Search Results

Search found 3046 results on 122 pages for 'hibernate validator'.

Page 29/122 | < Previous Page | 25 26 27 28 29 30 31 32 33 34 35 36  | Next Page >

  • Hibernate Subquery and DetachedCriteria

    - by dawez
    I have created a DetachedCriteria that is retrieving estates that have the isApproved and isPublished set to true. It is defined in this way: DetachedCriteria activePublishedCriteria = DetachedCriteria.forClass(Estate.class) .add(Restrictions.eq("isApproved", true)) .add(Restrictions.eq("isPublished", true)) .setResultTransformer(Criteria.DISTINCT_ROOT_ENTITY); I would like to reuse this criteria in some of the queries. In this case I would like to replace the isApproved and isPublished restrictions with the DetachedCriteria Criteria criteria = getSession().createCriteria(Estate.class) .createAlias("city", "c") .add(Restrictions.eq("c.id", cityID)) // the following 2 lines should be use the DetachedCriteria .add(Restrictions.eq("isApproved", true)) .add(Restrictions.eq("isPublished", true)) .setProjection(Projections.rowCount()); return (Integer) criteria.list().get(0); Is there a way to do this ? Tried to use .add.Subqueries.geAll(.... But cannot make it work properly. I could not find proper documentation on the Subqueries in Hibernate. Tips are welcomed.

    Read the article

  • Spring/Hibernate/Junit example of testing DAO against HSQLDB

    - by Ryan P.
    Hi guys, I'm working on trying to implement a JUnit test to check the functionality of a DAO. (The DAO will create/read a basic object/table relationship in HSQLDB). The trouble I'm having is the persistence of the DAO (for the non-test code) is being completed through an in-house solution using Spring/Hibernate, which eliminates the usual *.hbm.xml templates that most examples I have found contain. Beacuse of this, I'm having some trouble understanding how to setup a JUnit test to implement the DAO to create/read (just very basic funtionality) to an in-memory HSQLDB. I have found a few examples, but the usage of the in-house persistence means I can't extend some of the classes the examples show (I can't seem to get the application-context.xml setup properly). Can anyone suggest any projects/examples I could take a look at (or any documentation) to further my understanding of the best way to implement this test functionality? I feel like this should be really simple, but I keep running into problems implementing the examples I have found. Thanks in advance!

    Read the article

  • Hibernate schema parameter doesn't work in @SequenceGenerator annotation

    - by tabdulin
    I hav the following code: @Entity @Table(name = "my_table", schema = "my_schema") @SequenceGenerator(name = "my_table_id_seq", sequenceName = "my_table_id_seq", schema = "my_schema") public class MyClass { @Id @GeneratedValue(generator = "my_table_id_seq", strategy = GenerationType.SEQUENCE) private int id; } Database: Postgresql 8.4, Hibernate annotations 3.5.0-Final. When saving the object of MyClass it generates the following SQL query: select nextval('my_table_id_seq') So there is no schema prefix and therefore the sequence cannot be found. When I write the sequenceName like sequenceName = "my_schema.my_table_id_seq" everything works. Do I have misunderstandings for meaning of schema parameter or is it a bug? Any ideas how to make schema parameter working?

    Read the article

  • list-index hibernate ?

    - by kumar kasimala
    Hi I am bit confusion of list index type,my mapping file has like below <list name="transactionItems" cascade="save-update,delete-orphan" lazy="false"> <key column="TRANSACTION_ID" /> <list-index column="IDX" /> <one-to-many class="TransactionItem" /> </list> whenever hibernate load a mapped object,its through exception null index column for collection:transactionItems please suggest me what can be the problem here. can you exaplain a bit about list-index? thanks & Regards kumar kasiamla India,Hyderabad.

    Read the article

  • Hibernate sequence should only generate when ID is <=0

    - by Tim Leys
    Hi all, I'm using the folowing sequence in my code. (I got the sequence and @Id @SequenceGenerator(name = "S912_PRO_SEQ", sequenceName = "S912_PRO_SEQ", allocationSize = 1) @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "S912_PRO_SEQ") @Column(name = "PRO_ID", unique = true, nullable = false, precision = 9, scale = 0) public int getId() { return this.id; } And using the following sequence / triggers in my DB. CREATE SEQUENCE S912_PRO_SEQ nomaxvalue minvalue 20; CREATE OR REPLACE TRIGGER S912_PRO_B_I_TRG BEFORE INSERT ON S912_project REFERENCING OLD AS OLD NEW AS NEW FOR EACH ROW ENABLE begin IF :NEW.pro_ID IS NULL THEN select S912_PRO_SEQ.nextval into :new.pro_ID from dual; END IF; end; I was wondering if there is a way to let hibernate generate a sequence ONLY if the ID is <=0 (not set) or if the ID already exists. I know for most cases my trigger would fix the situation. But I do not want to rely completely on it. I hope someone can help me out :p

    Read the article

  • hibernate show real sql

    - by tommaso
    Hi all, if I set <property name="show_sql">true</property> in my hibernate.cfg.xml configuration file in the console I can see the sql. But it's not REAL sql... Can I see the SQL code that will be passed directly to database? Example: I see select this_.code from true.employee this_ where this_.code=? Can I see select employee.code from employee where employee.code=12 the real sql? thanks!

    Read the article

  • Specifying distinct sequence per table in Hibernate on subclasses

    - by gutch
    Is there a way to specify distinct sequences for each table in Hibernate, if the ID is defined on a mapped superclass? All entities in our application extend a superclass called DataObject like this: @MappedSuperclass public abstract class DataObject implements Serializable { @Id @GeneratedValue(strategy = GenerationType.SEQUENCE) @Column(name = "id") private int id; } @Entity @Table(name = "entity_a") public class EntityA extends DataObject { ... } @Entity @Table(name = "entity_b") public class EntityB extends DataObject { ... } This causes all entities to use a shared sequence, the default hibernate_sequence. What I would like to do is use a separate sequence for each entity, for example entity_a_sequence and entity_b_sequence in the example above. If the ID were specified on the subclasses then I could use the @SequenceGenerator annotation to specify a sequence for each entity, but in this case the ID is on the superclass. Given that ID is in the superclass, is there a way I can use a separate sequence for each entity — and if so, how? (We are using PostgreSQL 8.3, in case that's relevant)

    Read the article

  • org.hibernate.HibernateException: Error while accessing enum.values(): class com.mksoft.fbautomate.d

    - by Misha Koshelev
    This error is driving me nuts!!! Caused by: java.lang.NoSuchMethodException: com.mksoft.fbautomate.domain.Account$Type.values() The same exact class works fine in a separate Groovy file. Any ideas/help much appreciated. Most confusing... http://java.sun.com/j2se/1.5.0/docs/api/java/lang/Enum.html has no values() method! Here is my class: @Entity class Account { @Id @GeneratedValue(strategy=GenerationType.AUTO) public Long id enum Type {MYVALUE} @Enumerated(EnumType.STRING) public Type type public String email // @org.hibernate.annotations.Type(type="encryptedString") public String pass public String fullName String toString() { "type:\""+type+"\",email:\""+email+"\""+",fullName=\""+fullName+"\"" } } Thank you! Misha

    Read the article

  • Ignore Hibernate @Where annotation

    - by Zecrates
    I have an Entity which has an association to another Entity annotated with @Where, like so public class EntityA { @OneToMany @Where(...) private List<EntityB> entityBList; } Recently the inevitable has happened, I need to load EntityB's that don't conform to the @Where clause. I could remove the @Where annotation, but it is used a lot, so ideally I don't want to do that. Apart from loading the list of EntityB's manually, with another query, what are my options? Can I tell Hibernate to ignore the @Where annotation?

    Read the article

  • Calculated property with JPA / Hibernate

    - by Francois
    My Java bean has a childCount property. This property is not mapped to a database column. Instead, it should be calculated by the database with a COUNT() function operating on the join of my Java bean and its children. It would be even better if this property could be calculated on demand / "lazily", but this is not mandatory. In the worst case scenario, I can set this bean's property with HQL or the Criteria API, but I would prefer not to. The Hibernate @Formula annotation may help, but I could barely find any documentation. Any help greatly appreciated. Thanks.

    Read the article

  • Hibernate -using Table per subclass - how to link an existing superclass object to a sibclass object

    - by Chandni
    Hi, I have a User hibernate class, Clerk class and Consumer class. All these maps to their own tables in database. The User PK also acts as Clerk's and Consumer's PK. So now my problem is that if a user is initially a Clerk, he has a record in Users table and Clerks table. If that user wants to become a consumer, I want to link that User's record to the new Consumer's record. So even if I pass the userId to the consumer's record, it treats it as a new User to be persisted and gives a duplicate_key exception. How do I tell Hiernate to link the same user object with this new Consumer object. Thanks in advance, -Chandni

    Read the article

  • Fill object data from several tables using hibernate mapping

    - by Udo Fholl
    Hi all, I'd like to know if it is possible to fill up a class data from database using the hibernate hbm (mapping). For instance: public class someClass { List<OtherClass> otherClasses; List<YetAnotherClass> yetAnotherClasses; //Constructors ? class OtherClass { String name; //setters, getters } class YetAnotherClass { String name; //setters, getters } //setters, getters } Using an hbm can I fill in the data from tables OTHER_CLASS_TABLE and YET_ANOTHER_CLASS_TABLE? I have no such SOME_CLASS_TABLE since this info is for viewing only. I've been playing with the <join table=""><subselect> and different constructors... But it is not working Thanks! Sorry for my english!

    Read the article

  • question on database query using hibernate in java with annotations

    - by molleman
    Hello, simple question regarding HQL(Hibernate query language) so i have user class , that can hold a list of Projects, how do i take this out of the database depending on a username, this is how i take out my user String username = "stephen"; YFUser user = (YFUser) session.createQuery("select u FROM YFUser u where u.username = :username").setParameter("username", name).uniqueResult(); but i want to take out the list of projects here is the projects list within the class YFUser(my user class); how would i query the database to get this list of projects @Entity @Table(name = "yf_user_table") public class YFUser implements Serializable,ILightEntity { ......... @OneToMany(cascade = CascadeType.ALL,fetch = FetchType.LAZY) @JoinTable(name = "YFUSER_JOIN_PROJECT", joinColumns = { @JoinColumn(name = "user_id") }, inverseJoinColumns = { @JoinColumn(name = "project_id") }) private List<Project> projects = new ArrayList<Project>();

    Read the article

  • hibernate formula with column

    - by coolguy
    I have a table with a column that will be encrypted by a trigger after the record is inserted. When I read the column, I need to apply a decrypt function in the hibernate domain class. While saving the object, the value of the column will be saved as such. While reading the column, apply a database function on the read data. @Formula and @Column annotation cannot be applied to an attribute in the entity class. How do I achieve this functionality without using one attribute for saving and another one with @Formula for reading it?

    Read the article

  • Mixing table per subclass and per hierarchy in hibernate

    - by Xelluloid
    In my database there are two three tables. The first one, table ABSTRACT, holds three columns id, type, someText This table contains all abstract information for the abstract class abstract. Now the two tables CONCRETEONE and CONCRETETWO contain all information for the concrete classes concreteOne and concreteTwo. Now I know I could use the table per subclass strategy from hibernate to create a mapping with inheritance. But as I have a column that marks the type of the concrete implementation could it be possible to create some mixed behaviour like a table per subclass strategy with an discriminator?

    Read the article

  • Synchronization between hibernate running locally and on a server

    - by linead
    Is there an easy way using a library to facilitate the synchronization of two hibernate instances. One running locally on a client and one running on a central server exposed via a web service. So Client tracks changes it makes, pushes them to the Server. The server ensures that the clients is not updating out of sync objects and stores the clients changes. The Client can also sync with the Server so that it can see the changes made by other clients. The idea is that the client can be run offline, without access to the server and only come online to synchronize when needed.

    Read the article

  • Need to map classes to different databases at runtime in Hibernate

    - by serg555
    I have MainDB database and unknown number (at compile time) of UserDB_1, ..., UserDB_N databases. MainDB contains names of those UserDB databases in some table (new UserDB can be created at runtime). All UserDB have exactly the same table names and fields. How to handle such situation in Hibernate? (database structure cannot be changed). Currently I am planning to create generic User classes not mapped to anything and just use native SQL for all queries: session.createSQLQuery("select * from " + db + ".user where id=1") .setResultTransformer(Transformers.aliasToBean(User.class)); Is there anything better I can do? Ideally I would want to have mappings for UserDB tables and relations and use HQL on required database.

    Read the article

  • Hibernate/JPA and PostgreSQL - Primary Key?

    - by Shadowman
    I'm trying to implement some basic entities using Hibernate/JPA. Initially the code was deployed on MySQL and was working fine. Now, I'm porting it over to use PostgreSQL. In MySQL, my entity class defines its primary key as an auto-incrementing long value with the following syntax: @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; However, I've found that I get errors with PostgreSQL when I try and insert numerous records at a time. What do I need to annotate my primary key with to get the same auto-incrementing behavior in PostgreSQL as I have with MySQL? Thanks for any help you can provide!

    Read the article

  • Hierarchical Hibernate, how many queries are executed?

    - by ghost1
    So I've been dealing with a home brew DB framework that has some seriously flaws, the justification for use being that not using an ORM will save on the number of queries executed. If I'm selecting all possibile records from the top level of a joinable object hierarchy, how many separate calls to the DB will be made when using an ORM (such as Hibernate)? I feel like calling bullshit on this, as joinable entities should be brought down in one query , right? Am I missing something here? note: lazy initialization doesn't matter in this scenario as all records will be used.

    Read the article

  • Transactions in hibernate

    - by kumar1425
    Hi I new to hibernate In my project, i need to handle transactions. How to handle declarative transactions with in two classes Examples: //class 1 class A{ createA() { insert(A); } } //class 2 class B { createB() { insert(B); } } //class 3 @Transaction(Exception.class) class C { test() { create(A); create(B); } } As per the above code is there any possibility to handle transactions, in such a way that if the insert in classA success and the insert in the classB fails then the transaction should rollback and remove the record inserted in the table A corresponding to the Class A please help me with this using declarative transactions.... Thanks in adavace....

    Read the article

  • Hibernate/JPA - annotating bean methods vs fields

    - by Benju
    I have a simple question about usage of Hibernate. I keep seeing people using JPA annotations in one of two ways by annotating the fields of a class and also by annotating the get method on the corresponding beans. My question is as follows: Is there a difference between annotating fields and bean methods with JPA annoations such as @Id. example: @Entity public class User { **@ID** private int id; public int getId(){ return this.id; } public void setId(int id){ this.id=id; } } -----------OR----------- @Entity public class User { private int id; **@ID** public int getId(){ return this.id; } public void setId(int id){ this.id=id; } }

    Read the article

  • Hibernate multi column discriminator

    - by shikarishambu
    I have a single lookup table that manages all lookups - legacy and new lookup table structure is context,name, code, value context is either legacy or new name is the name of the lookup - state, status etc...for example code is the code and value is the value associated with the code Is there a way to specify multiple columns as discriminators so that I can get all legacy state code/values or all new status code/values. Is there a different way to do this if discriminators cannot do it? <class name="com.company.domain.Lookup"> <id name="Id" column="id" type="big_integer"> <generator class="org.hibernate.id.TableHiLoGenerator" /> </id> <discriminator column="context" insert="false" /> <property name="code" type="string"/> <property name="value" type="string"/> <property name="desc" type="string"/> <subclass name="com.company.domain.LegacyLookup" discriminator-value="legacy">

    Read the article

  • hibernate versioning parent entity

    - by Priit
    Consider two entities Parent and Child. Child is part of Parent's transient collection Child has a ManyToOne mapping to parent with FetchType.LAZY Both are displayed on the same form to a user. When user saves the data we first update Parent instance and then Child collection (both using merge). Now comes the tricky part. When user modifies only Child property on the form then hibernate dirty checking does not update Parent instance and thus does not increase optimistic locking version number for that entity. I would like to see situation where only Parent is versioned and every time I call merge for Parent then version is always updated even if actual update is not executed in db.

    Read the article

  • Java Hibernate id auto increment

    - by vinise
    Hy I'v a little problem with hibernate on netbeans. I've a table with an Auto increment id : CREATE TABLE "DVD" ( "DVD_ID" INT not null primary key GENERATED ALWAYS AS IDENTITY (START WITH 1, INCREMENT BY 1), "TITLE" VARCHAR(150), "COM" LONG VARCHAR, "COVER" VARCHAR(150) ); But this auto increment is not properly detected with Reverse Engineering. I get a map file with this : <id name="dvdId" type="int"> <column name="DVD_ID" /> <generator class="assigned" /> </id> i've looked on google and on this site ... foud some stuf but i'm still stuck.. i've tried to add insert="false" update="false" on the map file but i get back : Caused by: org.xml.sax.SAXParseException: Attribute "insert" must be declared for element type "id". Anny help will be pleased Vincent

    Read the article

  • [Hibernate] Problem with saveOrUpdate()

    - by kunkanwan
    Hi, I've problem with Hibernate. I have a class User class User { int id; String name; } where id is native generator in User.hbm.xml , and name is primary-key in DB. In my database , I saved some information about Users. Than, I want to connect with this information about User. For example in my DB i have row INSERT INTO User VALUES ('Bill'); Main.java User bill = new User(); bill.setName("Bill"); session.saveOrUpdate(bill); This code always trying insert bill to database , rather than update when row about Bill exists in DB... Could you help me ? Thank you for advance.

    Read the article

< Previous Page | 25 26 27 28 29 30 31 32 33 34 35 36  | Next Page >