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Search found 60 results on 3 pages for 'sajid shaikh'.

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  • Change array structure in PHP.

    - by Muhammad Sajid
    Refers to my previous question : Show values in TDropDownList in PRADO. ok fine the array i receive from query is an object array like : ContactRecord Object ( [id] => 1 [name] => leo [_recordState:protected] => 1 [_connection:protected] => [_invalidFinderResult:protected] => [_e:TComponent:private] => Array ( ) ) ContactRecord Object ( [id] => 2 [name] => ganda [_recordState:protected] => 1 [_connection:protected] => [_invalidFinderResult:protected] => [_e:TComponent:private] => Array ( ) ) If I convert it in to array like: Array ( [key 1] => leo [key 2] => ganda ) then I can populate values into TDropDownList. Now can anyone help me to convert array structure which I need ... ? Again thanks

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  • Flash Video Gallery using Jquery

    - by Muhammad Sajid
    Hi, my question referenced to my friend. I am trying to use jquery to show flash videos(swf) like a showcase and this is what I am trying to do: Show a video by default and then have "" below that so when an user click on prev or next, it will show the next one and so on. When a video is clicked after making the selection it can either open the video on top of it in a bigger size Or play the video once right there once they click the play button. I have seen examples for images and I tried those but it did not work with flash files. Please let me know if anyone can guide me. I prefer using jquery as there are applications on the site that uses jquery. Also, I just remembered one thing, how to stop the video if they navigate to the next one. This makes me think if its a good idea to do the gallery or showcase for flash videos. Please clarify my questions. thanks

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  • PHP: Find total number of images having same name in a folder.

    - by Muhammad Sajid
    Hi, I am creating code to upload images in a folder using PHP, & before upload an image I check that if any image with same name already exists in the folder by using below syntax: if (file_exists('profilephoto/' . 'frame.gif')) { } But actually I don't want to restrict the user to upload more images with same name & obviously it is impossible to save two images with same name , but there is a way to just find total number of images with same name & upload the next image with appending total number + 1 with image name. Now I just want to know that using PHP how could we find total number of images having same name in a folder? Thanks.

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  • Pass value to an include file in php.

    - by Muhammad Sajid
    Hi, How do you pass a parameter into an include file? I tried the following but it doesn't work. include "myfile.php?var=123"; and in myfile.php, I try to retrieve the parameter using $_GET["var"]. include "myfile.php?var=123"; will not work. PHP searches for a file with this exact name and does not parse the parameter for that I also did this: include "http://MyGreatSite.com/myfile.php?var=123";but it does not also work. Any hints? Thanks.

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  • Threads in PHP.

    - by Muhammad Sajid
    Hello.. I am creating a web application using zend, here i create an interface from where user-A can send email to more than one user(s) & it works excellent but it slow the execution time because of which user-A wait too much for the "acknowledged response" ( which will show after the emails have sent. ) In Java there are "Threads" by which we can perform that task (send emails) & it does not slow the rest application. Is there any technique in PHP/Zend just like in Java by which we can divide our tasks which could take much time eg: sending emails. Thanks..

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  • Get & set drop down value using jQuery.

    - by Muhammad Sajid
    If user select an option from dropdown it will shown it a textbox but if he select option having value "Other" then a row will appear to type value for other. my code works fine except when option value is not equal to "Other" <script type="text/javascript"><!-- function setAndReset(box) { if(box.value == 'Other'){ $("#ShowHide").hide(); } document.FormName.hiddenInput.value = box.value; } //--> </script> <body bgcolor="#ffffff"> <form id="FormName" action="" method="get" name="FormName"> <select name="choice1" size="1" onchange="setAndReset(this);"> <option value="one">first</option> <option value="two">second</option> <option value="three">third</option> <option value="other">Other</option> </select> <input type="text" name="hiddenInput" value=""> <tablt><tr id="ShowHide"><td> <input type="text" name="otherInput"> </td></tr></table> <input type="submit" name="submitButtonName"> </form> </body> but it does not show/hide & does not set value in textbox. If it's solve using jquery then i will be thankful to you for you code. Thanks.

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  • How to programmatically check availibilty of internet connection in Android?

    - by Fahad
    Hi! I want to check programmatically whether there is an internet connection in android phone/emulator. So that once I am sure that an internet connection is present then I'll make a call to the internet. So its like "Hey emulator! If you have an internet connection, then please open this page, else doSomeThingElse();" hope you get the idea. I would highly appreciate a quick response I need it quite early. regards Fahad Ali Shaikh

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  • How to upload a file into database by using Servlet?

    - by user1765496
    Hi all iam working on servlets, so i need to upload a file by using servlet as follows my code. package com.limrasoft.image.servlets; import java.io.*; import javax.servlet.*; import javax.servlet.http.*; import javax.servlet.annotation.*; import java.sql.*; @WebServlet(name="serv1",value="/s1") public class Account extends HttpServlet{ public void doPost(HttpServletRequest req,HttpServletResponse res)throws ServletException,IOException{ try{ Class.forName("oracle.jdbc.driver.OracleDriver"); Connecection con=null; try{ con=DriverManager.getConnection("jdbc:oracle:thin:@localhost:1521:xe","system","sajid"); PrintWriter pw=res.getWriter(); res.setContentType("text/html"); String s1=req.getParameter("un"); string s2=req.getParameter("pwd"); String s3=req.getParameter("g"); String s4=req.getParameter("uf"); PreparedStatement ps=con.prepareStatement("insert into account(?,?,?,?)"); ps.setString(1,s1); ps.setString(2,s2); ps.setString(3,s3); File file=new File("+s4+"); FileInputStream fis=new FileInputStream(fis); int len=(int)file.length(); ps.setBinaryStream(4,fis,len); int c=ps.executeUpdate(); if(c==0){pw.println("<h1>Registratin fail");} else{pw.println("<h1>Registration fail");} } finally{if(con!=null)con.close();} } catch(ClassNotFoundException ce){pw.println("<h1>Registration Fail");} catch(SQLException se){pw.println("<h1>Registration Fail");} pw.flush(); pw.close(); } } I have written the above code for file upload into database, but it giving error as "HTTP Status 500 - Servlet3.java (The system cannot find the file specified)" Could you plz help me to do this code,thanks in advanse.

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