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  • regex help using repreated groups

    - by Chris H
    I'm trying to match rc-update -s output in python. m = re.match(r"^\s*(\w+)\s*\|{\s*(\w+)\s*}*$", " network | level1 level2 leveln ") but m is always None the hard part for me is getting the regex to match the n levels. I thought that using {}* would match the n levels, but as soon as I add the {} nothing matches. thanks.

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  • regex part of url

    - by kyle
    So I'm trying to get the id from a url for youtube.. here is the url http://gdata.youtube.com/feeds/api/videos/kffacxfA7G4/related?v=2 then there's also - in the url too. it wouldn't let me post another url but it's the same as above but with the id ucvkO0x-mL4 how can I grab between videos/ and /related (the id) with regex? I tried to use txt2re.com which is what I always use, but it's not working for this case.. thanks!

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  • How Does ont use RegEX in C++?

    - by ML
    How does one use RegEx in C++? I suppose there is Boost or PCRE.. But what if I wanted to write my own for color syntax highlighting code opened in an editor? How would I do this from scratch?

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  • Allow sudo on specific file from active directory group

    - by tubaguy50035
    I have an Ubuntu Server 12.04 box that has active directory integration running on it. I want to allow a certain active directory group access to execute a script as sudo. I want to do something like this: %programmers ALL=NOPASSWD: /usr/local/bin/createSambaShare.php When I log in with my active directory user and issue groups I do not see the group programmers, but I am a part of the programmers group within active directory. I've set up the group under the Unix attributes tab and given it an id of 1000 and added my user to it. My first thought was that I needed to add the group to the Ubuntu box. When I tried to do that, it told me that the programmers group already existed. What am I missing here?

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  • How do I set a Group Policy's Password Policy in C#

    - by user343304
    I am trying to retrieve a group policy from a Windows Server 2008 Active Directory and change the minimum password age, maximum password age, and minimum password length in a C# application. Is there a way to do this? So far I have only found out how to create new Group Policy objects using Interop.GPMGMTLib (gpmgmt.dll), yet I haven't figured out how to change the policy's password rules and I am not sure if there is an easier way.

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  • Log files for group policy application deployment

    - by Cyril
    I'm looking into using group policy to deploy a couple of applications. I want to have the log of each installation written to a shared folder on a file server for tracking purposes. I can create the log if I pass the appropriate parameters. For example: msiexec /i Package.msi /l*vx c:\Package.log However using group policy for the deployment, you can't pass any parameters to the installation file. Is there anyway to specify the log file location in the process of creating the msi package?

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  • SQL Group By Modulo of Row Count

    - by Alex Czarto
    I have the following sample data: Id Name Quantity 1 Red 1 2 Red 3 3 Blue 1 4 Red 1 5 Yellow 3 So for this example, there are a total of 5 Red, 1 Blue, and 3 Yellow. I am looking for a way to group them by Color, but with a maximum of 2 items per group (sorting is not important). Like so: Name QuantityInPackage Red 2 Red 2 Red 1 Blue 1 Yellow 2 Yellow 1 Any suggestions on how to accomplish this using T-SQL on MS-SQL 2005?

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  • SQL Server Update Group by

    - by Gerardo Abdo
    I'm trying to execute this on MS-SQL but returns me an error just at the Group by line update #temp Set Dos=Count(1) From Temp_Table2010 s where Id=s.Total and s.total in (Select Id from #temp) group by s.Total Do anyone knows how can I solve this problem having good performance.

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  • How to do a case sensitive GROUP BY?

    - by Abe Miessler
    If I execute the code below: with temp as ( select 'Test' as name UNION ALL select 'TEST' UNION ALL select 'test' UNION ALL select 'tester' UNION ALL select 'tester' ) SELECT name, COUNT(name) FROM temp group by name It returns the results: TEST 3 tester 2 Is there a way to have the group by be case sensitive so that the results would be: Test 1 TEST 1 test 1 tester 2

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  • Is it possible to have a local group for an LDAP user

    - by fakedrake
    I have an LDAP server to which i do not have full privileges and an ubuntu system with LDAP authentication to which i am root. Is it possible to add an LDAP user to a local group? (i dont know if i phrase this correctly but all i want is to have a user in LDAP in a group without edititing the actual database)

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  • Help with specific Regex: need to match multiple instances of multiple formats in a single string.

    - by KevenK
    I apologize for the terrible title...it can be hard to try to summarize an entire situation into a single sentence. Let me start by saying that I'm asking because I'm just not a Regex expert. I've used it a bit here and there, but I just come up short with the correct way to meet the following requirements. The Regex that I'm attempting to write is for use in an XML schema for input validation, and used elsewhere in Javascript for the same purpose. There are two different possible formats that are supported. There is a literal string, which must be surrounded by quotation marks, and a Hex-value string which must be surrounded by braces. Some test cases: "this is a literal string" <-- Valid string, enclosed properly in "s "this should " still be correct" <-- Valid string, "s are allowed within (if possible, this requirement could be forgiven if necessary) "{00 11 22}" <-- Valid string, {}'s allow in strings. Another one that can be forgiven if necessary I am bad output <-- Invalid string, no "s "Some more problemss"you know <-- Invalid string, must be fully contained in "s {0A 68 4F 89 AC D2} <-- Valid string, hex characters enclosed in {}s {DDFF1234} <-- Valid string, spaces are ignored for Hex strings DEADBEEF <-- Invalid string, must be contained in either "s or {}s {0A 12 ZZ} <-- Invalid string, 'Z' is not a valid Hex character To satisfy these general requirements, I had come up with the following Regex that seems to work well enough. I'm still fairly new to Regex, so there could be a huge hole here that I'm missing.: &quot;.+&quot;|\{([0-9]|[a-f]|[A-F]| )+\} If I recall correctly, the XML Schema regex automatically assumes beginning and end of line (^ and $ respectively). So, essentially, this regex accepts any string that starts and ends with a ", or starts and ends with {}s and contains only valid Hexidecimal characters. This has worked well for me so far except that I had forgotten about another (although less common, and thus forgotten) input option that completely breaks my regex. Where I made my mistake: Valid input should also allow a user to separate valid strings (of either type, literal/hex) by a comma. This means that a single string should be able to contain more than one of the above valid strings, separated by commas. Luckily, however, a comma is not a supported character within a literal string (although I see that my existing regex does not care about commas). Example test cases: "some string",{0A F1} <-- Valid {1122},{face},"peanut butter" <-- Valid {0D 0A FF FE},"string",{FF FFAC19 85} <-- Valid (Spaces don't matter in Hex values) "Validation is allowed to break, if a comma is found not separating values",{0d 0a} <-- Invalid, comma is a delimiter, but "Validation is allowed to break" and "if a comma..." are not marked as separate strings with "s hi mom,"hello" <-- Invalid, String1 was not enclosed properly in "s or {}s My thoughts are that it is possible to use commas as a delimiter to check each "section" of the string to match a regex similar to the original, but I just am not that advanced in regex yet to come up with a solution on my own. Any help would be appreciated, but ultimately a final solution with an explanation would just stellar. Thanks for reading this huge wall of text!

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  • How to find the latest row for each group of data

    - by Jason
    Hi All, I have a tricky problem that I'm trying to find the most effective method to solve. Here's a simplified version of my View structure. Table: Audits AuditID | PublicationID | AuditEndDate | AuditStartDate 1 | 3 | 13/05/2010 | 01/01/2010 2 | 1 | 31/12/2009 | 01/10/2009 3 | 3 | 31/03/2010 | 01/01/2010 4 | 3 | 31/12/2009 | 01/10/2009 5 | 2 | 31/03/2010 | 01/01/2010 6 | 2 | 31/12/2009 | 01/10/2009 7 | 1 | 30/09/2009 | 01/01/2009 There's 3 query's that I need from this. I need to one to get all the data. The next to get only the history data (that is, everything but exclude the latest data item by AuditEndDate) and then the last query is to obtain the latest data item (by AuditEndDate). There's an added layer of complexity that I have a date restriction (This is on a per user/group basis) where certain user groups can only see between certain dates. You'll notice this in the where clause as AuditEndDate<=blah and AuditStartDate=blah Foreach publication, select all the data available. select * from Audits Where auditEndDate<='31/03/10' and AuditStartDate='06/06/2009'; foreach publication, select all the data but Exclude the latest data available (by AuditEndDate) select * from Audits left join (select AuditId as aid, publicationID as pid and max(auditEndDate) as pend from Audit where auditenddate <= '31/03/2009' /* user restrict / group by pid) Ax on Ax.pid=Audit.pubid where pend!=Audits.auditenddate AND auditEndDate<='31/03/10' and AuditStartDate='06/06/2009' / user restrict */ Foreach publication, select only the latest data available (by AuditEndDate) select * from Audits left join (select AuditId as aid, publicationID as pid and max(auditEndDate) as pend from Audit where auditenddate <= '31/03/2009'/* user restrict / group by pid) Ax on Ax.pid=Audit.pubid where pend=Audits.auditenddate AND auditEndDate<='31/03/10' and AuditStartDate='06/06/2009' / user restrict */ So at the moment, query 1 and 3 work fine, but query 2 just returns all the data instead of the restriction. Can anyone help me? Thanks jason

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  • "Most popular" GROUP BY in LINQ?

    - by tags2k
    Assuming a table of tags like the stackoverflow question tags: TagID (bigint), QuestionID (bigint), Tag (varchar) What is the most efficient way to get the 25 most used tags using LINQ? In SQL, a simple GROUP BY will do: SELECT Tag, COUNT(Tag) FROM Tags GROUP BY Tag I've written some LINQ that works: var groups = from t in DataContext.Tags group t by t.Tag into g select new { Tag = g.Key, Frequency = g.Count() }; return groups.OrderByDescending(g => g.Frequency).Take(25); Like, really? Isn't this mega-verbose? The sad thing is that I'm doing this to save a massive number of queries, as my Tag objects already contain a Frequency property that would otherwise need to check back with the database for every Tag if I actually used the property. So I then parse these anonymous types back into Tag objects: groups.OrderByDescending(g => g.Frequency).Take(25).ToList().ForEach(t => tags.Add(new Tag() { Tag = t.Tag, Frequency = t.Frequency })); I'm a LINQ newbie, and this doesn't seem right. Please show me how it's really done.

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  • JavaScript - string regex backreferences

    - by quano
    You can backreference like this in JavaScript: var str = "123 $test 123"; str = str.replace(/(\$)([a-z]+)/gi, "$2"); This would (quite silly) replace "$test" with "test". But imagine I'd like to pass the resulting string of $2 into a function, which returns another value. I tried doing this, but instead of getting the string "test", I get "$2". Is there a way to achieve this? // Instead of getting "$2" passed into somefunc, I want "test" // (i.e. the result of the regex) str = str.replace(/(\$)([a-z]+)/gi, somefunc("$2"));

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  • Using RegEx to replace invalid characters

    - by yeahumok
    Hello I have a directory with lots of folders, subfolder and all with files in them. The idea of my project is to recurse through the entire directory, gather up all the names of the files and replace invalid characters (invalid for a SharePoint migration). However, i'm completely unfamiliar with Regular Expressions. The characters i need to get rid in filenames are: ~, #, %, &, *, { } , \, /, :, <, ?, -, | and "" I want to replace these characters with a blank space. I was hoping to use a string.replace() method to look through all these file names and do the replacement. So far, the only code i've gotten to is the recursion. I was thinking of the recursion scanning the drive, fetching the names of these files and putting them in a List. Can anybody help me with how to find/replace invalid chars with RegEx with those specific characters?

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  • Regex to replace relative link with root relative link

    - by Kendall Hopkins
    I have a string of text that contains html with all different types of links (relative, absolute, root-relative). I need a regex that can be executed by PHP's preg_replace to replace all relative links with root-relative links, without touching any of the other links. I have the root path already. Replaced links: <tag ... href="path/to_file.ext" ... > ---> <tag ... href="/basepath/path/to_file.ext" ... > Untouched links: <tag ... href="/any/path" ... > <tag ... href="protocol://domain.com/any/path" ... >

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  • PHP regex to match sentences that contain a year

    - by zen
    I need a regular expression that will extract sentences from text that contain a year in them. Example text: Next, in 1988 the Bradys were back again for a holiday celebration, "A Very Brady Christmas". Susan Olsen (Cindy) would be missing from this reunion, Jennifer Runyon took her place. This was a two hour movie in which the Bradys got together to celebrate Christmas, introducing the world to the spouses and children of the Brady kids. This movie was the highest rated TV-movie of 1988. If the example text was variable $string, I need it to return: $sentenceWithYear[0] = Next, in 1988 the Bradys were back again for a holiday celebration, "A Very Brady Christmas". $sentenceWithYear[1] = This movie was the highest rated TV-movie of 1988. If it's possible to retain the year via regex, I'd use the year within the sentence and eventually insert the sentences into a database like: INSERT INTO table_name (year, sentence) VALUES ('$year', '$sentenceWithYear[x]')

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  • regex to match trailing whitespace, but not lines which are entirely whitespace (indent placeholders

    - by Tim
    I've been trying to construct a ruby regex which matches trailing spaces - but not indentation placeholders - so I can gsub them out. I had this /\b[\t ]+$/ and it was working a treat until I realised it only works when the line ends are [a-zA-Z]. :-( So I evolved it into this /(?!^[\t ]+)[\t ]+$/ and it seems like it's getting better, but it still doesn't work properly. I've spent hours trying to get this to work to no avail. Please help. Here's some text test so it's easy to throw into Rubular, but the indent lines are getting stripped so it'll need a few spaces and/or tabs. Once lines 3 & 4 have spaces back in, it shouldn't match on lines 3-5, 7, 9. some test test some test test some other test (text) some other test (text) likely here{ dfdf } likely here{ dfdf } and this ; and this ; Alternatively, is there an simpler / more elegant way to do this?

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  • Help with password complexity regex

    - by Alex
    I'm using the following regex to validate password complexity: /^.*(?=.{6,12})(?=.*[0-9]{2})(?=.*[A-Z]{2})(?=.*[a-z]{2}).*$/ In a nutshell: 2 lowercase, 2 uppercase, 2 numbers, min length is 6 and max length is 12. It works perfectly, except for the maximum length, when I'm using a minimum length as well. For example: /^.*(?=.{6,})(?=.*[0-9]{2})(?=.*[A-Z]{2})(?=.*[a-z]{2}).*$/ This correctly requires a minimum length of 6! And this: /^.*(?=.{,12})(?=.*[0-9]{2})(?=.*[A-Z]{2})(?=.*[a-z]{2}).*$/ Correctly requires a maximum length of 12. However, when I pair them together as in the first example, it just doesn't work!! What gives? Thanks!

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  • Problem with Regex in .NET (C#)

    - by Craig Bovis
    I'm trying to write a a regex to validate a string to match the following rules. Must start with a-z (case insensitive) Must only contain a-z A-Z 0-9 . - I've put something together based on my limited knowledge and ran it through an online testing tool for a whole bunch of situations and the results were as I had hoped however when I place the pattern into my .NET code it doesn't match correctly. The pattern I am using is, [a-zA-Z][a-zA-Z0-9.\-]* Is this the correct pattern or am I barking up the wrong tree? Some examples of what I'm expecting. craig.bovis - VALID 24craig - INVALID craig@bovis - INVALID craig24 - VALID -craig24 - INVALID craig24.bovis-test - VALID

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  • Javascript Regex to convert dot notation to bracket notation

    - by Tauren
    Consider this javascript: var joe = { name: "Joe Smith", location: { city: "Los Angeles", state: "California" } } var string = "{name} is currently in {location.city}, {location.state}"; var out = string.replace(/{([\w\.]+)}/g, function(wholematch,firstmatch) { return typeof values[firstmatch] !== 'undefined' ? values[firstmatch] : wholematch; }); This will output the following: Joe Smith is currently in {location.city}, {location.state} But I want to output the following: Joe Smith is currently in Los Angeles, California I'm looking for a good way to convert multiple levels of dot notation found between braces in the string into multiple parameters to be used with bracket notation, like this: values[first][second][third][etc] Essentially, for this example, I'm trying to figure out what regex string and function I would need to end up with the equivalent of: out = values[name] + " is currently in " + values["location"]["city"] + values["location"]["state"];

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  • How to make regex variables to capture of routes

    - by Zephiro
    anyone can help me with this problem. example $uri = '/username/carlos'; => $routes[] = '/username/@name'; @name convert in variable $name capturing string "carlos" $routes[] = '/list/edit/@id:[0-9]{3}'; $routes[] = '/username/@name'; $routes[] = '/archive/*'; $routes[] = '/'; $uri = '/username/carlos'; foreach ( $routes as $pattern ) { if ( preg_match( '#^' . preg_replace( '#(?:{{)?@(\w+\b)(?:}})?#i', '(?P<\1>[\w\-\.!~\*\'"(),\s]+)', str_replace( '\*', '(.*)', preg_quote( $pattern, '/' ) ) ) . '\/?$#i', $uri, $matchs ) ) { //how to make regex for this to work : echo $name; // carlos =>$uri = '/username/carlos'; or matt => $uri = '/username/matt'; } } thanks for reading

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