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• Django ForeignKey TemplateSyntaxError and ProgrammingError

  - by Daniel Garcia

  This is are my models i want to relate. i want for collection to appear in the form of occurrence. class Collection(models.Model): id = models.AutoField(primary_key=True, null=True) code = models.CharField(max_length=100, null=True, blank=True) address = models.CharField(max_length=100, null=True, blank=True) collection_name = models.CharField(max_length=100) def __unicode__(self): return self.collection_name class Meta: db_table = u'collection' ordering = ('collection_name',) class Occurrence(models.Model): id = models.AutoField(primary_key=True, null=True) reference = models.IntegerField(null=True, blank=True, editable=False) collection = models.ForeignKey(Collection, null=True, blank=True, unique=True), modified = models.DateTimeField(null=True, blank=True, auto_now=True) class Meta: db_table = u'occurrence' Every time i go to check the Occurrence object i get this error TemplateSyntaxError at /admin/hotiapp/occurrence/ Caught an exception while rendering: column occurrence.collection_id does not exist LINE 1: ...LECT "occurrence"."id", "occurrence"."reference", "occurrenc.. And every time i try to add a new occurrence object i get this error ProgrammingError at /admin/hotiapp/occurrence/add/ column occurrence.collection_id does not exist LINE 1: SELECT (1) AS "a" FROM "occurrence" WHERE "occurrence"."coll... What am i doing wrong? or how does ForeignKey works?

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• Django Formset validation with an optional ForeignKey field

  - by Camilo Díaz

  Having a ModelFormSet built with modelformset_factory and using a model with an optional ForeignKey, how can I make empty (null) associations to validate on that form? Here is a sample code: ### model class Prueba(models.Model): cliente = models.ForeignKey(Cliente, null = True) valor = models.CharField(max_length = 20) ### view def test(request): PruebaFormSet = modelformset_factory(model = Prueba, extra = 1) if request.method == 'GET': formset = PruebaFormSet() return render_to_response('tpls/test.html', {'formset' : formset}, context_instance = RequestContext(request)) else: formset = PruebaFormSet(request.POST) # dumb tests, just to know if validating if formset.is_valid(): return HttpResponse('0') else: return HttpResponse('1') In my template, i'm just calling the {{ form.cliente }} method which renders the combo field, however, I want to be able to choose an empty (labeled "------") value, as the FK is optional... but when the form gets submitted it doesn't validate. Is this normal behaviour? How can i make this field to skip required validation?

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• Django MultiWidget Phone Number Field

  - by Birdman

  I want to create a field for phone number input that has 2 text fields (size 3, 3, and 4 respectively) with the common "(" ")" "-" delimiters. Below is my code for the field and the widget, I'm getting the following error when trying to iterate the fields in my form during initial rendering (it happens when the for loop gets to my phone number field): Caught an exception while rendering: 'NoneType' object is unsubscriptable class PhoneNumberWidget(forms.MultiWidget): def __init__(self,attrs=None): wigs = (forms.TextInput(attrs={'size':'3','maxlength':'3'}),\ forms.TextInput(attrs={'size':'3','maxlength':'3'}),\ forms.TextInput(attrs={'size':'4','maxlength':'4'})) super(PhoneNumberWidget, self).__init__(wigs, attrs) def decompress(self, value): return value or None def format_output(self, rendered_widgets): return '('+rendered_widgets[0]+')'+rendered_widgets[1]+'-'+rendered_widgets[2] class PhoneNumberField(forms.MultiValueField): widget = PhoneNumberWidget def __init__(self, *args, **kwargs): fields=(forms.CharField(max_length=3), forms.CharField(max_length=3), forms.CharField(max_length=4)) super(PhoneNumberField, self).__init__(fields, *args, **kwargs) def compress(self, data_list): if data_list[0] in fields.EMPTY_VALUES or data_list[1] in fields.EMPTY_VALUES or data_list[2] in fields.EMPTY_VALUES: raise fields.ValidateError(u'Enter valid phone number') return data_list[0]+data_list[1]+data_list[2] class AdvertiserSumbissionForm(ModelForm): business_phone_number = PhoneNumberField(required=True)

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• Django admin site auto populate combo box based on input

  - by user292652

  hi i have to following model class Match(models.Model): Team_one = models.ForeignKey('Team', related_name='Team_one') Team_two = models.ForeignKey('Team', related_name='Team_two') Stadium = models.CharField(max_length=255, blank=True) Start_time = models.DateTimeField(auto_now_add=False, auto_now=False, blank=True, null=True) Rafree = models.CharField(max_length=255, blank=True) Judge = models.CharField(max_length=255, blank=True) Winner = models.ForeignKey('Team', related_name='winner', blank=True) updated = models.DateTimeField('update date', auto_now=True ) created = models.DateTimeField('creation date', auto_now_add=True ) def save(self, force_insert=False, force_update=False): pass @models.permalink def get_absolute_url(self): return ('view_or_url_name') class MatchAdmin(admin.ModelAdmin): list_display = ('Team_one','Team_two', 'Winner') search_fields = ['Team_one','Team_tow'] admin.site.register(Match, MatchAdmin) i was wondering is their a way to populated the winner combo box once the team one and team two is selected in admin site ?

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• Default value for field in Django model

  - by Daniel Garcia

  Suppose I have a model: class SomeModel(models.Model): id = models.AutoField(primary_key=True) a = models.IntegerField(max_length=10) b = models.CharField(max_length=7) Currently I am using the default admin to create/edit objects of this type. How do I set the field 'a' to have the same number as id? (default=???) Other question Suppose I have a model: event_date = models.DateTimeField( null=True) year = models.IntegerField( null=True) month = models.CharField(max_length=50, null=True) day = models.IntegerField( null=True) How can i set the year, month and day fields by default to be the same as event_date field?

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• How to manually render a Django template for an inlineformset_factory with can_delete = True / False

  - by chefsmart

  I have an inlineformset with a custom Modelform. So it looks something like this: MyInlineFormSet = inlineformset_factory(MyMainModel, MyInlineModel, form=MyCustomInlineModelForm) I am rendering this inlineformset manually in a template so that I have more control over widgets and javascript. So I go in a loop like {% for form in myformset.forms %} and then manually render each field as described on this page http://docs.djangoproject.com/en/dev/topics/forms/#customizing-the-form-template The formset has can_delete = True or can_delete = False depending on whether the user is creating new objects or editing existing ones. Question is, how do I manually render the can_delete checkbox?

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• Django make model field name a link

  - by Daniel Garcia

  what Im looking to do is to have a link on the name of a field of a model. So when im filling the form using the admin interface i can access some information. I know this doesn't work but shows what i want to do class A(models.Model): item_type = models.CharField(max_length=100, choices=ITEMTYPE_CHOICES, verbose_name="<a href='http://www.quackit.com/html/codes'>Item Type</a>") Other option would be to put a description next to the field. Im not even sure where to start from.

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• Default value for hidden field in Django model

  - by Daniel Garcia

  I have this Model: class Occurrence(models.Model): id = models.AutoField(primary_key=True, null=True) reference = models.IntegerField(null=True, editable=False) def save(self): self.collection = self.id super(Occurrence, self).save() I want for the reference field to be hidden and at the same time have the same value as id. This code works if the editable=True but if i want to hide it it doesnt change the value of reference. how can i fix that?

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• In django changing the file name of uploading file.

  - by Software Enthusiastic

  Hi Is it possible to change the file name of the uploading file in the django? I searched, but couldn't find any answer. My requirement is whenever a file is uploaded its file name should be changed in the following format. format = userid + transaction_uuid + file_extension Thank yo very much...

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• Multiple model forms with some pre-populated fields

  - by jimbocooper

  Hi! Hope somebody can help me, since I've been stuck for a while with this... I switched to another task, but now back to the fight I still can't figure out how to come out from the black hole xD The thing is as follows: Let's say I've got a product model, and then a set of Clients which have rights to submit data for the products they've been subscribed (Many to Many from Client to Product). Whenever my client is going to submit data, I need to create as many forms as products he's subscribed, and pre-populate each one of them with the "product" field as long as perform a quite simple validation (some optional fields have to be completed if it's client's first submission). I would like one form "step" for each product submission, so I've tried formWizards... but the problem is you can't pre-assign values to the forms... this can be solved afterwards when submitting, though... but not the problem that it doesn't allow validation either, so at the end of each step I can check some data before rendering next step. Then I've tried model formsets, but then there's no way to pre-populate the needed fields. I came across some django plugins, but I'm not confident yet if any of them will make it.... Did anybody has a similar problem so he can give me a ray of light? Thanks a lot in advance!! :) edit: The code I used in the formsets way is as follows: prods = Products.objects.filter(Q(start_date__lte=today) & Q(end_date__gte=today), requester=client) num = len(prods) PriceSubmissionFormSet = modelformset_factory(PriceSubmission, extra=num) formset = PriceSubmissionFormSet(queryset=PriceSubmission.objects.none())

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• Django: What's an awesome plugin to maintain images in the admin?

  - by meder

  I have an articles entry model and I have an excerpt and description field. If a user wants to post an image then I have a separate ImageField which has the default standard file browser. I've tried using django-filebrowser but I don't like the fact that it requires django-grappelli nor do I necessarily want a flash upload utility - can anyone recommend a tool where I can manage image uploads, and basically replace the file browse provided by django with an imagepicking browser? In the future I'd probably want it to handle image resizing and specify default image sizes for certain article types. Edit: I'm trying out adminfiles now but I'm having issues installing it. I grabbed it and added it to my python path, added it to INSTALLED_APPS, created the databases for it, uploaded an image. I followed the instructions to modify my Model to specify adminfiles_fields and registered but it's not applying in my admin, here's my admin.py for articles: from django.contrib import admin from django import forms from articles.models import Category, Entry from tinymce.widgets import TinyMCE from adminfiles.admin import FilePickerAdmin class EntryForm( forms.ModelForm ): class Media: js = ['/media/tinymce/tiny_mce.js', '/media/tinymce/load.js']#, '/media/admin/filebrowser/js/TinyMCEAdmin.js'] class Meta: model = Entry class CategoryAdmin(admin.ModelAdmin): prepopulated_fields = { 'slug': ['title'] } class EntryAdmin( FilePickerAdmin ): adminfiles_fields = ('excerpt',) prepopulated_fields = { 'slug': ['title'] } form = EntryForm admin.site.register( Category, CategoryAdmin ) admin.site.register( Entry, EntryAdmin ) Here's my Entry model: class Entry( models.Model ): LIVE_STATUS = 1 DRAFT_STATUS = 2 HIDDEN_STATUS = 3 STATUS_CHOICES = ( ( LIVE_STATUS, 'Live' ), ( DRAFT_STATUS, 'Draft' ), ( HIDDEN_STATUS, 'Hidden' ), ) status = models.IntegerField( choices=STATUS_CHOICES, default=LIVE_STATUS ) tags = TagField() categories = models.ManyToManyField( Category ) title = models.CharField( max_length=250 ) excerpt = models.TextField( blank=True ) excerpt_html = models.TextField(editable=False, blank=True) body_html = models.TextField( editable=False, blank=True ) article_image = models.ImageField(blank=True, upload_to='upload') body = models.TextField() enable_comments = models.BooleanField(default=True) pub_date = models.DateTimeField(default=datetime.datetime.now) slug = models.SlugField(unique_for_date='pub_date') author = models.ForeignKey(User) featured = models.BooleanField(default=False) def save( self, force_insert=False, force_update= False): self.body_html = markdown(self.body) if self.excerpt: self.excerpt_html = markdown( self.excerpt ) super( Entry, self ).save( force_insert, force_update ) class Meta: ordering = ['-pub_date'] verbose_name_plural = "Entries" def __unicode__(self): return self.title Edit #2: To clarify I did move the media files to my media path and they are indeed rendering the image area, I can upload fine, the <<<image>>> tag is inserted into my editable MarkItUp w/ Markdown area but it isn't rendering in the MarkItUp preview - perhaps I just need to apply the |upload_tags into that preview. I'll try adding it to my template which posts the article as well.

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• Problem with messages framework in Django 1.2

  - by Konstantin

  Hello! I'm running Django 1.2 beta and trying out the new feature: message framework. http://docs.djangoproject.com/en/dev/ref/contrib/messages/ Everything seems to work, but when I try to output the messages, I get nothing. Seems that messages variable is empty. I double checked all the settings, they seem to be just like in the manual. What could be wrong? settings.py MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.messages.middleware.MessageMiddleware', #send messages to users 'django.middleware.locale.LocaleMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', #debug tool 'debug_toolbar.middleware.DebugToolbarMiddleware', ) TEMPLATE_CONTEXT_PROCESSORS = ( 'django.contrib.messages.context_processors.messages', #send messages to users 'django.core.context_processors.auth', ) #Store messages in sessions MESSAGE_STORAGE = 'django.contrib.messages.storage.session.SessionStorage'; INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', #'django.contrib.sites', 'django.contrib.admin', 'django.contrib.messages', 'debug_toolbar', #my apps #... ) views.py def myview(request): from django.contrib import messages messages.error(request, 'error test'); messages.success(request, 'success test'); return render_to_response('mytemplate.html', locals()); mytemplate.html {% for message in messages %} {{ message }}<br /> {% endfor %} In template nothing is outputted.

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• Django 1.4.1 error loading MySQLdb module when attempting 'python manage.py shell'

  - by Paul

  I am trying to set up MySQL, and can't seem to be able to enter the Django manage.py shell interpreter. Getting the output below: rrdhcp-10-32-44-126:django pavelfage$ python manage.py shell Traceback (most recent call last): File "manage.py", line 10, in <module> execute_from_command_line(sys.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 443, in execute_from_command_line utility.execute() File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 382, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 196, in run_from_argv self.execute(*args, **options.__dict__) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 232, in execute output = self.handle(*args, **options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 371, in handle return self.handle_noargs(**options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/commands/shell.py", line 45, in handle_noargs from django.db.models.loading import get_models File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 40, in <module> backend = load_backend(connection.settings_dict['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 34, in __getattr__ return getattr(connections[DEFAULT_DB_ALIAS], item) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 92, in __getitem__ backend = load_backend(db['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 24, in load_backend return import_module('.base', backend_name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/backends/mysql/base.py", line 16, in <module> raise ImproperlyConfigured("Error loading MySQLdb module: %s" % e) django.core.exceptions.ImproperlyConfigured: Error loading MySQLdb module: No module named _mysql Any suggestions really appreciated.

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• Can Django admin handle a one-to-many relationship via related_name?

  - by Mat

  The Django admin happily supports many-to-one and many-to-many relationships through an HTML <SELECT> form field, allowing selection of one or many options respectively. There's even a nice Javascript filter_horizontal widget to help. I'm trying to do the same from the one-to-many side through related_name. I don't see how it's much different from many-to-many as far as displaying it in the form is concerned, I just need a multi-select SELECT list. But I cannot simply add the related_name value to my ModelAdmin-derived field list. Does Django support one-to-many fields in this way? My Django model something like this (contrived to simplify the example): class Person(models.Model): ... manager = models.ForeignKey('self', related_name='staff', null=True, blank=True, ) From the Person admin page, I can easily get a <SELECT> list showing all possible staff to choose this person's manager from. I also want to display a multiple-selection <SELECT> list of all the manager's staff. I don't want to use inlines, as I don't want to edit the subordinates details; I do want to be able to add/remove people from the list. (I'm trying to use django-ajax-selects to replace the SELECT widget, but that's by-the-by.)

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• Django - no module named app

  - by Koran

  Hi, I have been trying to get an application written in django working - but it is not working at all. I have been working on for some time too - and it is working on dev-server perfectly. But I am unable to put in the production env (apahce). My project name is apstat and the app name is basic. I try to access it as following Blockquote http://hostname/apstat But it shows the following error: MOD_PYTHON ERROR ProcessId: 6002 Interpreter: 'domU-12-31-39-06-DD-F4.compute-1.internal' ServerName: 'domU-12-31-39-06-DD-F4.compute-1.internal' DocumentRoot: '/home/ubuntu/server/' URI: '/apstat/' Location: '/apstat' Directory: None Filename: '/home/ubuntu/server/apstat/' PathInfo: '' Phase: 'PythonHandler' Handler: 'django.core.handlers.modpython' Traceback (most recent call last): File "/usr/lib/python2.6/dist-packages/mod_python/importer.py", line 1537, in HandlerDispatch default=default_handler, arg=req, silent=hlist.silent) File "/usr/lib/python2.6/dist-packages/mod_python/importer.py", line 1229, in _process_target result = _execute_target(config, req, object, arg) File "/usr/lib/python2.6/dist-packages/mod_python/importer.py", line 1128, in _execute_target result = object(arg) File "/usr/lib/pymodules/python2.6/django/core/handlers/modpython.py", line 228, in handler return ModPythonHandler()(req) File "/usr/lib/pymodules/python2.6/django/core/handlers/modpython.py", line 201, in __call__ response = self.get_response(request) File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py", line 134, in get_response return self.handle_uncaught_exception(request, resolver, exc_info) File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py", line 154, in handle_uncaught_exception return debug.technical_500_response(request, *exc_info) File "/usr/lib/pymodules/python2.6/django/views/debug.py", line 40, in technical_500_response html = reporter.get_traceback_html() File "/usr/lib/pymodules/python2.6/django/views/debug.py", line 114, in get_traceback_html return t.render(c) File "/usr/lib/pymodules/python2.6/django/template/__init__.py", line 178, in render return self.nodelist.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py", line 779, in render bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py", line 81, in render_node raise wrapped TemplateSyntaxError: Caught an exception while rendering: No module named basic Original Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/template/debug.py", line 71, in render_node result = node.render(context) File "/usr/lib/pymodules/python2.6/django/template/debug.py", line 87, in render output = force_unicode(self.filter_expression.resolve(context)) File "/usr/lib/pymodules/python2.6/django/template/__init__.py", line 572, in resolve new_obj = func(obj, *arg_vals) File "/usr/lib/pymodules/python2.6/django/template/defaultfilters.py", line 687, in date return format(value, arg) File "/usr/lib/pymodules/python2.6/django/utils/dateformat.py", line 269, in format return df.format(format_string) File "/usr/lib/pymodules/python2.6/django/utils/dateformat.py", line 30, in format pieces.append(force_unicode(getattr(self, piece)())) File "/usr/lib/pymodules/python2.6/django/utils/dateformat.py", line 175, in r return self.format('D, j M Y H:i:s O') File "/usr/lib/pymodules/python2.6/django/utils/dateformat.py", line 30, in format pieces.append(force_unicode(getattr(self, piece)())) File "/usr/lib/pymodules/python2.6/django/utils/encoding.py", line 71, in force_unicode s = unicode(s) File "/usr/lib/pymodules/python2.6/django/utils/functional.py", line 201, in __unicode_cast return self.__func(*self.__args, **self.__kw) File "/usr/lib/pymodules/python2.6/django/utils/translation/__init__.py", line 62, in ugettext return real_ugettext(message) File "/usr/lib/pymodules/python2.6/django/utils/translation/trans_real.py", line 286, in ugettext return do_translate(message, 'ugettext') File "/usr/lib/pymodules/python2.6/django/utils/translation/trans_real.py", line 276, in do_translate _default = translation(settings.LANGUAGE_CODE) File "/usr/lib/pymodules/python2.6/django/utils/translation/trans_real.py", line 194, in translation default_translation = _fetch(settings.LANGUAGE_CODE) File "/usr/lib/pymodules/python2.6/django/utils/translation/trans_real.py", line 180, in _fetch app = import_module(appname) File "/usr/lib/pymodules/python2.6/django/utils/importlib.py", line 35, in import_module __import__(name) ImportError: No module named basic My settings.py is as follows: INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'apstat.basic', 'django.contrib.admin', ) If I remove the apstat.basic, it goes through, but that is not a solution. Is it something I am doing in apache? My apache - settings are - <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot /home/ubuntu/server/ <Directory /> Options None AllowOverride None </Directory> <Directory /home/ubuntu/server/apstat> AllowOverride None Order allow,deny allow from all </Directory> <Location "/apstat"> SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE apstat.settings PythonOption django.root /home/ubuntu/server/ PythonDebug On PythonPath "['/home/ubuntu/server/'] + sys.path" </Location> </VirtualHost> I have now sat for more than a day on this. If someone can help me out, it would be very nice.

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• Error after installing Django (supposed PATH or PYTHONPATH "error")

  - by illuminated

  Hi all, I guess this is a PATH/PYTHONPATH error, but my attempts failed so far to make django working. System is Ubuntu 10.04, 64bit: mx:~/webapps$ cat /etc/lsb-release DISTRIB_ID=Ubuntu DISTRIB_RELEASE=10.04 DISTRIB_CODENAME=lucid DISTRIB_DESCRIPTION="Ubuntu 10.04 LTS" Python version: 2.6.5: @mx:~/webapps$ python -V Python 2.6.5 When I run django-admin.py, the following happens: mx:~/webapps$ django-admin.py Traceback (most recent call last): File "/usr/local/bin/django-admin.py", line 2, in <module> from django.core import management ImportError: No module named django.core Similar when I import django in python shell: mx:~/webapps$ python Python 2.6.5 (r265:79063, Apr 16 2010, 13:09:56) [GCC 4.4.3] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import django Traceback (most recent call last): File "<stdin>", line 1, in <module> ImportError: No module named django >>> quit() More details: mx:~/webapps$ python -c "from distutils.sysconfig import get_python_lib; print get_python_lib()" /usr/lib/python2.6/dist-packages Within python shell: Python 2.6.5 (r265:79063, Apr 16 2010, 13:09:56) [GCC 4.4.3] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import sys >>> print sys.path ['', '/usr/lib/python2.6/dist-packages/django', '/usr/local/lib/python2.6/dist-packages/django/bin', '/usr/local/lib/python2.6/dist-packages/django', '/home/petra/webapps', '/usr/lib/python2.6', '/usr/lib/python2.6/plat-linux2', '/usr/lib/python2.6/lib-tk', '/usr/lib/python2.6/lib-old', '/usr/lib/python2.6/lib-dynload', '/usr/lib/python2.6/dist-packages', '/usr/lib/python2.6/dist-packages/PIL', '/usr/lib/pymodules/python2.6'] django-admin.py can be found here: mx:~/webapps$ locate django-admin.py ~/install/sources/Django-1.2.1/build/lib.linux-i686-2.6/django/bin/django-admin.py ~/install/sources/Django-1.2.1/build/scripts-2.6/django-admin.py ~/install/sources/Django-1.2.1/django/bin/django-admin.py /usr/local/bin/django-admin.py /usr/local/lib/python2.6/dist-packages/django/bin/django-admin.py /usr/local/lib/python2.6/dist-packages/django/bin/django-admin.pyc and in the end this doesn't help: export PYTHONPATH="/usr/lib/python2.6/dist-packages/django:$PYTHONPATH" nor this: export PYTHONPATH="/usr/local/lib/python2.6/dist-packages/django:$PYTHONPATH" How to solve this !? Thanks all in advance! :)

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• django views question

  - by Hulk

  In my django views i have the following def create(request): query=header.objects.filter(id=a)[0] a=query.criteria_set.all() logging.debug(a.details) I get an error saying 'QuerySet' object has no attribute 'details' in the debug statement .What is this error and what should be the correct statemnt to query this.And the model corresponding to this is as follows where as the models has the following: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() Thanks..

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• A Custom View Engine with Dynamic View Location

  - by imran_ku07

      Introduction:          One of the nice feature of ASP.NET MVC framework is its pluggability. This means you can completely replace the default view engine(s) with a custom one. One of the reason for using a custom view engine is to change the default views location and sometimes you need to change the views location at run-time. For doing this, you can extend the default view engine(s) and then change the default views location variables at run-time.  But, you cannot directly change the default views location variables at run-time because they are static and shared among all requests. In this article, I will show you how you can dynamically change the views location without changing the default views location variables at run-time.       Description:           Let's say you need to synchronize the views location with controller name and controller namespace. So, instead of searching to the default views location(Views/ControllerName/ViewName) to locate views, this(these) custom view engine(s) will search in the Views/ControllerNameSpace/ControllerName/ViewName folder to locate views.           First of all create a sample ASP.NET MVC 3 application and then add these custom view engines to your application,   public class MyRazorViewEngine : RazorViewEngine { public MyRazorViewEngine() : base() { AreaViewLocationFormats = new[] { "~/Areas/{2}/Views/%1/{1}/{0}.cshtml", "~/Areas/{2}/Views/%1/{1}/{0}.vbhtml", "~/Areas/{2}/Views/%1/Shared/{0}.cshtml", "~/Areas/{2}/Views/%1/Shared/{0}.vbhtml" }; AreaMasterLocationFormats = new[] { "~/Areas/{2}/Views/%1/{1}/{0}.cshtml", "~/Areas/{2}/Views/%1/{1}/{0}.vbhtml", "~/Areas/{2}/Views/%1/Shared/{0}.cshtml", "~/Areas/{2}/Views/%1/Shared/{0}.vbhtml" }; AreaPartialViewLocationFormats = new[] { "~/Areas/{2}/Views/%1/{1}/{0}.cshtml", "~/Areas/{2}/Views/%1/{1}/{0}.vbhtml", "~/Areas/{2}/Views/%1/Shared/{0}.cshtml", "~/Areas/{2}/Views/%1/Shared/{0}.vbhtml" }; ViewLocationFormats = new[] { "~/Views/%1/{1}/{0}.cshtml", "~/Views/%1/{1}/{0}.vbhtml", "~/Views/%1/Shared/{0}.cshtml", "~/Views/%1/Shared/{0}.vbhtml" }; MasterLocationFormats = new[] { "~/Views/%1/{1}/{0}.cshtml", "~/Views/%1/{1}/{0}.vbhtml", "~/Views/%1/Shared/{0}.cshtml", "~/Views/%1/Shared/{0}.vbhtml" }; PartialViewLocationFormats = new[] { "~/Views/%1/{1}/{0}.cshtml", "~/Views/%1/{1}/{0}.vbhtml", "~/Views/%1/Shared/{0}.cshtml", "~/Views/%1/Shared/{0}.vbhtml" }; } protected override IView CreatePartialView(ControllerContext controllerContext, string partialPath) { var nameSpace = controllerContext.Controller.GetType().Namespace; return base.CreatePartialView(controllerContext, partialPath.Replace("%1", nameSpace)); } protected override IView CreateView(ControllerContext controllerContext, string viewPath, string masterPath) { var nameSpace = controllerContext.Controller.GetType().Namespace; return base.CreateView(controllerContext, viewPath.Replace("%1", nameSpace), masterPath.Replace("%1", nameSpace)); } protected override bool FileExists(ControllerContext controllerContext, string virtualPath) { var nameSpace = controllerContext.Controller.GetType().Namespace; return base.FileExists(controllerContext, virtualPath.Replace("%1", nameSpace)); } } public class MyWebFormViewEngine : WebFormViewEngine { public MyWebFormViewEngine() : base() { MasterLocationFormats = new[] { "~/Views/%1/{1}/{0}.master", "~/Views/%1/Shared/{0}.master" }; AreaMasterLocationFormats = new[] { "~/Areas/{2}/Views/%1/{1}/{0}.master", "~/Areas/{2}/Views/%1/Shared/{0}.master", }; ViewLocationFormats = new[] { "~/Views/%1/{1}/{0}.aspx", "~/Views/%1/{1}/{0}.ascx", "~/Views/%1/Shared/{0}.aspx", "~/Views/%1/Shared/{0}.ascx" }; AreaViewLocationFormats = new[] { "~/Areas/{2}/Views/%1/{1}/{0}.aspx", "~/Areas/{2}/Views/%1/{1}/{0}.ascx", "~/Areas/{2}/Views/%1/Shared/{0}.aspx", "~/Areas/{2}/Views/%1/Shared/{0}.ascx", }; PartialViewLocationFormats = ViewLocationFormats; AreaPartialViewLocationFormats = AreaViewLocationFormats; } protected override IView CreatePartialView(ControllerContext controllerContext, string partialPath) { var nameSpace = controllerContext.Controller.GetType().Namespace; return base.CreatePartialView(controllerContext, partialPath.Replace("%1", nameSpace)); } protected override IView CreateView(ControllerContext controllerContext, string viewPath, string masterPath) { var nameSpace = controllerContext.Controller.GetType().Namespace; return base.CreateView(controllerContext, viewPath.Replace("%1", nameSpace), masterPath.Replace("%1", nameSpace)); } protected override bool FileExists(ControllerContext controllerContext, string virtualPath) { var nameSpace = controllerContext.Controller.GetType().Namespace; return base.FileExists(controllerContext, virtualPath.Replace("%1", nameSpace)); } }             Here, I am extending the RazorViewEngine and WebFormViewEngine class and then appending /%1 in each views location variable, so that we can replace /%1 at run-time. I am also overriding the FileExists, CreateView and CreatePartialView methods. In each of these method implementation, I am replacing /%1 with controller namespace. Now, just register these view engines in Application_Start method in Global.asax.cs file,   protected void Application_Start() { ViewEngines.Engines.Clear(); ViewEngines.Engines.Add(new MyRazorViewEngine()); ViewEngines.Engines.Add(new MyWebFormViewEngine()); ................................................ ................................................ }             Now just create a controller and put this controller's view inside Views/ControllerNameSpace/ControllerName folder and then run this application. You will find that everything works just fine.       Summary:          ASP.NET MVC uses convention over configuration to locate views. For many applications this convention to locate views is acceptable. But sometimes you may need to locate views at run-time. In this article, I showed you how you can dynamically locate your views by using a custom view engine. I am also attaching a sample application. Hopefully you will enjoy this article too. SyntaxHighlighter.all()  

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• django views getid

  - by Hulk

  class host(models.Model): emp = models.ForeignKey(getname) def __unicode__(self): return self.topic In views there is the code as, real =[] for emp in my_emp: real.append(host.objects.filter(emp=emp.id)) This above results only the values of emp,My question is that how to get the ids along with emp values. Thanks..

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• django internationalization doesn't work

  - by xRobot

  I have: created translation strings in the template and in the application view. run this command: django-admin.py makemessages -l it and the file it/LC_MESSAGES/django.po has been created run this command: django-admin.py compilemessages and I receive: processing file django.po in /home/jobber/Desktop/library/books/locale/it/LC_MESSAGES set the language code in settings.py: LANGUAGE_CODE = 'it-IT' but.... translation doesn't work !! I always see english text. Why ?

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• ** EDITED ** 'NoneType' object has no attribute 'day'

  - by Asinox

  Hi guy, i dont know where is my error, but Django 1.2.1 is give this error: 'NoneType' object has no attribute 'day' when i try to save form from the Administrator Area models.py from django.db import models from django.contrib.auth.models import User class Editorial(models.Model): titulo = models.CharField(max_length=250,help_text='Titulo del editorial') editorial = models.TextField(help_text='Editorial') slug = models.SlugField(unique_for_date='pub_date') autor = models.ForeignKey(User) pub_date = models.DateTimeField(auto_now_add=True) activa = models.BooleanField(verbose_name="Activa") enable_comments = models.BooleanField(verbose_name="Aceptar Comentarios",default=False) editorial_html = models.TextField(editable=False,blank=True) def __unicode__(self): return unicode(self.titulo) def get_absolute_url(self): return "/editorial/%s/%s/" % (self.pub_date.strftime("%Y/%b/%d").lower(), self.slug) class Meta: ordering=['-pub_date'] verbose_name_plural ='Editoriales' def save(self,force_insert=False, force_update=False): from markdown import markdown if self.editorial: self.editorial_html = markdown(self.editorial) super(Editorial,self).save(force_insert,force_update) i dont know why this error, COMPLETED ERROR: Traceback: File "C:\wamp\bin\Python26\lib\site-packages\django\core\handlers\base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\contrib\admin\options.py" in wrapper 239. return self.admin_site.admin_view(view)(*args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\utils\decorators.py" in _wrapped_view 76. response = view_func(request, *args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\views\decorators\cache.py" in _wrapped_view_func 69. response = view_func(request, *args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\contrib\admin\sites.py" in inner 190. return view(request, *args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\utils\decorators.py" in _wrapper 21. return decorator(bound_func)(*args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\utils\decorators.py" in _wrapped_view 76. response = view_func(request, *args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\utils\decorators.py" in bound_func 17. return func(self, *args2, **kwargs2) File "C:\wamp\bin\Python26\lib\site-packages\django\db\transaction.py" in _commit_on_success 299. res = func(*args, **kw) File "C:\wamp\bin\Python26\lib\site-packages\django\contrib\admin\options.py" in add_view 777. if form.is_valid(): File "C:\wamp\bin\Python26\lib\site-packages\django\forms\forms.py" in is_valid 121. return self.is_bound and not bool(self.errors) File "C:\wamp\bin\Python26\lib\site-packages\django\forms\forms.py" in _get_errors 112. self.full_clean() File "C:\wamp\bin\Python26\lib\site-packages\django\forms\forms.py" in full_clean 269. self._post_clean() File "C:\wamp\bin\Python26\lib\site-packages\django\forms\models.py" in _post_clean 345. self.validate_unique() File "C:\wamp\bin\Python26\lib\site-packages\django\forms\models.py" in validate_unique 354. self.instance.validate_unique(exclude=exclude) File "C:\wamp\bin\Python26\lib\site-packages\django\db\models\base.py" in validate_unique 695. date_errors = self._perform_date_checks(date_checks) File "C:\wamp\bin\Python26\lib\site-packages\django\db\models\base.py" in _perform_date_checks 802. lookup_kwargs['%s__day' % unique_for] = date.day Exception Type: AttributeError at /admin/editoriales/editorial/add/ Exception Value: 'NoneType' object has no attribute 'day' thanks guys sorry with my English

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• So now that Django 1.2 is officially out...

  - by Fedor

  Since I have Django 1.1x on my Debian setup - how can I use virtualenv or similar and not have it mess up my system's default django version which in turn would break all my sites? Detailed instructions or a great tutorial link would very much be appreciated - please don't offer vague advice since I'm still a noob. Currently I store all my django projects in ~/django-sites and I am using Apache2 + mod_wsgi to deploy.

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• Django-Registration & Django-Profile, using your own custom form

  - by Issy

  Hey All, I am making use of django-registration and django-profile to handle registration and profiles. I would like to create a profile for the user at the time of registration. I have created a custom registration form, and added that to the urls.py using the tutorial on: http://dewful.com/?p=70 The basic idea in the tutorial is to override the default registration form to create the profile at the same time. forms.py - In my profiles app from django import forms from registration.forms import RegistrationForm from django.utils.translation import ugettext_lazy as _ from profiles.models import UserProfile from registration.models import RegistrationProfile attrs_dict = { 'class': 'required' } class UserRegistrationForm(RegistrationForm): city = forms.CharField(widget=forms.TextInput(attrs=attrs_dict)) def save(self, profile_callback=None): new_user = RegistrationProfile.objects.create_inactive_user(username=self.cleaned_data['username'], password=self.cleaned_data['password1'], email=self.cleaned_data['email']) new_profile = UserProfile(user=new_user, city=self.cleaned_data['city']) new_profile.save() return new_user In urls.py from profiles.forms import UserRegistrationForm and url(r'^register/$', register, {'backend': 'registration.backends.default.DefaultBackend', 'form_class' : UserRegistrationForm}, name='registration_register'), The form is displayed, and i can enter in City, however it does not save or create the entry in the DB.

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• Django Error: NameError name 'current_datetime' is not defined

  - by Diego

  I'm working through the book "The Definitive Guide to Django" and am stuck on a piece of code. This is the code in my settings.py: ROOT_URLCONF = 'mysite.urls' I have the following code in my urls.py from django.conf.urls.defaults import * from mysite.views import hello, my_homepage_view urlpatterns = patterns('', ('^hello/$', hello), ) urlpatterns = patterns('', ('^time/$', current_datetime), ) And the following is the code in my views.py file: from django.http import HttpResponse import datetime def hello(request): return HttpResponse("Hello World") def current_datetime(request): now = datetime.datetime.now() html = "<html><body>It is now %s.</body></html>" % now return HttpResponse(html) Yet, I get the following error when I test the code in the development server. NameError at /time/ name 'current_datetime' is not defined Can someone help me out here? This really is just a copy-paste from the book. I don't see any mistyping.

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• django error ,about django-sphinx

  - by zjm1126

  from django.db import models from djangosphinx.models import SphinxSearch class MyModel(models.Model): search = SphinxSearch() # optional: defaults to db_table # If your index name does not match MyModel._meta.db_table # Note: You can only generate automatic configurations from the ./manage.py script # if your index name matches. search = SphinxSearch('index_name') # Or maybe we want to be more.. specific searchdelta = SphinxSearch( index='index_name delta_name', weights={ 'name': 100, 'description': 10, 'tags': 80, }, mode='SPH_MATCH_ALL', rankmode='SPH_RANK_NONE', ) queryset = MyModel.search.query('query') results1 = queryset.order_by('@weight', '@id', 'my_attribute') results2 = queryset.filter(my_attribute=5) results3 = queryset.filter(my_other_attribute=[5, 3,4]) results4 = queryset.exclude(my_attribute=5)[0:10] results5 = queryset.count() # as of 2.0 you can now access an attribute to get the weight and similar arguments for result in results1: print result, result._sphinx # you can also access a similar set of meta data on the queryset itself (once it's been sliced or executed in any way) print results1._sphinx and Traceback (most recent call last): File "D:\zjm_code\sphinx_test\models.py", line 1, in <module> from django.db import models File "D:\Python25\Lib\site-packages\django\db\__init__.py", line 10, in <module> if not settings.DATABASE_ENGINE: File "D:\Python25\Lib\site-packages\django\utils\functional.py", line 269, in __getattr__ self._setup() File "D:\Python25\Lib\site-packages\django\conf\__init__.py", line 38, in _setup raise ImportError("Settings cannot be imported, because environment variable %s is undefined." % ENVIRONMENT_VARIABLE) ImportError: Settings cannot be imported, because environment variable DJANGO_SETTINGS_MODULE is undefined.

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