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  • ProgressBar isn't updating

    - by Nuru Salihu
    I have a progressbar that that is show progress returned by the backgroundworker do_dowork event like below . if (ftpSourceFilePath.Scheme == Uri.UriSchemeFtp) { FtpWebRequest objRequest = (FtpWebRequest)FtpWebRequest.Create(ftpSourceFilePath); NetworkCredential objCredential = new NetworkCredential(userName, password); objRequest.Credentials = objCredential; objRequest.Method = WebRequestMethods.Ftp.DownloadFile; FtpWebResponse objResponse = (FtpWebResponse)objRequest.GetResponse(); StreamReader objReader = new StreamReader(objResponse.GetResponseStream()); int len = 0; int iProgressPercentage = 0; FileStream objFS = new FileStream((cd+"\\VolareUpdate.rar"), FileMode.Create, FileAccess.Write, FileShare.Read); while ((len = objReader.BaseStream.Read(buffer, 0, buffer.Length)) > 0) { objFS.Write(buffer, 0, len); iRunningByteTotal += len; double dIndex = (double)(iRunningByteTotal); double dTotal = (double)buffer.Length; double dProgressPercentage = (dIndex / dTotal); iProgressPercentage = (int)(dProgressPercentage); if (iProgressPercentage > 100) { iProgressPercentage = 100; } bw.ReportProgress(iProgressPercentage); } } However, my progressbar does not update. While searching , i was told the UI thread is being blocked and then i thought may be passing the progress outside the loop will do the trick. then i change to this if (ftpSourceFilePath.Scheme == Uri.UriSchemeFtp) { FtpWebRequest objRequest = (FtpWebRequest)FtpWebRequest.Create(ftpSourceFilePath); NetworkCredential objCredential = new NetworkCredential(userName, password); objRequest.Credentials = objCredential; objRequest.Method = WebRequestMethods.Ftp.DownloadFile; FtpWebResponse objResponse = (FtpWebResponse)objRequest.GetResponse(); StreamReader objReader = new StreamReader(objResponse.GetResponseStream()); int len = 0; int iProgressPercentage = 0; FileStream objFS = new FileStream((cd+"\\VolareUpdate.rar"), FileMode.Create, FileAccess.Write, FileShare.Read); while ((len = objReader.BaseStream.Read(buffer, 0, buffer.Length)) > 0) { objFS.Write(buffer, 0, len); iRunningByteTotal += len; double dIndex = (double)(iRunningByteTotal); double dTotal = (double)buffer.Length; double dProgressPercentage = (dIndex / dTotal); iProgressPercentage = (int)(dProgressPercentage); if (iProgressPercentage > 100) { iProgressPercentage = 100; } // System.Threading.Thread.Sleep(2000); iProgressPercentage++; // SetText("F", true); } bw.ReportProgress(iProgressPercentage); progressBar.Refresh(); } However still didn't help. When i put break point in my workerprogresschanged event, it show the progressbar.value however does not update. I tried progressbar.update(0, i also tried sleeping the thread for a while in the loop still didn't help. Please any suggestion/help would be appreciated .

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  • Javascript using asp.net

    - by jimson
    I have a Login Page Contains two text boxes one is user name,password and one button if the two textboxes are empty that time how i can avoid post back of the buuton if any value enterd that time only postback occuers,,,, not using required fiekd validator any method is avilable in javascript.......

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  • Apache downloads php files instead of running their source

    - by Devils Child
    I have just recently upgraded PHP 5.3 to 5.4 on my Debian Squeeze server. Now, instead of executing PHP files, Apache just downloads them, which is really bad. When I try to follow these steps, I get "broken packages" upon installing the libapache2-mod-php5 package. Also the answer tells me to add something to my httpd.conf, but it's empty. Question: How can I make apache execute php files again, instead of just passing them through as download? dpkg -l | grep php returns this rc libapache2-mod-php5 5.3.3-7+squeeze15 server-side, HTML-embedded scripting language (Apache 2 module) rc php5-cli 5.3.3-7+squeeze15 command-line interpreter for the php5 scripting language ii php5-common 5.4.15-1~dotdeb.2 Common files for packages built from the php5 source rc php5-gd 5.3.3-7+squeeze15 GD module for php5 rc php5-mcrypt 5.3.3-7+squeeze15 MCrypt module for php5 rc php5-mysql 5.3.3-7+squeeze15 MySQL module for php5 rc php5-suhosin 0.9.32.1-1 advanced protection module for php5 rc phpmyadmin 4:3.3.7-7 MySQL web administration tool And apt-get install libapache2-mod-php5 produces this error The following packages have unmet dependencies: libapache2-mod-php5 : Depends: libdb5.1 but it is not installable Depends: libssl1.0.0 (>= 1.0.0) but it is not installable Depends: libxml2 (>= 2.8.0) but 2.7.8.dfsg-2+squeeze7 is to be installed Recommends: php5-cli but it is not going to be installed E: Broken packages

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  • How to build this encryption system that allows multiple users/objects.

    - by Patrick
    Hello! I am trying to figure out how to create an optimal solution for my project. I made this simple picture in Photoshop to try to illustrate the problem and how i want it (if possible). Illustrative image Ill also try to explain it based on the picture. First off we have a couple of objects to the left, these objects all get encrypted with their own encryption key (EKey on the picture) and then stored in the database. On the other side we have different users placed into roles (one user can be in a lot of roles) and the roles are associated with different objects. So one person only has access the to the objects that the role provides. So for instance Role A might have access to Object A and B. Role B have access only to Object C and Role C have access to all objects. Nothing strange in that, right? Different roles have different objects that they can access. Now to the problem part. Each user has to login with his/her username/password and then he/she gets access to the objects that his/her roles provide. All the objects are encrypted so she needs to get a decryption key somehow. I don't want to store the encryption key as a text string on the server. It should be, if possible, decrypted using the users password (along with the role) or similar. That way you have to be a user on the server in order to decrypt an object an to work with it. I was thinking about making a public/private key encryption system, but i am kinda stuck on how to give the different users the decryption key to the objects. Since i need to be able to move users to and from roles, add new users, add new roles and create/delete objects. There will be one administrator that then adds some data to allow the users in that role to get the decryption key to decrypt the object. Nothing is static and i am trying to get a picture of how this can be built or if there is a far better solution. The only criteria are: -Encrypted objects. -Decryption key should not be stored as text. -Different users have access to different objects. -Does NOT have to have roles.

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  • Getting text boxes on a webpage

    - by C-UNIT
    So what I am trying to do is make an application (just for fun, not a lot of purpose), where when you launch it a interface comes up consisting of Username: textboxhere Password: textbox2here then a connect button, and when you fill out your information in the textboxs' then click Connect, it navigates to facebook.com and puts in your information that you defined in the textbox and logs you in. Any ideas guys?

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  • PHP class function.

    - by Jordan Pagaduan
    What is wrong with this code? <?php class users { var $user_id, $f_name, $l_name, $db_host, $db_user, $db_name, $db_table; function user_input() { $this->$db_host = 'localhost'; $this->$db_user = 'root'; $this->$db_name = 'input_oop'; $this->$db_table = 'users'; } function userInput($f_name, $l_name) { $dbc = mysql_connect($this->db_host , $this->db_user, "") or die ("Cannot connect to database : " .mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "insert into $this->db_table values (NULL, \"$f_name\", \"$l_name\")"; $result = mysql_query($query); if(!$result) die (mysql_error()); $this->userID = mysql_insert_id(); mysql_close($dbc); $this->first_name = $f_name; $this->last_name = $l_name; } function userUpdate($new_f_name, $new_l_name) { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "UPDATE $this->db_table set = \"$new_f_name\" , \"$new_l_name\" WHERE user_id = \"$this->user_id\""; $result = mysql_query($query); $this->f_name = $new_f_name; $this->l_name = $new_l_name; $this->user_id = $user_id; mysql_close($dbc); } function userDelete() { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "DELETE FROM $this->db_table WHERE $user_id = \"$this->user_id\""; mysql_close($dbc); } } ?> The error is: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\jordan_pagaduan\class.php on line 21 Cannot connect to database : Access denied for user 'ODBC'@'localhost' (using password: NO) The code cannot define this "$this->db_host" as "localhost".

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  • PHP user sessions

    - by Temek
    I'm bit confused. I've been building my sites with my own session system, but i'm not sure how secure the php's own session system is. My session system usually just has user id and quite harsh hash, which does not include user name or password for generation. I save the hash in the user database and as a cookie to confirm the user session on every page load. So my question is should i keep using my own systems or try out php sessions?

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  • Declare a Dictionary inside a static class

    - by Ngu Soon Hui
    How to declare a static dictionary object inside a static class? I tried public static class ErrorCode { public const IDictionary<string , string > ErrorCodeDic =new Dictionary<string, string>() { {"1","User name or password problem"} }; } But the compiler complains that "A const field of a reference type other than string can only be initialized with null".

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  • Execute a command using php under ssh2 in php

    - by Mervyn
    Using Mint terminal my script connects using ssh2_connect and ssh2_auth-password. When am logged in successfully I want to run a command which will give me the hardware cpu. Is there a way I can use to exec the command in my script then show the results. I have used system and exec for pinging. if i was in the terminal i do the login. then type "get hardware cpu" in the terminal it would look like this: Test~ $ get hardware cpu

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  • problem with get http request from IPhone

    - by user317192
    Hi, I am writing a sample PHP Web Service that is sending GET Http request from the iphone to the web server. The server side code is returning JSON Data to iphone, the server side code looks like: function getUsers(){ $con=mysql_connect("localhost","root","123456") or die(mysql_error()); if(!mysql_select_db("eventsfast",$con)) { echo "Unable to connect to DB"; exit; } $sql="SELECT * from users"; $result=mysql_query($sql); if(!$result) { die('Could not successfully run query Error:'.mysql_error()); } $data = array(); while($row = mysql_fetch_assoc($result)){ $data['username'][] = $row['username']; $data['password'][]= $row['password']; } mysql_close($con); //print_r(json_encode($data)); //return (json_encode($data)); return json_encode('success'); } getUsers(); ? Its a simple code that Fetches all the data from the user table and send it to the iphone application. *****************************************************IPHONE APPLICATION (void)viewDidLoad { [super viewDidLoad]; responseData = [[NSMutableData data] retain]; NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:@"http://localhost:8888/GetData.php"]]; [[NSURLConnection alloc] initWithRequest:request delegate:self]; } (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response { [responseData setLength:0]; } (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data { [responseData appendData:data]; } (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error { label.text = [NSString stringWithFormat:@"Connection failed: %@", [error description]]; } (void)connectionDidFinishLoading:(NSURLConnection *)connection { [connection release]; NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding]; [responseData release]; NSError *error; SBJSON *json = [[SBJSON new] autorelease]; NSArray *luckyNumbers = [json objectWithString:responseString error:&error]; [responseString release]; if (luckyNumbers == nil) label.text = [NSString stringWithFormat:@"JSON parsing failed: %@", [error localizedDescription]]; else { NSMutableString *text = [NSMutableString stringWithString:@"Lucky numbers:\n"]; for (int i = 0; i < [luckyNumbers count]; i++) [text appendFormat:@"%@\n", [luckyNumbers objectAtIndex:i]]; NSLog(text); label.text = text; } } ********************PROBLEM**************** The problem is that nothing is coming on iphone side of the application........... the response doesn't contains anything.............. Please help..............

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  • How to set user environment variables in Windows Server 2008 R2 as a normal user?

    - by likm
    In older versions of Windows, it was just open the Control Panel, select the System applet, select the Advanced tab, and then hit the Environment variables button. As a normal user, you could edit the "User variables" but not the "System variables". In Windows Server 2008 R2, if I try to hit the Advanced System settings option in the System applet, it prompts for the Administrator password.

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  • Add if else function in Ajax Jquery function

    - by Naga Botak
    Is it possible to add other else function in my JS like this: ? if response == success redirect to home if response == failed redirect to failed $.ajax({ type: "POST", url: action, data: form_data, success: function(response) { if(response == 'success') window.location.replace("home"); else $("#message").html("<div class='error_log'><p class='error'>Invalid username and/or password.</p></div>"); } });

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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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  • Are cookies enough for storing login data? (PHP)

    - by jpjp
    I am reading the Head First PHP/Mysql book and they say to store both the user's username, email into cookies and sessions. Is it safe to assume that everyone know a day has cookies? Or should I store both in sessions and cookies? I am not storing any sensitive data in cookies such as password, etc.

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  • How can I get DVDs playing after a Vista to XP change? [closed]

    - by Liath
    I replaced my vista install on a Dell Inspiron 1525 with XP and have managed to get most things up and running again however I'm having trouble with playing DVDs. When I try and play a DVD I get the following message: Windows Media Player cannot play this DVD because there is a problem with digital copy protection between your DVD drive, decoder, and video card. Try installing an updated driver for your video card. I have ensured that my drive is configured to play Region 2 discs (I'm in the UK), I've installed the most up to date XP codec pack which makes me think it's a driver issue. In device manager I have got my DVD drivers up to date however under "Other Devices" I'm missing several which sound key: Audio Device on High Definition Audio Bus Modem Device on High Definition Audio Bus Video Controller Video Controller (VGA Compatible) However I've installed all the relevant drivers I can find on the Dell website. The drive itself is working - I've run software from the drive. I'm afraid I am far from a sys-admin so I'm struggling on this one. How can I get my DVDs playing again?

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  • How to project an ASP Classic Page?

    - by SH
    How to project an ASP Classic page with either HTTP AUTH (you must provide a username and password to OrderGroove) or a randomly generated access key that will be included as one of the parameters of the HTTP POST using the variable name access_key. Can anybody provide asp classic code in this regard? Quick help will be appreciated...

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  • Facebook Photo upload using PHP/Java

    - by shyam
    Is there a way I can post photos to my facebook profile using my username and password only? The code may be in PHP or Java. I dont want to make a facebook app and allow it to post photos to my profile. Any help is much appreciated. Thanks in advance.

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  • Accessing SVN from LAN

    - by Michael
    Hi, I am running a subversion service on my localhost, I want users on the LAN to be able to access this repository without being prompted for username and password. Is there any way to do this.

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  • Bypass Credential dialog box of internet explorer

    - by m23
    My c# application opens the Internet explorer for different web URL/ domains. And I have all those credential information (username, password and domain name) stored in the database for each web application. Now how I can authenticate automatically without entering credential in “Network Credential” dialog box using code or bypass that dialog box? In other words I need to store those credential on system so no need to enter. I am using c#

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  • Hello World to Twitter from C#

    - by cf_PhillipSenn
    A few days ago, I posted this question and this question asking about how to post "Hello World" to twitter. I've gotten helpful responses, which have propelled me further along, but I'm still lost. I need to use OAuth because (as I read it) using username and password is going to be deprecated soon. I need an example as simple as updating the status with the string constant 'Hello World!'. My client is specifying that I must use C#.

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  • Can i Use the value of a variable from within a ruby script inside ssh.exec()

    - by kamal
    If i have a # {} , like #{results}, in the snippet below: results = Array.new                                   f = open("/Users/kahmed/messages", "r")                                   f.each_line do |line|                                        results << "#{$.} #{line}" if line =~ /NFE/                                       put #{results}                                   end How can i use it in the following ssh.exec command Net::SSH.start( HOST, USER, :password = PASS ) do|ssh|                                   ssh.exec(#{results})

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