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  • User directory in PATH in zsh: ~ Does Not Work

    - by Yar
    I'm doing this in my .zshrc PATH="~/scripts:$PATH" and if I do echo $PATH it appears as the first thing in the path. Yet this directory isn't included in the executable path (nor for tab-completion). What am I doing wrong? ls ~/scripts shows the directory as expected. Edit: This works, though... I guess ~ doesn't work in the path? #PATH="~/scripts:$PATH" PATH="/Users/yar/scripts:$PATH"

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  • zsh conditional statement help

    - by Roy Rico
    Feeling kinda dumb right now: Why is my contional always true? I've tried # this should let me know what's not a directory or # symbolic link. whoa=`find ${MUSICDIR} ! -type l ! -type d | wc -l` # I would expect if it's 0 (meaning nothing was found) that # one of these statements would evaluate to false, but so far # it's always evaluating to true if [[ "${whoa}" != "0" ]] if [[ ${whoa} -gt 0 ]] What am I missing?

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  • Zsh, directory tab-completion with prefix

    - by nifty
    I have a directory where I put all my projects in, let's say it's ~/projects as an example. I've made a command called s which takes one argument, and moves me into that directory. E.g.: s foo moves me to ~/projects/foo. What I'd like is to have a completion command of some sorts, which would act like cd so I could do keep hitting tab to go further into the ~/projects/... directories. Basically, cd with a prefix which is always present. I've looked into zstyle completion in man zshcompsys, but realized I just don't know enough about it to understand it properly.

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  • Saving current directory to zsh history

    - by user130208
    I wanted to achieve the same as asked here http://stackoverflow.com/questions/945288/saving-current-directory-to-bash-history but within zsh shell. I haven't done any zsh trickry before but so far I have: function precmd { hpwd=$history[$((HISTCMD-1))] if [[ $hpwd == "cd" ]]; then cwd=$OLDPWD else cwd=$PWD fi hpwd="${hpwd% ### *} ### $cwd" echo "$hpwd" ~/.hist_log } Right now I save the command annotated with the directory name to a log file. This works fine for me. Just thought there might be a way to make replacement in the history buffer itself.

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  • zsh behaves weird in screen

    - by Nils Riedemann
    Hi there, I have zsh set up as my default shell. It works fine as long as i am not within a screen. When i start screen it looks as if some dotfiles are not loaded. For example my $PATH isn't set correctly and some directories are missing. I'm not quite sure where to start looking. Since all is fine, as long as i'm not in a screen. My dotfiles can be viewed on github. I also use oh-my-zsh — as you will notice.

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  • Translate This git_parse_function to zsh?

    - by yar
    I am using this function in Bash function parse_git_branch { git_status="$(git status 2> /dev/null)" pattern="^# On branch ([^${IFS}]*)" if [[ ! ${git_status}} =~ "working directory clean" ]]; then state="*" fi # add an else if or two here if you want to get more specific if [[ ${git_status} =~ ${pattern} ]]; then branch=${BASH_REMATCH[1]} echo "(${branch}${state})" fi } but I'm determined to use zsh. While I can use this perfectly as a shell script (even without a shebang) in my .zshrc the error is a parse error on this line if [[ ! ${git_status}}... What do I need to do to get it ready for zshell? Note: I realize the answer could be "go learn zsh syntax," but I was hoping for a quick hand with this if it's not too difficult.

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  • grep --include command doesn't work in OSX zsh

    - by icemelon
    I am following the best answer on Finding all files containing a text string in linux to search string in my project. This is my command grep --include=*.rb -rnw . -e "pattern" Zsh tells me that zsh: no matches found: --include=*.rb It seems that grep doesn't support --include option. When I type grep --help, it returns usage: grep [-abcDEFGHhIiJLlmnOoPqRSsUVvwxZ] [-A num] [-B num] [-C[num]] [-e pattern] [-f file] [--binary-files=value] [--color=when] [--context[=num]] [--directories=action] [--label] [--line-buffered] [--null] [pattern] [file ...] no --include here. Is my grep version too old? Or is there something wrong with my command?

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  • Default shell for running scripts (w/o shebang) in macos?

    - by Igor Spasic
    I have ZSH as default shell in MacOS, everything is working fine. ZSH is installed as brew package, Ive set default shell in my account, new shell is listed in /etc/shells... everything is set, like I've said. I have some shell scripts in which I use some commands from zsh, like print. When I execute the script from command line, the print command is not recognized and the script fails. This script does not have the shebang line. When I put the shebang line for zsh, then everything works; the print command is working. Since I am using only ZSH, is it possible to set default shell for running scripts, so I don't have to put shebang line in my .zsh scripts? Or is it possible to associate .zsh extension to ZSH shell execution?

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  • Split string with zsh as in Python

    - by Olivier
    In python: s = '1::3' a = s.split(':') print a[0] # '1' good print a[1] # '' good print a[2] # '3' good How can I achieve the same effect with zsh? The following attempt fails: s="1::3" a=(${(s/:/)s}) echo $a[1] # 1 echo $a[2] # 3 ?? I want an empty string, as in Python

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  • Translate parse_git_branch function to zsh from bash (for prompt)

    - by yar
    I am using this function in Bash function parse_git_branch { git_status="$(git status 2> /dev/null)" pattern="^# On branch ([^${IFS}]*)" if [[ ! ${git_status}} =~ "working directory clean" ]]; then state="*" fi # add an else if or two here if you want to get more specific if [[ ${git_status} =~ ${pattern} ]]; then branch=${BASH_REMATCH[1]} echo "(${branch}${state})" fi } but I'm determined to use zsh. While I can use this perfectly as a shell script (even without a shebang) in my .zshrc the error is a parse error on this line if [[ ! ${git_status}}... What do I need to do to get it ready for zshell? Edit: The "actual error" I'm getting is " parse error near } and it refers to the line with the strange double }}, which works on Bash. Edit: Here's the final code, just for fun: parse_git_branch() { git_status="$(git status 2> /dev/null)" pattern="^# On branch ([^[:space:]]*)" if [[ ! ${git_status} =~ "working directory clean" ]]; then state="*" fi if [[ ${git_status} =~ ${pattern} ]]; then branch=${match[1]} echo "(${branch}${state})" fi } setopt PROMPT_SUBST PROMPT='$PR_GREEN%n@$PR_GREEN%m%u$PR_NO_COLOR:$PR_BLUE%2c$PR_NO_COLOR%(!.#.$)' RPROMPT='$PR_GREEN$(parse_git_branch)$PR_NO_COLOR' Thanks to everybody for your patience and help. Edit: The best answer has schooled us all: git status is porcelain (UI). Good scripting goes against GIT plumbing. Here's the final function: parse_git_branch() { in_wd="$(git rev-parse --is-inside-work-tree 2>/dev/null)" || return test "$in_wd" = true || return state='' git diff-index HEAD --quiet 2>/dev/null || state='*' branch="$(git symbolic-ref HEAD 2>/dev/null)" test -z "$branch" && branch='<detached-HEAD>' echo "(${branch#refs/heads/}${state})" } PROMPT='$PR_GREEN%n@$PR_GREEN%m%u$PR_NO_COLOR:$PR_BLUE%2c$PR_NO_COLOR%(!.#.$)' RPROMPT='$PR_GREEN$(parse_git_branch)$PR_NO_COLOR' Note that only the prompt is zsh-specific. In Bash it would be your prompt plus "\$(parse_git_branch)". This might be slower (more calls to GIT, but that's an empirical question) but it won't be broken by changes in GIT (they don't change the plumbing). And that is very important for a good script moving forward. Days Later: Ugh, it turns out that diff-index HEAD is NOT the same as checking status against working directory clean. So will this mean another plumbing call? I surely don't have time/expertise to write my own porcelain....

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  • side effect of zsh echo?

    - by Mirai
    For some reason this script will work with all of the 'echo's at the end, but without them $wall is an empty string. This seems like really odd behaviour. #!/bin/zsh if [ ! -n "$1" ] ; then files=(~/pictures/backgrounds/*jpg) else while [ $1 ] ; do files+=(`echo $1/*jpg`) shift done fi echo $files N=${#files} echo $N ((N=RANDOM%N)) echo $N wall=${files[$N]} echo $wall cp $wall ~/wall.jpg

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  • zsh for loop exclusion

    - by ABach
    This is somewhat of a simple question, but for the life of me, I cannot figure out how to exclude something from a zsh for loop. For instance, let's say we have this: for $package in /home/user/settings/* do # do stuff done Let's say that in /home/user/settings/, there is a particular directory ("os") that I want to ignore. Logically, I tried the following variations: for $package in /home/user/settings/^os (works w/ "ls", but not with a foor loop) for $package in /home/user/settings/*^os for $package in /home/user/settings/^os* ...but none of those seem to work. Could someone steer my syntax in the right direction?

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  • How do I make zsh completion act more like bash completion?

    - by Tordek
    I'm a recent convert from bash to zsh (which I'm using "oh my zsh" with), but one thing annoys me: When I hit the tab key, the first autocompletion is filled out automatically, and you need to cycle through the completions by hitting tab repeatedly. This differs from bash, where you are just shown a list of the completions. If all completions have the same prefix, then this prefix is filled out. You can select the one you want by continuing to type. I find the latter preferable since it is faster to type, than to select a completion by hitting tab repeatedly. Is there any way to make zsh completion act more like bash in this regard?

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  • How can I make zsh completion behave like Bash completion?

    - by Nate
    I switched to zsh, but I dislike the completion. If I have 20 files, each with a shared prefix, on pressing tab, zsh will fully complete the first file, then continue going through the list with each press of tab. If I want one near the end, I would have to press tab many times. In bash, this was simple - press tab and I would get the prefix. If I continued typing (and pressing tab), bash would complete as far as it could be certain of. I find this behavior to be much more intuitive but prefer the other features of zsh to bash. Is there a way to get this style of completion? Google suggested setopt bash_autolist, but this had no effect for me (and no error message was printed upon starting my shell). Thanks.

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  • little oh notation as the limit of n goes to infinity

    - by Tony
    Hi all, I'm just trying to understand how in little o notation this is true: f(n)/g(n) as n goes to infinity = infinity? Can someone explain that to me? I do get the idea that f(n) = o(g(n)) means that f(n) grows no faster then cg(n) for all constants c 0. I just don't get the bit in bold above.

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  • To get a prompt which indicates Git-branch in Zsh

    - by Masi
    I run the following codes separately as my prompt unsuccessfully in .zshrc. This suggests me that apparently I do not have a program called __git_ps1. It is not in MacPorts. #1 PROMPT="$(__git_ps1 " \[\033[1;32m\] (%s)\[\033[0m\]")\$"$ #2 PROMPT="$(__git_ps1 " (%s)")\$"$ #3 # Get the name of the branch we are on git_prompt_info() { branch_prompt=$(__git_ps1) if [ -n "$branch_prompt" ]; then status_icon=$(git_status) echo $branch_prompt $status_icon fi } # Show character if changes are pending git_status() { if current_git_status=$(git status | grep 'added to commit' 2> /dev/null); then echo "?" fi } autoload -U colors colors setopt prompt_subst PROMPT=' %~%{$fg_bold[black]%}$(git_prompt_info) ? %{$reset_color%}' How can you get a prompt which shows the name of a Git-branch?

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  • Zsh: how to see all buffers?

    - by HH
    You can push things to buffer with ^Q and pop them with ESC-g. Alt+x vi-set-buffer changes buffer somehow. How can I see all the buffers? They are probably some files to look at.

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  • Any tips on switching from bash to zsh if often using shell inside of emacs?

    - by justingordon
    Related to this question: Advantages and disadvantages between zsh and emacs' (e)shell, I've read some great things about zsh, when using M-x shell, my familiar emacs shell seemed like it would need some customizations. I also use evil-mode in shell mode, so that means I use vi keystrokes for shell editing. Took a little while to get accustomed to this, but I really like it. Any advice or tips on going from bash to zsh if one uses emacs? Or better off adding the file completion mentioned in this question: Worth switching to zsh for casual use?.

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  • Is it possible to have zsh+keychain+tmux not ask for keys?

    - by Wayne Werner
    I'm using tmux and zsh, and I've recently been learning about ssh-agent and keychain. From the manpage for zsh, it says that it will source .zlogin only if the shell is, well, a login shell. Following advice I read, I stuck keychain --clear in my .zlogin, which worked perfectly. When I logged into the box I had to unlock my key. However, each time I create a new window in tmux, it clears/makes me re-add my key. This is a little annoying... but I can understand it if, in fact, each new tmux window is a login window. I haven't been able to find much help outside of the manpages on this topic. So is each new tmux window a login shell, or is there any way that I can make it not clear my keys only when I create a tmux window?

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  • How to make the cursor shape dependent on the current Vim mode using iTerm2 on OS X and zsh

    - by i0n
    I am using zsh and iTerm2 to edit with Vim. I really love the integration and portability, and because of that I have chosen not to use MacVim. But.... I can't work out how to get my cursor to change from a block to a line when in Vim's insert mode. I've been lead to believe that it's not possible by standard means, but people seem to think that it is possible using zsh. I've done as much Google searching as I can take without an answer, any help or advice would be greatly appreciated.

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  • Big Oh notation does not mention constant value

    - by user883561
    I am a programmer and have just started reading Algorithms. I am not completely convinced with the notations namely Bog Oh, Big Omega and Big Theta. The reason is by definition of Big Oh, it states that there should be a function g(x) such that it is always greater than or equal to f(x). Or f(x) <= c.n for all values of n n0. My doubt is the why dont we mention the constant value in the definition? For example. lets say a function 6n+4, we denote it as O(n). but its not true that the definition holds good for all constant value. this holds good only when c = 10 and n = 1. For lesser values of c than 6, the value of n0 increases. So why we do not mention the constant value as a part of the definition.

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