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  • What is the proper way to URL encode Unicode characters?

    - by Josh Gibson
    I know of the non-standard %uxxxx scheme but that doesn't seem like a wise choice since the scheme has been rejected by the W3C. Some interesting examples: The heart character. If I type this into my browser: http://www.google.com/search?q=? Then copy and paste it, I see this URL http://www.google.com/search?q=%E2%99%A5 which makes it seem like Firefox (or Safari) is doing this. urllib.quote_plus(x.encode("latin-1")) '%E2%99%A5' which makes sense, except for things that can't be encoded in Latin-1, like the triple dot character. … If I type the URL http://www.google.com/search?q=… into my browser then copy and paste, I get http://www.google.com/search?q=%E2%80%A6 back. Which seems to be the result of doing urllib.quote_plus(x.encode("utf-8")) which makes sense since … can't be encoded with Latin-1. But then its not clear to me how the browser knows whether to decode with UTF-8 or Latin-1. Since this seems to be ambiguous: In [67]: u"…".encode('utf-8').decode('latin-1') Out[67]: u'\xc3\xa2\xc2\x80\xc2\xa6' works, so I don't know how the browser figures out whether to decode that with UTF-8 or Latin-1. What's the right thing to be doing with the special characters I need to deal with?

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  • Using TextOptions.TextFormattingMode with FormattedText

    - by dan gibson
    With WPF4 you can have non-blurry text by adding TextOptions.TextFormattingMode="Display" and TextOptions.TextRenderingMode="Aliased" to your xaml: <Window TextOptions.TextFormattingMode="Display" TextOptions.TextRenderingMode="Aliased"> This works fine for me except for when I draw text with DrawingContext.DrawText like this: void DrawText(DrawingContext dc) { FormattedText ft = new FormattedText("Hello World", System.Globalization.CultureInfo.CurrentCulture, System.Windows.FlowDirection.LeftToRight, new Typeface(FontFamily, FontStyle, FontWeight, FontStretch), FontSize, brush); dc.DrawText(ft, new Point(rect.Left, rect.Top)); } How can I draw non-blurry text with FormattedText? ie I want TextOptions.TextFormattingMode="Display" and TextOptions.TextRenderingMode="Aliased" to be used.

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  • How to close a JFrame in the middle of a program

    - by Nick Gibson
    public class JFrameWithPanel extends JFrame implements ActionListener, ItemListener { int packageIndex; double price; double[] prices = {49.99, 39.99, 34.99, 99.99}; DecimalFormat money = new DecimalFormat("$0.00"); JLabel priceLabel = new JLabel("Total Price: "+price); JButton button = new JButton("Check Price"); JComboBox packageChoice = new JComboBox(); JPanel pane = new JPanel(); TextField text = new TextField(5); JButton accept = new JButton("Accept"); JButton decline = new JButton("Decline"); JCheckBox serviceTerms = new JCheckBox("I Agree to the Terms of Service.", false); JTextArea termsOfService = new JTextArea("This is a text area", 5, 10); public JFrameWithPanel() { super("JFrame with Panel"); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); pane.add(packageChoice); setContentPane(pane); setSize(250,250); setVisible(true); packageChoice.addItem("A+ Certification"); packageChoice.addItem("Network+ Certification "); packageChoice.addItem("Security+ Certifictation"); packageChoice.addItem("CIT Full Test Package"); pane.add(button); button.addActionListener(this); pane.add(text); text.setEditable(false); text.setBackground(Color.WHITE); text.addActionListener(this); pane.add(termsOfService); termsOfService.setEditable(false); termsOfService.setBackground(Color.lightGray); pane.add(serviceTerms); serviceTerms.addItemListener(this); pane.add(accept); accept.addActionListener(this); pane.add(decline); decline.addActionListener(this); } public void actionPerformed(ActionEvent e) { packageIndex = packageChoice.getSelectedIndex(); price = prices[packageIndex]; text.setText("$"+price); Object source = e.getSource(); if(source == accept) { if(serviceTerms.isSelected() == false) { JOptionPane.showMessageDialog(null,"Please accept the terms of service.", "Terms of Service", JOptionPane.ERROR_MESSAGE); } else { JOptionPane.showMessageDialog(null,"Thank you. We will now move on to registering your product."); pane.dispose(); } } else if(source == decline) { System.exit(0); } } public void itemStateChanged(ItemEvent e) { int select = e.getStateChange(); } public static void main(String[] args) { String value1; int constant = 1, invalidNum = 0, answerParse, packNum, packPrice; JOptionPane.showMessageDialog(null,"Hello!"+"\nWelcome to the CIT Test Program."); JOptionPane.showMessageDialog(null,"IT WORKS!"); } }//class How do I get this frame to close so that my JOptionPane Message Dialogs can continue in the program without me exiting the program completely. EDIT: I tried .dispose() but I get this: cannot find symbol symbol : method dispose() location: class javax.swing.JPanel pane.dispose(); ^

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  • A Guide to Windows Hacking for Mac Users?

    - by Carlton Gibson
    I am a long-time Mac user looking to gain a decent understanding of Windows. I'm not really interested in the history except as it is still relevant to Windows 7. I'm competent with the Mac and UNIX/Linux environment. I'm live in C, Objective-C, Bash, Python, JavaScript, AppleScript and PHP. As such I want something that is introductory but not aimed at beginners. Can anyone recommend a decent book (or other resource) to get me started? TIA

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  • string maniupulations, oops, how do I replace parts of a string

    - by Joe Gibson
    I am very new to python. Could someone explain how I can manipulate a string like this? This function receives three inputs: complete_fmla: has a string with digits and symbols but has no hyphens ('-') nor spaces. partial_fmla: has a combination of hyphens and possibly some digits or symbols, where the digits and symbols that are in it (other than hyphens) are in the same position as in the complete_formula. symbol: one character The output that should be returned is: If the symbol is not in the complete formula, or if the symbol is already in the partial formula, the function should return the same formula as the input partial_formula. If the symbol is in the complete_formula and not in the partial formula, the function should return the partial_formula with the symbol substituting the hyphens in the positions where the symbol is, in all the occurrences of symbol in the complete_formula. For example: generate_next_fmla (‘abcdeeaa’, ‘- - - - - - - - ’, ‘d’) should return ‘- - - d - - - -’ generate_next_fmla (‘abcdeeaa’, ‘- - - d - - - - ’, ‘e’) should return ‘- - - d e e - -’ generate_next_fmla (‘abcdeeaa’, ‘- - - d e e - - ’, ‘a’) should return ‘a - - d e e a a’ Basically, I'm working with the definition: def generate_next_fmla (complete_fmla, partial_fmla, symbol): Do I turn them into lists? and then append? Also, should I find out the index number for the symbol in the complete_fmla so that I know where to append it in the string with hyphens??

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  • assistance required, hangman game.

    - by Phillip Gibson
    I am making a hangman game and am having trouble with part of it. I have selected a random word from a file, but I want to display the word as a series of undersocres __ and then match the letter chosen to a position in the undersocres. Can anyone help me? cout <<"1. Select to play the game\n"; cout <<"2. Ask for help\n"; cout <<"3. Select to quit the game\n"; cout << "Enter a selection: "; int number; cin >> number; while(number < 1 || number > 3 || cin.fail()) { if(cin.fail()) { cin.sync(); cin.clear(); cout << "You have not entered a number, please enter a menu selection between 1 and 3\n"; cin >> number; } else { cout << "Your selection must be between 1 and 3!\n"; cin >> number; } } switch (number) { case 1: { string word; string name; cout << " Whats your name? "; cin >> name; Player player(); ifstream FileReader; FileReader.open("words.txt"); if(!FileReader.is_open()) cout << "Error"; //this is for the random selection of words srand(time(0)); int randnum = rand()%10+1; for(int counter = 0; counter < randnum; counter++) { getline(FileReader, word, '\n'); } cout << "my word: " << word << "\n"; // get length of word int length; //create for loop for(int i = 0; i < length; i++) cout << "_"; //_ _ _ _ _ SetCursorPos(2,10); FileReader.close(); break;

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  • How to check if something is stored in CoreData

    - by Terrel Gibson
    Hi I want to be able to tore some information in core data and but i am unsure of how to check if the file was saved properly. I tried using NSLog but it returns null when its called. I have a dictionary which has a uniqueID and a title which I want to save. I pass this in along with the context of the database. I then sort the database to check if it has any duplicates or not, if not then I add the file. +(VacationPhoto*) photoWithFlickrInfo: (NSDictionary*) flickrInfo inManagedObjectContext: (NSManagedObjectContext*) context{ //returns the dictionary NSLog(@"Photo To Store =%@", flickrInfo); VacationPhoto * photo = nil; NSFetchRequest *request = [NSFetchRequest fetchRequestWithEntityName:@"VacationPhoto"]; request.predicate = [NSPredicate predicateWithFormat:@"uniqueID = %@", [flickrInfo objectForKey:FLICKR_PHOTO_ID]]; NSSortDescriptor * descriptor = [NSSortDescriptor sortDescriptorWithKey:@"title" ascending:YES]; request.sortDescriptors = [NSArray arrayWithObject:descriptor]; NSError *error = nil; NSArray *matches = [context executeFetchRequest:request error:&error]; if (!matches || [matches count] > 1) { // handle error } else if ( [matches count] == 0){ photo.title = [flickrInfo objectForKey:FLICKR_PHOTO_TITLE]; //Returns NULL when called NSLog(@"title = %@", photo.title); photo.uniqueID = [flickrInfo objectForKey:FLICKR_PHOTO_ID]; //Returns NULL when called NSLog(@"ID = %@", photo.uniqueID); } else { //If photo already exists this is called photo = [matches lastObject]; } return photo; }

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  • How do I secure a .NET Web Service for use by an iPhone application?

    - by David A Gibson
    Hello, The title says it all, I have a Web Service written in .NET that provides data for an iPhone application. It will also allow the application make a "reservation." Currently it's all internal to the corporate network but obviously when the iPhone application is published I will need ensure the Web Service is available externally. How would I go about securing the Web Service? There are two aspects I'm looking into: Authentication for accessing the web service Protection for the data being transferred I'm no so bothered about the data being passed back and forth as it will be viewable in the application anyway (which will be free). The key issue for me is preventing users from accessing the Web Service and making reservations themselves. At the moment I am considering encrypting any strings in the XML data passed back and forth so only the client can effectively use the web service sidestepping the need for authentication and providing protection for the data. This is the only model I have seen but I think the overheads on the iPhone and even for the web service make for a poor user experience. Any solutions at all would be most welcome? Thanks

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  • Arrays not matching correctly

    - by Nick Gibson
    userAnswer[] holds the string of the answer the user types in and is comparing it to answers[] to see if they match up and then spits out correct or wrong. j is equal to the question number. So if j was question 6, answers[j] should refer to answers[6] right? Then userAnswer[6] should compare to answers[6] and match if its correct. But its giving me wrong answers and displaying the answer I typed as correct. int abc, loopCount = 100; int j = quesNum, overValue, forLoop = 100; for (int loop = 1; loop < loopCount; loop++) { aa = r.nextInt(10+1); abc = (int) aa; String[] userAnswer = new String[x]; JOptionPane.showMessageDialog(null,abc); if(abc < x) { userAnswer[j] = JOptionPane.showInputDialog(null,"Question "+quesNum+"\n"+questions[abc]+"\n\nA: "+a[abc]+"\nB: "+b[abc]+"\nC: "+c[abc]+"\nD: "+d[abc]); if(userAnswer[j].equals(answers[j])) { JOptionPane.showMessageDialog(null,"Correct. \nThe Correct Answer is "+answers[abc]); } else { JOptionPane.showMessageDialog(null,"Wrong. \n The Correct Answer is "+answers[abc]); }//else }//if }//for

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  • ActionListener isn't Implementing

    - by Nick Gibson
    JFrameWithPanel is not abstract and does not override abstract method actionPerformed(java.awt.event.ActionEvent) in java.awt.event.ActionListener public class JFrameWithPanel extends JFrame implements ActionListener I Don't get this code. Book and Java site tells me this is the syntax for the method, but again this error shows up constantly. import javax.swing.*; import javax.swing.JOptionPane; import java.awt.*; import java.awt.event.*; import java.lang.Math.*; import java.lang.Integer.*; import java.util.*; import java.util.Random; import java.io.*; import java.text.*; import java.text.DecimalFormat.*; public class JFrameWithPanel extends JFrame implements ActionListener { JButton button = new JButton("Exit"); public JFrameWithPanel() { super("JFrame with Panel"); JComboBox packageChoice = new JComboBox(); packageChoice.addItem("A+ Certification"); packageChoice.addItem("Network+ Certification "); packageChoice.addItem("Security+ Certifictation"); packageChoice.addItem("CIT Full Test Package"); packageChoice.addActionListener(this); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); JPanel pane = new JPanel(); pane.add(button); pane.add(packageChoice); setContentPane(pane); setSize(200,100); setVisible(true); } } then later public class CreateJFrameWithPanel { public static void main(String[] args) { JFrameWithPanel panel = new JFrameWithPanel(); } }

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  • In the JSON spec, what does "Since the first two characters of a JSON text will always be ASCII characters" mean?

    - by dan gibson
    The spec is http://www.ietf.org/rfc/rfc4627.txt?number=4627 It contains this: Encoding JSON text SHALL be encoded in Unicode. The default encoding is UTF-8. Since the first two characters of a JSON text will always be ASCII characters [RFC0020], it is possible to determine whether an octet stream is UTF-8, UTF-16 (BE or LE), or UTF-32 (BE or LE) by looking at the pattern of nulls in the first four octets. What does it mean "Since the first two characters of a JSON text will always be ASCII characters [RFC0020]"? I've looked at RFC0020 but couldn't find anything about it. JSON could be {" or { " (ie whitespace before the quote.

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  • How do I automatically delete an Excel file after creating it on a server and returning it to the us

    - by David A Gibson
    Hello, I am creating an Excel file on a web server, using OleDb to connect the the physical (well as physical as it can be) file and appending records. I am then returning a FilePathResult to the user via MVC, and would like to delete the physical file afterwards due to data protection concerns over the appended records. I have tried using a File.Delete in a Finally clause but I get a File Not Found error which must mean the file has gone when MVC is trying to send the file to the user. I thought about creating the File as a MemoryStream but I think OleDb needs a physical file to connect to so this isn't an option. Any suggestions on how to delete the file after returning it in one operation? Thanks

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  • Arrays not counting correctly

    - by Nick Gibson
    I know I was just asking a question earlier facepalm This is in Java coding by the way. Well after everyones VERY VERY helpful advice (thank you guys alot) I managed to get over half of the program running how I wanted. Everything is pointing in the arrays where I want them to go. Now I just need to access the arrays so that It prints the correct information randomly. This is the current code that im using: http://pastebin.org/301483 The specific code giving me problems is this: long aa; int abc; for (int i = 0; i < x; i++) { aa = Math.round(Math.random()*10); String str = Long.toString(aa); abc = Integer.parseInt(str); String[] userAnswer = new String[x]; if(abc > x) { JOptionPane.showMessageDialog(null,"Number is too high. \nNumber Generator will reset."); break; } userAnswer[i] = JOptionPane.showInputDialog(null,"Question "+quesNum+"\n"+questions[abc]+"\n\nA: "+a[abc]+"\nB: "+b[abc]+"\nC: "+c[abc]+"\nD: "+d[abc]); answer = userAnswer[i].compareTo(answers[i]); if(answer == 0) { JOptionPane.showMessageDialog(null,"Correct. \nThe Correct Answer is "+answers[abc]+""+i); } else { JOptionPane.showMessageDialog(null,"Wrong. \n The Correct Answer is "+answers[abc]+""+i); }//else

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  • Unexpected return value

    - by Nicholas Gibson
    Program stopped compiling at this point: What is causing this error? (Error is at the bottom of post) public class JFrameWithPanel extends JFrame implements ActionListener, ItemListener { int packageIndex; double price; double[] prices = {49.99, 39.99, 34.99, 99.99}; DecimalFormat money = new DecimalFormat("$0.00"); JLabel priceLabel = new JLabel("Total Price: "+price); JButton button = new JButton("Check Price"); JComboBox packageChoice = new JComboBox(); JPanel pane = new JPanel(); TextField text = new TextField(5); JButton accept = new JButton("Accept"); JButton decline = new JButton("Decline"); JCheckBox serviceTerms = new JCheckBox("I Agree to the Terms of Service.", false); JTextArea termsOfService = new JTextArea("This is a text area", 5, 10); public JFrameWithPanel() { super("JFrame with Panel"); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); pane.add(packageChoice); setContentPane(pane); setSize(250,250); setVisible(true); packageChoice.addItem("A+ Certification"); packageChoice.addItem("Network+ Certification "); packageChoice.addItem("Security+ Certifictation"); packageChoice.addItem("CIT Full Test Package"); pane.add(button); button.addActionListener(this); pane.add(text); text.setEditable(false); text.setBackground(Color.WHITE); text.addActionListener(this); pane.add(termsOfService); termsOfService.setEditable(false); termsOfService.setBackground(Color.lightGray); pane.add(serviceTerms); serviceTerms.addItemListener(this); pane.add(accept); accept.addActionListener(this); pane.add(decline); decline.addActionListener(this); } public void actionPerformed(ActionEvent e) { packageIndex = packageChoice.getSelectedIndex(); price = prices[packageIndex]; text.setText("$"+price); Object source = e.getSource(); if(source == accept) { if(serviceTerms.isSelected() = false) // line 79 { JOptionPane.showMessageDialog(null,"Please accept the terms of service."); } else { JOptionPane.showMessageDialog(null,"Thanks."); } } } Error: \Desktop\Java Programming\JFrameWithPanel.java:79: unexpected type required: variable found : value if(serviceTerms.isSelected() = false) ^ 1 error

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  • Setting Frame.Content doesn't always work

    - by dan gibson
    I have a Frame control and I'm setting the Content property. If I set it twice, first to one control then to another, it shows the first control instead of the second. If I display a message box after setting it the first time then it works fine (ie it displays the second control). It's like I can only set Content once until the screen has been repainted. Calling Frame.UpdateLayout also doesn't help. What should I call after setting Content so that I can be sure that Content is actually set to what I specify?

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  • loop prematurely quitting

    - by Nick Gibson
    This loop works fine but prematurely quits at times. I set a piece of code in it so that I can view the random number. It only closes prematurely when the random number is equal to the highest numbered question the user inputs (Example...a user wants 10 questions, if the random number is 10 the program quits.) I have no idea why since i have it set to if(random number <= the number of questions) for ( int loop = 1; loop < loopCount; loop++ ) { aa = r.nextInt ( 10 + 1 ); abc = ( int ) aa; String[] userAnswer = new String[x]; JOptionPane.showMessageDialog ( null, abc ); if ( abc <= x ) { for ( overValue = 1; overValue < forLoop; overValue++ ); { userAnswer[j] = JOptionPane.showInputDialog ( null, "Question " + quesNum + "\n" + questions[abc] + "\n\nA: " + a[abc] + "\nB: " + b[abc] + "\nC: " + c[abc] + "\nD: " + d[abc] ); if ( userAnswer[j].equals ( answers[j] ) ) { JOptionPane.showMessageDialog ( null, "Correct. \nThe Correct Answer is " + answers[abc] ); } else { JOptionPane.showMessageDialog ( null, "Wrong. \n The Correct Answer is " + answers[abc] ); }//else }//for }//if }//for

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  • Array returning Null values

    - by Nick Gibson
    Dunno why it is...heres the coding for it. http://pastebin.org/301343 I know theres a lot of repetitiveness in the coding...but its because the arrays were retuning null so I got tired of messing with them. Everything works until it reaches line 224, which returns null values.

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  • Calculations coming out to 0.0?

    - by Nick Gibson
    A simple percentage calculation. It wont return a value except 0.0 and I think once or twice it returned 100.0%. Other than that it won't do a thing. I have tried playing with the code in several different ways and it just wont work. for (int loop = 1; loop < loopCount; loop++) { aa = r.nextInt(10+1); abc = (int) aa; String[] userAnswer = new String[x]; int totalQues = (correctAnswer + wrongAnswer), actualQues = (totalQues - 1); if(abc < x) { userAnswer[abc] = JOptionPane.showInputDialog(null,"Question "+quesNum+"\n\n"+questions[abc]+"\n\nA: "+a[abc]+"\nB: "+b[abc]+"\nC: "+c[abc]+"\nD: "+d[abc]+"\nCorrect Answers: "+correctAnswer+"\nWrong Answers: "+wrongAnswer+"\nTotal Questions: "+totalQues); if(userAnswer[abc].equals(answers[abc])) { correctAnswer++; } else { wrongAnswer++; }//else if(actualQues == x); { score = (correctAnswer / actualQues) * 100; JOptionPane.showMessageDialog(null,"The test is finished."); JOptionPane.showMessageDialog(null,"You scored "+score+"%"); }//if }//if }//for

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  • Namespace and class conflict(?)

    - by dan gibson
    This is a bad title for the question, but I'm not quite sure of a better one. I have a namespace called Globals with a class X in it. I also have a class called Globals. When I try to access Globals.X.StaticMember it tries to access the class Globals.X and complains that X doesn't exist. How do I reference the namespace Globals - ie ::Globals.X.StaticMember (:: doesn't compile).

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  • AWS Cloud Formation.Requires capabilities : [CAPABILITY_IAM] (Child Stack)

    - by Drew Khoury
    I'm running a CloudFormation template in the AWS Console. Running Stack Directly I started with a template that used IAM resources, and the console prompts me to acknowledge IAM capabilities when running the stack directly. Running Stack as a child I then tried to call the same stack from a parent stack and did not receive the same prompt. The stack then failed with the message: Requires capabilities : [CAPABILITY_IAM] Research The docs indicate that I can run CF scripts in a number of ways. There's plenty of docs around CLI/API and supplying the capability parameter, but there appears to be no information about how to make sure it's applied when running through the console. http://docs.aws.amazon.com/AWSCloudFormation/latest/UserGuide/using-iam-template.html IAM Resources in AWS CloudFormation Templates CF Console CLI API What I've done / What I think I've raised an issue via the forum for now, but no response (yet): https://forums.aws.amazon.com/thread.jspa?threadID=139160 I suspect this is a bug in the Console, as there doesn't appear to be any documentation of how to change the behaviour via the console and as far as I'm aware this should just work. Anyone came across the same problem, or can report that it's working fine for them?

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  • Heartbeat (Linux HA) and NetApp?

    - by Drew
    Does anyone have any experience setting up a high availability two node Linux cluster using heartbeat (linux-ha.org) and NetApp storage (preferably using SnapDrive for Linux)? Basically I would like to mount the same NetApp LUN over Fibre Channel to two servers in an Active/Passive mode (only one server can access the LUN at a time) Thanks!

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  • IBook G4 Charging Problems?

    - by Drew
    Hello, I am having some trouble with my iBook G4. It seems that whenever I plug it into the wall charger that it doesn't charge. It's not the charger's fault. There's a button on the back of it right next the battery, when I push it all five lights next to the button light up. I don't think where the charger is put in is broken. Any help? .

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