Search Results

Search found 68 results on 3 pages for 'disp'.

Page 3/3 | < Previous Page | 1 2 3 

• GDB breakpoint problems attaching to QEMU

  - by Rickard von Essen

  Hi, I have the following problem. When I connect gdb to qemu for debugging it won't break on breakpoints. I can set breakpoints, break with ctrl-c etc. Any clues how this can be fixed? I have: $ qemu --version QEMU PC emulator version 0.11.0 (qemu-kvm-0.11.0), Copyright (c) 2003-2008 Fabrice Bellard $ gdb --version GNU gdb (GDB) 7.0-ubuntu. This GDB was configured as "x86_64-linux-gnu". This is an example session: (And yes this is pintos) gdb -x src/misc/gdb-macros kernel.o GNU gdb (GDB) 7.0-ubuntu Copyright (snip...) License (snip...) This GDB was configured as "x86_64-linux-gnu". Reading symbols from ../../threads/build/kernel.o...done. (gdb) debugpintos 0x0000fff0 in ?? () (gdb) break main Breakpoint 1 at 0xc01000b6: file ../../threads/init.c, line 68. (gdb) info break Num Type Disp Enb Address What 1 breakpoint keep y 0xc01000b6 in main at ../../threads/init.c:68 (gdb) cont Continuing. Remote connection closed Any ideas are welcome.

  Read the article

• Cisco ASA5505 won't sync with NTP

  - by Martijn Heemels

  Today I noticed that the clock my Cisco ASA 5505 firewall was running about 15 minutes late, which surprised me since I've set up the NTP client. My two NTP servers 10.10.0.1 and 10.10.0.2 are virtualized Windows Server 2008 R2 domain controllers, and both have the correct time. As shown below, the ASA knows about the two servers, can ping them and seems to poll them periodically, so I suppose it can reach them both. The ASA claims its time source is NTP, however the clock is unsynchronized. Neither host is marked as synced. Result of the command: "ping 10.10.0.1" Type escape sequence to abort. Sending 5, 100-byte ICMP Echos to 10.10.0.1, timeout is 2 seconds: !!!!! Success rate is 100 percent (5/5), round-trip min/avg/max = 1/1/1 ms Result of the command: "sh ntp ass" address ref clock st when poll reach delay offset disp ~10.10.0.1 .LOCL. 1 78 1024 377 0.5 643.69 17.0 ~10.10.0.2 10.10.0.1 2 190 1024 377 0.9 655.91 58.4 * master (synced), # master (unsynced), + selected, - candidate, ~ configured Result of the command: "sh ntp stat" Clock is unsynchronized, stratum 16, no reference clock nominal freq is 99.9984 Hz, actual freq is 99.9984 Hz, precision is 2**6 reference time is 00000000.00000000 (07:28:16.000 CEST Thu Feb 7 2036) clock offset is 0.0000 msec, root delay is 0.00 msec root dispersion is 0.00 msec, peer dispersion is 0.00 msec Result of the command: "sh clock detail" 10:33:23.769 CEDT Tue Jun 26 2012 Time source is NTP UTC time is: 08:33:23 UTC Tue Jun 26 2012 Summer time starts 02:00:00 CEST Sun Mar 25 2012 Summer time ends 03:00:00 CEDT Sun Oct 28 2012 I've tried the basic steps of manually setting the time and removing and adding the timeservers, to no avail. My ASA's ntp config is simply: ntp server 10.10.0.1 ntp server 10.10.0.2 Do I need to enable authentication to use a Windows NTP server? Any thoughts?

  Read the article

• VNC server failed to start CentOS

  - by Shaun

  I followed a tutorial on how to install and get VNCserver to run on CentOS 6 (since freenx isnt supported yet) and I keep getting Starting VNC server: 1:user [FAILED] How do I figure out whats going on here? Im new to Linux/CentOS and im trying to get RDP going so I can step away from SSH as much as possible (you know us Windows users love our pretty GUI's). So, where is the error log at and how do I find it? Or maybe someone else has experienced this and knows the solution based on the simple error given? After running in debug mode, here is my error + . /etc/init.d/functions ++ TEXTDOMAIN=initscripts ++ umask 022 ++ PATH=/sbin:/usr/sbin:/bin:/usr/bin ++ export PATH ++ '[' -z '' ']' ++ COLUMNS=80 ++ '[' -z '' ']' +++ /sbin/consoletype ++ CONSOLETYPE=pty ++ '[' -f /etc/sysconfig/i18n -a -z '' -a -z '' ']' ++ . /etc/profile.d/lang.sh ++ unset LANGSH_SOURCED ++ '[' -z '' ']' ++ '[' -f /etc/sysconfig/init ']' ++ . /etc/sysconfig/init +++ BOOTUP=color +++ RES_COL=60 +++ MOVE_TO_COL='echo -en \033[60G' +++ SETCOLOR_SUCCESS='echo -en \033[0;32m' +++ SETCOLOR_FAILURE='echo -en \033[0;31m' +++ SETCOLOR_WARNING='echo -en \033[0;33m' +++ SETCOLOR_NORMAL='echo -en \033[0;39m' +++ PROMPT=yes +++ AUTOSWAP=no +++ ACTIVE_CONSOLES='/dev/tty[1-6]' +++ SINGLE=/sbin/sushell ++ '[' pty = serial ']' ++ __sed_discard_ignored_files='/\(~\|\.bak\|\.orig\|\.rpmnew\|\.rpmorig\|\.rpmsave\)$/d' + '[' -r /etc/sysconfig/vncservers ']' + . /etc/sysconfig/vncservers ++ VNCSERVERS='1:larry 2:moe 3:curly' ++ VNCSERVERARGS[1]='-geometry 800x600' ++ VNCSERVERARGS[2]='-geometry 640x480' ++ VNCSERVERARGS[3]='-geometry 640x480' + prog='VNC server' + RETVAL=0 + case "$1" in + start + '[' 0 '!=' 0 ']' + . /etc/sysconfig/network ++ NETWORKING=yes ++ HOSTNAME=vps.binaryvisionaries.com ++ DOMAINNAME=server.name ++ GATEWAYDEV=venet0 ++ NETWORKING_IPV6=yes ++ IPV6_DEFAULTDEV=venet0 + '[' yes = no ']' + '[' -x /usr/bin/vncserver ']' + '[' -x /usr/bin/Xvnc ']' + echo -n 'Starting VNC server: ' Starting VNC server: + RETVAL=0 + '[' '!' -d /tmp/.X11-unix ']' + for display in '${VNCSERVERS}' + SERVS=1 + echo -n '1:larry ' 1:larry + DISP=1 + USER=larry + VNCUSERARGS='-geometry 800x600' + runuser -l larry -c 'cd ~larry && [ -r .vnc/passwd ] && vncserver :1 -geometry 800x600' + RETVAL=1 + '[' 1 -eq 0 ']' + break + '[' -z 1 ']' + '[' 1 -eq 0 ']' + failure 'vncserver start' + local rc=1 + '[' color '!=' verbose -a -z '' ']' + echo_failure + '[' color = color ']' + echo -en '\033[60G' + echo -n '[' [+ '[' color = color ']' + echo -en '\033[0;31m' + echo -n FAILED FAILED+ '[' color = color ']' + echo -en '\033[0;39m' + echo -n ']' ]+ echo -ne '\r' + return 1 + '[' -x /usr/bin/plymouth ']' + /usr/bin/plymouth --details + return 1 + echo + '[' 1 -eq 98 ']' + return 1 + exit 1

  Read the article

• Return call from ggplot object

  - by aL3xa

  I've been using ggplot2 for a while now, and I can't find a way to get formula from ggplot object. Though I can get basic info with summary(<ggplot_object>), in order to get complete formula, usually I was combing up and down through .Rhistory file. And this becomes frustrating when you experiment with new graphs, especially when code gets a bit lengthy... so searching through history file isn't quite convenient way of doing this... Is there a more efficient way of doing this? Just an illustration: p <- qplot(data = mtcars, x = factor(cyl), geom = "bar", fill = factor(cyl)) + scale_fill_manual(name = "Cylinders", value = c("firebrick3", "gold2", "chartreuse3")) + stat_bin(aes(label = ..count..), vjust = -0.2, geom = "text", position = "identity") + xlab("# of cylinders") + ylab("Frequency") + opts(title = "Barplot: # of cylinders") I can get some basic info with summary: > summary(p) data: mpg, cyl, disp, hp, drat, wt, qsec, vs, am, gear, carb [32x11] mapping: fill = factor(cyl), x = factor(cyl) scales: fill faceting: facet_grid(. ~ ., FALSE) ----------------------------------- geom_bar: stat_bin: position_stack: (width = NULL, height = NULL) mapping: label = ..count.. geom_text: vjust = -0.2 stat_bin: width = 0.9, drop = TRUE, right = TRUE position_identity: (width = NULL, height = NULL) But I want to get code I typed in to get the graph. I reckon that I'm missing something essential here... it's seems impossible that there's no way to get call from ggplot object!

  Read the article

• function taking in an input image and different kernel size

  - by drifterOcean19

  I have this filtering function that takes an input image, performs convolution using a given kernel, and returns the resulting image. However, I can't seem to work it out how to make it takes different kernel sizes.For example instead of pre-defined 3x3 kernel as below in the code, it could instead take 5x5 or 7x7. and then the user could input the type of kernel/filter they want(Depending on the intended effect). I can't seem to put my head around it. i'm quite new to matlab. function [newImg] = kernelFunc(imgB) img=imread(imgB); figure,imshow(img); img2=zeros(size(img)+2); newImg=zeros(size(img)); for rgb=1:3 for x=1:size(img,1) for y=1:size(img,2) img2(x+1,y+1,rgb)=img(x,y,rgb); end end end for rgb=1:3 for i= 1:size(img2,1)-2 for j=1:size(img2,2)-2 window=zeros(9,1); inc=1; for x=1:3 for y=1:3 window(inc)=img2(i+x-1,j+y-1,rgb); inc=inc+1; end end kernel=[1;2;1;2;4;2;1;2;1]/16; med=window.*kernel; disp(med); med=sum(med); med=floor(med); newImg(i,j,rgb)=med; end end end newImg=uint8(newImg); figure,imshow(newImg); end

  Read the article

• Unpacking varargin to individual variables

  - by Richie Cotton

  I'm writing a wrapper to a function that takes varargin as its inputs. I want to preserve the function signature in the wrapper, but nesting varargin causes all the variable to be lumped together. function inner(varargin) %#ok<VANUS> % An existing function disp(nargin) end function outer(varargin) % My wrapper inner(varargin); end outer('foo', 1:3, {}) % Uh-oh, this is 1 I need a way to unpack varargin in the outer function, so that I have a list of individual variables. There is a really nasty way to do this by constructing a string of the names of the variables to pass the inner, and calling eval. function outer2(varargin) %#ok<VANUS> % My wrapper, second attempt inputstr = ''; for i = 1:nargin inputstr = [inputstr 'varargin{' num2str(i) '}']; %#ok<AGROW> if i < nargin inputstr = [inputstr ', ']; %#ok<AGROW> end end eval(['inner(' inputstr ')']); end outer2('foo', 1:3, {}) % 3, as it should be Can anyone think of a less hideous way of doing things, please?

  Read the article

• MATLAB: svds() not converging

  - by Paul

  So using MATLAB's svds() function on some input data as such: [U, S, V, flag] = svds(data, nSVDs, 'L') I noticed that from run to run with the same data, I'd get drastically different output SVD sizes from run to run. When I checked whether 'flag' was set, I found that it was, indicating that the SVDs had not converged. My normal system here would be that if it really needs to converge, I'd do something like this: flag = 1 svdOpts = struct('tol', 1e-10, 'maxit', 600, 'disp', 0); while flag: if svdOpts.maxit > 1e6 error('There''s a real problem here.') end [U, S, V, flag] = svds(data, nSVDs, 'L', svdOpts) svdOpts.maxit = svdOpts.maxit*2 end But from what I can tell, when you use 'L' as the third argument, the fourth argument is ignored, meaning I just have to deal with the fact that it's not converging? I'm not even really sure how to use the 'sigma' argument in place of the 'L' argument. I've also tried reducing the number of SVDs calculated to no avail. Any help on this matter would be much appreciated. EDIT While following up on the comments below, I found that the problem had to do with the way I was building my data matrices. Turned out I had accidentally inverted a matrix and had an input of size (4000x1) rather than (20x200), which was what was refusing to converge. I also did some more timing tets and found that the fourth argument was not, in fact, being ignored, so that's on me. Thanks for the help guys.

  Read the article

• Better code for accessing fields in a matlab structure array?

  - by John

  I have a matlab structure array Modles1 of size (1x180) that has fields a, b, c, ..., z. I want to understand how many distinct values there are in each of the fields. i.e. max(grp2idx([foo(:).a])) The above works if the field a is a double. {foo(:).a} needs to be used in the case where the field a is a string/char. Here's my current code for doing this. I hate having to use the eval, and what is essentially a switch statement. Is there a better way? names = fieldnames(Models1); for ix = 1 : numel(names) className = eval(['class(Models1(1).',names{ix},')']); if strcmp('double', className) || strcmp('logical',className) eval([' values = [Models1(:).',names{ix},'];']); elseif strcmp('char', className) eval([' values = {Models1(:).',names{ix},'};']); else disp(['Unrecognized class: ', className]); end % this line requires the statistics toolbox. [g, gn, gl] = grp2idx(values); fprintf('%30s : %4d\n',names{ix},max(g)); end

  Read the article

• Email postfix marked as spam by google

  - by Rodrigo Ferrari

  Hello friends, I searched about this question, found some few answers but no idea how to fix, the problem is that I realy dumb with all this! I configured the postfix and done everything how the install how to told. It send the email, but get marked as spam! The header is this one: Delivered-To: [email protected] Received: by 10.223.86.203 with SMTP id t11cs837410fal; Wed, 12 Jan 2011 04:02:21 -0800 (PST) X-pstn-nxpr: disp=neutral, [email protected] X-pstn-nxp: bodyHash=9c6d0c64fa3a4d663c9968e9545c47d77ae0242e, headerHash=1ab8726bd17a23218309165bd20fe6e0911627cd, keyName=4, rcptHash=178929be6ed8451d98a4df01a463784e6c59b3b4, sourceip=174.121.4.154, version=1 Received: by 10.100.190.13 with SMTP id n13mr537609anf.76.1294833740396; Wed, 12 Jan 2011 04:02:20 -0800 (PST) Return-Path: <[email protected]> Received: from psmtp.com ([74.125.245.168]) by mx.google.com with SMTP id w2si1297960anw.132.2011.01.12.04.02.19; Wed, 12 Jan 2011 04:02:20 -0800 (PST) Received-SPF: pass (google.com: domain of [email protected] designates 174.121.4.154 as permitted sender) client-ip=174.121.4.154; Authentication-Results: mx.google.com; spf=pass (google.com: domain of [email protected] designates 174.121.4.154 as permitted sender) [email protected] Received: from source ([174.121.4.154]) by na3sys010amx168.postini.com ([74.125.244.10]) with SMTP; Wed, 12 Jan 2011 12:02:19 GMT Received: from localhost (server [127.0.0.1]) (using TLSv1 with cipher DHE-RSA-AES256-SHA (256/256 bits)) (No client certificate requested) by brasilyacht.com.br (Postfix) with ESMTP id 87C121290142; Wed, 12 Jan 2011 09:50:29 -0200 (BRST) From: YachtBrasil <[email protected]> Reply-To: Vendas <[email protected]> Cc: YachtBrasil <[email protected]> To: [email protected] Subject: teste Date: Wed, 12 Jan 2011 09:50:29 -0200 Content-Type: text/html; charset=UTF-8 Content-Transfer-Encoding: quoted-printable Content-Disposition: inline MIME-Version: 1.0 Message-Id: <[email protected]> X-pstn-2strike: clear X-pstn-neptune: 0/0/0.00/0 X-pstn-levels: (S: 1.96218/99.81787 CV:99.9000 FC:95.5390 LC:95.5390 R:95.9108 P:95.9108 M:97.0282 C:98.6951 ) X-pstn-settings: 3 (1.0000:1.0000) s cv gt3 gt2 gt1 r p m c X-pstn-addresses: from <[email protected]> [db-null] I'm out of ideas on how to fix this, I think it's dns issue, but I have marked the spf inside my tinydns =( Is there anything I can check to know why this email is marked as spam? Any help will be appreciated! Thanks and sorry for my bad english.

  Read the article

• ntpdate works, but ntpd can't synchronize

  - by dafydd

  This is in RHEL 5.5. First, ntpdate to the remote host works: $ ntpdate XXX.YYY.4.21 24 Oct 16:01:17 ntpdate[5276]: adjust time server XXX.YYY.4.21 offset 0.027291 sec Second, here are the server lines in my /etc/ntp.conf. All restrict lines have been commented out for troubleshooting. server 127.127.1.0 server XXX.YYY.4.21 I execute service ntpd start and check with ntpq: $ ntpq ntpq> peer remote refid st t when poll reach delay offset jitter ============================================================================== *LOCAL(0) .LOCL. 5 l 36 64 377 0.000 0.000 0.001 timeserver.doma .LOCL. 1 u 39 128 377 0.489 51.261 58.975 ntpq> opeer remote local st t when poll reach delay offset disp ============================================================================== *LOCAL(0) 127.0.0.1 5 l 40 64 377 0.000 0.000 0.001 timeserver.doma XXX.YYY.22.169 1 u 43 128 377 0.489 51.261 58.975 XXX.YYY.22.169 is the address of the host I'm working on. A reverse lookup on the IP address in my ntp.conf file validates that the ntpq output is correctly naming the remote server. However, as you can see, it appears to just roll over to my .LOCL. time server. Also, ntptrace just returns the local time server, and ntptrace XXX.YYY.4.21 times out. $ ntptrace localhost.localdomain: stratum 6, offset 0.000000, synch distance 0.948181 $ ntptrace XXX.YYY.4.21 XXX.YYY.4.21: timed out, nothing received ***Request timed out This looks like my ntp daemon is just querying itself. I am thinking about the possibility that the router-I-don't-control between my test network timeserver and the corporate network timeserver is blocking on source port. (I think ntpdate sends on port 123, which gets it around that filter and is why I can't use it while ntpd is running.) I have email in to the network folks to check that. Finally, telnet XXX.YYY.4.21 123 never times out or completes a connection. The questions: What am I missing, here? What else can I check to try to figure out where this connection is failing? Would strace ntptrace XXX.YYY.4.21 show me the source port ntptrace is sending from? I can deconstruct most strace calls, but I can't figure out the location of that datum. If I can't directly examine the gateway router between my test network and the timeserver, how might I build evidence that it's responsible for these disconnections? Alternately, how might I rule it out?

  Read the article

• Solaris ????????????????

  - by Homma

  ???? ???????????? CPU ?????????????????????????????????? OS ??????????????????????????????????????????????CPU ??????????????????? CPU ???????????????????????????????????????????????????????????????????????????? CPU ??????????????????????????????????? CPU ???????????????????????? CPU ????????????????????????? CPU ?????????????????????????????????????????????????????????????????????????????DTrace ????????????????? ?? ????????????????????????????????????????????? CPU ????????????????? # cat prog01.c int main() { while(1) {}; } # gcc prog01.c -o prog01 ?????????????????????pbind ?????????? CPU 1 ??????psradm ????????? CPU 1 ?????????????????????????? CPU 1 ?????????????? # ./prog01 & [1] 3247 # pbind -b 1 3247 process id 3247: was not bound, now 1 # psradm -i 1 # psrinfo 1 1 no-intr since 09/24/2012 05:46:25 ????????? Solaris 10 8/11 ????????? # cat /etc/release Oracle Solaris 10 8/11 s10x_u10wos_17b X86 Copyright (c) 1983, 2011, Oracle and/or its affiliates. All rights reserved. Assembled 23 August 2011 ????????????????????????? DTrace ??????????????(??????)???????????????????????????? preempt ??????????????????? DTrace ????????????????????????????????????????????????????????????????????????????? # dtrace -qn 'BEGIN{ ts = timestamp; } sched:::preempt/pid == $target/ { printf("%d\n",timestamp - ts); ts = timestamp }' -p 3247 ?????????????????????? 200 ????????????????????? # dtrace -qn 'BEGIN{ ts = timestamp; } sched:::preempt/pid == $target/ { printf("%d\n",timestamp - ts); ts = timestamp }' -p 3247 3547836 199976558 200030610 199964001 200001048 199999666 200021432 ???????????? 200 ????? CPU ????????????? CPU ????????????????????? ??????? CPU 1 ????????????? prog01 ?????????????????????????????????? prog01 ?????????????????????????????????????????????????????????? 200 ??????????????? ????????????????????????? ?????????????????????????????? DTrace ????????DTrace ???????????????????????????????????????????????????????????????????? # dtrace -qn 'sched:::preempt/pid == $target/ { printf("%d\n", ((tsproc_t*)curthread->t_cldata)->ts_timeleft); }' -p 3247 ??????????????????????????????? 1/100 ???????? 200 ????????????????? # dtrace -qn 'sched:::preempt/pid == $target/ { printf("%d\n", ((tsproc_t*)curthread->t_cldata)->ts_timeleft); }' -p 3247 20 20 20 20 20 20 ????????? 200 ???????????????????? ???????? 200 ??????????????????????????????????????????????????????????????????????????????? DTrace ???????DTrace ??????????????? # dtrace -qn 'sched:::preempt/pid == $target/ { printf("%d\n", ((tsproc_t*)curthread->t_cldata)->ts_cpupri); }' -p 3247 ???????????????????????????? # dtrace -qn 'sched:::preempt/pid == $target/ { printf("%d\n", ((tsproc_t*)curthread->t_cldata)->ts_cpupri); }' -p 3247 0 0 0 0 0 0 ????????????????? 0 ???????? 0 ?????????????????????? dispadmin ???????????????? # dispadmin -c TS -g | head # Time Sharing Dispatcher Configuration RES=1000 # ts_quantum ts_tqexp ts_slpret ts_maxwait ts_lwait PRIORITY LEVEL 200 0 50 0 50 # 0 200 0 50 0 50 # 1 200 0 50 0 50 # 2 200 0 50 0 50 # 3 200 0 50 0 50 # 4 200 0 50 0 50 # 5 ???????PRIORITY LEVEL 0 ???????? ts_quantum ? 200 ??????????? 0 ???? 200 ???????????????????????????(RES ??? 1000 ????ts_quantum ???? 1/1000 ?)? ????????? ????????????????????? mpstat ????????????????????????????icsw ??? 5 ???????????200 ?????????????????????????????????????????????????????? CPU ??? 200 ????????????? # mpstat 1 | egrep '^ 1|csw' CPU minf mjf xcal intr ithr csw icsw migr smtx srw syscl usr sys wt idl 1 0 0 347 196 1 42 1 3 0 0 2 9 1 0 90 CPU minf mjf xcal intr ithr csw icsw migr smtx srw syscl usr sys wt idl 1 0 0 0 16 0 0 5 0 0 0 0 100 0 0 0 CPU minf mjf xcal intr ithr csw icsw migr smtx srw syscl usr sys wt idl 1 0 0 0 7 0 0 5 0 0 0 0 100 0 0 0 CPU minf mjf xcal intr ithr csw icsw migr smtx srw syscl usr sys wt idl 1 0 0 0 8 0 0 5 0 0 0 0 100 0 0 0 CPU minf mjf xcal intr ithr csw icsw migr smtx srw syscl usr sys wt idl 1 0 0 0 18 1 0 5 0 0 0 0 100 0 0 0 ???????????? Solaris ????????????????????????????????????????????? priocntl ???????????????? 1 ?????????? # priocntl -s -c FX -t 1000 -i pid `pgrep prog01` ??????? mpstat ?????????CPU ??????? 1 ?????????????????????????????????????????????????????????????????????????????????????????????????????????????? # mpstat 1 | egrep '^ 1|csw' CPU minf mjf xcal intr ithr csw icsw migr smtx srw syscl usr sys wt idl 1 0 0 346 196 1 42 1 3 0 0 2 9 1 0 90 CPU minf mjf xcal intr ithr csw icsw migr smtx srw syscl usr sys wt idl 1 0 0 0 2 0 0 1 0 0 0 0 100 0 0 0 CPU minf mjf xcal intr ithr csw icsw migr smtx srw syscl usr sys wt idl 1 0 0 0 2 0 0 1 0 0 0 0 100 0 0 0 CPU minf mjf xcal intr ithr csw icsw migr smtx srw syscl usr sys wt idl 1 0 0 0 13 0 0 2 0 0 0 0 100 0 0 0 CPU minf mjf xcal intr ithr csw icsw migr smtx srw syscl usr sys wt idl 1 0 0 0 2 0 0 1 0 0 0 0 100 0 0 0 CPU minf mjf xcal intr ithr csw icsw migr smtx srw syscl usr sys wt idl 1 0 0 0 5 1 0 1 0 0 0 0 100 0 0 0 ????DTrace ????????????????????????????? # dtrace -qn 'sched:::preempt/pid == $target/ { printf("%d\n", ((fxproc_t*)curthread->t_cldata)->fx_timeleft); }' -p `pgrep prog01` 100 100 100 100 100 100 ??? Solaris ???????????????????????????????????????????????????????????????? 200 ???????????????????????????????????????????????? ??????????????????????????????????????????????????????????????? CPU ?????????I/O ?????????????????????????????????????????????????????????? ?????????????????????????? http://src.opensolaris.org/source/xref/onnv/onnv-gate/usr/src/uts/common/disp/ ????????? ???????????????????

  Read the article

• MATLAB image corner coordinates & referncing to cell arrays

  - by James

  Hi, I am having some problems comparing the elements in different cell arrays. The context of this problem is that I am using the bwboundaries function in MATLAB to trace the outline of an image. The image is of a structural cross section and I am trying to find if there is continuity throughout the section (i.e. there is only one outline produced by the bwboundaries command). Having done this and found where the is more than one section traced (i.e. it is not continuous), I have used the cornermetric command to find the corners of each section. The code I have is: %% Define the structural section as a binary matrix (Image is an I-section with the web broken) bw(20:40,50:150) = 1; bw(160:180,50:150) = 1; bw(20:60,95:105) = 1; bw(140:180,95:105) = 1; Trace = bw; [B] = bwboundaries(Trace,'noholes'); %Traces the outer boundary of each section L = length(B); % Finds number of boundaries if L > 1 disp('Multiple boundaries') % States whether more than one boundary found end %% Obtain perimeter coordinates for k=1:length(B) %For all the boundaries perim = B{k}; %Obtains perimeter coordinates (as a 2D matrix) from the cell array end %% Find the corner positions C = cornermetric(bw); Areacorners = find(C == max(max(C))) % Finds the corner coordinates of each boundary [rowindexcorners,colindexcorners] = ind2sub(size(Newgeometry),Areacorners) % Convert corner coordinate indexes into subcripts, to give x & y coordinates (i.e. the same format as B gives) %% Put these corner coordinates into a cell array Cornerscellarray = cell(length(rowindexcorners),1); % Initialises cell array of zeros for i =1:numel(rowindexcorners) Cornerscellarray(i) = {[rowindexcorners(i) colindexcorners(i)]}; %Assigns the corner indicies into the cell array %This is done so the cell arrays can be compared end for k=1:length(B) %For all the boundaries found perim = B{k}; %Obtains coordinates for each perimeter Z = perim; % Initialise the matrix containing the perimeter corners Sectioncellmatrix = cell(length(rowindexcorners),1); for i =1:length(perim) Sectioncellmatrix(i) = {[perim(i,1) perim(i,2)]}; end for i = 1:length(perim) if Sectioncellmatrix(i) ~= Cornerscellarray Sectioncellmatrix(i) = []; %Gets rid of the elements that are not corners, but keeps them associated with the relevent section end end end This creates an error in the last for loop. Is there a way I can check whether each cell of the array (containing an x and y coordinate) is equal to any pair of coordinates in cornercellarray? I know it is possible with matrices to compare whether a certain element matches any of the elements in another matrix. I want to be able to do the same here, but for the pair of coordinates within the cell array. The reason I don't just use the cornercellarray cell array itself, is because this lists all the corner coordinates and does not associate them with a specific traced boundary.

  Read the article

• Route Angular to New Controller after Login

  - by MizAkita

  I'm kind of stuck on how to route my angular app to a new controller after login. I have a simple app, that uses 'loginservice'... after logging in, it then routes to /home which has a different template from the index.html(login page). I want to use /home as the route that displays the partial views of my flightforms controllers. What is the best way to configure my routes so that after login, /home is the default and the routes are called into that particular templates view. Seems easy but I keep getting the /login page when i click on a link which is suppose to pass the partial view into the default.html template: var app= angular.module('myApp', ['ngRoute']); app.config(['$routeProvider', function($routeProvider) { $routeProvider.when('/login', { templateUrl: 'partials/login.html', controller: 'loginCtrl' }); $routeProvider.when('/home', { templateUrl: 'partials/default.html', controller: 'defaultCtrl' }); }]); flightforms.config(['$routeProvider', function($routeProvider){ //sub pages $routeProvider.when('/home', { templateUrl: 'partials/default.html', controller: 'defaultCtrl' }); $routeProvider.when('/status', { templateUrl: 'partials/subpages/home.html', controller: 'statusCtrl' }); $routeProvider.when('/observer-ao', { templateUrl: 'partials/subpages/aobsrv.html', controller: 'obsvaoCtrl' }); $routeProvider.when('/dispatch', { templateUrl: 'partials/subpages/disp.html', controller: 'dispatchCtrl' }); $routeProvider.when('/fieldmgr', { templateUrl: 'partials/subpages/fieldopmgr.html', controller: 'fieldmgrCtrl' }); $routeProvider.when('/obs-backoffice', { templateUrl: 'partials/subpages/obsbkoff.html', controller: 'obsbkoffCtrl' }); $routeProvider.when('/add-user', { templateUrl: 'partials/subpages/users.html', controller: 'userCtrl' }); $routeProvider.otherwise({ redirectTo: '/status' }); }]); app.run(function($rootScope, $location, loginService) { var routespermission=['/home']; //route that require login $rootScope.$on('$routeChangeStart', function(){ if( routespermission.indexOf($location.path()) !=-1) { var connected=loginService.islogged(); connected.then(function(msg) { if(!msg.data) $location.path('/login'); }); } }); }); and my controllers are simple. Here's a sample of what they look like: var flightformsControllers = angular.module('flightformsController', []); flightforms.controller('fieldmgrCtrl', ['$scope','$http','loginService', function($scope,loginService) { $scope.txt='You are logged in'; $scope.logout=function(){ loginService.logout(); } }]); Any ideas on how to get my partials to display in the /home default.html template would be appreciated.

  Read the article

• x11vnc working in Ubuntu 10.10

  - by pablorc

  I'm trying to start x11vnc in a Ubuntu 10.10 (my server is in Amazon EC2), but I have the next error $ sudo x11vnc -forever -usepw -httpdir /usr/share/vnc-java/ -httpport 5900 -auth /usr/sbin/gdm 25/11/2010 13:29:51 passing arg to libvncserver: -httpport 25/11/2010 13:29:51 passing arg to libvncserver: 5900 25/11/2010 13:29:51 -usepw: found /home/ubuntu/.vnc/passwd 25/11/2010 13:29:51 x11vnc version: 0.9.10 lastmod: 2010-04-28 pid: 3504 25/11/2010 13:29:51 XOpenDisplay(":0.0") failed. 25/11/2010 13:29:51 Trying again with XAUTHLOCALHOSTNAME=localhost ... 25/11/2010 13:29:51 *************************************** 25/11/2010 13:29:51 *** XOpenDisplay failed (:0.0) *** x11vnc was unable to open the X DISPLAY: ":0.0", it cannot continue. *** There may be "Xlib:" error messages above with details about the failure. Some tips and guidelines: ** An X server (the one you wish to view) must be running before x11vnc is started: x11vnc does not start the X server. (however, see the -create option if that is what you really want). ** You must use -display <disp>, -OR- set and export your $DISPLAY environment variable to refer to the display of the desired X server. - Usually the display is simply ":0" (in fact x11vnc uses this if you forget to specify it), but in some multi-user situations it could be ":1", ":2", or even ":137". Ask your administrator or a guru if you are having difficulty determining what your X DISPLAY is. ** Next, you need to have sufficient permissions (Xauthority) to connect to the X DISPLAY. Here are some Tips: - Often, you just need to run x11vnc as the user logged into the X session. So make sure to be that user when you type x11vnc. - Being root is usually not enough because the incorrect MIT-MAGIC-COOKIE file may be accessed. The cookie file contains the secret key that allows x11vnc to connect to the desired X DISPLAY. - You can explicitly indicate which MIT-MAGIC-COOKIE file should be used by the -auth option, e.g.: x11vnc -auth /home/someuser/.Xauthority -display :0 x11vnc -auth /tmp/.gdmzndVlR -display :0 you must have read permission for the auth file. See also '-auth guess' and '-findauth' discussed below. ** If NO ONE is logged into an X session yet, but there is a greeter login program like "gdm", "kdm", "xdm", or "dtlogin" running, you will need to find and use the raw display manager MIT-MAGIC-COOKIE file. Some examples for various display managers: gdm: -auth /var/gdm/:0.Xauth -auth /var/lib/gdm/:0.Xauth kdm: -auth /var/lib/kdm/A:0-crWk72 -auth /var/run/xauth/A:0-crWk72 xdm: -auth /var/lib/xdm/authdir/authfiles/A:0-XQvaJk dtlogin: -auth /var/dt/A:0-UgaaXa Sometimes the command "ps wwwwaux | grep auth" can reveal the file location. Starting with x11vnc 0.9.9 you can have it try to guess by using: -auth guess (see also the x11vnc -findauth option.) Only root will have read permission for the file, and so x11vnc must be run as root (or copy it). The random characters in the filenames will of course change and the directory the cookie file resides in is system dependent. See also: http://www.karlrunge.com/x11vnc/faq.html I've already tried with some -auth options but the error persist. I have gdm running. Thank you in advance

  Read the article

• Finding the groups of a user in WLS with OPSS

  - by user12587121

  How to find the group memberships for a user from a web application running in Weblogic server ?  This is useful for building up the profile of the user for security purposes for example. WLS as a container offers an identity store service which applications can access to query and manage identities known to the container.  This article for example shows how to recover the groups of the current user, but how can we find the same information for an arbitrary user ? It is the Oracle Platform for Securtiy Services (OPSS) that looks after the identity store in WLS and so it is in the OPSS APIs that we can find the way to recover this information. This is explained in the following documents.  Starting from the FMW 11.1.1.5 book list, with the Security Overview document we can see how WLS uses OPSS: Proceeding to the more detailed Application Security document, we find this list of useful references for security in FMW. We can follow on into the User/Role API javadoc. The Application Security document explains how to ensure that the identity store is configured appropriately to allow the OPSS APIs to work.  We must verify that the jps-config.xml file where the application  is deployed has it's identity store configured--look for the following elements in that file: <serviceProvider type="IDENTITY_STORE" name="idstore.ldap.provider" class="oracle.security.jps.internal.idstore.ldap.LdapIdentityStoreProvider">             <description>LDAP-based IdentityStore Provider</description>  </serviceProvider> <serviceInstance name="idstore.ldap" provider="idstore.ldap.provider">             <property name="idstore.config.provider" value="oracle.security.jps.wls.internal.idstore.WlsLdapIdStoreConfigProvider"/>             <property name="CONNECTION_POOL_CLASS" value="oracle.security.idm.providers.stdldap.JNDIPool"/></serviceInstance> <serviceInstanceRef ref="idstore.ldap"/> The document contains a code sample for using the identity store here. Once we have the identity store reference we can recover the user's group memberships using the RoleManager interface:             RoleManager roleManager = idStore.getRoleManager();            SearchResponse grantedRoles = null;            try{                System.out.println("Retrieving granted WLS roles for user " + userPrincipal.getName());                grantedRoles = roleManager.getGrantedRoles(userPrincipal, false);                while( grantedRoles.hasNext()){                      Identity id = grantedRoles.next();                      System.out.println("  disp name=" + id.getDisplayName() +                                  " Name=" + id.getName() +                                  " Principal=" + id.getPrincipal() +                                  "Unique Name=" + id.getUniqueName());                     // Here, we must use WLSGroupImpl() to build the Principal otherwise                     // OES does not recognize it.                      retSubject.getPrincipals().add(new WLSGroupImpl(id.getPrincipal().getName()));                 }            }catch(Exception ex) {                System.out.println("Error getting roles for user " + ex.getMessage());                ex.printStackTrace();            }        }catch(Exception ex) {            System.out.println("OESGateway: Got exception instantiating idstore reference");        } This small JDeveloper project has a simple servlet that executes a request for the user weblogic's roles on executing a get on the default URL.  The full code to recover a user's goups is in the getSubjectWithRoles() method in the project.

  Read the article

• jquery ajax and php arrays

  - by sea_1987

  Hi There, I am trying to submit some data to a PHP script, however the PHP scripts expects the data to arrive in a specific format, like this example which is a dump of the post, Array ( [save] => Add to shortlist [cv_file] => Array ( [849709537] => Y [849709616] => Y [849709633] => Y ) ) The process is currently that a user selects the product they want using checkboxes and then clicks a submit button which fires the PHP scripts, The HTML looks like this, div class="row"> <ul> <li class="drag_check ui-draggable"> <input type="checkbox" id="inp_cv_849709537" name="cv_file[849709537]" class="cv_choice" value="Y"> </li> <li class="id"><a href="/search/cv/849709537">849709537</a></li> <div class="disp"> <li class="location">Huddersfield</li> <li class="status"> Not currently working </li> <li class="education">other</li> <li class="role"> Temporary </li> <li class="salary">£100,000 or more</li> <div class="s">&nbsp;</div> </div> </ul> <dl> <dt>Current Role</dt> <dd>Developer </dd> <dt>Sectors</dt><dt> </dt><dd> Energy &amp; Utilities, Healthcare, Hospitality &amp; Travel, Installation &amp; Maintenance, Installation &amp; Maintenance </dd> <dt>About Me</dt><dt> </dt><dd></dd> </dl> <div class="s"></div> </div> I am needing to use AJAX instead now, but I need to send the data to PHP in the format it expects here is what I have so far, $('#addshortlist').click(function() { var datastring = ui.draggable.children().attr('name')+"="+ui.draggable.children().val()+"&save=Add to shortlist"; alert(datastring); $.ajax({ type: 'POST', url: '/search', data:ui.draggable.children().attr('name')+"="+ui.draggable.children().val()+"&save=Add to shortlist", success:function(){ alert("Success"+datastring); }, error:function() { alert("Fail"+datastring); } }); return false; }); I would really appreciate any help

  Read the article

• Running 32 bit assembly code on a 64 bit Linux & 64 bit Processor : Explain the anomaly.

  - by claws

  Hello, I'm in an interesting problem.I forgot I'm using 64bit machine & OS and wrote a 32 bit assembly code. I don't know how to write 64 bit code. This is the x86 32-bit assembly code for Gnu Assembler (AT&T syntax) on Linux. //hello.S #include <asm/unistd.h> #include <syscall.h> #define STDOUT 1 .data hellostr: .ascii "hello wolrd\n"; helloend: .text .globl _start _start: movl $(SYS_write) , %eax //ssize_t write(int fd, const void *buf, size_t count); movl $(STDOUT) , %ebx movl $hellostr , %ecx movl $(helloend-hellostr) , %edx int $0x80 movl $(SYS_exit), %eax //void _exit(int status); xorl %ebx, %ebx int $0x80 ret Now, This code should run fine on a 32bit processor & 32 bit OS right? As we know 64 bit processors are backward compatible with 32 bit processors. So, that also wouldn't be a problem. The problem arises because of differences in system calls & call mechanism in 64-bit OS & 32-bit OS. I don't know why but they changed the system call numbers between 32-bit linux & 64-bit linux. asm/unistd_32.h defines: #define __NR_write 4 #define __NR_exit 1 asm/unistd_64.h defines: #define __NR_write 1 #define __NR_exit 60 Anyway using Macros instead of direct numbers is paid off. Its ensuring correct system call numbers. when I assemble & link & run the program. $cpp hello.S hello.s //pre-processor $as hello.s -o hello.o //assemble $ld hello.o // linker : converting relocatable to executable Its not printing helloworld. In gdb its showing: Program exited with code 01. I don't know how to debug in gdb. using tutorial I tried to debug it and execute instruction by instruction checking registers at each step. its always showing me "program exited with 01". It would be great if some on could show me how to debug this. (gdb) break _start Note: breakpoint -10 also set at pc 0x4000b0. Breakpoint 8 at 0x4000b0 (gdb) start Function "main" not defined. Make breakpoint pending on future shared library load? (y or [n]) y Temporary breakpoint 9 (main) pending. Starting program: /home/claws/helloworld Program exited with code 01. (gdb) info breakpoints Num Type Disp Enb Address What 8 breakpoint keep y 0x00000000004000b0 <_start> 9 breakpoint del y <PENDING> main I tried running strace. This is its output: execve("./helloworld", ["./helloworld"], [/* 39 vars */]) = 0 write(0, NULL, 12 <unfinished ... exit status 1> Explain the parameters of write(0, NULL, 12) system call in the output of strace? What exactly is happening? I want to know the reason why exactly its exiting with exitstatus=1? Can some one please show me how to debug this program using gdb? Why did they change the system call numbers? Kindly change this program appropriately so that it can run correctly on this machine. EDIT: After reading Paul R's answer. I checked my files claws@claws-desktop:~$ file ./hello.o ./hello.o: ELF 64-bit LSB relocatable, x86-64, version 1 (SYSV), not stripped claws@claws-desktop:~$ file ./hello ./hello: ELF 64-bit LSB executable, x86-64, version 1 (SYSV), statically linked, not stripped All of my questions still hold true. What exactly is happening in this case? Can someone please answer my questions and provide an x86-64 version of this code?

  Read the article

• Running 32 bit assembly code on a 64 bit Linux & 64 bit Processor : Expalin the anomaly.

  - by claws

  Hello, I'm in an interesting problem.I forgot I'm using 64bit machine & OS and wrote a 32 bit assembly code. I don't know how to write 64 bit code. This is the x86 32-bit assembly code for Gnu Assembler (AT&T syntax) on Linux. #include <asm/unistd.h> #include <syscall.h> #define STDOUT 1 .data hellostr: .ascii "hello wolrd\n"; helloend: .text .globl _start _start: movl $(SYS_write) , %eax //ssize_t write(int fd, const void *buf, size_t count); movl $(STDOUT) , %ebx movl $hellostr , %ecx movl $(helloend-hellostr) , %edx int $0x80 movl $(SYS_exit), %eax //void _exit(int status); xorl %ebx, %ebx int $0x80 ret Now, This code should run fine on a 32bit processor & 32 bit OS right? As we know 64 bit processors are backward compatible with 32 bit processors. So, that also wouldn't be a problem. The problem arises because of differences in system calls & call mechanism in 64-bit OS & 32-bit OS. I don't know why but they changed the system call numbers between 32-bit linux & 64-bit linux. asm/unistd_32.h defines: #define __NR_write 4 #define __NR_exit 1 asm/unistd_64.h defines: #define __NR_write 1 #define __NR_exit 60 Anyway using Macros instead of direct numbers is paid off. Its ensuring correct system call numbers. when I assemble & link & run the program. Its not printing helloworld. In gdb its showing: Program exited with code 01. I don't know how to debug in gdb. using tutorial I tried to debug it and execute instruction by instruction checking registers at each step. its always showing me "program exited with 01". It would be great if some on could show me how to debug this. (gdb) break _start Note: breakpoint -10 also set at pc 0x4000b0. Breakpoint 8 at 0x4000b0 (gdb) start Function "main" not defined. Make breakpoint pending on future shared library load? (y or [n]) y Temporary breakpoint 9 (main) pending. Starting program: /home/claws/helloworld Program exited with code 01. (gdb) info breakpoints Num Type Disp Enb Address What 8 breakpoint keep y 0x00000000004000b0 <_start> 9 breakpoint del y <PENDING> main I tried running strace. This is its output: execve("./helloworld", ["./helloworld"], [/* 39 vars */]) = 0 write(0, NULL, 12 <unfinished ... exit status 1> Explain the parameters of write(0, NULL, 12) system call in the output of strace? What exactly is happening? I want to know the reason why exactly its exiting with exitstatus=1? Can some one please show me how to debug this program using gdb? Why did they change the system call numbers? Change this program appropriately so that it can run correctly on this machine.

  Read the article

< Previous Page | 1 2 3