Search Results

Search found 48839 results on 1954 pages for 'java ee next'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 296/1954 | < Previous Page | 292 293 294 295 296 297 298 299 300 301 302 303  | Next Page >

  • Who is preventing the release of Java 1.7

    - by Shawn
    I recently attended a talk by a Sun engineer Charlie Hunt regarding performance. The talk was interesting enough but one question was regarding release date of 1.7. He said it's delayed as there are parties who are refusing to sign off JSRs they own and thus preventing the 1.7 release. It apparently has something to do with the cost of determining your Sun compliance. I would be interested to know the full story if anyone knows or can point me in the right direction. What triggered my question was the amazing long release notes for 6u18. Thanks

    Read the article

  • java - volatile keyword

    - by Tiyoal
    Say I have two threads and an object. One thread assigns the object: public void assign(MyObject o) { myObject = o; } Another thread uses the object: public void use() { myObject.use(); } Does the variable myObject have to be declared as volatile? I am trying to understand when to use volatile and when not, and this is puzzling me. Is it possible that the second thread keeps a reference to an old object in its local memory cache? If not, why not? Thanks a lot.

    Read the article

  • How do I dynamically name objects in Java?

    - by hatboysam
    Let's say I needed to make a series of String[] objects. I know that if i wanted to make a string array called "test" to hold 3 Strings I could do String[] test = new String[3]; But let's say I needed to make a series of these arrays and I wanted them to be named, 1,2, 3, 4, 5... etc. For however many I needed and I didn't know how many I'd need. How do I achieve a similar effect to this: for (int k=0; k=5; k++){ String[] k = new String[3]; } Which would created 5 string arrays named 1 through 5. Basically I want to be able to create array objects with a name detemined by some other function. Why can't I seem to do this? Am I just being stupid?

    Read the article

  • Caesar Cipher in Java (Spanish Characters)

    - by Rodolfo
    I've reading this question, and I was wondering if Is there any way to consider the whole range of characters? For example, "á", "é", "ö", "ñ", and not consider " " (the [Space])? (For example, my String is "Hello World", and the standard result is "Khoor#Zruog"; I want to erase that "#", so the result would be "KhoorZruog") I'm sure my answer is in this piece of code: if (c >= 32 && c <= 127) { // Change base to make life easier, and use an // int explicitly to avoid worrying... cast later int x = c - 32; x = (x + shift) % 96; chars[i] = (char) (x + 32); } But I've tried some things, and it didn't work.

    Read the article

  • remove duplicates from object array data java

    - by zahir hussain
    hi i want to know how to remove duplicates in object. for example cat c[] = new cat[10]; c[1].data = "ji"; c[2].data = "pi"; c[3].data = "ji"; c[4].data = "lp"; c[5].data = "ji"; c[6].data = "pi"; c[7].data = "jis"; c[8].data = "lp"; c[9].data = "js"; c[10].data = "psi"; i would like to remove the duplicates value from object array. thanks and advance

    Read the article

  • Java For-Each Loop to Deal to multiple Hands

    - by qwertyRocker
    I'm trying to find a good way to 'deal' cards to 4 difference hands. System.out.println("Deal to 4 Hands: "); Hand hand1 = new Hand(); Hand hand2 = new Hand(); Hand hand3 = new Hand(); Hand hand4 = new Hand(); hand1.addSingleCard(Deck.deal()); hand2.addSingleCard(Deck.deal()); hand3.addSingleCard(Deck.deal()); hand4.addSingleCard(Deck.deal()); hand1.addSingleCard(Deck.deal()); hand2.addSingleCard(Deck.deal()); hand3.addSingleCard(Deck.deal()); hand4.addSingleCard(Deck.deal()); System.out.println("Cards left in deck: " + Deck.size()); System.out.println("Player 1's Hand: \n" + hand1.getHand()); System.out.println("Player 2's Hand: \n" + hand2.getHand()); System.out.println("Player 3's Hand: \n" + hand3.getHand()); System.out.println("Player 4's Hand: \n" + hand4.getHand()); Is there an easier way to deal to hands? For example using a For-Each loop? I tried this: but it doesn't work. I haven't really used this type of loop very must... for(Hand card : hand1){ System.out.println("Player 1's Hand: \n" + hand1); } By the way, this deals 2 cards to 4 difference hands, then prints each hand.

    Read the article

  • Dijkstras Algorithm exaplination java

    - by alchemey89
    Hi, I have found an implementation for dijkstras algorithm on the internet and was wondering if someone could help me understand how the code works. Many thanks private int nr_points=0; private int[][]Cost; private int []mask; private void dijkstraTSP() { if(nr_points==0)return; //algorithm=new String("Dijkstra"); nod1=new Vector(); nod2=new Vector(); weight=new Vector(); mask=new int[nr_points]; //initialise mask with zeros (mask[x]=1 means the vertex is marked as used) for(int i=0;i<nr_points;i++)mask[i]=0; //Dijkstra: int []dd=new int[nr_points]; int []pre=new int[nr_points]; int []path=new int[nr_points+1]; int init_vert=0,pos_in_path=0,new_vert=0; //initialise the vectors for(int i=0;i<nr_points;i++) { dd[i]=Cost[init_vert][i]; pre[i]=init_vert; path[i]=-1; } pre[init_vert]=0; path[0]=init_vert; pos_in_path++; mask[init_vert]=1; for(int k=0;k<nr_points-1;k++) { //find min. cost in dd for(int j=0;j<nr_points;j++) if(dd[j]!=0 && mask[j]==0){new_vert=j; break;} for(int j=0;j<nr_points;j++) if(dd[j]<dd[new_vert] && mask[j]==0 && dd[j]!=0)new_vert=j; mask[new_vert]=1; path[pos_in_path]=new_vert; pos_in_path++; for(int j=0;j<nr_points;j++) { if(mask[j]==0) { if(dd[j]>dd[new_vert]+Cost[new_vert][j]) { dd[j]=dd[new_vert]+Cost[new_vert][j]; } } } } //Close the cycle path[nr_points]=init_vert; //Save the solution in 3 vectors (for graphical purposes) for(int i=0;i<nr_points;i++) { nod1.addElement(path[i]); nod2.addElement(path[i+1]); weight.addElement(Cost[path[i]][path[i+1]]); } }

    Read the article

  • How to repaint a XYPlot from JFreeChart? (JAVA)

    - by mccrank
    Hi, I'm doing a GUI that has a XYPlot (from the JFreeChart package) and when I click a button I'm trying to add some values. I add them correctly to the XYSeries that are inside the XYPlot, but the GUI doesn't change. It only changes when y maximize or minimize. Is there some kind of repaint to do this? I have been looking for it and I have found nothing.

    Read the article

  • Java - Collections.sort() performance

    - by msr
    Hello, Im using Collections.sort() to sort a LinkedList whose elements implements Comparable interface, so they are sorted in a natural order. In the javadoc documentation its said this method uses mergesort algorithm wich has n*log(n) performance. My question is if there is a more efficient algorithm to sort my LinkedList? The size of that list could be very high and sort will be also very frequent. Thanks!

    Read the article

  • Static and overriding in Java

    - by Abhishek Jain
    public class B { static int i =1; public static int multiply(int a,int b) { return i; } public int multiply1(int a,int b) { return i; } public static void main(String args[]) { B b = new A(); System.out.println(b.multiply(5,2)); System.out.println(b.multiply1(5,2)); } } class A extends B { static int i =8; public static int multiply(int a,int b) { return 5*i; } public int multiply1(int a,int b) { return 5*i; } } Output: 1 40 Why is it so? Please explain.

    Read the article

  • Java: Combine 2 List <String[]>

    - by battousai622
    I have two List of array string. I want to be able to create a New List (newList) by combining the 2 lists. But it must meet these 3 conditions: 1) Copy the contents of store_inventory into newList. 2) Then if the item names in store_inventory & new_acquisitions match, just add the two quantities together and change it in newList. 3) If new_acquisitions has a new item that does not exist in store_inventory, then add it to the newList. The titles for the CSV list are: Item Name, Quantity, Cost, Price. The List contains an string[] of item name, quantity, cost and price for each row. CSVReader from = new CSVReader(new FileReader("/test/new_acquisitions.csv")); List <String[]> acquisitions = from.readAll(); CSVReader to = new CSVReader(new FileReader("/test/store_inventory.csv")); List <String[]> inventory = to.readAll(); List <String[]> newList; Any code to get me started would be great! =] this is what i have so far... for (int i = 0; i < acquisitions.size(); i++) { temp1 = acquisitions.get(i); for (int j = 1; j < inventory.size(); j++) { temp2 = inventory.get(j); if (temp1[0].equals(temp2[0])) { //if match found... do something? //break out of loop } } //if new item found... do something? }

    Read the article

  • Loading all files in a directory in a Java applet

    - by WarrenB
    How would one go about programatically loading all the resource files in a given directory in a JAR file for an applet? The resources will probably change several times over the lifetime of the program so I don't want to hardcode names in. Normally I would just traverse the directory structure using File.list(), but I get permission issues when trying to do that within an applet. I also looked at using an enumeration with something line ClassLoader.getResources() but it only finds files of the same name within the JAR file. Essentially what I want to do is (something like) this: ClassLoader imagesURL = this.getClass().getClassLoader(); MediaTracker tracker = new MediaTracker(this); Enumeration<URL> images = imagesURL.getResources("resources/images/image*.gif"); while (images.hasMoreElements()){ tracker.add(getImage(images.nextElement(), i); i++; } I know I'm probably missing some obvious function, but I've spent hours searching through tutorials and documentation for a simple way to do this within an unsigned applet.

    Read the article

  • question on database query using hibernate in java with annotations

    - by molleman
    Hello, simple question regarding HQL(Hibernate query language) so i have user class , that can hold a list of Projects, how do i take this out of the database depending on a username, this is how i take out my user String username = "stephen"; YFUser user = (YFUser) session.createQuery("select u FROM YFUser u where u.username = :username").setParameter("username", name).uniqueResult(); but i want to take out the list of projects here is the projects list within the class YFUser(my user class); how would i query the database to get this list of projects @Entity @Table(name = "yf_user_table") public class YFUser implements Serializable,ILightEntity { ......... @OneToMany(cascade = CascadeType.ALL,fetch = FetchType.LAZY) @JoinTable(name = "YFUSER_JOIN_PROJECT", joinColumns = { @JoinColumn(name = "user_id") }, inverseJoinColumns = { @JoinColumn(name = "project_id") }) private List<Project> projects = new ArrayList<Project>();

    Read the article

  • Can Java's random function be zero?

    - by ThirdD3gree
    Just out of curiosity, can Math.random() ever be zero? For example, if I were to have: while (true){ if (Math.random() == 0) return 1; } Would I ever actually get a return of one? There's also rounding error to consider because Math.random() returns a double. I ask because my CS professor stated that random() goes from 0 to 1 inclusive, and I always thought it was exclusive.

    Read the article

  • Passing a Java object from one Struts action to another

    - by Bernhard V
    Hello! In one of my Struts action I've got the following code in a method: ... List<Object> retrievedListOfObjects = c.getListOfObjects(); return mapping.findForward("fw_view"); } fw_view leads to a new Struts action with another Struts form. Let's say this form has got among others the following field List<Object> listOfObjects; I now want to pass the retrievedListOfObjects from within the first Struts action to the form of the following Struts action. Is this possible without storing it in the session?

    Read the article

  • java generated excel sorting color mess.

    - by afzal
    I am using jxl api for generating a excel sheet, in which the alternate rows are highlighted, when I sort the contents of a excel and sort manually, the cell background colors messup, usually this is because I am writing the color cell by cell, is there anyway through which i color the alternate rows of the excel while generating it, in such a way that it doesnt effect the sorting of the contents.

    Read the article

  • Java Netscape LDAP Remove One Attribute

    - by spex
    Hi, I have LDAP schema where are users. I need remove one attribute named "notify" which have values: phone number or mail or remove attribute from user. I found method LDAPConnection myCon = new LDAPConnection("localhost",389); myCon.delete("uid=test1, ou=People, o=domain.com, o=isp"); but this remove whole user and i need remove only one attribute "notifyTo" of this user. I need remove whole attribute not only its value. Thanks for reply

    Read the article

  • Java URLConnection Timeout

    - by Chris
    I am trying to parse an XML file from an HTTP URL. I want to configure a timeout of 15 seconds if the XML fetch takes longer than that, I want to report a timeout. For some reason, the setConnectTimeout and setReadTimeout do not work. Here's the code: URL url = new URL("http://www.myurl.com/sample.xml"); URLConnection urlConn = url.openConnection(); urlConn.setConnectTimeout(15000); urlConn.setReadTimeout(15000); urlConn.setAllowUserInteraction(false); urlConn.setDoOutput(true); InputStream inStream = urlConn.getInputStream(); InputSource input = new InputSource(inStream); And I am catching the SocketTimeoutException. Thanks Chris

    Read the article

  • Arrays- Square root of an Array and printing the result JAVA

    - by roger34
    Hello, The title says it all, really. I'm trying to get an array of (9) numbers squared then printed but I keep coming back with only one result - the number of numbers in the array squared- obviously not what I want. Thanks for any help. Ok, here is my terrible code so far. Trying to pass it to a method as well. public static void main ( String args[] ) { double[] nums = {126, 12.939, 795, 320.16, 110, 34.7676, 7773, 67, 567, 323}; System.out.println ("Square root is " +square); square(nums); } public static double square (double [] array) { double result; for( double i = 0; i < array.length ; i++ ) result = Math.sqrt(array[i]); return result; } }

    Read the article

  • Close resources before exiting JFrame and TCP communication in Java

    - by Oz Molaim
    1. I'm writing a chat based application on TCP communication. I'm using NetBeans and I want to add functionality to the default EXIT_ON_CLOSE when exiting JFrame. The reason of course is because I want to clean resources and end threads safely. How can I call a method that clear resources and only then close the JFrame safely and end the process. 2. I need to implement the server side. The server has List/HashMap/Queue of 'Socket' with their chat nick-names. Is there any simple design pattern to do it correctly because I don't want to re-invent the wheel. thanks.

    Read the article

  • Size of Objects in Java Heap w/ Regards to Methods

    - by Eric
    I know about primitives and objects living on the heap, but how does the number of methods effect heap size of the object? For example: public class A { int x; public getX() { return x; } } public class B { int x; public getX() { return x; } public getXString() { return String.valueOf(x); } public doMoreInterestingStuff() { return x * 42; } //etc } When instantiated, both objects live on the heap, both have memory allocated to their primitive x, but is B allocated more heap space due to having more method signatures? Or are those ONLY on the classLoader? In this example its trivial, but when there are 100,000+ of these objects in memory at any given time I imagine it could add up.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 292 293 294 295 296 297 298 299 300 301 302 303  | Next Page >