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  • django inner redirects

    - by Zayatzz
    Hello I have one project that in my own development computer (uses mod_wsgi to serve the project) caused no problems. In live server (uses mod_fastcgi) it generates 500 though. my url conf is like this: # -*- coding: utf-8 -*- from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', url(r'^admin/', include(admin.site.urls)), url(r'^', include('jalka.game.urls')), ) and # -*- coding: utf-8 -*- from django.conf.urls.defaults import * from django.contrib.auth import views as auth_views urlpatterns = patterns('jalka.game.views', url(r'^$', view = 'front', name = 'front',), url(r'^ennusta/(?P<game_id>\d+)/$', view = 'ennusta', name = 'ennusta',), url(r'^login/$', auth_views.login, {'template_name': 'game/login.html'}, name='auth_login'), url(r'^logout/$', auth_views.logout, {'template_name': 'game/logout.html'}, name='auth_logout'), url(r'^arvuta/$', view = 'arvuta', name = 'arvuta',), ) and .htaccess is like that: Options +FollowSymLinks RewriteEngine on RewriteOptions MaxRedirects=10 # RewriteCond %{HTTP_HOST} . RewriteCond %{HTTP_HOST} ^www\.domain\.com RewriteRule (.*) http://domain.com/$1 [R=301,L] AddHandler fastcgi-script .fcgi RewriteCond %{HTTP_HOST} ^jalka\.domain\.com$ [NC] RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*) cgi-bin/fifa2010.fcgi/$1 [QSA,L] RewriteCond %{HTTP_HOST} ^subdomain\.otherdomain\.eu$ [NC] RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*) cgi-bin/django.fcgi/$1 [QSA,L] Notice, that i have also other project set up with same .htaccess and that one is running just fine with more complex urls and views fifa2010.fcgi: #!/usr/local/bin/python # -*- coding: utf-8 -*- import sys, os DOMAIN = "domain.com" APPNAME = "jalka" PREFIX = "/www/apache/domains/www.%s" % (DOMAIN,) # Add a custom Python path. sys.path.insert(0, os.path.join(PREFIX, "htdocs/django/Django-1.2.1")) sys.path.insert(0, os.path.join(PREFIX, "htdocs")) sys.path.insert(0, os.path.join(PREFIX, "htdocs/jalka")) # Switch to the directory of your project. (Optional.) os.chdir(os.path.join(PREFIX, "htdocs", APPNAME)) # Set the DJANGO_SETTINGS_MODULE environment variable. os.environ['DJANGO_SETTINGS_MODULE'] = "%s.settings" % (APPNAME,) from django.core.servers.fastcgi import runfastcgi runfastcgi(method="threaded", daemonize="false") Alan

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  • Zend Layout and Bootstrapping

    - by emeraldjava
    So i'm using the standard Zend Layout for my site. I have a number of custom controllers and views, and the content of these pages is displayed, but the details in the head element of the layout.phtml are not shown. Do i need to manually associate the Zend_Layout with each specific controller?. I expected since the layout is loaded via the bootstrap this should be available for free. My app.ini file has # layout resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts" resources.layout.layout = "layout" #resources.view[] = # Views resources.view.encoding = "UTF-8" resources.view.basePath = APPLICATION_PATH "/views/" my layout.phtml <?php echo $this->doctype() ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <?php echo $this->headTitle() ?> <?php echo $this->jQuery();?> </head> <!-- application/layouts/scripts/layout.phtml --> <body> <div id="content"> <?php echo $this->layout()->content ?> </div> </body>

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  • Android Multiple Handlers Design Question

    - by Soumya Simanta
    This question is related to an existing question I asked. I though I'll ask a new question instead of replying back to the other question. Cannot "comment" on my previous question because of a word limit. Marc wrote - I've more than one Handlers in an Activity." Why? If you do not want a complicated handleMessage() method, then use post() (on Handler or View) to break the logic up into individual Runnables. Multiple Handlers makes me nervous. I'm new to Android. Is having multiple handlers in a single activity a bad design ? I'm new to Android. My question is - is having multiple handlers in a single activity a bad design ? Here is the sketch of my current implementation. I've a mapActivity that creates a data thread (a UDP socket that listens for data). My first handler is responsible for sending data from the data thread to the activity. On the map I've a bunch of "dynamic" markers that are refreshed frequently. Some of these markers are video markers i.e., if the user clicks a video marker, I add a ViewView that extends a android.opengl.GLSurfaceView to my map activity and display video on this new vide. I use my second handler to send information about the marker that the user tapped on ItemizedOverlay onTap(int index) method. The user can close the video view by tapping on the video view. I use my third handler for this. I would appreciate if people can tell me what's wrong with this approach and suggest better ways to implement this. Thanks.

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  • How to unit test this simple ASP.NET MVC controller

    - by Frank Schwieterman
    Lets say I have a simple controller for ASP.NET MVC I want to test. I want to test that a controller action (Foo, in this case) simply returns a link to another action (Bar, in this case). How would you test this? (either the first or second link) My implementation has the same link twice. One passes the url throw ViewData[]. This seems more testable to me, as I can check the ViewData collection returned from Foo(). Even this way though, I don't know how to validate the url itself without making dependencies on routing. The controller: public class TestController : Controller { public ActionResult Foo() { ViewData["Link2"] = Url.Action("Bar"); return View("Foo"); } public ActionResult Bar() { return View("Bar"); } } the "Foo" view: <%@ Page Title="" Language="C#" Inherits="System.Web.Mvc.ViewPage" MasterPageFile="~/Views/Shared/Site.Master"%> <asp:Content ContentPlaceHolderID="MainContent" runat="server"> <%= Html.ActionLink("link 1", "Bar") %> <a href="<%= ViewData["Link2"]%>">link 2</a> </asp:Content>

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  • GridView onTouch

    - by Jeff
    I am trying to set up a GridView of buttons that responds to onTouch. For example, if I swipe my finger across the screen horizontally, vertically or diagonally then I want the buttons which were touched to be selected. I tried setting OnTouchListener's for the buttons, but this didn't work, only the first button in the drag event received the onTouch events. Next I tried creating an OnTouchListener for the GridView and then using the X,Y coords to determine which buttons where touched. This doesn't seem to work either since the MOTION_DOWN events are only passed to the GridView's onTouch() if I start the drag on the very edge of the GridView. In fact if I drag my finger horizontally across the grid, the onTouch events aren't fired at all unless I start the drag at the edge of the GridView. Does anyone know of a better way to do this? Thanks in advance. gridview.setOnTouchListener(new View.OnTouchListener() { @Override public boolean onTouch(@SuppressWarnings("unused") View view, MotionEvent event) { float X = event.getX(); float Y = event.getY(); switch (event.getAction()) { case MotionEvent.ACTION_DOWN: System.out.println("Down: " + X + "," + Y); break; case MotionEvent.ACTION_MOVE: System.out.println("Move: " + X + "," + Y); break; case MotionEvent.ACTION_UP: System.out.println("Up: " + X + "," + Y); break; } return true; } }

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  • Zend Framework cleaning default routes when adding other

    - by Renato Aquino
    I have the following problem with Zend Framework. My project has several controllers like Video,Category and Post. The VideoController has an Action called categorylist, so the default URL/Route becomes /video/categorylist Since the action requires 3 parameters I whant to add one simple route: $router->addRoute( 'categorylist', new Zend_Controller_Router_Route('categorylist/:category/:page/:per_page', array('controller' => 'video', 'action' => 'categorylist','page'=>1,'per_page'=>6,'category'=>1)) ); With this I got my URL like www.siteurl.com/categorylist/42/1/6 but, the View Helper URL got crazy, and every url for the other controllers I try to echo it´s redirected to the categorylist route. So when I try this: <?= $this->url(array("controller"=> "video", "action" =>"view",'category'=>1),null,true)?> The expected result its /video/view/category/1, but I got /categorylit only. I tryied to debug the default routes but I got an empty array. print_r($ctrl->getRouter()->getRoutes()); Does anyone have some clue about this wierd behavior? I´m using Zend Framework Version 1.9.7

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  • Display a tree dijit using zend framework

    - by churris43
    I am trying to display a tree of categories and subcategories by using dijits with zend framework. Haven't been able to find a good example. This is what I've got: Basically I got the following code as my action: class SubcategoriesController extends Zend_Controller_Action{ ..... public function loadtreeAction() { Zend_Dojo::enableView($this->view); Zend_Layout::getMvcInstance()->disableLayout(); //Creating a sample tree of categories and subcategories $a["cat1"]["id"] = "id1"; $a["cat1"]["name"] = "Category1"; $a["cat1"]["type"] = "category"; $subcat1 = array("id" => "Subcat1","name" => "Subcategory1" , "type" => "subcategory"); $subcat2 = array("id" => "Subcat12","name" => "Subcategory12" , "type" => "subcategory"); $a["cat1"]["children"] = array($subcat1,$subcat2); $treeObj = new Zend_Dojo_Data('id', $a); $treeObj->setLabel('name'); $this->view->tree = $treeObj->toJson(); } .... } And on my view: <?php $this->dojo()->requireModule('dojo.data.ItemFileReadStore'); $this->dojo()->requireModule('dijit.Tree'); $this->dojo()->requireModule('dojo.parser'); ?> <div dojoType="dojo.data.ItemFileReadStore" url="/Subcategories/loadtree" jsId="store"></div> <div dojoType="dijit.tree.ForestStoreModel" jsId="treeModel" store="store" rootId="root" rootLabel="List of Categories" childrenAttrs="children" query="{type:'category'}"></div> <div dojoType="dijit.Tree" model="treeModel" labelAttrs="ListOfCategories"></div> It doesn't even seem to try to load the tree at all. Any help is appreciated

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  • Implement master detail in one datagrid in wpf

    - by Archie
    Hello, I have classes as following: public class Property { public string PropertyName { get; set; } public int SumSubPropertValue; private List<SubProperty> propertyList; public void CalculateSumSubPropertValue { // implementation} } public class SubProperty { public string SubPropertyName { get; set; } public int SubPropertyValue { get; set; } } I have grouped the rows in datagrid on PropertyName . When the user clicks on PropertyName expnader the columns should display SubPropertyName and SubPropertyValue. Also SumSubPropertValue should appear in front of PropertyName in the expander header. My Datagrid is bound to a CollectionViewSource as follows: CollectionViewSource view = new CollectionViewSource(); view.Source = infoList; view.GroupDescriptions.Add(new PropertyGroupDescription("PropertyName")); Where infoList is ObservableCollection<Property>. My datagrid colmns look like <my:DataGrid.Columns> <my:DataGridTextColumn Header="SubPropertyName" Binding="{Binding SubPropertName}" Width="*"/> <my:DataGridTextColumn Header="SubPropertyValue" Binding="{Binding SubPropertyValue}" Width="*"/> </my:DataGrid.Columns> Can someone help me with it?

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  • How can I read the properties of an object that I assign to the Session in ASP.NET MVC?

    - by quakkels
    Hey all, I'm trying my hand at creating a session which stores member information which the application can use to reveal certain navigation and allow access to certain pages and member role specific functionality. I've been able to assign my MemberLoggedIn object to the session in this way: //code excerpt start... MemberLoggedIn loggedIn = new MemberLoggedIn(); if (computedHash == member.Hash) { loggedIn.ID = member.ID; loggedIn.Username = member.Username; loggedIn.Email = member.Email; loggedIn.Superuser = member.Superuser; loggedIn.Active = member.Active; Session["loggedIn"] = loggedIn; } else if (ModelState.IsValid) { ModelState.AddModelError("Password", "Incorrect Username or Password."); } return View(); That works great. I then can send the properties of Session["loggedIn"] to the View in this way: [ChildActionOnly] public ActionResult Login() { if (Session["loggedIn"] != null) ViewData.Model = Session["loggedIn"]; else ViewData.Model = null; return PartialView(); } In the Partial View I can reference the session data by using Model.Username or Model.Superuser. However, it doesn't seem to work that way in the controller or in a custom Action Filter. Is there a way to get the equivalent of Session["loggedIn"].Username?

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  • Multiple WCF calls for a single ASP.NET page load

    - by Rodney Burton
    I have an existing asp.net web application I am redesigning to use a service architecture. I have the beginnings of an WCF service which I am able to call and perform functions with no problems. As far as updating data, it all makes sense. For example, I have a button that says Submit Order, it sends the data to the service, which does the processing. Here's my concern: If I have an ASP.NET page that shows me a list of orders (View Orders page), and at the top I have a bunch of drop down lists for order types, and other search criteria which is populated by querying different tables from the database (lookup tables, etc). I am hoping to eventually completely decouple the web application from the DB, and use data contracts to pass information between the BLL, the SOA, and the web app. With that said, how can I reduce the # of WCF calls needed to load my "View Orders" page? I would need to make 1 call get the list of orders, and 1 call for each drop down list, etc because those are populated by individual functions in my BLL. Is it good architecture to create a web service method that returns back a specialized data contract that consists of everything you would need to display a View Orders page, in 1 shot? Something like this pseudocode: public class ViewOrderPageDTO { public OrderDTO[] Orders { get; set; } public OrderTypesDTO[] OrderTypes { get; set; } public OrderStatusesDTO[] OrderStatuses { get; set; } public CustomerListDTO[] CustomerList { get; set; } } Or is it better practice in the page_load event to make 5 or 6 or even 15 individual calls to the SOA to get the data needed to load the page? Therefore, bypassing the need for specialized wcf methods or DTO's that conglomerate other DTO? Thanks for your input and suggestions.

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  • How does Select statement works in a Dynamic Linq Query?

    - by Richard77
    Hello, 1) I've a Product table with 4 columns: ProductID, Name, Category, and Price. Here's the regular linq to query this table. public ActionResult Index() { private ProductDataContext db = new ProductDataContext(); var products = from p in db.Products where p.Category == "Soccer" select new ProductInfo { Name = p.Name, Price = p.Price} return View(products); } Where ProductInfo is just a class that contains 2 properties (Name and Price). The Index page Inherits ViewPage - IEnumerable - ProductInfo. Everything works fine. 2) To dynamicaly execute the above query, I do this: Public ActionResult Index() { var products = db.Products .Where("Category = \"Soccer\"") .Select(/* WHAT SOULD I WRITE HERE TO SELECT NAME & PRICE?*/) return View(products); } I'm using both 'System.Lind.Dynamic' namespace and the DynamicLibrary.cs (downloaded from ScottGu blog). Here are my questions: What expression do I use to select only Name and Price? (Most importantly) How do I retrieve the data in my view? (i.e. What type the ViewPage inherits? ProductInfo?)

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  • NotFoundException in layout editor for Android?

    - by borg17of20
    I'm trying to extend a RelativeLayout object and include an embedded SurfaceView object that uses a png file in my /res/drawable folder as its background but I keep getting an error in the XML Layout editor. See the following code: public class StopMotionRelativeLayout extends RelativeLayout { private Context myContext; private SurfaceView surfaceView1; private BitmapFactory.Options myBitmapOptions; private final android.view.ViewGroup.LayoutParams params = new LayoutParams(LayoutParams.FILL_PARENT, android.view.ViewGroup.LayoutParams.FILL_PARENT); public StopMotionRelativeLayout(Context context, AttributeSet attrs) { super(context, attrs); myContext = context; this.setBackgroundColor(Color.GREEN); //init images surfaceView1 = new SurfaceView(myContext,attrs); surfaceView1.setVisibility(View.INVISIBLE); this.addView(surfaceView1, params); } @Override protected void onMeasure(int widthMeasureSpec, int heightMeasureSpec) { super.onMeasure(widthMeasureSpec, heightMeasureSpec); myBitmapOptions = new Options(); myBitmapOptions.outWidth = widthMeasureSpec; myBitmapOptions.outHeight = heightMeasureSpec; surfaceView1.setBackgroundDrawable(new BitmapDrawable(BitmapFactory.decodeResource(this.myContext.getResources(), R.drawable.golf1, myBitmapOptions))); } } I get the following error: NotFoundException: Could not find drawable resource matching value 0x7F020002 (resolved name: golf1) in current configuration. I have seen this type of error may times now and it always happens when I try to load something from a resource file via code and not XML. Curiously, this error does not stop me from compiling the app, and the app runs without error in the emulator. I'd like to get back the use of my layout editor though... Please help. UPDATE: Here is the layout XML <?xml version="1.0" encoding="utf-8"?> <com.games.test.StopMotionRelativeLayout android:id="@+id/RelativeLayout01" android:layout_width="fill_parent" android:layout_height="fill_parent" xmlns:android="http://schemas.android.com/apk/res/android"> </com.games.test.StopMotionRelativeLayout>

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  • xCode: iPhone Swipe Gesture crash

    - by David DelMonte
    I have an app that I'd like the swipe gesture to flip to a second view. The app is all set up with buttons that work. The swipe gesture though causes a crash ( “EXC_BAD_ACCESS”.). The gesture code is: - (void)handleSwipe:(UISwipeGestureRecognizer *)recognizer { NSLog(@"%s", __FUNCTION__); switch (recognizer.direction) { case (UISwipeGestureRecognizerDirectionRight): [self performSelector:@selector(flipper:)]; break; case (UISwipeGestureRecognizerDirectionLeft): [self performSelector:@selector(flipper:)]; break; default: break; } } and "flipper" looks like this: - (IBAction)flipper:(id)sender { FlashCardsAppDelegate *mainDelegate = (FlashCardsAppDelegate *)[[UIApplication sharedApplication] delegate]; [mainDelegate flipToFront]; } flipToBack (and flipToFront) look like this.. - (void)flipToBack { NSLog(@"%s", __FUNCTION__); BackViewController *theBackView = [[BackViewController alloc] initWithNibName:@"BackView" bundle:nil]; [self setBackViewController:theBackView]; [UIView beginAnimations:nil context:NULL]; [UIView setAnimationDuration:1.0]; [UIView setAnimationTransition:UIViewAnimationTransitionFlipFromLeft forView:window cache:YES]; [frontViewController.view removeFromSuperview]; [self.window addSubview:[backViewController view]]; [UIView commitAnimations]; [frontViewController release]; frontViewController = nil; [theBackView release]; // NSLog (@" FINISHED "); } Maybe I'm going about this the wrong way... All ideas are welcome...

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  • User authentication using CodeIgniter

    - by marcin_koss
    I have a problem creating authentication part for my application. Below is the simplified version of my controllers. The idea is that the MY_controller checks if session with user data exists. If it doesn’t, then redirects to the index page where you have to log in. MY_controller.php class MY_Controller extends Controller { function __construct() { parent::__construct(); $this->load->helper('url'); $this->load->library('session'); if($this->session->userdata('user') == FALSE) { redirect('index'); } else { redirect('search'); } } } order.php - main controller class Orders extends MY_Controller { function __construct() { parent::__construct(); $this->load->helper('url'); $this->load->library('session'); } function index() { // Here would be the code that validates information input by user. // If validation is successful, it creates user session. $this->load->view('header.html', $data); // load header $this->load->view('index_view', $data); // load body $this->load->view('footer.html', $data); // load footer } function search() { //different page } what is happening is that the browser is telling me that “The page isn’t redirecting properly. Firefox has detected that the server is redirecting the request for this address in a way that will never complete.” It seems like the redirect() is being looped. I looked at a few other examples of user auth and they were build using similar technique.

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  • iphone SDK buttons control views

    - by mangnv
    Hi, all I'v just started to learn SDK. I have several questions. First. I will do the project about university APP. if u clike the app, then u can c several buttons on one page, then each button( eg: event, BBS,courses, map....) has specific function...each one connect to anohter view. Are they buttons on the main page? Second, how to deal with one view has several buttons, one button connect to other view? Third, how to deal with controller classes? I'd like to make a app like this way. Main Page has 6 buttonss(event, community, directory...), take community for eg: community has two functions( Notices and BBS). if i clike Notices, then i can read notices, and if i clike BBS, then i could also read BBS. The thing that i do not get is..how to deal with classes. I mean main Page has one controller classes that control 6 buttons? If my question is not so clearly, then let me know....I really need help~

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  • Xcode 5 - remove storyboard and start app with a .xib

    - by Lucy
    I've tried to follow the instructions on this Question. But I must not be doing something correctly because I am still getting a SIGABRT before I even get into the ViewController methods. Here are the steps: Copied all items on the view in the story board and pasted into the new xib view. Copied all contents of .h and .m view controller files into the new ones for the xib. Changed the Main nib file base name to the new xib name in the info.plist file. Tried to change the owner but I don't know if I'm doing that correctly. Edited the appdelegate didFinishLaunchingWithOptions file as follows: - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]] ; // Override point for customization after application launch. TestViewController *test = [[TestViewController alloc] initWithNibName:@"TestViewController" bundle:nil]; UINavigationController *nav = [[UINavigationController alloc] initWithRootViewController:test]; self.window.rootViewController = nav; [self.window makeKeyAndVisible]; return YES; } I even tried to start with an empty project like one of the last posts suggested and still get a SIGABRT when I try to run. Has Apple made it impossible to remove the storyboard? I'm creating an SDK. I don't want a storyboard. But I do need one xib that is rotatable. Help?

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  • Codeigniter common templates

    - by Darthg8r
    Let's say that I have a website that has 100 different pages. Each page uses a common header and footer. Inside the header is some dynamic content that comes from a database. I'd like to avoid having to have code in every single controller and action that passes this common code into the view. function index() { // It sucks to have to include this on every controller action. data['title'] = "This is the index page"; data['currentUserName'] = "John Smith"; $this->load->view("main_view", data); } function comments() { // It sucks to have to include this on every controller action. data['title'] = "Comment list"; data['currentUserName'] = "John Smith"; $this->load->view("comment_view", data); } I realize that I could refactor the code so that the common parts are in a single function and the function is called by the action. Doing so would reduce SOME of the pain, but it still doesn't feel right since I'd still have to make a call to that function every time. What's the correct way to handle this?

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  • How to Change an MFC Modeless Dialog to be the child of a CView in an MDI application?

    - by Kieveli
    I have an MFC application that is a Doc/View/Frame implementation. One dialog is running as a modeless dialog which pops up on demand (from a menu option). I'm looking to add the modeless dialog to an MDI child view. Basically, I want to load the template from the resource file, and create it as a child of the CView in my new trio (doc/view/frame) that I am adding to the template lists for the MDI. I've tried a few things in my derived CMyView class: void CMyView::OnInitialUpdate() { m_ListDialog = new Dialogs::CListDialog( m_config, this ); m_ListDialog->Create( Dialogs::CListDialog::IDD, this ); m_ListDialog->ShowWindow( SW_SHOW ); } I've tried calling SetWindowPos, ModifyStyle (WS_CHILD, WS_VISIBLE, DS_CONTROL). I've tried modifying the resource file to set the child and control manually. Everytime it calls Create, the ListDialog's m_hWnd is left as 0. This tells me it's not getting created properly. Any call to SetWindowPos() or ShowWindow() fails because the m_hWnd is 0 (debug assertion fails). What do I need to do to get a modeless dialog to be constructed, created, and appear as a child to CMyView in my MDI application?

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  • Streaming Media Player Tutorial Stops Unexpectedly. How Should I Debug (And Other Questions From A

    - by Danny
    Hello! I'm a fledgling in the Android and Eclipse ways. I was reading and downloaded the source code for a Streaming Media Player tutorial from Pocket Journey, here. However, when I try to run it through the "Run As..." or "Debug As..." features in Eclipse, the emulator reports: "Sorry! The application Android Tutorials (process com.pocketjourney.tutorials) has stopped unexpectedly. Please try again." Now, from stepping through the Tutorial 1 activity (for those of you that may be familiar with it), it seems something funky happens here: button.setOnClickListener(new View.OnClickListener() { public void onClick(View view) { Toast.makeText(Tutorial1.this, "Button Clicked",Toast.LENGTH_SHORT).show(); }}); My questions are: What's up with that line? Apparently, other comments haven't had this problem; am I missing some library that I should be downloading from someplace? How should I go about debugging this other than/in addition to stepping through code? I'm used to Visual Studio, which has a nice box with exception details for me to sift through and copy/paste to google with. Eclipse debugging showed a "No Source Code" page, or a list of exceptions. I've heard of something called LogCat; is that relevant here? Thanks in advance!

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  • When are SQL views appropriate in ASP.net MVC?

    - by sslepian
    I've got a table called Protocol, a table called Eligibility, and a Protocol_Eligibilty table that maps the two together (a many to many relationship). If I wanted to make a perfect copy of an entry in the Protocol table, and create all the needed mappings in the Protocol_Eligibility table, would using an SQL view be helpful, from a performance standpoint? Protocol will have around 1000 rows, Eligibility will have about 200, and I expect each Protocol to map to about 10 Eligibility rows and each Eligibility to map to over 100 rows in Protocol. Here's how I'm doing this with the view: var pel_original = (from pel in _documentDataModel.Protocol_Eligibility_View where pel.pid == id select pel); Protocol_Eligibility newEligibility; foreach (var pel_item in pel_original) { newEligibility = new Protocol_Eligibility(); newEligibility.Eligibility = (from pel in _documentDataModel.Eligibility where pel.ID == pel_item.eid select pel).First(); newEligibility.Protocol = newProtocol; newEligibility.ordering = pel_item.ordering; _documentDataModel.AddToProtocol_Eligibility(newEligibility); } And this is without the view: var pel_original = (from pel in _documentDataModel.Protocol_Eligibility where pel.Protocol.ID == id select pel); Protocol_Eligibility newEligibility; foreach (var pel_item in pel_original) { pel_item.EligibilityReference.Load(); newEligibility = new Protocol_Eligibility(); newEligibility.Eligibility = pel_item.Eligibility; newEligibility.Protocol = newProtocol; newEligibility.ordering = pel_item.ordering; _documentDataModel.AddToProtocol_Eligibility(newEligibility); }

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  • GRID is not properly rendered in ExtJS 4 by using Store

    - by user548543
    Here is the Src code for HTML file <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4 /strict.dtd"> <html> <head> <title>MVC Architecture</title> <link rel="stylesheet" type="text/css" href="/bh/extjs/resources/css/ext-all.css" /> <script type="text/javascript" src="extjs/ext-debug.js"></script> <script type="text/javascript" src="Main.js"></script> </head> <body> </body> </html> File path: /bh/Main.js [Main File] Ext.require('Ext.container.Viewport'); Ext.application({ name: 'App', appFolder: 'app', controllers: ['UserController'], launch: function() { Ext.create('Ext.container.Viewport', { layout: 'border', items: [ { xtype: 'userList' } ] }); } }); File path: /app/controller/UserController.js [Controller] Ext.define('App.controller.UserController',{ extend: 'Ext.app.Controller', stores: ['UserStore'], models:['UserModel'], views:['user.UserList'], init: function() { this.getUserStoreStore().load(); } }); File path: /app/store/UserStore.js Ext.define('App.store.UserStore', { extend: 'Ext.data.Store', model: 'App.model.UserModel', proxy: { type: 'ajax', url: 'app/data/contact.json' } }); File path: /app/model/UserModel.js [Model] Ext.define('App.model.UserModel',{ extends:'Ext.data.Model', fields:[ {name: 'name', type: 'string'}, {name: 'age', type: 'string'}, {name: 'phone', type: 'string'}, {name: 'email', type: 'string'} ] }); File path: /app/view/UserList.js [View] Ext.define('App.view.user.UserList' ,{ extend: 'Ext.grid.Panel', alias:'widget.userList', title:'Contacts', region:'center', resizable:true, initComponent: function() { this.store = 'UserStore'; this.columns = [ {text: 'Name',flex:1,sortable: true,dataIndex: 'name'}, {text: 'Age',flex:1,sortable: true,dataIndex: 'age'}, {text: 'Phone',flex:1,sortable: true,dataIndex: 'phone'}, {text: 'Email',flex:1,sortable: true,dataIndex: 'email'} ]; this.callParent(arguments); } }); In fire bug it shows the JSON response as follows: [{ "name": "Aswini", "age": "32", "phone": "555-555-5555", "email": "[email protected]" }] Why the Data has not been displayed although I have a valid json response. Please help!!!

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  • SL3 TreeView Not Programmatically Scrolling

    - by Chris
    I have a treeview in Silverlight 3. The treeview is bound to a observable collection - which contains a list of hierarchical data. When the page loads initially, all nodes, by default, in the treeview, are collapsed. I have functionality that allows a certain item in the treeview to be selected programmatically. The problem that I am running into is when an item is selected that isn't immediately visible (i.e. one or more parent nodes are collapsed). I programmatically expand them, but, when I try to programmatically scroll into view, so the user can see the selected item, it doesn't work. I looked into this further, and I believe that it has to do with the calculated viewport height for the scroll viewer. It almost seems like a timing issue, as, if the item's parent node is expanded, and then the item is programmatically selected, the code that scrolls the treeview into view for that selected treeview item works perfectly. Please refer to the extension method below that I am using to scroll the treeview into view. Any help or suggestions on how to correct this would be greatly appreciated. Thanks. public static void BringIntoViewForScrollViewer(this FrameworkElement frameworkElement, ScrollViewer scrollViewer) { var transform = frameworkElement.TransformToVisual(scrollViewer); var positionInScrollViewer = transform.Transform(new Point(0, 0)); if (positionInScrollViewer.Y < 0 || positionInScrollViewer.Y > scrollViewer.ViewportHeight) scrollViewer.ScrollToVerticalOffset(scrollViewer.VerticalOffset + positionInScrollViewer.Y - ScrollPadding); }

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  • unable to delete file (jpeg)

    - by ile
    I implemented helper for showing thumbnails from here Next to thumbnail, there is delete link which calls this controller // // HTTP POST: /Photo/Delete/1 [AcceptVerbs(HttpVerbs.Post)] public ActionResult Delete(int id, string confirmButton) { var path = "~/Uploads/Photos/"; Photo photo = photoRepository.GetPhoto(id); if (photo == null) return View("NotFound"); FileInfo TheFile = new FileInfo(Server.MapPath(path + photo.PhotoID + ".jpg")); if (TheFile.Exists) { photoRepository.Delete(photo); photoRepository.Save(); TheFile.Delete(); } else return View("NotFound"); return View(); } If I disable showing thumbnails then the file is deleted. Otherwise it sends error: System.IO.IOException: The process cannot access the file 'C:\Documents and Settings\ilija\My Documents\Visual Studio 2008\Projects\CMS\CMS\Uploads\Photos\26.jpg' because it is being used by another process. I also don't know if my file delete function is properly written. Searching on the net, I see everyone uses File.Delete(TheFile);, which i'm unable to use and I use TheFile.Delete(); For File.Delete(TheFile); i get following error: Error 1 'System.Web.Mvc.Controller.File(string, string, string)' is a 'method', which is not valid in the given context C:\Documents and Settings\ilija\My Documents\Visual Studio 2008\Projects\CMS\CMS\Controllers\PhotoController.cs 109 17 CMS Am I missing something here? Thanks in advance

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  • oracle query with inconsistent results

    - by Spencer Stejskal
    Im having a very strange problem, i have a complicated view that returns incorrect data when i query on a particular column. heres an example: select empname, has_garnishment from timecard_v2 where empname = 'Testerson, Testy'; this returns the single result 'Testerson, Testy', 'N' however, if i use the query: select empname, has_garnishment from timecard_v2 where empname = 'Testerson, Testy' and has_garnishment = 'Y'; this returns the single result 'Testerson, Testy', 'Y' The second query should return a subset of the first query, but it returns a different answer. I have dissected the view and determined that this section of the view definition is where the problem arises(Note, I removed all of the select clause except the parts of interests for clarity, in the full query all joined tables are required): SELECT e.fullname empname , NVL2(ded.has_garn, 'Y', 'N') has_garnishment FROM timecard tc , orderdetail od , orderassign oa , employee e , employee3 e3 , customer10 c10 , order_misc om, (SELECT COUNT(*) has_garn, v_ssn FROM deductions WHERE yymmdd_stop = 0 OR (LENGTH(yymmdd_stop) = 7 AND to_date(SUBSTR(yymmdd_stop, 2), 'YYMMDD') sysdate) GROUP BY v_ssn ) ded WHERE oa.lrn(+) = tc.lrn_order AND om.lrn(+) = od.lrn AND od.orderno = oa.orderno AND e.ssn = tc.ssn AND c10.custno = tc.custno AND e.lrn = e3.lrn AND e.ssn = ded.v_ssn(+) One thing of note about the definition of the 'ded' subquery. The v_ssn field is a virtual field on the deductions table. I am not a DBA im a software developer but we recently lost our DBA and the new one is still getting up to speed so im trying to debug this issue. That being said, please explain things a little more thoroughly then you would for a fellow oracle expert. thanks

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  • ASP.NET MVC: How do I validate a model wrapped in a ViewModel?

    - by Deniz Dogan
    For the login page of my website I would like to list the latest news for my site and also display a few fields to let the user log in. So I figured I should make a login view model - I call this LoginVM. LoginVM contains a Login model for the login fields and a List<NewsItem> for the news listing. This is the Login model: public class Login { [Required(ErrorMessage="Enter a username.")] [DisplayName("Username")] public string Username { get; set; } [Required(ErrorMessage="Enter a password.")] [DataType(DataType.Password)] [DisplayName("Password")] public string Password { get; set; } } This is the LoginVM view model: public class LoginVM { public Login login { get; set; } public List<NewsItem> newsItems { get; set; } } This is where I get stuck. In my login controller, I get passed a LoginVM. [HttpPost] public ActionResult Login(LoginVM model, FormCollection form) { if (ModelState.IsValid) { // What? In the code I'm checking whether ModelState is valid and this would work fine if the view model was actually the Login model, but now it's LoginVM which has no validation attributes at all. How do I make LoginVM "traverse" through its members to validate them all? Am I doing something fundamentally wrong using ModelState in this manner?

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