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• PHP regex help -- reverse search?

  - by Ian Silber

  So, I have a regex that searches for HTML tags and modifies them slightly. It's working great, but I need to do something special with the last closing HTML tag I find. Not sure of the best way to do this. I'm thinking some sort of reverse reg ex, but haven't found a way to do that. Here's my code so far: $html = "<div id="test"><p style="hello_world">This is a test.</p></div>"; $pattern = array('/<([A-Z][A-Z0-9]*)(\b[^>]*)>/i'); $replace = array('<tag>'); $html = preg_replace($pattern,$replace,$html); // Outputs: <tag><tag>This is a test</p></div> I'd like to replace the last occurance of "" with something special, say for example, "". Any ideas?

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• Best way to reverse bitmap data that is upside down

  - by Wladimir

  Hello, I have a method that I call and it returns bitmap data from a capture device. It returns a pointer to the buffer data as an IntPtr and the buffer length as an int. I know in advance that this bitmap is a 24bpp and its width and height. The problem is that the buffer contains the bitmap data upside down and I need this data to be in the right order (reverse it). What I do is create a for loop and using CopyMemory, I copy each line (stride) of this data from bottom to up to a newly allocated memory space. Is there any way to make it faster than creating more memory each time I receive a new frame? It makes the application get a bit slow and consumes more memory as each bitmap is pretty big. I do this because I use another component that analyses the bitmaps and it doesn't work propertly if the bitmaps are upside down. I'm using .net, c# thanks!

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• How to create list of numbers and append its reverse to it efficiently in Ruby

  - by Kiwi

  Given a minimum integer and maximum integer, I want to create an array which counts from the minimum to the maximum by two, then back down (again by two, repeating the maximum number). For example, if the minimum number is 1 and the maximum is 9, I want [1, 3, 5, 7, 9, 9, 7, 5, 3, 1]. I'm trying to be as concise as possible, which is why I'm using one-liners. In Python, I would do this: range(1, 10, 2) + range(9, 0, -2) In Ruby, which I'm just beginning to learn, all I've come up with so far is: (1..9).inject([]) { |r, num| num%2 == 1 ? r << num : r }.reverse.inject([]) { |r, num| r.unshift(num).push(num) } Which works, but I know there must be a better way. What is it?

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• Twitter API + OAuth - 401 error developing locally using reverse SSH tunnel

  - by oliland

  I'm developing a django application which lets users connect their Twitter account. As I'm developing locally, I have set up a reverse SSH tunnel so that the Twitter API has a valid callback url (myserver.net): ssh -nNTR :6969:localhost:8000 myserver.net On successful authentication, Twitter passes back its OAuth access tokens to myserver.net, which in turn attempts to access Twitter's API, which returns a 401 error. I assume that because the callback is different to the address which is accessing the API (myserver.net / localhost), Twitter denies me access. I have tried this: export http_proxy="http://myserver.net:3128" Where myserver.net:3128 is running a Squid Proxy server to tunnel Twitter's API requests from my development machine so they appear to be coming from myserver, but receive the same 401 error. When I deploy to a server with a proper hostname / static IP address it works fine. What else do I need to do?

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• NTLM Authentication fails ONLY with IE against 2k8 App server behind 2k8 IIS7 Reverse Proxy

  - by CptSkippy

  I'm developing an ASP.NET application for an intranet site that is using Windows/NTLM/WIA/whatever authentication. The application is hosted on a Windows 2k8 server but is accessed through a Reverse Proxy using IIs7 on another 2k8 machine. Authentication works fine in FireFox, Chrome and Safari but fails in IE8. If I circumvent the Proxy and access the application server directly then it works fine so it has something to do with proxy. There's nothing in the Event Viewer on any of the 3 machines to indicate what might be happening. If you connect using IE8 it prompts for your credentials instead of automatically passing them, yes I've setup an explicit trust over an above the domain trust, but it still errors out with a 401 error returned from the proxy. Any ideas where to start troubleshooting this?

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• Howto Plot "Reverse" Cumulative Frequency Graph With ECDF

  - by neversaint

  I have no problem plotting the following cumulative frequency graph plot like this. library(Hmisc) pre.test <- rnorm(100,50,10) post.test <- rnorm(100,55,10) x <- c(pre.test, post.test) g <- c(rep('Pre',length(pre.test)),rep('Post',length(post.test))) Ecdf(x, group=g, what="f", xlab='Test Results', label.curves=list(keys=1:2)) But I want to show the graph in forms of the "reverse" cumulative frequency of values x ? (i.e. something equivalent to what="1-f"). Is there a way to do it? Other suggestions in R other than using Hmisc are also very much welcomed.

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• How can I reverse ruby's include function.

  - by Glen

  I'll explain what i'm looking for in code as thats probably the most succinct: module Mixin def method puts "Foo" end end class Whatever include Mixin end w = Whatever.new w.method => "Foo" # some magic here w2 = Whatever.new w.method => NoMethodError I had tried just undefining the Mixin module using remove_const, but this doesn't seem to make any difference to Whatever. I had assumed that #include just added a reference to the module into the class's method resolution chain - but this behaviour doesn't agree with that. Can anyone tell me what include actually does behind the scenes, and how to reverse this?

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• recursively reverse linked list.

  - by Amanda

  I am implementing a function to recursively reverse a linked-list, but getting seg-fault. typedef struct _node { int data; struct _node *next; } Node, *NodeP; NodeP recursiveReverseList(NodeP first){ if(first == NULL) return NULL; if(first->next == NULL) return head; NodeP rest = recursiveReverseList(head->next); rest->next = first; first->next = NULL; return first; } Can you please help. P.S. The iterative version is working fine though. Its not homework. Just practicing C.

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• Creating a New Reverse Java Array

  - by mandir08

  Given an array of ints length 3, return a new array with the elements in reverse order, so {1, 2, 3} becomes {3, 2, 1}. public int[] reverse3(int[] nums) { int[] values = new int[3]; for(int i=0; i<=nums.length-1; i++) { for(int j=nums.length-1; j>=0; j--) { values[i]=nums[j]; } } return values; } I cant get this to work properly, usually the last int in the array, becomes every single int in the new array

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• info about intel Cos embedded i86 os

  - by Tim Williscroft

  I've got some old Intel printer (Etherexpress XL ) print servers and they seem to be running an Intel OS called Cos aka Intel Client Os i86 I've found out that much just looking in the update files from Intel. It was at least partly written in C. How do I make a custom software image Intel Cos's boot loader will understand ? I know a host PC xmodem's the image to the client device, and I was wondering if anyone had already either reverse-engineered this or had original info ? or is my only recousre to reverse engineer the update file format ?

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• Core Data not-reverse relationship subquery

  - by user561485

  Hi, I have the following entities in CoreData: Village - villageID Bookmark - (relation) village There are multiple villages with each an unique villageID. I have a entity Bookmark which only has a relation to a Village entity; it isn't possible to make a reverse relation. Now I would like to get the village entities where there exists a Bookmark relation. I've red something about subqueries, but I can't get it right for this situation. It must be something like: Village.villageID IN (Bookmark.village.villageID) It isn't possible to get first all the Bookmarks and then loop to get all the Villages, because of the design of the framework. Can this be done in CoreData (I presume the answer is "Yes, of course!") and how?

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• undo or reverse argsort(), python

  - by Vincent

  Given an array 'a' I would like to sort the array by columns "a.sort(axis=0)" do some stuff to the array and then undo the sort. By that I don't mean re sort but basically reversing how each element was moved. I assume argsort() is what I need but it is not clear to me how to sort an array with the results of argsort() or more importantly apply the reverse/inverse of argsort() Here is a little more detail I have an array a, shape(a) = rXc I need to sort each column aargsort = a.argsort(axis=0) # May use this later aSort = a.sort(axis=0) now average each row aSortRM = asort.mean(axis=1) now replace each col in a row with the row mean. is there a better way than this aWithMeans = ones_like(a) for ind in range(r) # r = number of rows aWithMeans[ind]* aSortRM[ind] Now I need to undo the sort I did in the first step. ????

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• How to reverse a dictionary that it has repeated values (python)

  - by Galois

  Hi guys! So, I have a dictionary with almost 100,000 (key, values) pairs and the majority of the keys map to the same values. For example imagine something like that: dict = {'a': 1, 'c': 2, 'b': 1, 'e': 2, 'd': 3, 'h': 1, 'j': 3} What I want to do, is to reverse the dictionary so that each value in dict is going to be a key at the reverse_dict and is going to map to a list of all the dict.keys that used to map to that value at the dict. So based on the example above I would get: reversed_dict = {1: ['a', 'b', 'h'], 2:['e', 'c'] , 3:['d', 'j']} I came up with a solution that is very expensive and I would really want to hear any ideas more efficient than mine. my expensive solution: reversed_dict = {} for value in dict.values(): reversed_dict[value] = [] for key in dict.keys(): if dict[key] == value: if key not in reversed_dict[value]: reversed_dict[value].append(key) Output >> reversed_dict = {1: ['a', 'b', 'h'], 2: ['c', 'e'], 3: ['d', 'j']} I would really appreciate to hear any ideas better and more efficient than than mine. Thanks!

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• Error while trying to reverse a char array

  - by mpminnich

  Hi, I'm trying to get better at C++ (I know a little). I'm working on character arrays. I found an exercise where the objective is to reverse a character array (after I convert it from an integer). I'm getting the following error (using VS2005): Run-Time Check Failure #2 - Stack around the variable 'revBuffer' was corrupted. When I step through the code, I notice the following: revBuffer = 0x0012fe40 "100899ÌÌÌÌÌÌÌÌÌÌ998001" The relevant code is below. char buffer[5]; char revBuffer[5]; int i; int j=5; long number = 998001; itoa(number, buffer, 10); for(i=0; i<strlen(buffer);i++) { revBuffer[j] = buffer[i]; j--; } Any help would be great. TIA!

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• question on reverse array

  - by davit-datuashvili

  we know algorithm how reverse array of n integers for (int i=0;i<n/2;i++){ swap(a[i],a[n-1-i]): } is this method better according the speed of algorithm or not because swap using xor is more fast then in other method here is code public class swap { public static void main(String[]args){ int a[]=new int[]{2,4,5,7,8,11,13,12,14,24}; System.out.println(" array at the begining:"); for (int i=0;i<a.length;i++){ System.out.println(a[i]); } for (int j=0;j<a.length/2;j++){ a[j]^=a[a.length-1-j]; a[a.length-1-j]^=a[j]; a[j]^=a[a.length-1-j]; } System.out.println("reversed array:"); for (int j=0;j<a.length;j++){ System.out.println(a[j]); } } } Result: array at the begining: 2 4 5 7 8 11 13 12 14 24 reversed array: 24 14 12 13 11 8 7 5 4 2

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• Error while trying to reverse a char array in C++

  - by mpminnich

  Hi, I'm trying to get better at C++ (I know a little). I'm working on character arrays. I found an exercise where the objective is to reverse a character array (after I convert it from an integer). I'm getting the following error (using VS2005): Run-Time Check Failure #2 - Stack around the variable 'revBuffer' was corrupted. When I step through the code, I notice the following: revBuffer = 0x0012fe40 "100899ÌÌÌÌÌÌÌÌÌÌ998001" The relevant code is below. char buffer[5]; char revBuffer[5]; int i; int j=5; long number = 998001; itoa(number, buffer, 10); for(i=0; i<strlen(buffer);i++) { revBuffer[j] = buffer[i]; j--; } Any help would be great. TIA!

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• DNS lookup failures while accessing my website some proxy error

  - by Bond

  Here is a situation until today morning,every thing has been working perfectly fine with me. From past 6 months many of my domains wer accessible as http://site1.myserver.com http://site2.myserver.com http://site3.myserver.com http://site4.myserver.com All these were Reverse Proxy configurations. I have some applications on each of them. until today morning some people reported me that http://site1.myserver.com/app1 is not working but http://site1.myserver.com is accessible but http://site2.myserver.com is accessible but http://site3.myserver.com is accessible but http://site4.myserver.com not accessible In past 6 months I have not changed any of these Apache configurations (things were working perfectly so) The error which can be seen in browser are while accessing http://site1.myserver.com/app1 Proxy Error The proxy server received an invalid response from an upstream server. The proxy server could not handle the request GET /app1. Reason: DNS lookup failure for: myserver.com and same is the error for http://site4.myserver.com So what should I check in I have checked all the apache logs to an extent which I could see and 192.168.1.25 - - [10/Jan/2011:14:50:48 +0530] "GET /app1 HTTP/1.1" 502 531 "-" "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3" Mon Jan 10 14:27:42 2011] [error] (113)No route to host: proxy: HTTP: attempt to connect to 192.168.1.3:80 (192.168.1.3) failed [Mon Jan 10 14:27:42 2011] [error] ap_proxy_connect_backend disabling worker for (192.168.1.3) [Mon Jan 10 14:27:44 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:44 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:44 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:45 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:45 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:45 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:45 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:46 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:47 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:48 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:48 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:48 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:35:29 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: myserver.com returned by /app1 [Mon Jan 10 14:35:30 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: myserver.com returned by /app1 [Mon Jan 10 14:35:30 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: myserver.com returned by /app1 [Mon Jan 10 14:50:30 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: myserver.com returned by /app1 [Mon Jan 10 14:50:48 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: myserver.com returned by /app1 and for site4.myserver.com I get [Mon Jan 10 14:57:40 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: site4.myserver.com returned by /favicon.ico [Mon Jan 10 14:57:40 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: site4.myserver.com returned by /favicon.ico [Mon Jan 10 14:57:43 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: site4.myserver.com returned by /favicon.ico [Mon Jan 10 15:02:38 2011] [error] [client <some external IP>] proxy: DNS lookup failure for: site4.myserver.com returned by / [Mon Jan 10 15:03:04 2011] [error] [client <some external IP>] proxy: DNS lookup failure for: site4.myserver.com returned by /, referer: http://site4.myserver.com/ [Mon Jan 10 15:03:04 2011] [error] [client <some external IP>] proxy: DNS lookup failure for: site4.myserver.com returned by /favicon.ico [Mon Jan 10 15:03:08 2011] [error] [client <some external IP>] proxy: DNS lookup failure for: site4.myserver.com returned by /, referer: http://site4.myserver.com/ [Mon Jan 10 15:03:08 2011] [error] [client <some external IP>] proxy: DNS lookup failure for: site4.myserver.com returned by /favicon.ico [Mon Jan 10 15:03:10 2011] [error] [client <some external IP>] proxy: DNS lookup failure for: site4.myserver.com returned by /, referer: http://site4.myserver.com/ [Mon Jan 10 15:06:21 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: site4.myserver.com returned by / [Mon Jan 10 15:06:31 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: site4.myserver.com returned by /, referer: http://site4.myserver.com/ [Mon Jan 10 15:26:03 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: site4.myserver.com returned by /

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• what's wrong with my Ubuntu 11.10 bind9 configuration?

  - by John Bowlinger

  I've followed several tutorials on installing your own nameservers and I'm pretty much at my wit's end, because I cannot get them to resolve. Note, the actual domain and ip address has been changed for privacy to example.com and 192.168.0.1. My named.conf.local file: zone "example.com" { type master; file "/var/cache/bind/example.com.db"; }; zone "0.168.192.in_addr.arpa" { type master; file "/var/cache/bind/192.168.0.db"; }; My named.conf.options file: options { forwarders { 192.168.0.1; }; auth-nxdomain no; # conform to RFC1035 listen-on-v6 { any; }; }; My resolv.conf file: search example.com. nameserver 192.168.0.1 My Forward DNS file: ORIGIN example.com. $TTL 86400 @ IN SOA ns1.example.com. root.example.com. ( 2012083101 ; Serial 604800 ; Refresh 86400 ; Retry 2419200 ; Expire 3600 ) ; Negative Cache TTL example.com. NS ns1.example.com. example.com. NS ns2.example.com. example.com. MX 10 mail.example.com. @ IN A 192.168.0.1 ns1.example.com IN A 192.168.0.1 ns2.example.com IN A 192.168.0.2 mail IN A 192.168.0.1 server1 IN A 192.168.0.1 gateway IN CNAME ns1.example.com. headoffice IN CNAME server1.example.com. smtp IN CNAME mail.example.com. pop IN CNAME mail.example.com. imap IN CNAME mail.example.com. www IN CNAME server1.example.com. sql IN CNAME server1.example.com. And my reverse DNS: $ORIGIN 0.168.192.in-addr.arpa. $TTL 86400 @ IN SOA ns1.example.com. root.example.com. ( 2009013101 ; Serial 604800 ; Refresh 86400 ; Retry 2419200 ; Expire 3600 ) ; Negative Cache TTL 1 PTR mail.example.com. 1 PTR server1.example.com. 2 PTR ns1.example.com. Yet, when I restart bind9 and do: host ns1.example.com localhost I get: Using domain server: Name: localhost Address: 127.0.0.1#53 Aliases: Host ns1.example.com.example.com not found: 2(SERVFAIL) Similarly, for: host 192.168.0.1 localhost I get: ;; connection timed out; no servers could be reached Anybody know what's going on? Btw, my domain name "www.example.com" that I've used in this question is being forwarded to my ISP's nameservers. Would that affect my bind9 configuration? I want to learn how to do set up nameservers on my own for learning, so that is why I'm going through all this trouble.

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• VirtualServer reverseproxy works locally, but not from client

  - by Yep

  Setup: 2 Webservers pointed to 127.0.0.1:8080 and :8081. Curl validates they work as expected. Apache with the following virt hosts: NameVirtualHost 192.168.1.1:80 <VirtualHost 192.168.1.1:80> ServerAdmin [email protected] ProxyPass / http://127.0.0.1:8080/ ProxyPassReverse / http://127.0.0.1:8080/ ServerName 192.168.1.1 ServerAlias http://192.168.1.1 </VirtualHost> NameVirtualHost 192.168.1.2:80 <VirtualHost 192.168.1.2:80> ServerAdmin [email protected] ProxyPass / http://127.0.0.1:8081/ ProxyPassReverse / http://127.0.0.1:8081/ ServerName 192.168.1.2 ServerAlias http://192.168.1.2 </VirtualHost> On the server I can curl to the virtualhosts and receive appropriate responses. (curl 192.168.1.1 gives me the webservers response from localhost:8080, etc) remote hosts cannot however connect to 192.168.1.1 or .2 at all. What am I missing? Re: comments Yes, the default directory Directive is still in place. # Deny access to root file system <Directory /> Options None AllowOverride None Order Deny,Allow deny from all </Directory> No apache logs are generated when trying to reach 192.168.1.1 remotely. They do get generated when curl from local. If I point the webservers to *:8080 and *:8081 instead of binding to localhost, I can access them from a remote host via 192.168.1.1 and 192.168.1.2 if i specify the 8080 and 8081 ports (both ports work on both IP's, which is what I'm trying to avoid with apache reverse proxy bind to 80 on each interface) Edit2: curl verbose output: (similar for second webserver, and for 127.0.0.1:portnum) [user@host mingle_12_2_1]$ curl -v 192.168.1.1 * About to connect() to 192.168.1.1 port 80 * Trying 192.168.1.1... connected * Connected to 192.168.1.1 (192.168.1.1) port 80 > GET / HTTP/1.1 > User-Agent: curl/7.15.5 (x86_64-redhat-linux-gnu) libcurl/7.15.5 OpenSSL/0.9.8b zlib/1.2.3 libidn/0.6.5 > Host: 192.168.1.1 > Accept: */* > < HTTP/1.1 302 Found < Date: Tue, 16 Oct 2012 16:22:08 GMT < Server: Jetty(6.1.19) < Cache-Control: no-cache < Location: http://192.168.1.1/install < X-Runtime: 130 < Content-Type: text/html; charset=utf-8 < Content-Length: 94 < Connection: close Closing connection #0 <html><body>You are being <a href="http://192.168.1.1/install">redirected</a>.</body></html> log from the request local 192.168.1.1 - - [16/Oct/2012:12:22:08 -0400] "GET / HTTP/1.1" 302 94 no apache access log or error log generated when requests from remote clients.

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• How mod_cache working with "must-revalidate" and "max-age"?

  - by Dmitriy Sosunov

  Quick question before I will explain my flow: ?an mod_cache perform revalidate with if-none-match only if max-age is expired in case if it configured in reverse proxy mode? My goal is to reduce a number of revalidation requests to our the origin server. For instance: The first request goes to the origin server and then mod_cache save a response in to the cache according to header cache-control: max-age. And only when max-age is expired then mod_cache will revalidate with if-none-match. Currently, mod_cache revalidate each request, regardless that max-age is defined or not. My configuration of Apache 2.4.3 (Windows), on linux I see the same behavior that I will show below. ServerName proxy.lo ProxyRequests Off ProxyPreserveHost Off Header set Vary "Accept, Content-Type, Content-Encoding, Accept-Language" RequestHeader set X-Forwarded-Proto "http" # modify header for user agent's Header set Cache-Control "private, no-cache, no-store, no-transform" CacheQuickHandler off CacheDefaultExpire 300 # the origin server do not provide last-modified CacheIgnoreNoLastMod On CacheIgnoreCacheControl On # the origin server define cache-control: private, no-store only for user agents # Therefore, I would like ignore those headers on the proxy server. CacheStorePrivate On CacheStoreNoStore On CacheEnable disk / CacheRoot "C:/Apache.Cache" CacheDirLevels 5 CacheDirLength 4 CacheMinExpire 15 CacheDetailHeader on CacheHeader on KeepAlive Off ProxyPass / http://origin.lo/ ProxyPassReverse / http://origin.lo/ Also, I have turned on debug log level to see how mod_cache handles a content for caching: I provided this to show that mod_proxy always decides that a content isn't fresh. Why?I provided this to show that mod_proxy always decide that a content isn't fresh. Why? max-age was provided (see below). [Sun Nov 04 11:58:42.899890 2012] [cache:debug] [pid 6492:tid 1400] cache_storage.c(624): [client 192.168.1.100:63741] AH00698: cache: Key for entity /testpage?(null) is http://proxy.lo/testpage? [Sun Nov 04 11:58:42.899890 2012] [cache_disk:debug] [pid 6492:tid 1400] mod_cache_disk.c(569): [client 192.168.1.100:63741] AH00709: Recalled cached URL info header http://proxy.lo/testpage? [Sun Nov 04 11:58:42.899890 2012] [cache_disk:debug] [pid 6492:tid 1400] mod_cache_disk.c(865): [client 192.168.1.100:63741] AH00720: Recalled headers for URL http://proxy.lo/testpage? [Sun Nov 04 11:58:42.899890 2012] [cache:debug] [pid 6492:tid 1400] cache_storage.c(320): [client 192.168.1.100:63741] AH00695: Cached response for /testpage isn't fresh. Adding/replacing conditional request headers. [Sun Nov 04 11:58:42.899890 2012] [cache:debug] [pid 6492:tid 1400] mod_cache.c(414): [client 192.168.1.100:63741] AH00757: Adding CACHE_SAVE filter for /testpage [Sun Nov 04 11:58:42.899890 2012] [cache:debug] [pid 6492:tid 1400] mod_cache.c(448): [client 192.168.1.100:63741] AH00759: Adding CACHE_REMOVE_URL filter for /testpage [Sun Nov 04 11:58:42.899890 2012] [proxy:debug] [pid 6492:tid 1400] mod_proxy.c(1068): [client 192.168.1.100:63741] AH01143: Running scheme http handler (attempt 0) [Sun Nov 04 11:58:42.899890 2012] [proxy:debug] [pid 6492:tid 1400] proxy_util.c(1976): AH00942: HTTP: has acquired connection for (origin.lo) [Sun Nov 04 11:58:42.899890 2012] [proxy:debug] [pid 6492:tid 1400] proxy_util.c(2029): [client 192.168.1.100:63741] AH00944: connecting http://origin.lo/testpage to origin.lo:80 [Sun Nov 04 11:58:42.901890 2012] [proxy:debug] [pid 6492:tid 1400] proxy_util.c(2151): [client 192.168.1.100:63741] AH00947: connected /testpage to origin.lo:80 [Sun Nov 04 11:58:42.901890 2012] [proxy:debug] [pid 6492:tid 1400] proxy_util.c(2554): AH00962: HTTP: connection complete to 192.168.1.100:80 (origin.lo) [Sun Nov 04 11:58:42.903890 2012] [proxy:debug] [pid 6492:tid 1400] proxy_util.c(1991): AH00943: http: has released connection for (origin.lo) [Sun Nov 04 11:58:42.903890 2012] [headers:debug] [pid 6492:tid 1400] mod_headers.c(800): AH01502: headers: ap_headers_output_filter() [Sun Nov 04 11:58:42.903890 2012] [cache:debug] [pid 6492:tid 1400] mod_cache.c(1190): [client 192.168.1.100:63741] AH00769: cache: Caching url: /testpage [Sun Nov 04 11:58:42.903890 2012] [cache:debug] [pid 6492:tid 1400] mod_cache.c(1196): [client 192.168.1.100:63741] AH00770: cache: Removing CACHE_REMOVE_URL filter. [Sun Nov 04 11:58:42.904890 2012] [cache_disk:debug] [pid 6492:tid 1400] mod_cache_disk.c(1318): [client 192.168.1.100:63741] AH00737: commit_entity: Headers and body for URL http://proxy.lo/testpage? cached. The first request to the origin server without mod_proxy to http://origin.lo/ GET http://origin.lo/testpage HTTP/1.1 Host: origin.lo Connection: keep-alive User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.4 (KHTML, like Gecko) Chrome/22.0.1229.94 Safari/537.4 Accept: application/json Accept-Encoding: gzip,deflate,sdch Accept-Language: en-US,en;q=0.8 Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.3 The first response from the origin without mod_proxy HTTP/1.1 200 OK Cache-Control: must-revalidate, proxy-revalidate, max-age=30 Content-Type: application/json; charset=utf-8 ETag: "7cf651e2-176f-4ac1-808e-0e0c17cfd0a2" Server: Microsoft-IIS/7.5 X-AspNet-Version: 4.0.30319 X-Powered-By: ASP.NET Date: Sun, 04 Nov 2012 10:11:01 GMT Content-Length: 1877 So, I assumed that revalidation must be occur only in 30 seconds after the success response. Is't right? Let's check it:) Within 30 sec, the Google Chrome didn't perform any requests to the origin server to revalidate a request and has return the response from local cache. When max-age is expired, the Google Chrome perform a request to revalidate: GET http://origin.lo/testpage HTTP/1.1 Host: origin.lo Connection: keep-alive Cache-Control: max-age=0 User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.4 (KHTML, like Gecko) Chrome/22.0.1229.94 Safari/537.4 Accept: application/xml If-None-Match: "7cf651e2-176f-4ac1-808e-0e0c17cfd0a2" Accept-Encoding: gzip,deflate,sdch Accept-Language: en-US,en;q=0.8 Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.3 and response: HTTP/1.1 304 Not Modified Cache-Control: must-revalidate, proxy-revalidate, max-age=30 ETag: "7cf651e2-176f-4ac1-808e-0e0c17cfd0a2" Server: Microsoft-IIS/7.5 X-AspNet-Version: 4.0.30319 X-Powered-By: ASP.NET Date: Sun, 04 Nov 2012 10:16:20 GMT As you can see, all works as expected. User agent revalidates request only when max-age is expired. Let's now try perform the folling flow though mod_proxy (see configuration above). The first request: GET http://proxy.lo/testpage HTTP/1.1 Host: proxy.lo Connection: keep-alive User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.4 (KHTML, like Gecko) Chrome/22.0.1229.94 Safari/537.4 Accept: application/json Accept-Encoding: gzip,deflate,sdch Accept-Language: en-US,en;q=0.8 Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.3 and the response was: HTTP/1.1 200 OK Date: Sun, 04 Nov 2012 10:23:36 GMT Server: Apache Cache-Control: private, no-cache, no-store, no-transform Content-Type: application/json; charset=utf-8 ETag: "7cf651e2-176f-4ac1-808e-0e0c17cfd0a2" Content-Length: 1932 Vary: Accept,Content-Type,Content-Encoding,Accept-Language X-Cache: MISS from proxy.lo X-Cache-Detail: "cache miss: attempting entity save" from proxy.lo Connection: close Ok, let's see to the disk cache and try to see how request and response was stored. (I cut binary data) http://proxy.lo/testpage? Cache-Control: private, no-cache, no-store, no-transform Content-Type: application/json; charset=utf-8 ETag: "7cf651e2-176f-4ac1-808e-0e0c17cfd0a2" Date: Sun, 04 Nov 2012 10:27:15 GMT Content-Length: 1932 Vary: Accept, Content-Type, Content-Encoding, Accept-Language Host: proxy.lo User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.4 (KHTML, like Gecko) Chrome/22.0.1229.94 Safari/537.4 Accept: application/json Accept-Encoding: gzip,deflate,sdch Accept-Language: en-US,en;q=0.8 Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.3 X-Forwarded-Proto: http Cache-Control: max-age=300, must-revalidate X-Forwarded-For: 192.168.1.100 X-Forwarded-Host: proxy.lo X-Forwarded-Server: origin.lo Ok, what we see? We see that the first request was performed with max-age=300 & must-revalidate Ok, looks good, as for me, lets perform the next call: GET http://proxy.lo/testpage HTTP/1.1 Host: proxy.lo Connection: keep-alive User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.4 (KHTML, like Gecko) Chrome/22.0.1229.94 Safari/537.4 Accept: application/json Accept-Encoding: gzip,deflate,sdch Accept-Language: en-US,en;q=0.8 Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.3 and the second response from mod_proxy: HTTP/1.1 200 OK Date: Sun, 04 Nov 2012 10:31:58 GMT Server: Apache Cache-Control: private, no-cache, no-store, no-transform ETag: "7cf651e2-176f-4ac1-808e-0e0c17cfd0a2" Content-Length: 1932 Vary: Accept,Content-Type,Content-Encoding,Accept-Language X-Cache: REVALIDATE from proxy.lo X-Cache-Detail: "conditional cache hit: entity refreshed" from proxy.lo Connection: close Content-Type: application/json; charset=utf-8 SO, MY QUESTION IS: WHY mod_proxy perform revalidation on each request regardless that max-age is defined? N.B. Apache 2.4.3 Thanks, I would be grateful for any help.

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• Why is software quality so problematic?

  - by Yuval A

  Even when viewing the subject in the most objective way possible, it is clear that software, as a product, generally suffers from low quality. Take for example a house built from scratch. Usually, the house will function as it is supposed to. It will stand for many years to come, the roof will support heavy weather conditions, the doors and the windows will do their job, the foundations will not collapse even when the house is fully populated. Sure, minor problemsdo occur, like a leaking faucet or a bad paint job, but these are not critical. Software, on the other hand is much more susceptible to suffer from bad quality: unexpected crashes, erroneous behavior, miscellaneous bugs, etc. Sure, there are many software projects and products which show high quality and are very reliable. But lots of software products do not fall in this category. Take into consideration paradigms like TDD which its popularity is on the rise in the past few years. Why is this? Why do people have to fear that their software will not work or crash? (Do you walk into a house fearing its foundations will collapse?) Why is software - subjectively - so full of bugs? Possible reasons: Modern software engineering exists for only a few decades, a small time period compared to other forms of engineering/production. Software is very complicated with layers upon layers of complexity, integrating them all is not trivial. Software development is relatively easy to start with, anyone can write a simple program on his PC, which leads to amateur software leaking into the market. Tight budgets and timeframes do not allow complete and high quality development and extensive testing. How do you explain this issue, and do you see software quality advancing in the near future?

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• DotNetOpenAuth OpenID on ISA 2006 Reverse Proxy problem

  - by userb00

  I am trying to host my site that uses DotNetOpenAuth (OpenID) behind ISA 2006 (reverse proxy), and after it authenticated with a provider (such as Google), and it returns with a URL with %253A in the URL. However, ISA HTTP filter rejects the request. What I need to do is, on ISA web publishing rule, right click config HTTP policy properties uncheck "Verify Normalization" and it worked. Is this a problem on ISA 2006 generally? Are other firewalls having similar problems? Or, is it an OpenID or DotNetOpenAuth issue? Is it safe to disable Normalization checking on ISA? According to MSDN, quote "Web servers receive requests that are URL encoded. This means that certain characters may be replaced with a percent sign (%) followed by a particular number. For example, %20 corresponds to a space, so a request for http://myserver/My%20Dir/My%20File.htm is the same as a request for http://myserver/My Dir/My File.htm. Normalization is the process of decoding URL-encoded requests. Because the % can be URL encoded, an attacker can submit a carefully crafted request to a server that is basically double-encoded. If this occurs, Internet Information Services (IIS) may accept a request that it would otherwise reject as not valid. When you select Verify Normalization, the HTTP filter normalizes the URL two times. If the URL after the first normalization is different from the URL after the second normalization, the filter rejects the request. This prevents attacks that rely on double-encoded requests. Note that while we recommend that you use the Verify Normalization function, it may also block legitimate requests that contain a %."

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• Using Hibernate with MS ACCESS 2007 Database (Free JDBC Driver)

  - by Quentin T.

  1. I want to do a reverse engineering action with the Hibernate plugin of Eclipse on a MS Access 2007 Database. I'm forced to use a existing MS Access 2007 db. A easy solution is to buy the HXTT. But I want to use a free driver to do my work. So I tried to apply this post : http://www.programmingforfuture.com/2011/06/how-to-use-ms-access-with-hibernate.html (That uses the SQL Server dialect and the driver sun.jdbc.odbc.JdbcOdbcDriver) Unfortunately I have an error that nobody seems to have been on the internet: Exception while generating code Reason : org.hibernate.exception.GenericJDBCException: Error while reading primary key meta data for `c:/myaccessdb.mdb`.TableTest1 I have try to change the primary key on my MS Access DB (deleting all primary key) or to try the reverse engineering on a MS ACCESS with only one table without primary key, but I got all times the problems. 2. The purpose of my job is to transfer daily (weekly) an Oracle 11g database with data from an existing database MS ACCESS 2007. And I thought to use a procedure (Hibernate EJB) Java to be launched automatically every week to do the data transfer. Is this is the best solution ? Configuration : sun.jdbc.odbc.JdbcOdbcDriver v??? Hibernate v3.4 Eclipse ps: If you are a HXTT developer or seller please be indulgent with my post ;). Making money by making people believe that you help, it's bad ! A solution is to use Derby Client driver, as the solution in the post: Does anyone know if Hibernate and java will work effectively with Access? But a clarification of the answer of Rich Seller is required. Could you explain your answer and explain your configuration (hibernate.cfg.xml, persistence.xml and what URL you use in the property name="hibernate.connection.url") without using paying HXTT driver but with the free Derby driver.

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• Reverse alphabetic sort multidimensional PHP array maintain key

  - by useyourillusiontoo

  I'm dying here, any help would be great. I've got an array that I can sort a-z on the value of a specific key but cannot sort in reverse z-a. sample of my array which i'd like to sort by ProjectName (z-a): Array ( [0] => Array ( [count] => 1 [ProjectName] => bbcjob [Postcode] => 53.471922,-2.2996078 [Sector] => Public ) [1] => Array ( [count] => 1 [ProjectName] => commercial enterprise zone [Postcode] => 53.3742081,-1.4926439 [Sector] => Public ) [2] => Array ( [count] => 1 [ProjectName] => Monkeys eat chips [Postcode] => 51.5141492,-0.2271227 [Sector] => Private the desired results would be to maintain the entire array key - value structure but with the order: Monkeys eat chips Commericial enterprise zone bbcjob I hope this makes sense

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• How do i prevent my code from being stolen?

  - by Calmarius

  What happens exactly when I launch a .NET exe? I know that C# is compiled to IL code and I think the generated exe file just a launcher that starts the runtime and passes the IL code to it. But how? And how complex process is it? IL code is embedded in the exe. I think it can be executed from the memory without writing it to the disk while ordinary exe's are not (ok, yes but it is very complicated). My final aim is extracting the IL code and write my own encrypted launcher to prevent scriptkiddies to open my code in Reflector and just steal all my classes easily. Well I can't prevent reverse engineering completely. If they are able to inspect the memory and catch the moment when I'm passing the pure IL to the runtime then it won't matter if it is a .net exe or not, is it? I know there are several obfuscator tools but I don't want to mess up the IL code itself. EDIT: so it seems it isn't worth trying what I wanted. They will crack it anyway... So I will look for an obfuscation tool. And yes my friends said too that it is enough to rename all symbols to a meaningless name. And reverse engineering won't be so easy after all.

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