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  • Symfony2: validate an object that is not an entity

    - by Marronsuisse
    I am using CraueFormFlowBundle to have a multiple page form, and am trying to do some validation on some of the fields but can't figure out how to do this. The object that needs to be validated isn't an Entity, which is causing me trouble. I tried adding a collectionConstraint in the getDefaultOption function of my form type class, but this doesn't work as I get the "Expected argument of type array or Traversable and ArrayAccess" error. I tried with annotations in my object class, but they don't seem to be taken into account. Are annotations taken into account if the class isn't an entity? (i set enable_annotations to true) Anyway, what is the proper way to do this? Basically, I just want to validate that "age" is an integer... class PoemDataCollectorFormType extends AbstractType { public function buildForm(FormBuilder $builder, array $options) { switch ($options['flowStep']) { case 6: $builder->add('msgCategory', 'hidden', array( )); $builder->add('msgFIB','text', array( 'required' => false, )); $builder->add('age', 'integer', array( 'required' => false, )); break; } } public function getDefaultOptions(array $options) { $options = parent::getDefaultOptions($options); $options['flowStep'] = 1; $options['data_class'] = 'YOP\YourOwnPoetBundle\PoemBuilder\PoemDataCollector'; $options['intention'] = 'my_secret_key'; return $options; } } EDIT: add code, handle validation with annotations As Cyprian, I was pretty sure that using annotations should work, however it doesn't... Here is how I try: In my Controller: public function collectPoemDataAction() { $collector = $this->get('yop.poem.datacollector'); $flow = $this->get('yop.form.flow.poemDataCollector'); $flow->bind($collector); $form = $flow->createForm($collector); if ($flow->isValid($form)) { .... } } In my PoemDataCollector class, which is my data class (service yop.poem.datacollector): class PoemDataCollector { /** * @Assert\Type(type="integer", message="Age should be a number") */ private $age; } EDIT2: Here is the services implementation: The data class (PoemDataCollector) seems to be linked to the flow class and not to the form.. Is that why there is no validation? <service id="yop.poem.datacollector" class="YOP\YourOwnPoetBundle\PoemBuilder\PoemDataCollector"> </service> <service id="yop.form.poemDataCollector" class="YOP\YourOwnPoetBundle\Form\Type\PoemDataCollectorFormType"> <tag name="form.type" alias="poemDataCollector" /> </service> <service id="yop.form.flow.poemDataCollector" class="YOP\YourOwnPoetBundle\Form\PoemDataCollectorFlow" parent="craue.form.flow" scope="request"> <call method="setFormType"> <argument type="service" id="yop.form.poemDataCollector" /> </call> </service> How can I do the validation while respecting the craueFormFlowBundle guidelines? The guidelines state: Validation groups To validate the form data class a step-based validation group is passed to the form type. By default, if getName() of the form type returns registerUser, such a group is named flow_registerUser_step1 for the first step. Where should I state my constraint to use those validation groups..? I tried: YOP\YourOwnPoetBundle\PoemBuilder\Form\Type\PoemDataCollectorFormType: properties: name: - MinLength: { limit: 5, message: "Your name must have at least {{ limit }} characters.", groups: [flow_poemDataCollector_step1] } sex: - Type: type: integer message: Please input a number groups: [flow_poemDataCollector_step6] But it is not taken into acount.

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  • How do you do HTML form testing without real user input simulation ?

    - by justjoe
    this question is like this one, except it's for PHP testing via browser. It's about testing your form input. Right now, i have a form on a single page. It has 12 input boxes. Every time i test the form, i have write those 12 input boxes in my browser. i know it's not a specific coding question. This question is more about how to do direct testing on your form So, how to do recursive testing without consuming too much of your time ?

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  • scripting a google docs form submission

    - by justSteve
    I'm trying to create a bookmarklet that parses a page and sends the results to a googledocs spreadsheet via a form that I've defined. The relevent bit of the script is: var form = document.createElement("form"); form.action = "http://spreadsheets.google.com/formResponse?formkey=Fd0SHgwQ3YwSFd5UHZpM1QxMlNOdlE6MA&ifq"; form.method = "POST"; form.id="ss-form"; form.innerHTML = ["<input id='entry_0' name = 'entry.0.single' value = '" + orderDate + "'/>", "<input name = 'entry.2.single' value = '" + email + "'/>", "<input name = 'entry.3.single' value = '" + customerID + "'/>", ].join(""); form.submit(); alert(form.innerHTML); // returns: Nothing is being saved to the form via the bookmarklet - any way to capture google's response in my bookmarklet's code? (fwiw, i've injected jQuery via jQueryify) EDIT: Firebug's Net panel isn't hearing any of the activity triggered by the bookmarklet - How about i approach this from goolgle's viewform method instead of formresponse. The form i'm trying to submit is located at: http://spreadsheets.google.com/viewform?hl=en&formkey=dFd0SHgwQ3YwSFd5UHZpM1QxMlNOdlE6MA How can I go about injecting the script values into that form and then submitting that - again...via script within the bookmarklet that would have been triggered while on the page being parsed?

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  • JQuery Validation Plugin: Prevent validation issue on nested form

    - by Majid
    I have a form on which I use validation. This form has a section for photo upload. Initially this section contains six elements with the following code: <img class="photo_upload" src="image/app/photo_upload.jpg"> I have bound a function to the click event for the class of photo_upload. This function replaces the image with a minimal form with this code: Copy code <form onsubmit="startUploadImage();" target="control_target" enctype="multipart/form-data" method="post" action="index.php"> <input type="hidden" value="add_image" name="service"> <input type="hidden" value="1000000" name="MAX_FILE_SIZE"> <input type="file" size="10" name="photo" id="photo_file_upload"><br> <button onclick="javascript:cancel_photo_upload();return false;">Cancel</button> </form> So, essentially, after the image is clicked, I'd have a new form nested in my original, validated form. Now, when I use this new form and upload an image, I receive an error (repeated three times) saying: validator is undefined http://host.com/path/index.php Line 286 What is going on here? My guess is this Submit event bubbles up to the outer form As we have validation on that form, validation is triggered, Validation tries to find the form triggering it, Since we have not bound validation to the inner form it returns 'undefined' Now, is my assessment correct? Whether it is or not, how can I solve this issue?

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  • How to return id of a submitted form using Prototype?

    - by pstinnett
    I have a page that has several ajax submission forms. Each form has a dynamic id assigned to it when it's written to the page. Does anyone know if there is an easy way to return the id of the form that is being submitted? I'm basically looking to click "submit" and alert the id of the submitted form. From there I can use it in the ajax onSuccess function.

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  • Retrieving models from form with ModelMultipleChoiceField

    - by colinjameswebb
    I am having difficulties with forms, specifically ModelMultipleChoiceField. I've pieced together this code from various examples, but it sadly doesn't work. I would like to be able to: Search for some Works on work_search.html Display the results of the search, with checkboxes next to each result Select the Works I want, via the checkboxes After pressing Add, display which works were selected. I believe everything is okay except the last part. The page simply displays "works" :( Here is the code - sorry about the length. Models.py class Work(models.Model): title = models.CharField(max_length=200) artist = models.CharField(max_length=200) writers = models.CharField(max_length=200) def __unicode__(self): return self.title + ' - ' + self.artist forms.py class WorkSelectForm(forms.Form): def __init__(self, queryset, *args, **kwargs): super(WorkSelectForm, self).__init__(*args, **kwargs) self.fields['works'] = forms.ModelMultipleChoiceField(queryset=queryset, widget=forms.CheckboxSelectMultiple()) views.py def work_search(request): query = request.GET.get('q', '') if query: qset = ( Q(title__icontains=query) | Q(artist__icontains=query) | Q(writers__icontains=query) ) results = Work.objects.filter(qset).distinct() form = WorkSelectForm(results) return render_to_response("work_search.html", {"form": form, "query": query }) else: results = [] return render_to_response("work_search.html", {"query": query }) def add_works(request): #if request.method == POST: form = WorkSelectForm(request.POST) #if form.isvalid(): items = form.fields['works'].queryset return render_to_response("add_works.html", {"items":items}) work_search.html {% extends "base.html" %} {% block content %} <h1>Search</h1> <form action="." method="GET"> <label for="q">Search: </label> <input type="text" name="q" value="{{ query|escape }}"> <input type="submit" value="Search"> </form> {% if query %} <h2>Results for "{{ query|escape }}":</h2> <form action="add_works" method="post"> <ul> {% if form %} {{ form.as_ul }} {% endif %} </ul> <input type="submit" value="Add"> </form> {% endif %} {% endblock %} add_works.html {% extends "base.html" %} {% block content %} {% if items %} {% for item in items %} {{ item }} {% endfor %} {% else %} <p>Nothing selected</p> {% endif %} {% endblock %}

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  • How to redirect to the current page with form in php?

    - by garcon1986
    Hello, I tried to redirect to the current page with form in my php application. Now i have met a problem. <form name="myform" action="?page=matching" method="GET"> <input id="match_button" type="submit" name="button" value="button" onClick="func_load3()" /> </form> action="?page=matching" means the current page, because i use the single entry in my php application. With the code upon, When i click the button, it redirects to the homepage. And I tried to use: <form name="myform" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="GET"> but it still doesn't work. So i have to ask for help from you. Do you have any ideas about that? How to fix it? Thanks in advance.

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  • How can I retrieve the values of controls in the form that posted?

    - by Mike at KBS
    I know this has got to be the simplest-sounding question ever asked about ASP.Net but I'm baffled. I have a form wherein my visitor will enter name, address, etc. Then I am POSTing that form via the PostBackUrl property of my Submit button to another page, where the fields are supposed to be all re-formed into new hidden fields, then POSTed again to Paypal. My problem is I cannot get at the values entered by the visitor in the original page. Any time I put in "runat='server'", ASP.Net completely changes the ID of the control, making it impossible to figure out how to access. In the POSTed form I tried Request.Form["_txtFirstName"] and that turned up null. Then I tried ((TextBox)PreviousPage.FindControl("_txtFirstName")).Text and that was null, too. I've tried variations on those. I cannot figure out how I'm supposed to get at these controls. Why does this stuff need to be so difficult?

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  • How do I add descriptive text to form link .gif ?

    - by erynion
    I want to make the descriptive text around a form link also open the form. I want to make it so you can click on "Some Text Here" (below) and open the form on somesomite.com just as if you clicked on the image below this text (somebut.gif, below) <DIV style="position: absolute; top:10px; right:10px; width:70px; height:25px"> <font color="white"><b>Some Text Here<b></font> </div> <DIV style="position: absolute; top:50px; right:10px; width:70px; height:25px"> <form action="https://www.somesite.com/cgi-bin/something" method="post"> <input type="hidden" name="cmd" value="_s-xclick"> <input type="image" src="https://www.somesite.com/somebut.gif" border="0" name="submit"> <input type="hidden" name="encrypted" value="-----BEGIN PKCS7-----LONG_KEY...> </form> </div> Thanks

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  • Serializing form data with field names that have dots in them.

    - by Dave
    Does the serialize function in jQuery replace dots ('.') with underscores? For example, I have a form field such as: <input id="Project.name" name="Project.name" type="text"> When the form is POSTed, I'm serializing the form data and sending it to another PHP file to save. The dots seem to be converted to underscores. Is this normal behavior?

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  • Why is my form triggering the wrong controller action?

    - by COCoach
    This form has multiple submit buttons, when clicked, it calls a simple JavaScript function to change the value of a hidden input (function is called "setHidden". This worked before, after some other not relevant code, it has ceased working. Essentially, the action it is supposed to call is never called, instead it seems to default back to a previous URL. The Form: <form action="/League/RemoveOwner" method="post"> <input type="hidden" value="1007" name="lid"/> <input type="hidden" value="0" id="index" name="index"/> <input type="image" src="../../Resources/Images/Delete.png" height="12" alt="Remove Owner" title="Remove Owner" onclick="setHidden('index', '1031')"/></a> coach<br /> </form> The Controller: [HttpPost] public ActionResult RemoveOwner(int id, string index) { //yada return PartialView(); } When clicking the image, it should call the remove owner controller, instead it calls the "View" controller: public ActionResult View(int id) { //yada return View(); }

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  • How to send data after form has been validated using jQuery?

    - by Keith Donegan
    I have a simple email address sign up form as follows: <form action="" id="newsletterform" method="get"> <input type="text" name="email" class="required email" id="textnewsletter" /> <input type="submit" id="signup" /> </form> Here's what I want to be able to do: Validate the form to look for an empty string or a incorrectly filled out email address one the user clicks submit or hits enter. If one of the above happens (empty string etc), I would like to generate an error to let the user know. Then once the user fills out a correctly formed email address and hits submit (or enter) I want the form to send the email address to wherever I specify in the jQuery code and then generate a little "Thank you for signing up notice", all without reloading the browser. I have looked at too many tutorials and my eyes are pretty much aching at this stage, so please don't point me to any urls (I most likely have been there). If someone could provide a barebone outline of what to do It would be so much appreciated.

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  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    I have a form with multiple fields in it along with a image input field, just below the form i have a list to be displayed on every submit of this form... this has to be done without the use of DB.. I think this can be achieved by using session but its not working with me, as evrytime page gets refreshed and session gets recreated/reset.. Please help me in resolving this issue

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  • Can you set a form field value with PHP?

    - by dcp3450
    I use the $_GET function to pull a value with php from the url (http:..../index.html?variable=value), basic stuff. However, I need to use that value in my form. Typically, I would set <?php echo 'value="'.$variable.'"' ; ?> or something to that effect. However, I can't use php inside my form using the editor I'm working with. Can I set a value in the form without using PHP in my form? If so, how?

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  • how many dojo fliteringselect can I have on a form?

    - by Grant Collins
    I have a quick question How many dojo filteringselects can I have on a form? I have a form with 2 filteringselects on it, both getting data from different json datastores to populate the values. However only the first filteringselect is being populated, the other grabs no data. I am using Zend Framework and Zend_Dojo_Form to create the form elements for this. Many thanks. Ok looks like my code is broken somewhere then. The element that is failing in my form is: $location = new Zend_Dojo_Form_Element_FilteringSelect('location'); $location->setAutocomplete(true) ->setStoreId('countiesstore') ->setStoreType('dojo.data.ItemFileReadStore') ->setStoreParams(array('url' => $baseUrl.'/dojo/counties')) ->setAttrib('searchAttr', 'title') ->setRequired(true) ->removeDecorator('DtDdWrapper') ->removeDecorator('label') ->removeDecorator('HtmlTag') ->removeDecorator('Error'); When I go to http://localhost/dojo/counties I get the json file to read, but the element isn't populated with any data. Any ideas?

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  • Apache+LDAP auth on Ubuntu says "Can't contact LDAP server" while ldapsearch is perfect

    - by tw79
    Hi Gurus, I'm migrating from an existing apache+LDAP+mysql+php server to a new hardware platform. Old server is running Debian Lenny, which I have no config documentation available (was done by previous sysadmin); New server is running Ubuntu 10.04.2 LTS 32bit. After installing Apache and configured LDAP client on the new server, ldapsearch to the LDAP master (another dedicated server) returns results just fine. However, when using apache with https, logs complain that "Can't contact LDAP server". I'm authenticating using ldaps and can confirm that 636 port is open on the LDAP master. I can't understand why apache would fail while regular ldapsearch is working! Below is part of the virtualhost config: <Directory /> Options FollowSymLinks AllowOverride None #AuthLDAPEnabled on AuthType Basic AuthBasicProvider ldap AuthName "Private" AuthLDAPURL ldaps://master.ldap.organisation.com:636/ou=people,dc=organisation,dc=com?uid AuthzLDAPAuthoritative off require valid-user AddType application/x-httpd-php .php .phtml <IfModule mod_php4.c> php_flag magic_quotes_gpc Off php_flag track_vars On php_value include_path . </IfModule> </Directory> Any help/suggestion is very much appreciated!

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  • Connection Timed Out - Simple outbound Postfix for PHP Contact form

    - by BLaZuRE
    Alright, so I only got Postfix for a PHP contact form that will send email to a single . I only want it to send out mail to a single external address ([email protected]). I have domain sub1.sub2.domain.com. I installed Postfix out of the Ubuntu repo, with minimal config changes. I cannot get Postfix to send mail externally (though it succeeds for internal accounts, which is unnecessary). The email simply defers if I generate an email using PHP mail(). If I try to form my own in telnet, right after rcpt to: [email][email protected][/email], I get a postfix/smtpd[31606]: NOQUEUE: reject: RCPT from localhost[127.0.0.1]: 550 5.1.1 <[email protected]>: Recipient address rejected: example.com; from=<root@localhost> to=<[email protected]> proto=ESMTP helo=<localhost> when commenting out default_transport = error and relay_transport = error lines, I get the following: Jun 26 14:33:00 sub1 postfix/smtp[12191]: 2DA06F88206A: to=<[email protected]>, relay=none, delay=514, delays=409/0.01/105/0, dsn=4.4.1, status=deferred (connect to aspmx3.googlemail.com[74.125.127.27]:25: Connection timed out) Jun 26 14:36:36 sub1 postfix/smtp[12225]: connect to mta7.am0.yahoodns.net[98.139.175.224]:25: Connection timed out Jun 26 14:38:00 sub1 postfix/smtp[12225]: 22952F88208E: to=<[email protected]>, relay=none, delay=655, delays=550/0.01/105/0, dsn=4.4.1, status=deferred (connect to mta5.am0.yahoodns.net[67.195.168.230]:25: Connection timed out) My main.cf # See /usr/share/postfix/main.cf.dist for a commented, more complete version # Debian specific: Specifying a file name will cause the first # line of that file to be used as the name. The Debian default # is /etc/mailname. #myorigin = /etc/mailname smtpd_banner = $myhostname ESMTP $mail_name (Ubuntu) biff = no # appending .domain is the MUA's job. append_dot_mydomain = no # Uncomment the next line to generate "delayed mail" warnings #delay_warning_time = 4h readme_directory = no # TLS parameters smtpd_tls_cert_file=/etc/ssl/certs/ssl-cert-snakeoil.pem smtpd_tls_key_file=/etc/ssl/private/ssl-cert-snakeoil.key smtpd_use_tls=yes smtpd_tls_session_cache_database = btree:${data_directory}/smtpd_scache smtp_tls_session_cache_database = btree:${data_directory}/smtp_scache # See /usr/share/doc/postfix/TLS_README.gz in the postfix-doc package for # information on enabling SSL in the smtp client. myhostname = sub1.sub2.domain.com alias_maps = hash:/etc/aliases alias_database = hash:/etc/aliases myorigin = /etc/mailname mydestination = sub1.sub2.domain.com, localhost relayhost = mynetworks = 127.0.0.0/8 [::ffff:127.0.0.0]/104 [::1]/128 mailbox_size_limit = 0 recipient_delimiter = + inet_interfaces = all default_transport = error relay_transport = error Also, a dig sub1.sub2.domain.com MX returns: ; <<>> DiG 9.7.0-P1 <<>> sub1.sub2.domain.com MX ;; global options: +cmd ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 4853 ;; flags: qr aa rd ra; QUERY: 1, ANSWER: 0, AUTHORITY: 1, ADDITIONAL: 0 ;; QUESTION SECTION: ;sub1.sub2.domain.com. IN MX ;; AUTHORITY SECTION: sub2.domain.com. 600 IN SOA sub2.domain.com. sub5.domain.com. 2012062915 7200 600 1209600 600 ;; Query time: 0 msec ;; SERVER: x.x.x.x#53(x.x.x.x) ;; WHEN: Fri Jun 29 16:35:00 2012 ;; MSG SIZE rcvd: 84 lsof -i returns empty netstat -t -a | grep LISTEN returns tcp 0 0 localhost:mysql *:* LISTEN tcp 0 0 *:ftp *:* LISTEN tcp 0 0 *:ssh *:* LISTEN tcp 0 0 localhost:ipp *:* LISTEN tcp 0 0 *:smtp *:* LISTEN tcp6 0 0 [::]:netbios-ssn [::]:* LISTEN tcp6 0 0 [::]:www [::]:* LISTEN tcp6 0 0 [::]:ssh [::]:* LISTEN tcp6 0 0 localhost:ipp [::]:* LISTEN tcp6 0 0 [::]:microsoft-ds [::]:* LISTEN

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  • Clear Fillable Online PDF Files

    - by May
    I filled in an online pdf form. After I finished, I closed the window thinking that the form will clear itself since I didn't save it. When I went back to the website and clicked on the form again, it still had the information that I entered. Other than manually deleting all the information on the form, is there another way of clearing the form?

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  • Android - How do I load a contact Photo?

    - by PaulH
    I'm having trouble loading a photo for a contact in Android. I've googled for an answer, but so far have come up empty. Does anyone have an example of querying for a Contact, then loading the Photo? So, given a contactUri which comes from an Activity result called using startActivityForResult(new Intent(Intent.ACTION_PICK,ContactsContract.CommonDataKinds.Phone.CONTENT_URI),PICK_CONTACT_REQUEST) is: content://com.android.contacts/data/1557 The loadContact(..) works fine. However when I call the getPhoto(...) method, I get a null value for the photo InputStream. It is also confusing because the URI values are different. The contactPhotoUri evaluates to: content://com.android.contacts/contacts/1557 See the comments inline in the code below. class ContactAccessor { /** * Retrieves the contact information. */ public ContactInfo loadContact(ContentResolver contentResolver, Uri contactUri) { //contactUri --> content://com.android.contacts/data/1557 ContactInfo contactInfo = new ContactInfo(); // Load the display name for the specified person Cursor cursor = contentResolver.query(contactUri, new String[]{Contacts._ID, Contacts.DISPLAY_NAME, Phone.NUMBER, Contacts.PHOTO_ID}, null, null, null); try { if (cursor.moveToFirst()) { contactInfo.setId(cursor.getLong(0)); contactInfo.setDisplayName(cursor.getString(1)); contactInfo.setPhoneNumber(cursor.getString(2)); } } finally { cursor.close(); } return contactInfo; // <-- returns info for contact } public Bitmap getPhoto(ContentResolver contentResolver, Long contactId) { Uri contactPhotoUri = ContentUris.withAppendedId(Contacts.CONTENT_URI, contactId); // contactPhotoUri --> content://com.android.contacts/contacts/1557 InputStream photoDataStream = Contacts.openContactPhotoInputStream(contentResolver,contactPhotoUri); // <-- always null Bitmap photo = BitmapFactory.decodeStream(photoDataStream); return photo; } public class ContactInfo { private long id; private String displayName; private String phoneNumber; private Uri photoUri; public void setDisplayName(String displayName) { this.displayName = displayName; } public String getDisplayName() { return displayName; } public void setPhoneNumber(String phoneNumber) { this.phoneNumber = phoneNumber; } public String getPhoneNumber() { return phoneNumber; } public Uri getPhotoUri() { return this.photoUri; } public void setPhotoUri(Uri photoUri) { this.photoUri = photoUri; } public long getId() { return this.id; } public void setId(long id) { this.id = id; } } } Clearly, I'm doing something wrong here, but I can't seem to figure out what the problem is. Thanks.

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