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  • Too many heap subpools might break the upgrade

    - by Mike Dietrich
    Recently one of our new upcoming Oracle Database 11.2 reference customers did upgrade their production database - a huge EBS system - from Oracle 9.2.0.8 to Oracle Database 11.2.0.2. They've tested very well, we've optimized the upgrade process, the recompilation timings etc.  But once the live upgrade was done it did fail in the JAVA component piece with this error: begin if initjvmaux.startstep('CREATE_JAVA_SYSTEM') then * ORA-29553: classw in use: SYS.javax/mail/folder ORA-06512: at "SYS.INITJVMAUX", line 23 ORA-06512: at line 5 Support diagnosis was pretty quick - and refered to:Bug 10165223 - ORA-29553: class in use: sys.javax/mail/folder during database upgrade But how could this happen? Actually I don't know as we have used the same init.ora setup on test and production. The only difference: the prod system has more CPUs and RAM. Anyway, the bug names as workarounds to either decrease the SGA to less than 1GB or decrease the number of heap subpools to 1. Finally this query did help to diagnose the number of heap subpools: select count(distinct kghluidx) num_subpools from x$kghlu where kghlushrpool = 1; The result was 2 - so we did run the upgrade now with this parameter set: _kghdsidx_count=1 And finally it did work well. One sad thing:After the upgrade did fail Support did recommend to restore the whole database - which took an additional 3-4 hours. As the ORACLE SERVER component has been already upgraded successfully at the stage where the error did happen it would have been fine to go on with the manual upgrade and start catupgrd.sql script. It would have been detected that the ORACLE SERVER is upgraded already and just picked up the non-upgraded components. The good news:Finally I had one extra slide to add to our workshop presentation

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  • How to break out of if statement

    - by TheBroodian
    I'm not sure if the title is exactly an accurate representation of what I'm actually trying to ask, but that was the best I could think of. I am experiencing an issue with my character class. I have developed a system so that he can perform chain attacks, and something that was important to me was that 1)button presses during the process of an attack wouldn't interrupt the character, and 2) at the same time, button presses should be stored so that the player can smoothly queue up chain attacks in the middle of one so that gameplay doesn't feel rigid or unresponsive. This all begins when the player presses the punch button. Upon pressing the punch button, the game checks the state of the dpad at the moment of the button press, and then translates the resulting combined buttons into an int which I use as an enumerator relating to a punch method for the character. The enumerator is placed into a List so that the next time the character's Update() method is called, it will execute the next punch in the list. It only executes the next punch if my character is flagged with acceptInput as true. All attacks flag acceptInput as false, to prevent the interruption of attacks, and then at the end of an attack, acceptInput is set back to true. While accepting input, all other actions are polled for, i.e. jumping, running, etc. In runtime, if I attack, and then queue up another attack behind it (by pressing forward+punch) I can see the second attack visibly execute, which should flag acceptInput as false, yet it gets interrupted and my character will stop punching and start running if I am still holding down the dpad. Included is some code for context. This is the input region for my character. //Placed this outside the if (acceptInput) tree because I want it //to be taken into account whether we are accepting input or not. //This will queue up attacks, which will only be executed if we are accepting input. //This creates a desired effect that helps control the character in a // smoother fashion for the player. if (Input.justPressed(buttonManager.Punch)) { int dpadPressed = Input.DpadState(0); if (attackBuffer.Count() < 1) { attackBuffer.Add(CheckPunch(dpadPressed)); } else { attackBuffer.Clear(); attackBuffer.Add(CheckPunch(dpadPressed)); } } if (acceptInput) { if (attackBuffer.Count() > 0) { ExecutePunch(attackBuffer[0]); attackBuffer.RemoveAt(0); } //If D-Pad left is being held down. if (Input.DpadDirectionHeld(0, buttonManager.Left)) { flipped = false; if (onGround) { newAnimation = "run"; } velocity = new Vector2(velocity.X - acceleration, velocity.Y); if (walking == true && velocity.X <= -walkSpeed) { velocity.X = -walkSpeed; } else if (walking == false && velocity.X <= -maxSpeed) { velocity.X = -maxSpeed; } } //If D-Pad right is being held down. if (Input.DpadDirectionHeld(0, buttonManager.Right)) { flipped = true; if (onGround) { newAnimation = "run"; } velocity = new Vector2(velocity.X + acceleration, velocity.Y); if (walking == true && velocity.X >= walkSpeed) { velocity.X = walkSpeed; } else if (walking == false && velocity.X >= maxSpeed) { velocity.X = maxSpeed; } } //If jump/accept button is pressed. if (Input.justPressed(buttonManager.JumpAccept)) { if (onGround) { Jump(); } } //If toggle element next button is pressed. if (Input.justPressed(buttonManager.ToggleElementNext)) { if (elements.Count != 0) { elementInUse++; if (elementInUse >= elements.Count) { elementInUse = 0; } } } //If toggle element last button is pressed. if (Input.justPressed(buttonManager.ToggleElementLast)) { if (elements.Count != 0) { elementInUse--; if (elementInUse < 0) { elementInUse = Convert.ToSByte(elements.Count() - 1); } } } //If character is in the process of jumping. if (jumping == true) { if (Input.heldDown(buttonManager.JumpAccept)) { velocity.Y -= fallSpeed.Y; maxJumpTime -= elapsed; } if (Input.justReleased(buttonManager.JumpAccept) || maxJumpTime <= 0) { jumping = false; maxJumpTime = 0; } } //Won't execute abilities if input isn't being accepted. foreach (PlayerAbility ability in playerAbilities) { if (buffer.Matches(ability)) { if (onGround) { ability.Activate(); } if (!onGround && ability.UsableInAir) { ability.Activate(); } else if (!onGround && !ability.UsableInAir) { buffer.Clear(); } } } } When the attackBuffer calls ExecutePunch(int) method, ExecutePunch() will call one of the following methods: private void NeutralPunch1() //0 { acceptInput = false; busy = true; newAnimation = "punch1"; numberOfAttacks++; timeSinceLastAttack = 0; } private void ForwardPunch2(bool toLeft) //true == 7, false == 4 { forwardPunch2Timer = 0f; acceptInput = false; busy = true; newAnimation = "punch2begin"; numberOfAttacks++; timeSinceLastAttack = 0; if (toLeft) { velocity.X -= 800; } if (!toLeft) { velocity.X += 800; } } I assume the attack is being interrupted due to the fact that ExecutePunch() is in the same if statement as running, but I haven't been able to find a suitable way to stop this happening. Thank you ahead of time for reading this, I apologize for it having become so long winded.

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  • Xorg and Virtualbox break after installing Xen

    - by stueng
    I installed XEN using these instructions https://help.ubuntu.com/community/Xen Now when I rebooted virtualbox doesnt work, X doesnt work, lightdm doesnt work How can I set it back to how it was before? I presume I want to revert the following actions: Modify GRUB to default to booting Xen: sudo sed -i 's/GRUB_DEFAULT=.*\+/GRUB_DEFAULT="Xen 4.1-amd64"/' /etc/default/grub sudo update-grub Can someone tell me how?

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  • Wine causes twin view to break

    - by deanvz
    I have endlessly been playing around with the Nvidia X Server settings and changing my xorg.conf file to try and work for me and on most days its fine. In each instance I get it working for a while and then this morning the most bizarre thing happens. The moment I open any type of Wine program (which never use to be a problem) my Twin View setup disappears and am left with mirrored displays. I try and change the settings in the Nvidia driver, but its not interested and the screens remain mirrored. I have a work around. Restart my pc... Below are the contents of my current xorg.conf file. # nvidia-settings: X configuration file generated by nvidia-settings # nvidia-settings: version 295.33 (buildd@zirconium) Fri Mar 30 13:43:34 UTC 2012 Section "ServerLayout" Identifier "Layout0" Screen 0 "Screen0" 0 0 InputDevice "Keyboard0" "CoreKeyboard" InputDevice "Mouse0" "CorePointer" Option "Xinerama" "0" EndSection Section "Files" EndSection Section "InputDevice" # generated from default Identifier "Mouse0" Driver "mouse" Option "Protocol" "auto" Option "Device" "/dev/psaux" Option "Emulate3Buttons" "no" Option "ZAxisMapping" "4 5" EndSection Section "InputDevice" # generated from default Identifier "Keyboard0" Driver "kbd" EndSection Section "Monitor" # HorizSync source: edid, VertRefresh source: edid Identifier "Monitor0" VendorName "Unknown" ModelName "LG Electronics W1934" HorizSync 30.0 - 83.0 VertRefresh 56.0 - 75.0 Option "DPMS" EndSection Section "Device" Identifier "Device0" Driver "nvidia" VendorName "NVIDIA Corporation" BoardName "GeForce 9400 GT" EndSection Section "Screen" Identifier "Screen0" Device "Device0" Monitor "Monitor0" DefaultDepth 24 Option "TwinView" "1" Option "metamodes" "CRT-0: nvidia-auto-select +0+0, CRT-1: nvidia-auto-select +1440+0" SubSection "Display" Depth 24 EndSubSection EndSection

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  • Why did 13.10 break my custom keyboard layout?

    - by con-f-use
    I was using a custom keyboard layout. Basically I modified the us-mac layout to fit my ideal of a math-heavy version of the regular us layout that also throws German umlauts into mix. It went well and worked marvelously for 6 consecutive versions of Ubuntu. Today's version Upgrade (from 13.04 to 13.10) broke that streak. I now have the usual crappy Macintosh-Layout. Now xkb just ignores my layout and all of the other changes I make in /usr/share/X11/xkb/symbols/us (tried to switch '0' and '9' everywhere and rebooted - no effect). Why is that? I suspect I have to do an extra step now for the changes to take effect or something like that. Anyone care to point me in the right direction?

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  • Nvidia R310 Drivers break Starcraft

    - by user19192
    I was originally using the latest proprietary Nvidia drivers from nvidia-current, after upgrading the new R310 drivers my system works fine, but Starcraft 2 won't run anymore. (I'm running it through play-on-linux) I get that the application has attempted to load the C runtime library incorrectly and that DirectX failed to initialize. Previously, executing echo 0|sudo tee /proc/sys/kernel/yama/ptrace_scope would fix the problem, but does no longer work. Any ideas? Or do I have to downgrade back to nvidia-current drivers.

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  • How often do netbook parts break?

    - by kurresmack
    I need to know a list of how many percentage of all components break within a year. For example I would need to know how many percent of all netbook RAM is calculated to break within a year? This is a lot to ask, I know. But I really do need to know some facts on what to except to break when you have a lot of netbooks. Would be glad if someone had hard facts that could be backed up with resources. Only netbooks are considered.

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  • can I put the break on the same line

    - by brett
    I have a switch statement that has over 300 case statements. case 'hello': { $say = 'some text'; } break; case 'hi': { $say = 'some text'; } break; Why is it that the break is always on a separate line? Is this required? Is there anything syntactically incorrect about me doing this: case 'hello': { $say = 'some text'; } break; case 'hi': { $say = 'some text'; } break;

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  • Any way to break if statement in PHP?

    - by Usman
    Is there any command in PHP to stop executing the current or parent if statement, same as break or break(1) for switch/loop. For example $arr=array('a','b'); foreach($arr as $val) { break; echo "test"; } echo "finish"; in the above code PHP will not do echo "test"; and will go to echo "finish"; I need this for if $a="test"; if("test"==$a) { break; echo "yes"; // I don't want this line or lines after to be executed, without using another if } echo "finish"; I want to break the if statement above and stop executing echo "yes"; or such codes which are no longer necessary to be executed, there may be or may not be an additional condition, is there way to do this?

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  • How to break out of a nested parallel (OpenMP) Fortran loop idiomatically?

    - by J.F. Sebastian
    Here's sequential code: do i = 1, n do j = i+1, n if ("some_condition") then result = "here's result" return end if end do end do Is there a cleaner way to execute iterations of the outer loop concurrently other than: !$OMP PARALLEL private(i,j) !$OMP DO do i = 1, n if (found) goto 10 do j = i+1, n if (found) goto 10 if ("some_condition") then !$OMP CRITICAL !$OMP FLUSH if (.not.found) then found = .true. result = "here's result" end if !$OMP FLUSH !$OMP END CRITICAL goto 10 end if end do 10 continue end do !$OMP END DO NOWAIT !$OMP END PARALLEL

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  • How to add a footer to a table in Microsoft Word?

    - by dewalla
    I have a table that is longer than one page. I have found the option to make the header of the table to be added to the second portion of the table after the page break. Is there a way to do the same thing but with a footer on the table? I want to add a footer so that if my table was 1000 entries long (12 pages), that the first and last row of each page would be consistant; a header and footer for the table. If I edit the rest of the document (above the table) the table will shift up/down and I want to header and footer of the table to remain at the pagge breaks. Any Ideas? PAGE BREAK HEADER OF TABLE TBL TBL TBL TBL TBL TBL TBL TBL TBL TBL TBL TBL FOOTER OF TABLE PAGE BREAK HEADER OF TABLE TBL TBL TBL TBL TBL TBL FOOTER OF TABLE TEXTTEXTETEXT PAGE BREAK

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  • Is "}while(0);" always equal to "break;}while(1);" ?

    - by Hernán Eche
    I have compared gcc assembler output of do{ //some code }while(0); with do{ //some code break; }while(1); The output is equal, with or without optimization but.. It's always that way? No experiment can prove theories, they can only show they are wrong And because (I hope) programming is not an experimental science, and results can be predicted (at least simple things) I want to be sure next time I reeplace a break;}while(1); for the clearer (and less risky) while(0); Thank you for reading

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  • LEMP Stack on Ubuntu Server 13.04 not parsing PHP Switch Statement Properly

    - by schester
    On my Ubuntu 12.04 Server LTS on nginx 1.1.19, the following PHP code works properly: switch($_SESSION['user']['permissions']) { case 9: echo "Super Admin Privileges"; break; case 0: echo "Operator Privileges"; break; case 1: echo "Line Leader Privileges"; break; case 2: echo "Supervisor Privileges"; break; case 3: echo "Engineer Privileges"; break; case 4: echo "Manager Privileges"; break; case 5: echo "Administrator Privileges"; break; default: echo "Operator Privileges"; } However, I have a backup server running Ubuntu Server 13.04 on nginx 1.4.1 which has the exact same copy of the script (synced) but instead of breaking on the break; command, it echos the whole php script. The output on the 12.04 Box is similar to this: You are logged in with Super Admin Privileges But on the 13.04 Box, the output is like this: You are logged in logged in with Super Admin Privileges"; break; case 0: echo "Operator Privileges"; break; case 1: echo "Line Leader Privileges"; break; case 2: echo "Supervisor Privileges"; break; case 3: echo "Engineer Privileges"; break; case 4: echo "Manager Privileges"; break; case 5: echo "Administrator Privileges"; break; default: echo "Operator Privileges"; } ?> I have also tried changing the script from switch statement to if statements but same results. Any idea what is wrong?

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  • Break in Class Module vs. Break on Unhandled Errors (VB6 Error Trapping, Options Setting in IDE)

    - by Erx_VB.NExT.Coder
    Basically, I'm trying to understand the difference between the "Break in Class Module" and "Break on Unhandled Errors" that appear in the Visual Basic 6.0 IDE under the following path: Tools --> Options --> General --> Error Trapping The three options appear to be: Break on All Errors Break in Class Module Break on Unhandled Errors Now, apparently, according to MSDN, the second option (Break in Class Module) really just means "Break on Unhandled Errors in Class Modules". Also, this option appears to be set by default (ie: I think its set to this out of the box). What I am trying to figure out is, if I have the second option selected, do I get the third option (Break on Unhandled Errors) for free? In that, does it come included by default for all scenarios outside of the Class Module spectrum? To advise, I don't have any Class Modules in my currently active project. I have .bas modules though. Also, is it possible that by Class Mdules they may be referring to normal .bas Modules as well? (this is my second sub-question). Basically, I just want the setting to ensure there won't be any surprises once the exe is released. I want as many errors to display as possible while I am developing, and non to be displayed when in release mode. Normally, I have two types of On Error Resume Next on my forms where there isn't explicit error handling, they are as follows: On Error Resume Next ' REQUIRED On Error Resume Next ' NOT REQUIRED The required ones are things like, checking to see if an array has any length, if a call to its UBound errors out, that means it has no length, if it returns a value 0 or more, then it does have length (and therefore, exists). These types of Error Statements need to remain active even while I am developing. However, the NOT REQUIRED ones shouldn't remain active while I am developing, so I have them all commented out to ensure that I catch all the errors that exist. Once I am ready to release the exe, I do a CTRL+H to find all occurrences of: 'On Error Resume Next ' NOT REQUIRED (You may have noticed they are commented out)... And replace them with: On Error Resume Next ' NOT REQUIRED ... The uncommented version, so that in release mode, if there are any leftover errors, they do not show to users. For more on the description by MSDN on the three options (which I've read twice and still don't find adequate) you can visit the following link: http://webcache.googleusercontent.com/search?q=cache:yUQZZK2n2IYJ:support.microsoft.com/kb/129876&hl=en&lr=lang_en%7Clang_tr&gl=au&tbs=lr:lang_1en%7Clang_1tr&prmd=imvns&strip=1 I’m also interested in hearing your thoughts if you feel like volunteering them (and this would be my tentative/totally optional third sub-question, that being, your thoughts on fall-back error handling techniques). Just to summarize, the first two questions were, do we get option 3 included in all non-class scenarios if we choose option 2? And, is it possible that when they use the term "Class Module" they may be referring to .bas Modules as well? (Since a .bad Module is really just a class module that is pre-instantiated in the background during start-up). Thank you.

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  • Debugger does not break when debugging PowerShell console

    - by Adam Driscoll
    I'm developing a binary PowerShell module. I have a post build event that copies that module into the 'modules' directory in my "Documents\WindowsPowerShell" folder. I then have the project set to launch PowerShell.exe. My module is loaded via Import-Module and off I go. The problem is my break points are never hit and the debugger does not break on exceptions. If I run PowerShell outside of Visual Studio and then attach the debugger to the process I can break just fine. The other strange this is that my break points are not empty. Typically if different source versions are loaded they will be. I'm running Visual Studio 2010 on a Win 7 box. My module is currently targeting .NET 3.5. I've tried running both the x64 and x86 versions of PS with no luck.

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  • Break the nested(double) loop in python

    - by prosseek
    I use the following method to break the double loop in Python. for word1 in buf1: find = False for word2 in buf2: ... if res == res1: print "BINGO " + word1 + ":" + word2 find = True if find: break Is there better way to break the double loop?

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  • Is using the break statement bad practice?

    - by Lchi
    I've been told by professors and peers at my university that using the break statement is bad practice, but through my coursework haven't come up with a great reason why. Those who claim that it is bad say that it's a "get out of jail free card" and that you can always avoid using it. My guesses for why its considered bad would be that you could possibly skip some cleanup code after the break, or similarly exit some control structure in an inconsistent state. Is there any reason why using break is(n't) bad practice?

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  • C++: Short question regarding switch and break

    - by oh boy
    Example: switch( x ) { case y: if ( true ) { break; } cout << "Oops"; break; } If the switch statement selects y, will Oops be written to the standard output? - Is break in switch statements a dynamic keyword like continue which can be called under conditions or static like a closing bracket }?

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  • Storing unique values into an array and comparing against a loop - PHP

    - by Aphex22
    I'm writing a PHP report which is designed to be exported purely as a CSV file, using commma delimiters. There are three columns relating to product_id, these three columns are as follows: SKU Parent / Child Parent SKU 12345 parent 12345 12345_1 child 12345 12345_2 child 12345 12345_3 child 12345 12345_4 child 12345 18099 parent 18099 18099_1 child 18099 Here's a link to the full CSV file: http://i.imgur.com/XELufRd.png At the moment the code looks like this: $sql = "select * from product WHERE on_amazon = 'on' AND active = 'on'"; $result = mysql_query($sql) or die ( mysql_error() );?> <? // set headers echo " Type, SKU, Parent / Child, Parent SKU, Product name, Manufacturer name, Gender, Product_description, Product price, Discount price, Quantity, Category, Photo 1, Photo 2, Photo 3, Photo 4, Photo 5, Photo 6, Photo 7, Photo 8, Color id, Color name, Size name <br> "; // load all stock while ($line = mysql_fetch_assoc($result) ) { ?> <?php // Loop through each possible size variation to see whether any of the quantity column has stock > 0 $con_size = array (35,355,36,37,375,38,385,39,395,40,405,41,415,42,425,43,435,44,445,45,455,46,465,47,475,48,485); $arrlength=count($con_size); for($x=0;$x<$arrlength;$x++) { // check if size is available if($line['quantity_c_size_'.$con_size[$x].'_chain'] > 0 ) { ?> <? echo 'Shoes'; ?>, <?=$line['product_id']?>, , , <?=$line['title']?>, <? $brand = $line['jys_brand']; echo ucfirst($brand); ?>, <? $gender = $line['category']; if ($gender == 'Mens') { echo 'H'; } else{ echo 'F'; } ?>, <?=preg_replace('/[^\da-z]/i', ' ', $line['amazon_desc']) ?>, <?=$line['price']?>, <?=$line['price']?>, <?=$line['quantity_c_size_'.$con_size[$x].'_chain']?>, <? $category = $line['style1']; switch ($category) { case "ankle-boots": echo "10013"; break; case "knee-high-boots": echo "10011"; break; case "high-heel-boots": echo "10033"; break; case "low-heel-boots": echo "10014"; break; case "wedge-boots": echo "10014"; break; case "western-boots": echo "10032"; break; case "flat-shoes": echo "10034"; break; case "high-heel-shoes": echo "10039"; break; case "low-heel-shoes": echo "10039"; break; case "wedge-shoes": echo "10035"; break; case "ballerina-shoes": echo "10008"; break; case "boat-shoes": echo "10018"; break; case "loafer-shoes": echo "10037"; break; case "work-shoes": echo "10039"; break; case "flat-sandals": echo "10041"; break; case "low-heel-sandals": echo "10042"; break; case "high-heel-sandals": echo "10042"; break; case "wedge-sandals": echo "10042"; break; case "mule-sandals": echo "10038"; break; case "mary-jane-shoes": echo "10039"; break; case "sports-shoes": echo "10026"; break; case "court-shoes": echo "10035"; break; case "peep-toe-shoes": echo "10035"; break; case "flat-boots": echo "10609"; break; case "mid-calf-boots": echo "10014"; break; case "trainer-shoes": echo "10009"; break; case "wellington-boots": echo "10012"; break; case "lace-up-boots": echo "10609"; break; case "chelsea-and-jodphur-boots": echo "10609"; break; case "desert-and-chukka-boots": echo "10032"; break; case "lace-up-shoes": echo "10034"; break; case "slip-on-shoes": echo "10043"; break; case "gibson-and-derby-shoes": echo "10039"; break; case "oxford-shoes": echo "10039"; break; case "brogue-shoes": echo "10039"; break; case "winter-boots": echo "10021"; break; case "slipper-shoes": echo "10016"; break; case "mid-heel-shoes": echo "10039"; break; case "sandals-and-beach-shoes": echo "10044"; break; case "mid-heel-sandals": echo "10042"; break; case "mid-heel-boots": echo "10014"; break; default: echo ""; } ?>, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_1.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_2.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_3.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_4.jpg, , , , , <? $colour = preg_replace('/[^\da-z]/i', ' ', $line['colour']); if( preg_match( '/white.*/i', $colour)) { echo '1'; } elseif( preg_match( '/yellow.*/i', $colour)) { echo '4'; } elseif( preg_match( '/orange.*/i', $colour)) { echo '7'; } elseif( preg_match( '/red.*/i', $colour)) { echo '8'; } elseif( preg_match( '/pink.*/i', $colour)) { echo '13'; } elseif( preg_match( '/purple.*/i', $colour)) { echo '15'; } elseif( preg_match( '/blue.*/i', $colour)) { echo '19'; } elseif( preg_match( '/green.*/i', $colour)) { echo '25'; } elseif( preg_match( '/brown.*/i', $colour)) { echo '28'; } elseif( preg_match( '/grey.*/i', $colour)) { echo '35'; } elseif( preg_match( '/black.*/i', $colour)) { echo '38'; } elseif( preg_match( '/gold.*/i', $colour)) { echo '41'; } elseif( preg_match( '/silver.*/i', $colour)) { echo '46'; } elseif( preg_match( '/multi.*/i', $colour)) { echo '594'; } elseif( preg_match( '/beige.*/i', $colour)) { echo '6887'; } elseif( preg_match( '/nude.*/i', $colour)) { echo '6887'; } else { echo '534'; } ?>, <?=$line['colour']?>, <?=$con_size[$x]?> <br> <? // finish checking if size is available } } ?> So at the moment this is simply echoing out the product_ID into the SKU column. The code would need to enter the product_id into an array and check whether it is unique. If the product_id is unique to the array, then the product_id is echoed out unaltered, and parent is echoed out to the 'Parent/Child' column and then the product_id is repeated to the 'Parent SKU' column. However, if the array is checked and the product_id already exists in the array, then the product_id is echoed out to the 'SKU' column with a suffix i.e. _1. Then child is echoed to the 'Parent / Child' column and the original parent product_id echoed to the 'Parent SKU' column. HOWEVER - the same SKU cannot be repeated with the same suffix i.e. 12345_1, 12345_1 - so presumably there would be to be another array for the suffixed SKUs to be checked against. If anybody could help, it would be great. Thanks --- UPDATE ANSWER --- I managed to solved this myself and thought I would share my solution for future reference. /* * Array to collect product_ids and check whether unique. * If unique product_id becomes parent SKU * If not product_id becomes child of previous parent and suffixed with _1, _2 etc... */ if (!in_array($line['product_id'], $SKU)) { $SKU[] = $line['product_id']; $parent = $line['product_id']; $a = 0; ?> <? echo 'Shoes'; ?>, <? echo $parent; ?>, <? echo "Parent"; ?>, <? echo $parent; ?>, <? } else { $child = $line['product_id'] . "_" . $a; ?> <? echo 'Shoes'; ?>, <? echo $child; ?>, <? echo "Child"; ?>, <? echo $child; <? // increment suffix value for child SKU $a++; ?>

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  • Don't break header/footer when making page landscape format

    - by Steeven
    I have a document with a footer with page numbering and a header with some centered text. Long story short: I flipped one page to landscape format. Long story long: I made a forced page break to get a blank page. I then highlighted this page (that is, I highlighted the empty line on this page) and went to the page proporties menu window, clicked on the landscape format button, and chose to apply this setting for the highlighted text only. The result: All that is of course no big deal, and my page is flipped the 90 degrees as wished - but my header and footer break! They disappear from this page... and actually also from the next page (which is still upright portrait format), which is weird. And then the header and footer is back on the following pages again, though the page numbering restarts from 1. On this screenshot you can see that the previous and the following pages have headers and footers, but not the flipped one and not the page following the flipped one. What just happened here? How can I make the page numbering continue without restarting first of all, and then, how can I keep the header and footer on at least the upright page, that suddenly doesn't have them?

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  • Parallelism in .NET – Part 3, Imperative Data Parallelism: Early Termination

    - by Reed
    Although simple data parallelism allows us to easily parallelize many of our iteration statements, there are cases that it does not handle well.  In my previous discussion, I focused on data parallelism with no shared state, and where every element is being processed exactly the same. Unfortunately, there are many common cases where this does not happen.  If we are dealing with a loop that requires early termination, extra care is required when parallelizing. Often, while processing in a loop, once a certain condition is met, it is no longer necessary to continue processing.  This may be a matter of finding a specific element within the collection, or reaching some error case.  The important distinction here is that, it is often impossible to know until runtime, what set of elements needs to be processed. In my initial discussion of data parallelism, I mentioned that this technique is a candidate when you can decompose the problem based on the data involved, and you wish to apply a single operation concurrently on all of the elements of a collection.  This covers many of the potential cases, but sometimes, after processing some of the elements, we need to stop processing. As an example, lets go back to our previous Parallel.ForEach example with contacting a customer.  However, this time, we’ll change the requirements slightly.  In this case, we’ll add an extra condition – if the store is unable to email the customer, we will exit gracefully.  The thinking here, of course, is that if the store is currently unable to email, the next time this operation runs, it will handle the same situation, so we can just skip our processing entirely.  The original, serial case, with this extra condition, might look something like the following: foreach(var customer in customers) { // Run some process that takes some time... DateTime lastContact = theStore.GetLastContact(customer); TimeSpan timeSinceContact = DateTime.Now - lastContact; // If it's been more than two weeks, send an email, and update... if (timeSinceContact.Days > 14) { // Exit gracefully if we fail to email, since this // entire process can be repeated later without issue. if (theStore.EmailCustomer(customer) == false) break; customer.LastEmailContact = DateTime.Now; } } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } Here, we’re processing our loop, but at any point, if we fail to send our email successfully, we just abandon this process, and assume that it will get handled correctly the next time our routine is run.  If we try to parallelize this using Parallel.ForEach, as we did previously, we’ll run into an error almost immediately: the break statement we’re using is only valid when enclosed within an iteration statement, such as foreach.  When we switch to Parallel.ForEach, we’re no longer within an iteration statement – we’re a delegate running in a method. This needs to be handled slightly differently when parallelized.  Instead of using the break statement, we need to utilize a new class in the Task Parallel Library: ParallelLoopState.  The ParallelLoopState class is intended to allow concurrently running loop bodies a way to interact with each other, and provides us with a way to break out of a loop.  In order to use this, we will use a different overload of Parallel.ForEach which takes an IEnumerable<T> and an Action<T, ParallelLoopState> instead of an Action<T>.  Using this, we can parallelize the above operation by doing: Parallel.ForEach(customers, (customer, parallelLoopState) => { // Run some process that takes some time... DateTime lastContact = theStore.GetLastContact(customer); TimeSpan timeSinceContact = DateTime.Now - lastContact; // If it's been more than two weeks, send an email, and update... if (timeSinceContact.Days > 14) { // Exit gracefully if we fail to email, since this // entire process can be repeated later without issue. if (theStore.EmailCustomer(customer) == false) parallelLoopState.Break(); else customer.LastEmailContact = DateTime.Now; } }); There are a couple of important points here.  First, we didn’t actually instantiate the ParallelLoopState instance.  It was provided directly to us via the Parallel class.  All we needed to do was change our lambda expression to reflect that we want to use the loop state, and the Parallel class creates an instance for our use.  We also needed to change our logic slightly when we call Break().  Since Break() doesn’t stop the program flow within our block, we needed to add an else case to only set the property in customer when we succeeded.  This same technique can be used to break out of a Parallel.For loop. That being said, there is a huge difference between using ParallelLoopState to cause early termination and to use break in a standard iteration statement.  When dealing with a loop serially, break will immediately terminate the processing within the closest enclosing loop statement.  Calling ParallelLoopState.Break(), however, has a very different behavior. The issue is that, now, we’re no longer processing one element at a time.  If we break in one of our threads, there are other threads that will likely still be executing.  This leads to an important observation about termination of parallel code: Early termination in parallel routines is not immediate.  Code will continue to run after you request a termination. This may seem problematic at first, but it is something you just need to keep in mind while designing your routine.  ParallelLoopState.Break() should be thought of as a request.  We are telling the runtime that no elements that were in the collection past the element we’re currently processing need to be processed, and leaving it up to the runtime to decide how to handle this as gracefully as possible.  Although this may seem problematic at first, it is a good thing.  If the runtime tried to immediately stop processing, many of our elements would be partially processed.  It would be like putting a return statement in a random location throughout our loop body – which could have horrific consequences to our code’s maintainability. In order to understand and effectively write parallel routines, we, as developers, need a subtle, but profound shift in our thinking.  We can no longer think in terms of sequential processes, but rather need to think in terms of requests to the system that may be handled differently than we’d first expect.  This is more natural to developers who have dealt with asynchronous models previously, but is an important distinction when moving to concurrent programming models. As an example, I’ll discuss the Break() method.  ParallelLoopState.Break() functions in a way that may be unexpected at first.  When you call Break() from a loop body, the runtime will continue to process all elements of the collection that were found prior to the element that was being processed when the Break() method was called.  This is done to keep the behavior of the Break() method as close to the behavior of the break statement as possible. We can see the behavior in this simple code: var collection = Enumerable.Range(0, 20); var pResult = Parallel.ForEach(collection, (element, state) => { if (element > 10) { Console.WriteLine("Breaking on {0}", element); state.Break(); } Console.WriteLine(element); }); If we run this, we get a result that may seem unexpected at first: 0 2 1 5 6 3 4 10 Breaking on 11 11 Breaking on 12 12 9 Breaking on 13 13 7 8 Breaking on 15 15 What is occurring here is that we loop until we find the first element where the element is greater than 10.  In this case, this was found, the first time, when one of our threads reached element 11.  It requested that the loop stop by calling Break() at this point.  However, the loop continued processing until all of the elements less than 11 were completed, then terminated.  This means that it will guarantee that elements 9, 7, and 8 are completed before it stops processing.  You can see our other threads that were running each tried to break as well, but since Break() was called on the element with a value of 11, it decides which elements (0-10) must be processed. If this behavior is not desirable, there is another option.  Instead of calling ParallelLoopState.Break(), you can call ParallelLoopState.Stop().  The Stop() method requests that the runtime terminate as soon as possible , without guaranteeing that any other elements are processed.  Stop() will not stop the processing within an element, so elements already being processed will continue to be processed.  It will prevent new elements, even ones found earlier in the collection, from being processed.  Also, when Stop() is called, the ParallelLoopState’s IsStopped property will return true.  This lets longer running processes poll for this value, and return after performing any necessary cleanup. The basic rule of thumb for choosing between Break() and Stop() is the following. Use ParallelLoopState.Stop() when possible, since it terminates more quickly.  This is particularly useful in situations where you are searching for an element or a condition in the collection.  Once you’ve found it, you do not need to do any other processing, so Stop() is more appropriate. Use ParallelLoopState.Break() if you need to more closely match the behavior of the C# break statement. Both methods behave differently than our C# break statement.  Unfortunately, when parallelizing a routine, more thought and care needs to be put into every aspect of your routine than you may otherwise expect.  This is due to my second observation: Parallelizing a routine will almost always change its behavior. This sounds crazy at first, but it’s a concept that’s so simple its easy to forget.  We’re purposely telling the system to process more than one thing at the same time, which means that the sequence in which things get processed is no longer deterministic.  It is easy to change the behavior of your routine in very subtle ways by introducing parallelism.  Often, the changes are not avoidable, even if they don’t have any adverse side effects.  This leads to my final observation for this post: Parallelization is something that should be handled with care and forethought, added by design, and not just introduced casually.

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  • C++: Switch statement within while loop?

    - by Jason
    I just started C++ but have some prior knowledge to other languages (vb awhile back unfortunately), but have an odd predicament. I disliked using so many IF statements and wanted to use switch/cases as it seemed cleaner, and I wanted to get in the practice.. But.. Lets say I have the following scenario (theorietical code): while(1) { //Loop can be conditional or 1, I use it alot, for example in my game char something; std::cout << "Enter something\n -->"; std::cin >> something; //Switch to read "something" switch(something) { case 'a': cout << "You entered A, which is correct"; break; case 'b': cout << "..."; break; } } And that's my problem. Lets say I wanted to exit the WHILE loop, It'd require two break statements? This obviously looks wrong: case 'a': cout << "You entered A, which is correct"; break; break; So can I only do an IF statement on the 'a' to use break;? Am I missing something really simple? This would solve a lot of my problems that I have right now.

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