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  • How to prevent PHP variables from being arrays?

    - by MJB
    I think that (the title) is the problem I am having. I set up a MySQL connection, I read an XML file, and then I insert those values into a table by looping through the elements. The problem is, instead of inserting only 1 record, sometimes I insert 2 or 3 or 4. It seems to depend on the previous values I have read. I think I am reinitializing the variables, but I guess I am missing something -- hopefully something simple. Here is my code. I originally had about 20 columns, but I shortened the included version to make it easier to read. $ctr = 0; $sql = "insert into csd (id,type,nickname,hostname,username,password) ". "values (?,?,?,?,?,?)"; $cur = $db->prepare($sql); for ($ctr = 0; $ctr < $expected_count; $ctr++) { list ( $lbl, $type, $nickname, $hostname, $username, $password) = ""; $bind_vars = array(); $lbl = "csd_{$ctr}"; $type = $ref->itm->csds->$lbl->type; $nickname = $ref->itm->csds->$lbl->nickname; $hostname = $ref->itm->csds->$lbl->hostname; $username = $ref->itm->csds->$lbl->username; $password = $ref->itm->csds->$lbl->password; $bind_vars = array($id,$type,$nickname,$hostname,$username,$password); $res = $db->execute($cur, $bind_vars); # this is a separate function which works, but which only # does SELECTS and cannot be the problem. I include it because I # want to count the total rows. printf ("%d CSDs on that ITEM now.\n", CountCSDs($id_to_sync)); } P.S. I also tagged this SimpleXML because that is how I am reading the file, though that code is not included above. It looks like this: $Ref = simplexml_load_file($file);

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  • Converting from a day of week to unix time in PHP

    - by Rob
    Hi, I'm trying to get the unix time for date strings that are formatted like so: 'second sunday of march 2010' 'first sunday of november 2010' I was under the impression that strtotime could handle such a string, but apparently not, as this returns false. How can I convert to unix time when given a day of week, which one of those in the month (ie. first, second, etc.), a month and a year.

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  • Help with writing a php code that repeats itself per array value

    - by Mohammad
    Hi I'm using Closure Compiler to compress and join a few JavaScript files the syntax is something like this; $c = new PhpClosure(); $c->add("JavaScriptA.js") ->add("JavaScriptB.js") ->write(); How could I make it systematically add more files from an array lets say for each array element in $file = array('JavaScriptA.js','JavaScriptB.js','JavaScriptC.js',..) it would execute the following code $c = new PhpClosure(); $c->add("JavaScriptA.js") ->add("JavaScriptB.js") ->add("JavaScriptC.js") ->add ... ->write(); Thank you so much in advance!

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  • send email notifications to entrants of my contest form using php

    - by Zeljko Radic
    I am really stuck with the following issue and your assistance would be appreciated. Here is the deal. I have a contest form at http://www.beogradstore.com/mn/contest/main-contest/. Btw, I use WordPress contest domination plugin. So I want entrants of the contest to receive email notifications whenever they receive reward entries. After they enter the contest, they will receive referral link, which they can share online and whenever someone enters the contest with that referral link, the owner of the referral link will receive 10 new contest entries. What would be the easiest way to accomplish this?

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  • [PHP] Kohana-v3 ORM parent relationship

    - by VDVLeon
    Hi all, I just started with the version 3 of the Kohana Framework. I have worked a little with the $_has_many etc. Now I have the table pages. The primary key is pageID. The table has a column called parentPageID. Now I want to make a ORM model who, when accesed like this $page->parent->find() returns the page identified by parentPageID. I have the following already: // Settings protected $_table_name = 'pages'; protected $_primary_key = 'pageID'; protected $_has_one = array( 'parent' => array( 'model' => 'page', 'foreign_key' => 'parentPageID', ), ); But that does not work, it simply returns the first page from the table. Last query says this: SELECT `pages`.* FROM `pages` ORDER BY `pages`.`pageID` ASC LIMIT 1 Does somebody know how to solve this? I know this can: $parent = $page->parent->find($page->parentPageID); but it must be and can be cleaner (I think).

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  • php code to return xml

    - by anwar
    hi there i have a question and need help on this from you guys . I have a database created for a game called gamesleaderboard and the fields are id, player_name, score, leveltime. and my task is after getting the score, i have to insert it to a database and sort the dbase accordingly. after sorting, the code will return an xml in the following structure: Ahmad100080 Basel95090 Samer920100 Seyd900110 Ahmad100080 Basel95090 Samer920100 Seyd900110 Ahmad100080 Basel95090 plz tell me the necessary details how to do this thankyou.

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  • checkbox, php and update mysql!

    - by Ronnie Chester Lynwood
    Hello now I got this form. i get values with "while": mysql_query("select * from mp3 where aktif = '0'"); <form name="form" method="post" action=""> <input type="text" size="10" name="id" value="<?=$haciosman['id']?>" /> <input type="text" name="baslik" value="<?=$haciosman['baslik']?> <textarea name="sarkisozu"><?=$haciosman['sarkisozu']?></textarea> <input type="text" name="a3" value="<?=$haciosman['ekleyen']?"> <input type="checkbox" name="onay[]" /> <input type="submit" name="0" id="0" value="Onayla" /> <form> and updating values with: <? if (isset($_POST['onay'])) { $cikti = mysql_query("update mp3 set aktif = '1', baslik = '$_POST[baslik]' where id = '$_POST[id]'"); if ($cikti) { echo "islem tamam"; exit; } } ?> but this code only updating only one value. how can i let it update multiple values?

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  • PHP question on XSS

    - by user318466
    I need help in solving the following MCQ: Which of the following filtering techniques prevents cross-site scripting (XSS) vulnerabilities? A. Strip all occurrences of the string script. B. Strip all occurrences of the string javascript. C. Enable magic_quotes_gpc. D. None of the above. I think once the word java script is deleted there is no more threat. Am I correct ?

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  • PHP Timezone problem

    - by seaworthy
    I am in Albuquerque, NM. I am trying to update some stamps every time I put an entry into a database. Here is what I use. date_default_timezone_set("US/Mountain"); $stamp =mktime(); //$stamp = gmmktime(); $time = date("H:i:s",$stamp);$date = date("Y-m-d",$stamp); My local time is 12:15 PM but what I get is 18:15PM instead. If you can see what's going wrong please let me know.

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  • PHP & MySQLi timeout

    - by Dt7
    Whenever I try to create a mysqli object, as in; $mysqli = new mysqli(host, user, pass, table); ...the page just loads for around a minute, then stops, showing all the content of the page up until that line. info() says that MySQLi (and MySQL if that matters) are enabled, and I can access the MySQL CLI. I'm also working on a local machine, not a remote server. I feel like I've missed something obvious. Can anyone shed some light on it? Edit: just for clarification, I am actually putting real values into the mysqli constructor :)

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  • Reading large excel file with PHP

    - by Itamar Bar-Lev
    I'm trying to read a 17MB excel file (2003) with PHPExcel1.7.3c, but it crushes already while loading the file, after exceeding the 120 seconds limit I have. Is there another library that can do it more efficiently? I have no need in styling, I only need it to support UTF8. Thanks for your help

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  • Php, mysql selection

    - by cosy
    I have this table ATTRIBUTE id name um 12 capacity MB;GB;TB And this table2 : id id_attribute id_product name value um 1 12 40 hdd maxtor 30 GB 2 12 41 hdd maxtor 40 GB 3 12 42 hdd y 1 TB How can i select from table2 in this order : 30GB 40GB 1TB? Thanks a lot!

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  • Insert array to mysql database php

    - by ganjan
    Hi. I want to add an array to my db. I have set up a function that checks if a value in the db (ex. health and money) has changed. If the value is diffrent from the original I add the new value to the $db array. Like this $db['money'] = $money_input + $money_db;. function modify_user_info($conn, $money_input, $health_input){ (...) if ($result = $conn->query($query)) { while ($user = $result->fetch_assoc()) { $money_db = $user["money"]; $health_db = $user["health"]; } $result->close(); //lag array til db med kolonnene som skal fylles ut som keys i array if ($user["money"] != $money_input){ $db['money'] = $money_input + $money_db; //0 - 20 if (!preg_match("/^[[0-9]{0,20}$/i", $db['money'])){ echo "error"; return false; } } if ($user["health"] != $health_input){ $db['health'] = $health_input + $health_db; //0 - 4 if (!preg_match("/^[[0-9]{0,4}$/i", $db['health'])){ echo "error"; return false; } if (($db['health'] < 1) or ($db['health'] > 1000)) { echo "error"; return false; } } The keys in $db represent colums in my database. Now I want to make a function that takes the keys in the array $db and insert them in the db. Something like this ? $query = "INSERT INTO `main_log` ( `id` , "; foreach(range(0, x) as $num) { $query .= array_key.", "; } $query = substr($query, 0, -3); $query .= " VALUES ('', "; foreach(range(0, x) as $num) { $query .= array_value.", "; } $query = substr($query, 0, -3); $query .= ")";

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  • How to show a server side error message in a popup using php

    - by Fero
    Hi all, I found some of the similar questions here but they are all in C#. So kindly tell me the easiest way to show the server side error message using popup. The popup may be anything like thickbox, modalpopup etc... Here is the sample code. I didn't get the error message in the popup. <script type="text/javascript" src="thickbox/jquery-latest.js"></script> <script type="text/javascript" src="thickbox/thickbox.js"></script> <link href="thickbox/thickbox.css" rel="stylesheet" type="text/css" /> <span class="prtexterror" style="color:#FF0000;display:none;" id="hiddenModalContent" >{$error_login}</span> {literal} <script language="javascript" type="text/javascript"> $(document).ready(function() { tb_show("Please, login", "?tb_inline=true&inlineId=hiddenModalContent&height=180&width=300&modal=true", null); }); </script> {/literal} Any other ways are always welcome. thanks in advance

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  • [PHP] Condition for array with string as keys

    - by Kel
    My PL/SQL procedure returns a cursor. It always returns data. I fetch (oci_fetch_assoc) it and save it in an array. If results were found the keys of the array will be strings. If the cursor didn't find data, it will return value 0, thus the key of the array will be numeric. while($data = oci_fetch_assoc($cursor)){ if(!isset($data[0])){ ... } ... ... } What's the best way to check that the array is not just 0, but contains data? Thanks

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  • PHP Moving mySQL Tree Node

    - by TK
    I am having trouble trying to move sub nodes or parent nodes up or down... not that good at math. CREATE TABLE IF NOT EXISTS `pages` ( page-id mediumint(8) unsigned NOT NULL AUTO_INCREMENT, page-left mediumint(8) unsigned NOT NULL, page-right smallint(8) unsigned NOT NULL, page-title text NOT NULL, page-content text NOT NULL, page-time int(11) unsigned NOT NULL, page-slug text NOT NULL, page-template text NOT NULL, page-parent mediumint(8) unsigned NOT NULL, page-type text NOT NULL, PRIMARY KEY (page-id) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 ; INSERT INTO pages (page-id, page-left, page-right, page-title, page-content, page-time, page-slug, page-template, page-parent, page-type) VALUES (17, 1, 6, '1', '', 0, 'PARENT', '', 0, ''), (18, 2, 5, '2', '', 0, 'SUB', '', 17, ''), (19, 3, 4, '3', '', 0, 'SUB-SUB', '', 18, ''), (20, 7, 8, '5', '', 0, 'TEST', '', 0, ''); As example how would I move TEST up above PARENT and say move SUB down below SUB-SUB by playing with the page-left/page-right IDs? Code is not required just help with the SQL concept or math for it, would help me understand how to move it better...

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  • php forms insert and update

    - by DAFFODIL
    I have a form.The user enter the data ,the data will be stored in the data base. Now,using phpmysql,i need to display the whole data present in db to front end.The user will click a particular thing and make some modifications and if,he press update the data should get into database. Give me a snippet http://dpaste.com/hold/178740/

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  • MySQL access classes in PHP

    - by Mike
    I have a connection class for MySQL that looks like this: class MySQLConnect { private $connection; private static $instances = 0; function __construct() { if(MySQLConnect::$instances == 0) { //Connect to MySQL server $this->connection = mysql_connect(MySQLConfig::HOST, MySQLConfig::USER, MySQLConfig::PASS) or die("Error: Unable to connect to the MySQL Server."); MySQLConnect::$instances = 1; } else { $msg = "Close the existing instance of the MySQLConnector class."; die($msg); } } public function singleQuery($query, $databasename) { mysql_select_db(MySQLConfig::DB, $this->connection) or die("Error: Could not select database " . MySQLConfig::DB . " from the server."); $result = mysql_query($query) or die('Query failed.'); return $result; } public function createResultSet($query, $databasename) { $rs = new MySQLResultSet($query, MySQLConfig::DB, $this->connection ) ; return $rs; } public function close() { MySQLConnect::$instances = 0; if(isset($this->connection) ) { mysql_close($this->connection) ; unset($this->connection) ; } } public function __destruct() { $this->close(); } } The MySQLResultSet class looks like this: class MySQLResultSet implements Iterator { private $query; private $databasename; private $connection; private $result; private $currentRow; private $key = 0; private $valid; public function __construct($query, $databasename, $connection) { $this->query = $query; //Select the database $selectedDatabase = mysql_select_db($databasename, $connection) or die("Error: Could not select database " . $this->dbname . " from the server."); $this->result = mysql_query($this->query) or die('Query failed.'); $this->rewind(); } public function getResult() { return $this->result; } // public function getRow() // { // return mysql_fetch_row($this->result); // } public function getNumberRows() { return mysql_num_rows($this->result); } //current() returns the current row public function current() { return $this->currentRow; } //key() returns the current index public function key() { return $this->key; } //next() moves forward one index public function next() { if($this->currentRow = mysql_fetch_array($this->result) ) { $this->valid = true; $this->key++; }else{ $this->valid = false; } } //rewind() moves to the starting index public function rewind() { $this->key = 0; if(mysql_num_rows($this->result) > 0) { if(mysql_data_seek($this->result, 0) ) { $this->valid = true; $this->key = 0; $this->currentRow = mysql_fetch_array($this->result); } } else { $this->valid = false; } } //valid returns 1 if the current position is a valid array index //and 0 if it is not valid public function valid() { return $this->valid; } } The following class is an example of how I am accessing the database: class ImageCount { public function getCount() { $mysqlConnector = new MySQLConnect(); $query = "SELECT * FROM images;"; $resultSet = $mysqlConnector->createResultSet($query, MySQLConfig::DB); $mysqlConnector->close(); return $resultSet->getNumberRows(); } } I use the ImageCount class like this: if(!ImageCount::getCount()) { //Do something } Question: Is this an okay way to access the database? Could anybody recommend an alternative method if it is bad? Thank-you.

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  • PHP MySQL INSERT fails due to unique constraint

    - by sjw
    On insert I am catching the unique constraint mysql_errno() 1062. This works fine but I want to find the existing row to re-instate or modify it. Is there are method to obtain the row id on insert fail? I tried mysql_insert_id() but realised that would only return the row I'm inserting (or failed to insert) therefore, I get 0. Is there no option but to issue another mysql_query and simply perform a select on the duplicate value? I just want to make sure there is no better, quicker, more economical way to do this.

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  • PHP - stop calling on refresh

    - by Ross
    I need my class to create a new blank record when the page opens up the problem I am having is when the page refreshes it keeps incrementing by 1, if I write a session to keep the variable the next time I go back it does not increment. Any ideas? if(!isset($_POST['record_no'])) { echo $_POST['record_no'] = $projects->insert__blank_project(); } else { print "already Set"; }

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  • PHP Date Manipulations

    - by Ajith
    I need to get previous 30 days from a specific date which is available from database(eg: 2010-05-23 12:36:29).I am try it by using date('d', strtotime("-30 days")) Which is getting the currect answer what i looking for but it is not help me to enter date from database.Please help me to solve the issue.

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  • PHP & CodeIgniter Error: open_basedir restriction in effect

    - by iamdadude
    open_basedir restriction in effect. File(/var/www/vhosts/domain.com) is not within the allowed path(s): (/var/www/vhosts/domain.com/httpdocs:/tmp) How do I securely fix this? This is preventing me from listing and creating directories outside of the current directory. What I mean by securely is that I don't want to remove a piece of code from a configuration file and potentially make it easier for hackers to do whatever.

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  • Retrieve part of a MySQL column with PHP

    - by Gerardo Marset
    For instance, if I have the following table: +----+---+----------+ | id | a | position | +----+---+----------+ | 0 | 0 | 0 | | 1 | 0 | 1 | | 2 | 1 | 4 | | 3 | 1 | 9 | | 4 | 1 | 6 | | 5 | 1 | 1 | +----+---+----------+ and I want to get an array that contains the first 100 values from position where a is 1 in ascending order, what would I do? Im guessing something like this: $col = mysql_fetch_array( mysql_query(' SELECT `position` FROM `table` WHERE `a`="1" ORDER BY `position` ASC LIMIT 100 ')); I'd expect to get the following array: +-------+-------+ | index | value | +-------+-------+ | 0 | 1 | | 1 | 4 | | 2 | 6 | | 3 | 9 | +-------+-------+ but it doesn't work. ¿What should I do to make it work? Thanks

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