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  • How to extract data from Google Analytics and build a data warehouse (webhouse) from it?

    - by nkaur301
    I have click stream data such as referring URL, top landing pages, top exit pages and metrics such as page views, number of visits, bounces all in Google Analytics. I am required to build a data warehouse from scratch(which I believe is known as web-house) from this data. My questions are:- 1)Is it possible? Every day data increases (some in terms of metrics or measures such as visits and some in terms of new referring sites), how would the process of loading the warehouse go about? 2)What ETL tool would help me to achieve this? Pentaho I believe has a way to pull out data from Google Analytics, has anyone used it? How does that process go? Any references, links would be appreciated besides answers.

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  • PHP - Setting Database Info

    - by user1710648
    First off, I'm sorry if this shows no code which is not what Stack Overflow is about..But I have no clue where to go on this. I have a basic CMS I made, and I am trying to distribute it. I want to make it so that upon going to /cms/install for example, they set the database info, and different info to integrate into the CMS. Now my issue is, what would be the best method to allow the user to store that database info? A cookie seems to not be the right way..Could I store database info inside of a database? Not too sure where to go on this. More or less. What is the best way to temporarily store the database information the user gave before arrival of the full CMS.

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  • How to Best Setup a Website Project in VS.NET

    - by Jason
    I have very little experience with setting up a website from scratch in a .NET environment. As I am doing this now, I am wondering - what's the best way to go? Is it better to create a new Website Project, and include the various backend services and database code as part of that project, or is it better to split out the various aspects of the project? If the second, how would I go about doing that? I want to ensure that this project is easy to manage in the future (in terms of source control, deployment, etc), so I want to make sure I'm starting off on the right foot. I was unable to find any tutorials online, but if you have any, I would appreciate those as well. Thanks!

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  • Duplication in mysql/php

    - by user1334095
    I have a problem in the code.i have two tables 'sms' and 'bd_paid_bribe'.sms table has a column 'Message' and bd_paid_bribe table has a column 'c_addi_info'.when i execute the code first time all the values of Message column are inserted into c_addi_info column.when i enter a record for the second time instead of inserting the new record, all the records of Message column are inserted into bd_paid_bribe column.can u modify the code and provide a solution to avoid duplication and to insert only the newly added record. <?php $con=mysql_connect('localhost','root',''); if(!$con) { die("couldn't connect"); } mysql_select_db("ipab2",$con); $rs2=mysql_query(" select max(sms_index) from tab3"); do { $rs=mysql_query("insert into tab3(sms_index)select max(sms_index) from sms"); $rs3=mysql_query("SELECT max(sms_index) FROM sms"); $rs1=mysql_query("insert into bd_paid_bribe(c_addi_info) select Message from sms "); }while($rs2>$rs3); ?>

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  • php var_dump returning blank array

    - by Oroku
    I'm following this tutorial on youtube: https://www.youtube.com/watch?v=VSF5p00uorc Around 4:28 - I get the following array when I load the sql.php page as in the tutorial: array(8) { [1]=> NULL [2]=> NULL [3]=> NULL [4]=> NULL [5]=> NULL [6]=> NULL [7]=> NULL [8]=> NULL } I do have 8 ids all with values in my data table. This is my code: <?php $con = mysqli_connect("localhost","root","","test2") or die('error'); $query = "select * from data"; $result = mysqli_query($con,$query); while($row = mysqli_fetch_array($result)) { $id = $row['id']; $feed = $row['feed']; $data[$id] = $feed; } var_dump($data); ?>

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  • Why my query is not working?

    - by Poma
    my website has PHP command: mysql_query("SELECT * FROM users WHERE id=" . $_GET["id"]) or die(mysql_error()); When I enter URL http://example.com/index.php?id=1;%20UPDATE%20users%20SET%20password=123%20WHERE%20id=1 I get following error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'UPDATE users SET password=abc WHERE id=1' at line 1 But in phpmyamin query executes successfully. What's wrong here? Why it doesn't execute in browser?

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  • Skeleton framework spacing

    - by user1745014
    I tried to ask this question late lastnight but I was so sleepy i typed the question completely wrong. I'm looking to float my navigation to the right of its current position around 200px more, there is room but it wont move over. You can view the live code here - www.xronn.co.uk/hosting and here is an image to explain my issue a little more http://i.stack.imgur.com/JtL0C.png purple lines the 960px width of the site blue line shows the space free for the navigation to go and the red arrows of course shows which direction i want the navigation to go in (the right) Anyone got any clue why when I push to more to the right, the list starts to sit under each other

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  • [C#] Implementing different windows/forms in a Windows Mobile application?

    - by pbean
    I am a bit new to Windows Mobile (with C# and the compact framework) development, so I am kind of unsure how to do this. The user has to go through several pages of information in a wizard-like manner. At the start there is a login window. How would I go about and implement this? Would I just have different User Controls for each page and create/show and destroy/hide them on request? Or do I need to create different forms and somehow show those?

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  • PHP Localhost Application connect to server database

    - by Cross Vander
    I want to ask about how to connect my localhost application (C:xampp/htdocs/myproject) to database at my server host (www.someweb.somedomain)? Am I possible to do that? If it is, how to connect it at my php config? Right now my config (server.php) is: <?php $host = "my web IP public:3306"; $user = "root"; $pass = ""; $db = "dispatcherDB"; $conn = mysql_connect($host, $user, $pass) or die ("Cant connect to mySQL"); mysql_select_db($db); ?> what I got: Warning: mysql_connect(): No connection could be made because the target machine actively refused it. in C:\xampp\htdocs\XMS\server.php on line 7 So, what must I filled for $host? I'm trying using website IP, it still can't connect. Maybe there's someone here have experience at this problem? Sorry for my bad English

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  • Creating an array from a MySQL table

    - by Rob
    I'm trying to create an array to use for a curl_multi_exec, but I can't seem to create the array properly. Here is my code: $SQL = mysql_query("SELECT url FROM urls") or die(mysql_error()); //Query the shell table while($resultSet = mysql_fetch_array($SQL)){ $urls[]=$resultSet; } echo $urls; //Test that the array works But when I run this script, all it does is echo "Array" I have no idea what I'm doing wrong, I've checked around google a bit, but can't figure it out. Any insight would be appreciated.

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  • PHP parameter without value using for navigation

    - by somewalri
    Hello, I am trying to set up a navigation system that uses GET parameters with no value, example: http://foo.bar/?mainPage takes the visitor to the main page. So I am using if statements and I am wondering if there is a way I can do this without a bunch of if statements? I don't think switch statements would work for this. This is currently what I have: $mainPage = $_GET['mainPage']; $contact = $_GET['contact']; if(isset($mainPage)) { // go to main page } if(isset($contact)) { // go to contact page } I don't want to have to end up writing a ton of if statements, though. Any ideas? Thanks.

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  • php/mysql question, retrieving information

    - by chance
    Hey SO, I have a question, pretty new at PHP and MySql but was curious is it possible to display only the most recent column to a table, from a database? I know it is possible to display a list of all information, or if you have just one column of information in your table to display that using the Here is my code for my basic script (just loads 1 column of information) I would like it to only print out the recent column i added to the table $con = mysql_connect ("localhost","username","password"); if (!$con) { die ('Could not connect:' . mysql_error()0; } mysql_select_db("db_name", $con); $result = mysql_query(Select column FROM table"); while($row = mysql_fetch_array($result)) { echo $row['column']; } mysql_close($con); * keep in mind, im not looking for someone to shoot me my code with it completed, though it would be handy, however just giving me the options of what I have to do, or what the script is called would be plentiful enough for my research, thanks!

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  • What does "Only catch exceptions you can handle" really mean?

    - by KyleLib
    I'm tasked with writing an Exception Handling Strategy and Guidelines document for a .NET/C# project I'm working on. I'm having a tough go at it. There's plenty of information available for how/when to throw, catch, wrap exceptions, but I'm looking for describing what sorts of things should go on inside the catch block short of wrapping and throwing the exception. try { DoSomethingNotNice(); } catch (ExceptionICanHandle ex) { //Looking for examples of what people are doing in catch blocks //other than throw or wrapping the exception, and throwing. } Thanks in advance

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  • jQuery lightBox plugin, problem with first image

    - by torm
    Hi, for start sorry for my bad english... but i have a little problem with this plugin. http://leandrovieira.com/projects/jquery/lightbox/ - to be sure we know what i'm talking about. So... i've got an image gallery with thumbs, and everything goes well.. except... when i click on the first image... it shows - ok, but i can go to the next image by clicking "next". It's loading all the time. When i choose second image... everything is allright, and i can skip to the next images... but i also cannot go back to the first one.

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  • extended permissions

    - by melimoreno
    Hi i'm doing a fb app that update the status box(what's in your mind), i'm using set_status from facebooker .. first i have this error: set_status needs extended permission so i google it and find this: before_filter :ensure_has_status_update .. so i put it in my controller and that solves the problem, but when i try to update the status, all ways redirect me to a fb page that says: You have already granted permissions to this application. so i go to the controller comment before_filter :ensure_has_status_update and then go to my app again and it works.. so i want to do this if (has_status_update == false) ask for permision else update the status i google it for a long time but i can't find an answer..

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  • What causes session/forms authentication timeouts in MVC3

    - by SimpleUser
    Can somebody please let me know what are the reasons for your authentication to die suddenly, even when you are working on an application without any idle time? Both with and without AJAX calls. And what are the different reasons for getting a 302 redirect from an MVC3 application to the Logon page. Been struggling with an issue with timeouts that happen at random. Sometimes within a few minutes of login to the application and sometimes you can go for hours (with/without idle time) without being thrown out. Thank You

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  • Problem with mysql_query() ;Says resource expected .

    - by user364651
    I have this php file. The lines marked as bold are showing up the error :"mysql_query() expecets parameter 2 to be a resources. Well, the similar syntax on the line on which I have commented 'No error??' is working just fine. function checkAnswer($answerEntered,$quesId) { //This functions checks whether answer to question having ques_id = $quesId is satisfied by $answerEntered or not $sql2="SELECT keywords FROM quiz1 WHERE ques_id=$quesId"; **$result2=mysql_query($sql2,$conn);** $keywords=explode(mysql_result($result2,0)); $matches=false; foreach($keywords as $currentKeyword) { if(strcasecmp($currentKeyword,$answerEntered)==0) { $matches=true; } } return $matches; } $sql="SELECT answers FROM user_info WHERE user_id = $_SESSION[user_id]"; $result=mysql_query($sql,$conn); // No error?? $answerText=mysql_result($result,0); //Retrieve answers entered by the user $answerText=str_replace('<','',$answerText); $answerText=str_replace('>',',',$answerText); $answerText=substr($answerText,0,(strlen($answerText)-1)); $answers=explode(",",$answerText); //Get the questions that have been assigned to the user. $sql1="SELECT questions FROM user_info WHERE user_id = $_SESSION[user_id]"; **$result1=mysql_query($sql1,$conn);** $quesIdList=mysql_result($result1,0); $quesIdList=substr($quesIdList,0,(strlen($quesIdList)-1)); $quesIdArray=explode(",",$quesIdList); $reportCard=""; $i=0; foreach($quesIdArray as $currentQuesId) { $answerEnteredByUser=$answers[$i]; if(checkAnswer($answerEnteredByUser,$currentQuesId)) { $reportCard=$reportCard+"1"; } else { $reportCard=$reportCard+"0"; } $i++; } echo $reportCard; ?> Here is the file connect.php. It is working just fine for other PHP documents. <?php $conn= mysql_connect("localhost","root","password"); mysql_select_db("quiz",$conn); ?>

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  • Using Session to limit form submission by time

    - by user1733850
    I have spent over 2 hours scouring the net trying to figure this out. I am trying to stop multiple form submission any faster than 60 seconds. Here is what I am using. session_start(); if (!isset($_SESSION['last_submit'])) $_SESSION['last_submit'] = time(); if (time()-$_SESSION['last_submit'] < 60) die('Post limit exceeded. Please wait at least 60 seconds'); else $_SESION['last_submit'] = time(); I found this bit here on the site but haven't been able to figure anything else out as far as getting it to work. I have this bit of code on my page at the beginning that does the DB query with the previous pages POST results. Do I need to set $last_submit to a certain value? Any help is appreciated.

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  • Calculations coming out to 0.0?

    - by Nick Gibson
    A simple percentage calculation. It wont return a value except 0.0 and I think once or twice it returned 100.0%. Other than that it won't do a thing. I have tried playing with the code in several different ways and it just wont work. for (int loop = 1; loop < loopCount; loop++) { aa = r.nextInt(10+1); abc = (int) aa; String[] userAnswer = new String[x]; int totalQues = (correctAnswer + wrongAnswer), actualQues = (totalQues - 1); if(abc < x) { userAnswer[abc] = JOptionPane.showInputDialog(null,"Question "+quesNum+"\n\n"+questions[abc]+"\n\nA: "+a[abc]+"\nB: "+b[abc]+"\nC: "+c[abc]+"\nD: "+d[abc]+"\nCorrect Answers: "+correctAnswer+"\nWrong Answers: "+wrongAnswer+"\nTotal Questions: "+totalQues); if(userAnswer[abc].equals(answers[abc])) { correctAnswer++; } else { wrongAnswer++; }//else if(actualQues == x); { score = (correctAnswer / actualQues) * 100; JOptionPane.showMessageDialog(null,"The test is finished."); JOptionPane.showMessageDialog(null,"You scored "+score+"%"); }//if }//if }//for

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  • read variables from file

    - by TonyVipros
    Hi, I'm trying to write a shell script to backup websites, I've got it to go through each directory in vhosts and create a new directory vhosts/{siteurl}/private/backups/ and gzip up the site into there. However, I also want it to read a file from private that will contain database name, user and password. So I can then use these to perform a mysqldump to private/backups/. The problem is that I've never written a shell script before so I've go no idea how to read variable data into my script, or how I should format the file to be read. Hope that's enough information.

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  • How can I write my code to attempt a database action but continue executing code on failure?

    - by Chris
    Simple question I guess, I want to use PHP to write an update to an existing row in my database, if it doesn't happen I want to log the failure but continue executing the code. While it would be nice to have records of failures to track down issues, that the update failed isn't that important to my user, nor will it affect the running of any other code; the query is simply for a 'cosmetic' but entirely unnecessary piece of information. My database class's query function is set to die on failure, could I modify that or is there another way of doing it without altering my standard query code?

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  • Form Login Error

    - by ilp
    I'm having issues with a login form for my website. At the top of the login.php form I have this <?php if (isset($_SESSION['username'])){ header("Location: http://myurl/"); die;}?> <?php require 'includes/dbconnect.php' ; ?> <?php require 'includes/header.php'; ?> and when login is successful I redirect them to header('Location: http://myrul/'); Header.php has <?php session_start(); ?> at the top. When I tried to login, I get this error message: Warning: Cannot modify header information - headers already sent by (output started at /path/to/file/login.php:7) in /path/to/file/login.php on line 39. login.php:7 == <?php require 'includes/header.php'; ?> while Line 39 in login.php is == header('Location: http://myrul/'); Please where is the problem

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