!~\*\'"(),\s]+)', str_replace( '\*', '(.*)', preg_quote( $pattern, '/' ) ) ) . '\/?$#i', $uri, $matchs ) ) { //how to make regex for this to work : echo $name; // carlos =>$uri = '/username/carlos'; or matt => $uri = '/username/matt'; } } thanks for reading

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  • Javascript Regex to convert dot notation to bracket notation

    - by Tauren
    Consider this javascript: var joe = { name: "Joe Smith", location: { city: "Los Angeles", state: "California" } } var string = "{name} is currently in {location.city}, {location.state}"; var out = string.replace(/{([\w\.]+)}/g, function(wholematch,firstmatch) { return typeof values[firstmatch] !== 'undefined' ? values[firstmatch] : wholematch; }); This will output the following: Joe Smith is currently in {location.city}, {location.state} But I want to output the following: Joe Smith is currently in Los Angeles, California I'm looking for a good way to convert multiple levels of dot notation found between braces in the string into multiple parameters to be used with bracket notation, like this: values[first][second][third][etc] Essentially, for this example, I'm trying to figure out what regex string and function I would need to end up with the equivalent of: out = values[name] + " is currently in " + values["location"]["city"] + values["location"]["state"];

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  • How to improve my Python regex syntax?

    - by FarmBoy
    I very new to Python, and fairly new to regex. (I have no Perl experience.) I am able to use regular expressions in a way that works, but I'm not sure that my code is particularly Pythonic or consise. For example, If I wanted to read in a text file and print out text that appears directly between the words 'foo' and 'bar' in each line (presuming this occurred one or zero times a line) I would write the following: fileList = open(inFile, 'r') pattern = re.compile(r'(foo)(.*)(bar)') for line in fileList: result = pattern.search(line) if (result != None): print result.groups()[1] Is there a better way? The if is necessary to avoid calling groups() on None. But I suspect there is a more concise way to obtain the matching String when there is one, without throwing errors when there isn't. I'm not hoping for Perl-like unreadability. I just want to accomplish this common task in the commonest and simplest way.

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  • MySQL REGEXP: matching blank entries

    - by Erwin Paglinawan
    Hi, I have this SQL condition that is supposed to retrieve all rows that satisfy the given regexp condition: country REGEXP ('^(USA|Italy|France)$') However, I need to add a pattern for retrieving all blank country values. Currently I am using this condition country REGEXP ('^(USA|Italy|France)$') OR country = "" How can achieve the same effect without having to include the OR clause? Thanks, Erwin

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  • RegEx: Split String at Capitalized Letters and Non-capitalized letters to Create Small Cap Fonts

    - by Otaku
    So i've purposefully stayed away from RegEx as just looking at it kills me...ugh. But now I need it and could really use some help to do this in .NET (C# or VB.NET). I need to split a string based on capitalization or lack thereof. For example: I'm not upPercase "I" "'m not up" "P" "ercase" or FBI Agent Winters "FBI A" "gent " "W" "inters" The reason I'm doing this is to manually create small caps, in which non-capitalized strings will be sent to uppercase and their font size made 80% of the original font size. Appreciate any help that could be provided here.

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  • RegEx to extract all HTML tag attributes including inline JavaScript

    - by Mike
    I found this useful regex code here while looking to parse HTML tag attributes: (\S+)=["']?((?:.(?!["']?\s+(?:\S+)=|[>"']))+.)["']? It works great, but it's missing one key element that I need. Some attributes are event triggers that have inline Javascript code in them like this: onclick="doSomething(this, 'foo', 'bar');return false;" Or: onclick='doSomething(this, "foo", "bar");return false;' I can't figure out how to get the original expression to not count the quotes from the JS (single or double) while it's nested inside the set of quotes that contain the attribute's value.

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  • Add / remove a port number to/from a URL with REGEX in PHP

    - by SuperDuck
    Hello guys, I've searched but was unable to find an existing regex function. Has anybody done this before? I wish to add a port number, or remove a potantially existing one from a url in php. To use in some functions which translate a given url to the secure one, unsecure one, etc. Now I need a second SSL secured site on the server so I need to dynamically add a port number while converting http to https, and remove any port number while converting from https to http. Thanks, Duck

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  • Perl regex matching output from `w -hs` command

    - by Bushman
    I'm trying to write a Perl script that will work better with KDE's kwrited, which, as far as I can tell, is connected to a pts and puts every line it receives through the KDE system tray notifications, with the title "KDE write daemon". Unfortunately, it makes a separate notification for each and every line, so it spams up the system tray with multiline messages on regular old write, and for some reason it cuts off the entire last line of the message when using wall (One-line messages are also goners.). I was also hoping to make it so that it could broadcast across a LAN with thick clients. Before starting on that (which would require ssh, of course), I tried to make an ssh-less version to make sure it works. Unfortunately, it doesn't. perl ./write.pl "Testing 1 2 3" where the following is the contents of ./write.pl: #!/usr/bin/perl use strict; use warnings; my $message = ""; my $device = ""; my $possibledevice = '`w -hs | grep "/usr/bin/kwrited"`'; #Where is kwrited? $possibledevice =~ s/^[^\t][\t]//; $possibledevice =~ s/[\t][^\t][\t ]\/usr\/bin\/kwrited$//; $possibledevice = '/dev/'.$possibledevice; unless ($possibledevice eq "") { $device = $possibledevice; } if ($ARGV[0] ne "") { $message = $ARGV[0]; $device = $ARGV[1]; } else { $device = $ARGV[0] unless $ARGV[0] eq ""; while (<STDIN>) { chomp; $message .= <STDIN>; } } if ($message ne "") { system "echo \'$message\' > $device"; } else { print "Error: empty message" } produces the following error: $ perl write.pl "Testing 1 2 3" Use of uninitialized value $device in concatenation (.) or string at write.pl line 29. sh: -c: line 0: syntax error near unexpected token `newline' sh: -c: line 0: `echo 'foo' > ' Somehow, the regular expressions and/or the backtick escape in processing $possibledevice are not working properly, because where kwrited is connected to /dev/pts/0, the following works perfectly: $ perl write.pl "Testing 1 2 3" /dev/pts/0

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  • Regex to match 2 things in 1 HTML file

    - by CyberK
    Hi, I have a HTML file which contains the following: <img src="MATCH1" bla="blabla"> <something:else bla="blabla" bla="bla"><something:else2 something="something"> <something image="MATCH2" bla="abc"> Now I need a regex to match both MATCH1 and MATCH2 Also the HTML contains multiple parts like this, so it can be in the HTML 1, 2, 3 of x times.. When I say: <img\s*src="(.*?)".*?<something\s*image="(.*?)" It doesn't match it. What am I missing here? Thanks in advance!

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  • Matching a date in perl

    - by Zerobu
    Hello, I want to match a date in the format day/month/year. where day is two digits month is two digits and year is four digits. Also, I want to check see if it is a valid date, for example knows when is leap year, and know which month has 30days, 31days and 28, or 29 days for Februrary.

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  • Regex & BBCode - Perfecting Nested Quote

    - by Moe
    Hey there, I'm working on some BBcode for my website. I've managed to get most of the codes working perfectly, however the [QUOTE] tag is giving me some grief. When I get something like this: [QUOTE=1] [QUOTE=2] This is a quote from someone else [/QUOTE] This is someone else quoting someone else [/QUOTE] It will return: > 1 said: [QUOTE=2]This is a quote from > someone else This is someone else quoting someone else[/QUOTE] So what is happening is the [/quote] from the nested quote is closing the quote block. The Regex I am using is: "[quote=(.*?)\](.*?)\[/quote\]'is" How can I make it so nested Quotes will appear properly? Thank you.

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