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  • Debian sound on hdmi instead of jack

    - by Hans de Jong
    I installed debian (gnome) and i can't get my sound working. When i use inxi -A i get the following result: Audio: Card-1: Advanced Micro Devices [AMD] nee ATI Cayman/Antilles HDMI Audio [Radeon HD 6900 Series] driver: snd_hda_intel Card-2: Advanced Micro Devices [AMD] nee ATI SBx00 Azalia (Intel HDA) driver: snd_hda_intel Sound: Advanced Linux Sound Architecture ver: 1.0.24 My feeling tells me my sound output is on the HDMI instead of my jackplug on my motherboard. How can i change this to my motherboard sound output?

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  • 12.04 Ubuntu studio PREEMPT_RT kernel options

    - by Nate Iverson
    My audio processing needs require a preempt_rt kernel. I roughly followed the guide: https://wiki.ubuntu.com/KernelTeam/GitKernelBuild with a little help from: https://rt.wiki.kernel.org/index.php/RT_PREEMPT_HOWTO Currently I am using the 3.4 branch (which is the most recent at the time of this post): http://www.kernel.org/pub/linux/kernel/projects/rt/ I think I have a reasonable kernel config ( for my machine at least ). Multiple trials confirm I need the option: CONFIG_PREEMPT_RT_FULL=y I have the following questions: Is anyone maintaining a recent CONFIG_PREEMPT_RT_FULL kernel in a ppa? Is there any interest in providing a CONFIG_PREEMPT_RT_FULL in the official ubuntu-studio distribution? Does anyone have recent config pointers for a CONFIG_PREEMPT_RT_FULL kernel?

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  • Scheme homework Black jack help....

    - by octavio
    So I need to do a game of blackjack simulator, butt can't seem to figure out whats wrong with the shuffle it's suppose to take a card randomly from the pack the put it on top of the pack. The delete it from the rest. so : (ace)(2)(3)(4)(5)...(k) if random card is let say 5 (5)(ace)(2)(3)(4)(5)...(k) then it deletes the 2nd 5 (5)(ace)(2)(3)(4)(6)...(k) here is the code: (define deck '((A . C) (2 . C) (3 . C) (4 . C) (5 . C) (6 . C) (7 . C) (8 . C) (9 . C) (10 . C) (V . C) (Q . C) (K . C))) ;auxilliary function for shuffle let you randomly select a card. (define shuffAux (lambda (t) (define cardR (lambda (t) (list-ref t (random 13)))) (cardR t))) ;auxilliary function used to remove the card after the car to prevent you from removing the randomly selected from the car(begining of the deck). (define (removeDupC card deck) (delete card (cdr deck)) ) (define shuffle2ndtry (lambda (deck seed) (define do-shuffle (lambda (deck seed) (if (> seed 0)( (cons (shuffAux deck) deck) (removeDupC (car deck) deck) (- 1 seed)) (write deck) ) ) ) (do-shuffle deck seed))) (define (shuffle deck seed) (define cards (cons (shuffAux deck) deck)) (write cards) (case (> seed 0) [(#t) (removeDupC (car cards) (cdr cards)) (shuffle cards (- seed 1))] [(#f) (write cards)])) (define random (let ((seed 0) (a 3141592653) (c 2718281829) (m (expt 2 35))) (lambda (limit) (cond ((and (integer? limit)) (set! seed (modulo (+ (* seed a) c) m)) (quotient (* seed limit) m)) (else (/ (* limit (random 34359738368)) 34359738368)))))) ;function in which you can delete an element from the list. (define delete (lambda (item list) (cond ((equal? item (car list)) (cdr list)) (else (cons (car list) (delete item (cdr list))))))) (

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  • VMWare Headphone Issue

    - by Ash_Geek_Pickney
    I am running VMWare Workstation Version 7 on a Windows 7 partition on a Macbook Pro. I have built a virtual XP machine within vmware to run some old music programs. The sound from my virtual machines comes out of my macbook speakers but the volume is not controllable using my macbook volume controls, only by using the volume control on the XP machine. My problem is that i need to use headphones, and when i plug a headphone jack into my macbook, the sound from my vmware virtual machines still comes out of the macbook speakers. I am baffled. Please help. Thanks in advance...

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  • VBA/SQL recordsets

    - by intruesiive
    The project I'm asking about is for sending an email to teachers asking what books they're using for the classes they're teaching next semester, so that the books can be ordered. I have a query that compares the course number of this upcoming semester's classes to the course numbers of historical textbook orders, pulling out only those classes that are being taught this semester. That's where I get lost. I have a table that contains the following: -Professor -Course Number -Year -Book -Title The data looks like this: professor year course number title smith 13 1111 Pride and Prejudice smith 13 1111 The Fountainhead smith 13 1222 The Alchemist smith 12 1111 Pride and Prejudice smith 11 1222 Infinite Jest smith 10 1333 The Bible smith 13 1333 The Bible smith 12 1222 The Alchemist smith 10 1111 Moby Dick johnson 12 1222 The Tipping Point johnson 11 1333 Anna Kerenina johnson 10 1333 Everything is Illuminated johnson 12 1222 The Savage Detectives johnson 11 1333 In Search of Lost Time johnson 10 1333 Great Expectations johnson 9 1222 Proust on the Shore Here's what I need the code to do "on paper": Group the records by professor. Determine every unique course number in that group, and group records by course number. For each unique course number, determine the highest year associated. Then spit out every record with that professor+course number+year combination. With the sample data, the results would be: professor year course number title smith 13 1111 Pride and Prejudice smith 13 1111 The Fountainhead smith 13 1222 The Alchemist smith 13 1333 The Bible johnson 12 1222 The Tipping Point johnson 11 1333 Anna Kerenina johnson 12 1222 The Savage Detectives johnson 11 1333 In Search of Lost Time I'm thinking I should make a record set for each teacher, and within that, another record set for each course number. Within the course number record set, I need the system to determine what the highest year number is - maybe store that in a variable? Then pull out every associated record so that if the teacher ordered 3 books the last time they taught that class (whether it was in 2013 or 2012 and so on) all three books display. I'm not sure I'm thinking of record sets in the right way, though. My SQL so far is basic and clearly doesn't work: SELECT [All].Professor, [All].Course, Max([All].Year) FROM [All] GROUP BY [All].Professor, [All].Course; Thanks for your help.

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  • How do I stop and repair a RAID 5 array that has failed and has I/O pending?

    - by Ben Hymers
    The short version: I have a failed RAID 5 array which has a bunch of processes hung waiting on I/O operations on it; how can I recover from this? The long version: Yesterday I noticed Samba access was being very sporadic; accessing the server's shares from Windows would randomly lock up explorer completely after clicking on one or two directories. I assumed it was Windows being a pain and left it. Today the problem is the same, so I did a little digging; the first thing I noticed was that running ps aux | grep smbd gives a lot of lines like this: ben 969 0.0 0.2 96088 4128 ? D 18:21 0:00 smbd -F root 1708 0.0 0.2 93468 4748 ? Ss 18:44 0:00 smbd -F root 1711 0.0 0.0 93468 1364 ? S 18:44 0:00 smbd -F ben 3148 0.0 0.2 96052 4160 ? D Mar07 0:00 smbd -F ... There are a lot of processes stuck in the "D" state. Running ps aux | grep " D" shows up some other processes including my nightly backup script, all of which need to access the volume mounted on my RAID array at some point. After some googling, I found that it might be down to the RAID array failing, so I checked /proc/mdstat, which shows this: ben@jack:~$ cat /proc/mdstat Personalities : [linear] [multipath] [raid0] [raid1] [raid6] [raid5] [raid4] [raid10] md0 : active raid5 sdb1[3](F) sdc1[1] sdd1[2] 2930271872 blocks level 5, 64k chunk, algorithm 2 [3/2] [_UU] unused devices: <none> And running mdadm --detail /dev/md0 gives this: ben@jack:~$ sudo mdadm --detail /dev/md0 /dev/md0: Version : 00.90 Creation Time : Sat Oct 31 20:53:10 2009 Raid Level : raid5 Array Size : 2930271872 (2794.53 GiB 3000.60 GB) Used Dev Size : 1465135936 (1397.26 GiB 1500.30 GB) Raid Devices : 3 Total Devices : 3 Preferred Minor : 0 Persistence : Superblock is persistent Update Time : Mon Mar 7 03:06:35 2011 State : active, degraded Active Devices : 2 Working Devices : 2 Failed Devices : 1 Spare Devices : 0 Layout : left-symmetric Chunk Size : 64K UUID : f114711a:c770de54:c8276759:b34deaa0 Events : 0.208245 Number Major Minor RaidDevice State 3 8 17 0 faulty spare rebuilding /dev/sdb1 1 8 33 1 active sync /dev/sdc1 2 8 49 2 active sync /dev/sdd1 I believe this says that sdb1 has failed, and so the array is running with two drives out of three 'up'. Some advice I found said to check /var/log/messages for notices of failures, and sure enough there are plenty: ben@jack:~$ grep sdb /var/log/messages ... Mar 7 03:06:35 jack kernel: [4525155.384937] md/raid:md0: read error NOT corrected!! (sector 400644912 on sdb1). Mar 7 03:06:35 jack kernel: [4525155.389686] md/raid:md0: read error not correctable (sector 400644920 on sdb1). Mar 7 03:06:35 jack kernel: [4525155.389686] md/raid:md0: read error not correctable (sector 400644928 on sdb1). Mar 7 03:06:35 jack kernel: [4525155.389688] md/raid:md0: read error not correctable (sector 400644936 on sdb1). Mar 7 03:06:56 jack kernel: [4525176.231603] sd 0:0:1:0: [sdb] Unhandled sense code Mar 7 03:06:56 jack kernel: [4525176.231605] sd 0:0:1:0: [sdb] Result: hostbyte=DID_OK driverbyte=DRIVER_SENSE Mar 7 03:06:56 jack kernel: [4525176.231608] sd 0:0:1:0: [sdb] Sense Key : Medium Error [current] [descriptor] Mar 7 03:06:56 jack kernel: [4525176.231623] sd 0:0:1:0: [sdb] Add. Sense: Unrecovered read error - auto reallocate failed Mar 7 03:06:56 jack kernel: [4525176.231627] sd 0:0:1:0: [sdb] CDB: Read(10): 28 00 17 e1 5f bf 00 01 00 00 To me it is clear that device sdb has failed, and I need to stop the array, shutdown, replace it, reboot, then repair the array, bring it back up and mount the filesystem. I cannot hot-swap a replacement drive in, and don't want to leave the array running in a degraded state. I believe I am supposed to unmount the filesystem before stopping the array, but that is failing, and that is where I'm stuck now: ben@jack:~$ sudo umount /storage umount: /storage: device is busy. (In some cases useful info about processes that use the device is found by lsof(8) or fuser(1)) It is indeed busy; there are some 30 or 40 processes waiting on I/O. What should I do? Should I kill all these processes and try again? Is that a wise move when they are 'uninterruptable'? What would happen if I tried to reboot? Please let me know what you think I should do. And please ask if you need any extra information to diagnose the problem or to help!

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  • ssh without password does not work for some users

    - by joshxdr
    I have a new RHEL4 Linux box that I am using to copy data to old Solaris 2.6 and RHEL3 Linux boxes with scp. I have found that with the same setup, it works for some users but not for others. For user jane, this works fine: jane@host1$ ssh -v remhost debug1: Next authentication method: publickey debug1: Trying private key: /mnt/home/osborjo/.ssh/identity debug1: Offering public key: /mnt/home/osborjo/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: read PEM private key done: type RSA debug1: Authentication succeeded (publickey). for user jack it does not: jack@host1 ssh -v remhost debug1: Next authentication method: publickey debug1: Trying private key: /mnt/home/oper1/.ssh/identity debug1: Offering public key: /mnt/home/oper1/.ssh/id_rsa debug1: Authentications that can continue: publickey,password,keyboard-interactive I have looked at the permissions for all the keys and files, they look the same. Since I am using home directories mounted by NFS, the keys for both the remote host and the local host are in the same directory. This is how things look for jane: jane@host1$ ls -l $HOME/.ssh -rw-rw-r-- 1 jane operator 394 Jan 27 16:28 authorized_keys -rw------- 1 jane operator 1675 Jan 27 16:27 id_rsa -rw-r--r-- 1 jane operator 394 Jan 27 16:27 id_rsa.pub -rw-rw-r-- 1 jane operator 1205 Jan 27 16:46 known_hosts For user jack: jack@host1$ ls -l $HOME/.ssh -rw-rw-r-- 1 jack engineer 394 Jan 27 16:28 authorized_keys -rw------- 1 jack engineer 1675 Jan 27 16:27 id_rsa -rw-r--r-- 1 jack engineer 394 Jan 27 16:27 id_rsa.pub -rw-rw-r-- 1 jack engineer 1205 Jan 27 16:46 known_hosts As a last ditch effort, I copied the authorized_keys, id_rsa, and id_rsa.pub from jill to jack, and changed the username in authorized_keys and id_rsa.pub with vi. It still did not work. It seems there is something different between the two users but I cannot figure out what it is.

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  • 11 Types of Developers

    - by Lee Brandt
    Jack Dawson Jack Dawson is the homeless drifter in Titanic. At one point in the movie he says, “I figure life’s a gift, and I don’t intend on wasting it.” He is happy to wander wherever life takes him. He works himself from place to place, making just enough money to make it to his next adventure. The “Jack Dawson” developer clings on to any new technology as the ‘next big thing’, and will find ways to shoe-horn it in to places where it is not a fit. He is very appealing to the other developers because they want to try the newest techniques and tools too, He will only stay until the new technology either bores him or becomes problematic. Jack will also be hard to find once the technology has been implemented, because he will be on to the next shiny thing. However, having a Jack Dawson on your team can be beneficial. Jack can be a great ally when attempting to convince a stodgy, corporate entity to upgrade. Jack usually has an encyclopedic recall of all the new features of the technology upgrade and is more than happy to interject them in any conversation. Tom Smykowski Tom is the neurotic employee in Office Space, and is deathly afraid of being fired. He will do only what is necessary to keep the status quo. He believes as long as nothing changes, his job is safe. He will scoff at anything new and be the naysayer during any change initiative. Tom can be useful in off-setting Jack Dawson. Jack will constantly be pushing for change and Tom will constantly be fighting it. When you see that Jack is getting kind of bored with a new technology and Tom has finally stopped wetting himself at the mere mention of it, then it is probably the sweet spot of beginning to implement that new technology (providing it is the right tool for the job). Ray Consella Ray is the guy who built the Field of Dreams. He took a risk. Sometimes he screwed it up, but he knew he didn’t want to end up regretting not attempting it. He constantly doubted himself, but he knew he had to keep going. Granted, he was doing what the voices in his head were telling him to do, but my point is he was driven to do something that most people considered crazy. Even when his friends, his wife and even he told himself he was crazy, somewhere inside himself, he knew it was the right thing to do. These are the innovators. These are the Bill Gates and Steve Jobs of the world. The take risks, they fail, they learn and the get better. Obviously, this kind of person thrives in start-ups and smaller companies, but that is due to their natural aversion to bureaucracy. They want to see their ideas put into motion quickly, and withdrawn quickly if it doesn’t work. Short feedback cycles are essential to Ray. He wants to know if his idea is working or not. He wants to modify or reverse his idea if it is not working or makes things worse. These are the agilistas. May I always be one.

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  • SQL: Add counters in select

    - by etarvt
    Hi, I have a table which contains names: Name ---- John Smith John Smith Sam Wood George Wright John Smith Sam Wood I want to create a select statement which shows this: Name 'John Smith 1' 'John Smith 2' 'Sam Wood 1' 'George Wright 1' 'John Smith 3' 'Sam Wood 2' In other words, I want to add separate counters to each name. Is there a way to do it without using cursors?

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  • As an IT contractor, is it better to be a specialist or a jack-of-all-trades? [on hold]

    - by alimac83
    I've just entered the contracting market as a web developer and I've having a tough time figuring out how to plan for the future. Several developers I've worked with in the past have told me to become a specialist in one technology/area in order to secure the big contracts. However I've also heard from other sources that it's better to spread your expertise so that you're not limited in the types of work you can go for. Personally I've pretty much been involved in both back and front-end technologies during the course of my career, with slight variations in the weighting of each depending on the job. I don't really have a favourite - I enjoy it all. My question is mainly to the experienced contractors though: Do you feel specialising has helped your career or is it better to know a bit of everything? Thanks

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  • Is there a way to make the speaker silent while the headphone-jack keeps working? 12.04LTS

    - by Cees
    The PC I am working on is in a loud environment. If I need sound, I use the headphone. On my own account this is easy: I mute the speaker in the sound-setting. I am not the only user, others use the Guest-session. And that's what this question about: Is it possible to turn off the speaker by default on a guest-session AND leave the headphone-output working? If yes, how can I fix it? I tried to loosen the speaker (hardware) connection but it is soldered to the mainboard. The soundcard on the PC is: HDA Intel at 0xfea78000 irq 44 /proc/asound/pcm ---------------------------+ ¦00-00: ALC662 rev1 Analog : ALC662 rev1 Analog : playback 1 : capture 1¦ ¦00-02: ALC662 rev1 Analog : ALC662 rev1 Analog : capture 1 Ubuntu 12.04LTS is running on the system, my account has all the (admin) rights

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  • How can I correlate a wall jack to a user/machine on the domain?

    - by harryfino
    After reading Valve's new employee handbook, I was really interested in setting up a company map like they described on page 6: "The fact that everyone is always moving around within the company makes people hard to find. That’s why we have http://user — check it out. We know where you are based on where your machine is plugged in, so use this site to see a map of where everyone is right now." What I'm trying to figure out is: how I can tell which machine or domain user (either will do) is connected to a particular wall jack?

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  • How are views constructed in Josh Smith's MVVM sample?

    - by Wim Coenen
    Being new to both WPF and MVVM, I'm studying Josh Smith's article on the MVVM pattern and the accompanying sample code. I can see that the application is started in app.xaml.cs by constructing a MainWindow object, wiring it to a MainWindowViewModel object and then showing the main window. So far so good. However, I can't find any code which instantiates the AllCustomersView or CustomerView classes. Using "find all references" on the constructors of those views comes up with nothing. What am I missing here?

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  • 9 New BizTalk Wencasts in the Light & Easy Series

    - by Alan Smith
    During the MVP summit in February I managed to catch up with a few of the BizTalk MVPs who had recorded new webcasts for the “BizTalk Light & Easy” series. The 9 new webcasts are online now at CloudCasts. ·         BizTalk 2010 and Windows Azure – Paul Somers ·         BizTalk and AppFabric Cache Part 1 – Mike Stephenson ·         BizTalk and AppFabric Cache Part 2 – Mike Stephenson ·         Integration to SharePoint 2010 Part 1 – Mick Badran ·         Integration to SharePoint 2010 Part 2 – Mick Badran ·         Better BizTalk Testing by Taking Advantage of the CAT Logging Framework – Mike Stephenson ·         Calling Business Rules from a .NET Application – Alan Smith ·         Tracking Rules Execution in a .NET Application – Alan Smith ·         Publishing a Business Rules Policy as a Service – Alan Smith The link is here. Big thanks to Paul, Mike and Mick for putting the time in. “BizTalk Light & Easy” is an ongoing project, if you are feeling creative and would like to contribute feel free to contact me via this blog. I can email you some tips on webcasting and the best formats to use.

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  • SEO impact on subdomain for full name and obscure ccTLD

    - by Dan Christian
    There have been a few questions on subdomains and their impact on SEO, mostly in comparison to subfolders. The closest question I've found is this question but it still doesn't completely answer my query. I'm setting up a blog for 'Sam Smith'. It's imperative the SEO is based around his full name as he is a prominent blogger and his name is his value. All ccTLD variations of 'samsmith' (samsmith.com, samsmith.cc etc) are taken. However there has been the opportunity to register an obscure ccTLD for 'smith'. In regards to SEO value purely from the URL... 1) Will there be any negative SEO implications on searches for 'Sam Smith' when setting up the subdomain as 'sam.smith.' compared to a more regular 'samsmith.' domain? Will a search engine recognise the subdomain as the full name as oppose to just 'smith'? 2) Are there any negative SEO implications with an obscure ccTLD. For instance if Sam Smith was a prominent blogger in Canada with most of his audience based there, would there be any negative SEO if he had, for example, a .co ccTLD.

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  • Filter rows on the basis of "First Name" + "Last Name" in SQL

    - by Raghav Khunger
    Hi, I have a user table in my database which contains two columns FirstName and LastName. Now in my front end there is a textbox to filter out the users from this table. Let's suppose I am taking that input from the front end in the form of a input parameter "@SEARCHKEYWORD". I have created a sample below: DECLARE @Test TABLE ([ID] INT IDENTITY, [FNAME] NVARCHAR(100), [LNAME] NVARCHAR(100) ) INSERT INTO @Test( FNAME, LNAME ) SELECT 'John','Resig' UNION ALL SELECT 'Dave','Ward' UNION ALL SELECT 'Peter','Smith' UNION ALL SELECT 'Dave','Smith' UNION ALL SELECT 'Girija','Acharya' UNION ALL SELECT 'Devendra', 'Gujel' UNION ALL SELECT 'Arjit', 'Gupta' DECLARE @SEARCHKEYWORD NVARCHAR(100) SELECT * FROM @Test WHERE FNAME +' '+ LNAME LIKE @SEARCHKEYWORD i.e. so far I have thought of this query to filter out the rows but it is not giving the desired results: SELECT * FROM @Test WHERE FNAME +' '+ LNAME LIKE @SEARCHKEYWORD Here are the desired outputs which I needed for the inputs mentioned below: --WHEN @SEARCHKEYWORD='John Resig' --Desired OUTPUT: the row which contains 'John','Resig' --WHEN @SEARCHKEYWORD='Ac' --Desired OUTPUT: the row which contains 'Girija','Acharya' --WHEN @SEARCHKEYWORD='Smith' --Desired OUTPUT: the row which contains 'Peter','Smith' and 'Dave','Smith' --WHEN @SEARCHKEYWORD='g' --Desired OUTPUT: the row which contains 'Devendra', 'Gujel' and 'Arjit', 'Gupta' --WHEN @SEARCHKEYWORD='Smith' --Desired OUTPUT: the row which contains 'Peter','Smith' and 'Dave','Smith'

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  • Excel VBA Text To Column

    - by Pat
    This is what I currently have: H101 John Doe Jane Doe Jack Doe H102 John Smith Jane Smith Katie Smith Jack Smith And here is what I want: H101 John Doe H101 Jane Doe H101 Jack Doe H102 John Smith H102 Jane Smith H102 Katie Smith H102 Jack Smith Obviously I want to do this on a bigger scale. The number of columns is between 1 & 6, so I cant limit it that way. I was able to get a script that allows me to put each individual on one row. However, I am having a hard time getting the first column to copy over to each row. Sub ToOneColumn() Dim i As Long, k As Long, j As Integer Application.ScreenUpdating = False Columns(2).Insert i = 0 k = 1 While Not IsEmpty(Cells(k, 3)) j = 3 While Not IsEmpty(Cells(k, j)) i = i + 1 Cells(i, 1) = Cells(k, 1) //CODE IN QUESTION Cells(i, 2) = Cells(k, j) Cells(k, j).Clear j = j + 1 Wend k = k + 1 Wend Application.ScreenUpdating = True End Sub Like I said, it was working fine to get everyone each on their own row, but can't figure out how to get that first column. It seems like it should be so simple, but it's bugging me. Any help is greatly appreciated.

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  • Completely remove user account and create another with same name in Windows 7

    - by TeaJay
    Here's my question simply and then the details in case they help to get me an appropriate answer. Question: How can I completely and permanently delete a user account in Windows 7 so that I can create another one with the same user name without the computer name extension added, eg Jane Smith not Jane Smith.computer name? The details: I just did a clean install of Windows 7 Professional 32 bit. (My laptop crashed, I reinstalled Vista and restored backup files but things weren't working so I decided to just get Windows 7 since I had to start over anyway). I used Windows Easy Transfer to save just about everything, even customizing to include a user's appdata from Windows.old which was created when I reinstalled Vista -- not knowing that another windows.old file would be created with the installation of Windows 7. After installing Windows 7, I used Windows Easy Transfer to transfer the user file, appdata, to the new user account which I gave the same name (Jane Smith) in case having a different name would cause problems with reading files or something. Afterwards, I realized that I did not want ALL of that junk. So, I thought no problem, I'll just delete the user account I just created, nothing lost, and create another one this time transferring only the files I wanted (using the customize option in windows easy transfer). I wanted to keep the same user name, e.g. Jane Smith, so after I deleted the user account I checked the files, and I didn't see. It was late so I went to bed and the next morning I created a new user with that same name (Jane Smith). The files looked fine if I remember correctly. Meanwhile, I updated the computer and it restarted a couple times. As I was moving files to the "Jane Smith" user account file, things weren't working as they should. I was actually moving files to the deleted user account and that the current user account was named "Jane Smith.computer name" and that's where the files needed to go. I don't like this. It's too confusing. I want just "Jane Smith". How can I do this without just changing the user name (which doesn't change it in the file path etc)? I want the first one GONE. If I can't do this, is it a problem to create an account with another name and still transfer files to it without path or other problems? I hope this question makes sense and that someone can help me. Thank you in advance!

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  • Help using left outer joins in SQL...

    - by Waffles
    I'm trying to create a list of people, their friends, and their friends of friends. My table of people is this: People: NAME Jow Smith Sandy Phil Friends LIKER LIKEE jow smith smith jow sandy phil Now, what I want is a table like this: User Friend FriendofFriend Jow smith jow Smith jow smith sandy phil phil I'm trying to create a table using the following: SELECT P.NAME, F.LIKEE, F2.LIKEE FROM PEOPLE P LEFT OUTER JOIN FRIENDS F ON P.NAME = F.LIKER LEFT OUTER JOIN FRIENDS F2 ON F.LIKEE = F2.LIKER But the above isn't working. How can I get a table of people and their friends, regardless of whether or not they actually HAVE any friends?

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  • One to many too much data returned - MySQL

    - by Evan McPeters
    I have 2 related MySQL tables in a one to many relationship. Customers: cust_id, cust_name, cust_notes Orders: order_id, cust_id, order_comments So, if I do a standard join to get all customers and their orders via PHP, I return something like: Jack Black, jack's notes, comments about jack's 1st order Jack Black, jack's notes, comments about jack's 2nd order Simon Smith, simon's notes, comments about simon's 1st order Simon Smith, simon's notes, comments about simon's 2nd order The problem is that *cust_notes* is a text field and can be quite large (a couple of thousand words). So, it seems like returning that field for every order is inneficient. I could use *GROUP_CONCAT* and JOINS to return all *order_comments* on a single row BUT order_comments is a large text field too, so it seems like that could create a problem. Should I just use two separate queries, one for the customers table and one for the orders table? Is there a better way?

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  • A Nondeterministic Engine written in VB.NET 2010

    - by neil chen
    When I'm reading SICP (Structure and Interpretation of Computer Programs) recently, I'm very interested in the concept of an "Nondeterministic Algorithm". According to wikipedia:  In computer science, a nondeterministic algorithm is an algorithm with one or more choice points where multiple different continuations are possible, without any specification of which one will be taken. For example, here is an puzzle came from the SICP: Baker, Cooper, Fletcher, Miller, and Smith live on different floors of an apartment housethat contains only five floors. Baker does not live on the top floor. Cooper does not live onthe bottom floor. Fletcher does not live on either the top or the bottom floor. Miller lives ona higher floor than does Cooper. Smith does not live on a floor adjacent to Fletcher's.Fletcher does not live on a floor adjacent to Cooper's. Where does everyone live? After reading this I decided to build a simple nondeterministic calculation engine with .NET. The rough idea is that we can use an iterator to track each set of possible values of the parameters, and then we implement some logic inside the engine to automate the statemachine, so that we can try one combination of the values, then test it, and then move to the next. We also used a backtracking algorithm to go back when we are running out of choices at some point. Following is the core code of the engine itself: Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--Public Class NonDeterministicEngine Private _paramDict As New List(Of Tuple(Of String, IEnumerator)) 'Private _predicateDict As New List(Of Tuple(Of Func(Of Object, Boolean), IEnumerable(Of String))) Private _predicateDict As New List(Of Tuple(Of Object, IList(Of String))) Public Sub AddParam(ByVal name As String, ByVal values As IEnumerable) _paramDict.Add(New Tuple(Of String, IEnumerator)(name, values.GetEnumerator())) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(1, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(2, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(3, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(4, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(5, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(6, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(7, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(8, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Sub CheckParamCount(ByVal count As Integer, ByVal paramNames As IList(Of String)) If paramNames.Count <> count Then Throw New Exception("Parameter count does not match.") End If End Sub Public Property IterationOver As Boolean Private _firstTime As Boolean = True Public ReadOnly Property Current As Dictionary(Of String, Object) Get If IterationOver Then Return Nothing Else Dim _nextResult = New Dictionary(Of String, Object) For Each item In _paramDict Dim iter = item.Item2 _nextResult.Add(item.Item1, iter.Current) Next Return _nextResult End If End Get End Property Function MoveNext() As Boolean If IterationOver Then Return False End If If _firstTime Then For Each item In _paramDict Dim iter = item.Item2 iter.MoveNext() Next _firstTime = False Return True Else Dim canMoveNext = False Dim iterIndex = _paramDict.Count - 1 canMoveNext = _paramDict(iterIndex).Item2.MoveNext If canMoveNext Then Return True End If Do While Not canMoveNext iterIndex = iterIndex - 1 If iterIndex = -1 Then Return False IterationOver = True End If canMoveNext = _paramDict(iterIndex).Item2.MoveNext If canMoveNext Then For i = iterIndex + 1 To _paramDict.Count - 1 Dim iter = _paramDict(i).Item2 iter.Reset() iter.MoveNext() Next Return True End If Loop End If End Function Function GetNextResult() As Dictionary(Of String, Object) While MoveNext() Dim result = Current If Satisfy(result) Then Return result End If End While Return Nothing End Function Function Satisfy(ByVal result As Dictionary(Of String, Object)) As Boolean For Each item In _predicateDict Dim pred = item.Item1 Select Case item.Item2.Count Case 1 Dim p1 = DirectCast(pred, Func(Of Object, Boolean)) Dim v1 = result(item.Item2(0)) If Not p1(v1) Then Return False End If Case 2 Dim p2 = DirectCast(pred, Func(Of Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) If Not p2(v1, v2) Then Return False End If Case 3 Dim p3 = DirectCast(pred, Func(Of Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) If Not p3(v1, v2, v3) Then Return False End If Case 4 Dim p4 = DirectCast(pred, Func(Of Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) If Not p4(v1, v2, v3, v4) Then Return False End If Case 5 Dim p5 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) If Not p5(v1, v2, v3, v4, v5) Then Return False End If Case 6 Dim p6 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) Dim v6 = result(item.Item2(5)) If Not p6(v1, v2, v3, v4, v5, v6) Then Return False End If Case 7 Dim p7 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) Dim v6 = result(item.Item2(5)) Dim v7 = result(item.Item2(6)) If Not p7(v1, v2, v3, v4, v5, v6, v7) Then Return False End If Case 8 Dim p8 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) Dim v6 = result(item.Item2(5)) Dim v7 = result(item.Item2(6)) Dim v8 = result(item.Item2(7)) If Not p8(v1, v2, v3, v4, v5, v6, v7, v8) Then Return False End If Case Else Throw New NotSupportedException End Select Next Return True End FunctionEnd Class    And now we can use the engine to solve the problem we mentioned above:   Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--Sub Test2() Dim engine = New NonDeterministicEngine() engine.AddParam("baker", {1, 2, 3, 4, 5}) engine.AddParam("cooper", {1, 2, 3, 4, 5}) engine.AddParam("fletcher", {1, 2, 3, 4, 5}) engine.AddParam("miller", {1, 2, 3, 4, 5}) engine.AddParam("smith", {1, 2, 3, 4, 5}) engine.AddRequire(Function(baker) As Boolean Return baker <> 5 End Function, {"baker"}) engine.AddRequire(Function(cooper) As Boolean Return cooper <> 1 End Function, {"cooper"}) engine.AddRequire(Function(fletcher) As Boolean Return fletcher <> 1 And fletcher <> 5 End Function, {"fletcher"}) engine.AddRequire(Function(miller, cooper) As Boolean 'Return miller = cooper + 1 Return miller > cooper End Function, {"miller", "cooper"}) engine.AddRequire(Function(smith, fletcher) As Boolean Return smith <> fletcher + 1 And smith <> fletcher - 1 End Function, {"smith", "fletcher"}) engine.AddRequire(Function(fletcher, cooper) As Boolean Return fletcher <> cooper + 1 And fletcher <> cooper - 1 End Function, {"fletcher", "cooper"}) engine.AddRequire(Function(a, b, c, d, e) As Boolean Return a <> b And a <> c And a <> d And a <> e And b <> c And b <> d And b <> e And c <> d And c <> e And d <> e End Function, {"baker", "cooper", "fletcher", "miller", "smith"}) Dim result = engine.GetNextResult() While Not result Is Nothing Console.WriteLine(String.Format("baker: {0}, cooper: {1}, fletcher: {2}, miller: {3}, smith: {4}", result("baker"), result("cooper"), result("fletcher"), result("miller"), result("smith"))) result = engine.GetNextResult() End While Console.WriteLine("Calculation ended.")End Sub   Also, this engine can solve the classic 8 queens puzzle and find out all 92 results for me.   Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--Sub Test3() ' The 8-Queens problem. Dim engine = New NonDeterministicEngine() ' Let's assume that a - h represents the queens in row 1 to 8, then we just need to find out the column number for each of them. engine.AddParam("a", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("b", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("c", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("d", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("e", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("f", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("g", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("h", {1, 2, 3, 4, 5, 6, 7, 8}) Dim NotInTheSameDiagonalLine = Function(cols As IList) As Boolean For i = 0 To cols.Count - 2 For j = i + 1 To cols.Count - 1 If j - i = Math.Abs(cols(j) - cols(i)) Then Return False End If Next Next Return True End Function engine.AddRequire(Function(a, b, c, d, e, f, g, h) As Boolean Return a <> b AndAlso a <> c AndAlso a <> d AndAlso a <> e AndAlso a <> f AndAlso a <> g AndAlso a <> h AndAlso b <> c AndAlso b <> d AndAlso b <> e AndAlso b <> f AndAlso b <> g AndAlso b <> h AndAlso c <> d AndAlso c <> e AndAlso c <> f AndAlso c <> g AndAlso c <> h AndAlso d <> e AndAlso d <> f AndAlso d <> g AndAlso d <> h AndAlso e <> f AndAlso e <> g AndAlso e <> h AndAlso f <> g AndAlso f <> h AndAlso g <> h AndAlso NotInTheSameDiagonalLine({a, b, c, d, e, f, g, h}) End Function, {"a", "b", "c", "d", "e", "f", "g", "h"}) Dim result = engine.GetNextResult() While Not result Is Nothing Console.WriteLine("(1,{0}), (2,{1}), (3,{2}), (4,{3}), (5,{4}), (6,{5}), (7,{6}), (8,{7})", result("a"), result("b"), result("c"), result("d"), result("e"), result("f"), result("g"), result("h")) result = engine.GetNextResult() End While Console.WriteLine("Calculation ended.")End Sub (Chinese version of the post: http://www.cnblogs.com/RChen/archive/2010/05/17/1737587.html) Cheers,  

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  • sudo: apache restarting a service on CentOS

    - by WaveyDavey
    I need my web app to restart the dansguardian service (on CentOS) so it needs to run '/sbin/service dansguardian restart' I have a shellscript in /home/topological called apacherestart.sh which does the following: #!/bin/sh id=`id` /sbin/service dansguardian restart r=$? return $r This runs ok (logger statement in script for testing output to syslog, so I know it's running) To make it run, I put this in /etc/sudoers: User_Alias APACHE=www # Cmnd alias specification Cmnd_Alias HTTPRESTART=/home/topological/apacherestart.sh,/sbin/e-smith/db,/etc/rc7.d/S91dansguardian # Defaults specification # User privilege specification root ALL=(ALL) ALL APACHE ALL=(ALL) NOPASSWD: HTTPRESTART So far so good. But the service does not restart. To test this I created a user david, and fudged the uid/gid in /etc/passwd to be the same as www: www:x:102:102:e-smith web server:/home/e-smith:/bin/false david:x:102:102:David:/home/e-smith/files/users/david:/bin/bash then logged in as david and tried to run the apacherestart.sh. The problem I get is: /etc/rc7.d/S91dansguardian: line 51: /sbin/e-smith/db: Permission denied even though S91dansguardian and db are in the sudoers command list. Any ideas?

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  • Multiple 301 redirect and massive loss of ranking

    - by DoesNotCompute
    I just remade from scratch a website for a client, the client ask me to preverve their ranking by making 301 redirect from the original URL to the new URL. For instance: http://plumber-directory.my-website.com/john-smith-city-1.php became http://directory.my-website.com/plumber/city/john-smith.html So i put the website online for few days until the 301 partially kicks in the google results. Then the client call me back to tell me that his boss want to switch back to the ancients URLs _< So i put a new 301 redirect: http://directory.my-website.com/plumber/city/john-smith.html revert to http://plumber-directory.my-website.com/john-smith-city-1.php Because google had just few days to assimilate the new URLs, it have now the two kinds of URLs in it's own result pages. Also the ranking of the website keeps falling down every day, i suspect google to mistaking those redirects for duplicate content. Is there something i can do to avoid a total loss of rankings?

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