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  • WPF Buttons Style

    - by Polaris
    I have WPF Form which has many buttons with the same code. Appearance of all buttons must be the same For example, code for one of these buttons <Button x:Name="btnAddRelative" Width="120" Click="btnAddRelative_Click" > <Button.Content> <StackPanel Orientation="Horizontal"> <Image Height="26" HorizontalAlignment="Left"> <Image.Source> <BitmapImage UriSource="images/add.png" /> </Image.Source> </Image> <TextBlock Text=" Add Relative" Height="20" VerticalAlignment="Center"/> </StackPanel> </Button.Content> </Button> How can I create one style and use it for all my buttons. All buttons has the same png image, only their text different. How can I do this. I tried to do this with Style object in Resource Section: <UserControl.Resources> <Style TargetType="Button" x:Key="AddStyle"> <Setter Property="Content"> <Setter.Value> <StackPanel Orientation="Horizontal"> <Image Height="26" HorizontalAlignment="Left"> <Image.Source> <BitmapImage UriSource="images/add.png" /> </Image.Source> </Image> <TextBlock Text=" " Height="20" VerticalAlignment="Center"/> </StackPanel> </Setter.Value> </Setter> </Style> </UserControl.Resources> But this code not work. Can any body know how can I do this?

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  • Image re sizing not working after rotation in Html5 canvas

    - by Deepu the Don
    In my HTML 5 + Javascript application, we can drag, re size and rotate image in Html 5 canvas. But after doing rotation, re sizing is not working. (I think it i related to finding dx,dy,not sure). Please help me to fix the code given below. Thanks in advance. <!doctype html> <html> <head> <style> #canvas{ border:red dashed #ccc; } </style> <script type="text/javascript" src="http://code.jquery.com/jquery.min.js"></script> <script> $(function(){ var canvas=document.getElementById("canvas"),ctx=canvas.getContext("2d"),canvasOffset=$("#canvas").offset(); var offsetX=canvasOffset.left,offsetY=canvasOffset.top,startX,startY,isDown=false,pi2=Math.PI*2; var resizerRadius=8,rr=resizerRadius*resizerRadius,draggingResizer={x:0,y:0},imageX=50,imageY=50; var imageWidth,imageHeight,imageRight,imageBottom,draggingImage=false,startX,startY,doRotation=false; var r=0,rotImg = new Image(); rotImg.src="rotation.jpg"; var img=new Image(); img.onload=function(){ imageWidth=img.width; imageHeight=img.height; imageRight=imageX+imageWidth; imageBottom=imageY+imageHeight; w=img.width/2; h=img.height/2; draw(true,false); } img.src="https://dl.dropboxusercontent.com/u/139992952/stackoverflow/facesSmall.png"; function draw(withAnchors,withBorders){ ctx.fillStyle="black"; ctx.clearRect(0,0,canvas.width,canvas.height); ctx.save(); ctx.translate(imageX,imageY); ctx.translate(imageWidth/2,imageHeight/2); ctx.rotate(r); ctx.translate(-imageX,-imageY); ctx.translate(-imageWidth/2,-imageHeight/2); ctx.drawImage(img,0,0,img.width,img.height,imageX,imageY,imageWidth,imageHeight); ctx.restore(); if(withAnchors){ drawDragAnchor(imageX,imageY); drawDragAnchor(imageRight,imageY); drawDragAnchor(imageRight,imageBottom); drawDragAnchor(imageX,imageBottom); } if(withBorders){ ctx.save(); ctx.translate(imageX,imageY); ctx.translate(imageWidth/2,imageHeight/2); ctx.rotate(r); ctx.translate(-imageX,-imageY); ctx.translate(-imageWidth/2,-imageHeight/2); ctx.beginPath(); ctx.moveTo(imageX,imageY); ctx.lineTo(imageRight,imageY); ctx.lineTo(imageRight,imageBottom); ctx.lineTo(imageX,imageBottom); ctx.closePath(); ctx.stroke(); ctx.restore(); } ctx.fillStyle="blue"; ctx.save(); ctx.translate(imageX,imageY); ctx.translate(imageWidth/2,imageHeight/2); ctx.rotate(r); ctx.translate(-imageX,-imageY); ctx.translate(-imageWidth/2,-imageHeight/2); ctx.beginPath(); ctx.moveTo(imageRight+15,imageY-10); ctx.lineTo(imageRight+45,imageY-10); ctx.lineTo(imageRight+45,imageY+20); ctx.lineTo(imageRight+15,imageY+20); ctx.fill(); ctx.closePath(); ctx.restore(); } function drawDragAnchor(x,y){ ctx.save(); ctx.translate(imageX,imageY); ctx.translate(imageWidth/2,imageHeight/2); ctx.rotate(r); ctx.translate(-imageX,-imageY); ctx.translate(-imageWidth/2,-imageHeight/2); ctx.beginPath(); ctx.arc(x,y,resizerRadius,0,pi2,false); ctx.closePath(); ctx.fill(); ctx.restore(); } function anchorHitTest(x,y){ var dx,dy; dx=x-imageX; dy=y-imageY; if(dx*dx+dy*dy<=rr){ return(0); } // top-right dx=x-imageRight; dy=y-imageY; if(dx*dx+dy*dy<=rr){ return(1); } // bottom-right dx=x-imageRight; dy=y-imageBottom; if(dx*dx+dy*dy<=rr){ return(2); } // bottom-left dx=x-imageX; dy=y-imageBottom; if(dx*dx+dy*dy<=rr){ return(3); } return(-1); } function hitImage(x,y){ return(x>imageX && x<imageX+imageWidth && y>imageY && y<imageY+imageHeight); } function handleMouseDown(e){ startX=parseInt(e.clientX-offsetX); startY=parseInt(e.clientY-offsetY); draggingResizer= anchorHitTest(startX,startY); draggingImage= draggingResizer<0 && hitImage(startX,startY); doRotation = draggingResizer<0 && !draggingImage && ctx.isPointInPath(startX,startY); } function handleMouseUp(e){ draggingResizer=-1; draggingImage=false; doRotation=false; draw(true,false); } function handleMouseOut(e){ handleMouseUp(e); } function handleMouseMove(e){ mouseX=parseInt(e.clientX-offsetX); mouseY=parseInt(e.clientY-offsetY); if(draggingResizer>-1){ switch(draggingResizer){ case 0: //top-left imageX=mouseX; imageWidth=imageRight-mouseX; imageY=mouseY; imageHeight=imageBottom-mouseY; break; case 1: //top-right imageY=mouseY; imageWidth=mouseX-imageX; imageHeight=imageBottom-mouseY; break; case 2: //bottom-right imageWidth=mouseX-imageX; imageHeight=mouseY-imageY; break; case 3: //bottom-left imageX=mouseX; imageWidth=imageRight-mouseX; imageHeight=mouseY-imageY; break; } if(imageWidth<25) imageWidth=25; if(imageHeight<25) imageHeight=25; imageRight=imageX+imageWidth; imageBottom=imageY+imageHeight; draw(true,true); }else if(draggingImage){ imageClick=false; var dx=mouseX-startX; var dy=mouseY-startY; imageX+=dx; imageY+=dy; imageRight+=dx; imageBottom+=dy; startX=mouseX; startY=mouseY; draw(false,true); }else if(doRotation){ var dx=mouseX-imageX; var dy=mouseY-imageY; r=Math.atan2(dy,dx); draw(false,true); } } $("#canvas").mousedown(function(e){handleMouseDown(e);}); $("#canvas").mousemove(function(e){handleMouseMove(e);}); $("#canvas").mouseup(function(e){handleMouseUp(e);}); $("#canvas").mouseout(function(e){handleMouseOut(e);}); }); </script> </head> <body> <canvas id="canvas" width=800 height=500></canvas> </body> </html>

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  • position of options in HTML select element

    - by frenchie
    I have a element that contains options. The element is 150px wide but some of the options are wider. So when rendering, the browser shows the overflow to the right. How can I make the options list overflow to the left? JSFiddle Thanks. <select id="MySelect"> <option value="60" selected="selected"></option><option value="-60">(UTC-01:00) Azores</option> <option value="-60">(UTC-01:00) Cape Verde Is.</option><option value="0">(UTC) Casablanca</option> <option value="0">(UTC) Dublin, Edinburgh, Lisbon, London</option><option value="0">(UTC) Monrovia, Reykjavik</option> <option value="60">(UTC+01:00) Belgrade, Bratislava, Budapest, Ljubljana, Prague</option> <option value="60">(UTC+01:00) Brussels, Copenhagen, Madrid, Paris</option> <option value="60">(UTC+01:00) Sarajevo, Skopje, Warsaw, Zagreb</option> <option value="60">(UTC+01:00) West Central Africa</option> <option value="120">(UTC+01:00) Windhoek</option> </select>?????????????????????????????????????????????? ?#MySelect{ margin-top:20px; margin-left:200px; width:150px;}

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  • geting information from Treeview with HierarchicalDataTemplate

    - by lina
    Good day! I have such a template: <common:HierarchicalDataTemplate x:Key="my2ndPlusHierarchicalTemplate" ItemsSource="{Binding Children}"> <StackPanel Margin="0,2,5,2" Orientation="Vertical" Grid.Column="2"> <CheckBox IsTabStop="False" IsChecked="False" Click="ItemCheckbox_Click" Grid.Column="1" /> <TextBlock Text="{Binding Name}" FontSize="16" Foreground="#FF100101" HorizontalAlignment="Left" FontFamily="Verdana" FontWeight="Bold" /> <TextBlock Text="{Binding Description}" FontFamily="Verdana" FontSize="10" HorizontalAlignment="Left" Foreground="#FFA09A9A" FontStyle="Italic" /> <TextBox Width="100" Grid.Column="4" Height="24" LostFocus="TextBox_LostFocus" Name="tbNumber"></TextBox> </StackPanel> </common:HierarchicalDataTemplate> for a Treeview <controls:TreeView x:Name="tvServices" ItemTemplate="{StaticResource myHierarchicalTemplate}" ItemContainerStyle="{StaticResource expandedTreeViewItemStyle}" Grid.Column="1" Grid.Row="2" Grid.ColumnSpan="3" BorderBrush="#FFC1BCBC" FontFamily="Verdana" FontSize="14"> </controls:TreeView> I want to know the Name property of each TextBox in Treeview to make validation of each textbox such as: private void TextBox_LostFocus(object sender, RoutedEventArgs e) { tbNumber.ClearValidationError(); if ((!tbNumber.Text.IsZakazNumberValid()) && (tbNumber.Text != "")) { tbNumber.SetValidation(MyStrings.NumberError); tbNumber.RaiseValidationError(); isValid = false; } else { isValid = true; } } and I wnat to see what check boxes were checked how can I do it?

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  • Global and local variables in my script

    - by Acorn
    I'm starting out learning javascript, and tried to write a little script that would make a grid of divs on a page. Here's the script: var tileWidth=50; var tileHeight=100; var leftPos=10; var topPos=10; var columns=10; var rows=10; var spacing=5; $('document').ready(function() { placeTiles(); }); function makeRow() { for (var i=0; i<columns; i++) { $('#canvas').append('<div class="tile" style="left:' + leftPos + 'px;top:' + topPos + 'px;"></div>'); var leftPos = leftPos + tileWidth + spacing; } } function placeTiles() { for (var i=0; i<rows; i++) { makeRow(); var topPos = topPos + tileHeight + spacing; } } At the moment, 100 <div>s get created, all with a top position of 10px and a left position of undefined (for the first <div> in the row) or NaN. What should I be doing differently? Why can't makerow() see my global leftPos variable (and all the other variables for that matter)? Thanks.

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  • DVD ROM not working only in windows?

    - by Behrooz A
    I have an Asus N53SV laptop, My DVD rom doesn't read any type of DVD in windows , but I just installed windows 7 from a bootable DVD , I think this problem occurred after I tried to change my partitioning with paragon partition magic , I was trying to shrink , join and so , after that my windows showed an error that windows cannot find [weird address] on hard disk every time on starts. windows itself says the DVD drive works correctly and driver is working properly, but no DVD or CD can be read , note that the DVD I'm trying to read is the same DVD which I used to install windows some minutes ago. I don't know what's the problem

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  • ASP: Assigning CSS to dynamically created Label in C#

    - by Tucker
    I'm trying to figure out how to apply CSS to a Label created in C#. Everything compiles and runs, it just doesn't seem to be applying the CSS. The CSS is in the file linked to in the site master page. Everything else in the CSS file is being applied as it should be. Codebehind: ... Label label = new Label(); SqlCommand command = new SqlCommand("SELECT Q_Text FROM HRA.dbo.Questions WHERE QID = 1"); command.Connection = connection; reader = command.ExecuteReader(); reader.Read(); label.Text = reader["Q_Text"].ToString(); label.ID = "rblabel"; label.CssClass = "rblabel"; reader.Close(); ... ASP: <asp:Content runat="server" ID="BodyContent" ContentPlaceHolderID="MainContent"> <asp:PlaceHolder ID="holder" runat="server"> </asp:PlaceHolder> </asp:Content> CSS: .rblabel { text-align:left; padding-left: 2em; font-size: 4em; }

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  • Strange layout behaviour

    - by andrii
    I am a little bit confused. Here is an small web page. There are two main div-s: top and mainBlock. First contain image. The problem is that firebug shows that div#top's height is equal to 0 and because of that the next div mainBlock moves up. If I would delete this peace of code: div#logo{ float: left; } everything will start working fine and div#mainBlock will be below the div#top. Could you, please, explain me how it works and how to avoid this in proper way? Here is my code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/> <title>Paralab - Website &amp; interface design, web apps development, usability</title> <style text="text/css"> html, body{ } div#logo{ float: left; } #top{ width: 100%; } #mainBlock{ width:100%; } </style> </head> <body> <div id="top"> <div id="logo"> <img alt="logo" src="img/logo.png" /> </div> </div> <div id="mainBlock"> Contact Us </div> </body> </html>

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  • How to append \line into RTF using RichTextBox control

    - by Steve Sheldon
    When using the Microsoft RichTextBox control it is possible to add new lines like this... richtextbox.AppendText(System.Environment.NewLine); // appends \r\n However, if you now view the generated rtf the \r\n characters are converted to \par not \line How do I insert a \line control code into the generated RTF? What does't work: Token Replacement Hacks like inserting a token at the end of the string and then replacing it after the fact, so something like this: string text = "my text"; text = text.Replace("||" "|"); // replace any '|' chars with a double '||' so they aren't confused in the output. text = text.Replace("\r\n", "_|0|_"); // replace \r\n with a placeholder of |0| richtextbox.AppendText(text); string rtf = richtextbox.Rtf; rtf.Replace("_|0|_", "\\line"); // replace placeholder with \line rtf.Replace("||", "|"); // set back any || chars to | This almost worked, it breaks down if you have to support right to left text as the right to left control sequence always ends up in the middle of the placeholder. Sending Key Messages public void AppendNewLine() { Keys[] keys = new Keys[] {Keys.Shift, Keys.Return}; SendKeys(keys); } private void SendKeys(Keys[] keys) { foreach(Keys key in keys) { SendKeyDown(key); } } private void SendKeyDown(Keys key) { user32.SendMessage(this.Handle, Messages.WM_KEYDOWN, (int)key, 0); } private void SendKeyUp(Keys key) { user32.SendMessage(this.Handle, Messages.WM_KEYUP, (int)key, 0); } This also ends up being converted to a \par Is there a way to post a messaged directly to the msftedit control to insert a control character? I am totally stumped, any ideas guys? Thanks for your help!

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  • iPhone TabbarController Switch Transition

    - by user269737
    I've implemented gestures (touchBegan-moved-ended) in order to allow for swiping through my tabs. It works. I'd like to add a slide-from-left and slide-from-right transition. It would be better if it could be part of the gesture if statement which tells me if the swipe is towards the right of left. Since I determine which tab is displayed from that, I could show that specific transition along with the new tab. So my question is this: what's the simplest way to simplement a slide transition at a specific instance. I don't want it to be for the whole tabbarcontrol since this is specifically for the swiping. Thanks for the help, much appreciated. For clarification purposes, this is snippet shows how I'm switching tabs: if(abs(diffx / diffy) > 2.5 && abs(diffx) > HORIZ_SWIPE_DRAG_MIN) { // It appears to be a swipe. if(isProcessingListMove) { // ignore move, we're currently processing the swipe return; } if (mystartTouchPosition.x < currentTouchPosition.x) { isProcessingListMove = YES; self.tabBarController.selectedViewController = [self.tabBarController.viewControllers objectAtIndex:0]; return; } else { isProcessingListMove = YES; self.tabBarController.selectedViewController = [self.tabBarController.viewControllers objectAtIndex:1 ]; return; }

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  • How to insert and reterive key from registry editor

    - by deepa
    Hi.. I am new to cryptography.. i have to develop project based on cryptography..In part of my project I have to insert a key to the registry and afterwards i have to reterive the same key for decryption.. i done until getting the path of the registry .. Here i given my code.. import java.io.IOException; import java.io.InputStream; import java.io.StringWriter; public static final String readRegistry(String location, String key) { try { // Run reg query, then read output with StreamReader (internal class) Process process = Runtime.getRuntime().exec("reg query " + '"' + location + "\" /v " + key); StreamReader reader = new StreamReader(process.getInputStream()); reader.start(); process.waitFor(); reader.join(); String output = reader.getResult(); // Output has the following format: // \n<Version information>\n\n<key>\t<registry type>\t<value> if (!output.contains("\t")) { return null; } // Parse out the value String[] parsed = output.split("\t"); return parsed[parsed.length - 1]; } catch (Exception e) { return null; } } static class StreamReader extends Thread { private InputStream is; private StringWriter sw = new StringWriter(); ; public StreamReader(InputStream is) { this.is = is; } public void run() { try { int c; while ((c = is.read()) != -1) { System.out.println("Reading" + c); sw.write(c); } } catch (IOException e) { System.out.println("Exception in run() " + e); } } public String getResult() { System.out.println("Content " + sw.toString()); return sw.toString(); } } public static boolean addValue(String key, String valName, String val) { try { // Run reg query, then read output with StreamReader (internal class) Process process = Runtime.getRuntime().exec("reg add \"" + key + "\" /v \"" + valName + "\" /d \"\\\"" + val + "\\\"\" /f"); StreamReader reader = new StreamReader(process.getInputStream()); reader.start(); process.waitFor(); reader.join(); String output = reader.getResult(); System.out.println("Processing........ggggggggggggggggggggg." + output); // Output has the following format: // \n&lt;Version information&gt;\n\n&lt;key&gt;\t&lt;registry type&gt;\t&lt;value&gt; return output.contains("The operation completed successfully"); } catch (Exception e) { System.out.println("Exception in addValue() " + e); } return false; } public static void main(String[] args) { // Sample usage JAXRDeleteConcept hc = new JAXRDeleteConcept(); System.out.println("Before Insertion"); if (JAXRDeleteConcept.addValue("HKEY_CURRENT_USER\\Software\\Microsoft\\Windows\\CurrentVersion\\Explorer\\ComDlg32\\OpenSaveMRU", "REG_SZ", "Muthus")) { System.out.println("Inserted Successfully"); } String value = JAXRDeleteConcept.readRegistry("HKEY_CURRENT_USER\\Software\\Microsoft\\Windows\\CurrentVersion\\Explorer\\ComDlg32\\OpenSaveMRU" , "Project_Key"); System.out.println(value); } } But i dont know how to insert a key in a registry and read the particular key which i inserted..Please help me.. Thanks in advance..

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  • Cross-Forest Trust

    - by cdalley
    I am looking at testing a cross-domain trust we can have two domain controllers (with different forests and domain names) setup so we can move everyone onto the new domain. We do NOT run exchange on site and we do not have any links to O365 to AD currently. Onto the problem: I have setup two DCs in a Virtual Machine: They are on the same network 192.168.0.* The Windows 2003 server: Name: OLDSRVR "Clone" of our current Domain Controller IP: 192.168.0.1 Domain: internal.test.com The Windows 2012 server: Name: ADCTEST01 Brand new domain setup from scratch separate to internal.test.com Domain: internal.test2.com IP: 192.168.0.2 OLDSRVR can only see ADCTEST if it has dynamic IP set. If I set a static IP it cannot see it. If I try using the dynamic IP and try to join it gets to the end then complains "??The trust relationship between this workstation and the primary domain failed" Any ideas?

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  • Navigating through code with keyboard shortcuts

    - by MarceloRamires
    I'm starting to feel the need to run fastly through code with keyboard shortcuts, to arrive faster where I want to make any changes (avoiding use of mouse or long times holding [up], [left], [right] and [down]). I'm already using some: [home] - first position in current line [end] - last position in current line [ctrl] + [home] - first line of the entire code [ctrl] + [end] - last line of the entire code [pageup] - same vertical position, one screen above [pagedown] - same vertical position, one screen below [ctrl] + [pageup] - first line in current screen [ctrl] + [end] - last line in current screen [ctrl] + [left/right] - skipping word per word What have you got ? I use Visual Studio. (but I'm open to any answer, as I maybe can use others soon) obs: I've searched through stackoverflow and didn't find a nice question with this content, nor a list of keyboard code searching. If it's repeated, I'm sorry for not finding it, I'm here in my best intentions. This question is NOT about any shortcuts, and not only about visual studio, it's about running through code with shortcuts. Answers that suit the question so far: [Ctrl] + [-] - jumps to last cursor position [Ctrl] + [F3] - Jumps to next occurance of the word the curson is in [Shift] + [F3] - Same as the above, backwards. [F12] - Goes to definition of method/variable the cursor is in [Ctrl] + [ ] ] - Jumps to matching brace and select I'll ad more as there are answers.

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  • EC2 server in VPC stops responding after joining domain

    - by Geoff
    We have a EC2 Windows Server set up and running in our VPC, connected to our network via a Juniper 5GT. This is working well, with the tunnel up and stable. If I then join the server to our local domain, it appears to work - I can then log on using domain credentials, and use domain accounts when applying security to folders etc. After I log out, if I give it around an hour, the box becomes unresponsive. I can't ping it, although a tracert goes all the way barring the last hop - so the tunnel is ok. I can't RDP into it. If I reboot it, then it works for a while before doing the same thing. Un-joining it from the domain fixes the problem, and it stays up and stable. The event logs don't show anything obvious, at least to me. Any ideas?

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  • Position absolute for rounded corners and problems in IE6

    - by danit
    Im using position absolute to give the top left corner of a DIV a rounded corner. HTML: <div id="MyDiv"> Some content <div class="topLeft">&nbsp</div> </div> CSS: #MyDiv { position: relative; padding: 12px; background: #fff url('graident.png') repeat-x top left; } .topLeft { position: absolute; top: 0; right: 0; width: 10px; height: 10px; background: transparent url('corner.png') no-repeat top right; } This works fine in all browsers expcept IE6. In IE6 the corner.png image seems to be about 1px out at the top corner, essentially not top: 0; and right: 0; but more like top: 1px; right: 1px; Can anyone explain why this might be happening only in IE6?

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  • HTML + CSS: fixed background image and body width/min-width (including fiddle)

    - by insertusernamehere
    So, here is my problem. I'm kinda stuck at the moment. I have a huge background image and content in the middle with those attributes: content is centered with margin auto and has a fixed width the content is related to the image (like the image is continued within the content) this relation is only horizontally (vertically scrolling moves everything around) This works actually fine (I'm only talking desktop, not mobile here :) ) with a position fixed on the huge background image. The problem that occurs is the following: When I resize the window to "smaller than the content" the background image gets it width from the body instead of the viewport. So the relation between content and image gets lost. Now I have this little JavaScript which does the trick, but this is of course some overhead I want to avoid: $(window).resize(function(){ img.css('left', (body.width() - img.width()) / 2 ); }); This works with a fixed positioned image, but can get a litty jumpy while calculating. I also tried things like that: <div id="test" style=" position: absolute; z-index: 0; top: 0; left: 0; width: 100%: height: 100%; background: transparent url(content/dummy/brand_backgroud_1600_1.jpg) no-repeat fixed center top; "></div> But this gets me back to my problem described. Is there any "script-less", elegant solution for this problem? UPDATE: now with Fiddle The one I'm trying to solve: http://jsfiddle.net/insertusernamehere/wPmrm/ The one with Javascript that works: http://jsfiddle.net/insertusernamehere/j5E8z/ NOTE The image size is always fixed. The image never gets scaled by the browser. In the JavaScript example it get's blown. So don't care about the size.

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  • determine page UI culture throgh javascript

    - by mj-y
    I have two div tags in my html code as shown below. I want to change their float property depending on page UI culture ( Ui culture is en-US or fa-IR) ... I think I can use java script to do so. but I don't know how can I get the UI Culture through Javascript. I want a code in if condition to determine the Ui culture ... thx in advance for your help... <div id="zone1" style="float: left;"><img alt="" src="~/IconArrow.png" /> &nbsp;</div> <div id="zone2" style="float: left;"><img alt="" src="~/IconHome.png" /></div> <script type="text/javascript"> if(/* ui culture is fa-IR*/) { document.getElementById("zone1").style.float = "right"; document.getElementById("zone2").style.float = "right"; } </script>

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  • Pecking order of pigeons?

    - by sc_ray
    I was going though problems on graph theory posted by Prof. Ericksson from my alma-mater and came across this rather unique question about pigeons and their innate tendency to form pecking orders. The question goes as follows: Whenever groups of pigeons gather, they instinctively establish a pecking order. For any pair of pigeons, one pigeon always pecks the other, driving it away from food or potential mates. The same pair of pigeons always chooses the same pecking order, even after years of separation, no matter what other pigeons are around. Surprisingly, the overall pecking order can contain cycles—for example, pigeon A pecks pigeon B, which pecks pigeon C, which pecks pigeon A. Prove that any finite set of pigeons can be arranged in a row from left to right so that every pigeon pecks the pigeon immediately to its left. Since this is a question on Graph theory, the first things that crossed my mind that is this just asking for a topological sort of a graphs of relationships(relationships being the pecking order). What made this a little more complex was the fact that there can be cyclic relationships between the pigeons. If we have a cyclic dependency as follows: A-B-C-A where A pecks on B,B pecks on C and C goes back and pecks on A If we represent it in the way suggested by the problem, we have something as follows: C B A But the above given row ordering does not factor in the pecking order between C and A. I had another idea of solving it by mathematical induction where the base case is for two pigeons arranged according to their pecking order, assuming the pecking order arrangement is valid for n pigeons and then proving it to be true for n+1 pigeons. I am not sure if I am going down the wrong track here. Some insights into how I should be analyzing this problem will be helpful. Thanks

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  • Using Mergesort to calculate number of inversions in C++

    - by Brown
    void MergeSort(int A[], int n, int B[], int C[]) { if(n > 1) { Copy(A,0,floor(n/2),B,0,floor(n/2)); Copy(A,floor(n/2),n-1,C,0,floor(n/2)-1); MergeSort(B,floor(n/2),B,C); MergeSort(C,floor(n/2),B,C); Merge(A,B,0,floor(n/2),C,0,floor(n/2)-1); } }; void Copy(int A[], int startIndexA, int endIndexA, int B[], int startIndexB, int endIndexB) { while(startIndexA < endIndexA && startIndexB < endIndexB) { B[startIndexB]=A[startIndexA]; startIndexA++; startIndexB++; } }; void Merge(int A[], int B[],int leftp, int rightp, int C[], int leftq, int rightq) //Here each sub array (B and C) have both left and right indices variables (B is an array with p elements and C is an element with q elements) { int i=0; int j=0; int k=0; while(i < rightp && j < rightq) { if(B[i] <=C[j]) { A[k]=B[i]; i++; } else { A[k]=C[j]; j++; inversions+=(rightp-leftp); //when placing an element from the right array, the number of inversions is the number of elements still in the left sub array. } k++; } if(i=rightp) Copy(A,k,rightp+rightq,C,j,rightq); else Copy(A,k,rightp+rightq,B,i,rightp); } I am specifically confused on the effect of the second 'B' and 'C' arguments in the MergeSort calls. I need them in there so I have access to them for Copy and and Merge, but

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  • how to speed up the code??

    - by kaushik
    i have very huge code about 600 lines plus. cant post the whole thing here. but a particular code snippet is taking so much time,leading to problems. here i post that part of code please tell me what to do speed up the processing.. please suggest the part which may be the reason and measure to improve them if this small part of code is understandable. using_data={} def join_cost(a , b): global using_data #print a #print b save_a=[] save_b=[] print 1 #for i in range(len(m)): #if str(m[i][0])==str(a): save_a=database_index[a] #for i in range(len(m)): # if str(m[i][0])==str(b): #print 'save_a',save_a #print 'save_b',save_b print 2 save_b=database_index[b] using_data[save_a[0]]=save_a s=str(save_a[1]).replace('phone','text') s=str(s)+'.pm' p=os.path.join("c:/begpython/wavnk/",s) x=open(p , 'r') print 3 for i in range(6): x.readline() k2='a' j=0 o=[] while k2 is not '': k2=x.readline() k2=k2.rstrip('\n') oj=k2.split(' ') o=o+[oj] #print o[j] j=j+1 #print j #print o[2][0] temp=long(1232332) end_time=save_a[4] #print end_time k=(j-1) for i in range(k): diff=float(o[i][0])-float(end_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i #print pm_row #print temp #print o[pm_row] #pm_row=3 q=[] print 4 l=str(p).replace('.pm','.mcep') z=open(l ,'r') for i in range(pm_row): z.readline() k3=z.readline() k3=k3.rstrip('\n') q=k3.split(' ') #print q print 5 s=str(save_b[1]).replace('phone','text') s=str(s)+'.pm' p=os.path.join("c:/begpython/wavnk/",s) x=open(p , 'r') for i in range(6): x.readline() k2='a' j=0 o=[] while k2 is not '': k2=x.readline() k2=k2.rstrip('\n') oj=k2.split(' ') o=o+[oj] #print o[j] j=j+1 #print j #print o[2][0] temp=long(1232332) strt_time=save_b[3] #print strt_time k=(j-1) for i in range(k): diff=float(o[i][0])-float(strt_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i #print pm_row #print temp #print o[pm_row] #pm_row=3 w=[] l=str(p).replace('.pm','.mcep') z=open(l ,'r') for i in range(pm_row): z.readline() k3=z.readline() k3=k3.rstrip('\n') w=k3.split(' ') #print w cost=0 for i in range(12): #print q[i] #print w[i] h=float(q[i])-float(w[i]) cost=cost+math.pow(h,2) j_cost=math.sqrt(cost) #print cost return j_cost def target_cost(a , b): a=(b+1)*3 b=(a+1)*2 t_cost=(a+b)*5/2 return t_cost r1='shht:ra_77' r2='grx_18' g=[] nodes=[] nodes=nodes+[[r1]] for i in range(len(y_in_db_format)): g=y_in_db_format[i] #print g #print g[0] g.remove(str(g[0])) nodes=nodes+[g] nodes=nodes+[[r2]] print nodes print "lenght of nodes",len(nodes) lists=[] #lists=lists+[r1] for i in range(len(nodes)): for j in range(len(nodes[i])): lists=lists+[nodes[i][j]] #lists=lists+[r2] print lists distance={} for i in range(len(lists)): if i==0: distance[str(lists[i])]=0 else: distance[str(lists[i])]=long(123231223) #print distance group_dist=[] infinity=long(123232323) for i in range(len(nodes)): distances=[] for j in range(len(nodes[i])): #distances=[] if i==0: distances=distances+[[nodes[i][j], 0]] else: distances=distances+[[nodes[i][j],infinity]] group_dist=group_dist+[distances] #print distances print "group_distances",group_dist #print "check",group_dist[0][0][1] #costs={} #for i in range(len(lists)): #if i==0: # costs[str(lists[i])]=1 #else: # costs[str(lists[i])]=get_selfcost(lists[i]) path=[] for i in range(len(nodes)): mini=[] if i!=(len(nodes)-1): #temp=long(123234324) #Now calculate the cost between the current node and each of its neighbour for k in range(len(nodes[(i+1)])): for j in range(len(nodes[i])): current=nodes[i][j] #print "current_node",current j_distance=join_cost( current , nodes[i+1][k]) #t_distance=target_cost( current , nodes[i+1][k]) t_distance=34 #print distance #print "distance between current and neighbours",distance total_distance=(.5*(float(group_dist[i][j][1])+float(j_distance))+.5*(float(t_distance))) #print "total distance between the intial_nodes and current neighbour",total_distance if int(group_dist[i+1][k][1]) > int(total_distance): group_dist[i+1][k][1]=total_distance #print "updated distance",group_dist[i+1][k][1] a=current #print "the neighbour",nodes[i+1][k],"updated the value",a mini=mini+[[str(nodes[i+1][k]),a]] print mini

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  • access settings from whole jquery component

    - by Pacuraru Daniel
    I am trying to develop a jquery component for dialog modals and i dont know how to access the settings from all component functions. I need to access settings,zIndex from open function and it seems to not work. (function($) { var methods = { init: function(options) { var defaults = { bgClass: "fancy-dialog-bg", bgShow: null, zIndex: 100, show: null }; var settings = $.extend(defaults, options); return this.each(function() { var obj = $(this).hide().css("position", "fixed").css("z-index", settings.zIndex).css("left", "300px").css("top", "200px"); }); }, open: function() { // alert(settings.zIndex); not working var tes = $("<div></div>").css("backgroundColor", "#f00").css("position", "fixed").css("z-index", "99").css("width", "50%").css("height", "100%").css("left", "0").css("top", "0"); $('body').append(tes); var obj = $(this); obj.show(); }, close: function() { var obj = $(this); $("#fancy-dialog-bg-" + obj.attr('id')).remove(); obj.hide(); } }; $.fn.fancyDialog = function(method) { if (methods[method]) { return methods[method].apply(this, Array.prototype.slice.call(arguments, 1)); } else if (typeof method === 'object' || !method) { return methods.init.apply(this, arguments); } else { $.error('Method ' + method + ' does not exist.'); } }; })(jQuery);

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  • Got problem when uploading the html into the webview in iphone sdk.

    - by Monish Kumar
    Hi Guy's NSString* appendString=@""; appendString = [appendString stringByAppendingString:@"<body>"]; appendString =[appendString stringByAppendingString:@"<table background='footer.png' width='320' height='45' style='background-repeat:no-repeat'>"]; appendString =[appendString stringByAppendingString:@"<tr>"]; appendString =[appendString stringByAppendingString:@"<td align='left' width='57' height='31' style='padding: 6px 0 0 0' ><a href='/map/'><img src='details_Back.png'/></a></td>"]; appendString =[appendString stringByAppendingString:@"<td align='left' valign='middle' style='padding: 0 0 0 65px; font-family:Helvetica; font-size:21px ; font-weight:bold ; color:#FFF'>Details</td>"]; appendString =[appendString stringByAppendingString:@"</tr>"]; appendString =[appendString stringByAppendingString:@"</table>"]; appendString =[appendString stringByAppendingString:@"<br>"]; returnString = [returnString stringByReplacingOccurrencesOfString:@"<body>" withString:appendString]; printf("\n return string :%s",[returnString UTF8String]); [myWebView loadHTMLString:returnString baseURL:[NSURL URLWithString:@"http://abc.api.abcdefg.com/"]]; here in the above code the footer.png and details_back.png are the local images stored in my resource folder. Here the problem is I am gettin the background image from the server link I had passed to the webview as baseurl but the images footer.png and details_back.png which were stored in resource is not displayed. if I use the resource bundle as the baseurl then I am not displayed the background image from the server link. Can anyone please give me the suggestions to get rid of rid of this problem. thanks to all guy's, Monish.

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  • little java help....

    - by jona
    Hi I am doing some practice problems and trying to print a diagonal line like the example below. I have writen the program you see below and I honestly dont understand what I am doing wrong. I m a java beginner and I cant see how to find the error. Example ( If you only see a straight line of stars...then imagine it diagonally....from top left to bottom right) * * * * * code: class Diagonal{ public static void main(String args[]) { int row, col; for(row = 1; row < 6; row++) { for(col = 1; col <= row; col++) { if(col==row){ System.out.print("*"); } else{ System.out.print(""); } System.out.println(); } } } } I am trying to learn for loops because they really confuse me. Another practice is to print a similar diagonal line but this time from right to left. I cant do that without getting this right however :( I believe they will be pretty similar? Above my reasining is this: As long as the column # is the same as the row number the print the line or otherwise leave a blank....what's wrong with how i did it? THANK YOU!

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  • Why can't decimal numbers be represented exactly in binary?

    - by Barry Brown
    There have been several questions posted to SO about floating-point representation. For example, the decimal number 0.1 doesn't have an exact binary representation, so it's dangerous to use the == operator to compare it to another floating-point number. I understand the principles behind floating-point representation. What I don't understand is why, from a mathematical perspective, are the numbers to the right of the decimal point any more "special" that the ones to the left? For example, the number 61.0 has an exact binary representation because the integral portion of any number is always exact. But the number 6.10 is not exact. All I did was move the decimal one place and suddenly I've gone from Exactopia to Inexactville. Mathematically, there should be no intrinsic difference between the two numbers -- they're just numbers. By contrast, if I move the decimal one place in the other direction to produce the number 610, I'm still in Exactopia. I can keep going in that direction (6100, 610000000, 610000000000000) and they're still exact, exact, exact. But as soon as the decimal crosses some threshold, the numbers are no longer exact. What's going on? Edit: to clarify, I want to stay away from discussion about industry-standard representations, such as IEEE, and stick with what I believe is the mathematically "pure" way. In base 10, the positional values are: ... 1000 100 10 1 1/10 1/100 ... In binary, they would be: ... 8 4 2 1 1/2 1/4 1/8 ... There are also no arbitrary limits placed on these numbers. The positions increase indefinitely to the left and to the right.

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  • Lights off effect and jquery placement on wordpress

    - by Alexander Santiago
    I'm trying to implement a lights on/off on single posts of my wordpress theme. I know that I have to put this code on my css, which I did already: #the_lights{ background-color:#000; height:1px; width:1px; position:absolute; top:0; left:0; display:none; } #standout{ padding:5px; background-color:white; position:relative; z-index:1000; } Now this is the code that I'm having trouble with: function getHeight() { if ($.browser.msie) { var $temp = $("").css("position", "absolute") .css("left", "-10000px") .append($("body").html()); $("body").append($temp); var h = $temp.height(); $temp.remove(); return h; } return $("body").height(); } $(document).ready(function () { $("#the_lights").fadeTo(1, 0); $("#turnoff").click(function () { $("#the_lights").css("width", "100%"); $("#the_lights").css("height", getHeight() + "px"); $("#the_lights").css({‘display’: ‘block’ }); $("#the_lights").fadeTo("slow", 1); }); $("#soft").click(function () { $("#the_lights").css("width", "100%"); $("#the_lights").css("height", getHeight() + "px"); $("#the_lights").css("display", "block"); $("#the_lights").fadeTo("slow", 0.8); }); $("#turnon").click(function () { $("#the_lights").css("width", "1px"); $("#the_lights").css("height", "1px"); $("#the_lights").css("display", "block"); $("#the_lights").fadeTo("slow", 0); }); }); I think it's a jquery. Where do I place it and how do I call it's function? Been stuck on this thing for 6 hours now and any help would be greatly appreciated...

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