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• In a multidisciplicary team, how much should each member's skills overlap?

  - by spade78

  I've been working in embedded software development for this small startup and our team is pretty small: about 3-4 people. We're responsible for all engineering which involves an RF device controlled by an embedded microcontroller that connects to a PC host which runs some sort of data collection and analysis software. I have come to develop these two guidelines when I work with my colleagues: Define a clear separation of responsibilities and make sure each person's contribution to the final product doesn't overlap. Don't assume your colleagues know everything about their responsibilities. I assume there is some sort of technology that I will need to be competent at to properly interface with the work of my colleagues. The first point is pretty easy for us. I do firmware, one guy does the RF, another does the PC software, and the last does the DSP work. Nothing overlaps in terms of two people's work being mixed into the final product. For that to happen, one guy has to hand off work to another guy who will vet it and integrate it himself. The second point is the heart of my question. I've learned the hard way not to trust the knowledge of my colleagues absolutley no matter how many years experience they claim to have. At least not until they've demonstrated it to me a couple of times. So given that whenever I develop a piece of firmware, if it interfaces with some technology that I don't know then I'll try to learn it and develop a piece of test code that helps me understand what they're doing. That way if my piece of the product comes into conflict with another piece then I have some knowledge about possible causes. For example, the PC guy has started implementing his GUI's in .NET WPF (C#) and using LibUSBdotNET for USB access. So I've been learning C# and the .NET USB library that he uses and I build a little console app to help me understand how that USB library works. Now all this takes extra time and energy but I feel it's justified as it gives me a foothold to confront integration problems. Also I like learning this new stuff so I don't mind. On the other hand I can see how this can turn into a time synch for work that won't make it into the final product and may never turn into a problem. So how much experience/skills overlap do you expect in your teammates relative to your own skills? Does this issue go away as the teams get bigger and more diverse?

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• Questions about identifying the components in MVC

  - by luiscubal

  I'm currently developing an client-server application in node.js, Express, mustache and MySQL. However, I believe this question should be mostly language and framework agnostic. This is the first time I'm doing a real MVC application and I'm having trouble deciding exactly what means each component. (I've done web applications that could perhaps be called MVC before, but I wouldn't confidently refer to them as such) I have a server.js that ties the whole application together. It does initialization of all other components (including the database connection, and what I think are the "models" and the "views"), receiving HTTP requests and deciding which "views" to use. Does this mean that my server.js file is the controller? Or am I mixing code that doesn't belong there? What components should I break the server.js file into? Some examples of code that's in the server.js file: var connection = mysql.createConnection({ host : 'localhost', user : 'root', password : 'sqlrevenge', database : 'blog' }); //... app.get("/login", function (req, res) { //Function handles a GET request for login forms if (process.env.NODE_ENV == 'DEVELOPMENT') { mu.clearCache(); } session.session_from_request(connection, req, function (err, session) { if (err) { console.log('index.js session error', err); session = null; } login_view.html(res, user_model, post_model, session, mu); //I named my view functions "html" for the case I might want to add other output types (such as a JSON API), or should I opt for completely separate views then? }); }); I have another file that belongs named session.js. It receives a cookies object, reads the stored data to decide if it's a valid user session or not. It also includes a function named login that does change the value of cookies. First, I thought it would be part of the controller, since it kind of dealt with user input and supplied data to the models. Then, I thought that maybe it was a model since it dealt with the application data/database and the data it supplies is used by views. Now, I'm even wondering if it could be considered a View, since it outputs data (cookies are part of HTTP headers, which are output)

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• efficient collision detection - tile based html5/javascript game

  - by Tom Burman

  Im building a basic rpg game and onto collisions/pickups etc now. Its tile based and im using html5 and javascript. i use a 2d array to create my tilemap. Im currently using a switch statement for whatever key has been pressed to move the player, inside the switch statement. I have if statements to stop the player going off the edge of the map and viewport and also if they player is about to land on a tile with tileID 3 then the player stops. Here is the statement: canvas.addEventListener('keydown', function(e) { console.log(e); var key = null; switch (e.which) { case 37: // Left if (playerX > 0) { playerX--; } if(board[playerX][playerY] == 3){ playerX++; } break; case 38: // Up if (playerY > 0) playerY--; if(board[playerX][playerY] == 3){ playerY++; } break; case 39: // Right if (playerX < worldWidth) { playerX++; } if(board[playerX][playerY] == 3){ playerX--; } break; case 40: // Down if (playerY < worldHeight) playerY++; if(board[playerX][playerY] == 3){ playerY--; } break; } viewX = playerX - Math.floor(0.5 * viewWidth); if (viewX < 0) viewX = 0; if (viewX+viewWidth > worldWidth) viewX = worldWidth - viewWidth; viewY = playerY - Math.floor(0.5 * viewHeight); if (viewY < 0) viewY = 0; if (viewY+viewHeight > worldHeight) viewY = worldHeight - viewHeight; }, false); My question is, is there a more efficient way of handling collisions, then loads of if statements for each key? The reason i ask is because i plan on having many items that the player will need to be able to pickup or not walk through like walls cliffs etc. Thanks for your time and help Tom

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• Advice for how to handle company pride

  - by user17971

  We have this "amazing" little product using the latest development methodologies, components with all the bells and whistles. I took over this product maybe 6 months ago and struggled with it from day one. Even though it is supposedly is state of the art because of all its amazing structure, using dependency injections, inversion of control from the unity framework, hibernation and is domain driven in a .net mvvm xaml application to make it streamlined and modular. I knew from the moment I saw the monolith that it was going to be an uphill struggle for me. A lot of little code-bits scattered all around in neatly organized paradigms. Debugging is difficult, tracing the code is difficult, making new code is difficult, although some modifications is surprisinly easy but it doesn't out weight the problems I have with the code by a long shot. When I took over the project I was told that the new management console was ready for delivery and all I had to do was compile it and drop it. This was the beginning of a uphill struggle, our customer didn't agree at all that this was the functionality they had asked for so I had to do modifications to the program to their specifications. Since the project pretty much has been overdue since I took over it it has always been important that we didn't add or change much to the original system. I could modify the existing bits. fast forward until today where I finally completed all their comments and issues with the program but now I think that the users has opened their eyes (even though they saw this program many times) that they will be going backwards with this new system, that it will be much worse than the tool they got today (for a long time due to the fact that I'm the only resource on the project, project manager, tester, developer, integration specialist etc) My problem is that I lost faith in this system quite early due to the nature of the program. Although I made many changes and improvements to the system I wholeheartedly sympathize with the poor users who are going to start using this system. Its not nearly doing all the things it should do. I had this conversation internally with my boss where I told him what I thought about it, that if I were the customer I wouldn't have spent money developing it. So what do I do now? The system in ready, on a staging system and nobody likes it, its too slow and boring and does maybe do 50% of what they need it to do. Despite how much energy and working around the clock I've done to this project: I won't mind scrapping the system but we've spent much money (well my salaries) developing it and my company wants us to be proud of everything we do and advocate it. How will I tackle the contractor when he asks for advice? Surely I can tell him, this is what we agreed upon based on your use case scenarios, and be done with it? How will I inform my boss about this progress? He knows what I feel about it but I always get the feeling he let my criticism pass him by as just hot air, gone tomorrow,.

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• Error while removing the new kernel 2.6.37

  - by Tarek

  Hi! I tried to install the new kernel but something went wrong and I'm trying to remove it now. The error massege is: mhd@Tarek-Laptop:~$ sudo apt-get install -f Reading package lists... Done Building dependency tree Reading state information... Done The following packages will be REMOVED: linux-image-2.6.37-020637-generic 0 upgraded, 0 newly installed, 1 to remove and 9 not upgraded. 1 not fully installed or removed. After this operation, 111MB disk space will be freed. Do you want to continue [Y/n]? y (Reading database ... 188780 files and directories currently installed.) Removing linux-image-2.6.37-020637-generic ... Examining /etc/kernel/postrm.d . run-parts: executing /etc/kernel/postrm.d/initramfs-tools 2.6.37-020637-generic /boot/vmlinuz-2.6.37-020637-generic run-parts: executing /etc/kernel/postrm.d/zz-update-grub 2.6.37-020637-generic /boot/vmlinuz-2.6.37-020637-generic /etc/default/grub: 33: Syntax error: EOF in backquote substitution run-parts: /etc/kernel/postrm.d/zz-update-grub exited with return code 2 Failed to process /etc/kernel/postrm.d at /var/lib/dpkg/info/linux-image-2.6.37-020637-generic.postrm line 328. dpkg: error processing linux-image-2.6.37-020637-generic (--remove): subprocess installed post-removal script returned error exit status 1 Errors were encountered while processing: linux-image-2.6.37-020637-generic E: Sub-process /usr/bin/dpkg returned an error code (1) The previous unsloved error is on this bug. This is my grub configuration file: # If you change this file, run 'update-grub' afterwards to update # /boot/grub/grub.cfg. GRUB_DEFAULT=0 #GRUB_HIDDEN_TIMEOUT=0 GRUB_HIDDEN_TIMEOUT_QUIET=true GRUB_TIMEOUT=10 GRUB_DISTRIBUTOR=`lsb_release -i -s 2> /dev/null || echo Debian` RUB_CMDLINE_LINUX_DEFAULT="quiet splash nomodeset video=uvesafb:mode_option=1024x768-24,mtrr=3,scroll=ywrap" video=uvesafb:mode_option=>>1024x768-24<<,mtrr=3,scroll=ywrap" GRUB_CMDLINE_LINUX=" vga=792 splash" # Uncomment to enable BadRAM filtering, modify to suit your needs # This works with Linux (no patch required) and with any kernel that obtains # the memory map information from GRUB (GNU Mach, kernel of FreeBSD ...) #GRUB_BADRAM="0x01234567,0xfefefefe,0x89abcdef,0xefefefef" # Uncomment to disable graphical terminal (grub-pc only) #GRUB_TERMINAL=console # The resolution used on graphical terminal # note that you can use only modes which your graphic card supports via VBE # you can see them in real GRUB with the command `vbeinfo' GRUB_GFXMODE=1024x768-24 # Uncomment if you don't want GRUB to pass "root=UUID=xxx" parameter to Linux #GRUB_DISABLE_LINUX_UUID=true # Uncomment to disable generation of recovery mode menu entries #GRUB_DISABLE_LINUX_RECOVERY="true" # Uncomment to get a beep at grub start #GRUB_INIT_TUNE="480 440 1" thank you for answering.

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• WIF, ADFS 2 and WCF&ndash;Part 1: Overview

  - by Your DisplayName here!

  A lot has been written already about passive federation and integration of WIF and ADFS 2 into web apps. The whole active/WS-Trust feature area is much less documented or covered in articles and blogs. Over the next few posts I will try to compile all relevant information about the above topics – but let’s start with an overview. ADFS 2 has a number of endpoints under the /services/trust base address that implement the WS-Trust protocol. They are grouped by the WS-Trust version they support (/13 and /2005), the client credential type (/windows*, /username*, /certificate*) and the security mode (*transport, *mixed and message). You can see the endpoints in the MMC console under the Service/Endpoints page. So in other words, you use one of these endpoints (which exactly depends on your configuration / system setup) to request tokens from ADFS 2. The bindings behind the endpoints are more or less standard WCF bindings, but with SecureConversation (establishSecurityContext) disabled. That means that whenever you need to programmatically talk to these endpoints – you can (easily) create client bindings that are compatible. Another option is to use the special bindings that come with WIF (in the Microsoft.IdentityModel.Protocols.WSTrust.Bindings namespace). They are already pre-configured to be compatible with the ADFS endpoints. The downside of these bindings is, that you can’t use them in configuration. That’s definitely a feature request of mine for the next version of WIF. The next important piece of information is the so called Federation Service Identifier. This is the value that you (at least by default) have to use as a realm/appliesTo whenever you are requesting a token for ADFS (e.g. in  IdP –> RSTS scenario). Or (even more) technically speaking, ADFS 2 checks for this value in the audience URI restriction in SAML tokens. You can get to this value by clicking the “Edit Federation Service Properties” in the MMC when the Service tree-node is selected. OK – I will come back to this basic information in the following posts. Basically I want to go through the following scenarios: ADFS in the IdP role ADFS in the R-STS role (with a chained claims provider) Using the WCF bindings for automatic token issuance Using WSTrustChannelFactory for manual token handling Stay tuned…

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• Enum types, FlagAttribute & Zero value

  - by nmgomes

  We all know about Enums types and use them every single day. What is not that often used is to decorate the Enum type with the FlagsAttribute. When an Enum type has the FlagsAttribute we can assign multiple values to it and thus combine multiple information into a single enum. The enum values should be a power of two so that a bit set is achieved. Here is a typical Enum type: public enum OperationMode { /// <summary> /// No operation mode /// </summary> None = 0, /// <summary> /// Standard operation mode /// </summary> Standard = 1, /// <summary> /// Accept bubble requests mode /// </summary> Parent = 2 } In such scenario no values combination are possible. In the following scenario a default operation mode exists and combination is used: [Flags] public enum OperationMode { /// <summary> /// Asynchronous operation mode /// </summary> Async = 0, /// <summary> /// Synchronous operation mode /// </summary> Sync = 1, /// <summary> /// Accept bubble requests mode /// </summary> Parent = 2 } Now, it’s possible to do statements like: [DefaultValue(OperationMode.Async)] [TypeConverter(typeof(EnumConverter))] public OperationMode Mode { get; set; } /// <summary> /// Gets a value indicating whether this instance supports request from childrens. /// </summary> public bool IsParent { get { return (this.Mode & OperationMode.Parent) == OperationMode.Parent; } } or switch (this.Mode) { case OperationMode.Sync | OperationMode.Parent: Console.WriteLine("Sync,Parent"); break;[…]  But there is something that you should never forget: Zero is the absorber element for the bitwise AND operation. So, checking for OperationMode.Async (the Zero value) mode just like the OperationMode.Parent mode makes no sense since it will always be true: (this.Mode & 0x0) == 0x0 Instead, inverse logic should be used: OperationMode.Async = !OperationMode.Sync public bool IsAsync { get { return (this.Mode & ContentManagerOperationMode.Sync) != ContentManagerOperationMode.Sync; } } or public bool IsAsync { get { return (int)this.Mode == 0; } } Final Note: Benefits Allow multiple values combination The above samples snippets were taken from an ASP.NET control and enabled the following markup usage: <my:Control runat="server" Mode="Sync,Parent"> Drawback Zero value is the absorber element for the bitwise AND operation Be very carefully when evaluating the Zero value, either evaluate the enum value as an integer or use inverse logic.

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• Why does switching users completely hang my system every time?

  - by Stéphane

  I have a fresh install of 11.04 64bit, with 2 administrator accounts and 4 normal accounts. The 4 normal accounts (the kids' accounts) don't have passwords, they can login simply by clicking on their names. When any of the users -- either admin or normal -- tries to switch to another account by clicking in the top-right corner of the screen and selecting another user, the screen goes black and the entire system locks up. Even CTRL+ALT+F1 through F7 does nothing. This is reproducible 100% of the time on this system. I can ssh into the box when the console locks up, and by running top, I see that Xorg is consuming about 100% of the CPU. Looking at the output of "ps axfu" in bash while the system is in this "locked up" state, here is the lightdm and X process tree: USER PID %CPU %MEM VSZ RSS TTY STAT START TIME COMMAND root 1153 0.0 0.1 183508 4292 ? Ssl Dec26 0:00 lightdm root 2187 0.4 4.6 265976 164168 tty7 Ss+ 00:43 0:21 \_ /usr/bin/X :0 -auth /var/run/lightdm/root/:0 -nolisten tcp vt7 -novtswitch stephane 2612 0.0 0.3 266400 10736 ? Ssl 01:52 0:00 \_ /usr/bin/gnome-session --session=ubuntu stephane 2650 0.0 0.0 12264 276 ? Ss 01:52 0:00 | \_ /usr/bin/ssh-agent /usr/bin/dbus-launch --exit-with-session /usr/bin/gnome-session --session=ubuntu stephane 2703 0.8 3.0 562068 106548 ? Sl 01:52 0:08 | \_ compiz stephane 2801 0.0 0.0 4264 584 ? Ss 01:52 0:00 | | \_ /bin/sh -c /usr/bin/compiz-decorator stephane 2802 0.0 0.3 265744 13772 ? Sl 01:52 0:00 | | \_ /usr/bin/unity-window-decorator ...cut... root 3024 80.6 0.3 107928 13088 tty8 Rs+ 01:53 12:34 \_ /usr/bin/X :1 -auth /var/run/lightdm/root/:1 -nolisten tcp vt8 -novtswitch That last process, pid #3024 in this case, is what has the CPU pegged. In case it matters (I suspect it might) here is what I think may be the relevant information for my video card, taken from /var/log/Xorg.0.log: [ 3392.653] (II) Loading /usr/lib/x86_64-linux-gnu/xorg/extra-modules/extra-modules.dpkg-tmp/modules/extensions/libglx.so [ 3392.653] (II) Module glx: vendor="FireGL - AMD Technologies Inc." [ 3392.653] compiled for 6.9.0, module version = 1.0.0 ... [ 3392.655] (II) LoadModule: "fglrx" [ 3392.655] (II) Loading /usr/lib/x86_64-linux-gnu/xorg/extra-modules/extra-modules.dpkg-tmp/modules/drivers/fglrx_drv.so [ 3392.672] (II) Module fglrx: vendor="FireGL - ATI Technologies Inc." [ 3392.672] compiled for 1.4.99.906, module version = 8.88.7 [ 3392.672] Module class: X.Org Video Driver ... [ 3392.759] (==) fglrx(0): ATI 2D Acceleration Architecture enabled [ 3392.759] (--) fglrx(0): Chipset: "AMD Radeon HD 6410D" (Chipset = 0x9644) Lastly: I did see this posting: Change user on 11.10 hangs system ...but I checked, and the libpam-smbpass package isn't installed on this system.

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• Enabling EUS support in OUD 11gR2 using command line interface

  - by Sylvain Duloutre

  Enterprise User Security (EUS) allows Oracle Database to use users & roles stored in LDAP for authentication and authorization.Since the 11gR2 release, OUD natively supports EUS. EUS can be easily configured during OUD setup. ODSM (the graphical admin console) can also be used to enable EUS for a new suffix. However, enabling EUS for a new suffix using command line interface is currently not documented, so here is the procedure: Let's assume that EUS support was enabled during initial setup.Let's o=example be the new suffix I want to use to store Enterprise users. The following sequence of command must be applied for each new suffix: // Create a local database holding EUS context infodsconfig create-workflow-element --set base-dn:cn=OracleContext,o=example --set enabled:true --type db-local-backend --element-name exampleContext -n // Add a workflow element in the call path to generate on the fly attributes required by EUSdsconfig create-workflow-element --set enabled:true --type eus-context --element-name eusContext --set next-workflow-element:exampleContext -n // Add the context to a workflow for routingdsconfig create-workflow --set base-dn:cn=OracleContext,o=example --set enabled:true --set workflow-element:eusContext --workflow-name exampleContext_workflow -n //Add the new workflow to the appropriate network groupdsconfig set-network-group-prop --group-name network-group --add workflow:exampleContext_workflow -n // Create the local database for o=exampledsconfig create-workflow-element --set base-dn:o=example --set enabled:true --type db-local-backend --element-name example -n // Create a workflow element in the call path to the user data to generate on the fly attributes expected by EUS dsconfig create-workflow-element --set enabled:true --set eus-realm:o=example --set next-workflow-element:example --type eus --element-name eusWfe// Add the db to a workflow for routingdsconfig create-workflow --set base-dn:o=example --set enabled:true --set workflow-element:eusWfe --workflow-name example_workflow -n //Add the new workflow to the appropriate network groupdsconfig set-network-group-prop --group-name network-group --add workflow:example_workflow -n  // Add the appropriate acis for EUSdsconfig set-access-control-handler-prop \           --add global-aci:'(target="ldap:///o=example")(targetattr="authpassword")(version 3.0; acl "EUS reads authpassword"; allow (read,search,compare) userdn="ldap:///??sub?(&(objectclass=orclservice)(objectclass=orcldbserver))";)' dsconfig set-access-control-handler-prop \       --add global-aci:'(target="ldap:///o=example")(targetattr="orclaccountstatusevent")(version 3.0; acl "EUS writes orclaccountstatusenabled"; allow (write) userdn="ldap:///??sub?(&(objectclass=orclservice)(objectclass=orcldbserver))";)' Last but not least you must adapt the content of the ${OUD}/config/EUS/eusData.ldif  file with your suffix value then inport it into OUD.

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• How to diagnose computer lockups and freezes?

  - by Scott Mitchell

  I built a desktop computer a couple years back with the following specs: CPU: Intel Core 2 Quad Q9300 Yorkfield 2.5GHz 6 MB L2 Cache LGA 775 95W Quad-Core Processor BX80580Q9300 Motherboard: EVGA 122-CK-NF68-T1 LGA 775 NVIDIA nForce 680i SLI ATX Intel Motherboard Video Card: Two EVGA 256-P2-N758-TR GeForce 8600GT SCC 256 MB 128-bit GDDR3 PCI Express x16 SLI Supported Video Card PSU: SeaSonic S12 Energy Plus SS-550HT 550W ATX12V V2.3 / EPS12V V2.91 SLI Certified CrossFire Ready 80 PLUS Certified Active PFC Power Supply Memory: Two G.SKILL 4 GB (2 x 2 GB) 240-Pin DDR2 SDRAM DDR2 800 (PC2 6400) Dual Channel Kit Desktop Memory Model F2-6400CL5D-4GBPQ Since its inception, the machine has periodically locked up, the regularity having varied over the years from once a day to once a month. Typically, lockups happen once every few days. By "lockup" I mean my computer just freezes. The screen locks up, I can't move the mouse. Hitting keys on my keyboard that normally turn LEDs on or off on the keyboard (such as Caps Lock) no longer turn the LEDs on or off. If there was music playing at the time of the lockup, noise keeps coming out of the speakers, but it's just the current frequency/note that plays indefinitely. There is no BSOD. When such a lockup occurs I have to do a hard reboot by either turning off the computer or hitting the reset button. I have the most recent version of the NVIDIA hardware drivers, and update them semi-regularly, but that hasn't seemed to help. I am currently using Windows 7 x64, but was previously using Windows Server 2003 x64 and having the same lockup issues. My guess is that it's somehow video driver or motherboard related, but I don't know how to go about diagnosing this problem to narrow down which of the two is the culprit. Additional information re: cooling Regarding cooling... I've not installed any after-market cooling systems aside from two regular fans I scavenged from an older computer. The fan atop the CPU is the one that shipped with it. One of the two scavenged fans I added it located at the bottom tower of the corner, in an attempt to create some airflow from front to back. The second fan is pointed directly at the two video cards. SpeedFan installation and readings Per studiohack's suggestion, I installed SpeedFan, which provided the following temperature readings: GPU: 63C GPU: 65C System: 76C CPU: 64C AUX: 36C Core 0: 78C Core 1: 76C Core 2: 79C Core 3: 79C Update #3: Another Lockup :-( Well, I had another lockup last night. :-( SpeedFan reported the CPU temp at 38 C when it happened, and there was no spike in temperature leading up to the freeze. One thing I notice is that the freeze seems more likely to happen if I am watching a video. In fact, of the last 5 freezes over the past month, 4 of them have been while watching a video on Flickr. Not necessarily the same video, but a video nevertheless. I don't know if this is just coincidence or if it means anything. (As an aside, each night before bedtime my 2 year old daughter sits on my lap and watches some home videos on Flickr and, in the last month, has learned the phrase, "Uh oh, computer broke.") Update #4: MemTest86 and 3DMark06 Test Results: Per suggestions in the comments, I ran the MemTest86 overnight and it cycled through the 8 GB of memory 5 times without error. I also ran the 3DMark06 test without a problem (see my scores at http://3dmark.com/3dm06/15163549). So... what now? :-) Any further suggestions on what to check? Is there some way to get a stack trace or something when the computer locks like that? Resolution I have never did figure out the particular problems, but based on the suggestions here and elsewhere, I'm presuming it was a motherboard issue. In any event, I recently upgraded my system, buying a new motherbeard, PSU, CPU, and RAM, and that new rig has been working splendidly the past several weeks. I am using the same graphic cards as in the old setup, so I think it's safe to reason that they weren't the cause of the problem.

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• Once installed geos library (C++, and C), and then trying to install rgeos package (R), it reports geos-config missing!

  - by user1873888

  Knowing that the package rgeos, from the R language, requieres a prior installation of geos libraries, I installed, both, libgeos and libgeos-c1 (3.2.2), using the synaptic installer in my Ubuntu 12.04 (32 bit) machine. Then I tried to install rgeos directly from the R console, and it issued a message in the sense that geos-config was not found. The output is as follows: > install.packages("rgeos") Installing package(s) into ‘/home/checo/R/i486-pc-linux-gnu-library/2.15’ (as ‘lib’ is unspecified) also installing the dependency ‘sp’ probando la URL 'http://cran.rstudio.com/src/contrib/sp_1.0-9.tar.gz' Content type 'application/x-gzip' length 882102 bytes (861 Kb) URL abierta ================================================== downloaded 861 Kb probando la URL 'http://cran.rstudio.com/src/contrib/rgeos_0.2-19.tar.gz' Content type 'application/x-gzip' length 221471 bytes (216 Kb) URL abierta ================================================== downloaded 216 Kb * installing *source* package ‘sp’ ... ** package ‘sp’ successfully unpacked and MD5 sums checked ** libs gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG -fpic -O3 -pipe -g -c R centroid.c -o Rcentroid.o gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG -fpic -O3 -pipe -g -c gcdist.c -o gcdist.o gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG -fpic -O3 -pipe -g -c init.c -o init.o gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG -fpic -O3 -pipe -g -c pip.c -o pip.o gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG -fpic -O3 -pipe -g -c pip2.c -o pip2.o gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG -fpic -O3 -pipe -g -c sp_xports.c -o sp_xports.o gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG -fpic -O3 -pipe -g -c surfaceArea.c -o surfaceArea.o gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG -fpic -O3 -pipe -g -c zerodist.c -o zerodist.o gcc -std=gnu99 -shared -o sp.so Rcentroid.o gcdist.o init.o pip.o pip2.o sp_xports.o surfaceArea.o zerodist.o -L/usr/lib/R/lib -lR installing to /home/checo/R/i486-pc-linux-gnu-library/2.15/sp/libs ** R ** data ** demo ** inst ** preparing package for lazy loading ** help *** installing help indices ** building package indices ** installing vignettes ‘intro_sp.Rnw’ ‘over.Rnw’ ** testing if installed package can be loaded * DONE (sp) * installing *source* package ‘rgeos’ ... ** package ‘rgeos’ successfully unpacked and MD5 sums checked configure: CC: gcc -std=gnu99 configure: CXX: g++ configure: rgeos: 0.2-17 checking for /usr/bin/svnversion... no configure: svn revision: 394 checking geos-config usability... ./configure: line 1385: geos-config: command not found no configure: error: geos-config not usable ERROR: configuration failed for package ‘rgeos’ * removing ‘/home/checo/R/i486-pc-linux-gnu-library/2.15/rgeos’ Warning in install.packages : installation of package ‘rgeos’ had non-zero exit status Forgive my ignorance, but I don't know where this file, "geos-config", comes from: should it be generated by the gcc compilations above, or should it be previously installed when the libgeos libraries were intalled? I learnt, from another machine, that "geos-config" is an executable and that it should be installed in /usr/bin. Do you have any idea on what's wrong with my procedure? Thanks, -Sergio.

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• Java - Draw Cards and Eliminate Cards Problem

  - by Jen

  I am having a problem in this question. I want a system inside a game wherein the player draws 2 cards randomly, and the enemy draws 2 cards randomly. Then, what the program does is to print out to the console the cards the player draw and the enemy's. The cards should not conflict and must not be the same. Then lastly, the program prints out the card that was not drawn by both the player and the enemy. Here's how I did it but it was lengthy and full of errors: import java.util.Random; public class Draw { public static Random random = new Random(); public static String cards[] = {"Hall", "Kitchen", "Billiard", "Study", "Pool"}; public static int playercounter; public static int enemycounter; public static String playercardA = null; public static String playercardB = null; public static String enemycardA = null; public static String enemycardB = null; public String lastcard = null; public static void playercardAdraw() { playercounter = random.nextInt(5); playercardA = cards[playercounter]; } public static void playercardBdraw() { playercounter=random.nextInt(5); playercardB= cards[playercounter]; if (playercardB==playercardA || playercardB == enemycardA || playercardB == enemycardB) { return; } } public static void enemycardAdraw () { enemycounter = random.nextInt(5); enemycardA=cards[enemycounter]; if (enemycardA == playercardA || enemycardA == playercardB) { return; } } public static void enemycardBdraw () { enemycounter = random.nextInt(5); enemycardB=cards[enemycounter]; if (enemycardB == playercardA || enemycardB == playercardB || enemycardB == enemycardA) { return; } } public static void main (String args []) { System.out.println("Starting to draw..."); System.out.println("Player's Turn: "); playercardAdraw(); System.out.println("Player's first card: " + playercardA); playercardBdraw(); System.out.println("Player's second card: " + playercardB); System.out.println("Enemy's Turn: "); enemycardAdraw(); System.out.println("Enemy's first card: " + enemycardA); enemycardBdraw(); System.out.println("Enemy's Second card: " + enemycardB); } }

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• Methodology to understanding JQuery plugin & API's developed by third parties

  - by Taoist

  I have a question about third party created JQuery plug ins and API's and the methodology for understanding them. Recently I downloaded the JQuery Masonry/Infinite scroll plug in and I couldn't figure out how to configure it based on the instructions. So I downloaded a fully developed demo, then manually deleted everything that wouldn't break the functionality. The code that was left allowed me to understand the plug in much greater detail than the documentation. I'm now having a similar issue with a plug in called JQuery knob. http://anthonyterrien.com/knob/ If you look at the JQuery Knob readme file it says this is working code: $(function() { $('.dial') .trigger( 'configure', { "min":10, "max":40, "fgColor":"#FF0000", "skin":"tron", "cursor":true } ); }); But as far as I can tell it isn't at all. The read me also says the Plug in uses Canvas. I am wondering if I am suppose to wrap this code in a canvas context or if this functionality is already part of the plug in. I know this kind of "question" might not fit in here but I'm a bit confused on the assumptions around reading these kinds of documentation and thought I would post the query regardless. Curious to see if this is due to my "newbi" programming experience or if this is something seasoned coders also fight with. Thank you. Edit In response to Tyanna's reply. I modified the code and it still doesn't work. I posted it below. I made sure that I checked the Google Console to insure the basics were taken care of, such as not getting a read-error on the library. <!DOCTYPE html> <meta charset="UTF-8"> <title>knob</title> <link rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.2/themes/hot-sneaks/jquery-ui.css" type="text/css" /> <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.js" charset="utf-8"></script> <script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.21/jquery-ui.min.js"></script> <script src="js/jquery.knob.js"></script> <div id="button1">test </div> <script> $(function() { $("#button1").click(function () { $('.dial').trigger( 'configure', { "min":10, "max":40, "fgColor":"#FF0000", "skin":"tron", "cursor":true } ); }); }); </script>

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• VMware vSphere cluster design for site redundancy

  - by Stefan Radovanovici

  I have a question about the best design for site redudancy when using vSphere clusters. A bit of background info about our situation first though. We are a medium-sized company with two main offices, located in different countries. Our networks are linked by a Layer2 150Mbps leased line which is currently underused. We have a variety of services running for internal use within the company, some on physycal servers and some on existing vSphere clusters. In our department we also run several services (almost all running under various forms of Linux) like NTP, Syslog, jump servers, monitoring servers and so on. We have now the requirement that those servers need to be redundant within each location (which they are not at the moment) and also site redudant (which they are to some extent, the servers are duplicated in the 2nd location with configurations kept in sync via various methods at the application layer). There is no SAN available for us, at least not something that we can use at the moment. Cost is also an issue. While we do have some budget available for this, we can't afford to buy SANs for both locations for example. I looked at the VSA feature and it seems that this could be something for us but I am unsure how to solve the site-redudancy requirement. At the moment for testing purposes I am setting up in a lab a vSphere 5 with VSA on two ESXi hosts. I am currently using the Essentials Plus kit with VSA license, which allows me to build a VSA cluster on up to 3 hosts, together with a vCenter license to manage them. The hosts each have two dual-port network cards and two 600GB drives, running in Raid1. Hardware-wise this will be enough for us to run the all the services we need as VMs and will provide redundandcy within the site. At the moment I see only two option to have site redundancy: build an identical VSA cluter in the second location and keep the various services sync'ed at application layer (database sync, rsync and so on). simply move one of the hosts from the existing cluster to the second location, basically having the VSA cluster span the 150Mbps link between the sites. I would very much prefer the second option but I am unsure how well it'll work, if it can work at all. Technically it should, we can span the needed VLANs across the leased line and have them available in the second location. The advantage would be that we don't need to worry at all about sync'ing databases and the like. But I have the feeling that the bandwidth will not be enough, I have no way of knowing how much traffic will the VSA cluster generate between the hosts. I realize that this will most likely depend on the individual usage of the VMs but still, I have no idea how VSA replicates data between the ESXi hosts. Are these my only options or can my goals be achieved in some other way ? Is there perhaps a way to have some sort of "cold stand by" cluster in the second location where the VMs would be sync'ed once per night from the main location ? The idea is that in case the first site becomes unavailable, we would be able to bring all those VMs online there. We would be ok with the data being 1 day old. Any answers are appreciated. Best regards, Stefan

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• Draw Cards and Eliminate Cards Problem

  - by Jen

  I am having a problem in this question. I want a system inside a game wherein the player draws 2 cards randomly, and the enemy draws 2 cards randomly. Then, what the program does is to print out to the console the cards the player draw and the enemy's. The cards should not conflict and must not be the same. Then lastly, the program prints out the card that was not drawn by both the player and the enemy. Here's how I did it but it was lengthy and full of errors: import java.util.Random; public class Draw { public static Random random = new Random(); public static String cards[] = {"Hall", "Kitchen", "Billiard", "Study", "Pool"}; public static int playercounter; public static int enemycounter; public static String playercardA = null; public static String playercardB = null; public static String enemycardA = null; public static String enemycardB = null; public String lastcard = null; public static void playercardAdraw() { playercounter = random.nextInt(5); playercardA = cards[playercounter]; } public static void playercardBdraw() { playercounter=random.nextInt(5); playercardB= cards[playercounter]; if (playercardB==playercardA || playercardB == enemycardA || playercardB == enemycardB) { return; } } public static void enemycardAdraw () { enemycounter = random.nextInt(5); enemycardA=cards[enemycounter]; if (enemycardA == playercardA || enemycardA == playercardB) { return; } } public static void enemycardBdraw () { enemycounter = random.nextInt(5); enemycardB=cards[enemycounter]; if (enemycardB == playercardA || enemycardB == playercardB || enemycardB == enemycardA) { return; } } public static void main (String args []) { System.out.println("Starting to draw..."); System.out.println("Player's Turn: "); playercardAdraw(); System.out.println("Player's first card: " + playercardA); playercardBdraw(); System.out.println("Player's second card: " + playercardB); System.out.println("Enemy's Turn: "); enemycardAdraw(); System.out.println("Enemy's first card: " + enemycardA); enemycardBdraw(); System.out.println("Enemy's Second card: " + enemycardB); } }

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• Java Cloud Service for developers

  - by JuergenKress

  The advent of cloud computing has reinvented application development for many companies. “That’s the beauty of the cloud,” says Cameron Purdy, vice president of development, Oracle. “It dramatically improves developer productivity because they can do what they do best without having to manage complex development, testing, staging, and production environments.” The key is to find a platform that doesn’t impose proprietary restrictions or force developers to learn new tools. For example, Oracle Java Cloud Service is an enterprise-grade platform as a service for building and deploying Java EE, Oracle WebLogic Server, and Oracle Application Development Framework (Oracle ADF) applications. “It’s designed to be flexible and easy to use,” says Purdy. “And it is also a standards-based solution -it’s not proprietary and there is no cloud lock-in. Developers get instant access to an enterprise-grade environment for a simple, monthly subscription.” Oracle Java Cloud Service instances are created with just a few clicks, so businesses can create a rich application development environment within minutes. Running on Oracle WebLogic Server and Oracle Exalogic, the underlying infrastructure also leverages Oracle Fusion Middleware’s integration with common services. For example, instances come integrated and preconfigured with optimized Oracle Database and Oracle Identity Management configurations. Based on Oracle Enterprise Manager, the Oracle Java Cloud Service console lets customers easily manage and monitor their Oracle Java Cloud Service instances. The open nature of the Oracle Java Cloud Service lets developers integrate through Web services such as SOAP and REST APIs, as well as use their favorite developer tools, whether they are out-of-the-box tools such as Maven and Ant or the productivity features built into Oracle JDeveloper, Oracle Enterprise Pack for Eclipse, or NetBeans IDE. The service allows for the seamless movement of applications between on-premise Oracle WebLogic Server domains and instances of Oracle Java Cloud Service within Oracle Cloud. This approach allows flexibility to mix and match the use of on-premise environments with cloud instances for development, test, and production environments. Visit to learn more and watch videos about Oracle Java Cloud Service. WebLogic Partner Community For regular information become a member in the WebLogic Partner Community please visit: http://www.oracle.com/partners/goto/wls-emea ( OPN account required). If you need support with your account please contact the Oracle Partner Business Center. BlogTwitterLinkedInMixForumWiki Technorati Tags: java,cloud,oracle cloud,java cloud,WebLogic Community,Oracle,OPN,Jürgen Kress

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• Data Source Use of Oracle Edition Based Redefinition (EBR)

  - by Steve Felts

  Edition-based redefinition is a new feature in the 11gR2 release of the Oracle database. It enables you to upgrade the database component of an application while it is in use, thereby minimizing or eliminating down time. It works by allowing for a pre-upgrade and post-upgrade view of the data to exist at the same time, providing a hot upgrade capability. You can then specify which view you want for a particular session.  See the Oracle Database Advanced Application Developer's Guide for further information. There is also a good white paper at Edition Based Definition. Using this feature of the Oracle database does not require any new WebLogic Server functionality. It is set for each connection in the pool automatically by simply specifying SQL ALTER SESSION SET EDITION = edition_name in the Init SQL parameter in the data source configuration. This can be configured either via the console or via WLST (setInitSQL on the JDBCConnectionPoolParams). This SQL statement is executed for each newly created physical database connection.Note that we are assuming that a data source references only one edition of the database. To make use of this feature, you would have an earlier version of the application with a data source that references the earlier EDITION and a later version of the application with a data source that references the later EDITION.   Once you start talking about multiple versions of a WLS application, you should be using the WLS "side-by-side" or "versioned" deployment feature.  See Developing Applications for Production Redeployment for more information.  By combining Oracle database EBR and WLS versioned deployment, the application can be failed over with no downtime, making the combination of features more powerful than either independently. There is a catch - you need to be running with a versioned database and a versioned application initially so then you can switch versions.  The recommended way to version a WLS application is to simply add the "Weblogic-Application-Version" property in the MANIFEST.MF file(you can also specify it at deployment time). The recommended way to configure the data source is to use a packaged data source descriptor that's stored in the ear or war so that everything is self-contained.  There are some restrictions.  You can't use a packaged data source with Logging Last Resource (LLR) - you need to use a system resource.  You can't use an application-scoped packaged data source with EmulateTwoPhaseCommit for the global-transactions-protocol with a versioned application - use a global scope.  See Configuring JDBC Application Modules for Deployment for more details. There's one known problem - it doesn't work correctly with an XA data source (patch available with bug 14075837).

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• Why Java's JMF doesn't work in Linux?

  - by Visruth CV

  I got to do some image processing program in java using Linux. I chose to use the JMF for my camera (a webcam) access. But my program is not able to access the camera. But, the jmf works well in Windows. I downloaded jmf from oracle.com and I tried to install it in 'Ubuntu 10.10-the Maverick-released in October 2010 and supported until April 2012'. The downloaded file was a .bin file. I got the below output (last part of the output) when I tried the command provided by oracle /bin/sh ./jmf-2_1_1e-linux-i586.bin. For inquiries please contact: Sun Microsystems, Inc. 4150 Network Circle, Santa Clara, California 95054. LFI# 129621/Form ID#011801 Do you agree to the above license terms? [yes or no] yes Permit recording from an applet? (see readme.html) [yes or no] yes Permit writing local files from an applet? (recommend no, see readme.html) [yes or no] yes Unpacking... tail: cannot open `+309' for reading: No such file or directory Extracting... ./install.sfx.4140: 1: cannot open ==: No such file ./install.sfx.4140: 1: ==: not found ./install.sfx.4140: 3: Syntax error: ")" unexpected chmod: cannot access `JMF-2.1.1e/bin/jmstudio': No such file or directory chmod: cannot access `JMF-2.1.1e/bin/jmfregistry': No such file or directory chmod: cannot access `JMF-2.1.1e/bin/jmfinit': No such file or directory ./jmf-2_1_1e-linux-i586.bin: 305: JMF-2.1.1e/bin/jmfinit: not found /bin/cp: cannot stat `JMF-2.1.1e/lib/jmf.properties': No such file or directory Done. When try the same command again, getting nothing in the terminal (console). visruth@laptop:~/Desktop/mobileapps$ /bin/sh ./jmf-2_1_1e-linux-i586.bin visruth@laptop:~/Desktop/mobileapps$ Now, I'm not sure that whether it is properly installed or not.Whatever, I'm not getting camera access in my programme. I checked out the driver of the camera, it is available in the os itself I think because other softwares are able to access the camera (web cam). I tried it on both desktop and laptop, but no effect... Is there any solution for the problem?

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• Where does a "Technical Programmer" fit in, and what does the title mean? [closed]

  - by Mike E

  Was: "What is a 'Technical Programmer'"? I've noticed in job posting boards a few postings, all from European companies in the games industry, for a "Technical Programmer". The job description was similar, having to do with tools development, 3d graphics programming, etc. It seems to be somewhere between a Technical Artist who's more technical than artist or who can code, and a Technical Director but perhaps without the seniority/experience. Information elsewhere on the position is sparse. The title seems redundant and I haven't seen any American companies post jobs by that name, exactly. One example is this job posting on gamedev.net which isn't exactly thorough. In case the link dies: Subject: Technical Programmer Frictional Games, the creators of Amnesia: The Dark Descent and the Penumbra series, are looking for a talented programmer to join the company! You will be working for a small team with a big focus on finding new and innovating solutions. We want you who are not afraid to explore uncharted territory and constantly learn new things. Self-discipline and independence are also important traits as all work will be done from home. Some the things you will work with include: 3D math, rendering, shaders and everything else related. Console development (most likely Xbox 360). Hardware implementations (support for motion controls, etc). All coding is in C++, so great skills in that is imperative. Revised Summarised Question: So, where does a programmer of this nature fit in to software development team? If I had these on my team, what tasks am I expecting them to complete? Can I ask one to build a new level editor, or optimize the rendering engine? It doesn't seem to be a "tools programmer" which focuses on producing artist tools, often in high-level languages like C#, Python, or Java. Nor does it seem to be working directly on the engine, nor a graphics programmer, as such. Yet, a strong C++ requirement, which was mirrored in other postings besides this one I quoted. Edited To Add As far as it being a low-level programmer, I had considered that but lacking from the posting was a requirement of Assembly. Instead, they tend to require familiarity with higher-level hardware APIs such as DirectX, or DirectInput. I wasn't fully clear in my original post. I think, however, that Mathew Foscarini has it right in his answer, so barring someone who definitely works with or as a "Technical Programmer" stepping in to provide a clearer explanation, I'll go with that. A generalist, which also fits the description of a more-technical-than-artist TA.

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• How to perform Cross Join with Linq

  - by berthin

  Cross join consists to perform a Cartesian product of two sets or sequences. The following example shows a simple Cartesian product of the sets A and B: A (a1, a2) B (b1, b2) => C (a1 b1,            a1 b2,            a2 b1,            a2, b2 ) is the Cartesian product's result. Linq to Sql allows using Cross join operations. Cross join is not equijoin, means that no predicate expression of equality in the Join clause of the query. To define a cross join query, you can use multiple from clauses. Note that there's no explicit operator for the cross join. In the following example, the query must join a sequence of Product with a sequence of Pricing Rules: 1: //Fill the data source 2: var products = new List<Product> 3: { 4: new Product{ProductID="P01",ProductName="Amaryl"}, 5: new Product {ProductID="P02", ProductName="acetaminophen"} 6: }; 7:  8: var pricingRules = new List<PricingRule> 9: { 10: new PricingRule {RuleID="R_1", RuleType="Free goods"}, 11: new PricingRule {RuleID="R_2", RuleType="Discount"}, 12: new PricingRule {RuleID="R_3", RuleType="Discount"} 13: }; 14: 15: //cross join query 16: var crossJoin = from p in products 17: from r in pricingRules 18: select new { ProductID = p.ProductID, RuleID = r.RuleID };   Below the definition of the two entities using in the above example.   1: public class Product 2: { 3: public string ProductID { get; set; } 4: public string ProductName { get; set; } 5: } 1: public class PricingRule 2: { 3: public string RuleID { get; set; } 4: public string RuleType { get; set; } 5: }   Doing this: 1: foreach (var result in crossJoin) 2: { 3: Console.WriteLine("({0} , {1})", result.ProductID, result.RuleID); 4: }   The output should be similar on this:   ( P01   -    R_1 )   ( P01   -    R_2 )   ( P01   -    R_3 )   ( P02   -    R_1 )   ( P02   -    R_2 )   ( P02   -    R_3) Conclusion Cross join operation is useful when performing a Cartesian product of two sequences object. However, it can produce very large result sets that may caused a problem of performance. So use with precautions :)

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• stuck in busybox after update

  - by Lyra500

  I should start out by saying that I am not very tech savvy and have done my best to understand what is going on here from reading other people's posts and have fumbled my way through several attempted fixes without getting anywhere... I run ubuntu 12.04 on an admittedly cheap laptop from ebuyer and in spite of being cheap and not a brand laptop I have never had any major problems with it. Since updating to 12.04 when it was released the boot-up process has always been slow. Logging in takes about 30secs longer than it used to and if I closed my laptop and opened it again instead of being met with a login screen I'd be met with a black screen with a white mouse. As all of these problems had a behavior-changing fix (don't close laptop, patiently wait for login, etc.) I didn't think of reporting any of the issues. Last night when the update manager prompted me that there were updates available I duly did them as I usually do. At the time a bug report came up and I cannot remember what it said but I reported the bug as I was prompted to do. Then this morning when I started up my laptop it went through the usual sequence, GRUB, purple screen with 'ubuntu' etc. and then when it tried to boot up it went into BusyBox and I have not been able to do anything to solve this. I have tried going into the GRUB menu and starting previous versions but I come to the same point - busybox. I have borrowed another rather elderly laptop with Windows Vista to try and download Boot Repair and Ubuntu and burn them onto CD. I tried downloading boot repair five times, to laptop, CD and USB. Every time it would download and burn fine but then the windows laptop would tell me that 1% did not download properly and my laptop would not run the USB or CD upon booting. I then tried to download ubuntu and make a livecd, twice, but again was told that 1% did not download properly and again my laptop will not run ubuntu from the CD upon booting even if/when I went into the f2 menu and changed the menu priority (if that's what you call it) for booting up to make sure it was definitely trying the USB/CD first. This is the message I get from busybox: BusyBox v1.18.5 (Ubuntu 1:1.18.5-1ubuntu4) built-in shell (ash) Enter 'help' for a list of built-in commands I have tried 'exit' but it mentions things about 'kernal panic' and 'tried to quit init!' and 'can't find /root/dev/console : no such file'. I know that the problem is probably caused by a problem with a kernal caused by the update last night, but I couldn't honestly tell you exactly what was updated and without being able to boot from a livecd I'm not sure how to go about fixing this. As I said, I am not tech savvy and have done what I can to try and find a solution to the problem but I'm starting to feel like I'm out of options. Does anyone have any ideas?

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• 12.04 Booting into Terminal

  - by user170796

  To preface this, I would like to say that I am completely new to Ubuntu and have essentially zero programming experience/experience working with command line and terminal. I installed Ubuntu because I would like to get into programming. If you could provide me with the simplest instructions possible, I would be grateful. I have a Lenovo Ideapad Y500 (Intel i7, NVidia GT 750m, 1TB HDD, 16GB SSD cache, 8GB RAM) with Windows 8 on it. Using a Live CD, I installed Ubuntu 12.04 onto a 75 GB partition. During the installation, I kept all default settings except for one thing; I decided to encrypt my home folder, and so checked the corresponding box. The installation completed, and I restarted. Once I restarted, I saw the options "Ubuntu, with Linux 3.2.0-23-generic" "Ubuntu, with Linux 3.2.0-23-generic (recovery mode)" "Memory test (memtest86+)" "Memory test (memtest86+, serial console 115200)" "Windows Recovery Environment (loader) (on /dev/sdb3)" "Windows 8 (loader) (on /dev/sdb5)" "System Setup" I chose the first option, and was directed to a screen with the Ubuntu logo and the row of five dots below that change from orange to white. Then, I was brought to a full screen terminal that prompted me to login, which I did. I saw no option to boot into GUI at all, and am lost. I've been searching around and have tried the "startx" command to no avail. Should the command have some sort of context or something? I've also tried selecting the recovery mode option from the boot manager. I've tried the resume option from the following menu, which eventually just shuts down the computer after displaying a lot of scrolling text that's too fast for me to read. I've also tried the failsafex mode from the recovery mode menu, which only brings up a terminal box at the bottom of the window that covers the entire bottom part of the screen. Commands won't work in this window. When I try to access Windows 8, I get a message saying that the EFI file path was not specified or something along those lines. I had to enable Secure Boot in order to access Windows 8 (I had disabled it to be able to boot from the Live CD), which is functioning normally. I am at a complete loss for what to do. Any help will be extremely appreciated. EDIT: Bonus question! If you could figure out a way for me to boot to Windows 8 without having to enable Secure Boot, it would save me a lot of trouble. I can deal with switching every time, but I'd rather not have to.

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• chkdsk "An unspecified error occurred (696e647863686b2e e19)"

  - by Ex Umbris

  System is Win7x64 Pro on Core i7-920, 12GB I'm experiencing some system flakiness and am trying to pin down the cause. SMART shows zero bad sectors, zero pending reallocations on all drives Memory tests show no problems. Chkdsk fails in various different ways: When run from a normal command line (no /f option) it gets to 63% and then hangs When run on boot (autocheck) it hangs immediately on starting. Actually, the countdown timer (Press any key to skip chkdsk) gets to 1 second and the system hangs. When run from the F8 "Repair System" option (the Win7 "recovery console"), with /f, it runs to about 63% (end of stage 2) and then fails as follows:   Volume label is OS. CHKDSK is verifying files (stage 1 of 3)... 5068288 file records processed. File verification completed. 308 large file records processed. 0 bad file records processed. 2 EA records processed. 77 reparse records processed. CHKDSK is verifying indexes (stage 2 of 3)... 63 percent complete. (6078872 of 7562028 index entries processed) An unspecified error occurred (696e647863686b2e e19). Unable to obtain a handle to the event log. Googling and searching on Technet for the error code and "Unable to obtain a handle to the event log" both turn up nothing useful. Anybody have any info on what the problem is?

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• "shutting down hyper-v virtual machine management service"

  - by icelava

  I have a Windows 2008 R2 server that is a Hyper-V host (Dell PowerEdge T300). Today for the first time I encountered an odd situation; i lost connection with one of the guest machines but logging on physically it seems the guest OS is still running but no longer contactable via the network. I tried to shut down the guest machine (Windows XP) but it would not shut down, getting stuck in a "Not responding" dialog box that cannot be dismissed. I used the Hyper-V management console to reset the machine and it could not get out of resetting state. I tried to save another Windows 2003 guest machine, and it would be progress with its Saving state (0%). The other running Windows 2003 guest was stuck in the logon dialog. My first suspicion is perhaps one of the Windows update patches this week (10 Nov 2011) may something to do with it, which was still pending a system restart. Well, since I could not do anything with Hyper-V i proceeded with the Windows Update restart, and now it is stuck half an hour at "Shutting down hyper-v virtual machine management service" Prior to restarting I did not observe any hard disk errors reported in the system event log; doubt it is a disk-related condition. Shall I force a hard reboot? UPDATE As per answer report, it eventually restarted itself.

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• vsftpd 500 OOPS: priv_sock_get_int

  - by user1613878

  I have a problem with vsftpd that replies "500 OOPS: priv_sock_get_int" when i do command "ls". following is a snip of ftp client console running on osx. And I'm using test account that has home directory on the ftp server, not virtual account. Connected to 192.0.0.20. 220 satellite Name (192.0.0.20:john): test_account 331 Please specify the password. Password: 230 Login successful. Remote system type is UNIX. Using binary mode to transfer files. ftp> ls 500 OOPS: priv_sock_get_int 421 Service not available, remote server has closed connection. and my vsftpd.conf local_enable=YES write_enable=YES #local_umask=022 local_umask=002 #anon_upload_enable=YES #anon_mkdir_write_enable=YES #dirmessage_enable=YES #xferlog_enable=YES connect_from_port_20=YES #chown_uploads=YES #chown_username=whoever #xferlog_file=/var/log/vsftpd.log #xferlog_std_format=YES #idle_session_timeout=600 #data_connection_timeout=120 #nopriv_user=test #async_abor_enable=YES #ascii_upload_enable=YES #ascii_download_enable=YES ftpd_banner=welcome #deny_email_enable=YES #banned_email_file=/etc/vsftpd.banned_emails #chroot_local_user=YES #chroot_list_enable=YES #chroot_list_file=/etc/vsftpd.chroot_list #ls_recurse_enable=YES listen=YES #listen_ipv6=YES #ssl_enable=NO pasv_enable=YES pasv_max_port=12500 pasv_min_port=12000 port_enable=YES pasv_address=192.0.0.20 pasv_promiscuous=YES port_promiscuous=YES file_open_mode=0666

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