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  • Java: using endpoint to publish webservice to tomcat server

    - by Will
    hi all, i am creating a simple SOAP web service. i am to ensure that it runs on a tomcat web service. im trying to implement this with JAX-WS (see code) my question is: does the Endpoint.publish use the tomcat server to host this or is it a mini glassfish kind of server? should i be extending UnicastRemoveObject or something similiar instead? ideally it would be able to be packaged into a .WAR and dropped in the directory and just work. It doesn't seem to work with my installed tomcat server as is because it says the port is already in use. I'm using Ubuntu karmic with the tomcat6 package installed, it could also be my user doesnt have permissions to publish to the running tomcat on 8080 i hope this question is clear enough sample code: @WebService public class UserAttributes { public static void main(String[] args) { UserAttributes instance = new UserAttributes(); Endpoint.publish("http://localhost:8082/WebServices/userattributes", instance); } public string Hello() { return "Hello World"; } }

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  • [Java] Cannot find symbol

    - by m00st
    I've created a class called Entity this is the superclass. Actor has successfully extended Entity; now trying to do the same with Item results in the Cannot find symbol error. Here is example code: public class Actor extends Entity { Actor(String filename, int x, int y) { super(filename, x, y); } } works just fine but this doesn't: public class Item extends Entity { }

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  • Java: why can't iterate over an iterator?

    - by noamtm
    I read http://stackoverflow.com/questions/839178/why-is-javas-iterator-not-an-iterable and http://stackoverflow.com/questions/27240/why-arent-enumerations-iterable, but I still don't understand why this: void foo(Iterator<X> it) { for (X x : it) { bar(x); baz(x); } } was not made possible. In other words, unless I'm missing something, the above could have been nice and valid syntactic sugar for: void foo(Iterator<X> it) { for (X x; it.hasNext();) { x = it.next(); bar(x); baz(x); } }

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  • Parsing JSON to XML using net.sf.json (java)

    - by Castanho
    Hi guys, I'm parsing a generic JSON to a XML using net.sf.json. (I'm not using POJO Obj in the conversion) When dealing with vectors I'm receiving: <root> <entry> <Id>1</accountId> <Items> <e> <cost>0.1</cost> <debit>0.1</debit> </e> <e> <cost>0.1</cost> <debit>0.1</debit> </e> </Items> </entry> </root> When the correct for my point of view should be: <root> <entry> <accountId>1</accountId> <Items> <cost>0.1</cost> <debit>0.1</debit> </Items> <Items> <cost>0.2</cost> <debit>0.2</debit> </Items> </entry> </root> Do anyone have used this lib and could help me? Any tips could help! Thanks in advance

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  • Simple java syncrhonization question

    - by Misha Koshelev
    Dear All: Was wondering, which is correct: Option One class A { public void methodOne() { synchronized(this) { modifyvalue notifyAll() } } public void methodTwo() { while (valuenotmodified) { synchronized(this) { wait() } } } Option Two class A { public void methodOne() { modifyvalue synchronized(this) { notifyAll() } } public void methodTwo() { while (valuenotmodified) { synchronized(this) { wait() } } } and why? Thank you Misha

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  • How to make prevent public key inside jar to be saved using Java code

    - by Abhijith V R
    After signing a jar , we can retrieve the public keys from jar using Certificate[] cert = jarentry.getCertificates(); Once certificate is extracted we can save this to a new keystore as trusted cert. Once this is done , then second user can sign any jar using this certificate , isn't ? I want to distribute content as jars , contents will contain properties files for a application init. I want to make sure that an user is not capable to rebuilding the property files using the certificate he extracted from jarentry. In the code which reads the jar contents i am checking that jar is signed with my certificate only and also checking that jar is not tampered with . But the issue came to my mind that if i am able to extract the cerificate from jar then why don;t a third guy ? Can any one help me in this............

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  • how to create a JSON object in action class of JAVA

    - by Jugal
    I want to create a JSON object. I have tried the following myString=new JSONObject().put("JSON", sampleClass).toString(); but mystring gives me {"SampleClass@170f98"}. I also tried the following XStream xsStream=new XStream(new JsonHierarchicalStreamDriver()); SampleClass sampleClass=new SampleClass(userset.getId(),userset.getUsername()); myString=xsStream.toXML(sampleClass); It works but when i use getJSON in javascript to get myString it does not work.

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  • Use Java Annotation not to run a method

    - by Michael Mao
    Hi all: I've got a method in my class only for testing purpose : private void printOut(String msg, Object value) { System.out.println(msg + value); } It is a wrapper method for System.out.println(); So I hope, with the use of Annotation, I can choose not to run this method during productive environment while still keep those diagnostic output ready if I am to switch back to debugging environment. Which Annotation shall I put on top of the method name?

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  • How to resize .jpg images in Java?

    - by Daeyun
    This is what I want to do: Input: ArrayList that contains a bunch of .jpg URLs Download the image (using HttpURLConnection maybe?) Resize Save as xxx.jpg, locally I don't know where to start. I'd appreciate if anyone can tell me what to study to do the steps 1~3.

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  • Returning searched results in an array in Java without ArrayList

    - by Crystal
    I started down this path of implementing a simple search in an array for a hw assignment without knowing we could use ArrayList. I realized it had some bugs in it and figured I'd still try to know what my bug is before using ArrayList. I basically have a class where I can add, remove, or search from an array. public class AcmeLoanManager { public void addLoan(Loan h) { int loanId = h.getLoanId(); loanArray[loanId - 1] = h; } public Loan[] getAllLoans() { return loanArray; } public Loan[] findLoans(Person p) { //Loan[] searchedLoanArray = new Loan[10]; // create new array to hold searched values searchedLoanArray = this.getAllLoans(); // fill new array with all values // Looks through only valid array values, and if Person p does not match using Person.equals() // sets that value to null. for (int i = 0; i < searchedLoanArray.length; i++) { if (searchedLoanArray[i] != null) { if (!(searchedLoanArray[i].getClient().equals(p))) { searchedLoanArray[i] = null; } } } return searchedLoanArray; } public void removeLoan(int loanId) { loanArray[loanId - 1] = null; } private Loan[] loanArray = new Loan[10]; private Loan[] searchedLoanArray = new Loan[10]; // separate array to hold values returned from search } When testing this, I thought it worked, but I think I am overwriting my member variable after I do a search. I initially thought that I could create a new Loan[] in the method and return that, but that didn't seem to work. Then I thought I could have two arrays. One that would not change, and the other just for the searched values. But I think I am not understanding something, like shallow vs deep copying???....

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  • remove duplicate code in java

    - by Anantha Kumaran
    class A extends ApiClass { public void duplicateMethod() { } } class B extends AnotherApiClass { public void duplicateMethod() { } } I have two classes which extend different api classes. The two class has some duplicate methods(same method repeated in both class) and how to remove this duplication? Edit The ApiClass is not under my control

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  • Finding the actual runtime call tree of a Java Program

    - by Chathuranga Chandrasekara
    Suppose I have a big program that consists of hundreds of methods in it. And according to the nature of input the program flow is getting changed. Think I want to make a change to the original flow. And it is big hassle to find call hierarchy/ references and understand the flow. Do I have any solution for this within Eclipse? Or a plugin? As an example, I just need a Log of method names that is in order of time. Then I don't need to worry about the methods that are not relevant with my "given input" Update : Using debug mode in eclipse or adding print messages are not feasible. The program is sooooo big. :)

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  • java looping - declaration of a Class outside / inside the loop

    - by lisak
    when looping, for instance: for ( int j = 0; j < 1000; j++) {}; and I need to instantiate 1000 objects, how does it differ when I declare the object inside the loop from declaring it outside the loop ?? for ( int j = 0; j < 1000; j++) {Object obj; obj =} vs Object obj; for ( int j = 0; j < 1000; j++) {obj =} It's obvious that the object is accessible either only from the loop scope or from the scope that is surrounding it. But I don't understand the performance question, garbage collection etc. What is the best practice ? Thank you

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  • How to repaint a XYPlot from JFreeChart? (JAVA)

    - by mccrank
    Hi, I'm doing a GUI that has a XYPlot (from the JFreeChart package) and when I click a button I'm trying to add some values. I add them correctly to the XYSeries that are inside the XYPlot, but the GUI doesn't change. It only changes when y maximize or minimize. Is there some kind of repaint to do this? I have been looking for it and I have found nothing.

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  • Reducing Time Complexity in Java

    - by Koeneuze
    Right, this is from an older exam which i'm using to prepare my own exam in january. We are given the following method: public static void Oorspronkelijk() { String bs = "Dit is een boodschap aan de wereld"; int max = -1; char let = '*'; for (int i=0;i<bs.length();i++) { int tel = 1; for (int j=i+1;j<bs.length();j++) { if (bs.charAt(j) == bs.charAt(i)) tel++; } if (tel > max) { max = tel; let = bs.charAt(i); } } System.out.println(max + " keer " + let); } The questions are: what is the output? - Since the code is just an algorithm to determine the most occuring character, the output is "6 keer " (6 times space) What is the time complexity of this code? Fairly sure it's O(n²), unless someone thinks otherwise? Can you reduce the time complexity, and if so, how? Well, you can. I've received some help already and managed to get the following code: public static void Nieuw() { String bs = "Dit is een boodschap aan de wereld"; HashMap<Character, Integer> letters = new HashMap<Character, Integer>(); char max = bs.charAt(0); for (int i=0;i<bs.length();i++) { char let = bs.charAt(i); if(!letters.containsKey(let)) { letters.put(let,0); } int tel = letters.get(let)+1; letters.put(let,tel); if(letters.get(max)<tel) { max = let; } } System.out.println(letters.get(max) + " keer " + max); } However, I'm uncertain of the time complexity of this new code: Is it O(n) because you only use one for-loop, or does the fact we require the use of the HashMap's get methods make it O(n log n) ? And if someone knows an even better way of reducing the time complexity, please do tell! :)

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  • XML validation in Java - why does this fail?

    - by jd
    hi, first time dealing with xml, so please be patient. the code below is probably evil in a million ways (I'd be very happy to hear about all of them), but the main problem is of course that it doesn't work :-) public class Test { private static final String JSDL_SCHEMA_URL = "http://schemas.ggf.org/jsdl/2005/11/jsdl"; private static final String JSDL_POSIX_APPLICATION_SCHEMA_URL = "http://schemas.ggf.org/jsdl/2005/11/jsdl-posix"; public static void main(String[] args) { System.out.println(Test.createJSDLDescription("/bin/echo", "hello world")); } private static String createJSDLDescription(String execName, String args) { Document jsdlJobDefinitionDocument = getJSDLJobDefinitionDocument(); String xmlString = null; // create the elements Element jobDescription = jsdlJobDefinitionDocument.createElement("JobDescription"); Element application = jsdlJobDefinitionDocument.createElement("Application"); Element posixApplication = jsdlJobDefinitionDocument.createElementNS(JSDL_POSIX_APPLICATION_SCHEMA_URL, "POSIXApplication"); Element executable = jsdlJobDefinitionDocument.createElement("Executable"); executable.setTextContent(execName); Element argument = jsdlJobDefinitionDocument.createElement("Argument"); argument.setTextContent(args); //join them into a tree posixApplication.appendChild(executable); posixApplication.appendChild(argument); application.appendChild(posixApplication); jobDescription.appendChild(application); jsdlJobDefinitionDocument.getDocumentElement().appendChild(jobDescription); DOMSource source = new DOMSource(jsdlJobDefinitionDocument); validateXML(source); try { Transformer transformer = TransformerFactory.newInstance().newTransformer(); transformer.setOutputProperty(OutputKeys.INDENT, "yes"); StreamResult result = new StreamResult(new StringWriter()); transformer.transform(source, result); xmlString = result.getWriter().toString(); } catch (Exception e) { e.printStackTrace(); } return xmlString; } private static Document getJSDLJobDefinitionDocument() { DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = null; try { builder = factory.newDocumentBuilder(); } catch (Exception e) { e.printStackTrace(); } DOMImplementation domImpl = builder.getDOMImplementation(); Document theDocument = domImpl.createDocument(JSDL_SCHEMA_URL, "JobDefinition", null); return theDocument; } private static void validateXML(DOMSource source) { try { URL schemaFile = new URL(JSDL_SCHEMA_URL); Sche maFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI); Schema schema = schemaFactory.newSchema(schemaFile); Validator validator = schema.newValidator(); DOMResult result = new DOMResult(); validator.validate(source, result); System.out.println("is valid"); } catch (Exception e) { e.printStackTrace(); } } } it spits out a somewhat odd message: org.xml.sax.SAXParseException: cvc-complex-type.2.4.a: Invalid content was found starting with element 'JobDescription'. One of '{"http://schemas.ggf.org/jsdl/2005/11/jsdl":JobDescription}' is expected. Where am I going wrong here? Thanks a lot

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  • Java appending XML data

    - by Travis
    I've already read through a few of the answers on this site but none of them worked for me. I have an XML file like this: <root> <character> <name>Volstvok</name> <charID>(omitted)</charID> <userID>(omitted)</userID> <apiKey>(omitted)</apiKey> </character> </root> I need to add another <character> somehow. I'm trying this but it does not work: public void addCharacter(String name, int id, int userID, String apiKey){ Element newCharacter = doc.createElement("character"); Element newName = doc.createElement("name"); newName.setTextContent(name); Element newID = doc.createElement("charID"); newID.setTextContent(Integer.toString(id)); Element newUserID = doc.createElement("userID"); newUserID.setTextContent(Integer.toString(userID)); Element newApiKey = doc.createElement("apiKey"); newApiKey.setTextContent(apiKey); //Setup and write newCharacter.appendChild(newName); newCharacter.appendChild(newID); newCharacter.appendChild(newUserID); newCharacter.appendChild(newApiKey); doc.getDocumentElement().appendChild(newCharacter); }

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