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  • Android :WindowManager$BadTockenException on Spinner Click

    - by Miya
    Hi, I have a spinner in my home.class. When I click on the spinner, the process is stopped showing exception that WindowManager$BadTockenException is caught. I am calling this home.class from main.class which extends ActivityGroup. If I am simply run only the home.class, the spinner is showing all items. But the problem is only with calling home.class from main.class. The following are my code. Please tell me why this is happened. main.class public class main extends ActivityGroup { public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); Intent intent=new Intent(this,home.class); View view=getLocalActivityManager().startActivity("1", intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP)).getDecorView(); setContentView(view); } } home.class String[] country={"Please selects","US","INDIA","UK"}; Spinner s2 = (Spinner) findViewById(R.id.spinnerCountry); ArrayAdapter<CharSequence> adapterCountry=new ArrayAdapter(this,android.R.layout.simple_spinner_item,country); adapterCountry.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item); s2.setAdapter(adapterCountry); s2.setOnItemSelectedListener(new OnItemSelectedListener() { public void onItemSelected( AdapterView<?> parent, View view, int position, long id) { countryName=country[position]; } public void onNothingSelected(AdapterView<?> parent) { countryName=country[0]; } }); Stack Thread [<1 main] (Suspended (exception WindowManager$BadTokenException)) AlertDialog(Dialog).show() line: 245 AlertDialog$Builder.show() line: 802 Spinner.performClick() line: 260 View$PerformClick.run() line: 9080 ViewRoot(Handler).handleCallback(Message) line: 587 ViewRoot(Handler).dispatchMessage(Message) line: 92 Looper.loop() line: 123 ActivityThread.main(String[]) line: 3647 Method.invokeNative(Object, Object[], Class, Class[], Class, int, boolean) line: not available [native method] Method.invoke(Object, Object...) line: 507 ZygoteInit$MethodAndArgsCaller.run() line: 839 ZygoteInit.main(String[]) line: 597 NativeStart.main(String[]) line: not available [native method] Thank You....

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  • django updating m2m field

    - by Marconi
    I have a model service and a ModelForm named Service which I use to add and update the service model. The model looks like this: class Service(models.Model): categories = models.ManyToManyField(Category) The categories field is displayed as a tag with that allows multiple selection. It works well when I'm adding a new record but when I'm updating it, only one service is showing up on the request.POST['categories'] even if I selected multiple categories. I tried dumping the request object and I can see that the categories is showing something like: u'categories': [u'3', u'4', u'2'] I tried calling the request._get_post() and it did return only 1 category, hence the request.POST['categories'] returns only 1. Anybody who knows what's happening and how to fix it?

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  • ViewController behaving oddly when pushed on the window

    - by ayazalavi
    I am using multiple controller during launch of an application in app delegate. One controller is for registration and the second controller is tabbar. tabbar was loading fine but when I pushed registration controller on window, contents went up by 20 units and I have good white blank screen at bottom. Therefore I recreated frame of my registration view controller in its viewdidload method and slided it 20 units down. The code is self.view.frame = CGRectMake(0, 20, self.view.frame.size.width, self.view.frame.size.height); and code in my app delegate for launch application was - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { if (![self accountExists]) { //code if account does not exists on iphone app database self.registerAccount = [[registerViewController alloc] initWithNibName:@"registerViewController" bundle:nil]; [window addSubview:registerAccount.view]; } else if([self autoLoginForAnyAccount]){ //code for autologin to app } else { self.tabBarController.selectedIndex = 1; self.tabBarController.delegate = self; [window addSubview:tabBarController.view]; } [window makeKeyAndVisible]; return YES; } if anyone knows why there is a white space at bottom when registration controller is pushed then please share it with me.

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  • Accessing inter-schema tables and relations in hibernate

    - by nitesh
    There is a typical situation being faced where different tables are scattered through different schemas in Oracle database and they are related to each other (encompassing all different types of relations). How can they be represented in Hibernate using annotations as when a sessionfactory handle is created for one schema, tables in that schema can't access other related tables (foreign key relation to tables in other schema)? For a query like following, exception is thrown - "from table1 as model where model.table2Name.table2column = "+foo Exception comes as - org.hibernate.QueryException: could not resolve property: table2column of: com.test.table1 [from com.test.table1 as model where model.table2Name.table2column = 1] Here table1 and table2 are present in different schemas.

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  • Unknown ListView Behavior

    - by st0le
    I'm currently making a SMS Application in Android, the following is a code snippet from Inbox Listactivity, I have requested a cursor from the contentresolver and used a custom adapter to add custom views into the list. Now, in the custom view i've got 2 TextViews (tvFullBody,*tvBody*)... tvFullBody contains the Full SMS Text while tvBody contains a short preview (35 characters) The tvFullBody Visibility is by default set to GONE. My idea is, when the user clicks on a list item, the tvBody should dissappear(GONE) and the tvFullBody should become visible (VISIBLE). On Clicking again, it should revert back to its original state. //isExpanded is a BitSet of the size = no of list items...keeps track of which items are expanded and which are not @Override protected void onListItemClick(ListView l, View v, int position, long id) { if(isExpanded.get(position)) { v.findViewById(R.id.tvFullBody).setVisibility(View.GONE); v.findViewById(R.id.tvBody).setVisibility(View.VISIBLE); }else { v.findViewById(R.id.tvFullBody).setVisibility(View.VISIBLE); v.findViewById(R.id.tvBody).setVisibility(View.GONE); } isExpanded.flip(position); super.onListItemClick(l, v, position, id); } The Code works as it is supposed to :) except for an undesired sideeffect.... Every 10th (or so) List Item also gets "toggled". eg. If i Expand the 1st, then the 11th, 21th list items are also expanded...Although they remain off screen, but on scrolling you get to see the undesired "expansion". By my novice analysis, i'm guessing Listview keeps track of 10 list items that are currently visible, upon scrolling, it "reuses" those same variables, which is causing this problem...(i didn't check the android source code yet.) I'd be gratefull for any suggestion, on how i should tackle this! :) I'm open to alternative methods aswell....Thanks in advance! :)

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  • WPF StaticResource bound to subproperty

    - by mizipzor
    I have a class thats created as a resource: <Window.Resources> <Model:MyModel x:Key="model" /> </Window.Resources> The MyModel class has a cli property named Foo. I want the selected value in a combobox to be bound to this property. I thought I could do this but Im getting errors: <ComboBox SelectedItem="{Binding Source={StaticResource model.Foo}}" /> Heres the error: Cannot find resource named '{model.Foo}'. Where did I go wrong? What extra parameters do I need to specify to properly bind to a subproperty?

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  • How can I keep the the logic to translate a ViewModel's values to a Where clause to apply to a linq query out of My Controller?

    - by Mr. Manager
    This same problem keeps cropping up. I have a viewModel that doesn't have any persistent backing. It is just a ViewModel to generate a search input form. I want to build a large where clause from the values the user entered. If the Action Accepts as a parameter SearchViewModel How do I do this without passing my viewModel to my service layer? Service shouldn't know about ViewModels right? Oh and if I serialize it, then it would be a big string and the key/values would be strongly typed. SearchViewModel this is just a snippet. [Display(Name="Address")] public string AddressKeywords { get; set; } /// <summary> /// Gets or sets the census. /// </summary> public string Census { get; set; } /// <summary> /// Gets or sets the lot block sub. /// </summary> public string LotBlockSub { get; set; } /// <summary> /// Gets or sets the owner keywords. /// </summary> [Display(Name="Owner")] public string OwnerKeywords { get; set; } In my controller action I was thinking of something like this. but I would think all this logic doesn't belong in my Controller. ActionResult GetSearchResults(SearchViewModel model){ var query = service.GetAllParcels(); if(model.Census != null){ query = query.Where(x=>x.Census == model.Census); } if (model.OwnerKeywords != null){ query = query.Where(x=>x.Owners == model.OwnerKeywords); } return View(query.ToList()); }

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  • CodeIgniter - the right way to create "block" elements on web page

    - by kikkoman90
    Hello. I've been searching for a solutions for this problem a while but haven't seen any "valid mvc" solution for this. I hope I can explain my problem clearly enough for you guys. I need to create a dynamic block of HTML on my website. (eg. a block containing user's latest blog comments). I have a template view file (a file containing header, content container and a footer) where I need to add some content AND this block element. The problem is that I don't want to duplicate this block code on every controller. It just feels stupid and I'm sure there's a better way to do this than just duplicating same stuff all over again on all the controller files? I can add view inside another view just fine, but what bugs me is how to actually generate that dynamic content to this block's view-file. I can't call controller from view file, controller from controller filem or model from view file because what I understand that just isn't the "mvc" way? Anyone got any tricks or tips for this?

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  • Rails ActiveRecord - How to set association save order

    - by Altonymous
    I have a weird relationship that needs to be maintained for legacy processes. I'm trying to figure out how to create the relationship given the new model association. New Relationship Setup Machine has_many MachineReadings has_many Disks has_many DiskReadings Old Relationship Setup Machine has_many MachineReadings has_many DiskReadings has_many Disks The problem is data will come in on the Machine model as nested attributes using the new relationship setup. I need to update the machine_reading_id in the DiskReading model so the old association can continue to be used. I tried doing this via an after_save hook that would traverse back up to the machine and then down to the readings to get the machine_reading.id so I could populate the DiskReading model. However, the associations aren't being saved in the order I would expect. They are saving the Disks & DiskReadings before saving the MachineReadings. So when I go after the machine_reading.id it hasn't been written and thus I am unable to get access to it. For example: #machine_disk_reading.rb after_save :build_old_relationship def build_old_relationship self.machine_reading_id = self.disk.machine.readings.find_by_date_time(self.date_time).id end

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  • Teacher confused about MVC?

    - by Gideon
    I have an assignment to create a game in java using MVC as a pattern. The thing is that stuff I read about MVC aren't really what the teacher is telling me. What I read is that the Model are the information objects, they are manipulated by the controllers. So in a game the controller mutates the placement of the objects and check if there is any collision etc. What my teacher told me is that I should put everything that is universal to the platform in the models and the controllers should only tell the model which input is given. That means the game loop will be in a model class, but also collision checks etc. So what I get from his story is that the View is the screen, the Controller is the unput handeler, and the Model is the rest. Can someone point me in the right direction?

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  • How to create the automatic mass form submitter (javascript-ajax script) to be used on the 3rd part

    - by Daniel
    I need a script that can handle the following tasks. Take user data from my database and fill in and submit / post data to forms located on third part websites.: So I want to know if is it hard to create or do somebody knows if does exists some script for mass form submissions in PHP -Javascript-Ajax ? I run Dancers & Hostess & Model jobs website, I would like to find some script which allows the girls automaticly submit to hundreds websites forms (other 3rd part model agencies) with their similar model application form info on my website previously specified, 1).Firstly the girls will fill out my agency portfolio very detailed form , like this i will get all the model personal info from them , 2) Secondly i would like to allow for example models to submit to 100 and more other model agencies forms (I will find those websites before, and I will get their field names = values and thanks to some script would like to connect them with every girl data already created in my website to submit . I would like to implement it to my wordpress website where the girls has their portfolios instead of my pages . I would like to offer this service especially to models , it should work like some directory submitters , The script knows names - values and fill it out itself, but I want it online - browser side, where the girls should only fill out captcha if there is and click the button "submit".After succesful submit it should offer other form to submit. I would be very happy if you know the answer or if you can redirect me to some article

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  • With lots of help, I have gotten this android class activity down to only one error. Eclipse aks for me to add ")" ,"}", and ";" why though?

    - by AndroidNewb
    package com.android.drinksonme; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText; import android.widget.TextView; public class Screen2 extends Activity { // Declare our Views, so we can access them later private EditText etUsername; private EditText etPassword; private Button btnLogin; private Button btnSignUp; private TextView lblResult; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); // Get the EditText and Button References etUsername = (EditText)findViewById(R.id.username); etPassword = (EditText)findViewById(R.id.password); btnLogin = (Button)findViewById(R.id.login_button); btnSignUp = (Button)findViewById(R.id.signup_button); lblResult = (TextView)findViewById(R.id.result); btnLogin.setOnClickListener(new OnClickListener () { String username = etUsername.getText().toString(); String password = etPassword.getText().toString(); public void onClick(View v){ if(username.equals("test") && password.equals("test")){ Intent i = new Intent(Screen2.this, DrinksTwitter.class); startActivity(i);} else lblResult.setText("Invalid username or password."); } /* final Intent k = new Intent(Screen2.this, SignUp.class); btnSignUp.setOnClickListener(new OnClickListener() { public void onClick(View v) { startActivity(k); }*/ } ); } }

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  • Django admin - remove field if editing an object

    - by John McCollum
    I have a model which is accessible through the Django admin area, something like the following: # model class Foo(models.Model): field_a = models.CharField(max_length=100) field_b = models.CharField(max_length=100) # admin.py class FooAdmin(admin.ModelAdmin): pass Let's say that I want to show field_a and field_b if the user is adding an object, but only field_a if the user is editing an object. Is there a simple way to do this, perhaps using the fields attribute? If if comes to it, I could hack a JavaScript solution, but it doesn't feel right to do that at all!

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  • Does Spring MVC form submit data bind children objects automagically?

    - by predhme
    I have a data model that is something like this: public class Report { // report owner private User user; ... typical getter setter ... } public class User { ... omitted for clarity } What happens is when a report is created, the current user is set to the report user object. When the report is edited, the spring controller handling the POST request is receiving a report where the user object is null. Here is what my controller looks like: @Controller @RequestMapping("/report") public class ReportController { @RequestMapping(value = "/edit/{id}", method = RequestMethod.GET) public String editReport(@PathVariable Long id, Model model) { Report r = backend.getReport(id); // fully loads object model.addAttribute("report", report); return "report/edit"; } @RequestMapping(value = "/edit/{id}", method = RequestMethod.POST) public String process(@ModelAttribute("report") Report r) { backend.save(r); return "redirect:/report/show" + r.getId(); } } I ran things throw the debugger and it looks like in the editReport method the model object is storing the fully loaded report object (I can see the user inside the report). On the form jsp I can do the following: ${report.user.username} and the correct result is rendered. However, when I look at the debugger in the process method, the passed in Report r has a null user. I don't need to do any special data binding to ensure that information is retained do I?

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  • MVC3 html.TextBox

    - by BigTommy79
    I have login view that takes a LoginPageViewModel: public class LoginPageViewModel : PageViewModel { public string ReturnUrl { get; set; } public bool PreviousLoginFailed { get; set; } public LoginFormViewModel EditForm { get; set; } } which is rendered in the view. When a user tries to log in I only want to post the LoginFormViewModel (Model.EditForm) to the controller: public ActionResult Login(LoginFormViewModel loginDetails) { //do stuff } Using Html.TextBox I can specify the name of the form field manually 'loginDetails.UserName' and post back to the controller and everything works. @model Web.Controllers.User.ViewModels.LoginPageViewModel @using (Html.BeginForm()){ @Html.Hidden("loginDetails.ReturnUrl", Model.ReturnUrl) @Html.LabelFor(x => x.EditForm.UserName, "User Name:") @Html.TextBox("loginDetails.UserName", Model.EditForm.UserName) @Html.ValidationMessageFor(x => x.EditForm.UserName) ..... But what I want to do is to use the staticaly typed helper, something like: @Html.TextBoxFor(x => x.EditForm.UserName) But I'm unable to get this to work. Are you only able to post back the same model when useing the strongly typed helpers? Is there something I'm missing on this? Intellisense doesn't seem to give any clues such as a form field string.

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  • MVC Validator.TryValidateObject does not validate custom atrribute, validateAllProperties = true

    - by nealsu
    When calling Validator.TryValidateObject with validateAllProperties = true my custom validation attribute does not get triggered. The ValidationResult does not contain an entry for my erroneous property value. Below is the model, attribute and code used to test this. //Model public class Model { [AmountGreaterThanZero] public int? Amount { get; set; } } //Attribute public sealed class AmountGreaterThanZero: ValidationAttribute { private const string errorMessage = "Amount should be greater than zero."; public AmountGreaterThanZero() : base(errorMessage) { } public override string FormatErrorMessage(string name) { return errorMessage; } protected override ValidationResult IsValid(object value, ValidationContext validationContext) { if (value != null) { if ((int)value <= 0) { var message = FormatErrorMessage(validationContext.DisplayName); return new ValidationResult(message); } } return null; } } //Validation Code var container = new Container(); container.ModelList = new List<Model>() { new Model() { Amount = -5 } }; var validationContext = new ValidationContext(container, null, null); var validationResults = new List<ValidationResult>(); var modelIsValid = Validator.TryValidateObject(container, validationContext, validationResults, true); Note: That the validation works fine and ValidationResult returns with correct error message if I use the TryValidateProperty method.

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  • ASP.NET MVC Generic Partial

    - by gnome
    Is is possible to have a partial view inherit more than one model? I have three models (Contacts, Clients, Vendors) that all have address information (Address). In the interest of being DRY I pulled the address info into it's own model, Addresses. I created a partial create / update view of addresses and what to render this in other other three model's create / update views.

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  • Where do I put constants file for Codeigniter (PHP)?

    - by wag2639
    I have a list of constants (I'm using them as an enum), some are define statements, and some are just global variables. Where am I suppose to put them in the MVC framework so I can use them for both my model and my controller that needs to reference it? I'd rather not stick it into config/constants.php since they shouldn't be called except for by this model and the controllers that use it. Edit 1: Clarification To be more specific, I have my message_model model and it has a bunch of constants that I need that are stored in message_model_constants.php. Where should I put message_model_constants.php and is there a way to have it automatically included by the controller that loads message_model when message_model is not (and I don't want it to be) auto-loaded. Edit 2: I really don't want to have the constants auto-loaded except for when I use the model

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  • rendering html to png (server-side)

    - by jonny
    Hi! I have a workflow model. Internet Explorer doesn't support some features required for model editing functionality (and regular user doesn't need it). I want a read-only preview of my model. Is it possible to server-side render my html to image?

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  • Access: Expression too complex to be evaluated

    - by user2502964
    I'm trying to sort out values from a database by the weekending date. The script I'm using functions on 6 of my 7 databases (they are all constructed identically). The 7th database doesn't function. I get the expression too complex error. any help figuring out why?? Here is my code: SELECT UPC_Test.Type, UPC_Test.[Model No], UPC_Test.[Model Desc], UPC_Test.[Serial No], Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy") AS [Test Date], UPC_Test.Parameter, UPC_Test.[Failure Symptom], UPC_Test.[Repair Action], UPC_Test.[Factory Select], UPC_Test.[Test Station] FROM UPC_Test GROUP BY UPC_Test.Type, UPC_Test.[Model No], UPC_Test.[Model Desc], UPC_Test.[Serial No], Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy"), UPC_Test.Parameter, UPC_Test.[Failure Symptom], UPC_Test.[Repair Action], UPC_Test.[Factory Select], UPC_Test.[Test Station] HAVING (((UPC_Test.Type)="Production") AND ((Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy"))=[Enter]) AND ((UPC_Test.[Failure Symptom])<>"") AND ((UPC_Test.[Repair Action])<>"") AND ((UPC_Test.[Test Station])="UPC RF Test")) ORDER BY Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy");

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  • Setting Icon for wpf application (VS 08)

    - by baron
    Hi everyone, Before going much further i'll mention I have tried solutions in following: http://stackoverflow.com/questions/320677/how-do-i-set-the-icon-for-my-application-in-visual-studio-2008 http://stackoverflow.com/questions/198848/set-application-icon-from-resources-in-vs-05 I am trying to set an icon for my application. AFAIK, I need potentially 3 images? 1 image is the actual image in explorer when clicking on the .exe (thumbnail for the exe) 1 image (tiny) in the top left corner (16 x 16? Not entirely sure) 1 image in the start menu dock, to the left of the app (maybe 32x32? again not sure) So thats fine. Now I have selected an Icon. How do I use it in one of above situations? I have tried adding it in resources, nothing seems to happen. Following that first SO solution, "First go to Resource View (from menu: View -- Other Window -- Resource View). Then in Resource View navigate through resources, if any. If there is already a resource of Icon type, added by Visual Studio, then open and edit it. Otherwise right-click and select Add Resource, and then add a new icon." The resource view is empty, and I cannot right click in this view. If I right click on the solution properties resources I can add the icon image, but it doesn't show in either of the locations listed above. (or anywhere that I can see) What am I doing wrong?

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  • ManyToManyField error when having recursive structure. How to solve it?

    - by luc
    Hello, I have the following table in the model with a recursive structure (a page can have children pages) class DynamicPage(models.Model): name = models.CharField("Titre",max_length=200) parent = models.ForeignKey('self',null=True,blank=True) I want to create another table with manytomany relation with this one: class UserMessage(models.Model): name = models.CharField("Nom", max_length=100) page = models.ManyToManyField(DynamicPage) The generated SQL creates the following constraint: ALTER TABLE `website_dynamicpage` ADD CONSTRAINT `parent_id_refs_id_29c58e1b` FOREIGN KEY (`parent_id`) REFERENCES `website_dynamicpage` (`id`); I would like to have the ManyToMany with the page itself (the id) and not with the parent field. How to modify the model to make the constraint using the id and not the parent? Thanks in advance

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  • Need help getting buttons to work...

    - by Mike Droid
    I am trying to get my first button to update a display number in my view when clicked. This view will have several buttons and "outputs" displayed. After reading examples and Q's here, I finally put something together that runs, but my first button is still not working; public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.ship_layout); mSwitcher = (TextSwitcher) findViewById(R.id.eng_val); } private TextSwitcher mSwitcher; // Will be connected with the buttons via XML void onClick(View v){ switch (v.getId()) { case R.id.engplus: engcounter++; updateCounter(); break; case R.id.engneg: engcounter--; updateCounter(); break; } } private void updateCounter() { mSwitcher.setText(String.valueOf(engcounter)); } The .xml for this button is; <TextSwitcher android:id="@+id/eng_val" android:visibility="visible" android:paddingTop="9px" android:paddingLeft="50px" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_below="@+id/build" android:layout_toRightOf="@+id/engeq" android:textColor="#DD00ff00" android:textSize="24sp"/> This is within a Relative Layout that appears otherwise OK. When I had set the view to have a TextView with the number set as a string , the number displayed, but I could not figure out how to update the text with a numerical field. That may be my real problem. I have gone through many examples generally referenced from the dev. site (UI, Common Tasks, various samples), and I am still not seeing the connection here... Again, this is simply a try at getting variables to respond to buttons and update on the view. So, a few Q's for anyone that can help; 1) Is there any easier way of doing this (ie. send numerical value to View) ? 2) Why isn't my TextSwitcher displaying the number? 3) Should I be using a TextSwitcher here? 4) Any examples of this you can point me to?

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  • Entity framework: Need a easy going, clean database migration solution.

    - by user469652
    I'm using entity framework model first development, and I need to do database migration often, The EF database generation power pack doesn't help a lot, because that data migration never worked here. The database migration here I mean, change the model, and then I can update the existing database from the model, but creating a new one. Is there any free of charge tool here invented here yet? Or would this going to be a new feature of next EF release? PS: I love django's ORM.

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