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  • Can't edit a specific document in Word 2007

    - by Benjotron
    I have a document in Word 2007 that seems to be read only. There are forms in the document that I can type in, but I can't edit or reformat the rest of the document. There is probably a setting somewhere I can flip to make it editable again but I can't find it for the life of me. FOLLOW UP: The "Protect Document" button only had "Unrestricted Access" checked, this was one of the first things I checked. However, when I tried checking "Restrict Formatting and Editing" it brought up the Restrict Formatting and Editing sidebar, which stated: This document is protected from unintentional editing. You may only fill in forms in this region. With a stop protection button on the bottom, which of course solved the problem. I think that menu item just has a bad name, it should be "Restrict Formatting and Editing Options or Settings"

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  • Code in FOR loop not executed

    - by androniennn
    I have a ProgressDialog that retrieves in background data from database by executing php script. I'm using gson Google library. php script is working well when executed from browser: {"surveys":[{"id_survey":"1","question_survey":"Are you happy with the actual government?","answer_yes":"50","answer_no":"20"}],"success":1} However, ProgressDialog background treatment is not working well: @Override protected Void doInBackground(Void... params) { String url = "http://192.168.1.4/tn_surveys/get_all_surveys.php"; HttpGet getRequest = new HttpGet(url); Log.d("GETREQUEST",getRequest.toString()); try { DefaultHttpClient httpClient = new DefaultHttpClient(); Log.d("URL1",url); HttpResponse getResponse = httpClient.execute(getRequest); Log.d("GETRESPONSE",getResponse.toString()); final int statusCode = getResponse.getStatusLine().getStatusCode(); Log.d("STATUSCODE",Integer.toString(statusCode)); Log.d("HTTPSTATUSOK",Integer.toString(HttpStatus.SC_OK)); if (statusCode != HttpStatus.SC_OK) { Log.w(getClass().getSimpleName(), "Error " + statusCode + " for URL " + url); return null; } HttpEntity getResponseEntity = getResponse.getEntity(); Log.d("RESPONSEENTITY",getResponseEntity.toString()); InputStream httpResponseStream = getResponseEntity.getContent(); Log.d("HTTPRESPONSESTREAM",httpResponseStream.toString()); Reader inputStreamReader = new InputStreamReader(httpResponseStream); Gson gson = new Gson(); this.response = gson.fromJson(inputStreamReader, Response.class); } catch (IOException e) { getRequest.abort(); Log.w(getClass().getSimpleName(), "Error for URL " + url, e); } return null; } @Override protected void onPostExecute(Void result) { super.onPostExecute(result); Log.d("HELLO","HELLO"); StringBuilder builder = new StringBuilder(); Log.d("STRINGBUILDER","STRINGBUILDER"); for (Survey survey : this.response.data) { String x= survey.getQuestion_survey(); Log.d("QUESTION",x); builder.append(String.format("<br>ID Survey: <b>%s</b><br> <br>Question: <b>%s</b><br> <br>Answer YES: <b>%s</b><br> <br>Answer NO: <b>%s</b><br><br><br>", survey.getId_survey(), survey.getQuestion_survey(),survey.getAnswer_yes(),survey.getAnswer_no())); } Log.d("OUT FOR","OUT"); capitalTextView.setText(Html.fromHtml(builder.toString())); progressDialog.cancel(); } HELLO Log is displayed. STRINGBUILDER Log is displayed. QUESTION Log is NOT displayed. OUT FOR Log is displayed. Survey Class: public class Survey { int id_survey; String question_survey; int answer_yes; int answer_no; public Survey() { this.id_survey = 0; this.question_survey = ""; this.answer_yes=0; this.answer_no=0; } public int getId_survey() { return id_survey; } public String getQuestion_survey() { return question_survey; } public int getAnswer_yes() { return answer_yes; } public int getAnswer_no() { return answer_no; } } Response Class: public class Response { ArrayList<Survey> data; public Response() { data = new ArrayList<Survey>(); } } Any help please concerning WHY the FOR loop is not executed. Thank you for helping.

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  • using ruby-debug with jruby-1.5.0

    - by brad
    Release notes say that ruby-debug is installed by default. I'm using rvm. In my rails app I figured something as simple as script/server --debugger would suffice, but it complains that the ruby-debug gem isn't installed, suggests using gem install ruby-debug, which of course doesn't work (building native extensions) and is contrary to the docs anyway. Just wondering if anyone's had any luck using the built in ruby-debug in jruby 1.5 and what one needs to do in order run jruby in debug mode

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  • Problem while adding new Object to CoreData App

    - by elementsense
    Hi Another Day, another CoreData problem,...but hopefully the last one now. Ok here is a copy of what I have : I have a List of Hotel Guests that stay in one Room and have Preferences. Once ready the user should select a guest and see the data and should also be able to add new guest, select the room (maintained also by application) and select their preferences (where the user can also add new preferences). The guest can have no or many preferences. So here is what I have so far. I created 3 Entities : - Rooms with roomnumber - Preferences with name - GuestInfo with name - with these Relationships room (Destination Rooms) and prefs (Destination Preferences with "To-Many Relationship") The prefs is a NSSet when you create a Managed Object Class. Now I created a UITableViewController to display all the data. I also have an edit and add mode. When I add a new Guest and just fill out the name, everything works fine. But when I want to add the prefs or the room number I get this error : Illegal attempt to establish a relationship 'room' between objects in different contexts Now, what confuses me is that when I add a guest and enter just the name, save it, go back and edit it and select the prefs and room number it works ? I have this line in both ViewControllers to select the room or prefs : [editedObject setValue:selectedRoom forKey:editedFieldKey]; with this .h : NSManagedObject *editedObject; NSString *editedFieldKey; NSString *editedFieldName; Again, it works on the editing mode but not when I want to add a fresh object. And to be sure, this is what I do for adding an new Guest : - (IBAction)addNewItem { AddViewController *addViewController = [[AddViewController alloc] initWithStyle:UITableViewStyleGrouped]; addViewController.delegate = self; addViewController.context = _context; // Create a new managed object context for the new book -- set its persistent store coordinator to the same as that from the fetched results controller's context. NSManagedObjectContext *addingContext = [[NSManagedObjectContext alloc] init]; self.addingManagedObjectContext = addingContext; [addingContext release]; [addingManagedObjectContext setPersistentStoreCoordinator:[[_fetchedResultsController managedObjectContext] persistentStoreCoordinator]]; GuestInfo *info = (GuestInfo *)[NSEntityDescription insertNewObjectForEntityForName:@"GuestInfo" inManagedObjectContext:addingContext]; addViewController.info = info; UINavigationController *navController = [[UINavigationController alloc] initWithRootViewController:addViewController]; [self.navigationController presentModalViewController:navController animated:YES]; [addViewController release]; [navController release]; } Anything I have to do to initialize the Room or Prefs ? Hope someone can help me out. Thanks

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  • Is it possible to have all "git diff" commands use the "Python diff", in all git projects?

    - by EOL
    When including the line *.py diff=python in a local .gitattributes file, git diff produces nice labels for the different diff hunks of Python files (with the name of the function where the lines changed take place, etc.). Is is possible to ask git to use this diff mode for all Python files across all git projects? I tried to set a global ~/.gitattributes, but it is not used by local git repositories. Is there a more convenient method than initializing each new git project with a ln -s ~/.gitattributes?

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  • VS2008 loading designermode takes forever

    - by Younes
    Is there anything that can be done about the Designer mode for a ascx file taking forever to show? I'm currently waiting for like 1 minute and still nothing happened. This is not the first time i see this problem, the ascx file doesn't even have any components to show yet... The web user control is like empty and still it won't load. What can be the problem here?

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  • How to Disable F11 key

    - by Subhen
    Hi, I want to disable the F11 key in my silverlight application , because I dont want user to sqwitch to full screen mode. Or if is there a way I can write my code for f11 key event , I tried with key down event , but not working for f10 and f11 and set of other keys . Thanks, Subhen

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  • ValidationProperty not returning entered value for textbox in custom ontrol

    - by nat
    hi I have a custom control, (relevant code at the bottom) it consists of some text/links and a hidden textbox (rather than a hidden input). when rendered, the user via another dialog and some JS sets the value of the textbox to an integer and clicks submit on the form. i am trying to assure that the user has entered a number (via the JS) and that the textbox is not still set to its default of "0" the requiredfieldvalidator works just fine, if i dont change the value it spots it on the client and fills the validation summary on the page with the appropriate message. unfortunately when i do fill the textbox, the validator also rejests the post as the controls textbox text value is still set to "0", even though on the form it has changed. clearly i am doing something wrong.. but cant work out what it is? could someone enlighten me please, this is driving me potty if i step through the code, when the get of the mediaidtext is hit,the findcontrol finds does not the textbox, if i inspect the controls collection however i can find the textbox, but its value is still "0" it also seems that when findcontrol is called, the createchildcontrols is called again - thus resetting the value back to "0" there.. ! how can i ever assure the control realises that the textbox value has changed? many thanks code below nat [ValidationProperty("MediaIdText")] public class MediaLibraryFileControl: CompositeControl { private int mediaId = 0; public int MediaId { get { return mediaId; } set { mediaId = value; } } public string MediaIdText { get { string txt = "0"; Control ctrl = this.FindControl(this.UniqueID+ "_hidden"); try { txt = ((TextBox)ctrl).Text; MediaId = Convert.ToInt32(txt); } catch { MediaId = 0; } return txt; } } protected override void CreateChildControls() { this.Controls.Add(new LiteralControl("<span>")); this.Controls.Add(new LiteralControl("<span id=\"" + TextControlName + "\">" + getMediaDetails() + "</span>")); TextBox tb = new TextBox(); tb.Text = this.MediaId.ToString(); tb.ID = this.UniqueID + "_hidden"; tb.CssClass = "hidden"; this.Controls.Add(tb); if (Select == true) { this.Controls.Add(new LiteralControl(string.Format("&nbsp;[<a href=\"javascript:{0}(this,'{1}','{2}')\" class=\"select\">{3}</a>]", dialog, this.UniqueID, this.categoryId, "select"))); this.Controls.Add(new LiteralControl(string.Format("&nbsp;[<a href=\"javascript:{0}(this,'{1}')\" class=\"select\">{2}</a>]", clearDialog, this.ID, "clear"))); } this.Controls.Add(new LiteralControl("</span>")); } protected virtual string getMediaDetails() { //... return String.Empty; } } this is the code adding the validationcontrol the editcontrol is the instance of the control above public override Control RenderValidationControl(Control editControl) { Control ctrl = new PlaceHolder(); RequiredFieldValidator req = new RequiredFieldValidator(); req.ID = editControl.ClientID + "_validator"; req.ControlToValidate = editControl.ID; req.Display = ValidatorDisplay.None; req.InitialValue = "0"; req.EnableClientScript = false; req.ErrorMessage = "control cannot be blank"; ctrl.Controls.Add(req); return ctrl; }

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  • Ubuntu 9.04 Cannot Connect to visible open wifi ap (reason 6)

    - by Andrew Bolster
    I'm travelling currently so the last network i connected successfully to was my home wpa-psk network. I hadn't tried anything until i got to my accommodation that is an open network (that I'm on now on the Win7 partition on my laptop). The network (and a similar archetypical 'linksys' open network, aswell as some protected local networks are correctly displayed in network-manager and upon selection, it happily spins around to its hearts content for a while before saying 'no chance boy'. /var/log/syslog spills out the usual combination of wpa_supplicant and kernel messages, the most interesting of are that the kernel deauthentication reason 6 response. 6 apparently means class2FrameFromNonAuthStation...Client attempted to transfer data before it was authenticated. Anyone seen anything like this? I've already tried going closer to the router to no avail. I don't remember seeing this any other time I've connected to a open AP, even if that AP is far away. (Signal strength for this AP is good, kismet says its around -57dBm, well above the threshold of -80dBm, and I've tried all the suggestions from the 'Related Questions'

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  • Do I really need twho different Exchange servers 2007|2010?

    - by lrosa
    Given am Exchange Server 2003 running on a dedicated server on a LAN protected by a Linux in DMZ, Microsoft says that if you upgrade, you should install two different servers (meaning two boxes, two licenses of Windows Server and two installations of Exchange) with different Exchange "server role". Exchange is installed in a safe LAN, there is a Linux relay in DMZ that feeds messages to Exchanges and gets from it the messaged to be delivered on the Net (smart relay). The mail traffic is about 2000 Internet messages/day and probably another 2000 msg/day sent by local users within the organization. The servers hosts 200 users.

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  • How to detect when a user copies files from a server over the network?

    - by Mr. Graves
    I have a few virtual servers + desktops that are used for shared development with remote users, including some consultants. Each user has an account with access to most aspects of the server. I don't want to prevent people from being productive, or track passwords or read emails, but I do want to know when and what files they copy from the virtual server or what they upload from the server to a remote site, and what if any applications they install. This will help make sure my IP is protected, that no one is installing tools they shouldn't, and that things are licensed appropriately. What is the simplest way to do this? In order of importance I would say detecting file transfers off the machine to be most critical. Thanks

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  • link button property to open in new tab?

    - by Surya sasidhar
    hi, in my application i have some link buttons there but when i right click on them i not(they are in disable mode) found property open in new tab or open in new window, what is that property can u help me. thank you <asp:LinkButton id="lbnkVidTtile1" runat="Server" CssClass="bodytext" Text='<%# Eval("newvideotitle") %>' ></LinkButton>

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  • How to get all usages/references of control in DotNetNuke?

    - by macias
    Sorry for lame question but I am literally starting with DNN. When you are in admin/design mode you can list all modules used, and when you click on module at the end you will see the list of controls used in this module with info about filename of the source. The problem I have is in reverse -- I already know the filename with source, I would like to list all modules which use this control. How to do it?

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  • Why can't I shrink a transaction log file, even after backup?

    - by Jordan Hudson
    I have a database that has a 28gig transaction log file. Recovery mode is simple. I just took a full backup of the database, and then ran both: backup log dbmcms with truncate_only DBCC SHRINKFILE ('Wxlog0', TRUNCATEONLY) The name of the db is db_mcms and the name of the transaction log file is Wxlog0. Neither has helped. I'm not sure what to do next.

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  • Security of BitLocker with no PIN from WinPE?

    - by Scott Bussinger
    Say you have a computer with the system drive encrypted by BitLocker and you're not using a PIN so the computer will boot up unattended. What happens if an attacker boots the system up into the Windows Preinstallation Environment? Will they have access to the encrypted drive? Does it change if you have a TPM vs. using only a USB startup key? What I'm trying to determine is whether the TPM / USB startup key is usable without booting from the original operating system. In other words, if you're using a USB startup key and the machine is rebooted normally then the data would still be protected unless an attacker was able to log in. But what if the hacker just boots the server into a Windows Preinstallation Environment with the USB startup key plugged in? Would they then have access to the data? Or would that require the recovery key? Ideally the recovery key would be required when booted like this, but I haven't seen this documented anywhere.

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  • Accessing the Internet via browser

    - by ucas
    I am on Windows 7 and using Firefox browser. I am using WiFi, but since the morning I cannot access the Internet via the browsers (Firefox, Chrome, or IE). The laptop shows there is Internet connection, Skype is online, but I can't reach the Internet. Then I launched Tor application which creates secure channel and provides its Firefox browser. Well, I can now access the Internet over that browser. So, what might be the problem causing this malfunction? The error: The connection has timed out The server at mail.google.com is taking too long to respond. The site could be temporarily unavailable or too busy. Try again in a few moments. If you are unable to load any pages, check your computer's network connection. If your computer or network is protected by a firewall or proxy, make sure that Firefox is permitted to access the Web. Best regards

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  • what is wrong with connection string

    - by Hakan
    Can any one help me with this connection string. I can't manage how to fix. Dim constring As String Dim con As SqlCeConnection Dim cmd As SqlCeCommand constring = "(System.IO.Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase) + \\database.sdf;Password=pswrd;File Mode=shared read" con = New SqlCeConnection() con.Open() Thanks

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  • Unable to add item to dataset in Linq to SQL

    - by Mike B
    I am having an issue adding an item to my dataset in Linq to SQL. I am using the exact same method in other tables with no problem. I suspect I know the problem but cannot find an answer (I also suspect all i really need is the right search term for Google). Please keep in mind this is a learning project (Although it is in use in a business) I have posted my code and datacontext below. What I am doing is: Create a view model (Relevant bits are shown) and a simple wpf window that allows editing of 3 properties that are bound to the category object. Category is from the datacontext. Edit works fine but add does not. If I check GetChangeSet() just before the db.submitChanges() call there are no adds, edits or deletes. I suspect an issue with the fact that a Category added without a Subcategory would be an orphan but I cannot seem to find the solution. Command code to open window: CategoryViewModel vm = new CategoryViewModel(); AddEditCategoryWindow window = new AddEditCategoryWindow(vm); window.ShowDialog(); ViewModel relevant stuff: public class CategoryViewModel : ViewModelBase { public Category category { get; set; } // Constructor used to Edit a Category public CategoryViewModel(Int16 categoryID) { db = new OITaskManagerDataContext(); category = QueryCategory(categoryID); } // Constructor used to Add a Category public CategoryViewModel() { db = new OITaskManagerDataContext(); category = new Category(); } } The code for saving changes: // Don't close window unless all controls are validated if (!vm.IsValid(this)) return; var changes = vm.db.GetChangeSet(); // DEBUG try { vm.db.SubmitChanges(ConflictMode.ContinueOnConflict); } catch (ChangeConflictException) { vm.db.ChangeConflicts.ResolveAll(RefreshMode.KeepChanges); vm.db.SubmitChanges(); } The Xaml (Edited fror brevity): <TextBox Text="{Binding category.CatName, Mode=TwoWay, ValidatesOnDataErrors=True, UpdateSourceTrigger=PropertyChanged}" /> <TextBox Text="{Binding category.CatDescription, ValidatesOnDataErrors=True, UpdateSourceTrigger=PropertyChanged}" /> <CheckBox IsChecked="{Binding category.CatIsInactive, Mode=TwoWay}" /> IssCategory in the Issues table is the old, text based category. This field is no longer used and will be removed from the database as soon as this is working and pushed live.

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  • Load Pymacs & Ropemacs only when opening a Python file ?

    - by Mtgred
    I use Pymacs to load Ropemacs and Rope with the following lines in my .emacs as described here. (autoload 'pymacs-load "pymacs" nil t) (pymacs-load "ropemacs" "rope-") It however slowdown the startup of Emacs significantly as it takes a while to load Ropemacs. I tried the following line instead but that loads Ropemacs everytime a Python file opened... (add-hook 'python-mode-hook (lambda () (pymacs-load "ropemacs" "rope-"))) Is there a way to perform the pymacs-load when opening a Python file but only if ropemacs and rope aren't loaded yet?

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  • Settings aren't saving in WPF?

    - by JOSH
    I'm using the registry Settings.settings thingymabob I'm doing the following in my XAML: <TextBox x:Name="textBoxUsername" Text="{Binding Source={x:Static prop:Settings.Default}, Path=Username, Mode=TwoWay}"></TextBox> This is loading the settings fine. Now in my Window's Closing event I have the following: Properties.Settings.Default.Save(); But it wont save settings?

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