Java generics: Illegal forward reference
- by Arian
Given a generic interface
interface Foo<A, B> { }
I want to write an implementation that requires A to be a subclass of B. So I want to do
class Bar<A, B super A> implements Foo<A, B> { }
// --> Syntax error
or
class Bar<A extends B, B> implements Foo<A, B> { }
// --> illegal forward reference
But the…
