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  • Robust line of sight test on the inside of a polygon with tolerance

    - by David Gouveia
    Foreword This is a followup to this question and the main problem I'm trying to solve. My current solution is an hack which involves inflating the polygon, and doing most calculations on the inflated polygon instead. My goal is to remove this step completely, and correctly solve the problem with calculations only. Problem Given a concave polygon and treating all of its edges as if they were walls in a level, determine whether two points A and B are in line of sight of each other, while accounting for some degree of floating point errors. I'm currently basing my solution on a series of line-segment interection tests. In other words: If any of the end points are outside the polygon, they are not in line of sight. If both end points are inside the polygon, and the line segment from A to B crosses any of the edges from the polygon, then they are not in line of sight. If both end points are inside the polygon, and the line segment from A to B does not cross any of the edges from the polygon, then they are in line of sight. But the problem is dealing correctly with all the edge cases. In particular, it must be able to deal with all the situations depicted below, where red lines are examples that should be rejected, and green lines are examples that should be accepted. I probably missed a few other situations, such as when the line segment from A to B is colinear with an edge, but one of the end points is outside the polygon. One point of particular interest is the difference between 1 and 9. In both cases, both end points are vertices of the polygon, and there are no edges being intersected, but 1 should be rejected while 9 should be accepted. How to distinguish these two? I could check some middle point within the segment to see if it falls inside or not, but it's easy to come up with situations in which it would fail. Point 7 was also pretty tricky and I had to to treat it as a special case, which checks if two points are adjacent vertices of the polygon directly. But there are also other chances of line segments being col linear with the edges of the polygon, and I'm still not entirely sure how I should handle those cases. Is there any well known solution to this problem?

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  • receiving "command not found" error messages after fresh reinstall of Lubuntu 14.04

    - by user236378
    Lubuntu 14.04 was working really great. . .until I messed up and had to do a complete fresh reinstall. Now I receive error messages when I input commands into the Terminal, even after immediately completing the fresh install. For example I type: sudo leafpad ?/etc/default/ or sudo leafpad ?/etc/default/grub I get: sudo: leafpad: command not found I type: sudo update-initramfs ?-u or sudo update-grub I get: sudo: update-initramfs: command not found or sudo: update-grub: command not found If I use the command mkdir I get: mkdir: command not found I also get this same exact error message, command not found, with sudo apt-get and wget In other words I can't do anything that I was able to do when inputting commands into the terminal. So I cannot add any repositories or update anything at all. I am not really sure what is causing the problem(s). It appeared to me that Lubuntu installed and booted up OK. However just as soon as I enter anything into the Terminal I immediately get the above error messages. I have tried to do the reinstall three times, same error messages. If anyone can suggest any fixes I would really appreciate it very much. Thank you!

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  • Alternatives for 'egrep -o "success|error|fail" <filename> | sort | uniq -c'

    - by Wolfy
    I sometime need to check some logs and I do this with this command: egrep -o "success|error|fail" <filename> | sort | uniq -c Sample input: test error on line 10 test connect success test insert success test started at 00:00 test delete fail Sample output: 1 error 1 fail 2 success I would like to know if someone knows a way to do this with a shorter command? Before you ask why I would like to do this with an different command... No special reason, I'm just curious :)

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  • Connect to a network via the command line [closed]

    - by justasking
    I want to be able to connect to a network via command line in Windows. My goal is to script out remoting into my work computer. I hate having to always manually connect to the VPN connection and then rdping into my work machine. I want to just have a script which will do both of it for me. I know how to rdp via command line, I just need to know how to connect to my VPN via command line.

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  • ifconfig : Command 'ifconfig' is available in '/sbin/ifconfig'

    - by Sahil Grover
    My question is related to another open question. My echo $PATH gives me an output which is like /home/sahil/.rvm/gems/ruby-1.9.3-p125/bin:/home/sahil/.rvm/gems/ruby-1.9.3-p125@global/bin:/home/sahil/.rvm/rubies/ruby-1.9.3-p125/bin:/home/sahil/.rvm/bin:/usr/local/bin:/usr/bin:/bin:/usr/games:/home/sahil/.rvm/bin{}:/home/android-sdks/{}:/home/android-sdks/platform-tools/{}:/home/android-sdks/tools/{}:/home/sahil/android-sdks/tools{}:/home/sahil/android-sdks/tools:/home/sahil/android-sdks/platform-tools/ But running ifconfig gives me an output like Command 'ifconfig' is available in '/sbin/ifconfig' The command could not be located because '/sbin' is not included in the PATH environment variable. This is most likely caused by the lack of administrative privileges associated with your user account. ifconfig: command not found after running command like given in other question export PATH="/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games" it runs ifconfig but blocks other commands of ruby rails or rvm. Seeking help how to resolve this. Also why this happens?

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  • Terminal line glitches

    - by foxy
    I installed Ubuntu 11.10 mini + LXDE and wanted to make my command line different in terminal (than just plain white), so I added blue color to path line (everything until $ sign) and it works fine but I have two strange glitches now: When i write a line which is longer than terminal window, instead of starting at next line it starts at the same one, overwriting everything which was in there. Sometimes while navigating over previous commands (up/down arrow keys) some part of command gets stuck and is treated as part of prompt (the blue text), but it is white and is non-deletable and is not taken as part of command when i press enter. What could I mess up? The bad thing is that I don't remember what exactly did I change, but i'm sure I changed only one line in bashrc

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  • How do I get long command lines to wrap to the next line?

    - by BrianH
    Edit It was my .bashrc file. I've copied the same profile from machine to machine, and I used special characters in my $PS1 that are somehow throwing it off. I'm now sticking with the standard bash variables for my $PS1. Thanks to @ændrük for the tip on the .bashrc! ...End Edit... Something I have noticed in Ubuntu for a long time that has been frustrating to me is when I am typing a command at the command line that gets longer (wider) than the terminal width, instead of wrapping to a new line, it goes back to column 1 on the same line and starts over-writing the beginning of my command line. (It doesn't actually overwrite the actual command, but visually, it is overwriting the text that was displayed). It's hard to explain without seeing it, but let's say my terminal was 20 characters wide (Mine is more like 120 characters - but for the sake of an example), and I want to echo the English alphabet. What I type is this: echo abcdefghijklmnopqrstuvwxyz But what my terminal looks like before I hit the key is: pqrstuvwxyzghijklmno When I hit enter, it echos abcdefghijklmnopqrstuvwxyz so I know the command was received properly. It just wrapped my typing after the "o" and started over on the same line. What I would expect to happen, if I typed this command in on a terminal that was only 20 characters wide would be this: echo abcdefghijklmno pqrstuvwxyz Background: I am using bash as my shell, and I have this line in my ~/.bashrc: set -o vi to be able to navigate the command line with VI commands. I am currently using Ubuntu 10.10 server, and connecting to the server with Putty. In any other environment I have worked in, if I type a long command line, it will add a new line underneath the line I am working on when my command gets longer than the terminal width and when I keep typing I can see my command on 2 different lines. But for as long as I can remember using Ubuntu, my long commands only occupy 1 line. This also happens when I am going back to previous commands in the history (I hit Esc, then 'K' to go back to previous commands) - when I get to a previous command that was longer than the terminal width, the command line gets mangled and I cannot tell where I am at in the command. The only work-around I have found to see the entire long command is to hit "Esc-V", which opens up the current command in a VI editor. I don't think I have anything odd in my .bashrc file. I commented out the "set -o vi" line, and I still had the problem. I downloaded a fresh copy of Putty and didn't make any changes to the configuration - I just typed in my host name to connect, and I still have the problem, so I don't think it's anything with Putty (unless I need to make some config changes) Has anyone else had this problem, and can anyone think of how to fix it? Thanks in advance! Brian

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  • How do I get long command lines to wrap to the next line?

    - by BrianH
    Edit It was my .bashrc file. I've copied the same profile from machine to machine, and I used special characters in my $PS1 that are somehow throwing it off. I'm now sticking with the standard bash variables for my $PS1. Thanks to @ændrük for the tip on the .bashrc! ...End Edit... Something I have noticed in Ubuntu for a long time that has been frustrating to me is when I am typing a command at the command line that gets longer (wider) than the terminal width, instead of wrapping to a new line, it goes back to column 1 on the same line and starts over-writing the beginning of my command line. (It doesn't actually overwrite the actual command, but visually, it is overwriting the text that was displayed). It's hard to explain without seeing it, but let's say my terminal was 20 characters wide (Mine is more like 120 characters - but for the sake of an example), and I want to echo the English alphabet. What I type is this: echo abcdefghijklmnopqrstuvwxyz But what my terminal looks like before I hit the key is: pqrstuvwxyzghijklmno When I hit enter, it echos abcdefghijklmnopqrstuvwxyz so I know the command was received properly. It just wrapped my typing after the "o" and started over on the same line. What I would expect to happen, if I typed this command in on a terminal that was only 20 characters wide would be this: echo abcdefghijklmno pqrstuvwxyz Background: I am using bash as my shell, and I have this line in my ~/.bashrc: set -o vi to be able to navigate the command line with VI commands. I am currently using Ubuntu 10.10 server, and connecting to the server with Putty. In any other environment I have worked in, if I type a long command line, it will add a new line underneath the line I am working on when my command gets longer than the terminal width and when I keep typing I can see my command on 2 different lines. But for as long as I can remember using Ubuntu, my long commands only occupy 1 line. This also happens when I am going back to previous commands in the history (I hit Esc, then 'K' to go back to previous commands) - when I get to a previous command that was longer than the terminal width, the command line gets mangled and I cannot tell where I am at in the command. The only work-around I have found to see the entire long command is to hit "Esc-V", which opens up the current command in a VI editor. I don't think I have anything odd in my .bashrc file. I commented out the "set -o vi" line, and I still had the problem. I downloaded a fresh copy of Putty and didn't make any changes to the configuration - I just typed in my host name to connect, and I still have the problem, so I don't think it's anything with Putty (unless I need to make some config changes) Has anyone else had this problem, and can anyone think of how to fix it? Thanks in advance! Brian

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  • Connect to a network via Command Linke

    - by justasking
    Hi guys, I want to be able to connect to a network via command line in Windows. My goal is to script out remoting into my work computer. I hate having to always manually connect to the VPN connection and then rdping into my work machine. I want to just have a script which will do both of it for me. I know how to rdp via command line, I just need to know how to connect to my VPN via command line. Thanks!

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  • Command to zip a directory using a specific directory as the root

    - by Slokun
    I'm writing a PHP script that downloads a series of generated files (using wget) into a directory, and then zips then up, using the zip command. The downloads work perfectly, and the zipping mostly works. I run the command: zip -r /var/www/oraviewer/rgn_download/download/fcst_20100318_0319.zip /var/www/oraviewer/rgn_download/download/fcst_20100318_0319 which yields a zip file with all the downloaded files, but it contains the full /var/www/oraviewer/rgn_download/download/ directories, before reaching the fcst_20100318_0319/ directory. I'm probably just missing a flag, or something small, from the zip command, but how do I get it to use fcst_20100318_0319/ as the root directory?

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  • command line tool text output

    - by Martin
    I have a small command line tool and after running it, I'd like to display the text output in a way that's easy for someone to copy/paste and save it or email it to someone else. Copy/pasting from a command prompt is not done in the standard way, so I don't want people to have to copy/paste from there. Saving the file to disk is possible, but the folder where the tool is located may not have access rights so the user would have to configure the output file location (this may be too tricky for some users). I was thinking of launching notepad with some text in it, generated from the command line tool. Is this possible? Any other suggestions?

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  • Running Command via Java ProccesBuilder Different to Running the same in the Shell

    - by Tom Duckering
    I'm tearing my hair out trying to work out why the command I'm executing via Java using a ProcessBuilder & Process is not working. I run the "same" command at the Windows command line and it works as expected. It must be that they're not the same but I can't for the life of me work out why. The command is this: ccm start -nogui -m -q -n ccm_admin -r developer -d /path/to/db/databasename -s http://hostname:8400 -pw Passw0rd789$ The output is should be a single line string that I need to grab and set as an environment variable (hence the v. basic use of the BufferedReader). My Java code, which when it runs the command gets an application error, looks like this with entry point being startCCMAndGetCCMAddress(): private static String ccmAddress = ""; private static final String DATABASE_PATH = "/path/to/db/databasename"; private static final String SYNERGY_URL = "http://hostname:8400"; private static final String USERNAME = "ccm_admin"; private static final String PASSWORD = "Passw0rd789$"; private static final String USER_ROLE = "developer"; public static List<String> getCCMStartCommand() { List<String> command = new ArrayList<String>(); command.add("cmd.exe"); command.add("/C"); command.add("ccm"); command.add("start"); command.add("-nogui"); command.add("-m"); command.add("-q"); command.add("-n "+USERNAME); command.add("-r "+USER_ROLE); command.add("-d "+DATABASE_PATH); command.add("-s "+SYNERGY_URL); command.add("-pw "+PASSWORD); return command; } private static String startCCMAndGetCCMAddress() throws IOException, CCMCommandException { int processExitValue = 0; List<String> command = getCCMStartCommand(); System.err.println("Will run: "+command); ProcessBuilder procBuilder = new ProcessBuilder(command); procBuilder.redirectErrorStream(true); Process proc = procBuilder.start(); BufferedReader outputBr = new BufferedReader(new InputStreamReader(proc.getInputStream())); try { proc.waitFor(); } catch (InterruptedException e) { processExitValue = proc.exitValue(); } String outputLine = outputBr.readLine(); outputBr.close(); if (processExitValue != 0) { throw new CCMCommandException("Command failed with output: " + outputLine); } if (outputLine == null) { throw new CCMCommandException("Command returned zero but there was no output"); } return outputLine; } The output of the System.err.println(...) is: Will run: [cmd.exe, /C, ccm, start, -nogui, -m, -q, -n ccm_admin, -r developer, -d /path/to/db/databasename, -s http://hostname:8400, -pw Passw0rd789$]

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  • What does "0 is wrong flag id" mean?

    - by Andreas
    When I edit system files, for example when I edit rules for my trackpoint using this command: gksu gedit /etc/udev/rules.d/trackpoint.rules I get the following errors in the terminal (after closing gedit and saving the file): error: line 10034: 0 is wrong flag id error: line 10034: 0 is wrong flag id error: line 11351: 0 is wrong flag id error: line 11351: 0 is wrong flag id error: line 11849: 0 is wrong flag id error: line 11849: 0 is wrong flag id error: line 15609: 0 is wrong flag id error: line 15609: 0 is wrong flag id error: line 19814: 0 is wrong flag id error: line 23363: 0 is wrong flag id error: line 23363: 0 is wrong flag id error: line 26005: 0 is wrong flag id error: line 26005: 0 is wrong flag id error: line 26846: 0 is wrong flag id error: line 26846: 0 is wrong flag id error: line 28718: 0 is wrong flag id error: line 31695: 0 is wrong flag id error: line 31695: 0 is wrong flag id error: line 35272: 0 is wrong flag id This goes on up until line 150400. The changes are applied as desired, but can somebody explain the error to me as I'm a newbie and just trying to get a clue about the terminal.

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  • Reverse all words in current line

    - by KasiyA
    I have a file and I want to reverse all word in it. Read line as long as (.) not seen, or seen (\n), if found first (.) in line then It is a word , so reverse this word and continue reading for next word in current line until end of file. ex input file: DCBA. HGFE.GI MLK,PON.RQ UTS. ZYXWV. 321 ex output file: (What I Want) ABCD. EFGH.IG KLM,NOP.QR STU. VWXYZ. 123 With this sed script: sed '/\n/!G;s/\(.\)\(.*\n\)/&\2\1/;//D;s/.//' in the entire line is reversed. The wrong output produced by the command above: IG.EFGH .ABCD QR.NOP,KLM 123 .VWXYZ .STU How can I get my desired output? Thanks for your help

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  • Replacing LF, NEL line endings in text file with CR+LF

    - by Tomas Lycken
    I have a text file with a strange character encoding that I'd like to convert to standard UTF-8. I have managed to get part of the way: $ file myfile.txt myfile.txt: Non-ISO extended-ASCII text, with LF, NEL line endings $ iconv -f ascii -t utf-8 myfile.txt > myfile.txt.utf8 $ file myfile.txt.utf8 myfile.txt.utf8: UTF-8 Unicode text, with LF, NEL line endings ## edit myfile.txt.utf8 using nano, to fix failed character conversions (mostly åäö) $ file myfile.txt.utf8 myfile.txt.utf8: UTF-8 Unicode text, with LF, NEL line endings However, I can't figure out how to convert the line endings. How do I do to replace LF+NEL with CR+LF (or whatever is the standard)? When I'm done, I'd like to see the following: $ file myfile.txt myfile.txt: UTF-8 Unicode text

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  • How to mount nexus 7 file system to view files from command line

    - by knotech
    Just got a Nexus 7, switched MTP on and plugged it in. It pops right up in nautilus, is titled Nexus 7, and lets me browse all of the files. However, on the command line, it's simply listed as /media/usbdrive and when I try to list the files, nothing comes up. Do I have to manually mount it in order to navigate the files from the command line? And why is it that nautilus recognizes it, and has access immediately, but I can't get at it from the command line?

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  • Retrieve a command from another, remote bash session

    - by Oli
    So I was on our laptop, SSH'd into my desktop, dropping some mad bashfu skill. There was one command I ran which was particularly skilful. I'm now about minute walk from the laptop and I really want that command here on my desktop, so that I can run it again. I realise I've already spent more time that it would have taken to rewrite it, but this has raised a common issue I have with bash history. I know I can force it to update each command, but I haven't... so: Is there any way to get a history from a different, live bash session?

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  • Input to program without command-line arguments

    - by Core Xii
    Let's assume that there are no command-line arguments. How do you pass input data to a program? I'm thinking you'd write the input to a file with a specific name, such that the program knows to open and read it as input. However, how would one discover the name of that file? Usually, running a command-line program without arguments or with some standard help argument (e.g. \?) produces some instruction on how to use it. But given an environment with no command-line arguments, how does one discover how to operate a program?

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  • CSS Horizontal Line

    - by Neb
    In my site I added google friend connect. Now on the right where the sidebar is, there is a small line. How do I remove the line because I dont want it there.

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  • C# and T-SQL command-line Utility

    - by Chad Sellers
    Group, Part 1: I'm currently working on a command line utility that can take args and update a local database. The only issue I have is once i established a "Data connection"..how can I use those args for queries and searches. For example: ~//arrInput.exe "parm1" "pram2" "pram3" Part 2: I would like to take in command line args and use them as input parms for a "stored proc". Once finished execution....used the same inputs crate a log file. For example output file: mm-dd-yyyy hh:mm:ss - pram1,pram2,... pram1: updated/failed pram2: update/failed Thanks, Chad

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  • Modify cmd.exe properties using the command prompt

    - by CodexArcanum
    Isn't that nicely recursive? I've got a portable command prompt on my external drive, and it has a nice .bat file to configure some initial settings, but I'd like more! Here's what I know how to set from .bat: Colors = (color XY) where x and y are hex digits for the predefined colors Prompt = (prompt $p$g) sets the prompt to "C:\etc\etc " the default prompt Title = (title "text") sets the window title to "text" Screen Size = (mode con: cols=XX lines=YY) sets the columns and lines size of the window Path = (SET PATH=%~d0\bin;%PATH%) sets up local path to my tools and appends the computer's path So that's all great. But there are a few settings I can't seem to set from the bat. Like, how would I set these up wihtout using the Properties dialogue: Buffer = not screen size, but the buffer Options like quick edit mode and autocomplete Popup colors Font. And can you use a font on the portable drive, or must it be installed to work? Command history options

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  • Advanced command line argument parsing in Java?

    - by Bishop87
    Does anyone have any java examples for parsing a series of command line arguements in a robust way? I'm looking to be able to handle something like: java myapp [-l language] [-d int] [-f file1 file2 file3] I want to do this in a robust way so I can provide logical error messages to the user if they mistake a command line-option. Some of these options I'd like to make optional, etc, etc. Also, the -f file list should be able to handle a list of files. Is there some library out there to assist me in handling this?

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  • Using 'Copy as cURL' from Chrome in windows command line

    - by user2029890
    So, Google Chrome as this great 'copy as cURL' option under 'Network' of the Chrome DevTools. Works great in command lines for linux but not in windows. Apparently it has something to do with the single quotes as the error I get is protocol 'http not supported In other words its reading that single quote. Is there a simple way to make this formatable for windows? I tried replacing all the single quotes with double quotes but then nothing happens at all. The command is: curl 'http://www.test.com/login/' -H 'Cookie: PHPSESSID=7dvb25maaaaaa9d7bbbbbc3f6' -H 'Origin: http://www.test.com' -H 'Accept-Encoding: gzip,deflate,sdch' -H 'Host: www.test.com' -H 'Accept-Language: en-US,en;q=0.8' -H 'User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/28.0.1500.95 Safari/537.36' -H 'Content-Type: application/x-www-form-urlencoded' -H 'Accept: text/html,application/xhtml+xml,application/xml;q=0.9,/;q=0.8' -H 'Cache-Control: max-age=0' -H 'Referer: http://www.test.com/login/' -H 'Connection: keep-alive' --data 'loc=&login=user%40test.com&password=password&submit1=Sign+In' --compressed Thank you

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  • Haskell: reading multiple command line arguments

    - by Survot
    Hi all, Okay, so I am making a program in Haskell that needs to change certain words based on two command line arguments. I have made the replace function and everything works great, but I am stumped getting it to work with command line arguments. Here is the main code: (replace function not included) main = do text <- getContents (command1:command2:_) <- getArgs putStrLn (replace (read command1) (read command2) text) So for intstance in the terminal I want to be able to type something like: "--- cat textfile.txt | ./replace oldword newword" I know this code is close since I have seen others do it this way. O_o Thanks for any help

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  • How can I pass more than one command line argument via c#

    - by user293392
    I need to pass more than one command line argument via c# for a process called handle.exe: http://www.google.com.mt/search?sourceid=chrome&ie=UTF-8&q=handle.exe First, I need to run the executable file via ADMINISTRATOR permissions. This post has helped me achieve just that: http://stackoverflow.com/questions/667381/programatically-run-cmd-exe-as-adminstrator-in-vista-c But then comes the next problem of calling the actual line arguments such as "-p explore" How can I specify the command line arguments together, or maybe consecutively? Current code is as follows: Process p = new Process(); ProcessStartInfo processStartInfo = new ProcessStartInfo("filePath"); processStartInfo.CreateNoWindow = true; processStartInfo.UseShellExecute = false; processStartInfo.RedirectStandardOutput = true; processStartInfo.RedirectStandardInput = true; processStartInfo.Verb = "runas"; processStartInfo.Arguments = "/env /user:" + "Administrator" + " cmd"; p.StartInfo = processStartInfo; p.Start(); string output = p.StandardOutput.ReadToEnd(); p.WaitForExit(); Console.WriteLine(output); Thanks

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