Search Results

Search found 2455 results on 99 pages for 'lambda expressions'.

Page 3/99 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • Specializing a template on a lambda in C++0x

    - by Tony A.
    I've written a traits class that lets me extract information about the arguments and type of a function or function object in C++0x (tested with gcc 4.5.0). The general case handles function objects: template <typename F> struct function_traits { template <typename R, typename... A> struct _internal { }; template <typename R, typename... A> struct _internal<R (F::*)(A...)> { // ... }; typedef typename _internal<decltype(&F::operator())>::<<nested types go here>>; }; Then I have a specialization for plain functions at global scope: template <typename R, typename... A> struct function_traits<R (*)(A...)> { // ... }; This works fine, I can pass a function into the template or a function object and it works properly: template <typename F> void foo(F f) { typename function_traits<F>::whatever ...; } int f(int x) { ... } foo(f); What if, instead of passing a function or function object into foo, I want to pass a lambda expression? foo([](int x) { ... }); The problem here is that neither specialization of function_traits<> applies. The C++0x draft says that the type of the expression is a "unique, unnamed, non-union class type". Demangling the result of calling typeid(...).name() on the expression gives me what appears to be gcc's internal naming convention for the lambda, main::{lambda(int)#1}, not something that syntactically represents a C++ typename. In short, is there anything I can put into the template here: template <typename R, typename... A> struct function_traits<????> { ... } that will allow this traits class to accept a lambda expression?

    Read the article

  • Lambda&rsquo;s for .NET made easy&hellip;

    - by mbcrump
    The purpose of my blog is to explain things for a beginner to intermediate c# programmer. I’ve seen several blog post that use lambda expressions always assuming the audience is familiar with them. The purpose of this post is to make them simple and easily understood. Let’s begin with a definition. A lambda expression is an anonymous function that can contain expressions and statements, and can be used to create delegates or expression tree types. So anonymous function… delegates or expression tree types? I don’t get it??? Confused yet?   Lets break this into a few definitions and jump right into the code. anonymous function – is an "inline" statement or expression that can be used wherever a delegate type is expected. delegate - is a type that references a method. Once a delegate is assigned a method, it behaves exactly like that method. The delegate method can be used like any other method, with parameters and a return value. Expression trees - represent code in a tree-like data structure, where each node is an expression, for example, a method call or a binary operation such as x < y.   Don’t worry if this still sounds confusing, lets jump right into the code with a simple 3 line program. We are going to use a Function Delegate (all you need to remember is that this delegate returns a value.) Lambda expressions are used most commonly with the Func and Action delegates, so you will see an example of both of these. Lambda Expression 3 lines. using System; using System.Collections.Generic; using System.Linq; using System.Text;   namespace ConsoleApplication7 {     class Program     {          static void Main(string[] args)         {             Func<int, int> myfunc = x => x *x;             Console.WriteLine(myfunc(6).ToString());             Console.ReadLine();         }       } } Is equivalent to Old way of doing it. using System; using System.Collections.Generic; using System.Linq; using System.Text;   namespace ConsoleApplication7 {     class Program     {          static void Main(string[] args)         {               Console.WriteLine(myFunc(6).ToString());             Console.ReadLine();         }            static int myFunc(int x)          {              return x * x;            }       } } In the example, there is a single parameter, x, and the expression is x*x. I’m going to stop here to make sure you are still with me. A lambda expression is an unnamed method written in place of a delegate instance. In other words, the compiler converts the lambda expression to either a : A delegate instance An expression tree All lambda have the following form: (parameters) => expression or statement block Now look back to the ones we have created. It should start to sink in. Don’t get stuck on the => form, use it as an identifier of a lambda. A Lamba expression can also be written in the following form: Lambda Expression. using System; using System.Collections.Generic; using System.Linq; using System.Text;   namespace ConsoleApplication7 {     class Program     {          static void Main(string[] args)         {             Func<int, int> myFunc = x =>             {                 return x * x;             };               Console.WriteLine(myFunc(6).ToString());             Console.ReadLine();         }       } } This form may be easier to read but consumes more space. Lets try an Action delegate – this delegate does not return a value. Action Delegate example. using System; using System.Collections.Generic; using System.Linq; using System.Text;   namespace ConsoleApplication7 {     class Program     {          static void Main(string[] args)         {             Action<string> myAction = (string x) => { Console.WriteLine(x); };             myAction("michael has made this so easy");                                   Console.ReadLine();         }       } } Lambdas can also capture outer variables (such as the example below) A lambda expression can reference the local variables and parameters of the method in which it’s defined. Outer variables referenced by a lambda expression are called captured variables. Capturing Outer Variables using System; using System.Collections.Generic; using System.Linq; using System.Text;   namespace ConsoleApplication7 {     class Program     {          static void Main(string[] args)         {             string mike = "Michael";             Action<string> myAction = (string x) => {                 Console.WriteLine("{0}{1}", mike, x);          };             myAction(" has made this so easy");                                   Console.ReadLine();         }       } } Lamba’s can also with a strongly typed list to loop through a collection.   Used w a strongly typed list. using System; using System.Collections.Generic; using System.Linq; using System.Text;   namespace ConsoleApplication7 {     class Program     {          static void Main(string[] args)         {             List<string> list = new List<string>() { "1", "2", "3", "4" };             list.ForEach(s => Console.WriteLine(s));             Console.ReadLine();         }       } } Outputs: 1 2 3 4 I think this will get you started with Lambda’s, as always consult the MSDN documentation for more information. Still confused? Hopefully you are not.

    Read the article

  • QotD: Maurizio Cimadamore on Project Lambda Binary Snapshots

    - by $utils.escapeXML($entry.author)
    I'm glad to announce that the first binary snapshots of the lambda repository are available at the following URL:http://jdk8.java.net/lambda/As you can imagine, as the implementation of the compiler/libraries is still under heavy development, there are still many rough corners that need to be polished. I'd like to thank you all for all the patience and the valuable feedback provided so far - please keep it coming!Maurizio Cimadamore announcing the Project Lambda binary snapshots on the lambda-dev OpenJDK mailing list.

    Read the article

  • lambda traits inconsistency across C++0x compilers

    - by Sumant
    I observed some inconsistency between two compilers (g++ 4.5, VS2010 RC) in the way they match lambdas with partial specializations of class templates. I was trying to implement something like boost::function_types for lambdas to extract type traits. Check this for more details. In g++ 4.5, the type of the operator() of a lambda appears to be like that of a free standing function (R (*)(...)) whereas in VS2010 RC, it appears to be like that of a member function (R (C::*)(...)). So the question is are compiler writers free to interpret any way they want? If not, which compiler is correct? See the details below. template <typename T> struct function_traits : function_traits<decltype(&T::operator())> { // This generic template is instantiated on both the compilers as expected. }; template <typename R, typename C> struct function_traits<R (C::*)() const> { // inherits from this one on VS2010 RC typedef R result_type; }; template <typename R> struct function_traits<R (*)()> { // // inherits from this one g++ 4.5 typedef R result_type; }; int main(void) { auto lambda = []{}; function_traits<decltype(lambda)>::result_type *r; // void * } This program compiles on both g++ 4.5 and VS2010 but the function_traits that are instantiated are different as noted in the code.

    Read the article

  • How to convert a lambda to an std::function using templates

    - by retep998
    Basically, what I want to be able to do is take a lambda with any number of any type of parameters and convert it to an std::function. I've tried the following and neither method works. std::function([](){});//Complains that std::function is missing template parameters template <typename T> void foo(function<T> f){} foo([](){});//Complains that it cannot find a matching candidate The following code does work however, but it is not what I want because it requires explicitly stating the template parameters which does not work for generic code. std::function<void()>([](){}); I've been mucking around with functions and templates all evening and I just can't figure this out, so any help would be much appreciated. As mentioned in a comment, the reason I'm trying to do this is because I'm trying to implement currying in C++ using variadic templates. Unfortunately, this fails horribly when using lambdas. For example, I can pass a standard function using a function pointer. template <typename R, typename...A> void foo(R (*f)(A...)) {} void bar() {} int main() { foo(bar); } However, I can't figure out how to pass a lambda to such a variadic function. Why I'm interested in converting a generic lambda into an std::function is because I can do the following, but it ends up requiring that I explicitly state the template parameters to std::function which is what I am trying to avoid. template <typename R, typename...A> void foo(std::function<R(A...)>) {} int main() { foo(std::function<void()>([](){})); }

    Read the article

  • Python, lambda, find minimum

    - by qba
    I have foreach function which calls specified function on every element which it contains. I want to get minimum from thise elements but I have no idea how to write lambda or function or even a class that would manage that. Thanks for every help. I use my foreach function like this: o.foreach( lambda i: i.call() ) or o.foreach( I.call ) I don't like to make a lists or other objects. I want to iterate trough it and find min. I manage to write a class that do the think but there should be some better solution than that: class Min: def __init__(self,i): self.i = i def get_min(self): return self.i def set_val(self,o): if o.val < self.i: self.i = o.val m = Min( xmin ) self.foreach( m.set_val ) xmin = m.get_min() Ok, so I suppose that my .foreach method is non-python idea. I should do my Class iterable because all your solutions are based on lists and then everything will become easier. In C# there would be no problem with lambda function like that, so I though that python is also that powerful.

    Read the article

  • regular expressions: love or hate or alternatives?

    - by yamspog
    While I can see the value and usefulness of regular expressions, I also find that they are extremely complicated and difficult to create and debug. I am often at the point where I find their usefulness is offset by the difficulty in creating expressions. I am a bit astonished by the fact that there is nothing quite like them and that there hasn't been an effort to recreate them use a more verbose or less arcane syntax. so, are regular expressions here to stay? are there alternatives that are gaining traction? do other people just ignore them and write hundreds of lines of string compare functions?

    Read the article

  • Is it possible to define a generic lambda?

    - by Mike OBrien
    I have some logic in a method that operates on a specified type and I'd like to create a generic lambda that encapsulates the logic. This is the spirit of what I'm trying to do: public void DoSomething() { // ... Func<T> GetTypeName = () => T.GetType().Name; GetTypeName<string>(); GetTypeName<DateTime>(); GetTypeName<int>(); // ... } I know I can pass the type as a parameter or create a generic method but I'm interested if it can just be a generic lambda (So I'm not looking for alternatives). From what I can tell C# 3.0 doesn't support this. TIA, m

    Read the article

  • c# Delegates, Events and Lambda Expr for new students

    - by MarkP
    I've been asked by my pointy haired boss to educate our new co-ops (interns) in the ways of C#. I have roughly ~30mins to cover the topics of Delegates, Events and Lambda Expressions. The time restriction is rather tight and the topics are broad. Since I'm not a C# guru, I would like some hints and pointers. Since my time is short, what points should I cover with respect to the three topics listed above? What are some good Do's and Dont's when using those three things? I might have time for a short Lambda Expr demo. What is the most common use of LExpr (probably a Select().Where() statement on an enumerable??) that I could demo? Thanks. EDIT: The students have working knowledge of C++ and Java.

    Read the article

  • Lambda "if" statement?

    - by AndyC
    I have 2 objects, both of which I want to convert to dictionarys. I use toDictionary<(). The lambda expression for one object to get the key is (i = i.name). For the other, it's (i = i.inner.name). In the second one, i.name doesn't exist. i.inner.name ALWAYS exists if i.name doesn't. Is there a lambda expression I can use to combine these two? Basically to read as: "if i.name exists then set id to i.name, else set id to i.inner.name". Many thanks.

    Read the article

  • Windows: File copy/move with filename regular expressions?

    - by Ian Boyd
    i basically want to run: C:\>xcopy [0-9]{13}\.(gif|jpg|png) s:\TargetFolder /s i know xcopy doesn't support regular-express filename searches. i can't find out how to find out if PowerShell has a Cmdlet to copy files; and if it does, how to find out if it supports regular expression filename matching. Can anyone think of a way to perform a recursive file copy/move with regex filename matching?

    Read the article

  • Inspiring problems to show off the importance of regular expressions?

    - by ragu.pattabi
    I am planning to give a presentation/demonstration on regular expressions at work to encourage young developers to add this powerful and important tool in their toolbox. Just teaching syntax doesn't cut it. I often see people say nice. After the presentation, they get on with their programming lives without ever thinking of using it mostly. I am raking my grey matter to come up with some solid examples, not just problems that matches 'cat' and 'cut'. I missed to note down the occasions of my regex enlightenments to use here. :^( Do you have some inspiring problems to share that could be solved with regex?

    Read the article

  • Can non-IT people learn and take advantage of regular expressions? [closed]

    - by user1598390
    Often times, not-IT people has to deal with massive text data, clean it, filter it, modify it. Often times normal office tools like Excel lack the tools to make complex search and replace operations on text. Could this people benefit from regexps ? Can regexp be taught to them ? Are regular expressions the exclusive domain of programmers and unix/linux technicians ? Can they be learned by non-IT people, given regexps are not a programming language? Is this a valid or achievable goal to make some users regexp-literate through appopriate training ? Have you have any experiences on this issue? and if so, have it been successful ?

    Read the article

  • Regular Expressions Cookbook Code Samples

    - by Jan Goyvaerts
    %COOKBOOKFRAME% One of the common criticisms against the first edition was that we didn’t have the regular expressions and code samples available for download. Since our book only has very short code snippets rather than complete programs, we (the authors) did not have these available as separate files either. But for the second edition we’re trying to do better. You can now download the code samples from the 2nd edition of Regular Expressions Cookbook. This HTML file contains all the blocks with regular expressions and source code from the book, along with the titles of the chapters, recipes, and sections that they are found in. If you have purchased the book, you can use this file to easily copy and paste the regular expressions and source code snippets. Even if you purchased the ebook, you may prefer to use this file. The regexes in the ebook are formatted with line breaks and gray dots for spaces to make them easier to read in print. The HTML file does not use such formatting, so you can copy and paste them directly. This means that some very regexes will run beyond the edge of your browser window.

    Read the article

  • Multiple Conditions in Lambda Expressions at runtime C#

    - by Ryan
    Hi, I would like to know how to be able to make an Expression tree by inputting more than one parameter Example: dataContext.Users.Where(u => u.username == "Username" && u.password == "Password") At the moment the code that I did was the following but would like to make more general in regards whether the condition is OR or AND public Func<TLinqEntity, bool> ANDOnlyParams(string[] paramNames, object[] values) { List<ParameterExpression> paramList = new List<ParameterExpression>(); foreach (string param in paramNames) { paramList.Add(Expression.Parameter(typeof(TLinqEntity), param)); } List<LambdaExpression> lexList = new List<LambdaExpression>(); for (int i = 0; i < paramNames.Length; i++) { if (i == 0) { Expression bodyInner = Expression.Equal( Expression.Property( paramList[i], paramNames[i]), Expression.Constant(values[i])); lexList.Add(Expression.Lambda(bodyInner, paramList[i])); } else { Expression bodyOuter = Expression.And( Expression.Equal( Expression.Property( paramList[i], paramNames[i]), Expression.Constant(values[i])), Expression.Invoke(lexList[i - 1], paramList[i])); lexList.Add(Expression.Lambda(bodyOuter, paramList[i])); } } return ((Expression<Func<TLinqEntity, bool>>)lexList[lexList.Count - 1]).Compile(); } Thanks

    Read the article

  • C# and F# lambda expressions code generation

    - by ControlFlow
    Let's look at the code, generated by F# for simple function: let map_add valueToAdd xs = xs |> Seq.map (fun x -> x + valueToAdd) The generated code for lambda expression (instance of F# functional value) will looks like this: [Serializable] internal class map_add@3 : FSharpFunc<int, int> { public int valueToAdd; internal map_add@3(int valueToAdd) { this.valueToAdd = valueToAdd; } public override int Invoke(int x) { return (x + this.valueToAdd); } } And look at nearly the same C# code: using System.Collections.Generic; using System.Linq; static class Program { static IEnumerable<int> SelectAdd(IEnumerable<int> source, int valueToAdd) { return source.Select(x => x + valueToAdd); } } And the generated code for the C# lambda expression: [CompilerGenerated] private sealed class <>c__DisplayClass1 { public int valueToAdd; public int <SelectAdd>b__0(int x) { return (x + this.valueToAdd); } } So I have some questions: Why does F#-generated class is not marked as sealed? Why does F#-generated class contains public fields since F# doesn't allows mutable closures? Why does F# generated class has the constructor? It may be perfectly initialized with the public fields... Why does C#-generated class is not marked as [Serializable]? Also classes generated for F# sequence expressions are also became [Serializable] and classes for C# iterators are not.

    Read the article

  • Trouble move-capturing std::unique_ptr in a lambda using std::bind

    - by user2478832
    I'd like to capture a variable of type std::vector<std::unique_ptr<MyClass>> in a lambda expression (in other words, "capture by move"). I found a solution which uses std::bind to capture unique_ptr (http://stackoverflow.com/a/12744730/2478832) and decided to use it as a starting point. However, the most simplified version of the proposed code I could get doesn't compile (lots of template mistakes, it seems to try to call unique_ptr's copy constructor). #include <functional> #include <memory> std::function<void ()> a(std::unique_ptr<int>&& param) { return std::bind( [] (int* p) {}, std::move(param)); } int main() { a(std::unique_ptr<int>(new int())); } Can anybody point out what is wrong with this code? EDIT: tried changing the lambda to take a reference to unique_ptr, it still doesn't compile. #include <functional> #include <memory> std::function<void ()> a(std::unique_ptr<int>&& param) { return std::bind( [] (std::unique_ptr<int>& p) {}, // also as a const reference std::move(param)); } int main() { a(std::unique_ptr<int>(new int())); }

    Read the article

  • Use Lambda in Attribute constructor to get method's parameters

    - by Anthony Shaw
    I'm not even sure if this is possible, but I've exhausted all of my ideas trying to figure this out, so I figured I'd send this out to the community and see what you thought. And, if it's not possible, maybe you'd have some ideas as well. I'm trying to make an Attribute class that I can add to a method that would allow me to use a lambda expression to get each parameter of the method public ExampleAttribute : Attribute { public object Value { get; set; } public ExampleAttribute(--something here to make the lambda work--, object value) { Value = value; } } I'd like to be able to something like this below: [Example(x=x.Id, 4)] [Example(x=x.filter, "string value")] public ActionResult Index(int Id, string filter) { return View(); } I understand that I might be completely dreaming with this idea. I'm basically trying to write a model to allow for self-documenting REST API Documentation. In a recent project here at work we wrote a dozen or so services with 5 to 15 methods on each, I figure it's easier to write something to do this, than to hand code a documentation page for each. I would plan to eventually release this as an open-source project once I have it in a place that I feel it's releasable.

    Read the article

  • Boost lambda: Invoke method on object

    - by ckarras
    I'm looking at boost::lambda as a way to to make a generic algorithm that can work with any "getter" method of any class. The algorithm is used to detect duplicate values of a property, and I would like for it to work for any property of any class. In C#, I would do something like this: class Dummy { public String GetId() ... public String GetName() ... } IEnumerable<String> FindNonUniqueValues<ClassT> (Func<ClassT,String> propertyGetter) { ... } Example use of the method: var duplicateIds = FindNonUniqueValues<Dummy>(d => d.GetId()); var duplicateNames = FindNonUniqueValues<Dummy>(d => d.GetName()); I can get the for "any class" part to work, using either interfaces or template methods, but have not found yet how to make the "for any method" part work. Is there a way to do something similar to the "d = d.GetId()" lambda in C++ (either with or without Boost)? Alternative, more C++ian solutions to make the algorithm generic are welcome too. I'm using C++/CLI with VS2008, so I can't use C++0x lambdas.

    Read the article

  • Lambda Functions in PHP aren't Logical

    - by Chacha102
    Note: I have condensed this article into my person wiki: http://wiki.chacha102.com/Lambda - Enjoy I am having some troubles with Lambda style functions in PHP. First, This Works: $foo = function(){ echo "bar"; }; $foo(); Second, This Works: class Bar{ public function foo(){ echo "Bar"; } Third, This works: $foo = new stdClass; $foo->bar = function(){ echo "bar"; }; $test = $foo->bar; $test(); But, this does not work: $foo = new stdClass; $foo->bar = function(){ echo "bar"; }; $foo->bar(); And, this does not work class Bar{ public function foo(){ echo "Bar"; } $foo = new Bar; $foo->foo = function(){ echo "foo"; }; $foo->foo(); // echo's bar instead of Foo. My Question is Why?, and how can I assure that both this: $foo->bar = function(){ echo "test"; }; $foo->bar(); and this $foo = new Bar; $foo->bar(); are called properly? Extra Points if you can point to documentation stating why this problem occurs.

    Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >