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  • Finding the lowest average Hamming distance when the order of the strings matter

    - by user1049697
    I have a sequence of binary strings that I want to find a match for among a set of longer sequences of binary strings. A match means that the compared sequence gives the lowest average Hamming distance when all elements in the shorter sequence have been matched against a sequence in one of the longer sets. Let me try to explain with an example. I have a set of video frames that have been hashed using a perceptual hashing algorithm so that the video frames that look the same has roughly the same hash. I want to match a short video clip against a set of longer videos, to see if the clip is contained in one of these. This means that I need to find out where the sequence of the hashed frames in the short video has the lowest average Hamming distance when compared with the long videos. The short video is the sub strings Sub1, Sub2 and Sub3, and I want to match them against the hashes of the long videos in Src. The clue here is that the strings need to match in the specific order that they are given in, e.g. that Sub1 always has to match the element before Sub2, and Sub2 always has to match the element before Sub3. In this example it would map thusly: Sub1-Src3, Sub2-Src4 and Sub3-Src5. So the question is this: is there an algorithm for finding the lowest average Hamming distance when the order of the elements compared matter? The naïve approach to compare the substring sequence to every source string won't cut it of course, so I need something that preferably can match a (much) shorter sub string to a set of million of elements. I have looked at MVP-trees, BK-trees and similar, but everything seems to only take into account one binary string and not a sequence of them. Sub1: 100111011111011101 Sub2: 110111000010010100 Sub3: 111111010110101101 Src1: 001011010001010110 Src2: 010111101000111001 Src3: 101111001110011101 Src4: 010111100011010101 Src5: 001111010110111101 Src6: 101011111111010101 I have added a calculation of the examples below. (The Hamming distances aren't correct, but it doesn't matter) **Run 1.** dist(Sub1, Src1) = 8 dist(Sub2, Src2) = 10 dist(Sub3, Src3) = 12 average = 10 **Run 2.** dist(Sub1, Src2) = 10 dist(Sub2, Src3) = 12 dist(Sub3, Src4) = 10 average = 11 **Run 3.** dist(Sub1, Src3) = 7 dist(Sub2, Src4) = 6 dist(Sub3, Src5) = 10 average = 8 **Run 4.** dist(Sub1, Src3) = 10 dist(Sub2, Src4) = 4 dist(Sub3, Src5) = 2 average = 5 So the winner here is sequence 4 with an average distance of 5.

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  • Calculating multiple column average in SQLite3

    - by Benjamin Oakes
    I need to average some values in a row-wise fashion, rather than a column-wise fashion. (If I were doing a column-wise average, I could just use avg()). My specific application of this requires me ignore NULLs in averaging. It's pretty straightforward logic, but seems awfully difficult to do in SQL. Is there an elegant way of doing my calculation? I'm using SQLite3, for what it's worth. Details If you need more details, here's an illustration: I have a a table with a survey: | q1 | q2 | q3 | ... | q144 | |----|-------|-------|-----|------| | 1 | 3 | 7 | ... | 2 | | 4 | 2 | NULL | ... | 1 | | 5 | NULL | 2 | ... | 3 | (Those are just some example values and simple column names. The valid values are 1 through 7 and NULL.) I need to calculate some averages like so: q7 + q33 + q38 + q40 + ... + q119 / 11 as domain_score_1 q10 + q11 + q34 + q35 + ... + q140 / 13 as domain_score_2 ... q2 + q5 + q13 + q25 + ... + q122 / 12 as domain_score_14 ...but i need to pull out the nulls and average based on the non-nulls. So, for domain_score_1 (which has 11 items), I would need to do: Input: 3, 5, NULL, 7, 2, NULL, 3, 1, 5, NULL, 1 (3 + 5 + 7 + 2 + 3 + 1 + 5 + 1) / (11 - 3) 27 / 8 3.375 A simple algorithm I'm considering is: Input: 3, 5, NULL, 7, 2, NULL, 3, 1, 5, NULL, 1 Coalesce each value to 0 if NULL: 3, 5, 0, 7, 2, 0, 3, 1, 5, 0, 1 Sum: 27 Get the number of non-zeros by converting values 0 to 1 and sum: 3, 5, 0, 7, 2, 0, 3, 1, 5, 0, 1 1, 1, 0, 1, 1, 0, 1, 1, 1, 0, 1 8 Divide those two numbers 27 / 8 3.375 But that seems like a lot more programming than this should take. Is there an elegant way of doing this that I'm not aware of? Update: Unless I'm misunderstanding something, avg() won't work for this. Example of what I would want to do: select avg(q7, q33, q38, ..., q119) from survey; Output: SQL error near line 3: wrong number of arguments to function avg()

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  • sorting, average and finding the lowest number from a static array Java

    - by user3701322
    i'm trying to input students and input their results for course work and exams and what i'm having trouble with is finding the average total score, the lowest total score and printing all students in order of total scores highest - lowest import java.util.*; import java.text.*; public class Results { static String[] name = new String[100]; static int[] coursework = new int[100]; static int[] exam = new int[100]; static int count = 0; public static void main(String[] args) { Scanner input = new Scanner(System.in); boolean flag = true; while(flag) { System.out.println( "1. Add Student\n" + "2. List All Students\n" + "3. List Student Grades\n" + "4. Total Score Average\n" + "5. Highest Total Score\n" + "6. Lowest Total Score\n" + "7. List all Students and Total Scores\n" + "8. Quit\n"); System.out.print("Enter choice (1 - 8): "); int choice = input.nextInt(); switch(choice) { case 1: add(); break; case 2: listAll(); break; case 3: listGrades(); break; case 4: average(); break; case 5: highestTotal(); break; case 6: lowestTotal(); break; case 7: order(); break; case 8: flag = false; break; default: System.out.println("\nNot an option\n"); } DateFormat dateFormat = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss"); Date date = new Date(); System.out.println(dateFormat.format(date)); } System.out.println("\n\nHave a nice day"); }//end of main static void add() { Scanner input = new Scanner(System.in); System.out.println("Insert Name: "); String names = input.nextLine(); System.out.println("Insert Coursework: "); int courseworks = input.nextInt(); System.out.println("Insert Exam: "); int exams = input.nextInt(); name[count] = names; coursework[count] = courseworks; exam[count] = exams; count++; } static void listAll() { for(int i=0;i<count;i++) { System.out.printf("%s %d %d\n", name[i], coursework[i], exam[i]); } } static void listGrades() { for(int i=0;i<count;i++){ if(coursework[i] + exam[i] > 79) { System.out.println(name[i] + " HD"); } else if(coursework[i] + exam[i] > 69) { System.out.println(name[i] + " DI"); } else if(coursework[i] + exam[i] > 59) { System.out.println(name[i] + " CR"); } else if(coursework[i] + exam[i] > 49) { System.out.println(name[i] + " PA"); } else { System.out.println(name[i] + " NN"); } } } static void average() { } static void highestTotal() { int largest=exam[0]; String student=name[0]; for(int i=0; i<exam.length; i++){ if(exam[i]>largest){ largest = exam[i] + coursework[i]; student = name[i]; } } System.out.printf(student + ": "+ largest + "\n" ); } static void lowestTotal() { int min = 0; for(int i=0; i<=exam[i]; i++){ for(int j =0; j<=exam[i]; j++){ if(exam[i]<=exam[j] && j==exam[j]){ min = exam[i] + coursework[i]; } else{ continue; } } } System.out.printf(name + ": "+ min + "\n" ); } static void order() { } }

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  • Load Testing Java Web Application - find TPS / Avg transaction response time

    - by Steve
    I would like to build my own load testing tool in Java with the goal of being able to load test a web application I am building throughout the development cycle. The web application will be receiving server to server HTTP Post requests and I would like to find its starting transaction per second (TPS) capacity along with the avgerage response time. The Post request and response messages will be in XML (I dont' think that's really applicable though :) ). I have written a very simple Java app to send transactions and count how many transactions it was able to send in one second (1000 ms) however I don't think this is the best way to load test. Really what I want is to send any number of transactions at exactly the same time - i.e. 10, 50, 100 etc. Any help would be appreciated! Oh and here is my current test app code: Thread[] t = new Thread[1]; for (int a = 0; a < t.length; a++) { t[a] = new Thread(new MessageLoop()); } startTime = System.currentTimeMillis(); System.out.println(startTime); for (int a = 0; a < t.length; a++) { t[a].start(); } while ((System.currentTimeMillis() - startTime) < 1000 ) { } if ((System.currentTimeMillis() - startTime) > 1000 ) { for (int a = 0; a < t.length; a++) { t[a].interrupt(); } } long endTime = System.currentTimeMillis(); System.out.println(endTime); System.out.println("Total time: " + (endTime - startTime)); System.out.println("Total transactions: " + count); private static class MessageLoop implements Runnable { public void run() { try { //Test Number of transactions while ((System.currentTimeMillis() - startTime) < 1000 ) { // SEND TRANSACTION HERE count++; } } catch (Exception e) { } } }

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  • use Jquery load to load content in adiv?

    - by Khalid Omar
    simply i'm doing a test i have a div called test and mvc action in the client controler the view and the controler public string testout() { return DateTime.Now.ToString(); } and i'm using jquery to update the div $("#B1").live("click", function() { $("#test").load("/client/testout"); return false; }); first time a click the bottun i see the date and time in the div test second time i click the botton nothing changed

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  • load balancer question c# asp.net

    - by Migs
    The place where I work has 2 servers and a load balancer. The setup is horrible since I have to manually make sure both servers have the same files. I know there are ways to automate this but it has not been implemented, hopefully soon (I have no control over this). I wrote an application that collects a bunch of information from a user, then creates a folder named after the email of the user in one of the servers. The problem is that I can't control in which server the folder gets created in, so let say a user goes in.. fills his stuff and his folder gets created in server 1, user goes away for a while and goes back to the site but this time the load balancer throws the user into server 2, now the user does something that needs to be saved into his folder but since it didn't created in this server an error occurs. What can I do about this? any suggestions? Thanks

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  • Compute weighted averages for large numbers

    - by Travis
    I'm trying to get the weighted average of a few numbers. Basically I have: Price - 134.42 Quantity - 15236545 There can be as few as one or two or as many as fifty or sixty pairs of prices and quantities. I need to figure out the weighted average of the price. Basically, the weighted average should give very little weight to pairs like Price - 100000000.00 Quantity - 3 and more to the pair above. The formula I currently have is: ((price)(quantity) + (price)(quantity) + ...)/totalQuantity So far I have this done: double optimalPrice = 0; int totalQuantity = 0; double rolling = 0; System.out.println(rolling); Iterator it = orders.entrySet().iterator(); while(it.hasNext()) { System.out.println("inside"); Map.Entry order = (Map.Entry)it.next(); double price = (Double)order.getKey(); int quantity = (Integer)order.getValue(); System.out.println(price + " " + quantity); rolling += price * quantity; totalQuantity += quantity; System.out.println(rolling); } System.out.println(rolling); return totalQuantity / rolling; The problem is I very quickly max out the "rolling" variable. How can I actually get my weighted average? Thanks!

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  • No clue for high load average on top

    - by Oz.
    We have several machines on Amazon (ec2) of the type c1.xlarge with 16 cpus, running the Amazon AMI. Details on the machine: 7 GB of memory 20 EC2 Compute Units (8 virtual cores with 2.5 EC2 Compute Units each) 1690 GB of instance storage 64-bit platform I/O Performance: High API name: c1.xlarge One out of the several machines is showing a high load average, since we have run the last yum upgrade a couple of weeks a go. We did not yet update the other machines, and everything looks normal on them. The strange thing is that the top command not showing any hint for the cause of the load. CPUs are 4.8%us, 1.1%sy, 0.0%ni, 94.1%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st(see below). Mem is about 1.5GB free. Any idea what could it be, or where else can we check? Many thanks for the help. # # top # top - 07:57:42 up 4:18, 1 user, load average: 1.36, 1.45, 1.47 Tasks: 131 total, 1 running, 130 sleeping, 0 stopped, 0 zombie Cpu(s): 4.8%us, 1.1%sy, 0.0%ni, 94.1%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Mem: 7120092k total, 5644920k used, 1475172k free, 532888k buffers Swap: 0k total, 0k used, 0k free, 3463936k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 1557 mysql 20 0 1829m 374m 6448 S 14.3 5.4 11:15.09 mysqld 6655 apache 20 0 416m 49m 3744 S 9.3 0.7 0:04.85 httpd 27683 apache 20 0 421m 54m 3708 S 9.0 0.8 0:00.99 httpd 6682 apache 20 0 424m 57m 3788 S 8.3 0.8 0:03.81 httpd 16816 apache 20 0 419m 51m 3760 S 4.3 0.7 0:04.09 httpd 22182 apache 20 0 417m 50m 3756 S 1.7 0.7 0:06.34 httpd 219 root 20 0 0 0 0 S 0.3 0.0 0:00.34 kworker/7:1 699 root 20 0 0 0 0 S 0.3 0.0 0:00.40 kworker/3:1 1 root 20 0 19376 1508 1212 S 0.0 0.0 0:00.29 init 2 root 20 0 0 0 0 S 0.0 0.0 0:00.00 kthreadd 3 root 20 0 0 0 0 S 0.0 0.0 0:00.71 ksoftirqd/0

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  • ubuntu's average load never below "0.00 0.01 0.05"

    - by Karma Fusebox
    I have several ubuntu 12.04 VMs running on a ubuntu 12.04 KVM host. Those of the virtual machines that are totally idle with no services (except syslog and the other "small" standard stuff of a fresh installation) show a constant load of "0.00 0.01 0.05" in top/htop as average 1/5/15. When there are "real" applications running, the load averages behave perfectly normal but they never fall below the mentioned values. While this doesn't affect performance at all and could easily be ignored, it screws up the monitoring graphs in a very annoying way: (Notice how load15 behaves nicely if 0.05 for a short time in the right half of the pic) Unfortunately I don't know what diagnostic outputs might be helpful for you, so here's some default stuff: # top top - 16:31:01 up 1:05, 1 user, load average: 0.00, 0.01, 0.05 Tasks: 62 total, 1 running, 61 sleeping, 0 stopped, 0 zombie Cpu(s): 0.2%us, 0.2%sy, 0.0%ni, 99.2%id, 0.5%wa, 0.0%hi, 0.0%si, 0.0%st Mem: 1019464k total, 73452k used, 946012k free, 6140k buffers Swap: 0k total, 0k used, 0k free, 22504k cached . # free -m total used free shared buffers cached Mem: 995 72 923 0 6 21 -/+ buffers/cache: 43 951 Swap: 0 0 0 . # iostat -x /dev/vda Linux 3.2.0-32-virtual (vm3) 11/15/2012 _x86_64_ (2 CPU) avg-cpu: %user %nice %system %iowait %steal %idle 0.25 0.00 0.65 0.20 0.24 98.66 Device: rrqm/s wrqm/s r/s w/s rkB/s wkB/s avgrq-sz avgqu-sz await r_await w_await svctm %util vda 0.14 0.12 0.51 0.22 6.74 1.46 22.50 0.02 23.26 20.64 29.30 7.63 0.56 Need something else? Has anyone ever seen this behavior? Might this be a bug in kvm/ubuntu/kernel 3.x in the end? Thanks a lot!

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  • Average over a timeframe with missing data

    - by BHare
    Assuming a table such as: UID Name Datetime Users 4 Room 4 2012-08-03 14:00:00 3 2 Room 2 2012-08-03 14:00:00 3 3 Room 3 2012-08-03 14:00:00 1 1 Room 1 2012-08-03 14:00:00 2 3 Room 3 2012-08-03 14:15:00 1 2 Room 2 2012-08-03 14:15:00 4 1 Room 1 2012-08-03 14:15:00 3 1 Room 1 2012-08-03 14:30:00 6 1 Room 1 2012-08-03 14:45:00 3 2 Room 2 2012-08-03 14:45:00 7 3 Room 3 2012-08-03 14:45:00 8 4 Room 4 2012-08-03 14:45:00 4 I wanted to get the average user count of each room (1,2,3,4) from the time 2PM to 3PM. The problem is that sometimes the room may not "check in" at the 15 minute interval time, so the assumption has to be made that the previous last known user count is still valid. For example the check-in's for 2012-08-03 14:15:00 room 4 never checked in, so it must be assumed that room 4 had 3 users at 2012-08-03 14:15:00 because that is what it had at 2012-08-03 14:00:00 This follows on through so that the average user count I am looking for is as follows: Room 1: (2 + 3 + 6 + 3) / 4 = 3.5 Room 2: (3 + 4 + 4 + 7) / 4 = 4.5 Room 3: (1 + 1 + 1 + 8) / 4 = 2.75 Room 4: (3 + 3 + 3 + 4) / 4 = 3.25 where # is the assumed number based on the previous known check-in. I am wondering if it's possible to so this with SQL alone? if not I am curious of a ingenious PHP solution that isn't just bruteforce math, as such as my quick inaccurate pseudo code: foreach ($rooms_id_array as $room_id) { $SQL = "SELECT * FROM `table` WHERE (`UID` == $room_id && `Datetime` >= 2012-08-03 14:00:00 && `Datetime` <= 2012-08-03 15:00:00)"; $result = query($SQL); if ( count($result) < 4 ) { // go through each date and find what is missing, and then go to previous date and use that instead } else { foreach ($result) $sum += $result; $avg = $sum / 4; } }

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  • Average of Average in one row

    - by asrijaal
    Hi there, I'm not sure if this is possible what I'm trying to achieve. I want to get the avg of averaged columns. SELECT avg(col1), avg(col2), avg(col3) FROM tbl My Result should be the avg of all three avg columns, is this possible? Something like this SELECT avg( col1, col2, col3) FROM tbl doesn't work at MySQL 5.1

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  • High CPU load - Ubuntu 14.04

    - by watt
    I noticed that sometimes when browsing (with other processes in the background), I get very high CPU load for the browser process (over 100%) and the computer becomes really slow. I tried switching from Firefox (with just a few extensions) to Chromium, but same thing happens without me visiting graphics-intense sites, flash sites or anything like that. I also noticed python or node (when running "make") produce the same high CPU load from time to time so this is not necessarily browser-related. When I only have a browser open, it doesn't seem to happen and everything is fine in Windows 7. I switched from unity to gnome3 with no effect. Specs: lenovo w510 (4gb RAM, i7 q820 @ 1.73) + up to date Ubuntu 14.04 64bit. Printscreen: http://imgur.com/8MZJNKC Do you guys have any idea why this might happen? Please let me know if there's other info you need. Thanks!

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  • alsHigh CPU load - Ubuntu 14.04

    - by watt
    I noticed that sometimes when browsing (with other processes in the background), I get very high CPU load for the browser process (over 100%) and the computer becomes really slow. I tried switching from Firefox (with just a few extensions) to Chromium, but same thing happens without me visiting graphics-intense sites, flash sites or anything like that. I also noticed python or node (when running "make") produce the same high CPU load from time to time so this is not necessarily browser-related. When I only have a browser open, it doesn't seem to happen and everything is fine in Windows 7. I switched from unity to gnome3 with no effect. Specs: lenovo w510 (4gb RAM, i7 q820 @ 1.73) + up to date Ubuntu 14.04 64bit. Printscreen: http://imgur.com/8MZJNKC Do you guys have any idea why this might happen? Please let me know if there's other info you need. Thanks!

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  • New host, high load?

    - by dotancohen
    A few minutes ago I signed up at a new webhost. I have yet to move my sites over. Upon initial SSH connection, I checked the load and memory usage, they do seem rather higher than I would like: # uptime 12:06:51 up 71 days, 23:23, 1 user, load average: 9.02, 9.49, 9.45 # free total used free shared buffers cached Mem: 33014800 31927192 1087608 0 2384812 17729816 -/+ buffers/cache: 11812564 21202236 Swap: 16787916 8584 16779332 Is that a bit to packed? I'm only paying about $5 USD per month, so I don't expect <0.1 loads, but ~10 is worrisome. Is it not? Also, there is no /etc/issue file so I tried other methods to guess the OS: # uname -a Linux box358.bluehost.com 2.6.32-20120131.55.1.bh6.x86_64 #1 SMP Tue Jan 31 15:43:27 EST 2012 x86_64 x86_64 x86_64 GNU/Linux # which yum /usr/bin/yum # which apt-get # That looks like CentOS / RHEL 6.2 possibly?

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  • Is it possible to load balance requests from a single source?

    - by Shawn
    In our application, Server A establishes a TCP connection with Server B, then it sends a large amount of requests to Server B over the TCP connection. The request message is XML-based. Server B needs to respond within a very short period, and it takes time to process the requests. So we hope a load balancer can be introduced and we can expedite the processing by using multiple Server B's. This is not a web application. I did some research but failed to find a similar application of load balancer. Can anyone tell me if there's a load balancer can help in our application?

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  • DNS servers and load balancing

    - by RadiantHex
    Hi there! I'm wondering if a simple DNS server could offer, even a limited amount, of load balancing capability. I have a couple of servers and I've been told that multiple IPAddresses can be associated with one domain. Help would be very much appreciated!

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  • get average from set of objects in django

    - by dotty
    Hay, i have a simple rating system for a property. You give it a mark out of 5 (stars). The models are defined like this def Property(models.Model) # stuff here def Rating(models.Model) property = models.ForeignKey(Property) stars = models.IntegerField() What i want to do is get a property, find all the Rating objects, collect them, then get the average 'stars' from them. any ideas how to do this?

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  • Elastic Load Balancing in EC2

    - by Dom
    Hi Its been on the cards for a while, but now that Amazon have released Elastic Load balancing what are your thoughts on deploying this solution for a high-traffic web app. Should we replace HAProxy or consider ELB as a complimentary service in front of HAProxy Appreciate any comments or suggestions Thanks Dom

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  • Calculate rolling / moving average in c or c++

    - by Biohazard
    I know this is achievable with boost as per: Using boost::accumulators, how can I reset a rolling window size, does it keep extra history? But I really would like to avoid using boost. I have googled and not found any suitable or readable examples. Basically I want to track the moving average of an ongoing stream of a stream of floating point numbers using the most recent 1000 numbers as a data sample. What is the easiest way to achieve this?

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  • Calculating average (AVG) and grouping by week on large data set takes too long

    - by caioiglesias
    I'm getting average prices by week on 7 million rows, it's taking around 30 seconds to get the job done. This is the simple query: SELECT AVG(price) as price, yearWEEK(FROM_UNIXTIME(timelog)) as week from pricehistory where timelog > $range and product_id = $id GROUP BY week The only week that actually gets data changed and is worth averaging every time is always the last one, so this calculation for the whole period is a waste of resources. I just wanted to know if mysql has a tool to help out on this.

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  • 4.5 Load average on single CPU

    - by Webnet
    I'm currently looking at... top - 16:27:37 up 27 min, 1 user, load average: 4.96, 3.75, 2.87 Tasks: 141 total, 6 running, 135 sleeping, 0 stopped, 0 zombie Cpu(s): 91.4%us, 6.9%sy, 0.0%ni, 0.0%id, 0.0%wa, 0.3%hi, 1.3%si, 0.0%st Mem: 514952k total, 507500k used, 7452k free, 5652k buffers Swap: 1044184k total, 281400k used, 762784k free, 89164k cached This is a single 2.0 Ghz CPU with 2 GB RAM Is it time for an upgrade? I'm watching and it seems to stick around 50% CPU "us" which I assume means usage.

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  • Low load average with plenty of cpu-intersive processes

    - by sds
    I see loadavg at about 1 with at least 3 processes running at full tile. How can that be? top - 11:48:32 up 147 days, 5:38, 8 users, load average: 1.08, 1.11, 1.05 Tasks: 416 total, 4 running, 410 sleeping, 2 stopped, 0 zombie Cpu0 : 43.3%us, 13.7%sy, 0.0%ni, 43.0%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Cpu1 : 48.8%us, 12.4%sy, 0.0%ni, 38.8%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Cpu2 : 0.7%us, 0.7%sy, 0.0%ni, 98.3%id, 0.0%wa, 0.0%hi, 0.3%si, 0.0%st Cpu3 : 99.3%us, 0.7%sy, 0.0%ni, 0.0%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Cpu4 : 0.0%us, 0.3%sy, 0.0%ni, 99.7%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Cpu5 : 5.7%us, 0.7%sy, 0.0%ni, 93.6%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Cpu6 : 2.3%us, 0.3%sy, 0.0%ni, 97.4%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Cpu7 : 0.3%us, 0.3%sy, 0.0%ni, 99.0%id, 0.0%wa, 0.0%hi, 0.3%si, 0.0%st Cpu8 : 38.4%us, 17.4%sy, 0.0%ni, 44.2%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Cpu9 : 43.4%us, 13.5%sy, 0.0%ni, 43.1%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Cpu10 : 0.0%us, 0.0%sy, 0.0%ni,100.0%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Cpu11 : 0.0%us, 0.0%sy, 0.0%ni,100.0%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Cpu12 : 0.0%us, 0.0%sy, 0.0%ni,100.0%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Cpu13 : 0.3%us, 0.3%sy, 0.0%ni, 99.3%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Cpu14 : 0.0%us, 0.0%sy, 0.0%ni,100.0%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Cpu15 : 1.0%us, 0.7%sy, 0.0%ni, 98.3%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Mem: 132145404k total, 88125080k used, 44020324k free, 516476k buffers Swap: 8388600k total, 620232k used, 7768368k free, 55729064k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 25424 jonathan 20 0 4404m 4.1g 3268 R 99.7 3.3 212:58.17 python2.7 20939 sam 20 0 908m 733m 3376 R 81.2 0.6 603:08.07 python2.7 20987 sam 20 0 908m 732m 3376 R 79.8 0.6 598:49.18 python2.7 25428 jonathan 20 0 774m 164m 15m S 14.2 0.1 24:22.60 java 20996 sam 20 0 98.4m 7780 1880 S 4.3 0.0 17:48.15 vw 20941 sam 20 0 161m 70m 1880 S 3.0 0.1 18:10.03 vw 20940 sam 20 0 98.4m 8068 1880 S 2.6 0.0 18:06.28 vw 20942 sam 20 0 98.4m 8080 1880 S 2.6 0.0 17:39.45 vw 20944 sam 20 0 161m 71m 1880 S 2.6 0.1 17:29.29 vw 20947 sam 20 0 161m 71m 1880 S 2.6 0.1 17:25.58 vw 20959 sam 20 0 161m 70m 1880 S 2.6 0.1 17:28.00 vw 20962 sam 20 0 161m 70m 1880 S 2.6 0.1 17:26.96 vw 20963 sam 20 0 98.4m 8076 1880 S 2.6 0.0 18:07.19 vw 20965 sam 20 0 161m 71m 1880 S 2.6 0.1 18:08.13 vw 20995 sam 20 0 161m 71m 1880 S 2.6 0.1 17:38.67 vw 6399 root 20 0 558m 19m 5028 S 2.3 0.0 4329:56 BESClient 20945 sam 20 0 98.4m 8068 1880 S 2.3 0.0 17:35.38 vw 20948 sam 20 0 98.4m 8068 1880 S 2.3 0.0 17:26.01 vw 20950 sam 20 0 161m 70m 1880 S 2.3 0.1 17:25.79 vw 20952 sam 20 0 98.4m 8076 1880 S 2.3 0.0 17:32.94 vw 20955 sam 20 0 161m 70m 1880 S 2.3 0.1 17:26.61 vw 20956 sam 20 0 98.4m 8072 1880 S 2.3 0.0 17:34.76 vw 20960 sam 20 0 98.4m 8072 1880 S 2.3 0.0 17:34.04 vw Adding up CPU loads gives about 300%. The top process list also adds up to about 300%. Why is load average about 1?

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  • High load (and high temp) with idle processes

    - by Nanne
    I've got a semi-old laptop (toshiba satellite a110-228), that's appointed 'laptop for the kids' by my sister. I've installed ubuntu netbook (10.10) on it because of the lack-of memory and it seems to work fine, accept from some heat-issues. These where never a problem under windows. It looks like I've got something similar to this problem: Load is generally 1 or higher, sometimes its stuck at 0.80, but its way to high. Top/htop only show a couple of percentage CPU use (which isn't too shocking, as i'm not doing anything). At this point all the software is stock, and i'd like to keep it that way because its supposed to be the easy-to-maintain kids computer. Now I'd like to find out: What could be the cause of the high load? Could it be as this thread implies, some driver, are there other options to check? How could I see what is really keeping the system hot and bothered? How to check what runs, etc etc? I'd like to pinpoint the culprint. further steps to take for debugging? The big bad internet leads me to believe that it might be the graphics drivers. The laptop has an Intel 945M chipset, but that doesn't seem to be one of the problem childs in this manner (I read a lot abotu ATI drivers that need special isntall). I'd not only welcome hints to directly solve this (duh) but also help in starting to debug what is going on. I am really hesitant in installing an older kernel, as I want it to be stock, and easy upgradeable (because I don't live near it, it should run without me ;) ) As an afterthought: to keep the whole thing cooler, can I 'amp up' the fancontrol? Its only going "airplane" mode when the computer is 95 Celcius, which is a tad late for my taste. Top: powertop:

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  • How do i find dynamic average for not the 20 input boxes

    - by alpho07
    How do i find dynamic average for not the 20 input boxes with ".num" class but even just five out of 20. I have done it as below but it won't work $.fn.sumValues = function() { var sum = 0; this.each(function() { if ( $(this).is(':input') ) { var val = $(this).val(); } else { var val = $(this).text(); } sum += parseFloat( ('0' + val).replace(/[^0-9-\.]/g, ''), 10 ); }); return sum.toFixed(2); }; $(document).ready(function() { $('input.price').bind('keyup', function() { $('span.total').html( $('input.price').sumValues()/$('.num').length ); }); });

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