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  • Global and local variables in my script

    - by Acorn
    I'm starting out learning javascript, and tried to write a little script that would make a grid of divs on a page. Here's the script: var tileWidth=50; var tileHeight=100; var leftPos=10; var topPos=10; var columns=10; var rows=10; var spacing=5; $('document').ready(function() { placeTiles(); }); function makeRow() { for (var i=0; i<columns; i++) { $('#canvas').append('<div class="tile" style="left:' + leftPos + 'px;top:' + topPos + 'px;"></div>'); var leftPos = leftPos + tileWidth + spacing; } } function placeTiles() { for (var i=0; i<rows; i++) { makeRow(); var topPos = topPos + tileHeight + spacing; } } At the moment, 100 <div>s get created, all with a top position of 10px and a left position of undefined (for the first <div> in the row) or NaN. What should I be doing differently? Why can't makerow() see my global leftPos variable (and all the other variables for that matter)? Thanks.

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  • geting information from Treeview with HierarchicalDataTemplate

    - by lina
    Good day! I have such a template: <common:HierarchicalDataTemplate x:Key="my2ndPlusHierarchicalTemplate" ItemsSource="{Binding Children}"> <StackPanel Margin="0,2,5,2" Orientation="Vertical" Grid.Column="2"> <CheckBox IsTabStop="False" IsChecked="False" Click="ItemCheckbox_Click" Grid.Column="1" /> <TextBlock Text="{Binding Name}" FontSize="16" Foreground="#FF100101" HorizontalAlignment="Left" FontFamily="Verdana" FontWeight="Bold" /> <TextBlock Text="{Binding Description}" FontFamily="Verdana" FontSize="10" HorizontalAlignment="Left" Foreground="#FFA09A9A" FontStyle="Italic" /> <TextBox Width="100" Grid.Column="4" Height="24" LostFocus="TextBox_LostFocus" Name="tbNumber"></TextBox> </StackPanel> </common:HierarchicalDataTemplate> for a Treeview <controls:TreeView x:Name="tvServices" ItemTemplate="{StaticResource myHierarchicalTemplate}" ItemContainerStyle="{StaticResource expandedTreeViewItemStyle}" Grid.Column="1" Grid.Row="2" Grid.ColumnSpan="3" BorderBrush="#FFC1BCBC" FontFamily="Verdana" FontSize="14"> </controls:TreeView> I want to know the Name property of each TextBox in Treeview to make validation of each textbox such as: private void TextBox_LostFocus(object sender, RoutedEventArgs e) { tbNumber.ClearValidationError(); if ((!tbNumber.Text.IsZakazNumberValid()) && (tbNumber.Text != "")) { tbNumber.SetValidation(MyStrings.NumberError); tbNumber.RaiseValidationError(); isValid = false; } else { isValid = true; } } and I wnat to see what check boxes were checked how can I do it?

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  • Position absolute for rounded corners and problems in IE6

    - by danit
    Im using position absolute to give the top left corner of a DIV a rounded corner. HTML: <div id="MyDiv"> Some content <div class="topLeft">&nbsp</div> </div> CSS: #MyDiv { position: relative; padding: 12px; background: #fff url('graident.png') repeat-x top left; } .topLeft { position: absolute; top: 0; right: 0; width: 10px; height: 10px; background: transparent url('corner.png') no-repeat top right; } This works fine in all browsers expcept IE6. In IE6 the corner.png image seems to be about 1px out at the top corner, essentially not top: 0; and right: 0; but more like top: 1px; right: 1px; Can anyone explain why this might be happening only in IE6?

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  • DVD ROM not working only in windows?

    - by Behrooz A
    I have an Asus N53SV laptop, My DVD rom doesn't read any type of DVD in windows , but I just installed windows 7 from a bootable DVD , I think this problem occurred after I tried to change my partitioning with paragon partition magic , I was trying to shrink , join and so , after that my windows showed an error that windows cannot find [weird address] on hard disk every time on starts. windows itself says the DVD drive works correctly and driver is working properly, but no DVD or CD can be read , note that the DVD I'm trying to read is the same DVD which I used to install windows some minutes ago. I don't know what's the problem

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  • How to make parts of a div element resize automatically?

    - by vladimir
    I'm trying to create a small html fragment (a div element) consisted of three parts: a label, textbox, and a button. Within that div element the label would be on the left (autosized), the button would be on the right (again, autosized) and the textbox should take up all remaining space within the parent div element. This is what I've tried (assuming I want my div to be 400 pixels wide): <div style="width:400px"> <div style="float: left">Label</div> <input style="width:100%"> <!-- doesn't work --> <button type='button' style='float: right'>Click</button> </div> The trouble is, my textbox does not get resized automatically. Add 'width=100%' to the textbox doesn't work. What would be the way to make it take up all remaining space between the label and the button? Ideally it should be done just by applying some styles, not by introducing new elements. (I guess the issue isn't related only to div element, but that just happens to be my work scenario.)

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  • Image re sizing not working after rotation in Html5 canvas

    - by Deepu the Don
    In my HTML 5 + Javascript application, we can drag, re size and rotate image in Html 5 canvas. But after doing rotation, re sizing is not working. (I think it i related to finding dx,dy,not sure). Please help me to fix the code given below. Thanks in advance. <!doctype html> <html> <head> <style> #canvas{ border:red dashed #ccc; } </style> <script type="text/javascript" src="http://code.jquery.com/jquery.min.js"></script> <script> $(function(){ var canvas=document.getElementById("canvas"),ctx=canvas.getContext("2d"),canvasOffset=$("#canvas").offset(); var offsetX=canvasOffset.left,offsetY=canvasOffset.top,startX,startY,isDown=false,pi2=Math.PI*2; var resizerRadius=8,rr=resizerRadius*resizerRadius,draggingResizer={x:0,y:0},imageX=50,imageY=50; var imageWidth,imageHeight,imageRight,imageBottom,draggingImage=false,startX,startY,doRotation=false; var r=0,rotImg = new Image(); rotImg.src="rotation.jpg"; var img=new Image(); img.onload=function(){ imageWidth=img.width; imageHeight=img.height; imageRight=imageX+imageWidth; imageBottom=imageY+imageHeight; w=img.width/2; h=img.height/2; draw(true,false); } img.src="https://dl.dropboxusercontent.com/u/139992952/stackoverflow/facesSmall.png"; function draw(withAnchors,withBorders){ ctx.fillStyle="black"; ctx.clearRect(0,0,canvas.width,canvas.height); ctx.save(); ctx.translate(imageX,imageY); ctx.translate(imageWidth/2,imageHeight/2); ctx.rotate(r); ctx.translate(-imageX,-imageY); ctx.translate(-imageWidth/2,-imageHeight/2); ctx.drawImage(img,0,0,img.width,img.height,imageX,imageY,imageWidth,imageHeight); ctx.restore(); if(withAnchors){ drawDragAnchor(imageX,imageY); drawDragAnchor(imageRight,imageY); drawDragAnchor(imageRight,imageBottom); drawDragAnchor(imageX,imageBottom); } if(withBorders){ ctx.save(); ctx.translate(imageX,imageY); ctx.translate(imageWidth/2,imageHeight/2); ctx.rotate(r); ctx.translate(-imageX,-imageY); ctx.translate(-imageWidth/2,-imageHeight/2); ctx.beginPath(); ctx.moveTo(imageX,imageY); ctx.lineTo(imageRight,imageY); ctx.lineTo(imageRight,imageBottom); ctx.lineTo(imageX,imageBottom); ctx.closePath(); ctx.stroke(); ctx.restore(); } ctx.fillStyle="blue"; ctx.save(); ctx.translate(imageX,imageY); ctx.translate(imageWidth/2,imageHeight/2); ctx.rotate(r); ctx.translate(-imageX,-imageY); ctx.translate(-imageWidth/2,-imageHeight/2); ctx.beginPath(); ctx.moveTo(imageRight+15,imageY-10); ctx.lineTo(imageRight+45,imageY-10); ctx.lineTo(imageRight+45,imageY+20); ctx.lineTo(imageRight+15,imageY+20); ctx.fill(); ctx.closePath(); ctx.restore(); } function drawDragAnchor(x,y){ ctx.save(); ctx.translate(imageX,imageY); ctx.translate(imageWidth/2,imageHeight/2); ctx.rotate(r); ctx.translate(-imageX,-imageY); ctx.translate(-imageWidth/2,-imageHeight/2); ctx.beginPath(); ctx.arc(x,y,resizerRadius,0,pi2,false); ctx.closePath(); ctx.fill(); ctx.restore(); } function anchorHitTest(x,y){ var dx,dy; dx=x-imageX; dy=y-imageY; if(dx*dx+dy*dy<=rr){ return(0); } // top-right dx=x-imageRight; dy=y-imageY; if(dx*dx+dy*dy<=rr){ return(1); } // bottom-right dx=x-imageRight; dy=y-imageBottom; if(dx*dx+dy*dy<=rr){ return(2); } // bottom-left dx=x-imageX; dy=y-imageBottom; if(dx*dx+dy*dy<=rr){ return(3); } return(-1); } function hitImage(x,y){ return(x>imageX && x<imageX+imageWidth && y>imageY && y<imageY+imageHeight); } function handleMouseDown(e){ startX=parseInt(e.clientX-offsetX); startY=parseInt(e.clientY-offsetY); draggingResizer= anchorHitTest(startX,startY); draggingImage= draggingResizer<0 && hitImage(startX,startY); doRotation = draggingResizer<0 && !draggingImage && ctx.isPointInPath(startX,startY); } function handleMouseUp(e){ draggingResizer=-1; draggingImage=false; doRotation=false; draw(true,false); } function handleMouseOut(e){ handleMouseUp(e); } function handleMouseMove(e){ mouseX=parseInt(e.clientX-offsetX); mouseY=parseInt(e.clientY-offsetY); if(draggingResizer>-1){ switch(draggingResizer){ case 0: //top-left imageX=mouseX; imageWidth=imageRight-mouseX; imageY=mouseY; imageHeight=imageBottom-mouseY; break; case 1: //top-right imageY=mouseY; imageWidth=mouseX-imageX; imageHeight=imageBottom-mouseY; break; case 2: //bottom-right imageWidth=mouseX-imageX; imageHeight=mouseY-imageY; break; case 3: //bottom-left imageX=mouseX; imageWidth=imageRight-mouseX; imageHeight=mouseY-imageY; break; } if(imageWidth<25) imageWidth=25; if(imageHeight<25) imageHeight=25; imageRight=imageX+imageWidth; imageBottom=imageY+imageHeight; draw(true,true); }else if(draggingImage){ imageClick=false; var dx=mouseX-startX; var dy=mouseY-startY; imageX+=dx; imageY+=dy; imageRight+=dx; imageBottom+=dy; startX=mouseX; startY=mouseY; draw(false,true); }else if(doRotation){ var dx=mouseX-imageX; var dy=mouseY-imageY; r=Math.atan2(dy,dx); draw(false,true); } } $("#canvas").mousedown(function(e){handleMouseDown(e);}); $("#canvas").mousemove(function(e){handleMouseMove(e);}); $("#canvas").mouseup(function(e){handleMouseUp(e);}); $("#canvas").mouseout(function(e){handleMouseOut(e);}); }); </script> </head> <body> <canvas id="canvas" width=800 height=500></canvas> </body> </html>

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  • Joining Windows 7 Professional to a Windows Server 2003 R2 x64 domain fails.

    - by Vinko Vrsalovic
    I have a windows 7 professional (spanish) laptop trying to join a Windows Server 2003 (english) domain. It detect correctly the SRV record, finding the proper domain controller, but then the join fails with the error message (snippet, because the error is in spanish) An Active Directory Domain Controller for This Domain Could Not be Contacted The DNS is correctly set, and client can ping by name and IP the server, the server can ping the client by IP. I've tested with the FW down to no avail. A host of other XP Pro clients are connected to the domain. I've restarted Net Logon and checked that Windows Time is up. Also the times are in sync between the server and the client. I'll put below diagnostics output. I'm wondering if there's anything special to be done on either the server or the client to have a Win 7 Pro join a 2k3 R2 domain. The following diagnostic information follows: netdiag /q for the DC dcdiag on the DC ipconfig /all on the Win 7 client netdiag /q on the DC: .................................. Computer Name: HI-X2 DNS Host Name: hi-x2.hi.local System info : Microsoft Windows Server 2003 R2 (Build 3790) Processor : EM64T Family 6 Model 23 Stepping 10, GenuineIntel List of installed hotfixes : KB923561 KB924667-v2 KB925398_WMP64 KB925902 KB926122 KB927891 KB929123 KB930178 KB932168 KB936357 KB938127 KB941569 KB942830 KB942831 KB943055 KB943460 KB944338-v2 KB944653 KB945553 KB946026 KB948496 KB950760 KB950762 KB950974 KB951066 KB951748 KB952004 KB952069 KB952954 KB954155 KB954550-v7 KB955069 KB955759 KB956572 KB956802 KB956803 KB956844 KB958469 KB958644 KB958869 KB959426 KB960225 KB960803 KB960859 KB961063 KB961118 KB961501 KB967715 KB967723 KB968389 KB968816 KB969059 KB969947 KB970238 KB970430 KB970483 KB971032 KB971468 KB971657 KB971737 KB971961 KB971961-IE8 KB972270 KB973037 KB973354 KB973507 KB973540 KB973687 KB973815 KB973825 KB973869 KB973904 KB973917-v2 KB974112 KB974318 KB974392 KB974571 KB975025 KB975467 KB975560 KB975713 KB976662-IE8 KB977290 KB977816 KB977914 KB978037 KB978262 KB978338 KB978542 KB978601 KB978706 KB979306 KB979309 KB979683 KB980182 KB980182-IE8 KB980232 KB980302-IE8 KB981332-IE8 KB981350 Q147222 Per interface results: Adapter : Local Area Connection Host Name. . . . . . . . . : hi-x2.hi.local IP Address . . . . . . . . : 10.0.1.199 Subnet Mask. . . . . . . . : 255.0.0.0 Default Gateway. . . . . . : 10.0.1.1 Dns Servers. . . . . . . . : 10.0.1.199 WINS service test. . . . . : Skipped Global results: [WARNING] You don't have a single interface with the 'WorkStation Service', 'Messenger Service', 'WINS' names defined. DNS test . . . . . . . . . . . . . : Passed PASS - All the DNS entries for DC are registered on DNS server '10.0.1.199'. IP Security test . . . . . . . . . : Skipped The command completed successfully dcdiag on the DC: Domain Controller Diagnosis Performing initial setup: Done gathering initial info. Doing initial required tests Testing server: Default-First-Site-Name\HI-X2 Starting test: Connectivity ......................... HI-X2 passed test Connectivity Doing primary tests Testing server: Default-First-Site-Name\HI-X2 Starting test: Replications ......................... HI-X2 passed test Replications Starting test: NCSecDesc ......................... HI-X2 passed test NCSecDesc Starting test: NetLogons ......................... HI-X2 passed test NetLogons Starting test: Advertising ......................... HI-X2 passed test Advertising Starting test: KnowsOfRoleHolders ......................... HI-X2 passed test KnowsOfRoleHolders Starting test: RidManager ......................... HI-X2 passed test RidManager Starting test: MachineAccount ......................... HI-X2 passed test MachineAccount Starting test: Services ......................... HI-X2 passed test Services Starting test: ObjectsReplicated ......................... HI-X2 passed test ObjectsReplicated Starting test: frssysvol ......................... HI-X2 passed test frssysvol Starting test: frsevent ......................... HI-X2 passed test frsevent Starting test: kccevent ......................... HI-X2 passed test kccevent Starting test: systemlog ......................... HI-X2 passed test systemlog Starting test: VerifyReferences ......................... HI-X2 passed test VerifyReferences Running partition tests on : ForestDnsZones Starting test: CrossRefValidation ......................... ForestDnsZones passed test CrossRefValidation Starting test: CheckSDRefDom ......................... ForestDnsZones passed test CheckSDRefDom Running partition tests on : DomainDnsZones Starting test: CrossRefValidation ......................... DomainDnsZones passed test CrossRefValidation Starting test: CheckSDRefDom ......................... DomainDnsZones passed test CheckSDRefDom Running partition tests on : Schema Starting test: CrossRefValidation ......................... Schema passed test CrossRefValidation Starting test: CheckSDRefDom ......................... Schema passed test CheckSDRefDom Running partition tests on : Configuration Starting test: CrossRefValidation ......................... Configuration passed test CrossRefValidation Starting test: CheckSDRefDom ......................... Configuration passed test CheckSDRefDom Running partition tests on : hi Starting test: CrossRefValidation ......................... hi passed test CrossRefValidation Starting test: CheckSDRefDom ......................... hi passed test CheckSDRefDom Running enterprise tests on : hi.local Starting test: Intersite ......................... hi.local passed test Intersite Starting test: FsmoCheck ......................... hi.local passed test FsmoCheck ipconfig /all on the Windows 7 client: Configuraci¢n IP de Windows Nombre de host. . . . . . . . . : hi-p6 Sufijo DNS principal . . . . . : Tipo de nodo. . . . . . . . . . : h¡brido Enrutamiento IP habilitado. . . : no Proxy WINS habilitado . . . . . : no Adaptador de LAN inal mbrica Conexi¢n de red inal mbrica: Sufijo DNS espec¡fico para la conexi¢n. . : Descripci¢n . . . . . . . . . . . . . . . : Intel(R) WiFi Link 5100 AGN Direcci¢n f¡sica. . . . . . . . . . . . . : 00-22-FB-63-47-A0 DHCP habilitado . . . . . . . . . . . . . : no Configuraci¢n autom tica habilitada . . . : s¡ Direcci¢n IPv4. . . . . . . . . . . . . . : 10.0.1.42(Preferido) M scara de subred . . . . . . . . . . . . : 255.255.255.0 Puerta de enlace predeterminada . . . . . : 10.0.1.1 Servidores DNS. . . . . . . . . . . . . . : 10.0.1.199 NetBIOS sobre TCP/IP. . . . . . . . . . . : habilitado Adaptador de Ethernet Conexi¢n de  rea local: Estado de los medios. . . . . . . . . . . : medios desconectados Sufijo DNS espec¡fico para la conexi¢n. . : Descripci¢n . . . . . . . . . . . . . . . : Realtek PCIe GBE Family Controller Direcci¢n f¡sica. . . . . . . . . . . . . : 00-1E-33-1F-35-B1 DHCP habilitado . . . . . . . . . . . . . : s¡ Configuraci¢n autom tica habilitada . . . : s¡ Adaptador de t£nel isatap.{8926581E-09AC-4123-906B-DA6386AD2D60}: Estado de los medios. . . . . . . . . . . : medios desconectados Sufijo DNS espec¡fico para la conexi¢n. . : Descripci¢n . . . . . . . . . . . . . . . : Adaptador ISATAP de Microsoft Direcci¢n f¡sica. . . . . . . . . . . . . : 00-00-00-00-00-00-00-E0 DHCP habilitado . . . . . . . . . . . . . : no Configuraci¢n autom tica habilitada . . . : s¡ Adaptador de t£nel Teredo Tunneling Pseudo-Interface: Sufijo DNS espec¡fico para la conexi¢n. . : Descripci¢n . . . . . . . . . . . . . . . : Teredo Tunneling Pseudo-Interface Direcci¢n f¡sica. . . . . . . . . . . . . : 00-00-00-00-00-00-00-E0 DHCP habilitado . . . . . . . . . . . . . : no Configuraci¢n autom tica habilitada . . . : s¡ Direcci¢n IPv6 . . . . . . . . . . : 2001:0:5ef5:73ba:1cec:3883:f5ff:fed5(Preferido) V¡nculo: direcci¢n IPv6 local. . . : fe80::1cec:3883:f5ff:fed5%13(Preferido) Puerta de enlace predeterminada . . . . . : :: NetBIOS sobre TCP/IP. . . . . . . . . . . : deshabilitado

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  • How to center list tags inside an unordered list?

    - by Jack
    How can list tags that are given a display:block and are floated left, be centered inside an unordered list. The HTML: <div id="navigation"> <ul> <li>Home</li> <li>About Us</li> <li>Contact</li> <li>News</li> <li>Events</li> <li>Video</li> <li>Photos</li> </ul> </div><!-- navigation --> The CSS: #navigation { border: 3px solid orange; overflow: hidden; } #navigation ul { list-style-type: none; text-align: center; } #navigation ul li { float: left; display: block; padding: 10px 8px; border: 1px solid green; }

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  • Pecking order of pigeons?

    - by sc_ray
    I was going though problems on graph theory posted by Prof. Ericksson from my alma-mater and came across this rather unique question about pigeons and their innate tendency to form pecking orders. The question goes as follows: Whenever groups of pigeons gather, they instinctively establish a pecking order. For any pair of pigeons, one pigeon always pecks the other, driving it away from food or potential mates. The same pair of pigeons always chooses the same pecking order, even after years of separation, no matter what other pigeons are around. Surprisingly, the overall pecking order can contain cycles—for example, pigeon A pecks pigeon B, which pecks pigeon C, which pecks pigeon A. Prove that any finite set of pigeons can be arranged in a row from left to right so that every pigeon pecks the pigeon immediately to its left. Since this is a question on Graph theory, the first things that crossed my mind that is this just asking for a topological sort of a graphs of relationships(relationships being the pecking order). What made this a little more complex was the fact that there can be cyclic relationships between the pigeons. If we have a cyclic dependency as follows: A-B-C-A where A pecks on B,B pecks on C and C goes back and pecks on A If we represent it in the way suggested by the problem, we have something as follows: C B A But the above given row ordering does not factor in the pecking order between C and A. I had another idea of solving it by mathematical induction where the base case is for two pigeons arranged according to their pecking order, assuming the pecking order arrangement is valid for n pigeons and then proving it to be true for n+1 pigeons. I am not sure if I am going down the wrong track here. Some insights into how I should be analyzing this problem will be helpful. Thanks

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  • Adding a Windows Server 2012 Essentials server to an existing domain, without migrating the AD

    - by TiernanO
    I have an existing Active Directory in house, a mix between a Win2K8R2 and Win2K3 domain, and i would like to test out Windows Server 2012 Essentials BETA on the network. When walking though the install, it gives me the option of a new domain, or migrating from an existing domain. when clicking existing, it tells me i can only have one SBS server running on a domain at a time... So, i dont have any existing SBS servers in house (both are full standard or enterprise editions) but i do plan on keeping at least one of these extra servers running... So, how do i get a 2012 Essentials server to join a domain, and not migrate the existing domain? or if i do migrate, can i still get one of the other boxes to act as secondary controllers?

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  • XNA Vector2 Rotation Question

    - by Tom Allen
    I'm messing about with some stuff in XNA and am trying to move an object around asteroids-style in that you press left and right to rotate and up/down to go forwards and backwards in the direction you are pointing. I've got the rotation of the sprite done, but i can't get the object to move in the direction you've pointed it, it always moves up and down on the x = 0 axis. I'm guessing this is straight forward but I just can't figure it out. My "ship" class has the following properties which are note worthy here: Vector2 Position float Rotation The "ship" class has an update method is where the input is handled and so far I've got the following: public void Update(GameTime gameTime) { KeyboardState keyboard = Keyboard.GetState(); GamePadState gamePad = GamePad.GetState(PlayerIndex.One); float x = Position.X; float y = Position.Y; if (keyboard.IsKeyDown(Keys.Left)) Rotation -= 0.1f; if (keyboard.IsKeyDown(Keys.Right)) Rotation += 0.1f; if (keyboard.IsKeyDown(Keys.Up)) y -= ??; if (keyboard.IsKeyDown(Keys.Down)) y += ??; this.Position = new Vector2(x, y); } Any help would be most appreciated!

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  • Create PDF from HTML page with formatting retained in PDF in ASP.Net

    - by Vishal Avhad
    I am trying to convert an HTML page to a PDF using iTextSharp.dll in ASP.Net. I am able to convert the contents to my PDF , but the problem is that the Formatting of HTML page (which is inline) get removed from my PDF created. For instance I have the following code block to be formatted from my HTML page to PDF. <table style="width:90%; float:left; background:#dddddd; padding:15px; border:1px solid #000; color:#000;"><tr><td style="text-transform:uppercase; font-size:14px;font-weight:bold;">SPECIAL DELIVERY FOR:</td></tr><tr><td style="padding-left:40px; font-size:12px; color:#4e4e4e;">Name: #CustomerName# <br /><br /><label> <b>Date: #CreatedOn# </b></label><br /> </td></tr> </table> I have to format my PDF with much more HTML codes like this. I have used the Stylesheet class also, but that was not much of help.

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  • ASP: Assigning CSS to dynamically created Label in C#

    - by Tucker
    I'm trying to figure out how to apply CSS to a Label created in C#. Everything compiles and runs, it just doesn't seem to be applying the CSS. The CSS is in the file linked to in the site master page. Everything else in the CSS file is being applied as it should be. Codebehind: ... Label label = new Label(); SqlCommand command = new SqlCommand("SELECT Q_Text FROM HRA.dbo.Questions WHERE QID = 1"); command.Connection = connection; reader = command.ExecuteReader(); reader.Read(); label.Text = reader["Q_Text"].ToString(); label.ID = "rblabel"; label.CssClass = "rblabel"; reader.Close(); ... ASP: <asp:Content runat="server" ID="BodyContent" ContentPlaceHolderID="MainContent"> <asp:PlaceHolder ID="holder" runat="server"> </asp:PlaceHolder> </asp:Content> CSS: .rblabel { text-align:left; padding-left: 2em; font-size: 4em; }

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  • How to append \line into RTF using RichTextBox control

    - by Steve Sheldon
    When using the Microsoft RichTextBox control it is possible to add new lines like this... richtextbox.AppendText(System.Environment.NewLine); // appends \r\n However, if you now view the generated rtf the \r\n characters are converted to \par not \line How do I insert a \line control code into the generated RTF? What does't work: Token Replacement Hacks like inserting a token at the end of the string and then replacing it after the fact, so something like this: string text = "my text"; text = text.Replace("||" "|"); // replace any '|' chars with a double '||' so they aren't confused in the output. text = text.Replace("\r\n", "_|0|_"); // replace \r\n with a placeholder of |0| richtextbox.AppendText(text); string rtf = richtextbox.Rtf; rtf.Replace("_|0|_", "\\line"); // replace placeholder with \line rtf.Replace("||", "|"); // set back any || chars to | This almost worked, it breaks down if you have to support right to left text as the right to left control sequence always ends up in the middle of the placeholder. Sending Key Messages public void AppendNewLine() { Keys[] keys = new Keys[] {Keys.Shift, Keys.Return}; SendKeys(keys); } private void SendKeys(Keys[] keys) { foreach(Keys key in keys) { SendKeyDown(key); } } private void SendKeyDown(Keys key) { user32.SendMessage(this.Handle, Messages.WM_KEYDOWN, (int)key, 0); } private void SendKeyUp(Keys key) { user32.SendMessage(this.Handle, Messages.WM_KEYUP, (int)key, 0); } This also ends up being converted to a \par Is there a way to post a messaged directly to the msftedit control to insert a control character? I am totally stumped, any ideas guys? Thanks for your help!

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  • How to set up my network/bridging using Apple Airport equipment?

    - by John
    I'd like to set up my network like this, and I want to make sure it's possible using the hardware I have. I think it should be... I've got my cable modem in one room. I want to plug it into an Apple Airport Express and create my wireless my wireless network here. The airport express will do the NAT and DHCP. By my TV there are a few things to be networked (Xbox and Tivo). I have an airport extreme here. I'd like to have the airport extreme join the wireless network and share the connection to the ethernet ports. Can anyone provide some assistance on the best way to configure to do this? Thanks!

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  • how to speed up the code??

    - by kaushik
    i have very huge code about 600 lines plus. cant post the whole thing here. but a particular code snippet is taking so much time,leading to problems. here i post that part of code please tell me what to do speed up the processing.. please suggest the part which may be the reason and measure to improve them if this small part of code is understandable. using_data={} def join_cost(a , b): global using_data #print a #print b save_a=[] save_b=[] print 1 #for i in range(len(m)): #if str(m[i][0])==str(a): save_a=database_index[a] #for i in range(len(m)): # if str(m[i][0])==str(b): #print 'save_a',save_a #print 'save_b',save_b print 2 save_b=database_index[b] using_data[save_a[0]]=save_a s=str(save_a[1]).replace('phone','text') s=str(s)+'.pm' p=os.path.join("c:/begpython/wavnk/",s) x=open(p , 'r') print 3 for i in range(6): x.readline() k2='a' j=0 o=[] while k2 is not '': k2=x.readline() k2=k2.rstrip('\n') oj=k2.split(' ') o=o+[oj] #print o[j] j=j+1 #print j #print o[2][0] temp=long(1232332) end_time=save_a[4] #print end_time k=(j-1) for i in range(k): diff=float(o[i][0])-float(end_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i #print pm_row #print temp #print o[pm_row] #pm_row=3 q=[] print 4 l=str(p).replace('.pm','.mcep') z=open(l ,'r') for i in range(pm_row): z.readline() k3=z.readline() k3=k3.rstrip('\n') q=k3.split(' ') #print q print 5 s=str(save_b[1]).replace('phone','text') s=str(s)+'.pm' p=os.path.join("c:/begpython/wavnk/",s) x=open(p , 'r') for i in range(6): x.readline() k2='a' j=0 o=[] while k2 is not '': k2=x.readline() k2=k2.rstrip('\n') oj=k2.split(' ') o=o+[oj] #print o[j] j=j+1 #print j #print o[2][0] temp=long(1232332) strt_time=save_b[3] #print strt_time k=(j-1) for i in range(k): diff=float(o[i][0])-float(strt_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i #print pm_row #print temp #print o[pm_row] #pm_row=3 w=[] l=str(p).replace('.pm','.mcep') z=open(l ,'r') for i in range(pm_row): z.readline() k3=z.readline() k3=k3.rstrip('\n') w=k3.split(' ') #print w cost=0 for i in range(12): #print q[i] #print w[i] h=float(q[i])-float(w[i]) cost=cost+math.pow(h,2) j_cost=math.sqrt(cost) #print cost return j_cost def target_cost(a , b): a=(b+1)*3 b=(a+1)*2 t_cost=(a+b)*5/2 return t_cost r1='shht:ra_77' r2='grx_18' g=[] nodes=[] nodes=nodes+[[r1]] for i in range(len(y_in_db_format)): g=y_in_db_format[i] #print g #print g[0] g.remove(str(g[0])) nodes=nodes+[g] nodes=nodes+[[r2]] print nodes print "lenght of nodes",len(nodes) lists=[] #lists=lists+[r1] for i in range(len(nodes)): for j in range(len(nodes[i])): lists=lists+[nodes[i][j]] #lists=lists+[r2] print lists distance={} for i in range(len(lists)): if i==0: distance[str(lists[i])]=0 else: distance[str(lists[i])]=long(123231223) #print distance group_dist=[] infinity=long(123232323) for i in range(len(nodes)): distances=[] for j in range(len(nodes[i])): #distances=[] if i==0: distances=distances+[[nodes[i][j], 0]] else: distances=distances+[[nodes[i][j],infinity]] group_dist=group_dist+[distances] #print distances print "group_distances",group_dist #print "check",group_dist[0][0][1] #costs={} #for i in range(len(lists)): #if i==0: # costs[str(lists[i])]=1 #else: # costs[str(lists[i])]=get_selfcost(lists[i]) path=[] for i in range(len(nodes)): mini=[] if i!=(len(nodes)-1): #temp=long(123234324) #Now calculate the cost between the current node and each of its neighbour for k in range(len(nodes[(i+1)])): for j in range(len(nodes[i])): current=nodes[i][j] #print "current_node",current j_distance=join_cost( current , nodes[i+1][k]) #t_distance=target_cost( current , nodes[i+1][k]) t_distance=34 #print distance #print "distance between current and neighbours",distance total_distance=(.5*(float(group_dist[i][j][1])+float(j_distance))+.5*(float(t_distance))) #print "total distance between the intial_nodes and current neighbour",total_distance if int(group_dist[i+1][k][1]) > int(total_distance): group_dist[i+1][k][1]=total_distance #print "updated distance",group_dist[i+1][k][1] a=current #print "the neighbour",nodes[i+1][k],"updated the value",a mini=mini+[[str(nodes[i+1][k]),a]] print mini

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  • Why can't decimal numbers be represented exactly in binary?

    - by Barry Brown
    There have been several questions posted to SO about floating-point representation. For example, the decimal number 0.1 doesn't have an exact binary representation, so it's dangerous to use the == operator to compare it to another floating-point number. I understand the principles behind floating-point representation. What I don't understand is why, from a mathematical perspective, are the numbers to the right of the decimal point any more "special" that the ones to the left? For example, the number 61.0 has an exact binary representation because the integral portion of any number is always exact. But the number 6.10 is not exact. All I did was move the decimal one place and suddenly I've gone from Exactopia to Inexactville. Mathematically, there should be no intrinsic difference between the two numbers -- they're just numbers. By contrast, if I move the decimal one place in the other direction to produce the number 610, I'm still in Exactopia. I can keep going in that direction (6100, 610000000, 610000000000000) and they're still exact, exact, exact. But as soon as the decimal crosses some threshold, the numbers are no longer exact. What's going on? Edit: to clarify, I want to stay away from discussion about industry-standard representations, such as IEEE, and stick with what I believe is the mathematically "pure" way. In base 10, the positional values are: ... 1000 100 10 1 1/10 1/100 ... In binary, they would be: ... 8 4 2 1 1/2 1/4 1/8 ... There are also no arbitrary limits placed on these numbers. The positions increase indefinitely to the left and to the right.

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  • How to insert and reterive key from registry editor

    - by deepa
    Hi.. I am new to cryptography.. i have to develop project based on cryptography..In part of my project I have to insert a key to the registry and afterwards i have to reterive the same key for decryption.. i done until getting the path of the registry .. Here i given my code.. import java.io.IOException; import java.io.InputStream; import java.io.StringWriter; public static final String readRegistry(String location, String key) { try { // Run reg query, then read output with StreamReader (internal class) Process process = Runtime.getRuntime().exec("reg query " + '"' + location + "\" /v " + key); StreamReader reader = new StreamReader(process.getInputStream()); reader.start(); process.waitFor(); reader.join(); String output = reader.getResult(); // Output has the following format: // \n<Version information>\n\n<key>\t<registry type>\t<value> if (!output.contains("\t")) { return null; } // Parse out the value String[] parsed = output.split("\t"); return parsed[parsed.length - 1]; } catch (Exception e) { return null; } } static class StreamReader extends Thread { private InputStream is; private StringWriter sw = new StringWriter(); ; public StreamReader(InputStream is) { this.is = is; } public void run() { try { int c; while ((c = is.read()) != -1) { System.out.println("Reading" + c); sw.write(c); } } catch (IOException e) { System.out.println("Exception in run() " + e); } } public String getResult() { System.out.println("Content " + sw.toString()); return sw.toString(); } } public static boolean addValue(String key, String valName, String val) { try { // Run reg query, then read output with StreamReader (internal class) Process process = Runtime.getRuntime().exec("reg add \"" + key + "\" /v \"" + valName + "\" /d \"\\\"" + val + "\\\"\" /f"); StreamReader reader = new StreamReader(process.getInputStream()); reader.start(); process.waitFor(); reader.join(); String output = reader.getResult(); System.out.println("Processing........ggggggggggggggggggggg." + output); // Output has the following format: // \n&lt;Version information&gt;\n\n&lt;key&gt;\t&lt;registry type&gt;\t&lt;value&gt; return output.contains("The operation completed successfully"); } catch (Exception e) { System.out.println("Exception in addValue() " + e); } return false; } public static void main(String[] args) { // Sample usage JAXRDeleteConcept hc = new JAXRDeleteConcept(); System.out.println("Before Insertion"); if (JAXRDeleteConcept.addValue("HKEY_CURRENT_USER\\Software\\Microsoft\\Windows\\CurrentVersion\\Explorer\\ComDlg32\\OpenSaveMRU", "REG_SZ", "Muthus")) { System.out.println("Inserted Successfully"); } String value = JAXRDeleteConcept.readRegistry("HKEY_CURRENT_USER\\Software\\Microsoft\\Windows\\CurrentVersion\\Explorer\\ComDlg32\\OpenSaveMRU" , "Project_Key"); System.out.println(value); } } But i dont know how to insert a key in a registry and read the particular key which i inserted..Please help me.. Thanks in advance..

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  • problem in html, table class text stretching out.

    - by Andy
    Hey people, I've got a slight problem after weeks of html programming. I've got a large table which I use to construct tabs with, details don't really matter. On every tab there is a tab title (which is defined as one single cell in a table with a class from a .css) and under it there are other rows and columns for the table. sample code for the single table with the single cell in it: <table class='tabcontainer_title'><tr><td class='tabcontainer_title'>TEXT</td></tr></table> This table is again positioned in one cell of the table outside it, which has a different class 'tabcontainer_content' This is in the CSS: .tabcontainer_title{ background-color : #58af34; background-image : url(); text-align : right; vertical-align : top; margin-top : 0px; margin-right : 0px; margin-bottom : 0px; margin-left : 0px; padding-top : 5px; padding-right : 10px; padding-bottom : 5px; padding-left : 0px; font-size : 14px; font-style : normal; color : #000000; } .tabcontainer_content{ width : 100%; font-weight : bolder; background-color : #58af34; color : #000000; padding : 0px; border-collapse : collapse; } The problem I'm experiencing right now is that if there are like 3 rows in the table, which means there's a lot of emtpy space instead of those rows, the text in the tab title has a large margin from the top: but I haven't configured any margin to be present. When the table is full of rows though, hence the table is full, then the tab title holds no unnecessary empty space above the text. What am I missing here?

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  • position of options in HTML select element

    - by frenchie
    I have a element that contains options. The element is 150px wide but some of the options are wider. So when rendering, the browser shows the overflow to the right. How can I make the options list overflow to the left? JSFiddle Thanks. <select id="MySelect"> <option value="60" selected="selected"></option><option value="-60">(UTC-01:00) Azores</option> <option value="-60">(UTC-01:00) Cape Verde Is.</option><option value="0">(UTC) Casablanca</option> <option value="0">(UTC) Dublin, Edinburgh, Lisbon, London</option><option value="0">(UTC) Monrovia, Reykjavik</option> <option value="60">(UTC+01:00) Belgrade, Bratislava, Budapest, Ljubljana, Prague</option> <option value="60">(UTC+01:00) Brussels, Copenhagen, Madrid, Paris</option> <option value="60">(UTC+01:00) Sarajevo, Skopje, Warsaw, Zagreb</option> <option value="60">(UTC+01:00) West Central Africa</option> <option value="120">(UTC+01:00) Windhoek</option> </select>?????????????????????????????????????????????? ?#MySelect{ margin-top:20px; margin-left:200px; width:150px;}

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  • determine page UI culture throgh javascript

    - by mj-y
    I have two div tags in my html code as shown below. I want to change their float property depending on page UI culture ( Ui culture is en-US or fa-IR) ... I think I can use java script to do so. but I don't know how can I get the UI Culture through Javascript. I want a code in if condition to determine the Ui culture ... thx in advance for your help... <div id="zone1" style="float: left;"><img alt="" src="~/IconArrow.png" /> &nbsp;</div> <div id="zone2" style="float: left;"><img alt="" src="~/IconHome.png" /></div> <script type="text/javascript"> if(/* ui culture is fa-IR*/) { document.getElementById("zone1").style.float = "right"; document.getElementById("zone2").style.float = "right"; } </script>

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  • EC2 server in VPC stops responding after joining domain

    - by Geoff
    We have a EC2 Windows Server set up and running in our VPC, connected to our network via a Juniper 5GT. This is working well, with the tunnel up and stable. If I then join the server to our local domain, it appears to work - I can then log on using domain credentials, and use domain accounts when applying security to folders etc. After I log out, if I give it around an hour, the box becomes unresponsive. I can't ping it, although a tracert goes all the way barring the last hop - so the tunnel is ok. I can't RDP into it. If I reboot it, then it works for a while before doing the same thing. Un-joining it from the domain fixes the problem, and it stays up and stable. The event logs don't show anything obvious, at least to me. Any ideas?

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  • gluLookAt vectors and FPS-style camera

    - by Kevin Pamplona
    I am attempting to implemented an FPS-style camera by updating three vectors: EYE, DIR, UP. These vectors are the same that are used by gluLookAt (since gluLookAt is specified by the position of the camera, the direction it is looking at, and an up vector). I have already implemented the left-right and up-down strafing movements, but I'm having a lot of trouble understanding the math behind making the camera look-around while remaining stationary. In this case, the EYE vector remains the same, while I must update DIR and UP. Below is the code I tried, but it doesn't seem to work properly. Any suggestions? Thanks. void Transform::left(float degrees, vec3& dir, vec3& up) { vec3 axis; axis = glm::normalize(up); mat3 R = rotate(-degrees, axis); dir = R*dir; dir = R*up; }; void Transform::up(float degrees, vec3& dir, vec3& up) { vec3 axis; axis=glm::normalize(glm::cross(dir,up)); mat3 R = rotate(-degrees, axis); dir = R*dir-; up = R*up; };

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  • little java help....

    - by jona
    Hi I am doing some practice problems and trying to print a diagonal line like the example below. I have writen the program you see below and I honestly dont understand what I am doing wrong. I m a java beginner and I cant see how to find the error. Example ( If you only see a straight line of stars...then imagine it diagonally....from top left to bottom right) * * * * * code: class Diagonal{ public static void main(String args[]) { int row, col; for(row = 1; row < 6; row++) { for(col = 1; col <= row; col++) { if(col==row){ System.out.print("*"); } else{ System.out.print(""); } System.out.println(); } } } } I am trying to learn for loops because they really confuse me. Another practice is to print a similar diagonal line but this time from right to left. I cant do that without getting this right however :( I believe they will be pretty similar? Above my reasining is this: As long as the column # is the same as the row number the print the line or otherwise leave a blank....what's wrong with how i did it? THANK YOU!

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  • YUI-css problem in IE 6 and 7

    - by cvack
    If you look at the screenshot below you can see that the right menu box in red has the wrong position in IE6 and 7: <div id="doc4" class="yui-t2"> //yui-t2 = 180px on the left <div id="bd"> <div id="yui-main"> <div class="yui-b"> <div class="yui-gc"> // yui-gc 2/3, 1/3 <div class="yui-u first">content</div> // 2/3 <div class="yui-u">right menu</div> // 1/3 </div> </div> </div> <div class="yui-b">left menu</div> // 180px </div> <div id="ft">footer</div> </div> Anyone know how I can fix this problem?

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