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  • MS SQL 2008, join or no join?

    - by Patrick
    Just a small question regarding joins. I have a table with around 30 fields and i was thinking about making a second table to store 10 of those fields. Then i would just join them in with the main data. The 10 fields that i was planning to store in a second table does not get queried directly, it's just some settings for the data in the first table. Something like: Table 1 Id Data1 Data2 Data3 etc ... Table 2 Id (same id as table one) Settings1 Settings2 Settings3 Is this a bad solution? Should i just use 1 table? How much performance inpact does it have? All entries in table 1 would also then have an entry in table 2. Small update is in order. Most of the Data fields are of the type varchar and 2 of them are of the type text. How is indexing treated? My plan is to index 2 data fields, email (varchar 50) and author (varchar 20). And yes, all records in Table 1 will have a record in Table 2. Most of the settings fields are of the bit type, around 80%. The rest is a mix between int and varchar. The varchars can be null.

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  • SQL Server 2008, join or no join?

    - by Patrick
    Just a small question regarding joins. I have a table with around 30 fields and i was thinking about making a second table to store 10 of those fields. Then i would just join them in with the main data. The 10 fields that i was planning to store in a second table does not get queried directly, it's just some settings for the data in the first table. Something like: Table 1 Id Data1 Data2 Data3 etc ... Table 2 Id (same id as table one) Settings1 Settings2 Settings3 Is this a bad solution? Should i just use 1 table? How much performance inpact does it have? All entries in table 1 would also then have an entry in table 2. Small update is in order. Most of the Data fields are of the type varchar and 2 of them are of the type text. How is indexing treated? My plan is to index 2 data fields, email (varchar 50) and author (varchar 20). And yes, all records in Table 1 will have a record in Table 2. Most of the settings fields are of the bit type, around 80%. The rest is a mix between int and varchar. The varchars can be null.

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  • How to create full-text catalog as default catalog?

    - by Bill Paetzke
    This would save me the redundant ON MyCatalog phrase when I create full-text indices. For example, CREATE FULLTEXT INDEX ON MyTable ( MyField1, MyField2, MyField3 ) KEY INDEX PK_MyKey ON MyCatalog WITH CHANGE_TRACKING AUTO With MyCatalog set as default catalog, I wouldn't have to specify ON MyCatalog every time I want to create a full-text index. So how can I make MyCatalog default on this database?

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  • How to get permission to create full-text index?

    - by Bill Paetzke
    I tried to create a full-text index and got this error: Msg 9967, Level 16, State 1, Line 1 A default full-text catalog does not exist in database 'foo' or user does not have permission to perform this action. FYI--I connected to the target sql server with Windows Authentication. What do I need to do in Sql Server 2005 and/or in Windows Server 2003 to get permissions? Please be thorough (assume I am a n00b). Thank you.

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  • How to Always Load Internet Explorer 9 in Full Screen Mode

    - by Lori Kaufman
    Internet Explorer 9 has a minimal interface by default, with the tab bar and the toolbar and address bar on the same line. However, you can gain even more viewable space by pressing F11 to go to full screen mode. If you like full screen mode and want to use it most of the time, you can have Internet Explorer open in that mode automatically, by editing a setting in the registry. To begin, enter “regedit” (without the quotes) in the Search box on the Start menu. When the results display, click regedit.exe or press Enter when it’s highlighted. NOTE: Before making changes to the registry, be sure you back it up. We also recommend creating a restore point you can use to restore your system if something goes wrong. HTG Explains: Learn How Websites Are Tracking You Online Here’s How to Download Windows 8 Release Preview Right Now HTG Explains: Why Linux Doesn’t Need Defragmenting

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  • Hibernate: Perform criteria query with Sub-Select AND Left-Outer join?

    - by Markos Fragkakis
    Can I perform a Criteria query with Sub-Select AND Left-Outer join? For example, I have A 1-many B 1-many C. With Criteria.createAlias ("b", "b", Criteria.LEFT_JOIN) I can perform Left Outer join. With Criteria.setFetchMode ("b", org.hibernate.FetchMode.DEFAULT) I can perform Join with the default fetching strategy. I assume that having set @org.hibernate.annotations.FetchMode.SUBSELECT in both A.B and B.C is enough (is it?). Question 1: Why does org.hibernate.FetchMode not have SUBSELECT option, whereas the org.hibernate.annotations.FetchMode does? Question 2: Can I perform a Criteria query with Sub-Select AND Left-Outer join?

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  • Basics of Join Factorization

    - by Hong Su
    We continue our series on optimizer transformations with a post that describes the Join Factorization transformation. The Join Factorization transformation was introduced in Oracle 11g Release 2 and applies to UNION ALL queries. Union all queries are commonly used in database applications, especially in data integration applications. In many scenarios the branches in a UNION All query share a common processing, i.e, refer to the same tables. In the current Oracle execution strategy, each branch of a UNION ALL query is evaluated independently, which leads to repetitive processing, including data access and join. The join factorization transformation offers an opportunity to share the common computations across the UNION ALL branches. Currently, join factorization only factorizes common references to base tables only, i.e, not views. Consider a simple example of query Q1. Q1:    select t1.c1, t2.c2    from t1, t2, t3    where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c2 = 2 and t2.c2 = t3.c2   union all    select t1.c1, t2.c2    from t1, t2, t4    where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c3 = t4.c3; Table t1 appears in both the branches. As does the filter predicates on t1 (t1.c1 > 1) and the join predicates involving t1 (t1.c1 = t2.c1). Nevertheless, without any transformation, the scan (and the filtering) on t1 has to be done twice, once per branch. Such a query may benefit from join factorization which can transform Q1 into Q2 as follows: Q2:    select t1.c1, VW_JF_1.item_2    from t1, (select t2.c1 item_1, t2.c2 item_2                   from t2, t3                    where t2.c2 = t3.c2 and t2.c2 = 2                                  union all                   select t2.c1 item_1, t2.c2 item_2                   from t2, t4                    where t2.c3 = t4.c3) VW_JF_1    where t1.c1 = VW_JF_1.item_1 and t1.c1 > 1; In Q2, t1 is "factorized" and thus the table scan and the filtering on t1 is done only once (it's shared). If t1 is large, then avoiding one extra scan of t1 can lead to a huge performance improvement. Another benefit of join factorization is that it can open up more join orders. Let's look at query Q3. Q3:    select *    from t5, (select t1.c1, t2.c2                  from t1, t2, t3                  where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c2 = 2 and t2.c2 = t3.c2                 union all                  select t1.c1, t2.c2                  from t1, t2, t4                  where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c3 = t4.c3) V;   where t5.c1 = V.c1 In Q3, view V is same as Q1. Before join factorization, t1, t2 and t3 must be joined first before they can be joined with t5. But if join factorization factorizes t1 from view V, t1 can then be joined with t5. This opens up new join orders. That being said, join factorization imposes certain join orders. For example, in Q2, t2 and t3 appear in the first branch of the UNION ALL query in view VW_JF_1. T2 must be joined with t3 before it can be joined with t1 which is outside of the VW_JF_1 view. The imposed join order may not necessarily be the best join order. For this reason, join factorization is performed under cost-based transformation framework; this means that we cost the plans with and without join factorization and choose the cheapest plan. Note that if the branches in UNION ALL have DISTINCT clauses, join factorization is not valid. For example, Q4 is NOT semantically equivalent to Q5.   Q4:     select distinct t1.*      from t1, t2      where t1.c1 = t2.c1  union all      select distinct t1.*      from t1, t2      where t1.c1 = t2.c1 Q5:    select distinct t1.*     from t1, (select t2.c1 item_1                   from t2                union all                   select t2.c1 item_1                  from t2) VW_JF_1     where t1.c1 = VW_JF_1.item_1 Q4 might return more rows than Q5. Q5's results are guaranteed to be duplicate free because of the DISTINCT key word at the top level while Q4's results might contain duplicates.   The examples given so far involve inner joins only. Join factorization is also supported in outer join, anti join and semi join. But only the right tables of outer join, anti join and semi joins can be factorized. It is not semantically correct to factorize the left table of outer join, anti join or semi join. For example, Q6 is NOT semantically equivalent to Q7. Q6:     select t1.c1, t2.c2    from t1, t2    where t1.c1 = t2.c1(+) and t2.c2 (+) = 2  union all    select t1.c1, t2.c2    from t1, t2      where t1.c1 = t2.c1(+) and t2.c2 (+) = 3 Q7:     select t1.c1, VW_JF_1.item_2    from t1, (select t2.c1 item_1, t2.c2 item_2                  from t2                  where t2.c2 = 2                union all                  select t2.c1 item_1, t2.c2 item_2                  from t2                                                                                                    where t2.c2 = 3) VW_JF_1       where t1.c1 = VW_JF_1.item_1(+)                                                                  However, the right side of an outer join can be factorized. For example, join factorization can transform Q8 to Q9 by factorizing t2, which is the right table of an outer join. Q8:    select t1.c2, t2.c2    from t1, t2      where t1.c1 = t2.c1 (+) and t1.c1 = 1 union all    select t1.c2, t2.c2    from t1, t2    where t1.c1 = t2.c1(+) and t1.c1 = 2 Q9:   select VW_JF_1.item_2, t2.c2   from t2,             (select t1.c1 item_1, t1.c2 item_2            from t1            where t1.c1 = 1           union all            select t1.c1 item_1, t1.c2 item_2            from t1            where t1.c1 = 2) VW_JF_1   where VW_JF_1.item_1 = t2.c1(+) All of the examples in this blog show factorizing a single table from two branches. This is just for ease of illustration. Join factorization can factorize multiple tables and from more than two UNION ALL branches.  SummaryJoin factorization is a cost-based transformation. It can factorize common computations from branches in a UNION ALL query which can lead to huge performance improvement. 

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  • Lubuntu Full Install on USB Drive with Full Disk Encryption and Grub2

    - by vivi
    I apologise for the wall of text, but I want you to scrutinize my thought-process to make sure there's no mistakes and no other way around it: I wish to have a full install of lubuntu with full disk encryption on one of my usb drives. The laptop I would be booting it from also has windows 7. I want to maintain that OS. From what I've read I must place grub2 on the usb drive so that: If I have the usb plugged in, the laptop would start lubuntu (having USB HD in the BIOS Boot options) If I don't have the usb plugged in, it would normally start windows 7. That's exactly what I want it to do. But: If I install from the normal .iso: Clicking "install lubuntu alongside them" would install it onto my normal HD. Clicking "Erase disk and install lunbuntu" would delete all the stuff I have in my HD and install lubuntu on it. Clicking "Something else" would allow me to choose to install lunbuntu and grub2 onto the usb drive, but would not provide it with encryption. So the normal .iso won't work for what I want. Then I found the alternate .iso and this tutorial: It allows me to install lubuntu with all the options I want and gives me the option to choose where to place the grub2! Hopefully there are no flaws in my train of thought. If there aren't, I have a few questions regarding that tutorial: The author says in his case choosing "Yes to install GRUB to your MBR" installed the grub to the usb drive's mbr. I can't have "in his case". I need to be sure that's what it will do, so that it doesn't mess up the windows boot loader. Choosing "no" would open this window and allow to choose where I want to install the grub. Unfortunately I don't understand which option I should type in the box to install it into the usb drive. Would removing my laptop's Hard Drive ensure that the grub is installed onto the usb drive if i picked first option, "yes"? I apologise once again for the wall of text and appreciate any help you guys can offer me.

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  • Linq to Entities and LEFT OUTER JOIN issue with MANY:1 relations

    - by Robert Koritnik
    Can somebody tell me, why does Linq to Entities translate many to 1 relationships to left outer join instead of inner join? Because there's referential constraint on DB itself that ensures there's a record in the right table, so inner join should be used instead (and it would work much faster) If relation was many to 0..1 left outer join would be correct. Question Is it possible to write LINQ in a way so it will translate to inner join rather than left outer join. It would speed query execution a lot... I haven't used eSQL before, but would it be wise to use it in instead of LINQ? Edit I updated my tags to include technology I'm using in the background: Entity Framework V1 Devart dotConnect for Mysql MySql database If someone could test if the same is true on Microsoft SQL server it would also give me some insight if this is Devart's issue or it's a general L2EF functionality... But I suspect EF is the culprit here.

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  • Performing Inner Join for Multiple Columns in the Same Table

    - by frankiefrank
    I have a scenario which I'm a bit stuck on. Let's say I have a survey about colors, and I have one table for the color data, and another for people's answers. tbColors color_code , color_name 1 , 'blue' 2 , 'green' 3 , 'yellow' 4 , 'red' tbAnswers answer_id , favorite_color , least_favorite_color , color_im_allergic_to 1 , 1 , 2 3 2 , 3 , 1 4 3 , 1 , 1 2 4 , 2 , 3 4 For display I want to write a SELECT that presents the answers table but using the color_name column from tbColors. I understand the "most stupid" way to do it naming tbColors three times in the FROM section, using a different alias for each column to replace. How would a non-stupid way look?

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  • Entity framework support for table valued functions and thus full text

    - by simonsabin
    One of my most popular posts with over 10, 000 hits is how to enable full text when using LINQ to SQL http://sqlblogcasts.com/blogs/simons/archive/2008/12/18/LINQ-to-SQL---Enabling-Fulltext-searching.aspx , core to this is the use of a table valued function. I’m therefore interested to see that Entity Framework will support table valued functions in the next release for more details have a read of the efdesign blog http://blogs.msdn.com/b/efdesign/archive/2011/01/21/table-valued-function-support...(read more)

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  • Can MySQL / SQL's short hand of "Using" be used without saying "Inner Join" ?

    - by Jian Lin
    The following 2 statements are to join using gifts.giftID = sentgifts.giftID: mysql> select * from gifts, sentgifts using (giftID); ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'using (giftID)' at line 1 and the second one: mysql> select * from gifts INNER JOIN sentgifts using (giftID); +--------+------------+----------------+---------------------+--------+------------+--------+------+---------------------+ | giftID | name | filename | effectiveTime | sentID | whenSent | fromID | toID | trytryWhen | +--------+------------+----------------+---------------------+--------+------------+--------+------+---------------------+ | 2 | teddy bear | bear.jpg | 2010-04-24 04:36:03 | 4 | 2010-04-24 | NULL | 111 | 2010-04-24 03:10:42 | | 6 | beer | beer_glass.png | 2010-04-24 05:18:12 | 5 | 2010-03-03 | 11 | 22 | 2010-03-03 00:00:00 | | 6 | beer | beer_glass.png | 2010-04-24 05:18:12 | 6 | 2010-04-24 | 11 | 222 | 2010-04-24 03:54:49 | | 6 | beer | beer_glass.png | 2010-04-24 05:18:12 | 7 | 2010-04-24 | 1 | 2 | 2010-04-24 03:58:45 | +--------+------------+----------------+---------------------+--------+------------+--------+------+---------------------+ 4 rows in set (0.00 sec) Can the first statement also use the "using" shorthand? It seems that when it is used then the word "Inner Join" must be specified... but the first statement is actually an inner join?

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  • INNER JOIN vs LEFT JOIN performance in SQL Server

    - by Ekkapop
    I've created SQL command that use INNER JOIN for 9 tables, anyway this command take a very long time (more than five minutes). So my folk suggest me to change INNER JOIN to LEFT JOIN because the performance of LEFT JOIN is better, at first time its despite what I know. After I changed, the speed of query is significantly improve. I want to know why LEFT JOIN is faster than INNER JOIN? My SQL command look like below: SELECT * FROM A INNER JOIN B ON ... INNER JOIN C ON ... INNER JOIN D and so no

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  • How sql server evaluates the multiple different joins?

    - by ziang
    Hi, i have a general question about how sql server evaluates the joins.The query is SELECT * FROM TableA INNER JOIN TableB ON TableB.id = TableA.id LEFT JOIN TABLEC ON TABLEC.id = TABLEB.id Q1: What tables is the left join based on? I know it will based on the TABLEC but what is the other one? Is it the result of the first inner join or the TABLEB specified in the left join condition? Q2: Is "LEFT JOIN TABLEC ON TABLEC.id = TABLEB.id" equivalent to "LEFT JOIN TABLEC ON TABLEB.id = TABLEC.id" Q3: Is the query equivalent to the following one? (with TABLEB.id replaced by TABLEA.id?) SELECT * FROM TableA INNER JOIN TableB ON TableB.id = TableA.id LEFT JOIN TABLEC ON TABLEC.id = TABLEA.id Thank you!

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  • How to get full query string parameters not UrlDecoded

    - by developerit
    Introduction While developing Developer IT’s website, we came across a problem when the user search keywords containing special character like the plus ‘+’ char. We found it while looking for C++ in our search engine. The request parameter output in ASP.NET was “c “. I found it strange that it removed the ‘++’ and replaced it with a space… Analysis After a bit of Googling and Reflection, it turns out that ASP.NET calls UrlDecode on each parameters retreived by the Request(“item”) method. The Request.Params property is affected by this two since it mashes all QueryString, Forms and other collections into a single one. Workaround Finally, I solve the puzzle usign the Request.RawUrl property and parsing it with the same RegEx I use in my url re-writter. The RawUrl not affected by anything. As its name say it, it’s raw. Published on http://www.developerit.com/

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  • Problems with NVIDIA drivers: White screen with full(or almost full)screen apps

    - by Felipe
    My NVIDIA graphic card is a 7050/610i. My problem is that after upgrading to the last NVIDIA drivers when I use fullscreen apps (or almost fullscreen) the windows goes white. My xorg.conf file: # nvidia-xconfig: X configuration file generated by nvidia-xconfig # nvidia-xconfig: version 270.29 ([email protected]) Wed Feb 23 16:38:34 PST 2011 Section "Monitor" Identifier "Monitor0" VendorName "Unknown" ModelName "Unknown" HorizSync 28.0 - 33.0 VertRefresh 43.0 - 72.0 Option "DPMS" EndSection Section "Screen" Identifier "Screen0" Device "Device0" Monitor "Monitor0" Option "AddARGBGLXVisuals" "True" DefaultDepth 24 SubSection "Display" Depth 24 EndSubSection EndSection Section "Module" Load "glx" EndSection Section "InputDevice" Identifier "Mouse0" Driver "mouse" Option "Protocol" "auto" Option "Device" "/dev/psaux" Option "Emulate3Buttons" "no" Option "ZAxisMapping" "4 5" EndSection Section "InputDevice" Identifier "Keyboard0" Driver "kbd" # generated from default EndSection Section "ServerLayout" Identifier "Layout0" Screen 0 "Screen0" 0 0 InputDevice "Keyboard0" "CoreKeyboard" InputDevice "Mouse0" "CorePointer" EndSection Section "Device" Identifier "Device0" VendorName "NVIDIA Corporation" Driver "nvidia" Option "NoLogo" "True" EndSection Any idea on how to solve this? <--Sorry for bad english, ask for more info--

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  • Javascript Open a Window Full Size (Mazimized)

    - by SAMIR BHOGAYTA
    function f_open_window_max( aURL, aWinName ) { var wOpen; var sOptions; sOptions = 'status=yes,menubar=yes,scrollbars=yes,resizable=yes,toolbar=yes'; sOptions = sOptions + ',width=' + (screen.availWidth - 10).toString(); sOptions = sOptions + ',height=' + (screen.availHeight - 122).toString(); sOptions = sOptions + ',screenX=0,screenY=0,left=0,top=0'; wOpen = window.open( '', aWinName, sOptions ); wOpen.location = aURL; wOpen.focus(); wOpen.moveTo( 0, 0 ); wOpen.resizeTo( screen.availWidth, screen.availHeight ); return wOpen; }

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  • 3 SQL Join Concepts to Help You Choose the Right Join

    What do SQL joins and the "teach a man to fish" Chinese proverb have in common? SQL joins, like regular expressions, are one of those commonplace programming tasks in which true success is entirely dependent upon your ability to conceptualize the outcome. Fail to do so and you'll likely wind up spending a few hours in a frustrating round of trial and error. Like regular expressions, the proliferation of online examples has actually contributed to the frustration, providing the equivalent of a day's worth of fish rather than the proverbial fishing pool. The Future of SQL Server MonitoringMonitor wherever, whenever with Red Gate's SQL Monitor. See it live in action now.

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  • Duplicate Items Using Join in NHibernate Map

    - by Colin Bowern
    I am trying to retrieve the individual detail rows without having to create an object for the parent. I have a map which joins a parent table with the detail to achieve this: Table("UdfTemplate"); Id(x => x.Id, "Template_Id"); Map(x => x.FieldCode, "Field_Code"); Map(x => x.ClientId, "Client_Id"); Join("UdfFields", join => { join.KeyColumn("Template_Id"); join.Map(x => x.Name, "COLUMN_NAME"); join.Map(x => x.Label, "DISPLAY_NAME"); join.Map(x => x.IsRequired, "MANDATORY_FLAG") .CustomType<YesNoType>(); join.Map(x => x.MaxLength, "DATA_LENGTH"); join.Map(x => x.Scale, "DATA_SCALE"); join.Map(x => x.Precision, "DATA_PRECISION"); join.Map(x => x.MinValue, "MIN_VALUE"); join.Map(x => x.MaxValue, "MAX_VALUE"); }); When I run the query in NH using: Session.CreateCriteria(typeof(UserDefinedField)) .Add(Restrictions.Eq("FieldCode", code)).List<UserDefinedField>(); I get back the first row three times as opposed to the three individual rows it should return. Looking at the SQL trace in NH Profiler the query appears to be correct. The problem feels like it is in the mapping but I am unsure how to troubleshoot that process. I am about to turn on logging to see what I can find but I thought I would post here in case someone with experience mapping joins knows where I am going wrong.

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  • Would shell command join cause out of memory?

    - by Hancy
    I have two file to join. FILE 1: a A1 a A2 a A3 ... c C1 c C2 ... FILE 2: a feature1_of_a a feature2_of_a ... a featureN_of_a ... ... c feature1_of_c c feature2_of_c ... after join, i could get File like this: A1 feature1_of_a A2 feature1_of_a A3 feature1_of_a A1 feature2_of_a A2 feature2_of_a A3 feature2_of_a ... A1 featureN_of_a A2 featureN_of_a A3 featureN_of_a ... In order to do that: i wrote shell command join -11 -21 -o1.2,2.2 file1 file2. But the problem is: number N might be huge. So if join read all feautre of a into memory at once, memory might not be enough. I don't know how join is implemented. WQould the momery become a problem? If so, is there any way to get what I want?

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  • Left outer join null using VB.NET and LINQ

    - by jvcoach23
    I've got what I think is a working left outer join LINQ query, but I'm having problems with the select because of null values in the right hand side of the join. Here is what I have so far Dim Os = From e In oExcel Group Join c In oClassIndexS On c.tClassCode Equals Mid(e.ClassCode, 1, 4) Into right1 = Group _ From c In right1.DefaultIfEmpty I want to return all of e and one column from c called tClassCode. I was wondering what the syntax would be. As you can see, I'm using VB.NET. Update... Here is the query doing join where I get the error: _message = "Object reference not set to an instance of an object." Dim Os = From e In oExcel Group Join c In oClassIndexS On c.tClassCode Equals Mid(e.ClassCode, 1, 4) Into right1 = Group _ From c In right1.DefaultIfEmpty Select e, c.tClassCode If I remove the c.tClassCode from the select, the query runs without error. So I thought perhaps I needed to do a select new, but I don't think I was doing that correctly either.

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  • SQL SERVER – Challenge – Puzzle – Why does RIGHT JOIN Exists

    - by pinaldave
    I had interesting conversation with the attendees of the my SQL Server Performance Tuning course. I was asked if LEFT JOIN can do the same task as RIGHT JOIN by reserving the order of the tables in join, why does RIGHT JOIN exists? The definitions are as following: Left Join – select all the records from the LEFT table and then pick up any matching records from the RIGHT table   Right Join – select all the records from the RIGHT table and then pick up any matching records from the LEFT table Most of us read from LEFT to RIGHT so we are using LEFT join. Do you have any explaination why RIGHT JOIN exists or can you come up with example, where RIGHT JOIN is absolutely required and the task can not be achieved with LEFT JOIN. Other Puzzles: SQL SERVER – Puzzle – Challenge – Error While Converting Money to Decimal SQL SERVER – Challenge – Puzzle – Usage of FAST Hint Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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