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  • JavaScript regular expression literal persists between function calls

    - by Charles Anderson
    I have this piece of code: function func1(text) { var pattern = /([\s\S]*?)(\<\?(?:attrib |if |else-if |else|end-if|search |for |end-for)[\s\S]*?\?\>)/g; var result; while (result = pattern.exec(text)) { if (some condition) { throw new Error('failed'); } ... } } This works, unless the throw statement is executed. In that case, the next time I call the function, the exec() call starts where it left off, even though I am supplying it with a new value of 'text'. I can fix it by writing var pattern = new RegExp('.....'); instead, but I don't understand why the first version is failing. How is the regular expression persisting between function calls? (This is happening in the latest versions of Firefox and Chrome.) Edit Complete test case: <!DOCTYPE HTML> <html> <head> <meta http-equiv="Content-type" content="text/html;charset=UTF-8"> <title>Test Page</title> <style type='text/css'> body { font-family: sans-serif; } #log p { margin: 0; padding: 0; } </style> <script type='text/javascript'> function func1(text, count) { var pattern = /(one|two|three|four|five|six|seven|eight)/g; log("func1"); var result; while (result = pattern.exec(text)) { log("result[0] = " + result[0] + ", pattern.index = " + pattern.index); if (--count <= 0) { throw "Error"; } } } function go() { try { func1("one two three four five six seven eight", 3); } catch (e) { } try { func1("one two three four five six seven eight", 2); } catch (e) { } try { func1("one two three four five six seven eight", 99); } catch (e) { } try { func1("one two three four five six seven eight", 2); } catch (e) { } } function log(msg) { var log = document.getElementById('log'); var p = document.createElement('p'); p.innerHTML = msg; log.appendChild(p); } </script> </head> <body><div> <input type='button' id='btnGo' value='Go' onclick='go();'> <hr> <div id='log'></div> </div></body> </html> The regular expression continues with 'four' as of the second call on FF and Chrome, not on IE7 or Opera.

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  • Problem with duplicates in a SQL Join

    - by Chris Ballance
    I have the following result set from a join of three tables, an articles table, a products table, an articles to products mapping table. I would like to have the results with duplicates removed similar to a select distinct on content id. Current result set: [ContendId] [Title] [productId] 1 article one 2 1 article one 3 1 article one 9 4 article four 1 4 article four 10 4 article four 14 5 article five 1 6 article six 8 6 article six 10 6 article six 11 6 article six 13 7 article seven 14 Desired result set: [ContendId] [Title] [productId] 1 article one * 4 article four * 5 article five * 6 article six * 7 article seven * Here is condensed example of the relevant SQL: IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'tempdb.dbo.products') AND type = (N'U')) drop table tempdb.dbo.products go CREATE TABLE tempdb.dbo.products ( productid int, productname varchar(255) ) go IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'articles') AND type = (N'U')) drop table tempdb.dbo.articles go create table tempdb.dbo.articles ( contentid int, title varchar(255) ) IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'articles') AND type = (N'U')) drop table tempdb.dbo.articles go create table tempdb.dbo.articles ( contentid int, title varchar(255) ) IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'articleproducts') AND type = (N'U')) drop table tempdb.dbo.articleproducts go create table tempdb.dbo.articleproducts ( contentid int, productid int ) insert into tempdb.dbo.products values (1,'product one'), (2,'product two'), (3,'product three'), (4,'product four'), (5,'product five'), (6,'product six'), (7,'product seven'), (8,'product eigth'), (9,'product nine'), (10,'product ten'), (11,'product eleven'), (12,'product twelve'), (13,'product thirteen'), (14,'product fourteen') insert into tempdb.dbo.articles VALUES (1,'article one'), (2, 'article two'), (3, 'article three'), (4, 'article four'), (5, 'article five'), (6, 'article six'), (7, 'article seven'), (8, 'article eight'), (9, 'article nine'), (10, 'article ten') INSERT INTO tempdb.dbo.articleproducts VALUES (1,2), (1,3), (1,9), (4,1), (4,10), (4,14), (5,1), (6,8), (6,10), (6,11), (6,13), (7,14) GO select DISTINCT(a.contentid), a.title, p.productid from articles a JOIN articleproducts ap ON a.contentid = ap.contentid JOIN products p ON a.contentid = ap.contentid AND p.productid = ap.productid ORDER BY a.contentid

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  • Ordinal not found

    - by seven
    Hi, can anyone give me any advice on what to do about this error ?! i made a simple mfc app which works on windows7 but on winXP it throws the bellow error : "The ordinal 7118 could not be located in the dynamic link lybrary mfc90.dll" Thank you.

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  • Consuming Web Services in Netbeans

    - by Seven
    Hi. I've setup a project in Netbeans 6.5 with some web services that I've created myself and some web services that I've imported from WSDL files. I've setup a couple of desktop application through Netbeans in order to consume these web services. I'm not too sure where to go from here. I have the GUI setup but not sure how to reference the web services so they can be consumed. I was wondering would anybody be able to guide me through this process or point me in the direction of a relevant tutorial. I'd also like to learn how to consume a web service through a JSP (also created in Netbeans) if possible. Thanks.

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  • Getting RGB values for each pixel from a 24bpp Bitmap in C

    - by seven
    Hello, i want to read the RGB values for each pixel from a .bmp file , so i can convert the bmp into a format suitable for gba . so i need to get just the RGB for each pixel and then write this information to a file. i am trying to use the windows.h structures : typedef struct { char signature[2]; unsigned int fileSize; unsigned int reserved; unsigned int offset; }BmpHeader; typedef struct { unsigned int headerSize; unsigned int width; unsigned int height; unsigned short planeCount; unsigned short bitDepth; unsigned int compression; unsigned int compressedImageSize; unsigned int horizontalResolution; unsigned int verticalResolution; unsigned int numColors; unsigned int importantColors; }BmpImageInfo; typedef struct { unsigned char blue; unsigned char green; unsigned char red; unsigned char reserved; }Rgb; typedef struct { BmpHeader header; BmpImageInfo info; Rgb colors[256]; unsigned short image[1]; }BmpFile; but i only need RGB struct. So lets say i read "in.bmp": FILE *inFile, *outFile; inFile = fopen("C://in.bmp", "rb"); Rgb Palette[256]; for(i=0;i<256;i++) { fread(&Palette[i],sizeof(Rgb),1,inFile); } fclose(inFile); is this correct ? how do i write only the RGB information to a file ? can anyone please give me some information please . Thank you.

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  • How could I evaluate this in code?

    - by WM
    There is a medieval puzzle about an old woman and a basket of eggs. On her way to market, a horseman knocks down the old woman and all the eggs are broken. The horseman will pay for the eggs, but the woman does not remember the exact number she had, only that when she took the eggs in pair, there was one left over; similarly, there was one left over when she took them three or five at a time. When she took them seven at a time, however, none were left. Write an application that can determine the smallest number of eggs the woman could have had. It might be a multiple of seven because there are no eggs left when it's seven at a time. But I have a problem. 49 eggs -1=2*24 49 eggs -1=3*16 49 eggs-4=5*9 49 eggs-0=7*7

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  • macro function for printing

    - by seven
    Hi, if for example i have : define PRINT(x) fprintf(stderr, x); and in code i append it : PRINT(("print this")) output is : [print this] if i append it : PRINT(("print %s", "this")) output is : [this] could someone explain me why it receives just the "this" argument and not the whole string ?

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  • Split number and put each digit to separate html element

    - by Seven
    The problem is that I do not know how to break the loop for the first number and start again for the next one. Currently, one span.nNumber has a total digits of the two numbers (123456) and the next span.nNumber contains digits only from another number (456). Goal is to create sequence 123 and 456: <span class='nNumber'> <span>1</span> <span>2</span> <span>3</span> </span> and <span class='nNumber'> <span>4</span> <span>5</span> <span>6</span> </span> Example script: http://jsfiddle.net/PZ8Pt/2/

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  • How to config a default global EJB transaction attribute in JBoss Server?

    - by seven
    my project need to migrate from oc4j to jboss. But it seems that default EJB transaction attribute is different between them. For OC4J: If you do not specify any transaction attributes for an EJB method then OC4J uses default transaction attributes. OC4J by default uses Required for CMP 2.0, NotSupported for MDBs and Supports for all other types of EJBs. (refer to official doc) For JBoss: default for all types EJB is Required. (Maybe , refer to un-official site) To migrate my project within less effort, how to config a default global EJB transaction attribute, e.g. Supports, in JBoss Server?

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  • Most efficient way to maintain a 'set' in SQL Server?

    - by SEVEN YEAR LIBERAL ARTS DEGREE
    I have ~2 million rows or so of data, each row with an artificial PK, and two Id fields (so: PK, ID1, ID2). I have a unique constraint (and index) on ID1+ID2. I get two sorts of updates, both with a distinct ID1 per update. 100-1000 rows of all-new data (ID1 is new) 100-1000 rows of largely, but not necessarily completely overlapping data (ID1 already exists, maybe new ID1+ID2 pairs) What's the most efficient way to maintain this 'set'? Here are the options as I see them: Delete all the rows with ID1, insert all the new rows (yikes) Query all the existing rows from the set of new data ID1+ID2, only insert the new rows Insert all the new rows, ignore inserts that trigger unique constraint violations Any thoughts?

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  • Keeping Score in XNA Game

    - by Seven
    Hi. I'm following an XNA tutorial and have the following code for collision detecting (detecting when a bullet collides with a target). Basically I'm looking to increment a score variable to display the score to the screen without re-writing the whole program. No matter where I place it in this method it seems to start incrementing from the number of targets, not from zero. Is there something simple I'm missing here? Any help would be greatly appreciated. Thanks. private CollisionType CheckCollision(BoundingSphere sphere) { if (completeCityBox.Contains(sphere) != ContainmentType.Contains) return CollisionType.Boundary; for (int i = 0; i < targetList.Count; i++) { if (targetList[i].Contains(sphere) != ContainmentType.Disjoint) { targetList.RemoveAt(i); i--; AddTargets(); return CollisionType.Target; } } return CollisionType.None; }

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  • SQLAuthority News – 7th Anniversary of Blog – A Personal Note

    - by Pinal Dave
    Special Day Today is a very special day – seven years ago I blogged for the very first time.  Seven years ago, I didn’t know what I was doing, I didn’t know how to blog, or even what a blog was or what to write.  I was working as a DBA, and I was trying to solve a problem – at my job, there were a few issues I had to fix again and again and again.  There were days when I was rewriting the same solution over and over, and there were times when I would get very frustrated because I could not write the same elegant solution that I had written before.  I came up with a solution to this problem – posting these solutions online, where I could access them whenever I needed them.  At that point, I had no idea what a blog was, or even how the internet worked, I had no idea that a blog would be visible to others.  Can you believe it? Google it on Yahoo! After a few posts on this “blog,” there was a surprise for me – an e-mail saying that someone had left me a comment.  I was surprised, because I didn’t even know you could comment on a blog!  I logged on and read my comment.  It said: “I like your script,but there is a small bug.  If you could fix it, it will run on multiple other versions of SQL Server.”  I was like, “wow, someone figured out how to find my blog, and they figured out how to fix my script!”  I found the bug, I fixed the script, and a wrote a thank you note to the guy.  My first question for him was: how did you figure it out – not the script, but how to find my blog?  He said he found it from Yahoo Search (this was in the time before Google, believe it or not). From that day, my life changed.  I wrote a few more posts, I got a few more comments, and I started to watch my traffic.  People were reading, commenting, and giving feedback.  At the end of the day, people enjoyed what I was writing.  This was a fantastic feeling!  I never thought I would be writing for others.  Even today, I don’t feel like I am writing for others, but that I am simply posting what I am learning every day.  From that very first day, I decided that I would not change my intent or my blog’s purpose. 72 Million Views – 2600 Posts – 57000 comments – 10 books – 9 courses Today, this blog is my habit, my addiction, my baby.  Every day I try to learn something new, and that lesson gets posted on the blog.  Lately there have been days where I am traveling for a full 24 hours, but even on those days I try to learn something new, and later when I have free time, I will still post it to the blog.  Because of this habit, this blog has over 72 millions views, I have written more than 2600 posts, and there are 57,000 comments and counting.  I have also written 10 books, 9 courses, and learned so many things.  This blog has given me back so much more than I ever put it into it.  It gave me an education, a reason to learn something new every day, and a way to connect to people.  I like to think of it as a learning chain, a relay where we all pass knowledge from one to another. Never Ending Journey When I started the blog, I thought I would write for a few days and stop, but now after seven years I haven’t stopped and I have no intention of stopping!  However, change happens, and for this blog it will start today.  This blog started as a single resource for SQL Server, but now it has grown beyond, to Sharepoint, Personal Development, Developer Training, MySQL, Big Data, and lots of other things.  Truly speaking, this blog is more than just SQL Server, and that was always my intention.  I named it “SQL Authority,” not “SQL Server Authority”!  Loudly and clearly, I would like to announce that I am going to go back to my roots and start writing more about SQL, more about big data, and more about the other technology like relational databases, MySQL, Oracle, and others.  My goal is not to become a comprehensive resource for every technology, my goal is to learn something new every day – and now it can be so much more than just SQL Server.  I will learn it, and post it here for you. I have written a very long post on this anniversary, but here is the summary: Thank You.  You all have been wonderful.  Seven years is a long journey, and it makes me emotional.  I have been “with” this blog before I met my wife, before we had our daughter.  This blog is like a fourth member of the family.  Keep reading, keep commenting, keep supporting.  Thank you all. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: About Me, MySQL, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, SQLAuthority News, T SQL

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  • What's wrong with my grub configuration?

    - by Daniel Medrano
    I have one hard drive with 2 partitions. I had Windows XP and Windows Seven installed. I've deleted Seven partition and installed Ubuntu 11.10 on it. But when I turn on the computer and the grub menu appears on the screen, I can only see my ubuntu installations and a windows 7 loader. I've already got installed windows XP on another partition, but it doesn't boot. If I want to use Ubuntu alongside Windows XP, ¿how can I fix the problem?

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  • Windows gets progressively slower over time, why doesn't Ubuntu?

    - by William
    I, and many other previous Windows users notice that the computer seems to get progressively slower over time. I bought a leapfrog crammer only to find it installed process that sat there waiting for me to plug the crammer in so it could run the software. It took up three percent of the CPU twenty-four seven, seven day a week! This is one of the main reasons I left Windows. But, Ubuntu doesn't seem to slow down over time at all. Does Ubuntu allow programs to install background programs like the leapfrog crammer did to sit there like a leech and suck away at resources? Could someone explain why Windows tends to get slower over time, and is Ubuntu vulnrable to this too? Thanks for any help, this is puzzling me.

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  • Actor model to replace the threading model?

    - by prosseek
    I read a chapter in a book (Seven languages in Seven Weeks by Bruce A. Tate) about Matz (Inventor of Ruby) saying that 'I would remove the thread and add actors, or some other more advanced concurrency features'. Why and how an actor model can be an advanced concurrency model that replaces the threading? What other models are the 'advanced concurrency model'?

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