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  • How to extract keywords from a body of text in PHP

    - by Akeem
    Currently I'm leveraging http://developer.yahoo.com/search/content/V1/termExtraction.html which isn't ideal for performance and quality reasons. Before I embark on spending time on writing a system I wanted to see if there are any other available options that can do the trick.

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  • How to code a 'Next in Results' within search results in PHP

    - by thebluefox
    Right, bit of a head scratcher, although I've got a feeling there's an obvious answer and I'm just not seeing the wood for the trees. Baiscally, using Solr as a search engine for my site, bringing back 15 results per page. When you click on a result, you get a detail page, that has a "Next in Results" link on it, which obviously forwards you on to the next result. Whats the best way of doing this? I've come up with a few solutions but they're either too inpractical or just don't work. I could store all the ids in a session array, then grab the one after the current one and put that in the link. But with possibly hundreds/thousands of results, the memory that array would need, and the performance hit of dealing with it isn't practical. I could take the same approach and put it into the db, but I'll still have to deal with a potentially huge array when I grab them out of the db. Or; I could do the search again, only returning the id's, and grab the one after the one we're currently looking at. I think this could be the best option? Although it does seem kind of messy, namely because of when I have to select the id thats on a different 'page' (ie the 16th, 31st etc result). Unless I pass through where it was in the results, and select from there, but that still doesn't seem like the right way to do it. I'm really sorry if this is just complete nonsense, any help is massively appreciated as always, Cheers guys!

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  • function and class to show image not working in php

    - by Gully
    i am trying to get get the following working nothing is happen when i use the function i am trying to get it to display images class ItemRes { //items DB var $img=""; } function ShowItemImage($index,$res_a){ if(sizeof($res_a) > $index){ if($res_a[$index] != NULL) { $cimg = $res_a[$index]->img; return "<img src='$cimg' width='70' height='70' style='cursor:pointer'></img>"; } }else{ return "<center class='whitetxt'><strong>Empty</strong></center>"; } } $res_array = array(); $idx=0; $result21 = mysql_query("SELECT * FROM photos WHERE eid='$eid' ORDER BY id DESC") or die (mysql_error()); while ($row21 = mysql_fetch_array($result21)) { $img_path = $row21['path']; $obj = new ItemRes(); $obj->img = $img_path; $res_array[$idx] = $obj; $idx++; } ShowItemImage(0,$res_array) ShowItemImage(1,$res_array)

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  • Are Dynamic Prepared Statements Bad? (with php + mysqli)

    - by John
    I like the flexibility of Dynamic SQL and I like the security + improved performance of Prepared Statements. So what I really want is Dynamic Prepared Statements, which is troublesome to make because bind_param and bind_result accept "fixed" number of arguments. So I made use of an eval() statement to get around this problem. But I get the feeling this is a bad idea. Here's example code of what I mean // array of WHERE conditions $param = array('customer_id'=>1, 'qty'=>'2'); $stmt = $mysqli->stmt_init(); $types = ''; $bindParam = array(); $where = ''; $count = 0; // build the dynamic sql and param bind conditions foreach($param as $key=>$val) { $types .= 'i'; $bindParam[] = '$p'.$count.'=$param["'.$key.'"]'; $where .= "$key = ? AND "; $count++; } // prepare the query -- SELECT * FROM t1 WHERE customer_id = ? AND qty = ? $sql = "SELECT * FROM t1 WHERE ".substr($where, 0, strlen($where)-4); $stmt->prepare($sql); // assemble the bind_param command $command = '$stmt->bind_param($types, '.implode(', ', $bindParam).');'; // evaluate the command -- $stmt->bind_param($types,$p0=$param["customer_id"],$p1=$param["qty"]); eval($command); Is that last eval() statement a bad idea? I tried to avoid code injection by encapsulating values behind the variable name $param. Does anyone have an opinion or other suggestions? Are there issues I need to be aware of?

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  • php - arrange array to display in score order

    - by Phil Jackson
    hi, i have wrote a script to produce an array of data but now want to display in order of score. The array outputs as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user1_design [2] => user2_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 6 [2] => 15 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) so in a nutshell I am wanting it to be converted as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user2_design [2] => user1_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 15 [2] => 6 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) I have been looking at asort() but cant get anything to work. any help would be much appreciated.

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  • php push 2d array into mysql

    - by john
    Hay All, I cant seem to get my head around this dispite the number to examples i read. Basically I have a 2d array and want to insert it into MySQL. The array contains a few strings. I cant get the following to work... $value = addslashes(serialize($temp3));//temp3 is my 2d array, do i need to use keys? (i am not at the moment) $query = "INSERT INTO table sip (id,keyword,data,flags) VALUES(\"$value\")"; mysql_query($query) or die("Failed Query"); Thanks Guys,

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  • Soap Web Service PHP

    - by James Radford
    Is it possible to send a complexType to a SOAP web service by creating the complexType locally, i.e. create the type by creating a class and then sending the instance of that class back to the service? Admittedly this is only possible if I can get the definition of the type from the service provider. I'm looking to send a complexType back to a web service. So if this approach wont work please suggest an alternative...

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  • PHP MVC correct usage

    - by Ratt
    What is the correct (recommended method) for passing information to a view in a MVC environment. Currently we use Zend Framework, where we write classes to handle specific things EG a Book class with a save and load method to retrieve info from the DB, which is called from a particular nameAction(). What I would like to know is what is the best way to pass this information to the view, in some cases we do $this-view-book_name = $book-getBookName(); and in other cases we do the following $this-view-book = $book; OR $this-view-books = Book_Manager::getAllBooks(); and then access the object(s) properties in the view. Information on-line suggests we try limit what access a view has to information, i.e pass them only what they need and in some cases people say its ok to pass stuff through as long as nothing is done to that information. Regards

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  • problem creating jpg thumb with php

    - by Ross
    Hi, I am having problems creating a thumbnail from an uploaded image, my problem is (i) the quality (ii) the crop http://welovethedesign.com.cluster.cwcs.co.uk/phpimages/large.jpg http://welovethedesign.com.cluster.cwcs.co.uk/phpimages/thumb.jpg If you look the quality is very poor and the crop is taken from the top and is not a resize of the original image although the dimesions mean it is in proportion. The original is 1600px wide by 1100px high. Any help would be appreciated. $thumb = $targetPath."Thumbs/".$fileName; $imgsize = getimagesize($targetFile); $image = imagecreatefromjpeg($targetFile); $width = 200; //New width of image $height = 138; //This maintains proportions $src_w = $imgsize[0]; $src_h = $imgsize[1]; $thumbWidth = 200; $thumbHeight = 138; // Intended dimension of thumb // Beyond this point is simply code. $sourceImage = imagecreatefromjpeg($targetFile); $sourceWidth = imagesx($sourceImage); $sourceHeight = imagesy($sourceImage); $targetImage = imagecreate($thumbWidth,$thumbHeight); imagecopyresized($targetImage,$sourceImage,0,0,0,0,$thumbWidth,$thumbWidth,imagesx($sourceImage),imagesy($sourceImage)); //imagejpeg($targetImage, "$thumbPath/$thumbName"); imagejpeg($targetImage, $thumb); chmod($thumb, 0755);

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  • PHP combobox can't save the selected value on Edit Page

    - by bEtTy Barnes
    hello I've got problem with my combobox. It's not saving the selected value in Edit page. Here what I'm working with: private function inputCAR(){ $html = ""; $selectedId = $this->CAR; //$html .= '<option value="Roadmap Accelerator - Core">Roadmap Accelerator - Core</option>'; //$html .= '<option value="Roadmap Accelerator - Optional Core">Roadmap Accelerator - Optional Core</option>'; //$html .= '<option value="Regulatory">Regulatory</option>'; //$html .= '<option value="Mission Critical">Mission Critical</option>'; //$html .= '<option value="Various CARs/Types">Various CARs/types</option>'; $selection = array( "Roadmap Accelerator - Core", "Roadmap Accelerator - Optional Core", "Regulatory", "Mission Critical", "Various CARs/types" ); $html .= '<label for="car">CAR Type</label>'; $html .= HTML::selectStart("car"); foreach($selection as $value){ $text = $value; $html .= HTML::option($value, $text, $selectedId == $value ? true : false); } $html .= HTML::selectEnd(); return $html; } My option function: public static function option($value, $text, $isSelected=false) { $html = '<option value="' . $value . '"'; if($isSelected) { $html .= ' selected="selected"'; } $html .= '>'; $html .= $text; $html .= '</option>'; return $html; } When I first created a record. The selected value from my combobox got saved into the DB then the page refreshed to display. When I went to edit page, to select another value, and clicked save button. On the display page, it's not saving. For example. on Create page I selected Regulatory. then I changed my mind and changed it to Mission Critical on Edit page. On display page it is not changed. I don't know what's wrong or what I'm missing here. Any help is welcome and truly appreciated. Thanks.

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  • PHP & CodeIgniter Error: open_basedir restriction in effect

    - by iamdadude
    open_basedir restriction in effect. File(/var/www/vhosts/domain.com) is not within the allowed path(s): (/var/www/vhosts/domain.com/httpdocs:/tmp) How do I securely fix this? This is preventing me from listing and creating directories outside of the current directory. What I mean by securely is that I don't want to remove a piece of code from a configuration file and potentially make it easier for hackers to do whatever.

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  • Editing a remote file on-the-fly with PHP

    - by user275074
    Hi, I have a requirement to edit a remote text file on-the-fly, the content of which currently stands at ~1Mb. I have tried a couple of approaches and both seem to be clunky or hog memory which I can't rely on. Thinking out logically what I'm trying to achieve is: FTP to a remote server. Download a copy of the file for backup purposes and store it somewhere locally. Open the remote file and add the necessary lines required. Remove lines from the remote file as per an array of un-required data generated from the local server. Is this possible? I've managed to code steps 1 and 2 but I'm having difficult with 3 and 4. The way I'm doing it now is to use fgets and return the whole string. Really, I don't want to do this as it involves manipulating and re-generating the whole string (and it's large) and then re-inserting it in between two markers in the remote file. Is there no way of manipulating the lines of text in the file on-the-fly?

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  • PHP: codecomments inside functions prevents it work

    - by Karem
    $query = $connect->prepare("SELECT firstname, lastname FROM users WHERE id = '$id'"); $query->execute(); $row = $query->fetch(); // $full_name = $row["firstname"] . " ".$row["lastname"]; $full_name = $row["firstname"] . " ".substr($row["lastname"], 0, 1)."."; return $full_name; If i remove the line that is a comment ( // ), it will return $full_name, if its there then it wont work. I also tried commenting with #, but it still wont work(wont return anything) as soon as there is a codecomment weird issue

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  • Parse a json(?) string using php

    - by passatgt
    I have a string, more specifically, this one: a:16:{s:9:"pseudonym";O:16:"SimpleXMLElement":0:{}s:14:"parallel_title";O:16:"SimpleXMLElement":0:{}s:9:"title_var";O:16:"SimpleXMLElement":0:{}s:6:"series";O:16:"SimpleXMLElement":0:{}s:9:"vol_title";O:16:"SimpleXMLElement":0:{}s:9:"reference";O:16:"SimpleXMLElement":0:{}s:10:"bound_with";O:16:"SimpleXMLElement":0:{}s:15:"general_remarks";O:16:"SimpleXMLElement":0:{}s:6:"copies";O:16:"SimpleXMLElement":1:{i:0;s:1:"1";}s:11:"remarks_BPH";O:16:"SimpleXMLElement":0:{}s:3:"ICN";O:16:"SimpleXMLElement":1:{i:0;s:4:"neen";}s:10:"provenance";O:16:"SimpleXMLElement":0:{}s:7:"binding";O:16:"SimpleXMLElement":0:{}s:10:"size_hxwxd";O:16:"SimpleXMLElement":0:{}s:6:"BookID";O:16:"SimpleXMLElement":1:{i:0;s:4:"6271";}s:5:"repro";O:16:"SimpleXMLElement":0:{}} Is it possible to parse this string somehow? I need to display the keys and values in a list. I tried to use json_decode but it not returns anything, even with the second true parameter(json_decode($string,true))

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  • PHP upload with progress bar

    - by Mitchan Adams
    Hi all I want to create an upload form to upload large files. Thats pretty much easy, however, the upload process itself taks long and basically looks like nothing is happening for a few minutes. So now I'd like to insert a progress bar to show the user that something is happening and they should just sit tight. I've read of numerous methods like APC and certian flash plugins, but my site is hosted on a shared server and I cant install any new applications on it. I'm thinking, maybe if it is possible to read the size of the temp file it creates via an ajax page. By polling the size every few seconds I should be able to get the progress of the upload. Now the question I pose is...where is the temp file situated?

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  • PHP echo text if variable is blank

    - by user342391
    I am trying to echo €00.00 if my variable $amount equals zero I have done something wrong can you help?? Code while ($row9 = mysql_fetch_array($result9)) { $amount = $row9['amount']; } //$amount = $amount / 60; //$amount = round($amount, 2); if $amount == 0 echo "<b>Balance: &#8364;00.00</b>"; else echo "<b>Balance: $$amount</b>";

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  • php / mysql - select id from one table excepting ids which are in second table

    - by John
    hello. for example i have 2 tables: 1 . users: id Name 1 Mike 2 Adam 3 Tom 4 John 5 Andy 6 Ray 2 . visits: userID date 1 ... 3 ... 6 ... i want to make a page which can be visited once in 12 hours, when user visits that page his id is included in database ( visits ), how i can select all users ( from database users) excepting users who visited page in <= 12 hours ( users from database visits )?

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  • How to pass array element one by one in text box in php

    - by trainee
    i am Reading the file contents and passed it in explod function("=",$string) ,it gives me two array parts[0].parts[1] seprated by = .parts[1] array displays all the values of the variable .now how can i use these values one by one to pass in the text box .The variable value comes in this way (value1 value2 value3 value4...) my code also throws the undefined offset :1 notice when i prints the parts[1]arrray

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  • How to use default arguments in php

    - by liysd
    I want to define a function doSomething(arg1, arg2) with default values to arg1=val and arg2=val When I write function doSomething($arg1="value1", $arg2="value2"){ // do something } Is it possible now to call doSomething with default arg1 and arg2="new_value2"

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  • Disable popup message in php

    - by chupinette
    When i upload a excel file, i have used COM() to open and automate converting it to xml. It works fine, But when i run it, it always shows the message from Microsoft Excel: A file named ''' already exists in this location. Do you want to replace it? I can choose between Yes No and Cancel. normally i would choose Yes. But i dont want users to click on Yes each time. Can i disable this? Please inform me if any relevant codes need to be posted. Thanks

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  • PHP file_get_contents() does not work after uploading to the webserver

    - by Ethan
    Sample code: $html = file_get_contents('http://www.google.com'); echo $html; It works on localhost. But after uploading to the webserver, it gives me a warning: file_get_contents(): php_network_getaddresses: getaddrinfo failed: Temporary failure in name resolution. If I replace the domain name with google's IP address, it gives a warning: failed to open stream: Connection timed out. And ini_get("allow_url_fopen") return 1.

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