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  • Best practice -- Content Tracking Remote Data (cURL, file_get_contents, cron, et. al)?

    - by user322787
    I am attempting to build a script that will log data that changes every 1 second. The initial thought was "Just run a php file that does a cURL every second from cron" -- but I have a very strong feeling that this isn't the right way to go about it. Here are my specifications: There are currently 10 sites I need to gather data from and log to a database -- this number will invariably increase over time, so the solution needs to be scalable. Each site has data that it spits out to a URL every second, but only keeps 10 lines on the page, and they can sometimes spit out up to 10 lines each time, so I need to pick up that data every second to ensure I get all the data. As I will also be writing this data to my own DB, there's going to be I/O every second of every day for a considerably long time. Barring magic, what is the most efficient way to achieve this? it might help to know that the data that I am getting every second is very small, under 500bytes.

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  • In FLEX, How can you stop ENTER Key from my Alert being caught by the control that initiated the Al

    - by WeeJavaDude
    I am having an issue where I show an AlertBox message when the user hits ENTER and the focus is in a text area. The pop up works fine, but when the user hits enter the Alert closes as expected, but the TextArea listener receives the ENTER event from the Alert and pops the dialog up again. I have tried a number of ways to catch and eat the event but so far I have not been lucky. Is there way to accomplish this? public function init():void { myTextInput.addEventListener(KeyboardEvent.KEY_UP, handleKeyStrokes); } public function handleKeyStrokes(evt:KeyboardEvent):void { if(evt.keyCode == Keyboard.ENTER) { myAlert = Alert.show("This is a test and only a test", "Title", 4, null, alertCallBack); } } <mx:TextInput id="myTextInput" left="600" top="10"> </mx:TextInput>

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  • TOSM e WPC

    - by Valter Minute
    Per chi ha tempo e voglia di fare quattro chiacchiere sui sistemi embedded microsoft, il sottoscritto parteciperà al TOSM, dal 16 al 18 Novembre a Torino e, in qualità di speaker, a WPC 2011, il principale evento formativo Italiano per le tecnologie Microsoft dal 22 al 24 Novembre a Milano (Assago). Saranno due occasioni per presentare queste tecnologie a un’audience un po’ diversa da quella che di solito frequenta gli eventi embedded e per scambiare idee e opinioni con chi non lavora sui sistemi embedded ma, magari, pensa di poterli utilizzare in futuro.

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  • Assembly load and execute issue

    - by Jean Carlos Suárez Marranzini
    I'm trying to develop Assembly code allowing me to load and execute(by input of the user) 2 other Assembly .EXE programs. I'm having two problems: -I don't seem to be able to assign the pathname to a valid register(Or maybe incorrect syntax) -I need to be able to execute the other program after the first one (could be either) started its execution. This is what I have so far: mov ax,cs ; moving code segment to data segment mov ds,ax mov ah,1h ; here I read from keyboard int 21h mov dl,al cmp al,'1' ; if 1 jump to LOADRUN1 JE LOADRUN1 popf cmp al,'2' ; if 1 jump to LOADRUN2 JE LOADRUN2 popf LOADRUN1: MOV AH,4BH MOV AL,00 LEA DX,[PROGNAME1] ; Not sure if it works INT 21H LOADRUN2: MOV AH,4BH MOV AL,00 LEA DX,[PROGNAME2] ; Not sure if it works INT 21H ; Here I define the bytes containing the pathnames PROGNAME1 db 'C:\Users\Usuario\NASM\Adding.exe',0 PROGNAME2 db 'C:\Users\Usuario\NASM\Substracting.exe',0 I just don't know how start another program by input in the 'parent' program, after one is already executing. Thanks in advance for your help! Any additional information I'll be more than happy to provide. -I'm using NASM 16 bits, Windows 7 32 bits.

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  • How To Watch Indian Union Budget 2011-2012 Live On Your PC

    - by Gopinath
    The Union Budget of India 2011-2012 will be tabled on Lok Sabha on 26th Feb, 2011. The finance minister, Mr. Pranab Muhkerjee will present the budget in the house and it will be broadcasted live on the TV channels(DD, NDTV, IBN Live and others) as well as on the web. For those who are willing to watch the budget session live on computers here is the required information. National Informatics Centre – Budget 2011 Live Web Cast Indian Government official stream of Union Budget 2011-2011 is available  at  http://budgetlive.nic.in/. This live stream will provide the budget information as is, without any masala, hype or so called analysis by experts sitting in private TV channel studios (and talking rubbish!) To view the primary live stream you need to install Windows Media Player plugin on your browser. As it’s a government website, better you use Internet Explorer browser to watch it. It may not work on Firefox or Chrome. Also the live stream is provided in other formats like Real Media and Flash. Here are the various streaming formats for you to choose Flash Player – High Bandwidth Stream Windows Media Player – Low Bandwidth Stream (IE browser is preferred) Windows Media Player – High Bandwidth Stream  (IE browser is preferred) Real Media Player – Low Bandwidth Stream Real Media Player – High Bandwidth Stream Indian Media Channels Covering Live Of Union Budget 2011 – 2012 Most of the news media channels live stream are available for free on the web, here are the few new channels you can watch live to follow Union Budget 2011 – 2012. NDTV 24 x 7 News Live Stream (English) NDTV India Live Streaming (Hindi) CNBC TV 18 Live Streaming (English) CNN IBN Live Streaming (English) IBN 7 Live Streaming (Hindi) Caution: In the name of analysis, most of the media channels mislead the viewers and provide base less information at times. Take utmost care in absorbing the information you see in any of the Indian news channel. This article titled,How To Watch Indian Union Budget 2011-2012 Live On Your PC, was originally published at Tech Dreams. Grab our rss feed or fan us on Facebook to get updates from us.

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  • Mostrar Imagenes en ListView utilizando ImageList WinForms

    - by Jason Ulloa
    El día de hoy veremos como trabajar con los controles ListView e Imagelist de WindowsForms para poder leer y mostrar una serie de imágenes. Antes de ello debo decir que pueden existir otras formas de mostrar imagenes que solo requieren un control por ejemplo con un Gridview pero eso será en otro post, ahora nos centraremos en la forma de realizarlo con los controles antes mencionados. Lo primero que haremos será crear un nuevo proyecto de windows forms, en mi caso utilizando C#, luego agregaremos un Control ImageList. Este control será el que utilicemos para almacenar todas las imágenes una vez que las hemos leído. Si revisamos el control, veremos que tenemos la opción de agregar la imágenes mediante el diseñador, es decir podemos seleccionarlas manualmente o bien agregarlas mediante código que será lo que haremos. Lo segundo será agregar un control ListView al Formulario, este será el encargado de mostrar las imagenes, eso sí, por ahora será solo mostrarlas no tendrá otras funcionalidades. Ahora, vamos al codeBehind y en el Evento Load del form empezaremos a codificar: Lo primero será, crear una nueva variable derivando DirectoryInfo, a la cual le indicaremos la ruta de nuestra carpeta de imágenes. En nuestro ejemplo utilizamos Application.StartUpPath para indicarle que vamos a buscar en nuestro mismo proyecto (en carpeta debug por el momento). DirectoryInfo dir = new DirectoryInfo(Application.StartupPath + @"\images");   Una vez que hemos creado la referencia a la ruta, utilizaremos un for para obtener todas la imágenes que se encuentren dentro del Folder que indicamos, para luego agregarlas al imagelist y empezar a crear nuestra nueva colección. foreach (FileInfo file in dir.GetFiles()) { try { this.imageList1.Images.Add(Image.FromFile(file.FullName)); }   catch { Console.WriteLine("No es un archivo de imagen"); } }   Una vez, que hemos llenado nuestro ImageList, entonces asignaremos al ListView sus propiedades, para definir la forma en que las imágenes se mostrarán. Un aspecto a tomar en cuenta acá será la propiedad ImageSize ya que está será la que definirá el tamaño que tendrán las imágenes en el ListView cuando sean mostradas. this.listView1.View = View.LargeIcon;   this.imageList1.ImageSize = new Size(120, 100);   this.listView1.LargeImageList = this.imageList1;   Por último y con ayuda de otro for vamos a recorrer cada uno de los elementos que ahora posee nuestro ImageList y lo agregaremos al ListView para mostrarlo for (int j = 0; j < this.imageList1.Images.Count; j++) { ListViewItem item = new ListViewItem();   item.ImageIndex = j;   this.listView1.Items.Add(item); } Como vemos, a pesar de que utilizamos dos controles distintos es realmente sencillo  mostrar la imagenes en el ListView al final el control ImageList, solo funciona como un “puente” que nos permite leer la imagenes para luego mostrarlas en otro control. Para terminar, los proyectos de ejemplo: C# VB

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  • Screen problems

    - by Erick
    I struggled a lot in order to install Ubuntu because of a problem with the video drivers caused by when installing the driver and after turning it on it just appears a black screen, which worked for me was to use the terminal with sudo setpci -s 00:02.0 F4.B=0 and the screen starts, but after rebooting the changes won't remain and I have to run that command again. My question is: How can I make the changes permanent and not to be in need to execute that command always when I shut it down? Original Question in Spanish: Problemas con pantalla He batallado mucho al instalar ubuntu por el problema con el controlador de video ya que al instalarlo al encenderla aparece solo una pantalla negra lo que me funciono fue usar desde consola sudo setpci -s 00:02.0 F4.B=0 enciende la pantalla pero al reiniciarla los cambios no se quedan guardados y tengo que volver a ejecutar ese comando mi pregunta es ¿como hacerle para que los cambios queden igual y no tener que estar ejecutando eso siempre que la apago?

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  • Why to avoid SELECT * from tables in your Views

    - by Jeff Smith
    -- clean up any messes left over from before: if OBJECT_ID('AllTeams') is not null  drop view AllTeams go if OBJECT_ID('Teams') is not null  drop table Teams go -- sample table: create table Teams (  id int primary key,  City varchar(20),  TeamName varchar(20) ) go -- sample data: insert into Teams (id, City, TeamName ) select 1,'Boston','Red Sox' union all select 2,'New York','Yankees' go create view AllTeams as  select * from Teams go select * from AllTeams --Results: -- --id          City                 TeamName ------------- -------------------- -------------------- --1           Boston               Red Sox --2           New York             Yankees -- Now, add a new column to the Teams table: alter table Teams add League varchar(10) go -- put some data in there: update Teams set League='AL' -- run it again select * from AllTeams --Results: -- --id          City                 TeamName ------------- -------------------- -------------------- --1           Boston               Red Sox --2           New York             Yankees -- Notice that League is not displayed! -- Here's an even worse scenario, when the table gets altered in ways beyond adding columns: drop table Teams go -- recreate table putting the League column before the City: -- (i.e., simulate re-ordering and/or inserting a column) create table Teams (  id int primary key,  League varchar(10),  City varchar(20),  TeamName varchar(20) ) go -- put in some data: insert into Teams (id,League,City,TeamName) select 1,'AL','Boston','Red Sox' union all select 2,'AL','New York','Yankees' -- Now, Select again for our view: select * from AllTeams --Results: -- --id          City       TeamName ------------- ---------- -------------------- --1           AL         Boston --2           AL         New York -- The column labeled "City" in the View is actually the League, and the column labelled TeamName is actually the City! go -- clean up: drop view AllTeams drop table Teams

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  • SQL Error: ORA-00936: missing expression

    - by user2901548
    Qns: Item Description and the treatment date of all treatments for any patients named Jessie Stange (ie GivenName is Jessie & FamilyName is Stange) What i wrote: SELECT DISTINCT Description, Date as treatmentDate WHERE doothey.Patient P, doothey.Account A, doothey.AccountLine AL, doothey.Item.I AND P.PatientID = A.PatientID AND A.AccountNo = AL.AccountNo AND AL.ItemNo = I.ItemNo AND (p.FamilyName = 'Stange' AND p.GivenName = 'Jessie'); error: Error at Command Line:1 Column:30 Error report: SQL Error: ORA-00936: missing expression 00936. 00000 - "missing expression" *Cause: *Action: What is the missing expression???

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  • Looking for VPS Hosting for a LAMP Web Application

    - by Ali
    Hi guys, Trying to find a Managed VPS Hosting Solution for a LAMP Web Application. The more CPU, RAM, and Disk space the better Don't need a huge amount of bandwidth for now Would like to be able to easily grow into a stronger server Have really responsive, dedicated, smart support staff -- our current hosting is just terrible My main problem is that I can't even find a non-biased website out there that does a proper comparison of VPS Hosting providers. Can anybody either suggest a reviews/ranking site or a hosting with proven record? How would you go about finding the best hosting service? Thanks a lot! Ali

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  • How can I create blog post functionality without Wordpress or Drupal?

    - by Ali
    I'm currently learning Python (as a beginner in programming). I go through each chapter learning basics. I haven't gotten far enough to understand how CMS works. I eventually want a blog that doesn't depend on Wordpress or Drupal. I would like to develop it myself as my skills progress. My immediate curiosity is on blog posts. What is the component called that will allow me to make a daily post on my blog? There must be a technical term for this function. I would like to learn how to make one, but don't even know what to research. Everything I research points me to Wordpress or Drupal. I would like to create my own. Thanks in advance! Ali

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  • How to force GNOME panels et. al. to display on a different monitor without mirroring?

    - by GrueKun
    So, I recently purchased a new 23" monitor for my PC. However, I can't use it with the PC currently as I am waiting on a replacement heatsink. In the mean time, I wanted to use it with my Dell laptop. I hooked it up to the VGA port, and it seems to be working properly. However, I wanted to know if there was a way I could move all of the main display elements over to the attached monitor? I wanted to shut the LCD panel off on the laptop and hook it up like a desktop. Relevant specs: Ubuntu 10.10 x64 Intel graphics chipset The attached monitor is currently set as the default monitor. Any suggestions are welcome. :)

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  • Change an array's value in x86 assembly (embedded in C++)

    - by VV
    I am messing around with assembly for the first time, and can't seem to change the index values of an array. Here's the method I am working on int ascending_sort( char arrayOfLetters[], int arraySize ) { char temp; __asm { //??? } } And these are what I tried mov temp, 'X' mov al, temp mov arrayOfLetters[0], al And this gave me an error C2415: improper operand type so I tried mov temp, 'X' mov al, temp mov BYTE PTR arrayOfLetters[0], al This complied, but it didn't change the array...

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  • [Assembly] jnz after xor?

    - by kotarou3
    After using IDA Pro to disassemble a x86 dll, I found this code (Comments added by me in pusedo-c code. I hope they're correct): test ebx, ebx ; if (ebx == false) jz short loc_6385A34B ; Jump to 0x6385a34b mov eax, [ebx+84h] ; eax = *(ebx+0x84) mov ecx, [esi+84h] ; ecx = *(esi+0x84) mov al, [eax+30h] ; al = *(*(ebx+0x84)+0x30) xor al, [ecx+30h] ; al = al XOR *(*(esi+0x84)+0x30) jnz loc_6385A453 Lets make it simpler for me to understand: mov eax, b3h xor eax, d6h jnz ... How does the conditional jump instruction work after a xor instruction?

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  • Help with regex to detect urls in a string

    - by Ali Taha Ali Mahboub
    Hi guys i found this regex to detect urls in a string and wraps them inside the tag public static String detectUrls(String text) { String newText = text .replaceAll("(?<!http://)www\\.[\\w/%.\\-?&=]+", "http://$0") .replaceAll("(?:https?|ftps?|http?)://[\\w/%.\\-?&=]+", "<a href='$0'>$0</a>"); return newText; } but this regex doesn't work with the following pattern: https://www.myserver.com so please advise.

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  • Ruby on Rails - pass variable to nested form

    - by Krule
    I am trying to build a multilingual site using Rails, but I can't figure out how to pass variable to nested form. Right now I am creating nested form like this. @languages.each do @article.article_locale.build(:language_id => language.id) end But i would like to pass value of language to it so i can distinguish fields. Something like this. @languages.each do |language| @language = language @article.article_locale.build(:language_id => language.id) end However, I always end up with language of the last loop iteration. Any way to pass this variable? -- edit -- In the end, since I've got no answer I have solved this problem so it, at least, works as it should. Following code is my partial solution. In model: def self.languages Language.all end def self.language_name language = [] self.languages.each_with_index do |lang, i| language[i] = lang.longname end return language end In Controller: def new @article = Article.new Article.languages.each do |language| @article.article_locale.build(:language_id => language.id) end end In HAML View: -count = 0 -f.fields_for :article_locale do |al| %h3= Article.language_name[count] -count+=1 -field_set_tag do %p =al.label :name, t(:name) =al.text_field :name %p =al.label :description, t(:description) =al.text_area :description =al.hidden_field :language_id It's not the most elegant solution I suppose, but it works. I would really love if I could get rid of counter in view for instance.

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  • Motores tecnológicos para el crecimiento económico

    - by Fabian Gradolph
    Oracle ha participado hoy en el IV Curso de Verano AMETIC-UPM. La presentación a corrido a cargo de José Manuel Peláez, director de Preventa de Tecnología de Oracle Ibérica, quien ha hecho una completa revisión de cuáles son los impulsores actuales de la innvovación y del desarrollo en el entorno de las tecnologías, haciendo honor al título del curso:  Las TIC en el nuevo entorno socio-económico: Motores de la recuperación económica y el empleo. Peláez, en su presentación "De la tecnología a la innovación: impulsores de la actividad económica",  ha comenzado destacando la importancia estratégica que hoy en día tienen las tecnologías para cualquier modelo de negocio. No se trata ya de hacer frente a la crisis económica, que también, sino sobre todo de hacer frente a los desafíos presentes y futuros de las empresas. En este sentido, es esencial hacer frente a un reto: el alto coste que tiene para las organizaciones la complejidad de sus sistemas tecnológicos. Hay un ejemplo que Oracle utiliza con frecuencia. Si un coche se comprase del mismo modo en que las empresas adquieren los sistemas de información, compraríamos por un lado la carrocería, por otro lado el motor, las ventanas, el cambio de marchas, etc... y luego pasaríamos un tiempo muy interesante montándolo todo en casa. La pregunta clave es: ¿por qué no adquirir los sistemas de información ya preparados para funcionar, al igual que compramos un coche?. El sector TI, con Oracle a la cabeza, está dando uina respuesta adecuada con los sistemas de ingenería conjunta. Se trata de sistemas de hardware y software diseñados y concebidos de forma integrada que reducen considerablemente el tiempo necesario para la implementación, los costes de integración y los costes de energía y mantenimiento. La clave de esta forma de adquirir la tecnología, según ha explicado Peláez, es que al reducir la complejidad y los costes asociados, se están liberando recursos que pueden dedicarse a otras necesidades. Según los datos de Gartner, de la cantidad de recursos invertidos por las empresas en TI, el 63% se dedica a tareas de puro funcionamiento, es decir, a mantener el negocio en marcha. La parte de presupuesto que se dedica a crecimiento del negocio es el 21%, mientras que sólo un 16% se dedica a transformación, es decir, a innovación. Sólo mediante la utilización de tecnologías más eficientes -como los sistemas de ingeniería conjunta-, que lleven aparejados menores costes, es viable reducir ese 63% y dedicar más recursos al crecimiento y la innovación. Ahora bien, una vez liberados los recursos económicos, ¿hacia dónde habría que dirigir las inversiones en tecnología?. José Manuel Peláez ha destacado algunas áreas esenciales como son Big Data, Cloud Computing, los retos de la movilidad y la necesidad de mejorar la experiencia de los clientes, entre otros. Cada uno de estos aspectos lleva aparejados nuevos retos empresariales, pero sólo las empresas que sean capaces de integrarlos en su ADN e incorporarlos al corazón de su estrategia de negocio, podrán diferenciarse en el panorama competitivo del siglo XXI. Desde estas páginas los iremos desgranando poco a poco.

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  • Dual-booting Ubuntu and Pardus with GRUB2...Pardus no show?

    - by Ibn Ali al-Turki
    Hello all, I have Ubuntu 10.10 installed and used to dual-boot Fedora, but I replaced Fedora with Pardus. After the install, I went into ubuntu, and did a sudo update-grub. It detected my Pardus 2011 install there. When I rebooted, it did not show up in my grub2 menu however. I went back to Ubuntu and did it again...then checked the grub.cfg, and it is not there. I have read that Pardus uses a grub legacy. How can I get Pardus into my grub2 menu? Thanks! sudo fdisk -l Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xd9b3496e Device Boot Start End Blocks Id System /dev/sda1 * 1 15197 122067968 83 Linux /dev/sda2 36394 60802 196059757 5 Extended /dev/sda3 15197 30394 122067968 83 Linux /dev/sda5 36394 59434 185075308 7 HPFS/NTFS /dev/sda6 59434 60802 10983424 82 Linux swap / Solaris Partition table entries are not in disk order and update-grub Found linux image: /boot/vmlinuz-2.6.35-25-generic Found initrd image: /boot/initrd.img-2.6.35-25-generic Found memtest86+ image: /boot/memtest86+.bin Found Pardus 2011 (2011) on /dev/sda3 Yet after this, I go to grub.cfg, and Pardus is not there.

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  • Dual-booting Ubuntu and Pardus with GRUB2...Pardus no show?

    - by Ibn Ali al-Turki
    I have Ubuntu 10.10 installed and used to dual-boot Fedora, but I replaced Fedora with Pardus. After the install, I went into ubuntu, and did a sudo update-grub. It detected my Pardus 2011 install there. When I rebooted, it did not show up in my grub2 menu however. I went back to Ubuntu and did it again...then checked the grub.cfg, and it is not there. I have read that Pardus uses a grub legacy. How can I get Pardus into my grub2 menu? Thanks! sudo fdisk -l Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xd9b3496e Device Boot Start End Blocks Id System /dev/sda1 * 1 15197 122067968 83 Linux /dev/sda2 36394 60802 196059757 5 Extended /dev/sda3 15197 30394 122067968 83 Linux /dev/sda5 36394 59434 185075308 7 HPFS/NTFS /dev/sda6 59434 60802 10983424 82 Linux swap / Solaris Partition table entries are not in disk order and update-grub Found linux image: /boot/vmlinuz-2.6.35-25-generic Found initrd image: /boot/initrd.img-2.6.35-25-generic Found memtest86+ image: /boot/memtest86+.bin Found Pardus 2011 (2011) on /dev/sda3 Yet after this, I go to grub.cfg, and Pardus is not there.

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  • Qt Linker Errors

    - by Kyle Rozendo
    Hi All, I've been trying to get Qt working (QCreator, QIde and now VS2008). I have sorted out a ton of issues already, but I am now faced with the following build errors, and frankly I'm out of ideas. Error 1 error LNK2019: unresolved external symbol "public: void __thiscall FileVisitor::processFileList(class QStringList)" (?processFileList@FileVisitor@@QAEXVQStringList@@@Z) referenced in function _main codevisitor-test.obj Question1 Error 2 error LNK2019: unresolved external symbol "public: void __thiscall FileVisitor::processEntry(class QString)" (?processEntry@FileVisitor@@QAEXVQString@@@Z) referenced in function _main codevisitor-test.obj Question1 Error 3 error LNK2019: unresolved external symbol "public: class QString __thiscall ArgumentList::getSwitchArg(class QString,class QString)" (?getSwitchArg@ArgumentList@@QAE?AVQString@@V2@0@Z) referenced in function _main codevisitor-test.obj Question1 Error 4 error LNK2019: unresolved external symbol "public: bool __thiscall ArgumentList::getSwitch(class QString)" (?getSwitch@ArgumentList@@QAE_NVQString@@@Z) referenced in function _main codevisitor-test.obj Question1 Error 5 error LNK2019: unresolved external symbol "public: void __thiscall ArgumentList::argsToStringlist(int,char * * const)" (?argsToStringlist@ArgumentList@@QAEXHQAPAD@Z) referenced in function "public: __thiscall ArgumentList::ArgumentList(int,char * * const)" (??0ArgumentList@@QAE@HQAPAD@Z) codevisitor-test.obj Question1 Error 6 error LNK2019: unresolved external symbol "public: __thiscall FileVisitor::FileVisitor(class QString,bool,bool)" (??0FileVisitor@@QAE@VQString@@_N1@Z) referenced in function "public: __thiscall CodeVisitor::CodeVisitor(class QString,bool)" (??0CodeVisitor@@QAE@VQString@@_N@Z) codevisitor-test.obj Question1 Error 7 error LNK2001: unresolved external symbol "public: virtual struct QMetaObject const * __thiscall FileVisitor::metaObject(void)const " (?metaObject@FileVisitor@@UBEPBUQMetaObject@@XZ) codevisitor-test.obj Question1 Error 8 error LNK2001: unresolved external symbol "public: virtual void * __thiscall FileVisitor::qt_metacast(char const *)" (?qt_metacast@FileVisitor@@UAEPAXPBD@Z) codevisitor-test.obj Question1 Error 9 error LNK2001: unresolved external symbol "public: virtual int __thiscall FileVisitor::qt_metacall(enum QMetaObject::Call,int,void * *)" (?qt_metacall@FileVisitor@@UAEHW4Call@QMetaObject@@HPAPAX@Z) codevisitor-test.obj Question1 Error 10 error LNK2001: unresolved external symbol "protected: virtual bool __thiscall FileVisitor::skipDir(class QDir const &)" (?skipDir@FileVisitor@@MAE_NABVQDir@@@Z) codevisitor-test.obj Question1 Error 11 fatal error LNK1120: 10 unresolved externals ... \Visual Studio 2008\Projects\Assignment1\Question1\Question1\Debug\Question1.exe Question1 The code is as follows: #include "argumentlist.h" #include <codevisitor.h> #include <QDebug> void usage(QString appname) { qDebug() << appname << " Usage: \n" << "codevisitor [-r] [-d startdir] [-f filter] [file-list]\n" << "\t-r \tvisitor will recurse into subdirs\n" << "\t-d startdir\tspecifies starting directory\n" << "\t-f filter\tfilename filter to restrict visits\n" << "\toptional list of files to be visited"; } int main(int argc, char** argv) { ArgumentList al(argc, argv); QString appname = al.takeFirst(); /* app name is always first in the list. */ if (al.count() == 0) { usage(appname); exit(1); } bool recursive(al.getSwitch("-r")); QString startdir(al.getSwitchArg("-d")); QString filter(al.getSwitchArg("-f")); CodeVisitor cvis(filter, recursive); if (startdir != QString()) { cvis.processEntry(startdir); } else if (al.size()) { cvis.processFileList(al); } else return 1; qDebug() << "Files Processed: %d" << cvis.getNumFiles(); qDebug() << cvis.getResultString(); return 0; } Thanks in advance, I'm simply stumped.

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  • Poner aplicaci&oacute;n Asp.Net en modo OFFLINE

    - by Jason Ulloa
    Una de las opciones que todo aplicación debería tener es el poder ponerse en modo OFFLINE para evitar el acceso de usuarios. Esto es completamente necesario cuando queremos realizar cambios a nuestra aplicación (cambiar algo, poner una actualización, etc) o a nuestra base de datos y evitarnos problemas con los usuarios que se encuentren logueados dentro de la aplicación en ese momento. Muchos ejemplos a través de la Web exponen la forma de realizar esta tarea utilizando dos técnicas: 1. La primera de ellas es utilizar el archivo App_Offline.htm sin embargo, esta técnica tiene un inconveniente. Y es que, una vez que hemos subido el archivo a nuestra aplicación esta se bloquea completamente y no tenemos forma de volver a ponerla ONLINE a menos que eliminemos el archivo. Es decir no podemos controlarla. 2. La segunda de ellas es el utilizar la etiqueta httpRuntime, pero nuevamente tenemos el mismo problema. Al habilitar el modo OFFLINE mediante esta etiqueta, tampoco podremos acceder a un modo de administración para cambiarla. Un ejemplo de la etiqueta httpRuntime <configuration> <system.web> <httpRuntime enable="false" /> </system.web> </configuration>   Tomando en cuenta lo anterior, lo mas optimo seria que podamos por medio de alguna pagina de administración colocar nuestro sitio en modo OFFLINE, pero manteniendo el acceso a la pagina de administración para poder volver a cambiar el valor que pondrá nuestra aplicación nuevamente en modo ONLINE. Para ello, utilizaremos el web.config de nuestra aplicación y una pequeña clase que se encargara de Leer y escribir los valores. Lo primero será, abrir nuestro web.config y definir dentro del appSettings dos nuevas KEY que contendrán los valores para el modo OFFLINE de nuestra aplicación: <appSettings> <add key="IsOffline" value="false" /> <add key="IsOfflineMessage" value="Sistema temporalmente no disponible por tareas de mantenimiento." /> </appSettings>   En las KEY anteriores tenemos el IsOffLine con value de false, esto es para indicarle a nuestra aplicación que actualmente su modo de funcionamiento es ONLINE, este valor será el que posteriormente cambiemos a TRUE para volver al modo OFFLINE. Nuestra segunda KEY (IsOfflineMessage) posee el value (Sistema temporalmente….) que será mostrado al usuario como un mensaje cuando el sitio este en modo OFFLINE. Una vez definidas nuestras dos KEY en el web.config, escribiremos una clase personalizada para leer y escribir los valores. Así que, agregamos un nuevo elemento de tipo clase al proyecto llamado SettingsRules y la definimos como Public. Está clase contendrá dos métodos, el primero será para leer los valores: public string readIsOnlineSettings(string sectionToRead) { Configuration cfg = WebConfigurationManager.OpenWebConfiguration(System.Web.Hosting.HostingEnvironment.ApplicationVirtualPath); KeyValueConfigurationElement isOnlineSettings = (KeyValueConfigurationElement)cfg.AppSettings.Settings[sectionToRead]; return isOnlineSettings.Value; }   El segundo método, será el encargado de escribir los nuevos valores al web.config public bool saveIsOnlineSettings(string sectionToWrite, string value) { bool succesFullySaved;   try { Configuration cfg = WebConfigurationManager.OpenWebConfiguration(System.Web.Hosting.HostingEnvironment.ApplicationVirtualPath); KeyValueConfigurationElement repositorySettings = (KeyValueConfigurationElement)cfg.AppSettings.Settings[sectionToWrite];   if (repositorySettings != null) { repositorySettings.Value = value; cfg.Save(ConfigurationSaveMode.Modified); } succesFullySaved = true; } catch (Exception) { succesFullySaved = false; } return succesFullySaved; }   Por último, definiremos en nuestra clase una región llamada instance, que contendrá un método encargado de devolver una instancia de la clase (esto para no tener que hacerlo luego) #region instance   private static SettingsRules m_instance;   // Properties public static SettingsRules Instance { get { if (m_instance == null) { m_instance = new SettingsRules(); } return m_instance; } }   #endregion instance   Con esto, nuestra clase principal esta completa. Así que pasaremos a la implementación de las páginas y el resto de código que completará la funcionalidad.   Para complementar la tarea del web.config utilizaremos el fabuloso GLOBAL.ASAX, este contendrá el código encargado de detectar si nuestra aplicación tiene el valor de ONLINE o OFFLINE y además de bloquear todas las paginas y directorios excepto el que le hayamos definido como administrador, esto para luego poder volver a configurar el sitio.   El evento del Global.Asax que utilizaremos será el Application_BeginRequest   protected void Application_BeginRequest(Object sender, EventArgs e) {   if (Convert.ToBoolean(SettingsRules.Instance.readIsOnlineSettings("IsOffline"))) {   string Virtual = Request.Path.Substring(0, Request.Path.LastIndexOf("/") + 1);   if (Virtual.ToLower().IndexOf("/admin/") == -1) { //We don't makes action, is admin section Server.Transfer("~/TemporarilyOfflineMessage.aspx"); }   } } La primer Línea del IF, verifica si el atributo del web.config es True o False, si es true toma la dirección WEB que se ha solicitado y la incluimos en un IF para verificar si corresponde a la Sección admin (está sección no es mas que un folder en nuestra aplicación llamado admin y puede ser cambiado a cualquier otro). Si el resultado de ese if es –1 quiere decir que no coincide, entonces, esa será la bandera que nos permitirá bloquear inmediatamente la pagina actual, transfiriendo al usuario a una pagina de mantenimiento. Ahora, en nuestra carpeta Admin crearemos una nueva pagina asp.net llamada OnlineSettings.aspx para actualizar y leer los datos del web.config y una pagina Default.aspx para pruebas. Nuestra página OnlineSettings tendrá dos pasos importantes: 1. Leer los datos actuales de configuración protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) { IsOffline.Checked = Convert.ToBoolean(mySettings.readIsOnlineSettings("IsOffline")); OfflineMessage.Text = mySettings.readIsOnlineSettings("IsOfflineMessage"); } }   2. Actualizar los datos con los nuevos valores. protected void UpdateButton_Click(object sender, EventArgs e) { string htmlMessage = OfflineMessage.Text.Replace(Environment.NewLine, "<br />");   // Update the Application variables Application.Lock(); if (IsOffline.Checked) { mySettings.saveIsOnlineSettings("IsOffline", "True"); mySettings.saveIsOnlineSettings("IsOfflineMessage", htmlMessage); } else { mySettings.saveIsOnlineSettings("IsOffline", "false"); mySettings.saveIsOnlineSettings("IsOfflineMessage", htmlMessage); }   Application.UnLock(); }   Por último en la raíz de la aplicación, crearemos una nueva página aspx llamada TemporarilyOfflineMessage.aspx que será la que se muestre cuando se bloquee la aplicación. Al final nuestra aplicación se vería algo así Página bloqueada Configuración del Bloqueo Y para terminar la aplicación de ejemplo

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  • Data Guard - Snapshot Standby Database??

    - by Jian Zhang-Oracle
    ?? -------- ?????,??standby?????mount??????????REDO??,??standby????????????????????,???????read-only???open????,????ACTIVE DATA GUARD,????standby?????????(read-only)??(????????),????standby???????????(read-write)? ?????,?????????????Real Application Testing(RAT)??????????,?????????standby??????snapshot standby?????????,??snapshot standby??????????,???????????(read-write)??????snapshot standby??????????????,?????????,??????????,????????,?????????snapshot standby?????standby???,????????? ?? ---------  1.??standby?????? SQL> Alter system set db_recovery_file_dest_size=500M; System altered. SQL> Alter system set db_recovery_file_dest='/u01/app/oracle/snapshot_standby'; System altered. 2.??standby?????? SQL> alter database recover managed standby database cancel; Database altered. 3.??standby???snapshot standby,??open snapshot standby SQL> alter database convert to snapshot standby; Database altered. SQL> alter database open;    Database altered. ??snapshot standby??????SNAPSHOT STANDBY,open???READ WRITE: SQL> select DATABASE_ROLE,name,OPEN_MODE from v$database; DATABASE_ROLE    NAME      OPEN_MODE ---------------- --------- -------------------- SNAPSHOT STANDBY FSDB      READ WRITE 4.?snapshot standby???????????Real Application Testing(RAT)????????? 5.?????,??snapshot standby???physical standby,?????????? SQL> shutdown immediate; Database closed. Database dismounted. ORACLE instance shut down. SQL> startup mount; ORACLE instance started. Database mounted. SQL> ALTER DATABASE CONVERT TO PHYSICAL STANDBY; Database altered. SQL> shutdown immediate; ORA-01507: database not mounted ORACLE instance shut down. SQL> startup mount; ORACLE instance started. Database mounted. SQL>ALTER DATABASE RECOVER MANAGED STANDBY DATABASE DISCONNECT FROM SESSION; Database altered. 5.?????standby?,???????PHYSICAL STANDBY,open???MOUNTED SQL> select DATABASE_ROLE,name,OPEN_MODE from v$database; DATABASE_ROLE    NAME      OPEN_MODE ---------------- --------- -------------------- PHYSICAL STANDBY FSDB      MOUNTED 6.??????????????? ????: SQL> select ads.dest_id,max(sequence#) "Current Sequence",            max(log_sequence) "Last Archived"        from v$archived_log al, v$archive_dest ad, v$archive_dest_status ads        where ad.dest_id=al.dest_id        and al.dest_id=ads.dest_id        and al.resetlogs_change#=(select max(resetlogs_change#) from v$archived_log )        group by ads.dest_id;    DEST_ID Current Sequence Last Archived ---------- ---------------- -------------      1              361           361      2              361           362 --???? SQL>    select al.thrd "Thread", almax "Last Seq Received", lhmax "Last Seq Applied"       from (select thread# thrd, max(sequence#) almax           from v$archived_log           where resetlogs_change#=(select resetlogs_change# from v$database)           group by thread#) al,          (select thread# thrd, max(sequence#) lhmax           from v$log_history           where resetlogs_change#=(select resetlogs_change# from v$database)           group by thread#) lh      where al.thrd = lh.thrd;     Thread Last Seq Received Last Seq Applied ---------- ----------------- ----------------          1               361              361 ??????????,???blog,???????????,??"??:Data Guard - Snapshot Standby Database??" 

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  • how to set custom interval to horizontal axis in Flex Charts

    - by Ali Syed
    Hello folks, I am trying to set custom step (interval) to my Line Chart's horizontal axis. The chart gets its data from a grid. The grid has a lot of data and it is displayed accurately but because there are so many data points the horizontal axis is screwed up. I wanted to set a step on horizontal axis so that you get an idea when you see the graph without hovering the mouse on a data point! thanks for any help! -Ali Flexi Comment Box

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  • Storing Data from both POST variables and GET parameters

    - by Ali
    I want my python script to simultaneously accept POST variables and query string variables from the web address. The script has code : form = cgi.FieldStorage() print form However, this only captures the post variables and no query variables from the web address. Is there a way to do this? Thanks, Ali

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