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  • Can I use Eclipse JDT to create new 'working copies' of source files in memory only?

    - by RYates
    I'm using Eclipse JDT to build a Java refactoring platform, for exploring different refactorings in memory before choosing one and saving it. I can create collections of working copies of the source files, edit them in memory, and commit the changes to disk using the JDT framework. However, I also want to generate new 'working copy' source files in memory as part of refactorings, and only create the corresponding real source file if I commit the working copy. I have seen various hints that this is possible, e.g. http://www.jarvana.com/jarvana/view/org/eclipse/jdt/doc/isv/3.3.0-v20070613/isv-3.3.0-v20070613.jar!/guide/jdt%5Fapi%5Fmanip.htm says "Note that the compilation unit does not need to exist in the Java model in order for a working copy to be created". So far I have only been able to create a new real file, i.e. ICompilationUnit newICompilationUnit = myPackage.createCompilationUnit(newName, "package piffle; public class Baz{private int i=0;}", false, null); This is not what I want. Does anyone know how to create a new 'working copy' source file, that does not appear in my file system until I commit it? Or any other mechanism to achieve the same thing?

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  • Rails - Create if record doesn't exist or else update.....Whats Best way to do this?

    - by ChrisWesAllen
    Hi, I have a create statement for some models but its creating a record within a join table regardless if the record exist. Here is what my code looks like. @user = User.find(current_user) @event = Event.find(params[:id]) for interest in @event.interests @user.choices.create(:interest => interest, :score => 4) end The problem is it creates records no matter what. I would like it to create a record if it doesnt exist, if a record does exist I would just to it to take the attribute of the found record and add or subtract 1. So, I've been looking around and I see something called find_or_create_by. My question is what happens if it finds? Preferably if it finds,I would like to take the current :score attribute and +1. SO is it possible to find or create by id? I'm not sure what attribute I would find by since the model I'm looking at is a join model which only had id foreign keys and the score attribute. I tried @user.choices.find_or_create_by_user(:user => @user.id, :interest => interest, :score => 4) but got "undefined method `find_by_user'".....ANy ideas or help?

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  • $.fadeTo/fadeOut() operations on Table Rows in IE fail

    - by Rick Strahl
    Here’s a a small problem that one of customers ran into a few days ago: He was playing around with some of the sample code I’ve put out for one of my simple jQuery demos which deals with providing a simple pulse behavior plug-in: $.fn.pulse = function(time) { if (!time) time = 2000; // *** this == jQuery object that contains selections $(this).fadeTo(time, 0.20, function() { $(this).fadeTo(time, 1); }); return this; } it’s a very simplistic plug-in and it works fine for simple pulse animations. However he ran into a problem where it didn’t work when working with tables – specifically pulsing a table row in Internet Explorer. Works fine in FireFox and Chrome, but IE not so much. It also works just fine in IE as long as you don’t try it on tables or table rows specifically. Applying against something like this (an ASP.NET GridView): var sel = $("#gdEntries>tbody>tr") .not(":first-child") // no header .not(":last-child") // no footer .filter(":even") .addClass("gridalternate"); // *** Demonstrate simple plugin sel.pulse(2000); fails in IE. No pulsing happens in any version of IE. After some additional experimentation with single rows and various ways of selecting each and still failing, I’ve come to the conclusion that the various fade operations in jQuery simply won’t work correctly in IE (any version). So even something as ‘elemental’ as this: var el = $("#gdEntries>tbody>tr").get(0);$(el).fadeOut(2000); is not working correctly. The item will stick around for 2 seconds and then magically disappear. Likewise: sel.hide().fadeIn(5000); also doesn’t fade in although the items become immediately visible in IE. Go figure that behavior out. Thanks to a tweet from red_square and a link he provided here is a grid that explains what works and doesn’t in IE (and most last gen browsers) regarding opacity: http://www.quirksmode.org/js/opacity.html It appears from this link that table and row elements can’t be made opaque, but td elements can. This means for the row selections I can force each of the td elements to be selected and then pulse all of those. Once you have the rows it’s easy to explicitly select all the columns in those rows with .find(“td”). Aha the following actually works: var sel = $("#gdEntries>tbody>tr") .not(":first-child") // no header .not(":last-child") // no footer .filter(":even") .addClass("gridalternate"); // *** Demonstrate simple plugin sel.find("td").pulse(2000); A little unintuitive that, but it works. Stay away from <table> and <tr> Fades The moral of the story is – stay away from TR, TH and TABLE fades and opacity. If you have to do it on tables use the columns instead and if necessary use .find(“td”) on your row(s) selector to grab all the columns. I’ve been surprised by this uhm relevation, since I use fadeOut in almost every one of my applications for deletion of items and row deletions from grids are not uncommon especially in older apps. But it turns out that fadeOut actually works in terms of behavior: It removes the item when the timeout’s done and because the fade is relatively short lived and I don’t extensively test IE code any more I just never noticed that the fade wasn’t happening. Note – this behavior or rather lack thereof appears to be specific to table table,tr,th elements. I see no problems with other elements like <div> and <li> items. Chalk this one up to another of IE’s shortcomings. Incidentally I’m not the only one who has failed to address this in my simplistic plug-in: The jquery-ui pulsate effect also fails on the table rows in the same way. sel.effect("pulsate", { times: 3 }, 2000); and it also works with the same workaround. If you’re already using jquery-ui definitely use this version of the plugin which provides a few more options… Bottom line: be careful with table based fade operations and remember that if you do need to fade – fade on columns.© Rick Strahl, West Wind Technologies, 2005-2010Posted in jQuery  

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  • iTextSharp - Bug in the table functions?

    - by Matthias
    Hello all together, I try to make a table like this: PdfPTable Table = new PdfPTable(6); PdfPCell Cell = new PdfPCell(new Phrase("a", Font1)); Cell.Rowspan = 2; Cell.Colspan = 2; Table.AddCell(Cell); Cell = new PdfPCell(new Phrase("b", Font1)); Cell.Rowspan = 2; Cell.Colspan = 2; Table.AddCell(Cell); Cell = new PdfPCell(new Phrase("c", Font1)); Cell.Colspan = 2; Table.AddCell(Cell); Cell = new PdfPCell(new Phrase("d", Font1)); Cell.Colspan = 2; Table.AddCell(Cell); That works fine. But changing the number of columns will destory the table. Is it a bug or do I make something wrong? This code destroys the table: PdfPTable Table = new PdfPTable(17); PdfPCell Cell = new PdfPCell(new Phrase("a", Font1)); Cell.Rowspan = 2; Cell.Colspan = 2; Table.AddCell(Cell); Cell = new PdfPCell(new Phrase("b", Font1)); Cell.Rowspan = 2; Cell.Colspan = 10; Table.AddCell(Cell); Cell = new PdfPCell(new Phrase("c", Font1)); Cell.Colspan = 5; Table.AddCell(Cell); Cell = new PdfPCell(new Phrase("d", Font1)); Cell.Colspan = 5; Table.AddCell(Cell); Edit: The table should have this layout: |-------------------------------------------------------| | Cell "a" with | Cell "b" with | Cell "c", colspan = 5 | | colspan = 2 | colspan = 10 |-----------------------| | rowspan = 2 | rowspan = 2 | Cell "d", colspan = 5 | |-------------------------------------------------------| Best regards, Matthias

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  • Netlogo: error when putting variable in table, only constants allowe??

    - by Chantal
    Hello, Currently I am working on a Netlogo program where I need to use nodes and links for vehicle routing problem. (links are called streets in the program) Here I have some practical problems of how to input variable linkspeed in a table with another node. Constants like 200 etc are fine. Online I found some examples where variables are used, but I do not know why I keep getting the following error: Expected a constant. (or why netlogo expects a constant) Here is the relevant piece of code: extensions [table] streets-own [linkspeed linktoll] nodes-own [netw] ;; In another piece of code linkspeed is assigned successfully to the links to cheapcalc ;; start conditions set costs very high 300000 ;; state 3 unsearched state 2 searching state 1 searched (for later purposes) ask nodes [ set i 0 set j count nodes set netw table:make while [i < j][ table:put netw (i) [3000000 3] set i (i + 1)]] set i 0 let k 0 ask node 35 ;; here i use node 35 as an example. ;; node 35 is connected to node 34, 36, 20 and 50 [table:put netw (35) [0 1] ;; node need to search costs to travel to itself ;; putting constants is ok. while [i < j] [ask my-links [ask both-ends [if (who != 35) [set color blue ;; set temp ([linkspeed] of street 35 who) ;; here my real goal is to put this in stat of i. but i is easier than linkspeed. table:put netw (who) [ i 2 ] ] ] ] set i (i + 1)] ] ;; next node for later, no it is just repetition of the same. end I hope somebody knows what is going on... Kind regards, Chantal

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  • Problem in Fetching Table contents when adding rows in same table

    - by jasmine
    Im trying to write a function for adding category: function addCategory() { $cname = mysql_fix_string($_POST['cname']); $kabst = mysql_fix_string($_POST['kabst']); $kselect = $_POST['kselect']; $kradio = $_POST['kradio']; $ksubmit = $_POST['ksubmit']; $id = $_POST['id']; if($ksubmit){ $query = "INSERT INTO category VALUES (' ', '{$cname}', '{$kabst}', {$kselect}, {$kradio}, ' ') "; $result = mysql_query($query); if ($result) { echo "ok"; } else{ echo $query ; } } $text .= '<div class="form"> <h2>ADD new category</h2> <form action="?page=addCategory" method="post"> <ul> <li><label>Category</label></li> <li><input name="cname" type="text" class="inp" /></li> <li><label>Description</label></li> <li><textarea name="kabst" cols="40" rows="10" class="inx"></textarea></li> <li>Published:</li> <li> <select name="kselect" class="ins"> <option value="1">Active</option> <option value="0">Passive</option> </select> </li> <li>Show in home page:</li> <li> <input type="radio" name="kradio" value="1" /> yes <input type="radio" name="kradio" value="0" /> no </li> <li>Subcategory of</li> <li> <select>'; while ($row = mysql_fetch_assoc(mysql_query("SELECT * FROM category"))){ $text .= '<option>'.$row['name'].'</option>'; } $text .= '</select> </li> <li><input name="ksubmit" type="submit" value="ekle" class="int"/></li> </ul> </form> '; return $text;} And the error: Fatal error: Maximum execution time of 30 seconds exceeded What is wrong in my function?

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  • SQL Query Help - Return row in table which relates to another table row with max(column)

    - by Seth
    I have two tables: Table1 = Schools Columns: id(PK), state(nvchar(100)), schoolname Table2 = Grades Columns: id(PK), id_schools(FK), Year, Reading, Writing... I would like to develop a query to find the schoolname which has the highest grade for Reading. So far I have the following and need help to fill in the blanks: SELECT Schools.schoolname, Grades.Reading FROM Schools, Grades WHERE Schools.id = (* need id_schools for max(Grades.Reading)*)

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  • Nested query to find details in table B for maximum value in table A

    - by jpatokal
    I've got a huge bunch of flights travelling between airports. Each airport has an ID and (x,y) coordinates. For a given list of flights, I want to find the northernmost (highest x) airport visited. Here's the query I'm currently using: SELECT name,iata,icao,apid,x,y FROM airports WHERE y=(SELECT MAX(y) FROM airports AS a , flights AS f WHERE (f.src_apid=a.apid OR f.dst_apid=a.apid) ) This works beautifully and reasonably fast as long as y is unique, but fails once it isn't. What I'd want to do instead is find the MAX(y) in the subquery, but return the unique apid for the airport with the highest y. Any suggestions?

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  • php / mysql - select id from one table excepting ids which are in second table

    - by John
    hello. for example i have 2 tables: 1 . users: id Name 1 Mike 2 Adam 3 Tom 4 John 5 Andy 6 Ray 2 . visits: userID date 1 ... 3 ... 6 ... i want to make a page which can be visited once in 12 hours, when user visits that page his id is included in database ( visits ), how i can select all users ( from database users) excepting users who visited page in <= 12 hours ( users from database visits )?

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  • DotNetNuke create new portal didnt create new portal

    - by Jonesy
    hi folks, I've installed dotnetnuke today for the first time, I've created a new portal via host/portals. It says its created it but just doesn't find it. I just don't know how/why? The portal ID is 4. and there is a directory in dotnetnuke/Portals/4 But the url localhost/bmd (name of the portal) doesn't resolve to anything/ Anyone know a solution to this? maybe it happened to you too? Cheers

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  • Creating new table entry when updating another entry of another table - Ruby on Rails

    - by Michaël
    Hi, I have written this code in my "show" view of estimates and I want that, when submitting (update), it creates a new repairs (Repair.new(???)) with some parameters. I don't know where to write the "new repairs" code, in this view or the controller (in update part). I need that the Repair is created one time, not each time the @estimate is updated. <% form_for @estimate, :url => {:controller => "estimates", :action => "update"} do |f| %> <%= f.error_messages %> <select id="estimate_accept" name="estimate[accept]"> <option value="1" selected="selected">accept</option> <option value="2">refuse</option> </select> <%= f.submit "Update" %> <% end %> Thank you for your help, I hope my explanations are clear!

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  • Select 2 Rows from Table when COUNT of another table

    - by Marcus
    Here is the code that I currently have: SELECT `A`.* FROM `A` LEFT JOIN `B` ON `A`.`A_id` = `B`.`value_1` WHERE `B`.`value_2` IS NULL AND `B`.`userid` IS NULL ORDER BY RAND() LIMIT 2 What it currently is supposed to do is select 2 rows from A when the 2 rows A_id being selected are not in value_1 or value_2 in B. And the rows in B are specific to individual users with userid. What I need to do is make it also so that also checks if there are already N rows in B matching a A_id (either in value_1, or value_2) and userid, and if there are more than N rows, it doesn't select the A row.

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  • Inserting new argument to table through search form of another table

    - by owca
    In my database I have a form for searching products (fields : id, name, manufacturer_id[set to display manufacturer's name], category_id, price). I would like to have the ability of adding manufacturers through this form. So I've created vba script but it does not work. Still when I enter new name it gives me prompt to "Select element from the list". What am I doing wrong ? Private Sub manufacturer_id_NotInTheList(NewData As String, Response As Integer) Dim strSQL As String, strInfo As String strInfo = "Manufacturer " & NewData & " is not on the list." & vbCrLf & "Add?" If MsgBox(strInfo, vbYesNo + vbQuestion, "Element not on the list") = vbYes Then strSQL = "INSERT INTO manufacturer (name, country, id_distributor) VALUES ('" & NewData & "','Undefined', '0');" DoCmd.SetWarnings (False) DoCmd.RunSQL strSQL Response = acDataErrAdded Else Response = acDataErrContinue NewData = "" Me.manufacturer_id.Text = "" End If End Sub

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  • solution for updating table based on data from another table

    - by I__
    i have 2 tables in access this is what i need: 1. if the PK from table1 exists in table2, then delete the entire record with that PK from table2 and add the entire record from table1 into table2 2. if the PK does not exist then add the record i need help with both the sql statement and the VBA i guess the VBA should be a loop, going through every record in table1. inside the loop i should have the select statement

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  • How to display how many times each records in a table used by other table

    - by Fredy
    I have a problem with my query, below are two tables that tbl_tag and tbl_tag_usedby. I want to show how much of each record in tbl_tag used by record in tbl_tag_usedby. Here is a query that I use: SELECT t.*, COUNT(u.tagid) AS totale FROM tbl_tag t LEFT JOIN tbl_tag_usedby u ON u.tagid = t.id AND t.status =1 GROUP BY u.tagid and the results are as below: In this case the record id from 2 to 6 do not appear in the query results, I want record id from 2 to 6 are also shown and on the field "totale" its value is 0. Can anyone help me?

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  • Html, table, img & css - how to get text to wrap correctly?

    - by Michael Pasqualone
    I've got the following code; however it's not given me the desired result - what I am after is as per the image below, what am I doing wrong? <style> table.control_grid tr { text-align: center; width: 200px; } table.control_grid td { width: 120px; height: 48px; } table.control_grid a { text-decoration: none; } table.control_grid img { vertical-align: text-top; } </style> <table class="control_grid"> <tr> <td><img width="48" height="48" src="icon1.gif">My text & stuff, overflow??</td> <td><img width="48" height="48" src="icon1.gif">Icon1</td> <td><img width="48" height="48" src="icon1.gif">Icon2</td> <td></td> <td></td> </tr> </table> Desired result:

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  • Multisite Enabling a Table

    - by Joe Fitzgibbons
    I am creating a table (table A) that will have a number of columns(of course) and there will be another table (table B) that holds metadata associated to rows in table A. I am working with a multi site implementation that has one database for the whole shabang. Rows in table A could belong to any number of sites but must belong to at least one. The problem I have is I am not sure what the best practice is for defining what site each row in table A belongs to. I want performance and scalability. There is no finite number of sites going forward. Rows in table A could belong to any number of sites in the future. Right now there are only 3. My initial thoughts are to have a primary site ID in Table A and then metadata in table B will have rows defining additional sites as needed. Another thought is to have a column in Table A for each site and it is a boolean as to wether it belongs to that site. Lastly I have thought about having another table to map rows in Table A to each site. What is the best way to associate rows in a table with any number of sites with performance and scalability in mind?

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  • How to create a new Team Project Collection in TFS2010:

    - by jehan
    TFS 2010 has introduced the notion of Team Project Collection (TPC).  I have already discussed about TPC in my earlier post, you can check it out here. In this post, I will demonstrate how to create a new Team Project Collection in TFS2010. First, you have to open the TFS Administration Console (Start à All Programs à Microsoft Team Foundation Server 2010 à Team Foundation Server Administration Console), expand the Application Tier node in TFS Administration Console and click on Team Project Collection. Here you will see the TPC’s which are already exist, I am having only one TPC named New Collection and I’m going to create a new TPC called Demo Collection. To create a new Team Project Collection, you need to click on Create Collection; it will open the Create New Team Project Collection window.     Under the Name tab, you have to enter the name of Collection which you want to give for your new TPC (I naming it as Demo Collection). You can also provide some description about your TPC in Description tab which is optional and click next. Here, you need to enter the name of SQL Server Instance where you want your new TPC data to reside. You have the option either to choose the creating a Database for this TPC or use the already existing empty database and then click next.   In next screen, you have to choose SharePoint configuration. Here you have the options to either configure SharePoint Site for TPC at default collections or you can specify the your existing SharePoint site and  you can also choose not  to configure the SharePoint for this collection, if you choose last option then you cannot configure the Share Point sites for the all the Team Projects under this Project Collection. You also have the flexibility to create a Share Point site for this TPC later on, then if you need you have to configure SharePoint site for the existing team projects manually.   In next screen, you will have the Reports configuration. Here you have the options to either configure the Reports for TPC at default path or you can specify the path for at existing Reports folder, you can also choose not to configure the Reports for this collection, if you choose last option then you cannot create  the Reports  for the all the Team Projects under this Project Collection. Here also you can enable reporting for this TPC later on. The next screen is related to Lab Management Configuration, Lab Management is the new feature in TFS2010 which enables the users to create and manage virtual test environments where you can deploy and test your application. There are no options available here as I don’t have the Lab Management configured for my Team Foundation Server. The next screen is Review Configuration window, which will show up all the configuration settings you have specified, so that you can review the configurations before creating the Team Project Collection. If you want to make any changes to the configurations then you can go back to the previous windows and can make the changes. After Reviewing the configuration settings, you can click on verify button. Which will verify that if you’re Team Project Collection is ready to be created or not, it will show up the errors and warning (if any) which can make your Team Project Collection fail. You can then choose to create the Team Project Collection if the verify option doesn’t throw any warnings and errors. If the verify option throws any errors, then it is strongly suggested that you have to first rectify the issues then only go for TPC creation especially in case of warnings as it is a common practice to overlook the warnings.   If you choose the create TPC option, then it will start the process of creating a Team Project Collection  and once its completed you can check the status of configuration different components  during Team Project Collection. You can see in below screen that all the components are configured successfully.   In next screen, you can find the location of log file created for this Team Project Creation, this log file is really important in case of Team Project creation failure because it will help you to find  the root cause for the failure. Now, you can see that the New Team Projection (Demo Collection) which was created is now available in Team Foundation Collection tab and its status is Online.   You can now try to connect to this Team Project Collection from Team Explorer. Choose the newly created Team Project Collection and click on connect.     This Team Project Collection is empty because no Team Projects are created yet. Now, you can create the new Team Projects and start working.

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  • Mysql PHP generated table: doesn't work with Tablesorter

    - by echedey lorenzo
    Hi, I found this great Tablesorter plugin for jQuery but I can't make it work with my PHP generated table. Here's the code: <script type="text/javascript"> function table() { $("#container").load("table.php?randval="+Math.random()); } $(document).ready(function() { table(); $("table").tablesorter(); }); </script> Where #container is the div where the table will be and table is the name of the table. I get the table loaded but sorting function is not working. It works if I put the table directly in html in the page.. but I don't see the point in having a static table for sorting. Any help would be very appreciated.

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  • Python In-memory table

    - by nsharish
    What is the right way to forming in-memory table in python with direct lookups for rows and columns.I thought of using dict of dicts this way, class Table(dict): def __getitem__(self, key): if key not in self: self[key]={} return dict.__getitem__(self, key) table = Table() table['row1']['column1'] = 'value11' table['row1']['column2'] = 'value12' table['row2']['column1'] = 'value21' table['row2']['column2'] = 'value22' >>>table {'row1':{'column1':'value11','column2':'value12'},'row2':{'column1':'value21','column2':'value22'}} I had difficulty in looking up for values in columns. >>>'row1' in table True >>>'value11' in table['row1'].values() True Now how do I do lookup if 'column1' has 'value11' Is this method of forming tables wrong?Is there a better way to implement such tables with easier lookups?.Thanks

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  • Clone DB table row through MVC in SQL Server

    - by sslepian
    Is there a simple solution for duplicating table rows in SQL Server as well as all table rows with foreign keys pointing to the cloned table row? I've got a "master" table and a bunch of "child" tables which have a foreign key into the ID of the master table. I need to not only create a perfect copy of the master table, but clone each and every child table referencing the master table. Is there a simpler way to do this than creating a new row in the master table, copying in the information from the row to be cloned, then going through each child table and doing the same with each row pointing to the cloned row in the master table? I'm using a SQL Server 2005 Database accessed through C# ASP.net MVC 1.0.

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  • Clone DB table row through MVC in MSSQL

    - by sslepian
    Is there a simple solution for duplicating table rows in MSSQL as well as all table rows with foreign keys pointing to the cloned table row? I've got a "master" table and a bunch of "child" tables which have a foreign key into the ID of the master table. I need to not only create a perfect copy of the master table, but clone each and every child table referencing the master table. Is there a simpler way to do this than creating a new row in the master table, copying in the information from the row to be cloned, then going through each child table and doing the same with each row pointing to the cloned row in the master table? I'm using a MSSQL 2005 Database accessed through C# ASP.net MVC 1.0.

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  • How to create Custom ListForm WebPart

    - by DipeshBhanani
    Mostly all who works extensively on SharePoint (including meJ) don’t like to use out-of-box list forms (DispForm.aspx, EditForm.aspx, NewForm.aspx) as interface. Actually these OOB list forms bind hands of developers for the customization. It gives headache to developers to add just one post back event, for a dropdown field and to populate other fields in NewForm.aspx or EditForm.aspx. On top of that clients always ask such stuff. So here I am going to give you guys a flight for SharePoint Customization world. In this blog, I will explain, how to create CustomListForm WebPart. In my next blogs, I am going to explain easy deployment of List Forms through features and last, guidance on using SharePoint web controls. 1.       First thing, create a class library project through Visual Studio and inherit the class with WebPart class.     public class CustomListForm : WebPart   2.       Declare the public variables and properties which we are going to use throughout the class. You will get to know these once you see them in use.         #region "Variable Declaration"           Table spTableCntl;         FormToolBar formToolBar;         Literal ltAlertMessage;         Guid SiteId;         Guid ListId;         int ItemId;         string ListName;           #endregion           #region "Properties"           SPControlMode _ControlMode = SPControlMode.New;         [Personalizable(PersonalizationScope.Shared),          WebBrowsable(true),          WebDisplayName("Control Mode"),          WebDescription("Set Control Mode"),          DefaultValue(""),          Category("Miscellaneous")]         public SPControlMode ControlMode         {             get { return _ControlMode; }             set { _ControlMode = value; }         }           #endregion     The property “ControlMode” is used to identify the mode of the List Form. The property is of type SPControlMode which is an enum type with values (Display, Edit, New and Invalid). When we will add this WebPart to DispForm.aspx, EditForm.aspx and NewForm.aspx, we will set the WebPart property “ControlMode” to Display, Edit and New respectively.     3.       Now, we need to override the CreateChildControl method and write code to manually add SharePoint Web Controls related to each list fields as well as ToolBar controls.         protected override void CreateChildControls()         {             base.CreateChildControls();               try             {                 SiteId = SPContext.Current.Site.ID;                 ListId = SPContext.Current.ListId;                 ListName = SPContext.Current.List.Title;                   if (_ControlMode == SPControlMode.Display || _ControlMode == SPControlMode.Edit)                     ItemId = SPContext.Current.ItemId;                   SPSecurity.RunWithElevatedPrivileges(delegate()                 {                     using (SPSite site = new SPSite(SiteId))                     {                         //creating a new SPSite with credentials of System Account                         using (SPWeb web = site.OpenWeb())                         {                               //<Custom Code for creating form controls>                         }                     }                 });             }             catch (Exception ex)             {                 ShowError(ex, "CreateChildControls");             }         }   Here we are assuming that we are developing this WebPart to plug into List Forms. Hence we will get the List Id and List Name from the current context. We can have Item Id only in case of Display and Edit Mode. We are putting our code into “RunWithElevatedPrivileges” to elevate privileges to System Account. Now, let’s get deep down into the main code and expand “//<Custom Code for creating form controls>”. Before initiating any SharePoint control, we need to set context of SharePoint web controls explicitly so that it will be instantiated with elevated System Account user. Following line does the job.     //To create SharePoint controls with new web object and System Account credentials     SPControl.SetContextWeb(Context, web);   First thing, let’s add main table as container for all controls.     //Table to render webpart     Table spTableMain = new Table();     spTableMain.CellPadding = 0;     spTableMain.CellSpacing = 0;     spTableMain.Width = new Unit(100, UnitType.Percentage);     this.Controls.Add(spTableMain);   Now we need to add Top toolbar with Save and Cancel button at top as you see in the below screen shot.       // Add Row and Cell for Top ToolBar     TableRow spRowTopToolBar = new TableRow();     spTableMain.Rows.Add(spRowTopToolBar);     TableCell spCellTopToolBar = new TableCell();     spRowTopToolBar.Cells.Add(spCellTopToolBar);     spCellTopToolBar.Width = new Unit(100, UnitType.Percentage);         ToolBar toolBarTop = (ToolBar)Page.LoadControl("/_controltemplates/ToolBar.ascx");     toolBarTop.CssClass = "ms-formtoolbar";     toolBarTop.ID = "toolBarTbltop";     toolBarTop.RightButtons.SeparatorHtml = "<td class=ms-separator> </td>";       if (_ControlMode != SPControlMode.Display)     {         SaveButton btnSave = new SaveButton();         btnSave.ControlMode = _ControlMode;         btnSave.ListId = ListId;           if (_ControlMode == SPControlMode.New)             btnSave.RenderContext = SPContext.GetContext(web);         else         {             btnSave.RenderContext = SPContext.GetContext(this.Context, ItemId, ListId, web);             btnSave.ItemContext = SPContext.GetContext(this.Context, ItemId, ListId, web);             btnSave.ItemId = ItemId;         }         toolBarTop.RightButtons.Controls.Add(btnSave);     }       GoBackButton goBackButtonTop = new GoBackButton();     toolBarTop.RightButtons.Controls.Add(goBackButtonTop);     goBackButtonTop.ControlMode = SPControlMode.Display;       spCellTopToolBar.Controls.Add(toolBarTop);   Here we have use “SaveButton” and “GoBackButton” which are internal SharePoint web controls for save and cancel functionality. I have set some of the properties of Save Button with if-else condition because we will not have Item Id in case of New Mode. Item Id property is used to identify which SharePoint List Item need to be saved. Now, add Form Toolbar to the page which contains “Attach File”, “Delete Item” etc buttons.       // Add Row and Cell for FormToolBar     TableRow spRowFormToolBar = new TableRow();     spTableMain.Rows.Add(spRowFormToolBar);     TableCell spCellFormToolBar = new TableCell();     spRowFormToolBar.Cells.Add(spCellFormToolBar);     spCellFormToolBar.Width = new Unit(100, UnitType.Percentage);       FormToolBar formToolBar = new FormToolBar();     formToolBar.ID = "formToolBar";     formToolBar.ListId = ListId;     if (_ControlMode == SPControlMode.New)         formToolBar.RenderContext = SPContext.GetContext(web);     else     {         formToolBar.RenderContext = SPContext.GetContext(this.Context, ItemId, ListId, web);         formToolBar.ItemContext = SPContext.GetContext(this.Context, ItemId, ListId, web);         formToolBar.ItemId = ItemId;     }     formToolBar.ControlMode = _ControlMode;     formToolBar.EnableViewState = true;       spCellFormToolBar.Controls.Add(formToolBar);     The ControlMode property will take care of which button to be displayed on the toolbar. E.g. “Attach files”, “Delete Item” in new/edit forms and “New Item”, “Edit Item”, “Delete Item”, “Manage Permissions” etc in display forms. Now add main section which contains form field controls.     //Create Form Field controls and add them in Table "spCellCntl"     CreateFieldControls(web);     //Add public variable "spCellCntl" containing all form controls to the page     spRowCntl.Cells.Add(spCellCntl);     spCellCntl.Width = new Unit(100, UnitType.Percentage);     spCellCntl.Controls.Add(spTableCntl);       //Add a Blank Row with height of 5px to render space between ToolBar table and Control table     TableRow spRowLine1 = new TableRow();     spTableMain.Rows.Add(spRowLine1);     TableCell spCellLine1 = new TableCell();     spRowLine1.Cells.Add(spCellLine1);     spCellLine1.Height = new Unit(5, UnitType.Pixel);     spCellLine1.Controls.Add(new LiteralControl("<IMG SRC='/_layouts/images/blank.gif' width=1 height=1 alt=''>"));       //Add Row and Cell for Form Controls Section     TableRow spRowCntl = new TableRow();     spTableMain.Rows.Add(spRowCntl);     TableCell spCellCntl = new TableCell();       //Create Form Field controls and add them in Table "spCellCntl"     CreateFieldControls(web);     //Add public variable "spCellCntl" containing all form controls to the page     spRowCntl.Cells.Add(spCellCntl);     spCellCntl.Width = new Unit(100, UnitType.Percentage);     spCellCntl.Controls.Add(spTableCntl);       TableRow spRowLine2 = new TableRow();     spTableMain.Rows.Add(spRowLine2);     TableCell spCellLine2 = new TableCell();     spRowLine2.Cells.Add(spCellLine2);     spCellLine2.CssClass = "ms-formline";     spCellLine2.Controls.Add(new LiteralControl("<IMG SRC='/_layouts/images/blank.gif' width=1 height=1 alt=''>"));       // Add Blank row with height of 5 pixel     TableRow spRowLine3 = new TableRow();     spTableMain.Rows.Add(spRowLine3);     TableCell spCellLine3 = new TableCell();     spRowLine3.Cells.Add(spCellLine3);     spCellLine3.Height = new Unit(5, UnitType.Pixel);     spCellLine3.Controls.Add(new LiteralControl("<IMG SRC='/_layouts/images/blank.gif' width=1 height=1 alt=''>"));   You can add bottom toolbar also to get same look and feel as OOB forms. I am not adding here as the blog will be much lengthy. At last, you need to write following lines to allow unsafe updates for Save and Delete button.     // Allow unsafe update on web for save button and delete button     if (this.Page.IsPostBack && this.Page.Request["__EventTarget"] != null         && (this.Page.Request["__EventTarget"].Contains("IOSaveItem")         || this.Page.Request["__EventTarget"].Contains("IODeleteItem")))     {         SPContext.Current.Web.AllowUnsafeUpdates = true;     }   So that’s all. We have finished writing Custom Code for adding field control. But something most important is skipped. In above code, I have called function “CreateFieldControls(web);” to add SharePoint field controls to the page. Let’s see the implementation of the function:     private void CreateFieldControls(SPWeb pWeb)     {         SPList listMain = pWeb.Lists[ListId];         SPFieldCollection fields = listMain.Fields;           //Main Table to render all fields         spTableCntl = new Table();         spTableCntl.BorderWidth = new Unit(0);         spTableCntl.CellPadding = 0;         spTableCntl.CellSpacing = 0;         spTableCntl.Width = new Unit(100, UnitType.Percentage);         spTableCntl.CssClass = "ms-formtable";           SPContext controlContext = SPContext.GetContext(this.Context, ItemId, ListId, pWeb);           foreach (SPField listField in fields)         {             string fieldDisplayName = listField.Title;             string fieldInternalName = listField.InternalName;               //Skip if the field is system field or hidden             if (listField.Hidden || listField.ShowInVersionHistory == false)                 continue;               //Skip if the control mode is display and field is read-only             if (_ControlMode != SPControlMode.Display && listField.ReadOnlyField == true)                 continue;               FieldLabel fieldLabel = new FieldLabel();             fieldLabel.FieldName = listField.InternalName;             fieldLabel.ListId = ListId;               BaseFieldControl fieldControl = listField.FieldRenderingControl;             fieldControl.ListId = ListId;             //Assign unique id using Field Internal Name             fieldControl.ID = string.Format("Field_{0}", fieldInternalName);             fieldControl.EnableViewState = true;               //Assign control mode             fieldLabel.ControlMode = _ControlMode;             fieldControl.ControlMode = _ControlMode;             switch (_ControlMode)             {                 case SPControlMode.New:                     fieldLabel.RenderContext = SPContext.GetContext(pWeb);                     fieldControl.RenderContext = SPContext.GetContext(pWeb);                     break;                 case SPControlMode.Edit:                 case SPControlMode.Display:                     fieldLabel.RenderContext = controlContext;                     fieldLabel.ItemContext = controlContext;                     fieldLabel.ItemId = ItemId;                       fieldControl.RenderContext = controlContext;                     fieldControl.ItemContext = controlContext;                     fieldControl.ItemId = ItemId;                     break;             }               //Add row to display a field row             TableRow spCntlRow = new TableRow();             spTableCntl.Rows.Add(spCntlRow);               //Add the cells for containing field lable and control             TableCell spCellLabel = new TableCell();             spCellLabel.Width = new Unit(30, UnitType.Percentage);             spCellLabel.CssClass = "ms-formlabel";             spCntlRow.Cells.Add(spCellLabel);             TableCell spCellControl = new TableCell();             spCellControl.Width = new Unit(70, UnitType.Percentage);             spCellControl.CssClass = "ms-formbody";             spCntlRow.Cells.Add(spCellControl);               //Add the control to the table cells             spCellLabel.Controls.Add(fieldLabel);             spCellControl.Controls.Add(fieldControl);               //Add description if there is any in case of New and Edit Mode             if (_ControlMode != SPControlMode.Display && listField.Description != string.Empty)             {                 FieldDescription fieldDesc = new FieldDescription();                 fieldDesc.FieldName = fieldInternalName;                 fieldDesc.ListId = ListId;                 spCellControl.Controls.Add(fieldDesc);             }               //Disable Name(Title) in Edit Mode             if (_ControlMode == SPControlMode.Edit && fieldDisplayName == "Name")             {                 TextBox txtTitlefield = (TextBox)fieldControl.Controls[0].FindControl("TextField");                 txtTitlefield.Enabled = false;             }         }         fields = null;     }   First of all, I have declared List object and got list fields in field collection object called “fields”. Then I have added a table for the container of all controls and assign CSS class as "ms-formtable" so that it gives consistent look and feel of SharePoint. Now it’s time to navigate through all fields and add them if required. Here we don’t need to add hidden or system fields. We also don’t want to display read-only fields in new and edit forms. Following lines does this job.             //Skip if the field is system field or hidden             if (listField.Hidden || listField.ShowInVersionHistory == false)                 continue;               //Skip if the control mode is display and field is read-only             if (_ControlMode != SPControlMode.Display && listField.ReadOnlyField == true)                 continue;   Let’s move to the next line of code.             FieldLabel fieldLabel = new FieldLabel();             fieldLabel.FieldName = listField.InternalName;             fieldLabel.ListId = ListId;               BaseFieldControl fieldControl = listField.FieldRenderingControl;             fieldControl.ListId = ListId;             //Assign unique id using Field Internal Name             fieldControl.ID = string.Format("Field_{0}", fieldInternalName);             fieldControl.EnableViewState = true;               //Assign control mode             fieldLabel.ControlMode = _ControlMode;             fieldControl.ControlMode = _ControlMode;   We have used “FieldLabel” control for displaying field title. The advantage of using Field Label is, SharePoint automatically adds red star besides field label to identify it as mandatory field if there is any. Here is most important part to understand. The “BaseFieldControl”. It will render the respective web controls according to type of the field. For example, if it’s single line of text, then Textbox, if it’s look up then it renders dropdown. Additionally, the “ControlMode” property tells compiler that which mode (display/edit/new) controls need to be rendered with. In display mode, it will render label with field value. In edit mode, it will render respective control with item value and in new mode it will render respective control with empty value. Please note that, it’s not always the case when dropdown field will be rendered for Lookup field or Choice field. You need to understand which controls are rendered for which list fields. I am planning to write a separate blog which I hope to publish it very soon. Moreover, we also need to assign list field specific properties like List Id, Field Name etc to identify which SharePoint List field is attached with the control.             switch (_ControlMode)             {                 case SPControlMode.New:                     fieldLabel.RenderContext = SPContext.GetContext(pWeb);                     fieldControl.RenderContext = SPContext.GetContext(pWeb);                     break;                 case SPControlMode.Edit:                 case SPControlMode.Display:                     fieldLabel.RenderContext = controlContext;                     fieldLabel.ItemContext = controlContext;                     fieldLabel.ItemId = ItemId;                       fieldControl.RenderContext = controlContext;                     fieldControl.ItemContext = controlContext;                     fieldControl.ItemId = ItemId;                     break;             }   Here, I have separate code for new mode and Edit/Display mode because we will not have Item Id to assign in New Mode. We also need to set CSS class for cell containing Label and Controls so that those controls get rendered with SharePoint theme.             spCellLabel.CssClass = "ms-formlabel";             spCellControl.CssClass = "ms-formbody";   “FieldDescription” control is used to add field description if there is any.    Now it’s time to add some more customization,               //Disable Name(Title) in Edit Mode             if (_ControlMode == SPControlMode.Edit && fieldDisplayName == "Name")             {                 TextBox txtTitlefield = (TextBox)fieldControl.Controls[0].FindControl("TextField");                 txtTitlefield.Enabled = false;             }   The above code will disable the title field in edit mode. You can add more code here to achieve more customization according to your requirement. Some of the examples are as follow:             //Adding post back event on UserField to auto populate some other dependent field             //in new mode and disable it in edit mode             if (_ControlMode != SPControlMode.Display && fieldDisplayName == "Manager")             {                 if (fieldControl.Controls[0].FindControl("UserField") != null)                 {                     PeopleEditor pplEditor = (PeopleEditor)fieldControl.Controls[0].FindControl("UserField");                     if (_ControlMode == SPControlMode.New)                         pplEditor.AutoPostBack = true;                     else                         pplEditor.Enabled = false;                 }             }               //Add JavaScript Event on Dropdown field. Don't forget to add the JavaScript function on the page.             if (_ControlMode == SPControlMode.Edit && fieldDisplayName == "Designation")             {                 DropDownList ddlCategory = (DropDownList)fieldControl.Controls[0];                 ddlCategory.Attributes.Add("onchange", string.Format("javascript:DropdownChangeEvent('{0}');return false;", ddlCategory.ClientID));             }    Following are the screenshots of my Custom ListForm WebPart. Let’s play a game, check out your OOB List forms of SharePoint, compare with these screens and find out differences.   DispForm.aspx:   EditForm.aspx:   NewForm.aspx:   Enjoy the SharePoint Soup!!! ­­­­­­­­­­­­­­­­­­­­

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