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  • authorise user from mysql database

    - by Jacksta
    I suck at php, and cant find the error here. The script gets 2 variables "username" and "password" from a html from then check them against a MySQL databse. When I run this I get the follow error "Query was empty" <? if ((!$_POST[username]) || (!$_POST[password])) { header("Location: show_login.html"); exit; } $db_name = "testDB"; $table_name = "auth_users"; $connection = @mysql_connect("localhost", "admin", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $slq = "SELECT * FROM $table_name WHERE username ='$_POST[username]' AND password = password('$_POST[password]')"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = mysql_num_rows($result); if ($num != 0) { $msg = "<p>Congratulations, you're authorised!</p>"; } else { header("Location: show_login.html"); exit; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Secret Area</title> </head> <body> <? echo "$msg"; ?> </body> </html>

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  • Howto see if form fields are identical in Zend framework

    - by atjepatatje
    Hi there, In Zend Framework (1.10) i want to check if two input fields are identical I have the following code in my form: $this->addElement('password', 'password', array( 'label' => 'Wachtwoord:', 'required' => true ) ); $this->addElement('password', 'verifypassword', array( 'label' => 'Bevestig wachtwoord:', 'required' => true, ) ); I already tryed the "identical" validator, but I did'nt got it to work.

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  • How do I do client-side form validation in jQuery?

    - by marcamillion
    I am trying to use this plugin: http://docs.jquery.com/Plugins/Validation Where #user_new is the id for my form, this is what my code looks like: $('#user_new').validate({ rules: { user[username]: "required", user[email]: { required: true, email: true } }, messages: { user[username]: "Please specify your name", user[email]: { required: "We need your email address to contact you", email: "Your email address must be in the format of [email protected]" } } }) Where these are how my input fields look when the page is rendered (generated by Rails): <input class="clearField curved" id="user_f_name" name="user[f_name]" size="30" type="text" value="First Name" /><br /> <input class="clearField curved" id="user_l_name" name="user[l_name]" size="30" type="text" value="Last Name" /><br /> <input class="clearField curved" id="user_username" name="user[username]" size="30" type="text" value="Username" /><br /> <input class="clearField curved" id="user_password" name="user[password]" size="30" type="password" value="Password" /><br /> <input class="clearField curved" id="user_password_confirmation" name="user[password_confirmation]" size="30" type="password" value="Password" /><br /> <input class="clearField curved" id="user_email" name="user[email]" size="30" type="text" value="Email Address" /><br /> I was just trying to validate username & email first. Then take it from there. For the life of me, I can't figure out how to specify the syntax and the rules for working with this plugin. Help!

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  • SQL Server 2005 stored procedure error

    - by user1670625
    I have created a stored procedure of insert command for employee details in SQL Server 2005 in which one of the parameters is an image for which I have used varbinary as the datatype in the table.. But when I am adding that parameter in the stored procedure I am getting the following error- Implicit conversion from data type varchar to varbinary is not allowed. Use the CONVERT function to run this query. Stored procedure: ( @Employee_ID nvarchar(10)='', @Password nvarchar(10)='', @Security_Question nvarchar(50)='', @Answer nvarchar(50)='', @First_Name nvarchar(20)='', @Middle_Name nvarchar(20)='', @Last_Name nvarchar(20)='', @Employee_Type nvarchar(15)='', @Department nvarchar(15)='', @Photo varbinary(50)='' ) insert into Registration ( Employee_ID, Password, Security_Question, Answer, First_Name, Middle_Name, Last_Name, Employee_Type, Department, Photo ) values ( @Employee_ID, @Password, @Security_Question, @Answer, @First_Name, @Middle_Name, @Last_Name, @Employee_Type, @Department, @Photo ) Table structure: Column Name Data Type Allow Nulls Employee_ID nvarchar(10) Unchecked Password nvarchar(10) Checked Security_Question nvarchar(50) Checked Answer nvarchar(50) Checked First_Name nvarchar(20) Checked Middle_Name nvarchar(20) Checked Last_Name nvarchar(20) Checked Employee_Type nvarchar(15) Checked Department nvarchar(15) Checked Photo varbinary(50) Checked I am not getting what to do..can anyone give me some suggestion or solution? Thanks in advance.

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  • Why do i get segfault at the end of the application after everything's been done properly ?

    - by VaioIsBorn
    #include <string.h> #include <stdlib.h> #include <stdio.h> int main(void) { unsigned char *stole; unsigned char pass[] = "m4ak47"; printf("Vnesi password: \t"); scanf("%s", stole); if(strncmp(stole, pass, sizeof(pass)) != 0) { printf("wrong password!\n"); exit(0); } else printf("Password correct\n"); printf("some stuf here...\n\n"); return 0; } This program is working nice, but with one problem - if the password is correct then it DOES do the printing of 'some stuf here...' but it also shows me segmentation fault error at the end. Why ?

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  • Managing User Profiles with PHP/MySQL for Beginners

    - by serhio
    I am beginner in PHP/MySql and would develop a simple site that has user management. I like the idea of using OpenId's (like stackoverflow uses). I wonder from where to start? What should I read? I have not much time so probably will net enter in all details of PHP user session management, this because I search something like User profiles management in PHP for dummies 8D Environment: Linux OS Apache 2.2.15 MySQL 5.1.41 PHP 5.2.13 cPanel 11.25.0

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  • clean method for validation

    - by apoorva
    hi.. i have the following form class with corresponding clean methods... class SOFIATMUserLogin(forms.Form): Username=forms.CharField(label='Username') Password=forms.CharField(label='Password', widget=forms.PasswordInput) def clean_Username(self): user=self.cleaned_data['Username'] try: SOFIALogin.objects.get(UserName=user) except Exception: raise forms.ValidationError('Username invalid...') def clean_Password(self): upass=self.cleaned_data['Password'] In the clean_Password method i wish to check if the password entered for the valid username is correct... So i need to get the Username value... How can i access this in clean_Password method... Please assist!!!!

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  • Using Maven to Deploy to Weblogic Clusters

    - by Mark Sailes
    org.codehaus.mojo weblogic-maven-plugin 2.9.1 We're currently using the weblogic maven plugin successfully to deploy to our local WebLogic 9.2 instances. When we try to deploy to a remote environment we have a problem. We use a two machine cluster, with the admin server and managed server on one machine, and another managed server on a seperate machine. When your plugin uploads the application to the admin server, it doesn't copy it to the second managed server on the seperate machine. This then causes the second managed server a problem, as it cannot find the application in the location where the admin server saved it on its own machine. Config below <configuration> <adminServerHostName>${weblogic.adminServerHostName}</adminServerHostName> <adminServerPort>${weblogic.adminServerPort}</adminServerPort> <adminServerProtocol>${weblogic.adminServerProtocol}</adminServerProtocol> <userId>${weblogic.userId}</userId> <password>${weblogic.password}</password> <upload>${weblogic.upload}</upload> <remote>${weblogic.remote}</remote> <verbose>${weblogic.verbose}</verbose> <debug>${weblogic.debug}</debug> <stage>${weblogic.stage}</stage> <targetNames>${weblogic.targetNames}</targetNames> <exploded>${weblogic.exploded}</exploded> </configuration> <profile> <id>localhost</id> <properties> <weblogic.adminServerHostName>localhost</weblogic.adminServerHostName> <weblogic.adminServerPort>7001</weblogic.adminServerPort> <weblogic.adminServerProtocol>t3</weblogic.adminServerProtocol> <weblogic.userId>weblogic</weblogic.userId> <weblogic.password>weblogic</weblogic.password> <weblogic.upload>false</weblogic.upload> <weblogic.remote>false</weblogic.remote> <weblogic.verbose>true</weblogic.verbose> <weblogic.debug>true</weblogic.debug> <weblogic.stage>false</weblogic.stage> <weblogic.targetNames>AdminServer</weblogic.targetNames> <weblogic.exploded>false</weblogic.exploded> </properties> </profile> <profile> <id>dev</id> <properties> <weblogic.adminServerHostName>******</weblogic.adminServerHostName> <weblogic.adminServerPort>9141</weblogic.adminServerPort> <weblogic.adminServerProtocol>t3</weblogic.adminServerProtocol> <weblogic.userId>******</weblogic.userId> <weblogic.password>******</weblogic.password> <weblogic.upload>true</weblogic.upload> <weblogic.remote>true</weblogic.remote> <weblogic.verbose>true</weblogic.verbose> <weblogic.debug>true</weblogic.debug> <weblogic.stage>true</weblogic.stage> <weblogic.targetNames>dev_cluster01</weblogic.targetNames> <weblogic.exploded>false</weblogic.exploded> </properties> </profile>

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  • RMO on Windows 7 - The Specified module could not be found

    - by AGoodDisplayName
    My machine: Windows XP (x86), VS2008, .net 3.5, sql server 2005, WinForms - App works fine. Production Machines: Windows 7 (x64), SQl Server 2005 Express - App Starts but throws exception Visual Studio Targeting x86 on setup project and RMO project. Visual Studio gives me a a couple warnings but I can still build: Unable to find dependency 'MICROSOFT.SQLSERVER.MANAGEMENT.SQLPARSER' (Signature='89845DCD8080CC91' Version='10.0.0.0') of assembly 'Microsoft.SqlServer.Smo.dll' Unable to find dependency 'MICROSOFT.SQLSERVER.MANAGEMENT.SQLPARSER' (Signature='89845DCD8080CC91' Version='10.0.0.0') of assembly 'Microsoft.SqlServer.Management.SmoMetadataProvider.dll' This is a simple RMO (Replication Management Objects) app that initiates a pull subscription in SQL Server 2005 and displays status. Works fine on my machine, but fails on the production machine. I'm using a setup project to install the app on the production machine, but I think I'm missing a dependency somewhere, but I can't figure it out. On the production machine the app starts fine, but when I try to synch the subscription i get: System.IO.FileNotFoundException: The Specified module could not be found. (Exception from HResult: 0x8007007E)

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  • Remote application monitoring through Visual GC

    - by Poole
    I am trying to monitor an application available on remote machine using VisualVM & Visual GC. I have enabled the jmxremote on the remote side as follows: -Dcom.sun.management.jmxremote, -Dcom.sun.management.jmxremote.port=8888, -Dcom.sun.management.jmxremote.ssl=false, -Dcom.sun.management.jmxremote.authenticate=false While monitoring through VisualVM, everything runs fine but VisualGC doesn't displays any stats (getting Not Supported for this JVM error). While tried to monitor one local application, VisualGC runs fine... Got success with the remote app once started jstad on the remote jvm. Is this a known issue with VisualGC...? Remote JVM - 1.5 Local JVM - 1.6

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  • Python having problems writing/reading and testing in a correct format

    - by Ionut
    I’m trying to make a program that will do the following: check if auth_file exists if yes - read file and try to login using data from that file - if data is wrong - request new data if no - request some data and then create the file and fill it with requested data So far: import json import getpass import os import requests filename = ".auth_data" auth_file = os.path.realpath(filename) url = 'http://example.com/api' headers = {'content-type': 'application/json'} def load_auth_file(): try: f = open(auth_file, "r") auth_data = f.read() r = requests.get(url, auth=auth_data, headers=headers) if r.reason == 'OK': return auth_data else: print "Incorrect login..." req_auth() except IOError: f = file(auth_file, "w") f.write(req_auth()) f.close() def req_auth(): user = str(raw_input('Username: ')) password = getpass.getpass('Password: ') auth_data = (user, password) r = requests.get(url, auth=auth_data, headers=headers) if r.reason == 'OK': return user, password elif r.reason == "FORBIDDEN": print "Incorrect login information..." req_auth() return False I have the following problems(understanding and applying the correct way): I can't find a correct way of storing the returned data from req_auth() to auth_file in a format that can be read and used in load_auth file PS: Of course I'm a beginner in Python and I'm sure I have missed some key elements here :(

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  • how to redirect user depending on user type at time of login (codeignitor)

    - by Anam Tahir
    im facing problem while redirecting my user according to its type. how can do it here's my code plz suggest how to do it. <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class VerifyLogin extends CI_Controller { function __construct() { parent::__construct(); } function index() { $this->load->model('user','',TRUE); //This method will have the credentials validation $this->load->library('form_validation'); $this->load->library('session'); $this->form_validation->set_rules('username', 'Username','trim|required|xss_clean'); $this->form_validation->set_rules('password', 'Password' 'trim|required|xss_clean|callback_check_database'); if($this->form_validation->run() == FALSE) { //Field validation failed.&nbsp; User redirected to login page validation_errors(); $this->load->view('error'); } else { //Go to private area basically here i want to redirect if user is admin then redirect to admin page else redirect to home how can i do this ??? redirect('home', 'refresh'); } } function check_database($password) { //Field validation succeeded.&nbsp; Validate against database $username = $this->input->post('username'); //query the database $result = $this->user->login($username, $password); if($result) { $sess_array = array(); foreach($result as $row) { $sess_array = array( 'id' => $row->id, 'username' => $row->username ); $this->session->set_userdata('logged_in', $sess_array); } return TRUE; } else { $this->form_validation->set_message('check_database', 'Invalid username or password'); return false; } } } ?>

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  • Do similar passwords have similar hashes?

    - by SLC
    Our computer system at work requires users to change their password every few weeks, and you cannot have the same password as you had previously. It remembers something like 20 of your last passwords. I discovered most people simply increment a digit at the end of their password, so "thisismypassword1" becomes "thisismypassword2" then 3, 4, 5 etc. Since all of these passwords are stored somewhere, I wondered if there was any weakness in the hashes themselves, for standard hashing algorithms used to store passwords like MD5. Could a hacker increase their chances of brute-forcing the password if they have a list of hashes of similar passwords?

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  • create hgrc file for all paths on a machine

    - by noam
    I want to create a hgrc file to set the username and password for all paths on some machine, e.g no matter in which directory I am in, hg clone some_path will always work without prompting for a username and a password (this is for an auto-deploy script). I followed the instructions and created a file: /etc/mercurial/hgrc.d/deploy.rc it's contents: [auth] default.prefix= http://myrepo default.username = myuname default.password = pwd But when I do hg clone some_path I get abort: error: Connection refused. What Am i doing wrong?

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  • Security-Active Application in background-Does it store image of current screen

    - by user1509593
    Is this a probable security flaw. A user in public (lets say Starbucks) tries to log in to iOS application. He enters user id and password [Password is hidden using xxxxxxxx (not exposed)] and a call comes in or he presses home and the application goes to background. a) Does iOS store an image of current screen b) A malicious hacker with intent takes control of the device. Can he read the password ? Do we have to clear out sensitive information while going to background

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  • Paramiko ssh output stops at --more--

    - by Anesh
    The output stops printing at --more-- any idea how to get the end of the output >>> import paramiko >>> ssh = paramiko.SSHClient() >>> ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy()) >>> conn=ssh.connect("ipaddress",username="user", password="pass") >>> channel = ssh.invoke_shell() >>> channel.send("en\n") 3 >>> channel.send("password\n") 9 >>> channel.send("show security local-user-list\n") 30 >>> results = '' >>> channel.send("\n") 1 >>> results += channel.recv(5000) >>> print results bluecoat>en Password: bluecoat#show security local-user-list Default List: local_user_database Append users loaded from file to default list: false local_user_database Lockout parameters: Max failed attempts: 60 Lockout duration: 3600 Reset interval: 7200 Users: Groups: admin_local Lockout parameters: Max failed attempts: 60 Lockout duration: 3600 Reset interval: 7200 Users: <username> Hashed Password: Enabled: true Groups: <username> Hashed Password: Enabled: true **--More--** As you can see above the output stops printing at --more-- any idea how to get the output to print till the end.

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  • Problems with Ruby "||" "or"?

    - by Kevin
    Beginning Ruby Question: I'm trying to see if a string variable's contents is either "personal" "email" or "password". I'm trying: if params[:action] == "password" || "email" || "personal" foo else don't foo end But that doesn't work and returns strange results, and using IRB to play around with "or" statements I have no idea why the following happens: irb(main):040:0> a = "email" => "email" irb(main):041:0> a == "password" || "email" => "email" irb(main):042:0> a == "email" || "password" => true I just want something that if any of the 3 variables are true no matter what order they are in it returns true, if not it returns false. Anyone want to help this n00b out?

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  • Zend Framework :: Is this code good for user login (Its begining- because that I want to know if its

    - by Yosef
    Hi, I new in Zend. Main Question: Is this code good for user login (Its beginning- because that I want to know if its can be improve)? Code understanding question: Is every time that in action call to his view- code execution in action not going to next row until view request? (I asking about IndexAction that I write down) Thanks view index.phtml <? echo $this->form controller IndexAction.php public function indexAction() { $form=new Application_Form_Login(); $this->view->form = $form; if ($this->getRequest()->isPost()) { $formData = $this->getRequest()->getPost(); if ($form->isValid($formData)) { echo " test value username: ".$form->getValue('username'); } } } form Login.php public function init() { $this->setMethod('post'); $this->setName('user login'); $username = new Zend_Form_Element_Text('username'); $username->setLabel("username") ->setRequired(true) ->addFilter('StripTags') ->addFilter('StringTrim') ->addValidator('NotEmpty'); $password = new Zend_Form_Element_Password('password'); $password->setLabel('password') ->setRequired(true) ->addFilter('StripTags') ->addFilter('StringTrim') ->addValidator('NotEmpty'); $submit = new Zend_Form_Element_Submit('submit'); $this->addElements(array($username, $password, $submit)); }

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  • Accessing SVN repository from CCNet (CruiseControl.net) using an Active Directory user

    - by Tr1stan
    I have CCNet setup to talk to our SVN repository, which has it's ACLs setup using Active Directory groups. This is working fine, except I'm not happy with having the user name and password of the AD user stored in plain text on the CCNet instance. Is there a way to either encrypt the AD username/password, or get the CCNet service (I've tried running the service as the user and removing the the username/password section of the CCNet/SVN config) to use a domain account outside of the standard config?

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  • Problem with PHP; Posting Hidden Value!!?

    - by Derek
    Hi, I have a page which basically allows an admin user to create manager user types (basically a register function. So when the values are submitted, they are stored into the DB, very very basic stuff. However, I have a hidden variable type..reasons are I have 3 different user levels and I have declared they identification as an integer (e.g. 7 = manager, 8 =user etc.) Can someone help me out with how to correctly pass this hidden value so it stores in the database... Here is my form: <form id="userreg" name="userreg" method="post" action="adminadduser-process.php"> <label>Full Name:</label> <input name="fullname" size="40" id="fullname" value="<?php if (isset($_POST['fullname'])); ?>"/> <br /> <label>Username:</label> <input name="username" size="40" id="username" value="<?php if (isset($_POST['username'])); ?>"/> <br /> <label>Password:</label> <input name="password" size="40" id="password" value="<?php if (isset($_POST['password'])); ?>"/> <br /> <label>Email Address:</label> <input name="emailaddress" size="40" id="emailaddress" value="<?php if (isset($_POST['emailaddress'])); ?>"/> <br /> <input name="userlevel" type="hidden" size="1" id="userlevel" value="<?php $_POST[5]; ?>" /> <br /> <input value="Add User" class="addbtn" type="submit" /> </form></div> Next, here is the script that runs the query: <?php require_once "config.php"; $fullname = $_POST['fullname']; $username = $_POST['username']; $password = $_POST['password']; $emailaddress = $_POST['emailaddress']; $userlevel = $_POST[5]; $sql = "INSERT INTO users_tb VALUES('".$user_id."','".$fullname."','".$username."',MD5('".$password."'),'".$emailaddress."','".$userlevel."')"; $result = mysql_query($sql, $connection) or die("MySQL Error: ".mysql_error()); header("Location: adminhome.php"); exit(); ?> I'm basically trying to pass the hidden typem with a constant value of '5' just for this form, as it will not be changed...also while im here, for some reason, the 'fullname' is not stored in the DB either!!?? WTH?? all other fields are processed fine. Any help is much appreciated! Thank you.

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  • Ruby - Passing Blocks To Methods

    - by Chris Bunch
    I'm trying to do Ruby password input with the Highline gem and since I have the user input the password twice, I'd like to eliminate the duplication on the blocks I'm passing in. For example, a simple version of what I'm doing right now is: new_pass = ask("Enter your new password: ") { |prompt| prompt.echo = false } verify_pass = ask("Enter again to verify: ") { |prompt| prompt.echo = false } And what I'd like to change it to is something like this: foo = Proc.new { |prompt| prompt.echo = false } new_pass = ask("Enter your new password: ") foo verify_pass = ask("Enter again to verify: ") foo Which unfortunately doesn't work. What's the correct way to do this?

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  • ANDROID IF/ELSE FAILS CONTINUES TO EXECUTE JSON

    - by Keith Cesar Haizlett
    I am trying to create a Registration app with JSON to connect and post to MYSQL database. I created the following IF/ELSE statements to check for vacant input boxes, password match, and correct email characters before allowing it to be entered into the DATABASE. The code continues to execute the JSON posting even after the passwords don't match , invalid email characters are entered , and vacant text boxes are submitted. Why is it not returning and continuing to execute the JSON code? try { if (!inputEmail.getText().toString().matches("[a-zA-Z0-9._-]+@[a-z]+.[a-z]+") && email.length() > 0) { Toast.makeText(getApplicationContext(), "Enter Valid Email Address", Toast.LENGTH_LONG).show(); return; } else if(name.equals("") || email.equals("")|| password.equals("")||check.equals("")) { Toast.makeText(getApplicationContext(), "Field Vaccant", Toast.LENGTH_LONG).show(); return; } // check if both password matches else if(!password.equals(checkpass)) { Toast.makeText(getApplicationContext(), "Password does not match", Toast.LENGTH_LONG).show(); return; } if (json.getString(KEY_SUCCESS) != null) { registerErrorMsg.setText(""); String res = json.getString(KEY_SUCCESS); if(Integer.parseInt(res) == 1){ // user successfully registred // Store user details in SQLite Database DatabaseHandler db = new DatabaseHandler(getApplicationContext()); JSONObject json_user = json.getJSONObject("user"); // Clear all previous data in database userFunction.logoutUser(getApplicationContext()); db.addUser(json_user.getString(KEY_NAME), json_user.getString(KEY_EMAIL), json.getString(KEY_UID), json_user.getString(KEY_CREATED_AT)); // Launch Dashboard Screen Intent dashboard = new Intent(getApplicationContext(), DashboardActivity.class); // Close all views before launching Dashboard dashboard.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP); startActivity(dashboard); // Close Registration Screen finish(); }else{ // Error in registration registerErrorMsg.setText("User already Registered"); } } } catch (JSONException e) { } } });

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  • IE problem with javascript

    - by Syom
    i have the following simple script <input class="input" type="text" name="password" style="color: #797272;" value= "<?php if ($_POST[password] != '') {echo '';} else {echo '????????';}?>" onclick="if (this.value === this.defaultValue) { this.value=''; this.style.color='black'; this.type='password'; }" /> it works fine, but in IE7 it doesn't change the input type. this.type='password'; doesn't work could you help me? thanks

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  • Why Backbone.js isn't binding my event

    - by Saif Bechan
    I have a router like this, as main entry point: window.AppRouter = Backbone.Router.extend({ routes: { '': 'login' }, login: function(){ userLoginView = new UserLoginView(); } }); var appRouter = new AppRouter; Backbone.history.start({pushState: true}); I have a model/collection/view like this: window.User = Backbone.Model.extend({}); window.Users = Backbone.Collection.extend({ model: User }); window.UserLoginView = Backbone.View.extend({ events: { 'click #login-button': 'loginAction' }, initialize: function(){ _.bindAll(this, 'render', 'loginAction'); }, loginAction: function(){ var uid = $("#login-username").val(); var pwd = $("#login-password").val(); var user = new User({uid:uid, pwd:pwd}); } }); And body of my HTML looks like this: <form action="#" method="POST" id="login-form"> <p> <label for="login-username">username</label> <input type="text" id="login-username" autofocus /> </p> <p> <label for="login-password">password</label> <input type="password" id="login-password" /> </p> <a id="login-button" href="#">Inloggen</a> </form> Note: The HTML comes from Node.js using express.js, should I maybe wait for a document ready event somewhere? Edit: I have tried this, create the view when ready, did not solve the problem. $(function(){ userLoginView = new UserLoginView(); });

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  • Cannot Generate ParameterSetMetadata While Programmatically Creating A Parameter Block

    - by Steven Murawski
    I'm trying to programmatically create a parameter block for a function ( along the lines of this blog post ). I'm starting with a CommandMetadata object (from an existing function). I can create the ParameterMetadata object and set things like the ParameterType, the name, as well as some attributes. The problem I'm running into is that when I use the GetParamBlock method of the ProxyCommand class, none of my attributes that I set in the Attributes collection of the ParameterMetadata are generated. The problem this causes is that when the GetParamBlock is called, the new parameter is not annotated with the appropriate Parameter attribute. Example: function test { [CmdletBinding()] param ( [Parameter()] $InitialParameter) Write-Host "I don't matter." } $MetaData = New-Object System.Management.Automation.CommandMetaData (get-command test) $NewParameter = New-Object System.Management.Automation.ParameterMetadata 'NewParameter' $NewParameter.ParameterType = [string[]] $Attribute = New-Object System.Management.Automation.ParameterAttribute $Attribute.Position = 1 $Attribute.Mandatory = $true $Attribute.ValueFromPipeline = $true $NewParameter.Attributes.Add($Attribute) $MetaData.Parameters.Add('NewParameter', $NewParameter) [System.Management.Automation.ProxyCommand]::GetParamBlock($MetaData)

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