Search Results

Search found 837 results on 34 pages for 'xsl'.

Page 28/34 | < Previous Page | 24 25 26 27 28 29 30 31 32 33 34  | Next Page >

  • XmlReader throws on an RSS feed, when the RSS document includes an embedded <script> block.

    - by Cheeso
    The code: using (XmlReader xmlr = XmlReader.Create(new StringReader(allXml))) { var items = from item in SyndicationFeed.Load(xmlr).Items select item; } The exception: Exception: System.Xml.XmlException: Unexpected node type Element. ReadElementString method can only be called on elements with simple or empty content. Line 11, position 25. at System.Xml.XmlReader.ReadElementString() at System.ServiceModel.Syndication.Rss20FeedFormatter.ReadXml(XmlReader reader, SyndicationFeed result) at System.ServiceModel.Syndication.Rss20FeedFormatter.ReadFeed(XmlReader reader) at System.ServiceModel.Syndication.Rss20FeedFormatter.ReadFrom(XmlReader reader) at System.ServiceModel.Syndication.SyndicationFeed.Load[TSyndicationFeed](XmlReader reader) at System.ServiceModel.Syndication.SyndicationFeed.Load(XmlReader reader) at Ionic.ToolsAndTests.ReadRss.Run() in c:\dev\dotnet\ReadRss.cs:line 90 The XML content: <?xml version="1.0" encoding="utf-8"?> <?xml-stylesheet type="text/xsl" href="https://www.ibm.com/developerworks/mydeveloperworks/blogs/roller-ui/styles/rss.xsl" media="screen"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:atom="http://www.w3.org/2005/Atom" > <channel> <title>Software architecture, software engineering, and Renaissance Jazz</title> <link>https://www.ibm.com/developerworks/mydeveloperworks/blogs/gradybooch</link> <atom:link rel="self" type="application/rss+xml" href="https://www.ibm.com/developerworks/mydeveloperworks/blogs/gradybooch/feed/entries/rss?lang=en" /> <description>Software architecture, software engineering, and Renaissance Jazz</description> <language>en-us</language> <copyright>Copyright <script type='text/javascript'> document.write(blogsDate.date.localize (1273534889181));</script></copyright> <lastBuildDate>Mon, 10 May 2010 19:41:29 -0400</lastBuildDate> As you can see, on line 11, at position 25, there's a script block inside the <copyright> element. Other people have reported similar errors with other XML documents. The way I worked around this was to do a StreamReader.ReadToEnd, then do Regex.Replace on the result of that to yank out the script block, before passing the modified string to XmlReader.Create(). Feels like a hack. Has anyone got a better approach? I don't like this because I have to read in a 125k string into memory. Is it valid rss to include "complex content" like that - a script block inside an element? Thanks.

    Read the article

  • Apache FOP in Visual Studio 2008

    - by Igman
    I am writing some XML - PDF generating templates in Apache FOP for an asp web app. I need to use Visual Studio for my development. Visual studio has great editing and auto complete for regular XSL, I was wondering if there is any way to add this functionality for FOP tags. At least is there a way to stop it from thinking the file is hopelessly broken due to the tags? Thanks.

    Read the article

  • Could not find function: resolve-uri

    - by Nisarg Mehta
    When i am trying to transform xml it gives me erro that Could not find function: resolve-uri where resolve-uri is a xpath function . below is my xslt line which will use resolve uri function . <xsl:variable name="filename" select="resolve-uri(concat($dir,'/',$xmlFileName,'_',position(),'.xml'))" /> Can anybody please help me.Is it because of xslt version difference ? Thanks in Advance.

    Read the article

  • Is daisy chaining xslt an accepted practice?

    - by Stephen
    I have a situation where I think I need to daisy chain my xslt transformation (i.e. that output of one xslt transform being input into another). The first transform is rather complex with lots of xsl:choice and ancestor xpaths. My thought is to transform the xml into xml that can then be easily transformed to html. My question is 'Is this standard practice or am I missing something?' Thanks in advance. Stephen

    Read the article

  • TFS Notifications - change title

    - by Sebastian
    On action WorkItemChangeEvent TFS sending an email. Title of maile looks like: [Project] [Work Item Created] [Type of Work Item][Id] [Title of WorkItem] I would like to change this title. Can I do this ? I can't find it in WorkItemChangedEvent.xsl

    Read the article

  • Reusing xalan transformer causing its extension functions break

    - by Leslie Norman
    I am using xalan 2.7.1 to validate my xml docs with xslt style sheet. It works fine for the first document and returns error message in case of error along with correct line and column number of xml source by making use of NodeInfo.lineNumber and NodeInfo.columnNumber extensions. The problem is when I try to reuse transformer to validate other xml docs, it successfully transforms the document but always returns lineNumber=columnNumber=-1 for all errors. Any idea? Here is my code: TransformerFactory tFactory = TransformerFactory.newInstance("org.apache.xalan.processor.TransformerFactoryImpl", null); tFactory.setAttribute(TransformerFactoryImpl.FEATURE_SOURCE_LOCATION, Boolean.TRUE); StreamSource xsltStreamSource = new StreamSource(new File("E:\\Temp\\Test\\myXslt.xsl")); Transformer transformer=null; try { transformer = tFactory.newTransformer(xsltStreamSource); ByteArrayOutputStream outStream = new ByteArrayOutputStream(); File srcFolder = new File("E:\\Temp\\Test"); for (File file :srcFolder.listFiles()) { if (file.getName().endsWith("xml")) { transformer.transform(new StreamSource(file), new StreamResult(outStream)); transformer.reset(); } } System.out.println(outStream.toString()); } catch (TransformerException e) { e.printStackTrace(); } Edit: New code after implementing @rsp suggestions: package mycompany; import java.io.File; import javax.xml.transform.ErrorListener; import javax.xml.transform.Source; import javax.xml.transform.Transformer; import javax.xml.transform.TransformerException; import javax.xml.transform.TransformerFactory; import javax.xml.transform.stream.StreamResult; import javax.xml.transform.stream.StreamSource; import org.apache.xalan.processor.TransformerFactoryImpl; public class XsltTransformer { public static void main(String[] args) { TransformerFactory tFactory = TransformerFactory.newInstance("org.apache.xalan.processor.TransformerFactoryImpl", null); tFactory.setAttribute(TransformerFactoryImpl.FEATURE_SOURCE_LOCATION, Boolean.TRUE); StreamSource xsltStreamSource = new StreamSource(new File("E:\\Temp\\Test\\myXslt.xsl")); try { Transformer transformer = tFactory.newTransformer(xsltStreamSource); File srcFolder = new File("E:\\Temp\\Test"); for (File file : srcFolder.listFiles()) { if (file.getName().endsWith("xml")) { Source source = new StreamSource(file); StreamResult result = new StreamResult(System.out); XsltTransformer xsltTransformer = new XsltTransformer(); ErrorListenerImpl errorHandler = xsltTransformer.new ErrorListenerImpl(); transformer.setErrorListener(errorHandler); transformer.transform(source, result); if (errorHandler.e != null) { System.out.println("Transformation Exception: " + errorHandler.e.getMessage()); } transformer.reset(); } } } catch (TransformerException e) { e.printStackTrace(); } } private class ErrorListenerImpl implements ErrorListener { public TransformerException e = null; public void error(TransformerException exception) { this.e = exception; } public void fatalError(TransformerException exception) { this.e = exception; } public void warning(TransformerException exception) { this.e = exception; } } }

    Read the article

  • Reference XSLT-file using a project relative way (instead of an absolute path)

    - by Binary255
    The file at xsltFileName is in my project WebSite2 (at the root-level of the project). I currently use an absolute path to get the XSLT file name: XslCompiledTransform xslt = new XslCompiledTransform(); String xsltFileName = "file:///C:\\Documents and Settings\\kentl\\My Documents\\Visual Studio 2005\\WebSites\\WebSite2\\page.xsl"; xslt.Load(xsltFileName); I would like to have a solution without an absolute path. What would be the cleanest way?

    Read the article

  • Using XSLT, how do I separate nodes based on their value?

    - by Will Goring
    I have a pretty flat XML structure that I need to reorder into categorised sections and, for the life of me, I can't figure out how to do it in XSLT (not that I'm by any means an expert.) Basically, the original XML looks kinda like: <things> <thing> <value>one</value> <type>a</type> </thing> <thing> <value>two</value> <type>b</type> </thing> <thing> <value>thee</value> <type>b</type> </thing> <thing> <value>four</value> <type>a</type> </thing> <thing> <value>five</value> <type>d</type> </thing> </things> And I need to output something like: <data> <a-things> <a>one</a> <a>four</a> </a-things> <b-things> <b>two</b> <b>three</b> </b-things> <d-things> <d>five</d> </d-things> </data> Note that I can't output <c-things> if there aren't any <c> elements, but I do know ahead of time what the complete list of types is, and it's fairly short so handcoding templates for each type is definitely possible. It feels like I could probably hack something together using <xsl:if> and <xsl:for-each> but it also feels like there must be a more ... 'templatey' way to do it. Can anyone help? Cheers.

    Read the article

  • Xslt external parameter

    - by enrico
    In my server side TransformerFactory tfactory = TransformerFactory.newInstance(); Transformer transformer = tfactory.newTransformer( new StreamSource("mytext.xsl")); transformer.setParameter("parametro","hope"); transformer.transform( new DOMSource(document), outputStream ); --mytext.xslt-- . . . . . . why the value of $parametro isn't "hope" in my html output? Thanks

    Read the article

  • Why don't all XSLT templates get executed at once?

    - by Matt W
    Refer to: http://stackoverflow.com/questions/1613454/retrieving-one-element-and-filter-by-another In the above linked posting, I don't understand why the two template blocks don't get executed upon in the incoming XML at the same time. As far I can can see, the XSL risks the second template executing for every Document element whether it is called with apply-templates or not. Could someone explain this to my stifled brain, please? Thanks, Matt.

    Read the article

  • How to change the extension of a processed xml file (using eXist & cocoon)

    - by Carsten C.
    Hi all, I'm really new to this whole web stuff, so please be nice if I missed something important to post. Short: Is there a possibility to change the name of a processed file (eXist-DB) after serialization? Here my case, the following request to my eXist-db: http://localhost:8080/exist/cocoon/db/caos/test.xml and I want after serialization the follwing (xslt is working fine): http://localhost:8080/exist/cocoon/db/caos/test.html I'm using the followong sitemap.xmap with cocoon (hoping this is responsible for it) <map:match pattern="db/caos/**"> <!-- if we have an xpath query --> <map:match pattern="xpath" type="request-parameter"> <map:generate src="xmldb:exist:///db/caos/{../1}/#{1}"/> <map:act type="request"> <map:parameter name="parameters" value="true"/> <map:parameter name="default.howmany" value="1000"/> <map:parameter name="default.start" value="1"/> <map:transform type="filter"> <map:parameter name="element-name" value="result"/> <map:parameter name="count" value="{howmany}"/> <map:parameter name="blocknr" value="{start}"/> </map:transform> <map:transform src=".snip./webapp/stylesheets/db2html.xsl"> <map:parameter name="block" value="{start}"/> <map:parameter name="collection" value="{../../1}"/> </map:transform> </map:act> <map:serialize type="html" encoding="UTF-8"/> </map:match> <!-- if the whole file will be displayed --> <map:generate src="xmldb:exist:/db/caos/{1}"/> <map:transform src="..snip../stylesheets/caos2soac.xsl"> <map:parameter name="collection" value="{1}"/> </map:transform> <map:transform type="encodeURL"/> <map:serialize type="html" encoding="UTF-8"/> </map:match> So my Question is: How do I change the extension of the test.xml to test.html after processing the xml file? Background: I'm generating some information out of some xml-dbs, this infos will be displayed in html (which is working), but i want to change some entrys later, after I generated the html site. To make this confortable, I want to use Jquery & Jeditable, but the code does not work on the xml files. Saving the generated html is not an option. tia for any suggestions [and|or] help CC Edit: After reading all over: could it be, that the extension is irrelevant and that this is only a problem of port 8080? I'm confused...

    Read the article

  • IIS failed request log viewer

    - by Cédric Boivin
    Hello, It's there an existing application to visualize IIS 7.0 failed request log ? I know you can use IE to analyse the xml log file, and we get a visual generate by the xsl file, but my xml log file have 97 MO and the IE performance is not got. I cannot view the performance log, because i beleive there a javascript error generated. Thanks

    Read the article

  • XSLT modify node before applying template

    - by Grigory
    I have an XSL code that processes some nodes and if some condition is true, before doing apply-template select="." i need to modify current node(add and attribute). How can i add an attribute to the node before calling apply-template select=".", or it is not possible at all ?

    Read the article

  • How to get xslReportBuildPlugin to work on CruiseControl.net

    - by work3much
    Hi All, I'm using CC 1.5.6804.1 and i created and custom xslt file generate a custome report. I added the file to the xsl directory. I have also updated the dashboard.config file with the following: [my additions] I see no link on the web dashboard after saving and restarting the server. Has anyone seen this and/or have any ideals?? Thanks.

    Read the article

  • How to view doctype in generated source code

    - by wcpro
    I am using an XSL transformation on an xml file to create an xml document. The problem i am running into is that when i go to view the generated source (the transformed source) i can't see the DOCTYPE attribute of the html so i don't know if its being emitted properly. Is there any way to view the doctype in this way?

    Read the article

  • XSLT: Transform XML files tree

    - by Myniva
    I have the following file structure (XML files 'index.xml' in nested folders): index.xml foo/index.xml foo/sub/index.xml foo/.../index.xml bar/.../index.xml Now I have to transform each of this XML files with a given XSL stylesheet. The result should be the same folder structure (overwriting would be OK). What would be your approach to achieve this? My system: OS X 10.6, Saxon XSLT processor

    Read the article

  • Draw chart for every row of the dataset in SSRS. Loop through dataset rows

    - by Rushme
    Hi, Could anyone help me with how can we create chart for every row of the dataset in SSRS (rdl) ! Suppose the dataset has the following data Name Age ------- ------- A 25 B 26 C 22 3 chart needs to be drawn for the x-axis/y-axis combination of A/25, B/26, C/22. How can I loop through rows of the dataset. And how can I restrict the chart to that particular data point. What would be the xsl expression corresponding to this functionality.

    Read the article

  • Why can't I get XSLT to work in chrome?

    - by Eric
    I have a XSLT sample copied straight from http://www.w3schools.com/xsl/xsl_transformation.asp, which I can't seem to view in Google Chrome. However, it seems to work fine in IE. Does anyone know why this would be? EDIT: The online version works fine, but the local copy does not.

    Read the article

  • How to create XML webparts using sharepoint web services?

    - by Manish
    I have an XML to be rendered in sharepoint using a XSL file. I now the how to do this using object model of sharepoint but don't how to do this using sharepoint web services. i.e. I want to create XML web parts using sharepoint web services. Is it possible to do create XML web parts using sharepoint web services? If yes, how?

    Read the article

  • Generating text file from database

    - by Goldmember
    I have a requirement to hand-code an text file from data residing in a SQL table. Just wondering if there are any best practices here. Should I write it as an XMLDocument first and transform using XSL or just use Streamwriter and skip transformation altogether? The generated text file will be in EDIFACT format, so layout is very specific.

    Read the article

  • Filter a CSV list in XSLT

    - by Tom W
    Hello SO; I'm trying to convert xml elements whose content is a csv list of identifiers, the exact form doesn't matter. I want to exclude every item that contains the character "/". The best I've come up with is translate(./someElement, ",*/*", "") but this has at least two problems; I'm pretty sure that xsl doesn't accept wildcards, and "," is an illegal character in xpaths. Is there a straightforward way to do this sort of thing?

    Read the article

  • Using java provided parameters into xpath function while applying xslt transformation

    - by filmac
    I'm working at a java application that performs some xslt transformation. I would like to match nodes into the xslt document, using a parameter provided by java. Which is the right way to do something like: <xsl:template match="//m:properties/*[contains($pattern,name())]"> because when I launch my application, it claims it's not able to compile the stylesheet, since pattern is not defined but I'm setting it using the setParameter method and I was able to use another parameter defined in the same way but in a different context. Thanks in advance Fil

    Read the article

< Previous Page | 24 25 26 27 28 29 30 31 32 33 34  | Next Page >