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Search found 344 results on 14 pages for 'rock'.

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  • Unable to locate using find element by link

    - by First Rock
    Newbie in testing. I generated a test case using Selenium, and then exported it as a Python script. Now, when I try to run that in terminal, I get following error: raise exception_class(message, screen, stacktrace) NoSuchElementException: Message: u'Unable to locate element: {"method":"link text","selector":"delete"}' I am using the command generated by Selenium i.e driver.find_element_by_link_text("delete").click() The reason for the error I believe is that the link "delete" in my web page is seen only when I click on a particular line to be deleted. So I guess it is being unable to locate the link. Please suggest what alternative measure could I use to locate and click on the "delete" link. Thanks in Advance:)

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  • How to write a cgi script in perl that accepts output (an image file) from a urlconnection in a Java applet and writes it to the server?

    - by Brad Rock
    I created a Java applet for my web page that creates an image file. I want users to be able to run the applet and create unique images, click a button, and have the image they created be saved to the web server. I think I have the code down for writing the image to a URLconnection in the Java applet itself after having successfully written a file while running the applet on my system rather than the web page and saving a file to the local disk, and then altering a few things to write to a URLConnection instead of to the local disk (although we shall see how that works too). I am now trying to write a cgi script in perl that takes the image output from the URLConnection and writes the image to a file on my web server (note: I am a newbie to perl). I have found many examples of how to do something similar with simple text coming from an applet and then writing it to a text file, but I want to know how to apply the same concept to an image. Particularly, how do I read in the image? I've seen text input get read by using read(STDIN, $some_variable)--does the same thing work with an image? Likewise, how do I write the image file? What function do I use? Thanks for your help. I know that I am rather naive about all of this.

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  • The SQL Beat Podcast-Capturing a SQL Rockstar

    - by SQLBeat
      This is the first permissible (waiting for signed disclaimers) episode of the SQL Beat Podcast featuring the gracious and famous Thomas La Rock. We talk about gay marriage, abortion, SQL community and a 9 inch pipe with a hole in it at the tip. No really. If there ever was a gentleman, SQL Rockstar is one and I want to thank him from the bottom of my digital recorder for agreeing to talk to me and my audience. All forty of them will appreciate the candor. Enjoy World. I did. Oh and a special rock start drum intro from me to you. CLICK HERE TO PLAY >>

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  • The SQL Beat Podcast–Capturing a SQL Rockstar

    - by SQLBeat
      This is the first permissible (waiting for signed disclaimers) episode of the SQL Beat Podcast featuring the gracious and famous Thomas La Rock. We talk about gay marriage, abortion, SQL community and a 9 inch pipe with a hole in it at the tip. No really. If there ever was a gentleman, SQL Rockstar is one and I want to thank him from the bottom of my digital recorder for agreeing to talk to me and my audience. All forty of them will appreciate the candor. Enjoy World. I did. Oh and a special rock start drum intro from me to you. CLICK BELOW TO LISTEN >>>>>>>>>CLICK HERE TO PLAY >>>>>>>>> CLICK ABOVE TO SPEAR A FISH INSTEAD

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  • Easiest turn-base games you can think of?

    - by Edgar Miranda
    I'm planning to get into the process of programming multiplayer turn-base games. I would like to start off by making some of the simplest (yet fun) multiplayer turn-base games out there. What are some that you can provide? For example... Tic-Tac-Toe Rock-Paper-Scissors Checkers Some not so easy games... 4 in a row chess poker In terms of "ease" of implementation I'm mainly looking at logic. For example, Rock-Paper-Scissors has very simple logic, while chess has logic that is more complicated. So far I have the following: Hexagon Heroes of Might and Magic Nine Men's Morris Connect 4 21 (card game) Pen the Pig (The Dot game) Memory Match

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  • Cocos2d Tiled Dynamic Object Layer

    - by Rodrigo Camargo
    I'm trying to develop a cocos2d tiled based game using a sort of 'dynamic' object layer. What I want to do is after the tiled map is loaded, the user can drag something into the map and that will become an event when the 'hero' pass over it. I know how to build an object layer in tiled but it seems that is for fixed positions and what I want is a dynamic action position based on what the user can select. For instance, the user can drag a rock into a tile and when the character hit that rock he may die, or something. I'm a little lost about how to make it work. Do you have any idea of what should I use or what should I look for? Thanks in advance!

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  • The SQL Beat Podcast-Capturing a SQL Rockstar

    - by SQLBeat
    This is the first permissible (waiting for signed disclaimers) episode of the SQL Beat Podcast featuring the gracious and famous Thomas La Rock. We talk about gay marriage, abortion, SQL community and generally convivial and ergonomic as will be witnessed by THAT LONG PIPE IN THE CHAIR. If there ever was a gentleman, SQL Rockstar is one and I want to thank him from the bottom of my digital recorder for agreeing to talk to me and my audience. All forty of them will appreciate the candor. Enjoy World. I did. Oh and a special rock start drum intro from me to you. CLICK HERE TO PLAY

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  • gwt ext combobox

    - by usman
    hi, i am using gwt ext.i have a combo box.i want to set my own filter to display the value. Any idea please eg: combobox contain : jon , jockey jo, rock k, michle ken, jonty mark, if i enter k the combo box has to show rock k. condition is it has to check the starting letter word of the list

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  • Getting percentage of "Count(*)" to the number of all items in "GROUP BY"

    - by celalo
    Let's say I need to have the ratio of "number of items available from certain category" to "the the number of all items". Please consider a MySQL table like this: /* mysql> select * from Item; +----+------------+----------+ | ID | Department | Category | +----+------------+----------+ | 1 | Popular | Rock | | 2 | Classical | Opera | | 3 | Popular | Jazz | | 4 | Classical | Dance | | 5 | Classical | General | | 6 | Classical | Vocal | | 7 | Popular | Blues | | 8 | Popular | Jazz | | 9 | Popular | Country | | 10 | Popular | New Age | | 11 | Popular | New Age | | 12 | Classical | General | | 13 | Classical | Dance | | 14 | Classical | Opera | | 15 | Popular | Blues | | 16 | Popular | Blues | +----+------------+----------+ 16 rows in set (0.03 sec) mysql> SELECT Category, COUNT(*) AS Total -> FROM Item -> WHERE Department='Popular' -> GROUP BY Category; +----------+-------+ | Category | Total | +----------+-------+ | Blues | 3 | | Country | 1 | | Jazz | 2 | | New Age | 2 | | Rock | 1 | +----------+-------+ 5 rows in set (0.02 sec) */ What I need is basically a result set resembles this one: /* +----------+-------+-----------------------------+ | Category | Total | percentage to the all items | (Note that number of all available items is "9") +----------+-------+-----------------------------+ | Blues | 3 | 33 | (3/9)*100 | Country | 1 | 11 | (1/9)*100 | Jazz | 2 | 22 | (2/9)*100 | New Age | 2 | 22 | (2/9)*100 | Rock | 1 | 11 | (1/9)*100 +----------+-------+-----------------------------+ 5 rows in set (0.02 sec) */ How can I achieve such a result set in a single query? Thanks in advance.

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  • Need help extrapolating Java code

    - by Berlioz
    If anyone familiar with Rebecca Wirfs-Brock, she has a piece of Java code found in her book titled, Object Design: Roles, Responsibilities, and Collaborations. Here is the quote Applying Double Dispatch to a Specific Problem To implement the game Rock, Paper, Scissors we need to write code that determines whether one object “beats” another. The game has nine possible outcomes based on the three kinds of objects. The number of interactions is the cross product of the kinds of objects. Case or switch statements are often governed by the type of data that is being operated on. The object-oriented language equivalent is to base its actions on the class of some other object. In Java, it looks like this Here is the piece of Java code on page 16 ' import java.util.*; import java.lang.*; public class Rock { public static void main(String args[]) { } public static boolean beats(GameObject object) { if (object.getClass.getName().equals("Rock")) { result = false; } else if (object.getClass.getName().equals("Paper")) { result = false; } else if(object.getClass.getName().equals("Scissors")) { result = true; } return result; } }' ===This is not a very good solution. First, the receiver needs to know too much about the argument. Second, there is one of these nested conditional statements in each of the three classes. If new kinds of objects could be added to the game, each of the three classes would have to be modified. Can anyone share with me how to get this "less than optimal" piece of code to work in order to see it 'working'. She proceeds to demonstrate a better way, but I will spare you. Thanks

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  • Best way to implement mouse-based movement in MMOG

    - by fiftyeight
    I want to design an MMO where players click the destination they want to walk to with their mouse and the character moves there, similar to Runescape in this manner. I think it should be easier than keyboard movement since the client can simply send the server the destination each time the player clicks on a destination. The main thing I'm trying to decide is what to do when there are obstacles in the way. It's no problem to implement a simple path-finding solution on the client, the question is if the server will do path-finding as well, since it'll probably take too much Computation power from the server. What I though is that when there is an obstacle the client will send only the first coordinate it plans to go to and then when he gets there he'll send the next coordinate automatically. For example if there is a rock in the way the character will decide on a route that is made of two destinations so it goes around the rock and when it arrives at the first destination it sends the next coordinate. That way if the player changes destination is the middle he won't send unnecessary information. Is this a good way to implement it and is there a standard way MMOGs usually do it? EDIT: I should also mention that the server will make sure all movements are legal and there aren't any walls in the way etc. In the way I wrote it should be quite easy since all movements will be sent in straight lines so the server will just check there aren't any obstacles along that line.

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  • JavaOne Gangnam Style

    - by Tori Wieldt
    Yes, JavaOne is *the* place for excellent content, including technical information, opportunities to learn best practices from your peers, and access to industry experts. You can find lots of information about content in Java Evangelist Arun Gupta's 25 Reasons to attend JavaOne 2012. But you also have to let your Gangnam Style loose. Here are the Top Ten Fun Reasons to attend JavaOne 2012: 10. Connect with developers from more than 80 countries 9. Kick off the week at GlassFish and Friends Party Sunday night 8. Meet the community of Java Rock Stars 7. Enjoy all San Francisco has to offer 6. Meet your next best friend playing pinball in the Game Zone 5. Have your picture taken with Duke 4. Java in the morning and brews in the afternoon at the Taylor Street Cafe 3. Ride across the Golden Gate Bridge at the Community Geek Bike Ride 2. Rock out at the first-ever Oracle OpenWorld Music Festival and #1... 1. It beats being at work!  If you haven't registered, there's still time. Join us!

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  • MSSQL Efficiently dropping a group of rows with millions and millions of rows

    - by Net Citizen
    I recently asked this question: http://stackoverflow.com/questions/2519183/ms-sql-share-identity-seed-amongst-tables (Many people wondered why) I have the following layout of a table: Table: Stars starId bigint categoryId bigint starname varchar(200) But my problem is that I have millions and millions of rows. So when I want to delete stars from the table Stars it is too intense on MS SQL. I cannot use built in partitioning for 2005+ because I do not have an enterprise license. When I do delete though, I always delete a whole category Id at a time. I thought of doing a design like this: Table: Star_1 starId bigint CategoryId bigint constaint rock=1 starname varchar(200) Table: Star_2 starId bigint CategoryId bigint constaint rock=2 starname varchar(200) In this way I can delete a whole category and hence millions of rows in O(1) by doing a simple drop table. My question is, is it a problem to have thousands of tables in your MS SQL? The drop in O(1) is extremely desirable to me. Maybe there's a completely different solution I'm not thinking of?

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  • C++ cin keeps skipping.....

    - by user69514
    I am having problems with my program. WHen I run it, it asks the user for the album, the title, but then it just exits the loop without asking for the price and the sale tax. Any ideas what's going on? This is a sample run Discounts effective for September 15, 2010 Classical 8% Country 4% International 17% Jazz 0% Rock 16% Show 12% Are there more transactions? Y/N y Enter Artist of CD: Sevendust Enter Title of CD: Self titled Enter Genre of CD: Rock enter price Are there more transactions? Y/N Thank you for shopping with us! Program code: #include <iostream> #include <string> using namespace std; int counter = 0; string discount_tiles[] = {"Classical", "Country", "International", "Jazz", "Rock", "Show"}; int discount_amounts[] = {8, 4, 17, 0, 16, 12, 14}; string date = "September 15, 2010"; // Array Declerations //Artist array char** artist = new char *[100]; //Title array char** title = new char *[100]; //Genres array char** genres = new char *[100]; //Price array double* price[100]; //Discount array double* tax[100]; // sale price array double* sale_price[100]; //sale tax array double* sale_tax[100]; //cash price array double* cash_price[100]; //Begin Prototypes char* getArtist(); char* getTitle(); char* getGenre(); double* getPrice(); double* getTax(); unsigned int* AssignDiscounts(); void ReadTransaction (char ** artist, char ** title, char ** genre, float ** cash, float & taxrate, int albumcount); void computesaleprice(); bool AreThereMore (); //End Prototypes bool areThereMore () { char answer; cout << "Are there more transactions? Y/N" << endl; cin >> answer; if (answer =='y' || answer =='Y') return true; else return false; } char* getArtist() { char * artist= new char [100]; cout << "Enter Artist of CD: " << endl; cin.getline(artist,100); cin.ignore(); return artist; } char* getTitle() { char * title= new char [100]; cout << "Enter Title of CD: " << endl; cin.getline(title,100); cin.ignore(); return title; } char* getGenre() { char * genre= new char [100]; cout << "Enter Genre of CD: " << endl; cin.getline(genre,100); cin.ignore(); return genre; } double* getPrice() { //double* price = new double(); //cout << "Enter Price of CD: " << endl; //cin >> *price; //return price; double p = 0.0; cout<< "enter price" << endl; cin >> p; cin.ignore(); double* pp = &p; return pp; } double* getTax() { double* tax= new double(); cout << "Enter local sales tax: " << endl; cin >> *tax; return tax; } int findDiscount(string str){ if(str.compare(discount_tiles[0]) == 0) return discount_amounts[0]; else if(str.compare(discount_tiles[0]) == 0) return discount_amounts[1]; else if(str.compare(discount_tiles[0]) == 0) return discount_amounts[2]; else if(str.compare(discount_tiles[0]) == 0) return discount_amounts[3]; else if(str.compare(discount_tiles[0]) == 0) return discount_amounts[4]; else if(str.compare(discount_tiles[0]) == 0) return discount_amounts[5]; else{ cout << "Error in findDiscount function" << endl; return 0; } } void computesaleprice() { /** fill in array for all purchases **/ for( int i=0; i<=counter; i++){ double temp = *price[i]; temp -= findDiscount(genres[i]); double* tmpPntr = new double(); tmpPntr = &temp; sale_price[i] = tmpPntr; delete(&temp); delete(tmpPntr); } } void printDailyDiscounts(){ cout << "Discounts effective for " << date << endl; for(int i=0; i < 6; i++){ cout << discount_tiles[i] << "\t" << discount_amounts[i] << "%" << endl; } } //Begin Main int main () { for( int i=0; i<100; i++){ artist[i]=new char [100]; title[i]=new char [100]; genres[i]=new char [100]; price[i] = new double(0.0); tax[i] = new double(0.0); } // End Array Decleration printDailyDiscounts(); bool flag = true; while(flag == true){ if(areThereMore() == true){ artist[counter] = getArtist(); title[counter] = getTitle(); genres[counter] = getGenre(); price[counter] = getPrice(); //tax[counter] = getTax(); //counter++; flag = true; } else { flag = false; } } //compute sale prices //computesaleprice(); cout << "Thank you for shopping with us!" << endl; return 0; } //End Main /** void ReadTransaction (char ** artist, char ** title, char ** genre, float ** cash, float & taxrate, int albumcount) { strcpy(artist[albumcount],getArtist()); strcpy(title[albumcount],getTitle()); strcpy(genre[albumcount],getGenre()); //cash[albumcount][0]=computesaleprice();??????? //taxrate=getTax;?????????????? } * * */ unsigned int * AssignDiscounts() { unsigned int * discount = new unsigned int [7]; cout << "Enter Classical Discount: " << endl; cin >> discount[0]; cout << "Enter Country Discount: " << endl; cin >> discount[1]; cout << "Enter International Discount: " << endl; cin >> discount[2]; cout << "Enter Jazz Discount: " << endl; cin >> discount[3]; cout << "Enter Pop Discount: " << endl; cin >> discount[4]; cout << "Enter Rock Discount: " << endl; cin >> discount[5]; cout << "Enter Show Discount: " << endl; cin >> discount[6]; return discount; } /** char ** AssignGenres () { char ** genres = new char * [7]; for (int x=0;x<7;x++) genres[x] = new char [20]; strcpy(genres [0], "Classical"); strcpy(genres [1], "Country"); strcpy(genres [2], "International"); strcpy(genres [3], "Jazz"); strcpy(genres [4], "Pop"); strcpy(genres [5], "Rock"); strcpy(genres [6], "Show"); return genres; } **/ float getTax(float taxrate) { cout << "Please enter store tax rate: " << endl; cin >> taxrate; return taxrate; }

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  • Tag/Keyword based recommendation

    - by Hellnar
    Hello I am wondering what algorithm would be clever to use for a tag driven e-commerce enviroment: Each item has several tags. IE: Item name: "Metallica - Black Album CD", Tags: "metallica", "black-album", "rock", "music" Each user has several tags and friends(other users) bound to them. IE: Username: "testguy", Interests: "python", "rock", "metal", "computer-science" Friends: "testguy2", "testguy3" I need to generate recommendations to such users by checking their interest tags and generating recommendations in a sophisticated way. Ideas: A Hybrid recommendation algorithm can be used as each user has friends.(mixture of collaborative + context based recommendations). Maybe using user tags, similar users (peers) can be found to generate recommendations. Maybe directly matching tags between users and items via tags. Any suggestion is welcome. Any python based library is also welcome as I will be doing this experimental engine on python language.

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  • SQL Server Efficiently dropping a group of rows with millions and millions of rows

    - by Net Citizen
    I recently asked this question: http://stackoverflow.com/questions/2519183/ms-sql-share-identity-seed-amongst-tables (Many people wondered why) I have the following layout of a table: Table: Stars starId bigint categoryId bigint starname varchar(200) But my problem is that I have millions and millions of rows. So when I want to delete stars from the table Stars it is too intense on SQL Server. I cannot use built in partitioning for 2005+ because I do not have an enterprise license. When I do delete though, I always delete a whole category Id at a time. I thought of doing a design like this: Table: Star_1 starId bigint CategoryId bigint constaint rock=1 starname varchar(200) Table: Star_2 starId bigint CategoryId bigint constaint rock=2 starname varchar(200) In this way I can delete a whole category and hence millions of rows in O(1) by doing a simple drop table. My question is, is it a problem to have hundreds of thousands of tables in your SQL Server? The drop in O(1) is extremely desirable to me. Maybe there's a completely different solution I'm not thinking of?

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  • STDOUT can not return to Screen

    - by rockyurock
    STDOUT can not return to Screen Hello all below is the part of my code, my code enters "if loop" with $value =1 and output of the process "iperf.exe" is getting into my_output.txt. As i am timing out the process after alram(20sec) time,also wanted to capture the output of this process only. then after i want to continue to the command prompt but i am not able to return to the command promt... not only this code itself does not PRINT on the command prompt , rather it is priniting on the my_output.txt file (i am looping this if loop through rest of my code) output.txt ========== inside value loop2 ------------------------------------------------------------ Server listening on UDP port 5001 Receiving 1470 byte datagrams UDP buffer size: 8.00 KByte (default) ------------------------------------------------------------ [160] local 10.232.62.151 port 5001 connected with 10.232.62.151 port 1505 [ ID] Interval Transfer Bandwidth Jitter Lost/Total Datagrams [160] 0.0- 5.0 sec 2.14 MBytes 3.59 Mbits/sec 0.000 ms 0/ 1528 (0%) inside value loop3 clue1 clue2 inside value loop4 one iperf completed Transfer Transfer Starting: Intent { act=android.settings.APN_SETTINGS } ******AUTOMATION COMPLETED****** Looks some problem with reinitializing the STDOUT.. even i tried to use close(STDOUT); but again it did not return to STDOUT could sombbody please help out ?? /rocky CODE:: if($value) { my $file = 'my_output.txt'; use Win32::Process; print"inside value loop\n"; # redirect stdout to a file open STDOUT, '>', $file or die "can't redirect STDOUT to <$file> $!"; Win32::Process::Create(my $ProcessObj, "iperf.exe", "iperf.exe -u -s -p 5001", 0, NORMAL_PRIORITY_CLASS, ".") || die ErrorReport(); $alarm_time = $IPERF_RUN_TIME+2; #20sec print"inside value loop2\n"; sleep $alarm_time; $ProcessObj->Kill(0); sub ErrorReport{ print Win32::FormatMessage( Win32::GetLastError() ); } print"inside value loop3\n"; print"clue1\n"; #close(STDOUT); print"clue2\n"; print"inside value loop4\n"; print"one iperf completed\n"; } my $data_file="my_output.txt"; open(ROCK, $data_file)|| die("Could not open file!"); @raw_data=<ROCK>; @COUNT_PS =split(/ /,$raw_data[7]); my $LOOP_COUNT_PS_4 = $COUNT_PS[9]; my $LOOP_COUNT_PS_5 = $COUNT_PS[10]; print "$LOOP_COUNT_PS_4\n"; print "$LOOP_COUNT_PS_5\n"; my $tput_value = "$LOOP_COUNT_PS_4"." $LOOP_COUNT_PS_5"; print "$tput_value"; close(ROCK); print FH1 "\n $count \| $tput_value \n"; regds rakesh

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  • Why are these strings escaping from my regular expression in python?

    - by dohkoxar
    In my code, I load up an entire folder into a list and then try to get rid of every file in the list except the .mp3 files. import os import re path = '/home/user/mp3/' dirList = os.listdir(path) dirList.sort() i = 0 for names in dirList: match = re.search(r'\.mp3', names) if match: i = i+1 else: dirList.remove(names) print dirList print i After I run the file, the code does get rid of some files in the list but keeps these two especifically: ['00. Various Artists - Indie Rock Playlist October 2008.m3u', '00. Various Artists - Indie Rock Playlist October 2008.pls'] I can't understand what's going on, why are those two specifically escaping my search.

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  • The .NET Rocks! Visual Studio 2010 Road Trip

    - by Laila
    Carl Franklin and Richard Campbell, the two .NET Rocks radio show hosts, have decided to set off to 15 cities in the US, between April 19th and May 7th, in their DotNetMobile (a 30 foot RV). What for you'll ask me? Well, to drive around the US, meet up with .NET developers, and show off the latest and greatest in Visual Studio 2010 and .NET 4.0! Each evening, they stop in a city and host a three hour event in front of a 100 to 300 crowd of developers, where Carl is showing off media features in Silverlight 4 and their road trip tracking application, whilst Richard is demo-ing the web performance testing features of VS2010 using his portable server rig. But before they take to the stage, they have a special guest brought in - a rock star from the Visual Studio world - whom they interview for an hour as a .NET Rock episode. So far, they've had - amongst others - Phil Haack, a Program Manager with the ASP.NET team working on ASP.NET MVC, Dan Fernandez, an Evangelism Manager in the Developer and Platform Evangelism team at Microsoft, and Beth Massi, Senior Program Manager on the Visual Studio Community Team at Microsoft. I love the fact that the audience gets a chance to participate, ask questions and have a great laugh, as you can hear in the first episode! Along the way, the .NET Rocks guys are giving away great prizes (including .NET Reflector Pro, ANTS Memory Profiler licenses, and "40" LCD TVs!). Even more out of the ordinary, at each stop on the road trip, one lucky attendee (who entered in the Ride Along competition) gets to jump in the RV with Carl and Richard and ride along with them to the next stop on the roadtrip. How cool is that! Richard told us: "Our first winner in Mountain View was Eric Ziko. I was looking for him to announce that he had won, when he found us and gave us a bottle of scotch he had brought just to say 'thanks for the great show'. We all had a toast from the bottle the next night when he headed back home." Cheeky! There's still space to a few of these events, so if you want to attend, register now, because it's first come first serve. We're grateful to Richard and Carl for giving us the opportunity to sponsor this major .NET event! A unique .NET adventure worth following for sure. Cheers, Laila

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  • The Latest Dish: Black Eyed Peas to Headline at Appreciation Event

    - by Justin Kestelyn
    If you're coming to Oracle Develop Conference to fill up on content, collaboration, and community, be sure to save room for dessert. At the Wednesday evening "Appreciation Event," which is open to Oracle Develop, JavaOne, and Oracle OpenWorld Full Conference attendees, you'll be savoring the music of the world's hottest funk pop band, Black Eyed Peas, plus superstar rock legends Don Henley (of the Eagles) and Steve Miller. Save the date now: When: Wednesday, September 22, 8 p.m.­12 a.m. Where: Treasure Island, San Francisco Get all the details here!

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