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  • Which of these is pythonic? and Pythonic vs. Speed

    - by Kashyap Nadig
    Hi! I'm new to python and just wrote this module level function: def _interval(patt): """ Converts a string pattern of the form '1y 42d 14h56m' to a timedelta object. y - years (365 days), M - months (30 days), w - weeks, d - days, h - hours, m - minutes, s - seconds""" m = _re.findall(r'([+-]?\d*(?:\.\d+)?)([yMwdhms])', patt) args = {'weeks': 0.0, 'days': 0.0, 'hours': 0.0, 'minutes': 0.0, 'seconds': 0.0} for (n,q) in m: if q=='y': args['days'] += float(n)*365 elif q=='M': args['days'] += float(n)*30 elif q=='w': args['weeks'] += float(n) elif q=='d': args['days'] += float(n) elif q=='h': args['hours'] += float(n) elif q=='m': args['minutes'] += float(n) elif q=='s': args['seconds'] += float(n) return _dt.timedelta(**args) My issue is with the for loop here i.e the long if elif block, and was wondering if there is a more pythonic way of doing it. So I re-wrote the function as: def _interval2(patt): m = _re.findall(r'([+-]?\d*(?:\.\d+)?)([yMwdhms])', patt) args = {'weeks': 0.0, 'days': 0.0, 'hours': 0.0, 'minutes': 0.0, 'seconds': 0.0} argsmap = {'y': ('days', lambda x: float(x)*365), 'M': ('days', lambda x: float(x)*30), 'w': ('weeks', lambda x: float(x)), 'd': ('days', lambda x: float(x)), 'h': ('hours', lambda x: float(x)), 'm': ('minutes', lambda x: float(x)), 's': ('seconds', lambda x: float(x))} for (n,q) in m: args[argsmap[q][0]] += argsmap[q][1](n) return _dt.timedelta(**args) I tested the execution times of both the codes using timeit module and found that the second one took about 5-6 seconds longer (for the default number of repeats). So my question is: 1. Which code is considered more pythonic? 2. Is there still a more pythonic was of writing this function? 3. What about the trade-offs between pythonicity and other aspects (like speed in this case) of programming? p.s. I kinda have an OCD for elegant code. EDITED _interval2 after seeing this answer: argsmap = {'y': ('days', 365), 'M': ('days', 30), 'w': ('weeks', 1), 'd': ('days', 1), 'h': ('hours', 1), 'm': ('minutes', 1), 's': ('seconds', 1)} for (n,q) in m: args[argsmap[q][0]] += float(n)*argsmap[q][1]

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  • Double Timezone offset

    - by gAMBOOKa
    I have a timezone name and I want the name of the timezone double its offset. For instance, Asia/Dubai is +4, I want to double that to +8... and have it resolved to Asia/HonkKong Language: PHP Here's a sample of what it would look like: $timezone = "Asia/Dubai" $offset = $timezone->getOffset(); $offset *= 2; $timezone = $offset->getTimeZone(); Output: Asia/HonkKong

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  • Time zone for Force.com API fiscal date literals?

    - by Nick
    I have a question about fiscal date literals in the Force.com API (http://www.salesforce.com/us/developer/docs/api/Content/sforce_api_calls_soql_select_dateformats.htm): For which time zone are date ranges calculated? For example, suppose we execute the query: SELECT Id FROM Opportunity WHERE CloseDate = THIS_FISCAL_QUARTER where, according to our company's fiscal settings, THIS_FISCAL_QUARTER runs from Jan 1 to Mar 31. Does the range for THIS_FISCAL_QUARTER use... the user's time zone? For example, if the user's time zone is GMT-8, THIS_FISCAL_QUARTER = Jan 1 00:00 GMT-8 to Mar 31 23:59 GMT-8 (or Jan 1 08:00 UTC to Mar 31 07:59 UTC) the company's default time zone (according to the company profile)? For example, if the company's default time zone is GMT-8, THIS_FISCAL_QUARTER = Jan 1 00:00 GMT-8 to Mar 31 23:59 GMT-8 (or Jan 1 08:00 UTC to Mar 31 07:59 UTC) UTC? THIS_FISCAL_QUARTER = Jan 1 00:00 UTC to Mar 31 23:59 UTC something else?

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  • Why Java SimpleDateFormat().parse() is printing weird formate?

    - by MAK
    My input is String formated as the following: 3/4/2010 10:40:01 AM 3/4/2010 10:38:31 AM My code is: DateFormat dateFormat = new SimpleDateFormat("dd/mm/yyyy hh:mm:ss aa"); try { Date today = dateFormat.parse(time); System.out.println("Date Time : " + today); } catch (ParseException e) { e.printStackTrace(); } the output is: Sun Jan 03 10:38:31 AST 2010 Sun Jan 03 10:40:01 AST 2010 I'm not sure from where the day (Sun) came from? or (AST)? and why the date is wrong? I just wanted to keep the same format of the original String date and make it into a Date object. I'm using Netbeans 6.8 Mac version.

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  • simpledateformat parsing date with 'Z' literal

    - by DanInDC
    I am trying to parse a date that looks like this: 2010-04-05T17:16:00Z This is a valid date per http://www.ietf.org/rfc/rfc3339.txt. The 'Z' literal "imply that UTC is the preferred reference point for the specified time." If I try to parse it using SimpleDateFormat and this pattern: yyyy-MM-dd'T'HH:mm:ss It will be parsed as a Mon Apr 05 17:16:00 EDT 2010 SimpleDateFormat is unable to parse the string with these patterns: yyyy-MM-dd'T'HH:mm:ssz yyyy-MM-dd'T'HH:mm:ssZ I can explicitly set the TimeZone to use on the SimpleDateFormat to get the expected output, but I don't think that should be necessary. Is there something I am missing? Is there an alternative date parser?

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  • How do you convert date taken from a bash script to milliseconds in a Java program?

    - by Matt Pascoe
    I am writing a piece of code in Java that needs to take a time sent from a bash script and parse the time to milliseconds. When I check the millisecond conversion on the date everything is correct except for the month I have sent which is January instead of March. Here is the variable I create in the bash script, which later in the script I pass to the Java program: TIME=`date +%m%d%Y_%H:%M:%S` Here is the Java code which parses the time to milliseconds: String dt = "${scriptstart}"; java.text.SimpleDateFormat scriptStart = new java.text.SimpleDateFormat("MMDDyyyy_HH:mm:ss"); long start = scriptStart.parse(dt).getTime(); The goal of this statement is to find the elapsed time between the start of the script and the current system time. To troubleshoot this I printed out the two: System Time = 1269898069496 (converted = Mon Mar 29 2010 16:27:49 GMT-0500 (Central Daylight Time)) Script Start = 03292010_16:27:45 Script Start in Milli = 1264804065000 (Converted = Fri Jan 29 2010 16:27:45 GMT-0600 (Central Standard Time))

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  • Rows in their own columns depending on their date and simbolized by 'x'

    - by Chandradyani
    Dear All, please help me since I'm newbie in SQL Server. I have a select query that currently produces the following results: DoctorName Team Visit date dr. As A 5 dr. Sc A 4 dr. Gh B 6 dr. Nd C 31 dr As A 7 Using the following query: SELECT d.DoctorName, t.TeamName, ca.VisitDate FROM cActivity AS ca INNER JOIN doctor AS d ON ca.DoctorId = d.Id INNER JOIN team AS t ON ca.TeamId = t.Id WHERE ca.VisitDate BETWEEN '1/1/2010' AND '1/31/2010' I want to produce the following: DoctorName Team 1 2 3 4 5 6 7 ... 31 Visited dr. As A x x ... 2 times dr. Sc A x ... 1 times dr. Gh B x ... 1 times dr. Nd C ... X 1 times

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  • Next month, same day in PHP

    - by Guillermo
    I got a last time (and urgent) requeriment of an "event" that needs to be scheduled the same day of every month. Say of you set the start date on the 1st May you should get the next events on the 1st of Jun, 1 Jul etc. The problem comes with a start date on the 31st (the next ones could be 30 or 28 depending on the month) Considering that there are months with different numbers of days (28,30,31) depending on the month itself and the year... what would ba an easy way to setup this? Consider the following (and flawed) nextmonth function: $events = array() function nextmonth($date) { return $date+(60*60*24*30); } $curr = $start; while($curr < $end) { $events[ = $curr; $curr = nextmonth($curr); } Edited to add: The problem for me is, simply enought, is to solve what the number of days of any given month is and thus get the next corresponding date..

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  • Get Date Strings for draw_calendar() Function

    - by Brandon
    I'm using the David Walsh PHP calendar script and need to format my date arguments like this: draw_calendar(7,2009); I want to get today's Month and Year as well as the next month and the month after that (so current month, plus one, plus one). How can I call the function three times in succession to generate these three calendars only knowing today's Month and Year? -Brandon

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  • Most idiomatic way to print a time difference in Java?

    - by Zombies
    I'm familiar with printing time difference in milliseconds: long time = System.currentTimeMillis(); //do something that takes some time... long completedIn = System.currentTimeMillis() - time(); But, is there a nice way print a complete time in a specified format (eg: HH:MM:SS) either using Apache Commons or even the dreaded platform API's Date/Time objects? In other words, what is the shortest, simplest, no nonsense way to write this in Java?

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  • Why Java SimpleDateFormat().parse() is giving weird formate?

    - by MAK
    My input is String formated as the following: 3/4/2010 10:40:01 AM 3/4/2010 10:38:31 AM My code is: DateFormat dateFormat = new SimpleDateFormat("dd/mm/yyyy hh:mm:ss aa"); try { Date today = dateFormat.parse(time); System.out.println("Date Time : " + today); } catch (ParseException e) { e.printStackTrace(); } the output is: Sun Jan 03 10:38:31 AST 2010 Sun Jan 03 10:40:01 AST 2010 I'm not sure from where the day (Sun) came from? or (AST)? and why the date is wrong? I just wanted to keep the same format of the original String date and make it into a Date object. I'm using Netbeans 6.8 Mac version.

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  • Codeigniter or PHP Amazon API help

    - by faya
    Hello, I have a problem searching through amazon web servise using PHP in my CodeIgniter. I get InvalidParameter timestamp is not in ISO-8601 format response from the server. But I don't think that timestamp is the problem,because I have tryed to compare with given date format from http://associates-amazon.s3.amazonaws.com/signed-requests/helper/index.html and it seems its fine. Could anyone help? Here is my code: $private_key = 'XXXXXXXXXXXXXXXX'; // Took out real secret key $method = "GET"; $host = "ecs.amazonaws.com"; $uri = "/onca/xml"; $timeStamp = gmdate("Y-m-d\TH:i:s.000\Z"); $timeStamp = str_replace(":", "%3A", $timeStamp); $params["AWSAccesskeyId"] = "XXXXXXXXXXXX"; // Took out real access key $params["ItemPage"] = $item_page; $params["Keywords"] = $keywords; $params["ResponseGroup"] = "Medium2%2525COffers"; $params["SearchIndex"] = "Books"; $params["Operation"] = "ItemSearch"; $params["Service"] = "AWSECommerceService"; $params["Timestamp"] = $timeStamp; $params["Version"] = "2009-03-31"; ksort($params); $canonicalized_query = array(); foreach ($params as $param=>$value) { $param = str_replace("%7E", "~", rawurlencode($param)); $value = str_replace("%7E", "~", rawurlencode($value)); $canonicalized_query[] = $param. "=". $value; } $canonicalized_query = implode("&", $canonicalized_query); $string_to_sign = $method."\n\r".$host."\n\r".$uri."\n\r".$canonicalized_query; $signature = base64_encode(hash_hmac("sha256",$string_to_sign, $private_key, True)); $signature = str_replace("%7E", "~", rawurlencode($signature)); $request = "http://".$host.$uri."?".$canonicalized_query."&Signature=".$signature; $response = @file_get_contents($request); if ($response === False) { return "response fail"; } else { $parsed_xml = simplexml_load_string($response); if ($parsed_xml === False) { return "parse fail"; } else { return $parsed_xml; } } P.S. - Personally I think that something is wrong in the generation of the from the $string_to_sign when hashing it.

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  • Yet another date formatting problem :(

    - by Jonesy
    Hi folks, I seem to have a date formatting problem every day! I am querying a table and am getting a date back in the format dd/mm/yyyy (as a string btw). Brilliant! thats what I want. But, now I want to convert that string to a date so i can do dim dayNumber as integer = day.DayOfWeek But when I convert it to a date it changes it to #m/dd/yyyy#. AHHHH! how can I change this? Cheers

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