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  • What does the following Regex expression do?

    - by Jim
    Hi, I would like to understand what the following code is doing. This logic is part of a routine to strip out html from the body of an email message. mBBSREgEx.IgnoreCase = True mBBSREgEx.Global = True mBBSREgEx.Pattern = "<[^>]*>" sResult = mBBSREgEx.Replace(sResult, "") Thank you, Jim

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  • On a Mac how to determine a user logout is occuring

    - by JIm
    Hello All, I am very new to the Mac platform and Objective-C in general and in my application I would like to know how to determine that a user is logging out and perform some actions prior to this. Any info or pointers for this will be greatly appreciated. Regards, -Jim

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  • how to create media player on iphone?

    - by Jim
    I want to create my own media player. There is so much restriction with default media player control on iphone. I have written lots of applications using default media player. Now i want to write my own media player.If any one can give pointer from where to start to create custom media player. Thanks in advance. Jim.

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  • How do I debug a ASP.NET application

    - by Jim McKintosh
    I have a ASP.NET application I've inherited from the person who did my job previously, when I try to debug the program I get the error below. "A project with an output type of class librart cannot be started directly" I'm familiar with desktop programs but I'm new to working with ASP.NET, the code is easy enough to understand but I can't get my head around how to successfully debug it. PS VS 2008 if that helps. Thanks Jim

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  • PHPFOG and MySql

    - by jim dif
    I am playing around with PHPFog and as a result I ended up with a MySql database. I am trying to figure out how to connect to it with a success message. PHPFog says use this: mysql_connect( $server = getenv('MYSQL_DB_HOST'), $username = getenv('MYSQL_USERNAME'), $password = getenv('MYSQL_PASSWORD')); mysql_select_db(getenv('MYSQL_DB_NAME')); So I basically plug my variables into the above? Or Do I do something different? Thanks, Jim

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  • Another void C# question

    - by Jim Jones
    Have a type in the header files I'm working with called VTVOID it is the type of a struct element and a number of parameters. In the header file defining types is the line #define VTVOID void I read in another discussion the void maps to System.Void however when I plug that into the C# code I get the error "System.Void cannot be used in C# -- use typeof(void) to get the void object." So what type do I plug in? Jim

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  • Retour de fonctions ou exceptions ? Une traduction de LittleWhite

    Bonjour à tous, Lorsqu'une erreur se produit dans une fonction, un développeur C++ a deux solutions : il peut soit retourner une valeur indiquant une erreur (par exemple avec return false; ou return ERROR_CODE;), soit lancer une exception. Mais quelle est la meilleure approche ? Dans cet article, Aaron Lahman apporte des éléments de réponse à cette question cruciale en regardant les différences en terme de lisibilité et d...

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  • Multiple SSL Certificates Running on Mac OS X 10.6

    - by frodosghost.mp
    I have been running into walls with this for a while, so I posted at stackoverflow, and I was pointed over here... I am attempting to setup multiple IP addresses on Snow Leopard so that I can develop with SSL certificates. I am running XAMPP - I don't know if that is the problem, but I guess I would run into the same problems, considering the built in apache is turned off. So first up I looked into starting up the IPs on start up. I got up an running with a new StartupItem that runs correctly, because I can ping the ip address: ping 127.0.0.2 ping 127.0.0.1 And both of them work. So now I have IP addresses, which as you may know are not standard on OSx. I edited the /etc/hosts file to include the new sites too: 127.0.0.1 site1.local 127.0.0.2 site2.local I had already changed the httpd.conf to use the httpd-vhosts.conf - because I had a few sites running on the one IP address. I have edited the vhosts file so a site looks like this: <VirtualHost 127.0.0.1:80> DocumentRoot "/Users/jim/Documents/Projects/site1/web" ServerName site1.local <Directory "/Users/jim/Documents/Projects/site1"> Order deny,allow Deny from All Allow from 127.0.0.1 AllowOverride All </Directory> </VirtualHost> <VirtualHost 127.0.0.1:443> DocumentRoot "/Users/jim/Documents/Projects/site1/web" ServerName site1.local SSLEngine On SSLCertificateFile "/Applications/XAMPP/etc/ssl-certs/myssl.crt" SSLCertificateKeyFile "/Applications/XAMPP/etc/ssl-certs/myssl.key" SetEnvIf User-Agent ".*MSIE.*" nokeepalive ssl-unclean-shutdown <Directory "/Users/jim/Documents/Projects/site1"> Order deny,allow Deny from All Allow from 127.0.0.1 AllowOverride All </Directory> </VirtualHost> In the above code, you can change the 1's to 2's and it is the setup for the second site. They do use the same certificate, which is why they are on different IP addresses. I also included the NameVirtualHost information at the top of the file: NameVirtualHost 127.0.0.1:80 NameVirtualHost 127.0.0.2:80 NameVirtualHost 127.0.0.1:443 NameVirtualHost 127.0.0.2:443 I can ping site1.local and site2.local. I can use telnet ( telnet site2.local 80 ) to get into both sites. But in Safari I can only get to the first site1.local - navigating to site2.local gives me either the localhost main page (which is included in the vhosts) or gives me a Access forbidden!. I am usure what to do, any suggestions would be awesome.

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  • Multiple SSL Certificates Running on Mac OS X 10.6

    I have been running into walls with this for a while, so I posted at stackoverflow, and I was pointed over here... I am attempting to setup multiple IP addresses on Snow Leopard so that I can develop with SSL certificates. I am running XAMPP - I don't know if that is the problem, but I guess I would run into the same problems, considering the built in apache is turned off. So first up I looked into starting up the IPs on start up. I got up an running with a new StartupItem that runs correctly, because I can ping the ip address: ping 127.0.0.2 ping 127.0.0.1 And both of them work. So now I have IP addresses, which as you may know are not standard on OSx. I edited the /etc/hosts file to include the new sites too: 127.0.0.1 site1.local 127.0.0.2 site2.local I had already changed the httpd.conf to use the httpd-vhosts.conf - because I had a few sites running on the one IP address. I have edited the vhosts file so a site looks like this: <VirtualHost 127.0.0.1:80> DocumentRoot "/Users/jim/Documents/Projects/site1/web" ServerName site1.local <Directory "/Users/jim/Documents/Projects/site1"> Order deny,allow Deny from All Allow from 127.0.0.1 AllowOverride All </Directory> </VirtualHost> <VirtualHost 127.0.0.1:443> DocumentRoot "/Users/jim/Documents/Projects/site1/web" ServerName site1.local SSLEngine On SSLCertificateFile "/Applications/XAMPP/etc/ssl-certs/myssl.crt" SSLCertificateKeyFile "/Applications/XAMPP/etc/ssl-certs/myssl.key" SetEnvIf User-Agent ".*MSIE.*" nokeepalive ssl-unclean-shutdown <Directory "/Users/jim/Documents/Projects/site1"> Order deny,allow Deny from All Allow from 127.0.0.1 AllowOverride All </Directory> </VirtualHost> In the above code, you can change the 1's to 2's and it is the setup for the second site. They do use the same certificate, which is why they are on different IP addresses. I also included the NameVirtualHost information at the top of the file: NameVirtualHost 127.0.0.1:80 NameVirtualHost 127.0.0.2:80 NameVirtualHost 127.0.0.1:443 NameVirtualHost 127.0.0.2:443 I can ping site1.local and site2.local. I can use telnet ( telnet site2.local 80 ) to get into both sites. But in Safari I can only get to the first site1.local - navigating to site2.local gives me either the localhost main page (which is included in the vhosts) or gives me a Access forbidden!. I am usure what to do, any suggestions would be awesome.

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  • Add 2 values to 1 key in a PHP array

    - by Mike Munroe
    I have a result set of data that I want to write to an array in php. Here is my sample data: **Name** **Abbrev** Mike M Tom T Jim J Using that data, I want to create an array in php that is of the following: 1|Mike|M 2|Tom|T 3|Jim|j I tried array_push($values, 'name', 'abbreviation') [pseudo code], which gave me the following: 1|Mike 2|M 3|Tom 4|T 5|Jim 6|J I need to do a look up against this array to get the same key value, if I look up "Mike" or "M". What is the best way to write my result set into an array as set above where name and abbreviation share the same key?

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  • Join one row to multiple rows in another table

    - by Ghostrider
    I have a table to entities (lets call them people) and properties (one person can have an arbitrary number of properties). Ex: People Name Age -------- Jane 27 Joe 36 Jim 16 Properties Name Property ----------------- Jane Smart Jane Funny Jane Good-looking Joe Smart Joe Workaholic Jim Funny Jim Young I would like to write an efficient select that would select people based on age and return all or some of their properties. Ex: People older than 26 Name Properties Jane Smart, Funny, Good-looking Joe Smart, Workaholic It's also acceptable to return one of the properties and total property count. The query should be efficient: there are millions of rows in people table, hundreds of thousands of rows in properties table (so most people have no properties). There are hundreds of rows selected at a time. Is there any way to do it?

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  • Match HTML tags in two strings using regex in Python

    - by jack
    I want to verify that the HTML tags present in a source string are also present in a target string. For example: >> source = '<em>Hello</em><label>What's your name</label>' >> verify_target(’<em>Hi</em><label>My name is Jim</label>') True >> verify_target('<label>My name is Jim</label><em>Hi</em>') True >> verify_target('<em>Hi<label>My name is Jim</label></em>') False

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  • Jasper Reports Crosstab Query

    - by Sean McDaid
    I'm using Jasper Reports/iReports crosstabs to create a matrix of student and results. So for example Jim is doing subjects A, B, C and Sally is doing A, C What I want is something like: Subj-A Subj-B Subj-C Jim P M D Sally D D But as my SQL orders by name then subject I get: Subj-A Subj-B Subj-C Subj-A Subj-C Jim P M D Sally D D As you can see in the above the results are correct but the formatting is woeful. Is there anyway I can generate the reports to use names and subject only once and filling in the values from here? This probably isn't clear.

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  • Complicated MySQL query?

    - by Scott
    I have two tables: RatingsTable that contains a ratingname and a bit whether it is a positive or negative rating: Good 1 Bad 0 Fun 1 Boring 0 FeedbackTable that contains feedback on things...the person rating, the rating and the thing rated. The feedback can be determined if it's a positive or negative rating based on RatingsTable. Jim Chicken Good Jim Steak Bad Ted Waterskiing Fun Ted Hiking Fun Nancy Hiking Boring I am trying to write an efficient MySQL query for the following: On a page, I want to display the the top 'things' that have the highest proportional positive ratings. I want to be sure that the items from the feedback table are unique...meaning, that if Jim has rated Chicken Good 20 times...it should only be counted once. At some point I will want to require a minimum number of ratings (at least 10) to be counted for this page as well. I'll want to to do the same for highest proportional negative ratings, but I am sure I can tweak the one for positive accordingly.

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  • How to convert submitted form array to this array on php?

    - by drfanai
    Lets suppose i have the following array submitted by a html form: array( 'firstname' => array('Sara','Jim'), 'lastname' => array('Gibson','Jobs') ); What i wanna achieve is the following array: array( array( 'firstname' => 'sara', 'lastname' => 'Gibson' ), array( 'firstname' => 'Jim', 'lastname' => 'Jim' ) ); I need a function to automatically sort the array not manually by entering data but automatically processing array data.

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  • HAProxy reqrep remove URI on backend request

    - by Jim
    real quick question regarding HAProxy reqrep. I am trying to rewrite/replace the request that gets sent to the backend. I have the following example domain and URIs http://domain/web1 http://domain/web2 I want web1 to go to backend webfarm1, and web2 to go to webfarm2. Currently this does happen. However I want to strip off the web1 or web2 URI when the request is sent to the backend. Here is my haproxy.cfg frontend webVIP_80 mode http bind :80 #acl routing to backend acl web1_path path_beg /web1 acl web2_path path_beg /web2 #which backend use_backend webfarm1 if web1_path use_backend webfarm2 if web2_path default_backend webfarm1 backend webfarm1 mode http reqrep ^([^\ ]*)\ /web1/(.*) \1\ /\2 balance roundrobin option httpchk HEAD /index HTTP/1.1\r\nHost:\ example.com server webtest1 10.0.0.10:80 weight 5 check slowstart 5000ms server webtest2 10.0.0.20:80 weight 5 check slowstart 5000ms backend webfarm2 mode http reqrep ^([^\ ]*)\ /web2/(.*) \1\ /\2 balance roundrobin option httpchk HEAD /index HTTP/1.1\r\nHost:\ example.com server webtest1-farm2 10.0.0.110:80 weight 5 check slowstart 5000ms server webtest2-farm2 10.0.0.120:80 weight 5 check slowstart 5000ms If I go to http://domain/web1 or http://domain/web2 I see it in the error logs that the request on a server in each backend that the requst is for the resource /web1 or /web2 respectively. Therefore I believe there to be something wrong with my regular expression, even though I copied and pasted it from the Documentation. http://code.google.com/p/haproxy-docs/wiki/reqrep Summary: I'm trying to route traffic based on URI, however I want to strip the URI on the backend side. Go to http://domain/web1 -- backend request of / to webfarm1 Thank you! -Jim

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  • Connectivity with SQL Server Express 2008 r2 and SQL Server 2000 on same machine

    - by Jim R
    At first glance this may same a duplicate of Installing both SQL Server 2000 and SQL Server 2008 on the same machine, but it is not. I have SQL Server 2000 and SQL Server 2008 R2 installed on the same machine and working fine. My problem lies with connecting to the 2008 R2 server from a remote machine. My connectivity needs to be TCP. The legacy installation or SQL 2000 uses the default port of 1433. The named instance is by default configured to use 'Shared Memory' and is working fine. When I configured the 2008 R2 server to use 1433 (I did not think that thru) the service refused to start becasue 1433 was already in use by the legacy SQL 2000 default instance. Doh! What I want to do is have both servers available simultaneously via TCP. both servers need not be on the same port, put if I cannot run them on the same port, then how do I configure the clients? Is there not some kind of proxy available that can monitor the 1433 port and pass the request thru to the correct SQL instance by name? Is this capability built into SQL server already? Thanks, Jim

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  • Converting a Windows 2003 server

    - by Jim Bass
    We have a legacy database system based upon MS SQL running on Windows Server 2003. The client software will only run on Windows XP. We have recently had success converting a client into a virtual machine and running it under Fusion on Mac minis. So far, it is working incredibly well. So well, in fact, that we are now considering trying to convert the server to a virtual machine. This raises several questions, though: 1. The server uses a raid array. Does the VM virtualize the raid array? I only ask because in my experience Windows products don't like it when you change core hardware. 2. Is there any reason why running SQL server on a virtual machine won't work? It will be up 24/7. 3. Is there a different converter for servers? 4. Will I have to track down the licensing for MS SQL and Server 2003 or will they come across ok? 5. The company that designed the software is no longer in business. There is some fear that the software is somehow tied to the hardware configuration. We bought the hardware, but their engineers came out and configured the system. Will the virtual machine be able to spoof particular chip sets? Thanks! Jim Bass

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